Hypothetical element A has three stable isotopes. The first isotope has a mass of 35.01 amu and an abundance of 35.00%. The second isotope has a mass of 36.01 amu and an abundance of 15.00%. The third isotope has a mass of 37.02 amu and an abundance of 50.00%. What is the atomic mass of element A
Answer:
36.16 amu
Explanation:
From the question given above, the following data were obtained:
1st Isotope:
Mass of 1st isotope = 35.01 amu
Abundance of 1st isotope = 35%
2nd isotope:
Mass of 2nd isotope = 36.01 amu
Abundance of 2nd isotope = 15%
3rd isotope:
Mass of 3rd isotope = 37.02 amu
Abundance of 3rd isotope = 50%
Atomic mass of element A =?
The atomic mass of element A can be obtained as follow:
Atomic mass = [(mass of 1st × Abundance)/100] + [(mass of 2nd × Abundance)/100] + [(mass of 3rd × Abundance)/100]
= [(35.01 × 35)/100] + [(36.01 × 15)/100] + [(37.02 × 50)/100]
= 12.25 + 5.40 + 18.51
= 36.16 amu
Thus, the atomic mass of element A is 36.16 amu
Quais são os nomes dos planetas anões
Answer:
Can you translate it on English so we can understand
Which statement describes the law of conservation of energy? A. All systems will exchange matter and energy with their surroundings. B. All systems can exchange energy, but not matter, with their surroundings. C. Energy cannot be created nor destroyed, but it changes from one form to another. D. Energy is destroyed in most chemical reactions when new products are formed.
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Answer:
C, energy cannot be created nor destroyed.
Explanation:
The gases in a hair spray can are at a temperature of 26.0 °C and a pressure of 25.0 lbs/in2. If the gases in the can reach a pressure of
90.0 Ibs/in?, the can will explode. To what temperature in Celsius must the gases be raised in order for the can to explode?
Answer:
The gases in a hair spray can are at a temperature of 26.0 °C and a pressure of 25.0 lbs/in2.
If the pressure becomes [tex]90.0lbs/in^{2}[/tex], what is the temperature of the gases?
Explanation:
According to Gay lussac's law:
the pressure of a gas is directly proportional to its absolute temperature.
[tex]P\alpha T[/tex]
[tex]\frac{P{1} }{T{1} }=\frac{P{2} }{T{2} }[/tex]
Given,
[tex]P1=25.0lbs/in^{2} \\P2=90.0lbs/in^{2} \\T1=26^{o} C=(26+273)K=299K\\T2=?[/tex]
Substitute these values in the above formula:
[tex]\frac{P{1} }{T{1} }=\frac{P{2} }{T{2} }\\\\\frac{25lbs/in^{2} }{299K} }=\frac{90.0lbs/in^{2} }{T{2} }\\\\\\On simplification \\T2=1076.4K\\T2=(1076.4-273)^{o} C=803.4^{o} C[/tex]
Answer:
The gases will be raised to a temperature of 803.4[tex]^{o} C[/tex].
g a 144 g metal bar requires 2500 J to change its temperature from 23.5 to 100 degree C what is the specific heat of the metal
Answer:
226.9 J·kg⁻¹·°C⁻¹
Explanation:
The specific heat of a substance can be defined as the amount is heat that has to be added in order for a given mass of the substance to increase its temperature:
c = ΔQ/(m*ΔT)In this case:
ΔQ = 2500 Jm = 144 g ⇒ 144 g / 1000 = 0.144 kgΔT = 100 - 23.5 = 76.5 °CWe input the data:
c = 2500 J / (0.144 kg * 76.5 °C)And calculate c:
c = 226.9 J·kg⁻¹·°C⁻¹What are the IUPAC name?
Answer:
IUPAC
Explanation:
International Union of Pure and Applied Chemistry
In the reaction below does water acts as the acid or as the base?
H2S + H20 - HS1- + H30+ *
O a. Neither, water is neutral
O b. Acid
O C. Base
Answer:
C. Base.
Explanation:
Hello there!
In this case, according to the given information, it turns out convenient for us to realize that the concept acid and base we should use here is based off the Bronsted-Lowry one, which says that an acid is a hydrogen donor. In such a way, since water accepts one H ion as it goes to H3O⁺, we infer it is C. Base and the H2S the acid.
Also, we can tell HS⁻ is the conjugate base and H3O⁺ the conjugate acid.
Regards!
HEEELP! What are some examples of nuclear fusion? Select all the correct answers.
A: Being the power source of stars
B: Forming heavier elements from light elements
C: Generating electricity in power plants
D: Being used in thermonuclear weapons
E: Supplying the power source in nuclear submarines
Answer:
A B D
Explanation:
Answer: A: Being the power source of stars
B: Forming heavier elements from light elements
D: Being used in thermonuclear weapons
Explanation: (Edmentum)
Which of the following statements about the pH of 0.010 M HClO4 is correct?
pH=2.00, because [H+]=1.0×10−2M.
A: p H equals 2.00 , because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar .
pH=2.00, because [H+]=2.0×10−2M.
B: p H equals 2.00 , because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar .
pH>2.00, because HClO4 is a strong acid.
C: p H is greater than 2.00 , because H C l O 4 is a strong acid.
pH<2.00, because HClO4 is a weak acid.
Answer:
Option B: p H equals 2.00 , because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar .
pH = 2 because [H⁺] = 1×10¯² M
Explanation:
To know which option is correct, we shall determine the pH of the 0.010 M HClO₄ solution. This can be obtained as follow:
We'll begin by calculating the concentration of the hydrogen ion [H⁺] in the solution. This is illustrated below:
HClO₄ is a strong acid and will dessociates as follow:
HClO₄ (aq) —> H⁺ (aq) + ClO₄¯ (aq)
From the balanced equation above,
1 mole of HClO₄ produced 1 mole H⁺.
Therefore, 0.010 M HClO₄ will also produce 0.010 M H⁺.
Finally we shall determine the pH of the solution. This can be obtained as follow:
Concentration of the hydrogen ion [H⁺] = 0.010 = 1×10¯² M
pH =?
pH = –Log [H⁺]
pH = –Log 1×10¯²
pH = 2
Thus,
The pH = 2
because,
[H⁺] = 1×10¯² M
Thus, option B gives the correct answer to the question.
Based on the definition of pH, pH of 0.010 M solution of HClO4 equals 2.00, because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar.
What is pH?The pH of a solution is the negative logarithm of the hydrogen ion concentration of a solution.
pH of a solution is a measure of the acidity of the solution.
pH = - log[H+]where
[H+] is hydrogen ion concentrationFor the 0.010 M solution of HClO4, [H+} = 0.01 M
pH = -log(0.01)
pH = 2.00
Therefore, pH of 0.010 M solution of HClO4 equals 2.00, because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar.
Learn more about pH at: https://brainly.com/question/172153
ch3cooh number of bonding pairs and lone pairs.
Answer:
whats the question?
Explanation:
Name one common base that is NOT harmful to the body when ingested AND a product, or way, in which it is used.
Answer:
well when you eat some food you will get many tastes mixed with base and acid but salt from NA2CO3 can be a base if it is contained with weak acid.
Explanation:
Basically SALT can be one common base that is NOT harmful to the body when ingested AND a product, or way, in which it is used.
Magnesium hydroxide (Mg(OH)2) is not harmful to our body when ingested AND a product, or way, in which it is used. It is commonly used to get relief from acidity, that is caused when our stomach releases excessive acid. It neutrelises the acid and gives us relief. It is also called Milk of Magnesia commonly.
from E=mc²=hv show that wavelength=h/mv
Explanation:
To show - from E=mc²=hv show that wavelength=h/mv
Proof -
Given that,
E = mc²
E = hν
By equating both the equations, we get
mc² = hν
Because real particles do not travel at the speed of light, De Broglie submitted velocity ( v ) for the speed of light ( c ).
mv² = hν
Through the equation λ , de Broglie substituted v/λ for ν and arrived at the final expression that relates wavelength and particle with speed.
mv² = hv/λ
⇒λ = hv/mv²
⇒λ = h/mv
Hence showed.
In this image, which fundamental interaction is responsible for attracting the electron?
a. electromagnetism
b. nuclear weak force
c. gravitation
d. nuclear strong force
Answer:
a.
Explanation:
electromagnetism
(i)What happens when an aqueous solution of sodium sulphate reacts with an aqueous
solution of barium chloride ? (i) Write the balanced chemical equation for the reaction which takes place.(ii) Name the type of chemical reaction which occurs. Define.
Explanation:
2nacl+baso4
the orginal equation is
Na2so4+Bacl2
then na react with cl and ba react with so4
Give the Shorthand Electron Configuration for the following elements:
Nickel
Group of answer choices
[Kr] 3d8 4s2
[Ne] 3d6 4s2
[Ar] 3d8 4s2
answer of this question is [Ar]3d8 4s2
Answer: [Ar] 3d8 4s2
Explanation: Wikipedia
A 0.457-M aqueous solution of (CH3)2NH (dimethylamine) has a pH of 12.2. Calculate the pH of a buffer solution that is 0.457 M in (CH3)2NH and 0.280 M in (CH3)2NH2 .
Answer:
pH = 10.95
Explanation:
To solve this question we must, as first, find pKb of dimethylamine. Then, using H-H equation we can solve the pH of the buffer:
pKb dimethylamine:
Based on the equilibrium:
(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH2⁺(aq) + OH-(aq)
Kb is defined as:
Kb = [OH-] [(CH3)2NH2⁺] / [(CH3)2NH]
Both (CH3)2NH2⁺(aq) + OH- comes from the same equilibrium, that means:
[OH-] = [(CH3)2NH2⁺]
And: [(CH3)2NH] = 0.457M
[OH-] can be obtained from pH as follows:
14 -pH = pOH
14-12.2 = 1.8 =pOH
10^-pOH = [OH-] = 0.01585M
Replacing:
Kb = [0.01585M] [(0.01585M] / [0.457M]
Kb = 5.50x10⁻⁴
pKb = -logkb = 3.26
pH of the buffer:
Using H-H equation for bases:
pOH = pKb + log [conjugate acid] / [weak base]
pOH = 3.26 + log [0.280M] / [0.457M]
pOH = 3.05
pH = 14 - pOH
pH = 10.95If 5.0 liters of hydrogen react with excess oxygen, what mass of water would be produced?
Answer:
our equation specifies that
32
⋅
g
of dioxygen and
4
⋅
g
of dihydrogen give
36
⋅
g
of water upon reaction, so..........
Explanation:
2
H
2
(
g
)
+
O
2
(
g
)
→
2
H
2
O
(
g
)
We started with
5.0
⋅
g
32.00
⋅
g
⋅
m
o
l
−
1
=
0.156
⋅
m
o
l
dioxygen
.
Given excess dihydrogen, this molar quantity thus gives
2
×
0.156
⋅
m
o
l
water.
And thus,
2
×
0.156
⋅
m
o
l
×
18.01
⋅
g
⋅
m
o
l
−
1
≅
6
⋅
g
water are evolved. Is this reaction exothermic or endothermic?
can someone please help me im stuck
Answer:
The answers to your questions are given below.
Explanation:
1. __H₂ + __O₂ —> __H₂O
The above equation can be balance as follow:
H₂ + O₂ —> H₂O
There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 2 before H₂O as shown below:
H₂ + O₂ —> 2H₂O
There are 2 atoms of H on the left side and a total of 4 atoms on the right side. It can be balance by writing 2 before H₂ as shown below:
2H₂ + O₂ —> 2H₂O
Now the equation is balanced.
Elements >>> Reactants >>> Products
H >>>>>>>>> 4 >>>>>>>>>>> 4
O >>>>>>>>> 2 >>>>>>>>>>> 2
2. __ P₄ + __O₂ —> __P₂O₃
The above equation can be balance as follow:
P₄ + O₂ —> P₂O₃
There are 4 atoms of P on the left side and 2 atoms on the right side. It can be balance by writing 2 before P₂O₃ as shown below:
P₄ + O₂ —> 2P₂O₃
There are 2 atoms of O on the left side and a total of 6 atoms on the right side. It can be balance by writing 3 before O₂ as shown below:
P₄ + 3O₂ —> 2P₂O₃
Now, the equation is balanced
Elements >>> Reactants >>> Products
P >>>>>>>>> 4 >>>>>>>>>>> 4
O >>>>>>>>> 6 >>>>>>>>>>> 6
What is the present Ba in Ba(NO3)2?
Answer:
Percentage of Ba = 52.5%
Explanation:
We'll begin by calculating the molar mass of Ba(NO3)₂. This can be obtained as follow:
Molar mass of Ba(NO3)₂ = 137 + 2[14 +(16×3)]
= 137 + 2[14 + 48]
= 137 + 2[62]
= 137 + 124
= 261 g/mol
Next, we shall determine the mass of Ba in Ba(NO3)₂. This can be obtained as follow:
Mass of Ba in Ba(NO3)₂ = 137 g/mol
Finally, we shall determine the percentage of Ba in Ba(NO3)₂. This can be obtained as follow:
Percentage of Ba = mass of Ba / mass of Ba(NO3)₂ × 100
Percentage of Ba = 137 / 261 × 100
Percentage of Ba = 13700 / 261
Percentage of Ba = 52.5%
Thus, the percentage of Ba in Ba(NO3)₂ is 52.5%
match the following
Of scinece chapter
Describe the process of making 1.0 L of a 0.03 M solution of cobalt (II) chloride from the solid state. Be sure to include all instrumentation and glassware.
Answer:
By measuring out 3.9 grams of cobalt (II) chloride up to a volume of 1.0 L of solution.
Explanation:
Hello there!
In this case, considering this question about molarity, it turns out possible for us to calculate the required mass of cobalt (II) chloride by firstly compute the moles present in 1.0L of the given 0.03-M solution:
[tex]M=\frac{n}{V} \\n=V*M\\\\n=1.0L*0.03\frac{molCoCl_2}{L}\\\\n=0.03molCoCl_2[/tex]
Next, since the molar mass of cobalt (II) chloride is 129.84 g/mol, we compute the grams we need to measure out in order to prepare this solution:
[tex]m_{CoCl_2}=0.03molCoCl_2*\frac{129.84gCoCl_2}{1molCoCl_2} \\\\m_{CoCl_2}=3.9gCoCl_2[/tex]
Regards!
What is a metal oxide + acid
Metal oxide + acid —> __+__
Answer:
Metal oxide + acid —> salt + water
Explanation:
Please hurry!!! And help!!
*URGENT*
Best answer gets marked Brainliest!
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Why is elemental zinc considered a pure substance
A) it is a metal
B) it is a mixture of different atoms
C) it must be created in a lab
D) all elements are considered pure substances
Answer:
D
Explanation:
Answer:
D
Explanation:
Because it is true
what is the definition of isomerism
Answer:
Isomerism is the phenomenon in which more than one compounds have the same chemical formula but different chemical structures. Chemical compounds that have identical chemical formulae but differ in properties and the arrangement of atoms in the molecule are called isomers. Therefore, the compounds that exhibit isomerism are known as isomers.
The word “isomer” is derived from the Greek words “isos” and “meros”, which mean “equal parts”. This term was coined by the Swedish chemist Jacob Berzelius in the year 1830.
Explanation:
Helpppp pleaseee ill give brainliest
Answer:
The answers are in the explanation.
Explanation:
The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:
Increasing temperature of ice from -10°C - 0°C:
Q = S*ΔT*m
Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g
Q = 2.06J/g°C*10°C*10g
Q = 206J
Change from solid to liquid:
The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:
Q = 333.55J/g*10g
Q = 3335.5J
Increasing temperature of liquid water from 0°C - 100°C:
Q = S*ΔT*m
Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g
Q = 4.18J/g°C*100°C*10g
Q = 4180J
Change from liquid to gas:
The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:
Q = 2260J/g*10g
Q = 22600J
Increasing temperature of gas water from 100°C - 120°C:
Q = S*ΔT*m
Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g
Q = 1.87J/g°C*20°C*10g
Q = 374J
Total Energy:
206J + 3335.5 J + 4180J + 22600J + 374J =
30695.5J =
30.7kJ
What is the molar mass of 4.23 g of an elemental gas in a 2.5L container at 282K and 1.4 atm?
Answer:
27.98g/mol
Explanation:
Using ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
T = temperature (K)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
According to the information given:
V = 2.5L
P = 1.4 atm
T = 282K
n = ?
Using PV = nRT
n = PV/RT
n = 1.4 × 2.5/0.0821 × 282
n = 3.5/23.1522
n = 0.151mol
Using the formula to calculate molar mass of the elemental gas:
mole = mass/molar mass
Molar mass = mass/mole
Molar mass = 4.23g ÷ 0.151mol
Molar mass = 27.98g/mol
A 2.00 L flask is filled with propane gas (C3H8) at a pressure of 1.10 atm and a temperature of 258 K. What is the mass of propane in the flask?
Answer:
m = 4.58 g.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to realize this problem is solved via the ideal gas equation:
[tex]PV=nRT[/tex]
As we can calculate the moles of propane given the pressure, temperature and volume as shown below:
[tex]n=\frac{PV}{RT} \\\\n=\frac{1.10atm*2.00L}{0.08206\frac{atm*L}{mol*K}*258K} \\\\n=0.104mol[/tex]
Finally, since the molar mass of propane is 44.1 g/mol, we calculate the mass by following the shown below mole-mass conversion factor:
[tex]m=0.104mol*\frac{44.1g}{1mol}\\\\m= 4.58g[/tex]
Regards!
How many grams of chlorine are required in order to consume 100g of sodium chloride?
Answer:
92.1 g
Explanation:
Answer: 92.1 grams
I hope this helped :3
What is the equation for the reaction between ethanoic acid and butanol in the presence of H2SO4?
Answer:
[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to realize this is a question about esterification, process whereby a carboxylic acid and an alcohol react to produce water an an ester, we can set it up as shown below:
[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH[/tex]
For the reaction between ethanoic acid and butanol; and therefore, the products side is:
[tex]CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]
It means that the overall equation is:
[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]
And the ester product is butyl ethanoate.
Regards!
I
Gggggggggggggsgstststsysgtetwtwtst
Answer:
ummm u ok?
Explanation: