how does different color show exist

Answers

Answer 1

Answer:Light is made up of wavelengths of light, and each wavelength is a particular colour. The colour we see is a result of which wavelengths are reflected back to our eyes. The visible spectrum showing the wavelengths of each of the component colours. The spectrum ranges from dark red at 700 nm to violet at 400 nm.  

Explanation:

hope it helps

Answer 2

Answer:When light hits an object, the object reflects some of that light and absorbs the rest of it. Some objects reflect more of a certain wavelength of light than others. That's why you see a certain colour. For example, a lemon reflects mainly yellow light.

Explanation:


Related Questions

Galileo is considered the father of modern science. Do you agree with this description? Give reasons for your answer.

Answers

Answer:

Galileo Galilei pioneered the experimental scientific method and was the first to use a refracting telescope to make important astronomical discoveries

Explanation:

Yes I agree with this. He made significant scientific discoveries that changed the way of life.

A man standing on the Earth can exert the same force with his legs as when he is standing on the moon. We know that the mass of the man is the same on the Earth and the moon. We also know that F=ma is true on both the Earth and the moon. Will the man be able to jump higher on the moon than the Earth? Why or why not?
PLEASE HELPPPP

Answers

Answer:

yes

Explanation:

earth has gravity force that is high than the moon gravity force which is 1/6 of earth gravity

Earth has gravity force that is high than the moon gravity force which is 1/6 of earth gravity.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

The force on the moon is less than earth as gravity is 1/6 on the moon

When man jump than he will jump high on the moon than the earth.

Earth has gravity force that is high than the moon gravity force which is 1/6 of earth gravity.

To learn more about force refer to the link:

brainly.com/question/13191643

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1) The cause of magnetism is
A. atoms forming “domains” that are arranged randomly
B. atoms forming "domains” that are arranged uniformly
C. atoms forming "dolomites” that are arranged randomly
D. atoms forming “dolomites” that are arranged uniformly

Answers

Answer:

I think it's A, I'm not sure though

Consider a 2 m wide and 5 m long slab resting on flat, fixed, earthen bed. The slab is 20 cm thick with uniform properties. You may assume the slab is much longer and wider than it is thick. Write the reduced form of the governing equation for the slab. Clearly identify your coordinate system on a sketch and state your assumptions identifying which terms you are eliminating and why.

Answers

Answer:

Explanation:

The coordinate sketch for the system is shown in the attached file below. Also, in the cartesian coordinate system, since the height is less than the length and width, we did neglect the height. Thus, we eliminate the height and converted it to a two-dimension.

A car company is doing crash tests and has installed forcesensors in the chairs and seatbelts to measure the forces thatare exerted on crash test dummies during a crash. In oneparticular test the sensors measure a horizontal net force onthe dummy of 39,400 N when the car comes to a complete stopfrom an initial speed of 35 m/s in 1.4 m. Treating the dummyas a point particle and assuming it comes to rest in the samedistance, what is the mass of the test dummy used during thistest

Answers

Answer:

[tex]m=90.1kg[/tex]

Explanation:

From the question we are told that

Force F=39400

Initial speed [tex]V_1=35m/s[/tex]

Distance[tex]d=1.4m[/tex]

Generally the equation for acceleration is mathematically given by

[tex]a=\frac{V^2-U^2}{2d}[/tex]

[tex]a=\frac{0^2-35^2}{21.4}[/tex]

[tex]a=\frac{0^2-35^2}{21.4}[/tex]

[tex]a=-437.5m/sec^2[/tex]

Generally the equation for mass is mathematically given by

[tex]F=ma\\m=F/a[/tex]

[tex]m=\frac{-39400}{-437.5}[/tex]

[tex]m=90.1kg[/tex]

during what part of their drive are the not moving?

Answers

C answer is c math ez
The correct answer is c

What is the kinetic energy of a 30 kg dog that is running at a speed of 8.6 m/s (about 19 mi/h)?

Answers

Answer:

Uhm thags hsed

Explanation:

Dkrr

Which equation will tell you the acceleration of the object?

Answers

Answer:

In summation, acceleration can be defined as the rate of change of velocity with respect to time and the formula expressing the average velocity of an object can be written as: a =Δ v/ Δt The other 4 equations: d = vit+ (1/2) at2

Explanation:

Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.

Answers

This question is incomplete, the complete question is;

A positive charge of magnitude Q1 = 6.5 nC is located at the origin.

A negative charge Q2 = -3.5 nC is located on the positive x-axis at x = 16.5 cm from the origin. The point P is located y = 10.5 cm above charge Q2.

Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.

Answer:

the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C    

Explanation:

Given the data in the question;

Q1 = 6.5 nC, Q2 = -3.5 nC

from the image below, to get our angle ∅

tan∅ = opp/adj

tan∅ = 10.5 / 16.5

tan∅ = 0.636363

∅ = tan⁻¹( 0.636363 )

∅ = 32.47°

also, r1 = √( 16.5² + 10.5²)

r1 = √( 272.25 + 110.25 )

r1 = √382.5

r1 = 19.55 cm = 0.1955 m

Now, the x-component of the electric field at point P due to charge Q1 will be;

Ex = E2cos32.47°

= (kQ1/r1²)cos32.47°

we know that;  k is Coulomb's law constant ( 9 × 10⁹ N.m²/ C²

Q1 = 6.5 nC = 6.5 × 10⁻⁹ C

so we substitute

= ((9 × 10⁹ × 6.5 × 10⁻⁹) / (0.1955)²) cos32.47°

= (58.5 / 0.03822025) × 0.843672

= 1291.33 N/C

Therefore, the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C

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