How does deploying slats or slots on an airfoil affect CL max and Stall AOA?
a) Stall AOA increases, CL max increases.
b) Stall AOA decreases, CL max increases.
c) Stall AOA increases, CL max decreases.
d) Stall AOA decreases, CL max decreases.

Answer:

Case Studies

Explanation:

A case study in psychology is a descriptive research approach used to obtain in-depth information about a person, group, or phenomenon.Case studies use techniques such as personal interviews, direct observation, psychometric tests, and archival records to gather information.

Answer:

5000 m/s

Explanation:

Answer:

yes. everything around you is matter including you!

Answer:

yes

Explanation:

because it takes up space

Answer: hey

your answer is gonna be

71000.

Explanation:

Answer:

Part A

You have to ride 8.0 km before turning north to get to your friend’s house.

Part B

The sine of the angle  θ at the location of the friend's house is 0.8

Explanation:

The remaining part of the question which is an image is attached below

Explanation:

Part A

To determine how far you will ride ride before turning north,

From the diagram, that is the distance of your street.

Let the distance of your street be [tex]A[/tex]

and the distance of your friend's street be [tex]B[/tex]

and let the displacement between your friends house and your house be [tex]C[/tex]

The relation in the diagram shows a right angle triangle.

The sides of the right angle triangle are represented as [tex]A,B[/tex] and [tex]C[/tex].

To find [tex]A[/tex], which is the distance of your street,

From Pythagorean theorem, 'The square of hypotenuse is the sum of squares of the other two sides'

That is,

[tex]/Hypoyenuse/^{2} = /Adjacent/^{2} + /Opposite/^{2}[/tex]

[tex]C[/tex] is the hypotenuse, which is the displacement between your friends house and your house,

Hence, [tex]C = 10.0 km[/tex]

[tex]B[/tex] is adjacent, which is the distance of your friends street

then, [tex]B = 6.0 km[/tex]

and [tex]A[/tex] is the opposite, which is the distance of your house

From Pythagoras theorem, we can then write that,

[tex]C^{2} = B^{2} + A^{2}[/tex]

Then, [tex]10.0^{2} = 6.0^{2} + A^{2}[/tex]

[tex]A^{2} = 100.0 - 36.0\\A^{2} = 64.0\\A = \sqrt{64.0}[/tex]

[tex]A = 8.0km[/tex]

Hence, you have to ride 8.0 km before turning north to get to your friend’s house.

Part B

To find the sine of the angle  θ at the location of the friend's house,

In the diagram, the sine of the angle  θ is given by

[tex]Sin\theta = \frac{Opposite}{Hypotenuse}[/tex]

Hence, [tex]Sin\theta = \frac{A}{C}[/tex]

Then,

[tex]Sin\theta = \frac{8.0}{10}[/tex]

[tex]Sin\theta = 0.8[/tex]

Hence, the sine of the angle  θ at the location of the friend's house is 0.8

A. The amount of distance you have to ride before turning North to get to your friend’s house is 8 kilometers.

B. The sine of the angle (θ) at the location of your friend's house is 0.8.

Given the following data:

A. To determine the amount of distance you have to ride before turning North to get to your friend’s house, we would apply Pythagorean's theorem:

Mathematically, Pythagorean's theorem is given by the formula:

[tex]c^2 = a^2 + b^2\\\\10^2 =6^2+b^2\\\\100=36+b^2\\\\b^2 =100-36\\\\b^2 =64\\\\b=\sqrt{64}[/tex]

b = 8 kilometers

B. To find the sine of the angle (θ) at the location of the friend's house:

Mathematically, the sine of an angle is given by the formula:

[tex]Sin\theta = \frac{opposite}{hypotenuse}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Sin\theta = \frac{8}{10} \\\\Sin\theta = 0.8[/tex]

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Answer:

The satellite that is 7500 km above earth's surface is 1.24 times faster than the satellite at 15000 km above earth's surface

Explanation:

Generally the gravitational force acting on each satellite is mathematically represented as

[tex]F = \frac{G * M_e * m_2 }{r^2}[/tex]

Here [tex]M_e[/tex] is the mass of the earth

[tex]r = r_e + R [/tex]

So [tex] r_e [/tex] is the radius of the satellite and R is the radius of earth with value R = 6371 km

This force is also equivalent to the centripetal force acting on each satellite which is mathematically represented as

[tex]F = \frac{mv^2}{ r^2}[/tex]

So

[tex]\frac{mv^2}{ r^2} = \frac{G * m_1 * m_2 }{r^2}[/tex]

=> [tex]v = \sqrt{ \frac{GM_e}{r} }[/tex]

So for [tex]r = 7500+ 6371 = 13871 \ km [/tex]

We have that

[tex]v_1 = \sqrt{ \frac{GM_e}{13871} }[/tex]

and [tex]r = 15000+ 6371 = 21371 \ km [/tex]

We have that

[tex]v_2 = \sqrt{ \frac{GM_e}{21371} }[/tex]

So

[tex]\frac{v_1}{v_2} = \frac{\sqrt{\frac{GM_e}{13871} } }{ \sqrt{\frac{GM_e}{21371}} }[/tex][tex]v = \sqrt{ \frac{GM_e}{r} }[/tex]

 =>  [tex]\frac{v_1}{v_2}  = \sqrt{ \frac{21371}{13871} }[/tex]

 =>   [tex]v_1    = 1.24 v_2[/tex]

So satellite that is 7500 km above earth's surface is 1.24 times faster than the satellite at 15000 km above earth's surface

Answer:

1.551×10^-8 Ωm

Explanation:

Resistivity of a material is expressed as shown;.

Resistivity = RA/l

R is the resistance of the material

A is the cross sectional area

l is the length of the wire.

Given;

R = 0.0310 Ω

A = πd²/4

A = π(2.05×10^-3)²/4

A = 0.000013204255/4

A = 0.00000330106375

A = 3.30×10^-6m

l = 6.60m

Substituting this values into the formula for calculating resistivity.

rho = 0.0310× 3.30×10^-6/6.60

rho = 1.023×10^-7/6.60

rho = 1.551×10^-8 Ωm

Hence the resistivity of the material is 1.551×10^-8 Ωm

Answer:

2 m/s

Explanation:

The following data were obtained from the question:

Distance (D) = 40 m

Time (t) = 20 s.

Average speed =?

Average speed is the total distance travelled divided by the total time taken. Mathematically, it is expressed as:

Average speed = Total distance /Total time

Thus, we can obtain the average speed as follow:

Total Distance (D) = 40 m

Time time (t) = 20 s.

Average speed =?

Average speed = Total distance /Total time

Average spee= 40/20

Average speed = 2 m/s

Therefore, the average speed between 0 and 20 seconds is 2 m/s.

Answer:

displacement = 55 cm

Explanation:

Initial position = 25 cm

Final position = 80 cm

Displacement = final position-finitial position

Putting values in above formula,

D = 80 cm - 25 cm

D = 55 cm

It means that the displacement of the ant is 55 cm.

The question is incomplete. Here is the complete question.

To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the decibel scale is logarithmic, it changes by an additive constant when the intensity when the intensity as measured in W/m² changes by a multiplicative factor. The number of decibels increase by 10 for a factor of 10 increase in intensity. The general formula for the sound intensity level, in decibels, corresponding to intensity I is

[tex]\beta=10log(\frac{I}{I_{0}} )dB[/tex],

where [tex]I_{0}[/tex] is a reference intensity. for sound waves, [tex]I_{0}[/tex] is taken to be [tex]10^{-12} W/m^{2}[/tex]. Note that log refers to the logarithm to the base 10.

Part A: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 10 times the reference intensity, i.e. [tex]I=10I_{0}[/tex]? Express the sound intensity numerically to the nearest integer.

Part B: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 100 times the reference intensity, i.e. [tex]I=100I_{0}[/tex]? Express the sound intensity numerically to the nearest integer.

Part C: Calculate the change in decibels ([tex]\Delta \beta_{2},\Delta \beta_{4}[/tex] and [tex]\Delta \beta_{8}[/tex]) corresponding to f = 2, f = 4 and f = 8. Give your answer, separated by commas, to the nearest integer -- this will give an accuracy of 20%, which is good enough for sound.

Answer and Explanation: Using the formula for sound intensity level:

A) [tex]I=10I_{0}[/tex]

[tex]\beta=10log(\frac{10I_{0}}{I_{0}} )[/tex]

[tex]\beta=10log(10 )[/tex]

β = 10

The sound Intensity level with intensity 10x is 10dB.

B) [tex]I=100I_{0}[/tex]

[tex]\beta=10log(\frac{100I_{0}}{I_{0}} )[/tex]

[tex]\beta=10log(100)[/tex]

β = 20

With intensity 100x, level is 20dB.

C) To calculate the change, take the f to be the factor of increase:

For [tex]\Delta \beta_{2}[/tex]:

[tex]I=2I_{0}[/tex]

[tex]\beta=10log(\frac{2I_{0}}{I_{0}} )[/tex]

[tex]\beta=10log(2)[/tex]

β = 3

For [tex]\Delta \beta_{4}[/tex]:

[tex]I=4I_{0}[/tex]

[tex]\beta=10log(\frac{4I_{0}}{I_{0}} )[/tex]

[tex]\beta=10log(4)[/tex]

β = 6

For [tex]\Delta \beta_{8}[/tex]:

[tex]I=8I_{0}[/tex]

[tex]\beta=10log(\frac{8I_{0}}{I_{0}} )[/tex]

β = 9

Change is

[tex]\Delta \beta_{2},\Delta \beta_{4}[/tex], [tex]\Delta \beta_{8}[/tex] = 3,6,9 dB

Answer:

44.078 m/s

Explanation:

convert 98.6 miles to meters then convert the hour to minutes and minutes to seconds

Answer:

Speed is 0.08 m/s.

Explanation:

Given the distance that the bird flies = 3.7 meters

The time is taken by the bird to fly the 3.7 meters = 46 seconds  

We have given distance and time. Now we have to find the speed at which the bird flies. So, to calculate the speed of the bird we have to divide the distance by the time.  

Below is the formula to find the speed.

Speed = Distance / Time

Now insert the given value in the formula.

Speed = 3.7 / 46 = 0.08 m/s

the boot kecked the ball which is frictinal force

Answer:

(A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

Explanation:

Given that,

Mass of marble = 0.0073 kg

Speed = 0.65 m/s

(A). We need to calculate the magnitude of the momentum of the marble

Using formula of momentum

[tex]p = mv[/tex]

Where, m = mass

v = velocity

Put the value into the formula

[tex]p=0.0073\times0.65[/tex]

[tex]p=0.004745\ kg m/s[/tex]

(B). Mass of baseball = 0.136 kg

Momentum of baseball = 3.14 kg m/s

We need to calculate the speed of baseball

Using formula of momentum

[tex]p=mv[/tex]

[tex]v=\dfrac{p}{m}[/tex]

Put the value into the formula

[tex]v=\dfrac{3.14}{0.136}[/tex]

[tex]v=23.0\ m/s[/tex]

Hence, (A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

Answer:

The tension in the light rope must be equal to the weight of the bucket

Explanation:

Given that,

Constant velocity of bucket and direction of bucket in downward

We need to find the tension in the rope

Using given data,

When a bucket  moves downward with a constant velocity then the net force does not applied on the bucket.

So, The weight of the bucket will be equal to the tension in the light rope

In mathematically,

[tex]T=mg[/tex]

Where, T = tension

m = mass of bucket

g = acceleration due to gravity

Hence, The tension in the light rope must be equal to the weight of the bucket.

Answer:

i think gravity created a force strong enough to push him down.but it also depends how slow or fast the bus is going

Explanation:

gravity as we all now it is pretty strong so if the bus is going fast then the person standing up will fall but if the bus is going pretty slow then it'll just nudge him.

Answer:

the answer is b reducing the thickness of the conductor

Explanation:

The resistance to electric current increases as the cross-section of the conductor is reduced, as the conductor is lengthened, and as the conductor is heated. Replacing the conductor with a less-conductive material increases the resistance as well.

Answer:

Reducing the thickness of the conductor

Explanation:

Answer:

Unbalanced

Explanation:

It would be speeding and under the influence of an imbalanced force if it were rounding a curve. The train must be subject to an unbalanced force in order for it to continue moving at a constant speed.

Newton's first law is only this one. Unless operated upon by an imbalanced force, an item at rest remains at rest and an object in motion maintains constant speed in the same direction.

The car tends to maintain its travel at a steady speed and direction because the two forces balance each other out and cancel each other out.

The forces are out of balance when an object's motion changes. Equal in size and directed in the opposite direction, balanced forces are. When forces are evenly distributed, motion remains unchanged.

Therefore, One of your scenarios from the previous section involved pushing or pulling an object with the equal amount of force in opposite directions.

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Answer:

True

Explanation:

Acceleration by definition is the change in velocity divided by the change in time.  Thus when the velocity changes, there must be an acceleration.

Answer:

It is independent variable

Explanation:

Answer:

D!!!!!

Explanation:

edge 2021!

1 s  =  1,000 ms

2 s  =  2,000 ms

3 s  =  3,000 ms

.

.

10 s  =  10,000 ms

20 s  =  20,000 ms

30 s  =  30,000 ms

.

.

.

100 s  =  100,000 ms

200 s  =  200,000 ms

300 s  =  300,000 ms

310 s  =  310,000 ms

320 s  =  320,000 ms

.

.

.

350 s  =  350,000 ms

360 s  =  360,000 ms

370 s  =  370,000 ms

.

.

.

Answer:

a) The magnitude of the satellite's velocity when the thruster turns off is approximately 24.177 meters per second.

b) The direction of the satellite's velocity when the thruster turns off is approximately 62.266º.

Explanation:

Statement is incomplete. The complete description is now described below:

A satellite in outer space is moving at a constant velocity of 21.4 m/s in the y direction when one of its onboard thruster turns on, causing an acceleration of 0.250 m/s2 in the x direction. The acceleration lasts for 45.0 s, at which point the thruster turns off.

(a) What is the magnitude of the satellite's velocity when the thruster turns off

(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis. ° counterclockwise from the +x-axis

Let be x and y-directions orthogonal to each other and the satellite is accelerated uniformly from rest in the +x direction and moves at constant velocity in the +y direction. The velocity vector of the satellite ([tex]\vec{v}_{S}[/tex]), measured in meters per second, is:

[tex]\vec{v}_{S} = (v_{o,x}+a_{x}\cdot t)\,\hat{i}+v_{y}\,\hat{j}[/tex]

Where:

[tex]v_{o,x}[/tex] - Initial velocity in +x direction, measured in meters per second.

[tex]a_{x}[/tex] - Acceleration in +x direction, measured in meter per square second.

[tex]t[/tex] - Time, measured in seconds.

[tex]v_{y}[/tex] - Velocity in +y direction, measured in meters per second.

If we know that [tex]v_{o,x} = 0\,\frac{m}{s}[/tex], [tex]a_{x} = 0.250\,\frac{m}{s^{2}}[/tex], [tex]t = 45\,s[/tex] and [tex]v_{y} = 21.4\,\frac{m}{s}[/tex], the final velocity of the satellite is:

[tex]\vec{v}_{S} = \left[0\,\frac{m}{s}+\left(0.250\,\frac{m}{s^{2}} \right)\cdot (45\,s) \right]\,\hat{i}+\left(21.4\,\frac{m}{s} \right)\,\hat{j}[/tex]

[tex]\vec{v_{S}} = 11.25\,\hat{i}+21.4\,\hat{j}\,\,\left[\frac{m}{s} \right][/tex]

a) The magnitud of the satellite's velocity can be found by the resource of the Pythagorean Theorem:

[tex]\|\vec {v}_{S}\| = \sqrt{\left(11.25\,\frac{m}{s} \right)^{2}+\left(21.4\,\frac{m}{s} \right)^{2}}[/tex]

[tex]\|\vec{v}_{S}\| \approx 24.177\,\frac{m}{s}[/tex]

The magnitude of the satellite's velocity when the thruster turns off is approximately 24.177 meters per second.

b) The direction of the satellite's velocity when the thruster turns off is determined with the help of trigonometric functions:

[tex]\tan \alpha = \frac{v_{y}}{v_{x}} = \frac{21.4\,\frac{m}{s} }{11.25\,\frac{m}{s} }[/tex]

[tex]\tan \alpha = 1.902[/tex]

[tex]\alpha = \tan^{-1}1.902[/tex]

[tex]\alpha \approx 62.266^{\circ}[/tex]

The direction of the satellite's velocity when the thruster turns off is approximately 62.266º.

Answer:

D) either 436 Hz or 444 Hz

Explanation:

frequency of the tuning fork, F₁ =  440 Hz

frequency of the piano, F₂ = ?

Beat frequency, F = 4 Hz

Beat frequency is given as the difference between the frequency of the two instruments  and it is given by;

F = F₂ - F₁                    or        F =  F₁ - F₂

F₂ = F + F₁                   or        F - F₁ = - F₂

F₂ = 4 Hz + 440 Hz    or       4 - 440 = - F₂

F₂ = 444 Hz                or      - 436 = - F₂

F₂ = 444 Hz               or         F₂ = 436 Hz

Therefore, the frequency of the piano is 444 Hz or 436 Hz

Answer:

350 N

Explanation:

F=ma

[tex]f = force \\ m = mass \\ a = acceleration[/tex]

[tex]m = 2(55kg) + 240kg \\ a = 1.0 \frac{m}{ {s}^{2} } [/tex]

Force = 350 Newtons

The net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The mathematical expression for Newton's second law is as follows

F = ma

As given in the problem two people each have a mass of 55 kg. They are both in an elevator that has a mass of 240 kg. When the elevator begins to move, the people and the elevator have an upward acceleration of 1.00 m/s2, then we have to find the net force acting on the elevator,

The net force acting on the elevator,

F = ma

F =(2×55 + 240)×1

  = 350 Newtons

Thus, the net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2

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Answer:

5.15J

Explanation:

First. 54% of the 7kg refrigerant is liquid

So we find mass of vapour at inlet generator

M1 = ( 1-0.54)*7= 3.2kg

At compressor mass of vapour will be

M2= 0.95*7= 6.7kg

So the Mass of vapour at exit generator is

M2-M1= 3.5kg

So to find heat absorbed by refrigerant in evaporation

Its using

Q= mh

°= 3.5x 1.50×10^5 J/kg

=5.15J

Answer:

A. smaller arteries

Explanation:

A. because it makes no sence.

Answer:

Because its wet

Explanation: