Answer:
0.0000047
Step-by-step explanation:
Simply move the decimal place 6 places to the left while filling in the zeros.
involving the use of variables, properties, expressions, and equations
Use a calculator to find tan 72°. Round to the nearest thousandth.
Answer:
3.078
Step-by-step explanation:
tan 72° = 3.078
Answer:
tan 72 = 3.078
Step-by-step explanation:
rounded like requested
Find
[tex]( {10x}^{2} - 11x + 8) + ( {2x}^{2} + 7x - 5 )[/tex]
Answer:
[tex]12x^2-4x+3[/tex]
Step-by-step explanation:
Parentheses do not matter in this equation.
[tex](10x^2-11x+8)+(2x^2+7x-5)=\\10x^2-11x+8+2x^2+7x-5=\\12x^2-11x+8+7x-5=\\12x^2-4x+8-5=\\12x^2-4x+3[/tex]
Our answer is [tex]12x^2-4x+3[/tex]
Antonio was eating a bag of M&Ms. There were 4 green M&Ms, 20 brown M&Ms, 16 red
M&Ms, and 11 blue M&Ms. What is the probability of Antonio eating a blue M&M next?
Answer:
11/51 or 0.21468627
Step-by-step explanation:
Andy has $7,411 in a savings account. The interest rate is 11%, compounded annually.
To the nearest cent, how much interest will he earn in 2 years?
Use the formula B = P(1 + r), where B is the balance (final amount), p is the principal
(starting amount), r is the interest rate expressed as a decimal, and t is the time in years.
Submit
Please help :)
Answer:
$1720.0931 will earn as interest in 2 years
Step-by-step explanation:
Principal = $7411
Rate of interest = 11% compounded annually
Time = 2 years
Formula : [tex]A = P(1+r)^t[/tex]
[tex]A=7411(1+0.11)^2[/tex]
A=9131.0931
Interest = Amount - Interest =$9131.0931 - $7411
Interest = $1720.0931
Hence $1720.0931 will earn as interest in 2 years
Find all possible values of the fraction below. (Assume different letters are different digits, and the same letters are the same digits.) (G*R*O*U*N*D)/(B*A*S*E)
Answer:
there is one possible value: 0.
Step-by-step explanation:
We have 10 different letters in this fraction {G,R,O,U,N,D,B,A,S,E} and only 10 different digits {0,1,2,3,4,5,6,7,8,9}. It means that some letter must be equal to 0. Consider two cases:
I case:
[tex]0 \in \{G, R, O, U, N, D\}[/tex]. Then enumerator of fraction must be equal to zero (because product of numbers with zero among them always zero).
So [tex]\frac{GROUND}{BASE} = \frac{0}{BASE} = 0[/tex] in this case.
II case:
[tex]0 \in \{B,A,S,E\}[/tex]. Then for the same reasons as in I case denominator of fraction is equal to zero. And we know that fraction
[tex]\frac{BASE}{0}[/tex] is not well-defined.
The vertex of this parabola is at (2,-1). When the y value is 0, the value is 5.
What is the coefficient of the squared term in the parabola's equation?
(2.-1)
A.-3
B. -4
c. 4
D. 3
Answer:
Option D.
Step-by-step explanation:
The vertex form of a parabola along y-axis is
[tex]y=a(x-h)^2+k[/tex]
where, (h,k) is vertex and, a is constant and it is equal to coefficient of the squared term in the parabola's equation.
The vertex of the parabola is (2,-1). So, h=2 and k=-1.
[tex]y=a(x-2)^2-1[/tex]
The graph passes through (5,0). So,
[tex]0=a(5-2)^2-1[/tex]
[tex]1=9a[/tex]
[tex]\dfrac{1}{9}=a[/tex]
It means coefficient of the squared term is 1/9, which is not the option. So, parabola must be along the x-axis.
The vertex form of a parabola along x-axis is
[tex]x=a(y-k)^2+h[/tex]
where, (h,k) is vertex and, a is constant and it is equal to coefficient of the squared term in the parabola's equation.
The vertex of the parabola is (2,-1). So, h=2 and k=-1.
[tex]x=a(y+1)^2+2[/tex]
The graph passes through (5,0). So,
[tex]5=a(0+1)^2+2[/tex]
[tex]5-2=a[/tex]
[tex]3=a[/tex]
It means coefficient of the squared term is 3.
Therefore, the correct option is D.
Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0.-4).
Oy=-x?
Oy2 = -4x
Oy2 = -16%
Oyə tox?
Answer:
[tex]x^2 = -16y[/tex]
Step-by-step explanation:
Given
[tex]Vertex = (0,0)\\Focus = (0,-4)[/tex]
Required
Equation of the parabola (in standard form)
The standard form of a parabola is [tex](x - h)^2 = 4p (y - k),[/tex]
Such that
Vertex = (h,k)
Focus = (h, k + p)
For the vertex
This implies that (h,k) = (0,0)
h = 0 and k = 0
For the focus
This implies that (h, k + p) = (0, -4)
[tex]h = 0\\k + p = -4[/tex]
Recall that [tex]k = 0;[/tex]
Hence, [tex]0 + p = -4[/tex]
[tex]p = -4[/tex]
Substitute [tex]p = -4[/tex], [tex]h = 0\ and\ k = 0[/tex] in the given formula
[tex](x - h)^2 = 4p (y - k),[/tex] becomes
[tex](x - 0)^2 = 4 * -4 (y - 0),[/tex]
[tex](x)^2 = 4 * -4 (y),[/tex]
[tex]x^2 = -16 (y),[/tex]
[tex]x^2 = -16y[/tex]
Hence,, the standard form is [tex]x^2 = -16y[/tex]
jessica put 4 tables together for the Pie day sale. Each table is 42 inches long. What is the total length of the tables expressed in feet and inches
Answer:
14 feet OR 168 inches
Step-by-step explanation:
4 tables multiplied by 42 inches equals 168 inches total
168 inches divided by 12 inches per feet equals 14 feet.
A water tank is leaking such that for each of the next 5 hours, the amount of water in the tank will be 2 gallons less than at the end of the previous hour. What type of relationship most appropriately models this situation? A. linear increase B. exponential growth C. linear decrease D. exponential decay
Answer:
C. Linear decrease
Step-by-step explanation:
I can't really show a graph but I will try to explain
The water is leaking at a constant rate, meaning its not regaining it water (its only leaking). So if u were to graph this it would be a linear decrease
( That was a Terrible explanation but the answer is right lol)
Find the missing number in the pattern! PLEASE HELP The half-life of caffeine is 5 hours; this means that approximately 1/2 of the caffeine in the bloodstream is eliminated every 5 hours. Suppose you drink a 16-ounce drink that contains 80 mg of caffeine. Suppose the caffeine in your bloodstream peaks at 80 mg. 1. How much caffeine will remain in your bloodstream after 5 hours? 10 hours? 1 hour? 2 hours? Record your answers in the table
Answer:
After five hours, there will be 40 mg of caffeine remaining in the blood.
After 10 hours, 20 mg.
After only one hour, about 69.64 mg.
And after two hours, about 60.63 mg.
Step-by-step explanation:
We are given that one-half of the caffeine in the bloodstream is eliminated every five hours.
We are also given that the initial amount is 80 mg.
Using this information, we can write the following function:
[tex]\displaystyle f(x)=80\left(\frac{1}{2}\right)^{\dfrac{x}{5} }[/tex]
Where x is the number of hours that has passed.
Using this function, we can evaluate for f(5), f(10), f(1), and f(2).
They evaluate to:
[tex]f(5)=40[/tex] [tex]f(10)=20[/tex] [tex]f(1)\approx 69.6440[/tex] [tex]f(2) \approx 60.6287[/tex]
So, after five hours, there are 40 mg of caffeine remaining in the blood.
After 10 hours, 20 mg of caffeine.
After only one hour, about 69.64 mg.
And after two hours, about 60.63 mg.
The segments shown below could form a triangle
O A. True
O B. False
Answer:
Which value of a in the exponential function below would cause the function to stretch?
(one-third) Superscript x
0.3
0.9
1.0
1.5
Step-by-step explanation:
Answer:
This can form a triangle
Step-by-step explanation:
Taking the two smaller segments
The larger segment must be greater than the sum of the two smaller
6+5 > 8
11>8 true
The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as L = 10 log StartFraction I Over I 0 EndFraction, where I 0 = 10 Superscript negative 12 and is the least intense sound a human ear can hear. What is the approximate loudness of a rock concert with a sound intensity of 10–1?
a. 2Db
b.22Db
c. 60Db
d. 110Db
Answer:
D. 110Db
Step-by-step explanation:
Db = 10log (10^-1 / 10 ^-12)
Db = 10log(10^11)
Db = 110
(even without calculating, we could guess that it was 110Db. 70 Db is about the normal talking Db, and rock concerts are generally a lot louder than regular talking)
Answer:
D. 110Db
Step-by-step explanation:
Select the three expressions that are equivalent to 6^{2}6 2 6, squared. a: (6^9/6^8)^2 b: 6 times 6 times 6 times 6 times 6 times 6 times 6 / 6 times 6 times 6 c: 6^4/6^2 d: 6^5 times 6^7/6^10
Question:
Select the three expressions that are equivalent to [tex]6^2[/tex]:
a: [tex](\frac{6^9}{6^8})^2[/tex]
b: [tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }[/tex]
c: [tex]\frac{6^4}{6^2}[/tex]
d: [tex]\frac{6^5 * 6^7}{6^{10}}[/tex]
Answer:
a: [tex](\frac{6^9}{6^8})^2[/tex]
c: [tex]\frac{6^4}{6^2}[/tex]
d: [tex]\frac{6^5 * 6^7}{6^{10}}[/tex]
Step-by-step explanation:
Given
[tex]6^2[/tex]:
Required
Find equivalent expressions
To solve this question; we'll simplify options a to do, one after the other
a: [tex](\frac{6^9}{6^8})^2[/tex]
From laws of indices;
[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]
This implies that;
[tex](\frac{6^9}{6^8})^2 = (6^{9-8})^2[/tex]
[tex](\frac{6^9}{6^8})^2 = (6^{1})^2[/tex]
From laws of indices;
[tex]{a^m}^n = a^{m*n} = a^{mn}[/tex]
This implies that
[tex](\frac{6^9}{6^8})^2 = (6^{1*2})[/tex]
[tex](\frac{6^9}{6^8})^2 = 6^{2}[/tex]
Hence, [tex](\frac{6^9}{6^8})^2[/tex] is equivalent to [tex]6^2[/tex]
b. [tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }[/tex]
From laws of indices;
[tex]a^m * a^n = a^{m+n}[/tex]
This implies that
[tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = \frac{6^{1+1+1+1+1+1}}{6^{1+1+1}}[/tex]
[tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = \frac{6^{6}}{6^{3}}[/tex]
From laws of indices;
[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]
This implies that
[tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = 6^{6-3}[/tex]
[tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = 6^{3}[/tex]
Hence; [tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }[/tex] is not equivalent to [tex]6^2[/tex]
c. [tex]\frac{6^4}{6^2}[/tex]
From laws of indices;
[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]
This implies that
[tex]\frac{6^4}{6^2} = 6^{4-2}[/tex]
[tex]\frac{6^4}{6^2} = 6^{2}[/tex]
Hence, [tex]\frac{6^4}{6^2}[/tex] is equivalent to [tex]6^2[/tex]
d. [tex]\frac{6^5 * 6^7}{6^{10}}[/tex]
From laws of indices;
[tex]a^m * a^n = a^{m+n}[/tex]
This implies that
[tex]\frac{6^5 * 6^7}{6^{10}} = \frac{6^{5+7}}{6^{10}}[/tex]
From laws of indices;
[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]
This implies that
[tex]\frac{6^5 * 6^7}{6^{10}} = 6^{5+7-10}[/tex]
[tex]\frac{6^5 * 6^7}{6^{10}} = 6^{2}[/tex]
Hence, [tex]\frac{6^5 * 6^7}{6^{10}}[/tex] is equivalent to [tex]6^2[/tex]
The composite figure is made up of a triangle, a square and a trapezoid find the area
===============================================
Work Shown:
P = area of triangle
P = 0.5*base*height
P = 0.5*5*4
P = 10 square units
----------------
Q = area of square
Q = side*side
Q = 5*5
Q = 25 square units
----------------
R = area of trapezoid
R = height*(base1+base2)/2
R = 5*(7+5)/2
R = 5*12/2
R = 60/2
R = 30
----------------
T = total area of the entire figure
T = P+Q+R
T = 10+25+30
T = 65 square units
Answer: 71 sq. units
Step-by-step explanation:
formula: 1/2bh + lw + 1/2h(b1+b2)
1/2(20) + (25) + 1/2 (6) (12)
10 + 25 + (3) (12)
10+ 25 + 36 = 71
Which formula is used to calculate the standard deviation of sample data?
2.
X, - x
+ X2-X
+ ... + X-X
(1928)
s=1
n-1
(x1 - x)2 + (x2-x) +...+(XN-)?
2
11
N
w
(x1 - x)+ (x2-x)2 +...+(x+4) ?
N
2
Xq- x
-3)
+ X2-X
+
+ X
S=
n-1
Answer:
The first option from the picture
Step-by-step explanation:
In the picture attached, the question is shown.
In the first option:
s is the standard deviation[tex] x_1, x_2, \dots, x_n [/tex] are the members of the sample[tex] \bar{x} [/tex] is the sample meann is the number of members in the sampleThe formula for calculating the standard deviation of sample data is expressed as [tex]\sigma=\sqrt{\frac{\sum(x_1-\overline x)^2+(x_2-\overline x)^2+...(x_n-\overline x)^2)}{N} }[/tex]
What is a standard deviation?The standard deviation is a measure of the amount of variation or dispersion of a set of values.
A lower value of the standard deviation shows that value is close to the mean otherwise it is far from the mean
The formula for calculating the standard deviation of sample data is expressed as:
[tex]\sigma=\sqrt{\frac{\sum(x_1-\overline x)^2}{N} }[/tex]
Assume we have the following data x1, x2, ....xn, the standard deviation will be given as:
[tex]\sigma=\sqrt{\frac{\sum(x_1-\overline x)^2+(x_2-\overline x)^2+...(x_n-\overline x)^2)}{N} }[/tex]
Learn more on standard deviation here: https://brainly.com/question/475676
Which scatterplot correctly represents the table of values below? Number of years collecting stamps Number of stamps in collection 2 100 5 175 4 150 3 125 4 175 3 100 A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 125), (4, 150), (4, 175), (5, 200). A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 150), (4, 150), (4, 175), and (5, 175). A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 125), (4, 150), (4, 175), (5, 175). A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 75), (3, 100), (3, 125), (4, 150), (4, 175), and (5, 175).
Answer:
C. A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 125), (4, 150), (4, 175), (5, 175)
Step-by-step explanation:
In the x-axis goes the values from the column 'Number of years collecting stamps' of the table. And In the y-axis goes the values from the column 'Number of stamps in collection' of the table.
To make the graph identify each pair of values in the plane and mark it.
Answer:
c
Step-by-step explanation:
its corect on edge
Given:
MNOP is a parallelogram
Prove:
PM ON
(For this proof, use only the definition of a parallelogram; don’t use any properties)
Answer:
[tex]\overline{PM}\cong\overline{ON}[/tex]:, Segment subtended by the same angle on two adjacent parallel lines are congruent
Step-by-step explanation:
Statement, Reason
MNOP is a parallelogram:, Given
[tex]\overline{PM}\left | \right |\overline{ON}[/tex]:, Opposite sides of a parallelogram
∠PMO ≅ ∠MON:, Alternate Int. ∠s Thm.
[tex]\overline{MN}\left | \right |\overline{PO}[/tex]:, Opposite sides of a parallelogram
∠POM ≅ ∠NMO:, Alternate Int. ∠s Thm.
OM ≅ OM:, Reflexive property
[tex]\overline{PM}\cong\overline{ON}[/tex]:, Segment subtended by the same angle and on two adjacent parallel lines are congruent
A sequence is defined by the recursive function f(n+1)= f(n) -2. If f(1) =10. what is f(3)?
Answer:
f(3) is 30
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
using soh cah toa find length of PN and round answer to nearest tenth of a foot?
Answer:
About 2.6 feet
Step-by-step explanation:
The tangent of an angle in a right triangle is the length of the opposite side divided by the length of the adjacent side. Therefore:
[tex]\tan 17= \dfrac{x}{8.6} \\\\x=\tan 17 \cdot 8.6\approx 2.6[/tex]
Hope this helps!
Help please For the following function, construct a table.
Answer:
See the attachment below.
Step-by-step explanation:
Best Regards!
simplify 10+4(−8q−4)
Answer:
10 + 4(-8q - 4)
= 10 + 4 * (-8q) + 4 * (-4) (Distribute 4)
= 10 - 32q - 16 (Expand)
= -32q - 6 (Combine like terms)
Answer:
[tex]-32q-6[/tex]
Step-by-step explanation:
[tex]10+4(-8q-4)[/tex]
[tex]10+4(-8q)+4(-4)[/tex]
[tex]10+-32q+-16[/tex]
[tex]-32q+-16+10[/tex]
[tex]-32q+-6[/tex]
Which relationships have the same constant of proportionality between y and x as in the equation y=1/2x Choose 3 answers:
This is from Khan academy. I'm stuck on it
Answer:
A and B has the same constant of proportionality
Step-by-step explanation:
[tex]y \propto x[/tex]
[tex]y = kx ----1[/tex]
Where k is the constant of proportionality
We are supposed to find Which relationships have the same constant of proportionality between y and x as in the equation [tex]y=\frac{1}{2}x[/tex]
On comparing with 1
[tex]k = \frac{1}{2}[/tex]
A)6y = 3x
[tex]y = \frac{3}{6}x\\y = \frac{1}{2}x[/tex]
So, this equation has the same constant of proportionality
B)[tex](x_1,y_1)=(2,1)\\(x_2,y_2)=(4,2)[/tex]
To find the equation :
Formula : [tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
So, [tex]y - 1=\frac{2-1}{4-2}(x-2)\\y-1=\frac{1}{2}(x-2)\\y-1=\frac{1}{2}x-1\\y=\frac{1}{2}x[/tex]
So, this equation has the same constant of proportionality
C)
[tex](x_1,y_1)=(1,2)\\(x_2,y_2)=(2,4)[/tex]
To find the equation :
Formula : [tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
So, [tex]y - 2=\frac{4-2}{2-1}(x-1)\\y - 2=2(x-1)\\y - 2=2x-2\\y=2x[/tex]
So, this equation do not has the same constant of proportionality
D)
[tex](x_1,y_1)=(2,1)\\(x_2,y_2)=(3,2.5)[/tex]
To find the equation :
Formula :[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
So, [tex]y - 1=\frac{2.5-1}{3-2}(x-2)[/tex]
[tex]y-1=1.5(x-2)\\y-1=1.5x-3\\y=1.5x-2[/tex]
So, this equation do not has the same constant of proportionality
Hence A and B has the same constant of proportionality
Options A and B has the same constant of proportionality.
What is Slope of Line?The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.
The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.
The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is
m=y₂-y₁/x₂-x₁
For option A,
6y=3x
y=3/6x
y=1/2x
This equation has the same constant of proportionality
For Option B
(2,1) and (4,2)
m=2-1/4-2=1/2
We have equation as y-y₁=m(x-x₁)
y-1=1/2(x-2)
y-1=1/2x-1
y=1/2x
this equation has the same constant of proportionality
For option C
(1,2) and (2,4)
m=4-2/2-1=2
We have equation as y-y₁=m(x-x₁)
y-2=2(x-1)
y-2=2x-2
y=2x
Equation do not has the same constant of proportionality
and option D does not have same constant of proportionality
Hence options A and B has the same constant of proportionality.
To learn more on slope of line click:
https://brainly.com/question/14511992
#SPJ2
Need help if you can, help please help
Answer:
4.4 km/h
Step-by-step explanation:
From the graph you can see she was at the shop after 30 minutes. If you travel 2.2 km in 30 minutes, your speed is 2.2 / 0.5 = 4.4 km/h
So the trick is to express the 30 minutes as 1/2 hour.
Answer:
4.4 km/h
Step-by-step explanation:
Find the total current drawn by the following appliances by adding the currents of
each appliance. Electric iron: 4.12 amps, clock: 0.02 amps, light bulb: 0.91 amps, and a
workshop motor: 1 amp.
Answer:
The total current drawn is 6.05 amps
Step-by-step explanation:
Simply add the current that each appliance draws, to get the total current required. Notice that they are all given in the same units (amps), so there is no units conversion needed:
Electric iron : 4.12 amps
Clock; 0.02 amps
light bulb : 0.91 amps
motor : 1 amp
Total current : 4.12 amps + 0.02 amps + 0.91 amps + 1 amp = 6.05 amps
graph of a cubic polynomial that falls to the left and rises to the right with x intercepts negative 3, negative 2, and 2 Which of the following functions best represents the graph? f(x) = (x − 2)(x − 3)(x + 2) f(x) = (x + 2)(x + 3)(x + 12) f(x) = (x + 2)(x + 3)(x − 2) f(x) = (x − 2)(x − 3)(x − 12)
Answer:
i would say f(x) = (x-2)(x-3)(x+2) but i could be wrong its a confusing question the way it's worded
Step-by-step explanation:
Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a
sample of size 131 with 81% successes. Enter your answer as a tri-linear inequality using decimals (not
percents) accurate to three decimal places.
apa
> Next Question
Answer:
[tex]0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730[/tex]
[tex]0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890[/tex]
And the confidence interval would be:
[tex] 0.730 \leq \p \leq 0.890[/tex]
Step-by-step explanation:
Information given:
[tex] n=131[/tex] represent the sample size
[tex] \hat p=0.81[/tex] represent the estimated proportion
The confidence interval would be given by this formula
[tex]\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]
For the 98% confidence interval the value of [tex]\alpha=1-0.98=0.02[/tex] and [tex]\alpha/2=0.01[/tex], with that value we can find the quantile required for the interval in the normal standard distribution.
[tex]z_{\alpha/2}=2.326[/tex]
And replacing into the confidence interval formula we got:
[tex]0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730[/tex]
[tex]0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890[/tex]
And the confidence interval would be:
[tex] 0.730 \leq \p \leq 0.890[/tex]
whats the answer???
Answer:The answer is C 20 cm^3
Step-by-step explanation:
You just multiply 2 by 2 and get 4 and you have 5 squares and you get 4 times 5 which is 20 cm^3
Answer:
Divide the figure into 5 squares.
then find the area 1 square and multiply with 5.
Area of square=s*s
=4 cm²
Then 5*4=20 cm²
so c is the correct option.
HOPE IT HELPS!
If y varies directly as x, and y is 6 when x is 72, what is the value of y when x is 8?
1/9
2/3
54
96
Answer:
Y=2/3
Step-by-step explanation:
Y varies directly as X
Y=k x
K is a constant
6=k72
K=1/12
Y=1/12x
Y=1/12×8
y=2/3
If anyone is good at math can you help me pls :/
Answer:
C
Step-by-step explanation:
An apothem is a line segment connecting the center of a regular polygon to the midpoint of its vertex.