Answer:
That depends.
Explanation:
We can measure force as mass*accelerations for physics
A solid is dissolved in a liquid, and over time a solid forms again. How can
you confirm the type of change that took place?
A. Testing the new solid to show that its properties are the same as
the starting solid would confirm that a physical change took
place.
B. The solid dissolving in a liquid is confirmation that a chemical
change took place.
C. The solid forming from the liquid is confirmation that a physical
change took place.
D. Showing that the total mass of the solid and liquid changed would
confirm that a chemical change took place.
an auto of an element has 17 protons in its nucleus.a) write the electronic configuration of the atom.b)to what period and group does the element belong
Answer:
i hope it will help you
Explanation:
electronic configuration 1s²,2s,²2p^6,3s²3p^6,4s^1
as it has one electron in its valence shell so it is the member of group 1A(ALKALI METALS) and the number of shells is 4 so it is in period 4
The number of atoms or molecules whose concentration determine the rate of a reaction is called
Consider the following chemical reaction: 2H2O(l)→2H2(g)+O2(g) What mass of H2O is required to form 1.3 L of O2 at a temperature of 325 K and a pressure of 0.991 atm ? Express your answer using two significant figures.
Answer:
1.73g of H2O
Explanation:
The following data were obtained from the question:
Volume (V) of O2 = 1.3L
Temperature (T) = 325 K
Pressure (P) = 0.991 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Next, we shall determine the number of mole (n) of O2 produced from the reaction. This can be obtained by using the ideal gas equation as shown below:
PV = nRT
0.991 x 1.3 = n x 0.0821 x 325
Divide both side by 0.0821 x 325
n = (0.991 x 1.3) /(0.0821 x 325)
n = 0.048 mole
Therefore, 0.048 mole of O2 was produced from the reaction.
Next, we shall determine the number of mole H2O that produce 0.048 mole of O2. This is illustrated below:
2H2O(l) → 2H2(g) + O2(g)
From the balanced equation above,
2 moles of H2O produced 1 mole of O2.
Therefore, Xmol of H2O will produce 0.048 mole of O2 i.e
Xmol of H2O = (2 x 0.048)/1
Xmol of H2O = 0.096 mole
Therefore, 0.096 mole of H2O was used in the reaction.
Finally, we shall convert 0.096 mole of H2O to grams. This is illustrated below:
Molar mass of H2O = (2x1) + 16 = 18g/mol
Number of mole H2O = 0.096 mole
Mass of H2O =..?
Mole = mass /molar mass
0.096 = mass /18
Cross multiply
Mass = 0.096 x 18
Mass of H2O = 1.73g
Therefore, 1.73g of H2O is required for the reaction.
Substances like krypton, which is a gas at room temperature and pressure, can often be liquified or solidified only at very low temperatures. At a pressure of 1 atm, does not condense to a liquid until –153.2°C and does not freeze until –157.1°C. What are the equivalent absolute temperatures?
Answer:
The boiling and freezing temperatures of krypton at absolute scale are 119.95 K and 116.05 K, respectively.
Explanation:
The absolute temperature on SI units corresponds to Kelvin scale, whose conversion formula in terms of the Celsius scale is:
[tex]T_{K} = T_{C} + 273.15[/tex]
Where:
[tex]T_{K}[/tex] - Absolute temperature, measured in Kelvins.
[tex]T_{C}[/tex] - Relative temperature, measured in Celsius.
Finally, freezing and boiling temperatures are converted into absolute scale:
Boiling temperature
[tex]T_{K} = (-153.2 + 273.15)\,K[/tex]
[tex]T_{K} = 119.95\,K[/tex]
Freezing temperature
[tex]T_{K} = (-157.1 + 273.15)\,K[/tex]
[tex]T_{K} = 116.05\,K[/tex]
The boiling and freezing temperatures of krypton at absolute scale are 119.95 K and 116.05 K, respectively.
The reason for the dramatic decline in the number of measles cases from the 1960s to 2010 in the United States was because the vaccine
Answer:
It was because the vaccine generated actively acquired immunity, that is, inoculation of a portion of the measles virus so that the body forms the antibodies for a second contact and thus can destroy it without triggering the pathology.
Explanation:
Vaccines are methods of active acquired immunity since the antibody is not passively inoculated, it is manufactured by the body with a physiological process once part of the virus is inoculated.
The measles virus most of all affected the lives of infants or newborn children with severe rashes and high fevers that led to death.
non-luminous flame is yellow.Explain
Answer:
It contains unburnt carbon particles of hot glowing solid carbon that gives out light
The amount of calcium in a 15.0-g sample was determined by converting the calcium to calcium oxalate, CaC2O4. The CaC2O4 weighed 40.3 g. What is the percent of calcium in the original sample
Answer:
128 gram of CaC2O4 contains 40 gram of Calcium
40.3 gram of CaC2O4 cotnains = 40*40.3/128 = 12.59 gram of Calcium
out of 15 gram 12.59 gram is Calcaim that means around 50% of orginal sample has Calcium
The lock-and-key model and the induced-fit model are two models of enzyme action explaining both the specificity and the catalytic activity of enzymes. Following are several statements concerning enzyme and substrate interaction. Indicate whether each statement is part of the lock-and-key model, the induced-fit model, or is common to both models.
a. Enzyme conformation changes when it binds the substrate so the active site fits the substrate.
b. Substrate binds to the enzyme at the active site, forming an enzyme-substrate complex.
c. Enzyme active site has a rigid structure complementary
d. Substrate binds to the enzyme through noncovalent interactions
Answer:
The lock-and-key model:
c. Enzyme active site has a rigid structure complementary
The induced-fit model:
a. Enzyme conformation changes when it binds the substrate so the active site fits the substrate.
Common to both The lock-and-key model and The induced-fit model:
b. Substrate binds to the enzyme at the active site, forming an enzyme-substrate complex.
d. Substrate binds to the enzyme through non-covalent interactions
Explanation:
Generally, the catalytic power of enzymes are due to transient covalent bonds formed between an enzyme's catalytic functional group and a substrate as well as non-covalent interactions between substrate and enzyme which lowers the activation energy of the reaction. This applies to both the lock-and-key model as well as induced-fit mode of enzyme catalysis.
The lock and key model of enzyme catalysis and specificity proposes that enzymes are structurally complementary to their substrates such that they fit like a lock and key. This complementary nature of the enzyme and its substrates ensures that only a substrate that is complementary to the enzyme's active site can bind to it for catalysis to proceed. this is known as the specificity of an enzyme to a particular substrate.
The induced-fit mode proposes that binding of substrate to the active site of an enzyme induces conformational changes in the enzyme which better positions various functional groups on the enzyme into the proper position to catalyse the reaction.
In the presence of a strong base, the following reaction between (CH3)3CCl and OH- occurs: (CH3)3CCl + OH- → (CH3)3COH + Cl- Studies have suggested that the mechanism for the reaction takes place in 2 steps: Step 1) (CH3)3CCl → (CH3)3C+ + Cl- (slow) Step 2) (CH3)3C+ + OH- → (CH3)3COH (fast) What is the rate law expression for the overall reaction? Group of answer choices
Answer:
D. rate = k [(CH3)3CCl]
Explanation:
(CH3)3CCl + OH- → (CH3)3COH + Cl-
The mechanisms are;
Step 1)
(CH3)3CCl → (CH3)3C+ + Cl- (slow)
Step 2)
(CH3)3C+ + OH- → (CH3)3COH (fast)
In kinetics, the slowest step is the ratee determining step.
For a given reaction;
A → B + C, the rate law expression is given as;
rate = k [A]
In this problem, from step 1. The rate expression is;
rate = k [(CH3)3CCl]
Dissolving NaOH (s) in water is exothermic. Two calorimetry experiments are set up.
Exp 1: 2 g of NaOH are dissolved in 100 mL of water
Exp 2: 4 g of NaoH are dissolved in 200 mL of water.
Which of the following is true?
A. both temperature changes will be the same
B. the second temeprature change will be approximately twice the first
C. the second temperature change will be approximately four times the first
D. the second temperature change will be approximately one-half of the first
E. the second temperature change will be approximately one-fourth the first
Answer:
Option-E
Explanation:
In the given question, the experiment was set up with 2 reactions in which reaction two has double the amount of reactants.
To calculate the heat released in experiments, the formula used will be
ΔH = mcΔT, where m= mass of
1. For reaction 1,
ΔH₁ = m₁c₁ΔT₁
2. For reaction 2,
ΔH₂ = m₂c₂ΔT₂
here, the concentration of each solute is the same but the amount is different. Reaction two has double the amount compared to the first reaction.
we compare ΔH₁ = 2 ΔH₂
m₁c₁ΔT₁= m₂c₂ΔT₂
here since concentration is the same, therefore cancelled out
m₁ΔT₁ = 2 m₂ΔT₂
m₁/2 x m₂ xΔT₁ = ΔT₂
100 / 2 x 200 ΔT₁
= 100/400 ΔT₁
= 1/4 ΔT₁= ΔT₂.
This shows that the second temperature change is 1/4 of the first.
Thus, Option-E is the correct answer.
A friend asks you to help them decide which crackers are healthier. Comparing approximately equal serving sizes of 1 cracker (approx. 4.5 g Breton serving size vs. 4.7 g Triscuit), which would be a better choice with regards to calories, fat and sodium content?
a. Breton
b. Triscsuit
Answer:
The correct option is "Triscsuit"
Explanation:
In my opinion the correct option is tricsuit, because it has 0% saturated fat and TRANS fat, which is healthy fats since these fats are the worst for our body.
They also contain sodium but their levels are not high enough to trigger hypertension.
Cl2 + F2 → ClF3, 5. How many moles of Cl2 are needed to react with 3.44 moles of F2? 6. How many grams of ClF3 form when 0.204 moles of F2 react with excess Cl2? 7. How many grams of ClF3 form from 130.0 grams of Cl2 when F2 is in excess? 8. How many grams of F2 are needed to react with 3.50 grams of Cl2?
Answer:
5) 1.147 moles Cl2
6) 12.57 grams ClF3
7) 339.10 grams ClF3
8) 5.63 grams F2
Explanation:
Step 1: Data given
Number of moles F2 = 3.44 moles
Molar mass F2 = 38.00 g/mol
Step 2: The balanced equation
Cl2 + 3F2 → 2ClF3
Step 3: Calculate moles F2
For 1 mol Cl2 we need 3 moles F2 to produce 2 moles ClF3
For 3.44 moles F2 we'll need 3.44/3 = 1.147 moles Cl2
Step 1: Data given
Number of moles F2 = 0.204 moles
Molar mass F2 = 38.00 g/mol
Molar mass ClF3 = 92.448 g/mol
Step 2: The balanced equation
Cl2 + 3F2 → 2ClF3
Step 3: Calculate moles ClF3
For 1 mol Cl2 we need 3 moles F2 to produce 2 moles ClF3
For 0.204 moles F2 we'll have 2/3 * 0.204 = 0.136 moles
Step 4: Calculate mass ClF3
Mass ClF3 = Moles ClF3 * molar mass ClF3
Mass ClF3 = 0.136 moles * 92.448 g/mol
Mass ClF3 = 12.57 grams ClF3
Step 1: Data given
Mass of Cl2 = 130.0 grams
Molar mass F2 = 38.00 g/mol
Molar mass ClF3 = 92.448 g/mol
Step 2: The balanced equation
Cl2 + 3F2 → 2ClF3
Step 3: Calculate moles Cl2
Moles Cl2 = mass Cl2 / molar mass Cl2
Moles Cl2 = 130.0 grams / 70.9 g/mol
Moles Cl2 = 1.834 moles
Step 4: Calculate moles
For 1 mol Cl2 we need 3 moles F2 to produce 2 moles ClF3
For 1.834 moles Cl2 e'll have 2*1.834 = 3.668 moles ClF3
Step 5: Calculate mass ClF3
Mass ClF3 = Moles ClF3 * molar mass ClF3
Mass ClF3 = 3.668 moles * 92.448 g/mol
Mass ClF3 = 339.10 grams ClF3
Step 1: Data given
Mass of Cl2 = 3.50 grams
Molar mass F2 = 38.00 g/mol
Molar mass ClF3 = 92.448 g/mol
Step 2: The balanced equation
Cl2 + 3F2 → 2ClF3
Step 3: Calculate moles Cl2
Moles Cl2 = Mass Cl2 / molar mass Cl2
Moles Cl2 = 3.50 grams / 70.9 g/mol
Moles Cl2 = 0.0494 moles
Step 4: Calculate moles F2
For 1 mol Cl2 we need 3 moles F2
For 0.0494 moles we need 3*0.0494 = 0.1482 moles
Step 5: Calculate mass F2
Mass F2 = moles F2 * molar mass F2
Mass F2 = 0.1482 moles * 38.00 g/mol
Mass F2 = 5.63 grams F2
What is the coefficient for oxygen in the balanced equation? C 5H 12 + ? O2 → ? CO2 + ? H2O. 2 4 5 6 8
Answer:
8
Explanation:
When you balance the entire equation, you should get:
C5H12 + 8O2 ---> 5CO2 + 6H2O
When an automobile engine starts, the metal parts immediately begin to absorb heat released during the combustion of gasoline. How much heat will be absorbed by a 165 kg iron engine block as the temperature rises from 15.7°C to 95.7°C? (The specific heat of iron is 0.489 J/g·°C.)
Answer:
H = 4,034,250 J
Explanation:
Mass, m = 165kg = 165,000g (Converting to grams)
Initial temperature = 15.7°C
Final temperature = 95.7°C
Temperature change, ΔT = 95.7 - 15.7 = 50°C
Specific heat capacity, c = 0.489 J/g·°C
Heat = ?
All the parameters are related with the equation below;
H = m * c * ΔT
H = 165000 * 0.489 * 50
H = 4,034,250 J
1.the particles in a_are packed very closely together. 2.the_in a liquid are loosely together. they can flow. 3.in a gas the_between the particles are bigger. if u re genius then answer this question class 4
Answer:
1. Solid
2. Particles.
3. Space.
Explanation:
1. The particles in a solid are packed very closely together. This is the most reason why solid particles have definite shapes of volume. This closeness is as a result of strong intermolecular forces force that exist between the particles. Hence, they can not flow but only vibrates about their mean position. Solids can not be compressed because of the strong intermolecular forces between their particles.
2. The particles of liquid are loosely together. In liquid, the particles are loosely packed and free to move about to certain degree. This is so because the intermolecular force between the particles are not as strong as those within the solid particles. Hence liquid has no definite shape but they have definite volume. They only assume the shape of the container they are poured into. Liquid can no be compressed..
3. In a gas, the space between the particles are bigger. This is so because the intermolecular forces between the particles are negligible i.e very small and so, the gas particles are free to move about and only restricted by the wall of the container they poured into. This negligible intermolecular forces are the reason why gas has no definite shapes and no volume. They can be compressed to fill a particular container.
A 54.0 mL aliquot of a 1.60 M solution is diluted to a total volume of 218 mL. A 109 mL portion of that solution is diluted by adding 161 mL of water. What is the final concentration? Assume the volumes are additive g
Answer: The final concentration is 0.16 M.
Explanation:
According to the dilution law:
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of stock solution = 1.60 M
[tex]V_1[/tex] = volume of stock solution = 54.0 ml
[tex]M_2[/tex] = molarity of diluted solution = ?
[tex]V_2[/tex] = volume of diluted solution = 218 ml
Putting these values:
[tex]1.60\times 54.0=M_2\times 218[/tex]
[tex]M_2=0.40M[/tex]
Now 109 ml of this diluted solution is further diluted by adding 161 mL of water.
Again applying dilution law:
[tex]0.40\times 109=M_3\times (109+161)[/tex]
[tex]0.40\times 109=M_3\times 270[/tex]
[tex]M_3=0.16M[/tex]
Thus the final concentration is 0.16 M
. A 0.100 M solution of the weak acid HA was titrated with 0.100 M NaOH. The pH measured when Vb = ½Ve was 4.62. Using activity coefficients, calculate pKa. The size of the A- anion is 450 pm.
Answer:
[tex]pk_a = 4.69[/tex]
Explanation:
[tex]V_b = \frac{1}{2} V_e[/tex]
[tex]pk_a(c) = 4.62\\pk_a(c) = - logk_a(c)\\4.62 = - logk_a(c)\\k_a(c) = antilog (-4.62)\\k_a(c) = 2.4 * 10^{-65}[/tex]
Activity coefficients:
[tex]f_A = 0.854\\f_H = 1.00\\f_{HA} = 1.00[/tex]
[tex]k_a = k_a(c) *f_A* \frac{f_H}{f_{HA}} \\k_a = 2.4 * 10^{-5} *0.854* \frac{1.0}{1.0}\\k_a = 2.05 * 10^{-5}[/tex]
[tex]pk_a = -log(k_a)\\pk_a = -log(2.05*10^{-5})\\pk_a = 4.69[/tex]
In an open system, the vapor _____ is equal to the outside air pressure.
Answer:
Pressure
Explanation:
In an open system, the vapor pressure is equal to the outside air pressure.
Three elements have the electron configurations 1s2 2s2 2p6 3s2 3p6, 1s2 2s2 2p6 3s2, and
1s2 2s2 2p6 3s2 3p6 4s1. The first ionization energies of the three elements (not in the same order) are 0.4189, 0.7377, and 1.505 MJ/mol. The atomic radii are 1.60, 0.94, and 2.35 .Identify the three elements and match the appropriate values of ionization energy and atomic radius to each configuration.
Explanation:
First element
1s2 2s2 2p6 3s2 3p6
Atomic Number = 18
Element = Argon
Second Element
1s2 2s2 2p6 3s2
Atomic Number = 12
Element = Magnesium
Second Element
1s2 2s2 2p6 3s2 3p6 4s1
Atomic Number = 19
Element = Potassium
In the periodic table;
The general trend is for ionization energy to increase moving from left to right across an element period. It would decrease down the group.
Both Argon and Magnesium are on the same period. Potassium is o the period below.
This leads us to;
Magnesium - 0.7377 MJ/mol
Argon - 1.505 MJ/mol
Potassium - 0.4189 MJ/mol
The atomic radius of atoms generally decreases from left to right across a period. It would increase down the group.
This leads to;
Magnesium - 1.60
Argon - 0.94
Potassium - 2.35
Arrange the following elements in order of decreasing atomic radius: Ba, Sn, S, Pb, and As. Rank elements from largest to smallest.
Answer:
Ba>Sn>Pb>As>S
Explanation:
Hello,
In this case, we can write the atomic radius for the given elements:
[tex]r_{Ba}=268pm\\r_{Sn}=225pm\\r_{S}=100pm\\r_{Pb}=202pm\\r_{As}=185pm[/tex]
In such a way, the required order is:
Ba>Sn>Pb>As>S
This is also in agreement as a periodic trend which states that the higher the period, the higher the radius.
Regards.
When 18.0 mL of a 8.43×10-4 M cobalt(II) fluoride solution is combined with 22.0 mL of a 9.72×10-4 M sodium hydroxide solution does a precipitate form? no (yes or no) For these conditions the Reaction Quotient, Q, is equal to .
Answer:
Q = 1.08x10⁻¹⁰
Yes, precipitate is formed.
Explanation:
The reaction of CoF₂ with NaOH is:
CoF₂(aq) + 2 NaOH(aq) ⇄ Co(OH)₂(s) + 2 NaF(aq).
The solubility product of the precipitate produced, Co(OH)₂, is:
Co(OH)₂(s) ⇄ Co²⁺(aq) + 2OH⁻(aq)
And Ksp is:
Ksp = 3x10⁻¹⁶= [Co²⁺][OH⁻]²
Molar concentration of both ions is:
[Co²⁺] = 0.018Lₓ (8.43x10⁻⁴mol / L) / (0.018 + 0.022)L = 3.79x10⁻⁴M
[OH⁻] = 0.022Lₓ (9.72x10⁻⁴mol / L) / (0.018 + 0.022)L = 5.35x10⁻⁴M
Reaction quotient under these concentrations is:
Q = [3.79x10⁻⁴M] [5.35x10⁻⁴M]²
Q = 1.08x10⁻¹⁰
As Q > Ksp, the equilibrium will shift to the left producing Co(OH)₂(s) the precipitate
El número de átomos de una molécula depende de la --- de los elementos ya que es la capacidad de la union de átomos ?
Answer:
El número de átomos de una molécula depende de la "valencia" de los elementos, ya que es la capacidad de la unión de los átomos.
Explanation:
La valencia de un elemento se define como la medida de la capacidad de combinación de un elemento. Es la capacidad de combinación de un elemento con otros elementos para formar un compuesto químico o molécula.
Básicamente es el número de electrones de valencia que un elemento puede perder, ganar o compartir para formar enlaces químicos requeridos a partir de compuestos o moléculas.
¡¡¡Espero que esto ayude!!!
English Translation
The number of atoms of a molecule depends on the "valency" of the elements since it is the capacity of the union of atoms.
The valency of an element is defined as the measure of the combining ability of an element. It is the combining capacity of an element with other elements to form a chemical compound or molecule.
It is basically the number of valence electrons that an element can lose, gain or share in order to form chemical bonds required to from compounds or molecules.
Hope this Helps!!!
The Rf value of compound A is 0.35 when TLC plate is developed in hexane and 0.45 when the plate is developed in diethyl ether. Compound B has an Rf value of 0.45 in hexane and 0.60 in diethyl ether. Hexane would be better for separating a mixture of compounds A and B by TLC. If yes then why?
Answer:
No.
Explanation:
Under TLC chromatography, the compounds are separated based on the different affinity between stationary phase and mobile phase. The higher difference between Rf's of the compounds will produce the better separation.
In Hexane compound A has a Rf of 0.35 and compound B of 0.45.
The difference is 0.45 - 0.35 = 0.10
In dietyl ether, Rf of compound A is 0.45 and for compound B is 0.60.
The difference is 0.60 - 0.45 = 0.15.
As the difference in Rf is higher for dietyl ether:
Hexane would be better for separating a mixture of compounds A and B by TLC. NO. The better separation would be using dietyhl ether.
Question 4
What is the sum of these two reactions? Write your answer below, but don't worry about formatting with subscripts-Do write chemical formulas with
proper atomic symbols, though (e.g., write CuCl2, not CUCL2).
(1) Ca + 2HCl - CaCl2 + H2
(2) CaCl2+H2O = CaO + 2HCl
Answer:
[tex]Ca +H_2O \rightarrow + H_2 + CaO[/tex]
Explanation:
Hello,
In this case, considering the given two reactions, when we add them, we obtain:
[tex]Ca + 2HCl +CaCl_2 +H_2O \rightarrow CaCl_2 + H_2 + CaO+2HCl[/tex]
Thus, we can simplify both hydrochloric acid and calcium chloride as they are both sides to obtain:
[tex]Ca +H_2O \rightarrow H_2 + CaO[/tex]
Best regards.
The element silver has an atomic weight of 108 and consists of two stable isotopes silver-107 and silver-109. The isotope silver-107 has a mass of 107 amu and a percent natural abundance of 51.8 %. The isotope silver-109 has a percent natural abundance of 48.2 %. What is the mass of silver-109
Answer:
109
Explanation:
Let silver-107 be isotope A
Let silver-109 be isotope B
Let silver-107 abundance be A%
Let silver-109 abundance be B%
The following data were obtained from the question:
Atomic weight of silver = 108
Mass of isotope A (silver-107) = 107
Abundance of isotope A (silver-107) = 51.8%
Abundance of isotope B (silver-109) = 48.2%
Mass of isotope B (silver-109) =?
Now, we shall determine the mass silver-109 as follow:
Atomic weight = [(Mass of A x A%)/100] + [(Mass of B x B%)/100]
108 = [(107 x 51.8)/100] + [(Mass of B x 48.2)/100]
108 = 55.426 + (Mass of B x 0.482)
Collect like terms
Mass of B x 0.482 = 108 – 55.426
Mass of B x 0.482 = 52.574
Divide both side by 0.482
Mass of B = 52.574/0.482
Mass of B = 109
Therefore, the mass of silver-109 is 109.
What is the daughter nucleus (nuclide) produced when Po210 undergoes alpha decay? Replace the question marks with the proper integers or symbols.
Answer:
Po - 206
Explanation:
Think about the nuclear equation for the alpha decay of Po - 210. Po - 210 has 84 protons and 126 neutrons in it's nucleus, and an alpha particle is identical to a helium - 4 nucleus, meaning it is present with 2 protons and 2 neutrons.
_______________________________________________________
Knowing that, during the alpha decay, Po - 210 will form a daughter nucleus identical to a polonium - 210 present with 4 less of it's atomic mass ( number of protons and neutrons ), and 2 less of it's atomic number ( number of protons ). Why? Because Po - 210 will split into this daughter nucleus and an alpha particle.
Po - 210 has an atomic mass of 210 and an atomic number of 84. It's daughter nucleus will have an atomic mass of 206, and an atomic number of 82, Po - 206.
Hope that helps!
The daughter nucleus (nuclide) produced when Po210 undergoes alpha decay is lead 206 decays by alpha emission to lead-206 (atomic number 82).
What is alpha decay ?The process of radioactive decay known as "alpha decay," in which an atomic nucleus produces an alpha particle and changes into a separate atomic nucleus with a mass number that is reduced by four and an atomic number that is reduced by two, is known as radioactive decay.
When a nucleus has too many protons, it becomes unstable and undergoes alpha decay. Energy and an alpha particle are released by the nucleus.
Po-210's atomic mass and atomic number both decrease by four after the emission of an alpha particle. The resulting atomic mass will be 2016, and the atomic number will be 82. This is an example of the lead isotope.
Thus, The daughter nucleus (nuclide) produced when Po210 undergoes alpha decay is lead 206.
To learn more about an alpha decay, follow the link;
https://brainly.com/question/2600896
#SPJ5
When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H2S(g) 2.10 g were obtained. What is the percent yield of the reaction?
Answer:
[tex]Y=58.15\%[/tex]
Explanation:
Hello,
For the given chemical reaction:
[tex]Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)[/tex]
We first must identify the limiting reactant by computing the reacting moles of Al2S3:
[tex]n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3[/tex]
Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:
[tex]n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol Al_2S_3[/tex]
Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:
[tex]m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3[/tex]
Finally, we compute the percent yield with the obtained 2.10 g:
[tex]Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%[/tex]
Best regards.
In which of the following reactions will Kc = Kp? a. 4 NH3(g) + 3 O2(g) ⇌ 2 N2(g) + 6 H2O(g) b. SO3(g) + NO(g) ⇌ SO2(g) + NO2(g) c. 2 N2(g) + O2(g) ⇌ 2 N2O(g) d. 2 SO2(g) + O2(g) ⇌ 2 SO3(g)
Answer:
The correct option is b) SO₃(g) + NO(g) ⇌ SO₂(g) + NO₂(g)
Explanation:
The relation between Kc and Kp is given by the following equation:
[tex]Kp = Kc (RT)^{dn}[/tex]
where R is the gas constant (0,082 L.atm/K.mol), T is the temperature (in K) and dn is the change in moles.
The change in moles (dn) is calculated as:
dn = moles of products - moles reactants
If dn=0, RT= 1 ⇒ Kc=Kp
We calculate dn for each reaction from the estequiometrial coefficients of products and reactants as follows:
a) 4 NH₃(g) + 3 O₂(g) ⇌ 2 N₂(g) + 6 H₂O(g)
dn= (2+6) - (4+3) = 1 ⇒ Kc ≠ Kp
b) SO₃(g) + NO(g) ⇌ SO₂(g) + NO₂(g)
dn = (1+1) - (1+1)= 0 ⇒ Kc = Kp
c) 2 N₂(g) + O₂(g) ⇌ 2 N₂O(g)
dn= 2 - (2+1) = -1 ⇒ Kc ≠ Kp
d) 2 SO₂(g) + O₂(g) ⇌ 2 SO₃(g)
dn = 2 - (2+1) = -1 ⇒ Kc ≠ Kp
The reaction in which Kc=Kp is b), because reactants and products have the same number of moles.
A certain lightbulb containing argon at 1.20 atm and 18°C is
heated to 85°C at constant volume. Calculate its final pressure
(in atm).
Answer:
certain lightbulb containing argon at 1.20 atm and 18 0 C is heated to 85 0 C at constant volume. What is the final pressure of argon in the lightbulb (in atm)? P 1 T 1 P 2 T 2 ... Ideal Gas Equation 5.4 Charles' law: V T (at constant n and P ) ... Consider a case in which two gases, A and B , are in a container of volume V.
Explanation: