Answer:
The sun, like all stars, is able to create energy because it is essentially a massive fusion reaction. Technically known as nuclear fusion, this process releases an incredible amount of energy in the form of light and heat.
Types of energy produced: Stars produce energy from nuclear reactions, primarily the fusion of hydrogen to form helium.
Explanation:
hope this helped :D
__M+__Q2----->___MQ3
Answer: 2M + 3Q2 -----> 2MQ3
Explanation:
2 Ms either side, and 6 Qs either side
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Answer:
See Explanation
Explanation:
10) From the options provided for this question, gamma particle is the most energetic. Recall that gamma rays are high energy electromagnetic radiation which are capable of causing a high degree of ionization in matter.
11) The bombardment of U-235 with neutrons leads to the reaction;
[tex]U\frac{235}{92} + n\frac{1}{0}---> I\frac{138}{53} + Y\frac{95}{39} +3n \frac{1}{0}[/tex]
Hence
a = 92, b= 95, c= 53
12) In positron emission, a proton is transformed into a neutron. The mass number of the daughter nucleus is the same as its parent but the atomic number decreases by 1.
Hence;
[tex]Th\frac{231}{90} -----> e\frac{1}{0} +Ac \frac{231}{89}[/tex]
If the speed of a wave is 150 m/s and its frequency is 2 Hz, what is its wavelength?
A. 300m
B. 75m
C. 152m
D. 148m
Answer:
75m
Explanation:
7. A certain hydrocarbon, CxHy, is burned (reacts with O2 gas) and produces 1.955 g of CO2 for every
1.000 g of H20. What is the empirical formula of this hydrocarbon?
CxHy + (X + y/4) O2 -> xCO2 + y/2 H2O
Answer:
The empirical formula of the hydrocarbon is C₂H₅
Explanation:
The formula for the hydrocarbon is [tex]C_xH_y[/tex]
The mass of CO₂ produced per 1,000 g of H₂O = 1,955 g
The equation for the chemical reaction is given as follows;
[tex]C_xH_y[/tex] + (x + y/4) O₂ → XCO₂ + y/2H₂O
From the given chemical equation, counting the number of atoms on both sides of the equation, we have;
The molar mass of CO₂ = 44.01 g/mol
The molar mass of H₂O = 18.01528 g/mol
The number of moles of H₂O in 1,000 g of H₂O = 1,000 g/(18.01528 g/mol) = 55.5084351 moles
The number of moles of CO₂ in 1,955 g of H₂O = 1,955 g/(44.01 g/mol) = 44.4217223 moles
Therefore, given that X moles of CO₂ is produced alongside Y/2 moles of H₂O. we have;
X = 44.4217223, Y/2 = 55.5084351
∴ Y = 2 × 55.5084351 = 111.0168702
The ratio of X to Y = X/Y = 44.4217223/111.0168702 = 0.40013488238
∴ The ratio of X to Y = X/Y ≈ 0.4 = 4/10
X/Y ≈ 4/10
The empirical formula is the representation of molecular formula in the smallest whole number ratio of the elements of the molecules
Therefore, when X = 4, Y = 10, from which we have the smallest ratio as;
When X = 2, Y = 5
The empirical formula of the hydrocarbon is therefore, [tex]C_xH_y[/tex] = C₂H₅
The given chemical equation becomes;
C₂H₅ + (2 + 5/4) O₂ → 2CO₂ + 5/2H₂O
C₂H₅ + 3.25 O₂ → 2CO₂ + 2.5 H₂O
We then have;
4C₂H₅ + 13 O₂ → 8CO₂ + 10 H₂O
The empirical formula of the hydrocarbon, [tex]C_xH_y[/tex] = C₂H₅.
Acid rain due to air pollution when water reacts with sulfur dioxide, nitric oxide, and carbon dioxide, causes
Answer:
Acid rain is caused by a chemical reaction that begins when compounds like sulfur dioxide and nitrogen oxides are released into the air. These substances can rise very high into the atmosphere, where they mix and react with water, oxygen, and other chemicals to form more acidic pollutants, known as acid rain.
Explanation:
Slow cooling of magma leads to the formation of large crystals, such as halite and calcite.
Select the correct response:
True
False
dlaczego emaliowane garnki rdzewieją w miejscach uszkodzenia emalii
Answer:
Explanation: I don’t even know what you said
Answer:
so basically
Explanation:
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Which reaction type is really part of another type of reaction but treated separately? Explain
Answer:
Oxidation - reduction reaction which is called redox reaction.
Explanation:
The type of reaction that is a part of another type but treated separately is called Oxidation - reduction reaction.
Thus is because they usually involve 2 separate half reactions which are oxidation reactions that involve loss of electrons and then reduction equations which involve gain of electrons.
They are treated separately for example when sodium reacts with chlorine to form sodium chloride.
2Na + Cl2 = 2NaCl
Now, sodium undergoes oxidation by loosing elctrons and it's half reaction is;
2Na → 2Na^(+) + 2e^(-)
Meanwhile chlorine undergoes reduction by gaining electrons and its half reaction is;
Cl2 + 2e^(-) → 2Cl^(-)