Explanation:
the pressure exerted by the gas is due to the random motion of particles in the gas. Gases have weak intermolecular forces and the particles in continuous random motion and these particles collide with the walls of the container. This collisions with the walls of the container exerts pressure on the gas
100.00 mL of 0.15 M nitrous acid (HNO2) are titrated with a 0.15 M NaOH solution. (a) Calculate the pH for the initial solution. (b) Calculate the pH for the point at which 80.0 mL of the base has been added. (c) Calculate the pH for the equivalence point. (d) Calculate the pH for the point at which 105 mL of the base has been added.
Answer:
a. pH = 2.04
b. pH = 3.85
c. pH = 8.06
d. pH = 11.56
Explanation:
The nitrous acid is a weak acid (Ka = 5.6x10⁻⁴) that reacts with NaOH as follows:
HNO₂ + NaOH → NaNO₂(aq) + H₂O(l)
a. At the beginning there is just a solution of 0.12M HNO₂. As Ka is:
Ka = [H⁺] [NO₂⁻] / [HNO₂]
Where [H⁺] and [NO₂⁻] ions comes from the same equilibrium ([H⁺] = [NO₂⁻] = X):
5.6x10⁻⁴ = X² / 0.15M
8.4x10⁻⁵ = X²
X = [H⁺] = 9.165x10⁻³M
As pH = -log [H⁺]
pH = 2.04b. At this point we have HNO₂ and NaNO₂ (The weak acid and the conjugate base), a buffer. The pH of a buffer is obtained using H-H equation:
pH = pKa + log [NaNO₂] / [HNO₂]
Where pH is the pH of the buffer,
pKa is -log Ka = 3.25
And [NaNO₂] [HNO₂] could be taken as the moles of each compound.
The initial moles of HNO₂ are:
0.100L * (0.15mol / L) = 0.015moles
The moles of base added are:
0.0800L * (0.15mol / L) = 0.012moles
The moles of base added = Moles of NaNO₂ produced = 0.012moles.
And the moles of HNO₂ that remains are:
0.015moles - 0.012moles = 0.003moles
Replacing in H-H equation:
pH = 3.25 + log [0.012moles] / [0.003moles]
pH = 3.85c. At equivalence point all HNO2 reacts producing NaNO₂. The volume added of NaOH must be 100mL. That means the concentration of the NaNO₂ is:
0.15M / 2 = 0.075M
The NaNO₂ is in equilibrium with water as follows:
NaNO₂(aq) + H₂O(l) ⇄ HNO₂(aq) + OH⁻(aq) + Na⁺
The equilibrium constant, kb, is:
Kb = Kw/Ka = 1x10⁻¹⁴ / 5.6x10⁻⁴ = 1.79x10⁻¹¹ = [OH⁻] [HNO₂] / [NaNO₂]
Where [OH⁻] = [HNO₂] = x
[NaNO₂] = 0.075M
1.79x10⁻¹¹ = [X] [X] / [0.075M]
1.34x10⁻¹² = X²
X = 1.16x10⁻⁶M = [OH⁻]
pOH = -log [OH-] = 5.94
pH = 14-pOH
pH = 8.06d. At this point, 5mL of NaOH are added in excess, the moles are:
5mL = 5x10⁻³L * (0.15mol / L) =7.5x10⁻⁴moles NaOH
In 100mL + 105mL = 205mL = 0.205L. [NaOH] = 7.5x10⁻⁴moles NaOH / 0.205L =
3.66x10⁻³M = [OH⁻]
pOH = 2.44
pH = 14 - pOH
pH = 11.56An unknown compound was found to be soluble in concentrated sulfuric acid; however, the 2,4-DNP, chromic acid, and potassium permanganate gave negative results. The only positive result detected was the ferrous hydroxide test. What is the most likely functional group present in such compound
Explanation:
2,4-DNP is negative: aldehyde and ketone absent
Chromic acid is negative: alcohol absent.
KMnO4 test negative: alkene absent
The only positive result is for Fe(OH)2.
Nitro group-containing compounds react with ferrous hydroxide to give amine and ferric hydroxide red ppt. Hence given compound contains the nitro group (-NO2).
C3H8, + 5O2
+ 5O2,3CO2 + 4H20
If 2.50 moles of C3H8react, how many moles of H20 are produced?
Answer:
[tex]from \: the \: equation \\ 1 \: moles \: of \: propane \: produce \: 4 \: moles \: of \: water \\ 2.50 \:moles \: of \: propane \: will \: produce \: ( \frac{(2.50 \times 4)}{1} ) \: moles \\ = 10 \: moles \: of \: water[/tex]
how many energy levels are known about Bohr's atomic model?
What is the charge that a Phosphorus atom would likely form?
+1
+2
+3
-1
-2
-3
Answer:(b) By referring to a periodic table or table of elements, we see that phosphorus (symbol P) has an atomic number of 15. Thus, each atom has 15 protons. The mass number of the ion is 15 + 16 = 31. Because the ion has 15 protons and 18 electrons (three more electrons than protons), its net charge is 3-
What needs to be taken into consideration when increasing either the acid or base concentration in order to increase the buffering capacity of a solution?
The more concentrated the buffer solution, the greater its buffer capacity.
What is an acid?An acid is any substance that in water solution tastes sour, changes blue litmus paper to red, reacts with some metals to liberate hydrogen, reacts with bases to form salts, and promotes chemical reactions.
The more concentrated the buffer solution, the greater its buffer capacity.
If the buffer capacity is 10 times larger, then the buffer solution can absorb 10 times more strong acid or base before undergoing a significant change in pH.
Hence, we need to take this into consideration when increasing either the acid or base concentration in order to increase the buffering capacity of a solution.
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75.0 grams of MgCl, is dissolved in 500.0 g of water, density 1.00 g/ml. What is the MOLALITY of this solution?
es -)
A)
0.50 m
B)
1.00 m
C)
1.58 m
D)
2.02 m
Answer:
C
Explanation:
Check it. So u can know it
What is another name for a mole?
O A. Rutherford's number
O B. Mendeleev's number
O C. Dalton's number
D. Avogadro's number
Answer: D Avogadro’s Number
Explanation:
Another name for a mole is Avogadro's number. option D) is correct.
What is a Mole?
A mole refers to the amount of a substance that contains as many elementary units as can be found in 12g of Carbon-12. It can also be a number of a substance /particles, such as atoms or ions. molecules or electrons. The number of particles is approximately 6.02* 10²³ in magnitude and is called Avogadro's number of particles. it can be denoted with 'mol'.
Formula for calculating mole.
n = N/Nₐ
Where,
n = number of moles of the substance (or elementary entity)
N = total number of elementary entities in the sample
Nₐ= Avogadro constant.
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What is the smallest ph possible
Answer: -3.6
Explanation:
The lowest pH of -3.6 is the lowest known for any water in the environment
Given the following chemical reaction:
N2 + 202 --> 2 NO2
How many liters of N2 are needed to react with 10 liters of Q? Explain
Answer:
1
Explanation:
one volume of nitrogen to react
Reacting Solutions of Aluminum Chloride with Potassium Hydroxide
Mixing the solutions of aluminum chloride and potassium hydroxide results in the following.
AlCl3(aq) + KOH(aq) --> KCl (aq) + Al(OH)3(s)
150 mL of a 1.50M aluminum chloride solution is mixed with 155 mL of a 2.50M potassium hydroxide solution and heated.
QUESTIONS:
1. Balance the equation: __AlCl3 + __KOH --> __KCl + __Al(OH)3
Write coefficients in order space between each number or a comma and a space for exam 1 2 3 4 or 1, 2, 3, 4
2. How many moles of aluminum chloride is needed to completely react with the given amount of potassium hydroxide?
A. 10.0 mol AlCl3
B. 0.225 mol AlCl3
C. 0.388 mol AlCl3
D. 0.129 mol AlCl3
3. How much aluminum hydroxide is made from this reaction? (reminder to leave space between number and unit)
1Al2(SO4)3 + 3ZnCl2 → 2AlCl3 + 3ZnSO4
The coefficients represents moles. There is 1 mole of Aluminum Sulfate, 3 moles of Zinc(II) Chloride, 2 moles of Aluminum Chloride, and 3 moles of Zinc(II) Sulfate.
Now add all the coefficients/moles.
9 is the sum of all the coefficients.
Amir observes Wave 1 and Wave 2 crashing into each other at two different intervals. His experiments produce Wave 3 and Wave 4. Amir records his data in a table.
A 2-column table with 4 rows titled Amir's Waves. The first column labeled Wave has entries 1, 2, 3, 4. The second column labeled Information has entries Amplitude of 6 centimeters, Amplitude of 4 centimeters, Amplitude of 7 centimeters, Amplitude of 3 centimeters.
What is the best statement about the data collected in Amir’s table?
Wave 3 resulted from destructive interference, and Wave 4 resulted from constructive interference.
Waves 3 and 4 resulted from constructive interference.
Waves 3 and 4 resulted from destructive interference.
Wave 3 resulted from constructive interference, and Wave 4 resulted from destructive interference.
Answer:
d
Explanation:
wave a and b clashing constructively would make c a bigger wave and clashing destructively would make d a smaller wave, which they are.
Answer:
d
Explanation:
What is the most likely effect of people logging a forest faster than it can grow back?
The forest will eventually disappear and no longer provide any resources.
The forest will eventually reach a smaller population size and remain at that size.
The forest will gradually grow faster to keep up with increased demand.
The forest will keep its current population size and continue to provide resources.
Answer:
D
Explanation:
A growing body of scientific evidence shows that the felling of tropical forests creates optimal conditions for the spread of mosquito-borne scourges, including malaria and dengue. Primates and other animals are also spreading disease from cleared forests to people.
A 5.0L balloon in a freezer is at a temperature of - 50 degrees * C has a pressure of 800 mm Hg. What will be the new pressure if the balloon is taken out and placed in a warm room (Temperature 37°C) and the volume expands to 7.0 L?
Answer:
794 mmHg
Explanation:
We are going to be using the Combined Gas Law for this problem as well. Just to refresh out memory - the Combined Gas Law expresses the relationship between pressure, volume, and temperature (in KELVIN) of a fixed amount of gas. The equation itself? Right here: [tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]
Now, looking at the problem, let's assign the values to its corresponding variable:
P1 = 800mmHg; V1 = 5.0L; T1 = -50°C + 273 = 223K
V2 = 7.0L; T2 = 37°C + 273 = 310K; P2 = ?
We are looking to find the new pressure, a.k.a. P2. So, let's plug and chug the values into the equation.
Set up: [tex]\frac{(800 mmHg)(5.0L)}{223K} = \frac{(7.0L)(P_{2})}{310K}[/tex]
==> [tex]\frac{(800 mmHg)(5.0L)}{223K} * 310K = (7.0L)(P_{2})}[/tex]
==> [tex]P_{2} = \frac{(800 mmHg)(5.0L)}{223K} * \frac{310K}{7.0} }[/tex]
==> [tex]P_{2} =[/tex] 794.36 = 794 mmHg
List 3 technologies that have made jobs easier.
Answer:
-security hardware
- artificial intelligence
wifi, internet, phones, voice assistants, drones.
Please write the answer in format below
Answer:
0.95 L
Explanation:
Step 1: Given data
Concentration of the Mg(NO₃)₂ solution (C): 0.32 M (0.32 mol/L)
Mass of Mg(NO₃)₂ (solute): 45 g
Step 2: Calculate the moles corresponding to 45 g of Mg(NO₃)₂
The molar mass of Mg(NO₃)₂ is 148.33 g/mol.
45 g Mg(NO₃)₂ × 1 mol Mg(NO₃)₂ /148.33 g Mg(NO₃)₂ = 0.303 mol Mg(NO₃)₂
Step 3: Calculate the volume of solution that contains 0.303 moles of Mg(NO₃)₂
The concentration of the solution is 0.32 M, that is, there are 0.32 moles of Mg(NO₃)₂ per liter of solution.
0.303 mol Mg(NO₃)₂ × 1 L Solution / 0.32 mol Mg(NO₃)₂ = 0.95 L
Like in a cat's eye, the human pupil changes shape in response to changes in
the environment. What is the most likely function of this structure?
A. To allow humans to read
B. To allow humans to see clearly in different levels of light
C. To allow humans to see shades in color
D. To allow humans to see at varying distances
Answer:
B.
Our pupils contract and expand depending on the amount of light at any given time in order to avoid being blinded and to see better in the darkness.
during evaporation, the volume of the liquid decreases and the liquid becomes what???
Answer:
Evaporation happens when a liquid substance becomes a gas. When water is heated, it evaporates. The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor. ... Once water evaporates, it also helps form clouds
What is the minimum temperature
needed to dissolve 35 grams of KCl in 100 grams of water?
Answer:
[tex]30^{\circ}\text{C}[/tex]
Explanation:
To know the temperature at which KCl dissolves in water we need to refer to the general solubility curves.
In the case of [tex]KCl[/tex], [tex]35\ \text{g}[/tex] of it will dissolve in [tex]100\ \text{g}[/tex] of water at a minimum temperature of [tex]30^{\circ}\text{C}[/tex].
So, the the minimum temperature needed to dissolve 35 grams of KCl in 100 grams of water is [tex]30^{\circ}\text{C}[/tex].
Which do you use to qualify matter?
A. Thermometer
B. Five senses
C. Balance
D. Tape measure
Answer:
c balance
Explanation:
if you weigh something, you prove it's there.
2) A balloon was inflated to a volume of 5.0 liters at a temperature of
7.0°C. It landed in an oven and was heated to 147°C. What is its new
volume?
Answer:
6.12 L
Explanation:
Given that,
Initial volume, V₁ = 5 L
Initial temperature, T₁ = 7.0°C = 343 K
Final temperature, T₂ = 147°C = 420 K
We need to find its new volume. The relation between volume and temperature is given by :
[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{5\times 420}{343}\\\\V_2=6.12\ L[/tex]
So, the new volume is 6.12 L.
2) A balloon was inflated to a volume of 5.0 liters at a temperature of
7.0°C. It landed in an oven and was heated to 147°C. What is its new
volume?
Answer:
[tex]V_1=7.5L[/tex]
Explanation:
Hello there!
In this case, according to the Charles' law equation which help us to understand the directly proportional relationship between volume and temperature:
[tex]\frac{V_2}{T_2}= \frac{V_1}{T_1}[/tex]
Thus, by solving for the initial volume, V1, and making sure we use the temperatures in Kelvin, we can calculate the final volume as shown below:
[tex]V_1= \frac{V_2T_1}{T_2} \\\\V_1= \frac{5.0L*(147+273)K}{(7.0+273)K} \\\\V_1=7.5L[/tex]
Best regards!
i really need help with this
Answer:
i hope i can help you with this
Answer: focus in class
Explanation:
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A watt is
A. 1 cal/s.
B. 1 joule/s.
C. 1 s/cal.
D. 1 s/joule.
Answer:
The answer would be B. 1 joule/s.
Explanation:
The answer is B because the power in general is normally defined as energy over time. Watts are defined as 1 Watt = 1 Joule per second (1W = 1 J/s) which means that 1 kW = 1000 J/s.
Another reason why it's B is because I had the same exact question in class, I took a screenshot of it a day ago:
Hope this helps
Calculate the OH-ion concentration of a 6.2x10-3 M HCIO3 solution.
Answer:
1.62x10⁻¹² M
Explanation:
HClO₃ is a strong acid, meaning that a 6.2x10⁻³ M solution has a molar concentration of H⁺ of 6.2x10⁻³.
With the above information in mind, we can calculate the pH of the solution:
pH = -log(6.2x10⁻³) = 2.21Now we can calculate the pOH of the solution, using the pH:
pOH = 14 - pHpOH = 11.79Finally we calculate [OH⁻], using the definition of pOH:
pOH = -log[OH⁻][OH⁻] = [tex]10^{-pOH}[/tex] = 1.62x10⁻¹² MFe2O3 + 3H2 → 2Fe + 3H20
About how many grams of H20 will be produced from 150 grams of
Fe2O3?
The mass of water will be produced from 150 grams of iron (III) oxide is equal to 50.7 g.
What is the balanced chemical equation?A chemical equation depicts a chemical reaction in terms of symbols of the substances. A chemical equation consists of reactants participating, products, and their physical states.
The law of conservation of mass should be followed by a balancing of a chemical equation so that the number of atoms of substances is equal on either side of the equation is a balanced chemical equation.
Given the balanced chemical equation of the reaction of iron oxide and hydrogen:
[tex]Fe_2O_3 + 3H_2 \longrightarrow 2Fe + 3H_2O[/tex]
Given, the mass of the iron oxide = 150 g
The number of moles of iron oxide = 159.69 g/mol
The number of moles of iron (III) oxide = 150/159.69 = 0.939 mol
One mole of iron (III) oxide produces water = 3 mol
Then 0.939 mol of iron (III) oxide produces water = 3 ×0.939 = 2.82 mol
The mass of water produced = 2.82 ×18 = 50.7 g
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HELP I DON'T HAVE LONG LEFT AND I'M STRUGGLING SO BAD PLEASE I BEG U TO HELP
What is the force being applied to an object with a mass of 12 KG and an acceleration of 4M/S
Answer:
48 newtons
Explanation:
PLEASE HELPP WILL MARK BRAINLEST!!!!
Answer:
B i think
Explanation:
Think
about the physical properties used to identify elements as either metal,non-metals, or metalloids. Write
Imagine that you are asked to classify a group of elements as either metal, non-metals, or metalloids.
Explain how you would use their physical properties to accomplish this task.
Be sure to –Address the prompt, provide support, and conclude your thoughts. Write legibly and concisely.
Answer:
The elements can be classified as metals, nonmetals, or metalloids. ... Elements are further classified into metals, non-metals, and metalloids based on their properties, ... when they undergo chemical reactions They normally do not accept ... Most metal oxides are basic oxides and dissolve in water to form .
Explanation: