how do find the domain and range from a graph, and writing it as an inequality ​

Answers

Answer 1
To determine the domain is the same as to determine which numbers appear as the first number (the x-value) in an ordered pair that is part of the graph.
To determine the range is the same as to determine which numbers appear as the second number (the y-value) in an ordered pair that is part of the graph.
Here are some examples:
y

x
2
+
3
graph{y >= x^2+3 [-11.6, 13.72, 0.15, 12.81]}
Although it is not 100% certain from just the graph, this graph does get wider and wider. Every
x
does appear in some ordered pair on the graph. The domain is all real numbers.
The
y
values that appear start at
3
and go up. We get all numbers greater than or equal to
3
. Inequality:
y

3
.
If you've learned interval notation, you write:
[
3
,

)
x
2
+
y
2
9

1
# graph{x^2 + y^2/9 <= 1 [-5.35, 7.14, -3.105, 3.14]}
Domain (x-values) Go from

1
to
1
(inequality:

1

x

1
)(interval:
[

1
,
1
]
)
Range:

3
to
3
(inequal:

3

y

3
(interval:
[

3
,
3
]
)
More challenging:
x
2
+
y
2
<
9
graph{x^2+y^2 < 9 [-5.35, 7.14, -3.105, 3.14]}
The dotted line is not included, so we do not include the points at

3
or at
3
.
Domain:

3
<
x
<
3
(interval
(

3
,
3
)
)
R
a
n

:
-3(

e
r
v
a
l
(-3, 3))
Last one:
x

y
2
<
6
graph{x- y^2 < 6 [-9.87, 30.68, -9.96, 10.32]}
Domain: all real numbers
Range: all real numbers

Related Questions

3. [W] Consider the following data from NASA about the density of the sun. • When you are 10% of the way out from the center of the sun (use x = 0.1), the density is approximately 82.9619 g/cm3 . • When you are 20% of the way out of the sun, the density is approximately 38.7504 g/cm3 . • When you are 70% of the way out of the sun, the density is approximately 1.7819 g/cm3 . • When you are 80% of the way out of the sun, the density is approximately 1.9824 g/cm3 . • When you are 90% of the way out of the sun, the density is approximately 0.7859 g/cm3 . We want to use this data to find a quartic (4th degree) interpolating polynomial for the density of the sun throughout. y = Ax4 + Bx3 + Cx2 + Dx + E (a) Set up this problem as a system of linear equations. (b) Find the quartic polynomial that goes through these data points. (c) Use this polynomial to approximate the density 50% of the way out of the sun.

Answers

Answer:

a)

A(0.1)^4 + B(0.1)^3 + C(0.1)^2 + D(0.1) + E = 82.9619  ----------1

A(0.2)^4 + B(0.2)^3 + C(0.2)^2 + D(0.2) + E = 38.7504 -------2

A(0.7)^4 + B(0.7)^3 + C(0.7)^2 + D(0.7) + E = 1.7819   ----------3

A(0.8)^4 + B(0.8)^3 + C(0.8)^2 + D(0.8) + E = 1.9824 ----------4

A(0.9)^4 + B(0.9)^3 + C(0.9)^2 + D(0.9) + E = 0.7859 ----------5

b)  y = 519x^4 - 1630x^3 + 1844x^2 - 889x + 155

c)  0.1875

Step-by-step explanation:

a)

Let y = Ax^4 + Bx^3 + Cx^2 + Dx + E

Setting up the problem as a system of linear equations

when x=(10%)=0.1, y = 82.9619

therefore

A(0.1)^4 + B(0.1)^3 + C(0.1)^2 + D(0.1) + E = 82.9619  ----------1

when x=(20%)=0.2, y = 38.7504

A(0.2)^4 + B(0.2)^3 + C(0.2)^2 + D(0.2) + E = 38.7504 -------2

when x=(70%)=0.7, y = 1.7819

A(0.7)^4 + B(0.7)^3 + C(0.7)^2 + D(0.7) + E = 1.7819   ----------3

when x=(80%)=0.8, y = 1.9824

A(0.8)^4 + B(0.8)^3 + C(0.8)^2 + D(0.8) + E = 1.9824 ----------4

when x=(90%)=0.9, y = 0.7859

A(0.9)^4 + B(0.9)^3 + C(0.9)^2 + D(0.9) + E = 0.7859 ----------5

b)

Find the quartic polynomial that goes through these data points

Now to find the values ( A,B,C,D,E)

[MATRIX]

║A║         ║   (0.1)^4  (0.1)^3    (0.1)^2   (0.1)    1    ║^-1    ║ 82.9619  ║

║B║         ║     (0.2)^4  (0.2)^3  (0.2)^2   (0.2) 1   ║         ║ 38.7504 ║

║C║     =  ║    (0.7)^4  (0.7)^3  (0.7)^2   (0.7)   1   ║         ║ 1.7819     ║

║D║         ║    (0.8)^4  (0.8)^3  (0.8)^2  (0.8)   1   ║         ║ 1.9824    ║

║E║         ║    (0.9)^4  (0.9)^3  (0.9)^2  (0.9)   1   ║         ║ 0.7859    ║

║A║      ║  29.7619  -47.619  166.667   -238.095   89.2857 ║ ║ 82.9619║

║B║      ║  -77.381  119.048  -333.333   452.381 -160.714      ║ ║ 38.7504║

║C║  =  ║   71.131  -102.381  208.333  -269.048 91.9643      ║ ║ 1.7819    ║

║D║      ║  -26.369 33.0952  -41.6667  52.619  -17.6786     ║ ║ 1.9824   ║

║E║       ║   3.00      -2.4         -2.4        -3.00          -1.00       ║  ║ 0.7859  ║

║A║       ║ 519   ║

║B║       ║ -1630║

║C║  =   ║ 1844 ║ ,         y = 519x^4 - 1630x^3 + 1844x^2 - 889x + 155

║D║       ║ -889 ║

║E║       ║ 155    ║

c)

approximate the density 50% of the way out of the sun

so at 50% (0.5) x=0.5

we substitute

y = 519(0.5)^4 - 1630(0.5)^3 + 1844(0.5)^2 - 889(0.5) + 155

= 0.1875

Lisa's age is 4 years older than three times Sammy's age. Lisa is 28 years old. Let s represent Sammy's age. Which equation can be used to solve for Sammy's age?

Answers

Answer:

24

Step-by-step explanation:

let Sammy's age be x and Lisa y

since Lisa is 4years older than Sammy

y=x+4

28-4=y

y=24

3a+8+2ax≥3ax-4a what is a

Answers

Answer:

A=3 I'm 95% sure but if you're not sure then use PEMDAS

P-parentheses

E-exponets

M-multiply

D-divide

A-add

S-subtract

olve. 4 + x 7 = 2 A) -14 B) 10 C) 12 D) 42

Answers

Answer:

-14 I believe

Step-by-step explanation:

Answer:

Its A.

Step-by-step explanation:

what is the formular for 1+4+16+64+256

Answers

Answer:

341

Step-by-step explanation:

1+4=5

5+16=21

21+64=85

85+256=341

Write Three and eight thousandths in standard form? What is it

Answers

Thousandths is the 3rd decimal place

The answer is 3.008

1/2x^2+3x+7 find axis of symetry ​

Answers

Answer:

x=-3

Step-by-step explanation:

when examining distributions of numerical data, what three components should you look for

Answers

Answer:

The three components you should look for when examining distributions of numerical data are Shape, center, and spread

-Source(I took AP statistics in senior year of high school and passed the AP test)

The three components for examining distributions of numerical data are Shape, centre, and spread.

What is distribution of data?

A normal distribution is a common probability distribution. It has a shape often referred to as a "bell curve." Many everyday data sets typically follow a normal distribution: for example, the heights of adult humans, the scores on a test given to a large class, errors in measurements.

When examining the distribution of a quantitative variable, one should describe the overall pattern of the data (shape, centre, spread), and any deviations from the pattern (outliers). When describing the shape of a distribution, one should consider: Symmetry/skewness of the distribution Peakedness (modality) - the number of peaks (modes) the distribution has. Not all distributions have a simple, recognizable shape. Outliers are data points that fall outside the overall pattern of the distribution. It is always important to interpret the features of the distribution (as they appear in the histogram) mean in the context of the data.

Hence, The three components for examining distributions of numerical data are Shape, centre, and spread.

For more references on distribution, click;

https://brainly.com/question/29062095

#SPJ2

Find the value of x that will make A||B.
A
B
4x
2x
X =
?

Answers

Answer:

x = 30

Step-by-step explanation:

Lines A and B are parallel lines and a transverse line is intersecting these lines at two distinct points.

By the definition of interior consecutive angles, sum of the measures of interior consecutive angles is 180°.

4x + 2x = 180°

6x = 180

x = 30

Therefore x = 30 will be the answer.

You earn $15 an hour tutoring and $9 an hour working at the Sippy Drink. You can tutor a maximum of 10 hours a week. You have to put in at least 20 hours a week at the Sippy Drink to keep your job there. You can't work more than 40 hours a week. Create and graph a system of inequalities that represents the constraints

Answers

Answer:

how is the maximum 10 hrs but you need to put in 20hrs

what is 2/3 + 1/2 equal?

Answers

Answer: To add fractions, find the LCD and then combine.

Exact Form:

7 /6

\( ̄︶ ̄*\)) Hope this helps!!

Answer:

7/6

Step-by-step explanation:

2/3+1/2

4/6+3/6

4+3/6

7/6

a retail chain buys 1000 wireless speakers if the price is $190 and $2600 if the price is $110. A wholesaler will supply 800 wireless speakers at $128 each and 2400 at $192. Assuming that the supply and demand functions are linear, find the market equilibrium price and market equilibrium quantity

Answers

Answer:

The market equilibrium price is $160 and market equilibrium quantity is 1600

Step-by-step explanation:

A linear function is of the form y = m * x + b, where m is the slope and b is called the intercept.

The shape of a demand and supply curve will be: Q = m * P + b

The point-slope form of the linear function is written as y- y1 = m * (x- x1) where (x, y) and (x1, y1) are the coordinates of the point. In this case: Q- Q1 = m * (P- P1)

A retail chain buys 1000 wireless speakers if the price is $ 190 and 2,600 if the price is $ 110. Then (P, Q) = (190,1000) and (P1, Q1) = (110, 2600). Replacing in the point-slope form:

1000 - 2600= m*(190 - 110)

and solving for m you get:

-1600=m*80

[tex]m=\frac{-1600}{80}[/tex]

m= -20

To find the value of b from the demand curve Q = m * P + b, you plug in the value of m and either of the two points into the equation and solve for b. So:

Q= -20*P + b

Replacing (P, Q) = (190,1000)

1000= -20*190 + b

1000= -3800 + b

1000 + 3800= b

4800= b

The demand function is Q= -20*P + 4800

In an analogous way, the supply function can be deduced. A wholesaler will supply 800 wireless speakers at $128 each and 2400 at $192. Then (P, Q) = (128,800) and (P1, Q1) = (192, 2400). Replacing in the point-slope form:

800 - 2400= m*(128 - 192)

and solving for m you get:

-1600=m*(-64)

[tex]m=\frac{-1600}{-64}[/tex]

m= 25

To find the value of b from the supply curve Q = m * P + b, you plug in the value of m and either of the two points into the equation and solve for b. So:

Q= 25*P + b

Replacing (P, Q) = (128,800)

800= 25*128 + b

800= 3200 + b

800 - 3200= b

-2400= b

The supply function is Q= 25*P - 2400

The point where the supply and demand curves intersect is called the market equilibrium point. At this point the quantity supplied and the quantity demanded is the same and the price must also be the same. So:

-20*P + 4800= 25* P -2400

Solving for P:

-20*P - 25*P= -2400 - 4800

-45*P= -7200

[tex]P=\frac{-7200}{-45}[/tex]

P= 160

Since at the equilibrium point the quantity supplied and the quantity demanded is the same, replacing the price P in either of the two functions (demand or supply) I obtain the equilibrium quantity. In this case, it is replaced in the supply function:

Q= 25*160 -2400

Q= 1600

Finally, the market equilibrium price is $160 and market equilibrium quantity is 1600

3÷1/3+1=

PLEASE HELP!!!!!

Answers

Answer:

9+1=10 following bodmas rule

Find the coordinates of point P that partition AB in the
ratio 1:4.

Please give explanation

Answers

Answer:

(1.6, 0)

Step-by-step explanation:

Point P, partitioning AB in the ratio 1:4, implies that it divides AB into, AP and PB, such that AP to PB = 1:4.

Use the formuka below to find the coordinates of point P:

[tex] x = \frac{mx_2 + nx_1}{m + n} [/tex]

[tex] y = \frac{my_2 + ny_1}{m + n} [/tex]

Where,

[tex] A(1, -1) = (x_1, y_1) [/tex]

[tex] B(4, 4) = (x_2, y_2) [/tex]

[tex] m = 1, n = 4 [/tex]

Solve by plugging the above values where necessary as follows:

[tex] x = \frac{mx_2 + nx_1}{m + n} [/tex]

[tex] x = \frac{1(4) + 4(1)}{1 + 4} [/tex]

[tex] x = \frac{4 + 4}{5} [/tex]

[tex] x = \frac{8}{5} [/tex]

[tex] x = 1.6 [/tex]

[tex] y = \frac{my_2 + ny_1}{m + n} [/tex]

[tex] y = \frac{1(4) + 4(-1)}{1 + 4} [/tex]

[tex] y = \frac{4 - 4}{5} [/tex]

[tex] y = \frac{0}{5} [/tex]

[tex] y = 0 [/tex]

The coordinates of P that partitions AB into the ratio 1:4 are (1.6, 0)



Estimate the answers after rounding to the indicated place value.

56.1: 6.6 (ones)

A 9

B10

C8

D7

E6

Answers

The answer is D:7 ㅤㅤㅤ

Catherine wants to pass year for Ms. Ford's class and all she has left is to take the final Spring Final. If she earned a 60 on Semester 1, a 62 on RC3 and a 53 on RC4 what is the minimum score she would need to earn on the final to pass for the year? RC3 and RC4 are averaged together for 90% of the semester 2 grade. The Spring final is 10% of the semester 2 grade. The final grade is the average of the Semester 1 and Semester 2 grade. A 70% is passing.

Answers

Step-by-step explanation:

The final grade is the average of the two semesters.

70 = ½ (60 + x)

x = 80

So Catherine needs a Semester 2 grade of 80%.

The average of RC3 and RC4 is ½ (62 + 53) = 57.5.  This accounts for 90% of the Semester 2 grade.  The other 10% is the Spring final.

80 = 0.90 (57.5) + 0.10 (x)

x = 282.5

Catherine would have to score 282.5% on the Spring final in order to pass.

The original price of a camera was $50 and the sale price this week is $38. What is the percent of change in the price
of the camera?
A.24% B. 12% C.20% D.25%

Answers

Answer:

24%

Step-by-step explanation:

x (original price) = 50$

y (sale price) = 38$

p (percentage) = ?

p = (x - y) / x

p = (50-38) / 50

p = 12/50

p = 0.24

p = 24%

Answer:

24%

Step-by-step explanation:

i did it in my head

If -3x–7 =23 then 6x=?

Answers

Answer:

6x = -60

Step-by-step explanation:

-3x - 7 = 23

-3x = 30

x = -10

6(-10) = -60

I need help on this question 109^41/109^94

Answers

Answer:

[tex]\frac{1}{109^{53}}[/tex]

Step-by-step explanation:

[tex]\frac{109^{41}}{109^{94}}=109^{41-94}=109^{-53}=\frac{1}{109^{53}}[/tex]

A 35-foot ladder is leaning against the side of a building and is positioned such that the base of the ladder is 21 feet from the base of the building. How far above the ground is the point where the ladder touches the building?​

Answers

Answer:

Step-by-step explanation:

A plane flew to its destination 300 miles away. With a tail wind, the flight took 5/6 of an hour. The return
trip, with a head wind, took 1 hour. Find the speed of the wind and the speed of the plane.


Thank youu

Answers

Answer:A plane flew to its destination 300 miles away. With a tail wind, the flight took 5/6 of an hour. The return trip, with a head wind, took 1 hour....

Step-by-step explanation:

what kind of number is -18 and explain why it is

Answers

Answer:

Step-by-step explanation:

-18 is a integer because it has negative sign

☽------------❀-------------☾

Hi there!

~

-18 is an integer number because of the " - " sign. I hope the picture will explain why -18 is an integer number!

❀Hope this helped you!❀

☽------------❀-------------☾

How many cups of flour are needed to make 3 dozens of dinner rolls

Answers

Answer: 1/15

Step-by-step explanation: A. If 1/3 cup makes 5 rolls, you need to know how many cups make one. (1/3)/5 = 1/15  Take the number of cups for one roll and multiply it by 3.  1/15 x 3  Final Answer = 3/15

B. Take the number of cups you have divided by 1/3 (since you know how many roles this makes)  (5 2/3) / (1/3)  Final Answer = 17

C. Well, we already solved for this one in A, didn't we?  Final Answer = 1/15

Help me please and show work and this is geometry

Answers

Answer:

-433

Step-by-step explanation:

Step 1: Define

-5(4 + 9s) - 7(4q - 6)

s = 7

q = 5

Step 2: Simplify expression

Distribute: -20 - 45s - 28q + 42

Combine like terms: -45s - 28q + 22

Step 3: Substitute

-45(7) - 28(5) + 22

Step 4: Evaluate

-315 - 140 + 22

-445 + 22

-433

100 x 0.64

Please help sorry I keep asking questions I’m doing a test and it’s kinda hard

Answers

100 x 0.64 = 64.

All you have to do is multiply the numbers as if there wasn’t a decimal.

Then you add a decimal after 2 numbers.

.64 has a decimal after 2 numbers so your answer would have a decimal after 2 numbers also.

So when you get 6400 you out a decimal after 00.

That gives you 64

Write the name of the
period that has the
digits 913.

Answers

the answer is the thousands group . its the way they word the problem that complicates it . 913,256 256 being the ones group 913 being the thousands group . so the name of the period with 913 , is the thousands group .
It’s kinda in between, but I’ll say the thousands since it’s rlly close.

Plz help! I dont understand this

Answers

Solve for x the. You can find your answer from there.

A 130 gallon tank initially contains 10 lbs salt dissolved in 60 gallons of water. Brine containing 1 lb salt per gallon begins to flow into the tank at the rate of 3 gal/min and the well-mixed solution is drawn off at the rate of 1 gal/min. How much salt is in the tank when it is about to overflow

Answers

Answer:

80 lb of salt

Step-by-step explanation:

Let us assume the water flows into the rank for x minutes.

There is an initial of 60 gallons of water in the tank and water flows in at 3 gal/min. In x minute, the amount of water in the tank = 60 + 3x

Water flows out at 1 gal/min, therefore in x minute the amount of water in the tank = 60 + 3x - x = 60 + 2x

The tank begins to overflow when it is full (has reached 130 gallons). Therefore:

130 = 60 + 2x

2x = 130 - 60

2x = 70

x = 35 minutes.

In 35 minutes the tank would start to overflow.

1 lb salt per gallon flows into the tank at 3 gal/min, in 35 min the amount of salt that entered the tank = 3 gal/min × 35 min × 1 lb/gal = 105 lb

1 lb salt per gallon flows out of the tank at 1 gal/min, in 35 min the amount of salt that flow out of the tank = 1 gal/min × 35 min × 1 lb/gal = 35 lb

Initially there is 10 lb of salt dissloved into 60 gallons of water.

Therefore the amount of salt is in the tank when it is about to overflow = 10 + 105 - 35 = 80 lb of salt.

Help ASAP
Find the Distance between (5,2) and (-3,-4)

Answers

Answer:

[tex]d = 10[/tex]

Step-by-step explanation:

Distance Formula: [tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Simply plug in your 2 coordinates into the formula to find distance d:

[tex]d=\sqrt{(-3-5)^2+(-4-2)^2}[/tex]

[tex]d=\sqrt{(-8)^2+(-6)^2}[/tex]

[tex]d=\sqrt{64+36}[/tex]

[tex]d=\sqrt{100}[/tex]

[tex]d = 10[/tex]

1
Tamara spun the arrow on a spinner 50 times. The number of times the arrow landed on each colored section of the spinner is shown in the table.
Section
Red
Blue
Orange
Yellow
Number of Times
Arrow Landed on
23
8
10
9
Based on the results in the table, what fraction of the area of the spinner is most likely represented by the Red section?
А.
SO
O B. 3
Ос. 4
O D. 1 / 4

Answers

Answer:

Area covered by red target = 23/50

Step-by-step explanation:

Given:

Total number of shot = 50

Section      Number of shots

Red                      23

Blue                      8

Orange               10  

Yellow                 9

Find:

Area covered by red target

Computation:

Area covered by red target = 23/50

Area covered by red target = 1/2 of total area

Answer:

The fraction of the area of the Red section is [tex]\dfrac{23}{50}[/tex]

Step-by-step explanation:

Given that,

The number of times the arrow landed on each colored section of the spinner is shown in the table.

Tamara spun the arrow on a spinner 50 times.

Section = Red, Blue, Orange, Yellow

Number of times arrow landed = 23, 8, 10, 9

We need to calculate the fraction of the area of the Red section

Using formula of fraction of area

[tex]fraction\ of\ area=\dfrac{Red\ section}{total\ section}[/tex]

Put the value into the formula

[tex]fraction\ of\ area=\dfrac{23}{50}[/tex]

Hence, The fraction of the area of the Red section is [tex]\dfrac{23}{50}[/tex]

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