Answer:
Autotrophs store chemical energy in carbohydrate food molecules they build themselves. Most autotrophs make their food through photosynthesis using the energy of the sun. Heterotrophs cannot make their own food, so they must eat or absorb it.
Light and radio are examples of the __________________________ or ______________________ energy form, which is ________________ because it is always moving.
Answer:
Radiant; electromagnetic; kinetic energy.
Explanation:
Energy can be defined as the ability (capacity) to do work. The various forms of energy are solar energy, electrical energy, chemical energy, thermal energy, wind energy, nuclear energy etc.
The two (2) main types of energy are;
a. Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.
b. Kinetic energy (KE): it is an energy possessed by an object or body due to its motion.
Light and radio are examples of the radiant or electromagnetic energy form, which is kinetic energy because it is always moving.
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;
[tex] K.E = \frac{1}{2}MV^{2}[/tex]
Where;
K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents velocity measured in metres per seconds square.
Copper can be shaped into wires because it is
.ANSWER:Copper is a ductile metal
EXPLAIN :This means that it can easily be shaped into pipes and drawn into wires. Copper pipes are lightweight because they can have thin walls. They don't corrode and they can be bent to fit around corners.
Copper is a ductile metal due to ductility.This means that it can easily be shaped into pipes and drawn into wires. Copper pipes are lightweight because they can have thin walls.
Ductility is a mechanical property commonly described as a material's amenability to drawing (e.g. into wire).In materials science, ductility is defined by the degree to which a material can sustain plastic deformation under tensile stress before failure. Ductility is an important consideration in engineering and manufacturing. It defines a material's suitability for certain manufacturing operations (such as cold working) and its capacity to absorb mechanical overload.
Some metals that are generally described as ductile include gold and copper, while platinum is the most ductile of all metals in pure form.However, not all metals experience ductile failure as some can be characterized with brittle failure like cast iron. Polymers generally can be viewed as ductile materials as they typically allow for plastic deformation.
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what are the isomers of hexane
Physical properties
Isomer M.P. (°C) B.P. (°C)
n-hexane −95.3 68.7
3-methylpentane −118.0 63.3
2-methylpentane (isohexane) −153.7 60.3
2,3-dimethylbutane −128.6 58.0
1 more row
if u mix 10ml of 70%ethanol with 20ml of 80% ethanol with 50ml water what is the concentration of the resulted solution
Answer:
29% is the final concentration
Explanation:
To solve this question we must find the volume of ethanol added and the volume of the whole solution. The concentration will be:
Volume ethanol / Total volume * 100
Volume ethanol:
10mL * 70% = 7mL ethanol
+
20mL * 80% = 16mL ethanol
= 23mL ethanol
Total volume:
10mL + 20mL + 50mL = 80mL
Concentration:
23mL / 80mL * 100
= 29% is the final concentration
In order to determine the magnetic properties of phosphorus atom we need to find out the number of unpaired electrons present in the ground state of phosphorus atom! Select one of the answers below that represents this number.
Group of answer choices
1
4
3
0
2
Answer:
Think of it this way If you have a phosphorus atom whats its oposites once you found that out you may be able to find the answer
Explanation:
Hope this helps :)
URGENT PLEASE HELP! Given 3.4 grams of x element with a molar mass of 24 g/mol and 4.2 grams of y element with a molar mass of 35 g/mol. How much of compound xy2 can be generated?
x + 2y -> xy2
4.4 g XY
I'm not sure but that's the closest I can get or try
what causes ignition
Answer:
An ignition coil can fail due to a high voltage puncture of its body, or an open primary or secondary winding. A few are killed by overheating when the control side of the primary side develops a short to ground. Something as simple as badly worn spark plugs will increase the demand from the coil, and eventually lead to failure.
But if I were to discuss the current leading cause of ignition coil replacement, I would have to say misdiagnosis and bad internet information. This is especially true of modern “coil on plug” systems. Often, the actual coil is fine, and the only damage is the replaceable spark plug boot.
I've seen countless examples of online “advice” to start with replacing all spark plugs and coils at the suggestion of any power loss or hiccup. Then the car owner purchases the cheapest set of coils that they can find. Not only is the initial problem still present , but they likely WILL have a future misfire due to poor quality parts selection. All misfires are not caused by coils and spark plugs.
Explanation:
An acetate buffer solution is prepared by combining 50. mL of 0.20 M acetic acid,
HC2H3O2(aq), and 50. mL of 0.20 M sodium acetate, NaC2H3O2(aq). A 5.0 mL sample of 0.10 M NaOH(aq) is added to the buffer solution.
Which of the following is a correct pairing of the acetate species present in greater concentration and of the pH of the solution after the NaOH(aq) is added? (The pKa of acetic acid is 4.7.)
Acetate Species -- pH
(A) HC2H3O2 -- < 4.7
(B) HC2H3O2 -- > 4.7
(C) C2H3O2 -- < 4.7
(D) C2H3O2 -- > 4.7
Answer:
The answer is "Option B".
Explanation:
[tex]\to CH_3COOH + NaOH \longleftrightarrow CH_3COONa + H_2O\\\\\to CH_3COONa + NaOH\longleftrightarrow CH3COONa\\\\\therefore \ mol\ NaOH = (5 \ E-3\ L)\times(0.10 \ \frac{mol}{L}) = 5 \ E-4\ mol\\\\[/tex]
[tex]\to mol\ CH_3COOH = (0.05 \ L)\times(0.20 \frac{mol}{L}) = 0.01 \ mol\\\\\to C \ CH_3COOH = \frac{(0.01 \ mol - 5 \ E-4\ mol) }{(0.105 \ L)}\\\\\to C \ CH_3COOH = 0.0905 \ M\\\\\therefore \ mol \ CH_3COONa = (0.05\ L )\times (0.20 \ \frac{mol}{L}) = 0.01 \ mol\\\\[/tex]
[tex]\to C \ CH_3COONa = \frac{(0.01\ mol + 5 \ E-4\ mol)}{(0.105\ L )}\\\\\to C \ CH_3COONa = 0.1 \ M\\\\\therefore Ka = ([H_3O^{+}]\times \frac{(0.1 + [H_3O^+]))}{(0.0905 - [H_3O^+])} = 1.75\ E-5\\\\\to 0.1[H_3O^+] + [H_3O^+]^2 = (1.75 E-5)\times (0.0905 - [H_3O^+])\\\\[/tex]
[tex]\to [H_3O^+]^2 \ 0.1[H_3O^+] = 1.584\ E-6 - 1.75\ E-5[H_3O^+]\\\\\to [H_3O^+]^2 + 0.1000175[H_3O^+] - 1.584 \ E-6 = 0\\\\\to [H_3O^+] = 1.5835\ E-5 \ M\\\\\therefore pH = - \log [H_3O^+]\\\\\to pH = - \log (1.5835 \ E-5)\\\\ \to pH = 4.8004 > 4.7[/tex]
Can You please solve the question b in the photo. Will give branliest.
Answer:
Br₂ + 2e⁻ ⇄ 2Br⁻ Half reaction of reduction
2I⁻ ⇄ 2e⁻ + I₂ Half reaction of oxidation
Br₂ + 2I⁻ + 2K⁺ ⇄ I₂ + 2Br⁻ + 2K⁺
Explanation:
This is an easy redox reaction:
Br₂ + 2KI → I₂ + 2KBr
We determine the oxidation states.
0 for the elements at ground state.
K does not change the oxidation state during the reaction.
Bromine is reduced to bromide (oxidation state decreases)
and iodide is oxidized to Iodine (oxidation state increases)
Br₂ + 2e⁻ ⇄ 2Br⁻ Half reaction of reduction
2I⁻ ⇄ 2e⁻ + I₂ Half reaction of oxidation
In oxidation, electrons are released while in reduction, the electrons are gained. To make the ionic equation, we just add K⁺
So we sum both reactions
Br₂ + 2e⁻ + 2I⁻ + 2K⁺ ⇄ 2e⁻ + I₂ + 2Br⁻ + 2K⁺
We cancel the electrons on both sides of the equation:
Br₂ + 2I⁻ + 2K⁺ ⇄ I₂ + 2Br⁻ + 2K⁺
Draw the atomic structure with electronic configuration of Potassium
Answer:
Explanation:
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Solution A has a pH of 3, and solution B has a pH of 5. Which statement best
describes these solutions?
A. Solution A is acidic, and solution B is basic.
B. Solution A is basic, and solution B is acidic.
C. Solution B is less acidic than solution A.
O D. Solution B is more acidic than solution A.
Answer:
C. Solution B is less acidic than solution A.
What is the pH of a solution that has a hydrogen ion concentration of 6.9*10^-4?
The pH would be 3.16 because the formula for finding the pH from a H± ion is pH = -log [H±]
So with that formula, you first have to substitute the H± with your numbers which in this case is 6.9 × 10^-4.
It should like this:
pH = -log (6.9 × 10^-4)
And lastly, just calculate.
pH = 3.16
Hope that helps, do let me know if you need more help in understanding this!
A piece of copper has a density of 8.96 g/cm3, what is the volume of a 4.2 g piece?
Answer:
0.47 cm³
Explanation:
[tex]Volume=Mass/Density\\[/tex]
Plug in the mass (4.2 grams) and the density (8.96 g/cm³)
[tex]Volume=4.2/8.96\\Volume=0.47[/tex]
Therefore, the volume of a 4.2 g piece of copper is approximately 0.47 cm³.
I hope this helps!
what charge does copper have?
Answer: 1+charge
Explanation: hoped this helped:)
Explain what might happen to tundra animals, such as polar bears, as earth's climate warms. pls explain
Answer:
They will die.
Explanation:
Polar Bears were made to live in the frigid temperatures of the tundras. If there is a temperature change it can affect their habitat. It can destroy it and they would have to move out to another place. They can die due to global warming.
Consider a iron-silver voltaic cell that is constructed such that one half-cell consists of the iron, Fe, electrode immersed in a Fe(NO3)3 solution, and the other half-cell consists of the silver, Ag, electrode immersed in a AgNO3 solution. The two electrodes are connected by a copper wire. The Fe electrode acts as the anode, and the Ag electrode acts as the cathode. To maintain electric neutrality, you add a KNO3 salt bridge separating the two half-cells. Use this information to solve Parts B, C, and D. Part B The half-cell is a chamber in the voltaic cell where one half-cell is the site of the oxidation reaction and the other half-cell is the site of the reduction reaction. Type the half-cell reaction that takes place at the anode for the iron-silver voltaic cell. Indicate the physical states of atoms and ions using the abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively. Use (aq) for an aqueous solution. Do not include phases for electrons. Express your answer as a chemical equation.
Answer:
See explanation
Explanation:
In the voltaic cell, energy is produced by spontaneous chemical reaction. One half cell functions as the anode (in this case it is the Fe/Fe^2+ half cell) while the other half cell functions as the cathode (in this case it is the the Ag/Ag^+ half cell).
At the anode;
Fe(s) -----> Fe^2+(aq) + 2e
At the anode;
2Ag^+(aq) + 2e ------> 2 Ag(s)
Overall cell equation;
Fe(s) + 2Ag^+(aq) ------> Fe^2+(aq) + 2 Ag(s)
During the age of the dinosaurs, most mammals grew no bigger than a?
Answer:
T-rex
Explanation:
4 methyl 2 pentanone structural formula
Answer:
(CH3)2CHCH2COCH3
Explanation:
. Elements in the Periodic Table are arranged according to increasing numbers of _____________, which is called the ___________ ______________ on an element key.
Answer:. Elements in the Periodic Table are arranged according to increasing numbers of ______atoms_______, which is called the ______atomic _____ _______number_______ on an element key.
Explanation: I just learned about this at school!! ; )
Which of the following is NOT correct about the mole concept?
1 point
1 mole of sodium atoms will ionize to produce 1 mole of sodium ions and 1 mole of
electrons
A mole is the number of carbon atoms in 12g of C-12 isotope.
A mole is the number of molecules in 22.4 dm3 of all gases at all temperatures and
pressures
A mole is the number of electrons that carry one Faraday of electricity
A mole is the number of molecules of water in 18 g of ice, water or water vapour
Answer:
a mole is the number of molecules in 22.4 dm³ for all gases at all temperatures and pressures
Calculate the molar mass of PbSo3
Answer:
Lead sulfite is the inorganic compound with the formula PbSo3 or O3PbS.
Explanation:
How many lone pairs are on the central atom of a molecule of RnCl4?
A. 0
B. 2
C. 3
D. 1
A flexible container at an initial volume of 6.13 L contains 2.51 mol of gas. More gas is then added to the container until it reaches a final volume of 11.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Answer:
2.12 moles of gas were added.
Explanation:
We can solve this problem by using Avogadro's law, which states that at constant temperature and pressure:
V₁n₂=V₂n₁Where in this case:
V₁ = 6.13 Ln₂ = ?V₂ = 11.3 Ln₁ = 2.51 molWe input the data:
6.13 L * n₂ = 11.3 L * 2.51 moln₂ = 4.63As 4.63 moles is the final number of moles, the number of moles added is:
4.63 - 2.51 = 2.12 molesable 1 Cell Type Operating Cell Potential for Commercial Batteries, E (V) Lithium-iodine Zinc-mercury +2.80 +1.35 Table 2 Standard Reduction Potential, E' (V) -1.20 Half-Reaction [Zn(OH)212 +2e → Zn + 4 OH Zn(OH)2 +2e → Zn +20H- HgO + H2O +2e → Hg+20H O2 + 2H20 +40 →40H -1.25 +0.10 +0.40 ctronic devices that help regulate the heart rate. Currently, lithium-iodine cells are commonly used to power pacemakers and have replaced zinc-me otential, E, for each cell. Table 2 provides the standard reduction potentials for several half-reactions related to zinc-mercury and zinc-air cells. dation given, which of the following is a major difference between the zinc-mercury cell and the lithium-iodine cell? 0, +2H2O + 4e +40H +0.40 Pacemakers are electronic devices that help regulate the heart rate Currently, lithium-iodine cells are commonly used to power pacemakers and have replaced zinc-mercury cells. Table 1 provides the operating cell potential, E, for each cell. Table 2 provides the standard reduction potentials for several half-reactions related to zinc-mercury and zinc air cells. Based on the information given, which of the following is a major difference between the zinc mercury cell and the lithium-iodine cell?
A. During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is less thermodynamically favorable.
B. During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable.
C. During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not.
D. During the initial cell operation, the oxidation of mercury is thermodynamically favorable but not the oxidation of iodine is not.
Answer:
During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable. ( B )
During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not. ( C )
Explanation:
The major Differences between The Zinc mercury cell and Lithium-iodine cell are :
During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable. and
During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not.
Given the relationship below,
Δ G = -nFE
E = emf of cell , G = free energy.
This relationship shows that if E is positive the reaction will be thermodynamically favorable also if E is large it will increase the negativity of free energy also From the question we can see that with the reduction of mercury the value of E is more positive and this shows that Mercury is thermodynamically unfavorable
If a gas is cooled from 343.0 K to 283.15 K and the volume is kept constant what final pressure would result if the original pressure was 760.0 mm HG?
Answer:
627.4 mmHg
Explanation:
From Gay-Lussac law:
[tex] \frac{p1}{t1} = \frac{p2}{t2} [/tex]
p1 = 760 mmHg
t1 = 343 K
t2=283.15 K
[tex]p2 = p1 \times \frac{t2}{t1} [/tex]
[tex]p2 = 760 \times \frac{283.15}{343.0} [/tex]
[tex]p2 = 627.4 \: mmhg[/tex]
If a gas is cooled from 343.0 K to 283.14 K and the volume is kept constant the final pressure would be 627.4 mm Hg if the original pressure was 760.0 mm Hg.
Gay-Lussac's LawGay-Lussac's law states that the pressure of a given mass of gas at a constant volume varies directly with the temperature of the gas. Gay-Lussac's law defined the relationship between pressure and temperature of a gas when kept at a constant volume.
According to the Gay-Lussac's LawP ∝ T (When V = constant)
or, P = kT
or, [tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]
Here,
[tex]P_{1}[/tex] = 760.0 mm Hg,
[tex]T_{1}[/tex]= 343.0 K
[tex]T_{2}[/tex] = 283.15 K
Now put the values in above formula, we get
[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]
[tex]\frac{760.0\ \text{mm Hg}}{343.0K} = \frac{P_2}{283.15\ K}[/tex]
[tex]P_{2} = \frac{760.0\ \text{mm Hg} \times 283.15\ K}{343.0\ K}[/tex]
[tex]P_{2} = \frac{215194\ \text{mm Hg}}{343}[/tex]
[tex]P_{2}[/tex] = 627.4 mm Hg
Thus, we can say that if a gas is cooled from 343.0 K to 283.14 K and the volume is kept constant the final pressure would be 627.4 mm Hg if the original pressure was 760.0 mm Hg.
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What is the difference between 13.254 m/s and 7.7 m/s? Round your answer to the correct number of significant digits.
Answer:
5.6 m/s
Explanation:
Given,
First number = 13.254 m/s
Second number = 7.7 m/s
We need to find the difference between these two numbers. First we round off 13.254 to one decimal place i.e. 13.254 = 13.3 m/s
The difference between them is given by :
D = 13.3 - 7.7
= 5.6 m/s
Hence, the difference of the two numbers is 5.6 m/s.
The galaxies pictured above would best be classified as
A barred galaxies
C irregular galaxies
B spiral galaxies
D
elliptical galaxies
Answer:
Spiral galaxies
Explanation:
1) ____C3H8 + ____O2 → ____CO2 + ____H2O
2) Using the following equation:
Water is added to iron and over time iron (III) oxide along with hydrogen gas is produced.
a. How many grams of iron (III) oxide will be produced when 15.5g of iron reacts with excess water?
b. Calculate the percent yield if your team produced 14.5g of iron (III) oxide.
c. If the reaction takes place under STP then how many liters of hydrogen gas are produced?
the answer is 133
because thats how the water is
If 18.0 g of CO2 is produced in the reaction of C2H2 with O2 to form CO2 and
H2O, how many grams of H20 are produced in this reaction?
O 3.68 g
9.0 g
14.7 g
None of the above
7.37 g
Answer:
3.68 g
Explanation:
[tex]n_{CO2}[/tex] = 18 ÷ 44 = 0.4
2C2H2 + 5O2 → 4CO2 + 2H2O
2 : 5 : 4 : 2
0.409 (moles)
⇒ [tex]n_{H2O}[/tex] = 0.409 × 2 ÷ 4 = 0.2045 moles
⇒ [tex]m_{H2O}[/tex] = 0.2045 × 18 = 3.68 grams