Answer:
We multiply [tex]x = 23.78\times 10^{-6}\,\frac{m^{3}}{mol}[/tex] by the amount of mole to change units to cubic meters.
Explanation:
Let [tex]x = 23.78\times 10^{-6}\,\frac{m^{3}}{mol}[/tex], we change the unit to cubic meters by multiplying this number by the amount of moles of the sample. For instance, let [tex]n = 1\,mol[/tex], then the obtain the following result:
[tex]m = x\cdot n[/tex] (1)
[tex]m = \left(23.78\times 10^{-6}\,\frac{m^{3}}{mol} \right)\cdot (1\,mol)[/tex]
[tex]m = 23.78\times 10^{-6}\,m^{3}[/tex]
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How are ribosomes different from other complex animal cell organelles?
Explanation:
Ribosomes are not quite the same as different organelles since they have no layer around them that isolates them from different organelles, they comprise of two subunits, and when they are creating sure proteins they can become film bound to the endoplasmic reticulum, however they can likewise be free drifting while at the same time performing
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Why is the value of a substance’s specific gravity always the same numerically as its density?
Because it is always the substance’s density divided by the density of water which is 1 g/cm 3
Because it is always the substance’s density multiplied by the density of water which is 1 g/cm 3
Because specific gravity is the inverse of density
Because these represent the same measurement
Answer:
Because it is always the substance’s density divided by the density of water which is 1 g/cm 3
Explanation:
The density of water is 1g/cm³;
Specific gravity = [tex]\frac{density of substance}{density of water}[/tex]
Since specific gravity is a relative comparison of a substance density with that of water, the values always the same.
Density of water is 1 and it will have no effect on the density of the substance.
The only difference is in the units. The density of a substance will have a unit but that of the specific gravity will have no unit.
Numerically, dividing by 1 has no implication.
Answer: the answer is C
Explanation:Specific gravity is the density of a substance divided by the density of water. Since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density
What voltage is required to move 6A through 20?
Answer:
120V
Explanation:
Given parameters:
Current = 6A
Resistance = 20Ω
Unknown:
Voltage = ?
Solution:
According to ohms law;
V = IR
Where V is the voltage
I is the current
R is the resistance
Now, insert the parameters and solve;
V = 6 x 20 = 120V
If an object has a weight of 4050 N near the surface of the Earth, what is its mass?
Answer:
417.5 kg
Explanation:
Since the gravitational for of attraction F, equals the weight of the object W when its close to the earth, F = GMm/R² = W = mg where m = mass of object and g = acceleration due to gravity close to the earth = 9.8 m/s².
g = GM/R² where g = acceleration due to gravity close to the earth, G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of earth = 5.927 × 10²⁴ kg and R = radius of earth = 6.4 × 10⁶ m
So, g = GM/R²
= 6.67 × 10⁻¹¹ Nm²/kg² × 5.927 × 10²⁴ kg/(6.4 × 10⁶ m)²
= 39.53 × 10¹³ Nm²/kg ÷ 40.96 × 10¹² m²
= 9.65 N/kg
≅ 9.7 N/kg
= 9.7 m/s²
Since W = 4050 N and W = mg
m = W/g = 4050 N/9.7 m/s²
= 417.53 kg
≅ 417.5 kg
So, the mass of the object is 417.5 kg
the rubber covering over a wire acts as a / an ?
Answer:
Most electrical wire is covered in a rubber or plastic coating called insulation. The purpose of insulation covering the metal part of an electrical wire is to prevent accidental contact with other conductors of electricity, which might result in an unintentional electric current through those other conductors.
Explanation:
what is the avarage speed during kick 1
How much power does it take to do 1000 J of work in 8 seconds?
How much force would be needed to
push a 22 kg box across the floor with
an acceleration of 1.9 m/s^2? Assume
that there is a coefficient of friction of.
17 between the box and the floor.
Help me with this!!!!!!!it’s due in 10 minutes
There would be two forces acting on the box parallel to the floor, with a net force of
∑ F = p - f = m a
where p = magnitude of the push, f = mag. of friction, m = mass of the box, and a = acceleration. To find p, we first need f .
There are also only two forces acting on the box perpendicular to the floor, with net force
∑ F = n - w = 0
where n = mag. of normal force of the floor on the box and w = weight of the box. The net force is 0 because the box is only accelerating parallel to the floor.
w = m g, where g = 9.8 m/s² is the mag. of the acceleration due to gravity, so we can solve for n :
n = w = m g
n = (22 kg) (9.8 m/s²)
n = 215.6 N
The kinetic friction is proportional to the normal force by a factor of the given coefficient of friction, µ = 0.17, such that
f = µ n
f = 0.17 (215.6 N)
f = 36.652 N
Now solve for the required pushing force:
p - 36.652 N = (22 kg) (1.9 m/s²)
p ≈ 78 N
Answer:
0
Explanation:
If you push an 5 N object 2 m and then push a 10 N object 2 m. Which is TRUE?
You do the same amount of work.
You do more work when you move the 10 N object.
You are more powerful when you move the 5 N object
O You use the same amount of force.
Answer:
Explanation:
You don't do the same amount of work. The work formula is F*d = W
W = work
F = force
d = the distance moved.
So you do more work when you move the 10N object because the Force (F) has doubled.