Answer:
3,958.8 mi
Explanation:
A moving car initially has kinetic energy K. The car then moves in the opposite direction with four times its initial speed. What is the kinetic energy now
If initial speed was v, Kinetic energy was K = 1/2mv^2
When speed will be 4v, KE will be:
= 1/2 m (4v)^2
=1/2m 16 v^2
=16K
Now kinetic energy will become 16 times of initial Kinetic Energy
Why is it important that we learn about our solar system, the sun, and planets in our solar system other than Earth?
Answer:
To understand all the different kind of elements and how they work. Nature is a beautiful thing and it is important we understand how they survive and how we can help. The solar system is a mandatory nature. Learning about other planets also helps us feel safe and more knowledgable.
a 2000kg car initially traveling at a speed of 15 m/s is accelerated by a constant force of 10000 n for 3 seconds. the new speed of the car is
Answer:
The new speed of the car is 30 m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Question: Self-test 3.12 Calculate the change in G for ice at -10°C, with density 917 kg mº, when the pressure is increased from 1.0 bar to 2.0 bar.
The change in the Gibb's free energy per mole (G) is 1.96 J.
The given parameters:
Density of the ice, ρ = 917 kg/m³Initial pressure, P₁ = 1.0 barFinal pressure, P₂ = 2.0 barTemperature, T = - 10 CMass of water = 18 gThe change in the Gibb's free energy per mole (G) is calculated as follows;
[tex]\Delta G = V(P_2-P_1) \\\\[/tex]
where;
V is the volume of the ice
[tex]Density = \frac{Mass}{Volume} \\\\Volume = \frac{Mass}{Density} \\\\Volume = \frac{18 \times 10^{-3} \ kg}{917 \ m^3} \\\\Volume = 1.96 \times 10^{-5} \ m^3\\\\Volume = 1.96 \times 10^{-5} \ m^3 \times \frac{1000 \ L}{m^3} \\\\Volume = 0.0196 \ L[/tex]
Change in pressure;
[tex]P_2 - P_1 = 2.0 \ bar \ - \ 1.0 \ bar = 1.0 \ bar = 0.987 \ atm[/tex]
The change in the Gibb's free energy per mole (G);
[tex]\Delta G= V(P_2-P_1)\\\\\Delta G = 0.0196\ L \times 0.987\ atm \\\\\Delta G = 0.0193 \ L.atm\\\\1 \ L.atm = 101.325 \ J\\\\\Delta G = 0.0193 \ L.atm \times \frac{101.325 \ J}{1 \ L.atm} \\\\\Delta G = 1.96 \ J[/tex]
Thus, the change in the Gibb's free energy per mole (G) is 1.96 J.
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The average value of the load between A and B is 6.0 N. The spring has an unstretched length
increases from 4.0 cm to 6.0 cm.
The change in the length of the spring as it stretches from 4.0 cm to 6.0 cm is 2.0 cm.
The change in length of the spring can be calculated by subtracting the initial unstretched length (4.0 cm) from the final stretched length (6.0 cm).
Change in length = Final length - Initial length
Change in length = 6.0 cm - 4.0 cm
Change in length = 2.0 cm
Therefore, the change in the length of the spring as it stretches from 4.0 cm to 6.0 cm is 2.0 cm. This means the spring elongates by 2.0 cm under the applied load between points A and B.
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The complete question is:
The average value of the load between A and B is 6.0 N. The spring has an unstretched length increases from 4.0 cm to 6.0 cm. What is the change in the length of the spring as it stretches from 4.0 cm to 6.0 cm?
A. 4.0 cmB. 1.0 cmC. 2.0 cmD. 6.0 cmplease help me rn rn
Answer:
merry Christmas ⛄
Which one is it??? The question and the choice are in the photo.
The answer is:
That they are switched on
Below are three graphs. The shape of graph 3 shows that the current flowing through this component is __________ proportional to the potential difference across it. What one word completes the sentence?
The relationship between variables might be either directly porportional to each other or inversely proportional to each other. For instance, the current flowing is _directly_ proportional to the potential difference across it.
---------------------
Since I do not have the graph, I will propose two potential options and I will describe each of them.
I suggest you to choose the one that matches the shape of graph 3.
GraphsProbably your graph is composed of the X and Y axes, perpendicularly placed, in a way in which four quadrants are formed.You might see that one of the axes represents the current (I), and the other one represents the potential difference (V).
And a straight line that represents the relationship between the current and the potential difference.
The direction of the straight line reflects the relationship between variables.The change on each variable is proportional to the change on the other variable. Now we have to analyze how that change occurs. Option 1
The current flowing through this component is __DIRECTLY__ proportional to the potential difference across it.
If this is the case of your graph, you should see the straight line crossing from the left inferior quadrant to the right superior one.
The direction of the line suggests that one of the variables increases as the other one increases too. The current increases as the potential increases.
This is the case of the Ohm's law.
Option 2The current flowing through this component is __INVERSELY__ proportional to the potential difference across it.
If this is the case of your graph, you should see the straight line crossing the right quadrant from the superior left corner to the inferior right one.
The direction of the line suggests that the variable represented in the Y ax decreases as the other one increases.
For instance, The current decreases as the potential increases. Or the potential decreases as the current increases.
In the attached files you will find graphs of both options.
-------------------------
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Answer: The relationship between variables might be either directly proportional to each other or inversely proportional to each other. For instance, the current flowing is directly proportional to the potential difference across it.
Explanation:
Wtz the answer to this question? I need to get it right
Answer: Next time you create a question, add an image or PDF. Because I do not know the question. So, may you please create a new question?
What net force acting on a 6 kg car produces an acceleration of 6 m/s2?
Explanation:
Mass (m) = 6 kgAcceleration (a) = 6 m/s²Force (F) = ?We know that,
• F = ma→ F = (6 × 6) N
→ F = 36 N
Therefore, the net force is 36N.
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A. In the Bohr model of the hydrogen atom, the speed of the electron is approximately
2.16 × 10⁶ m/s. Find the central force acting on the electron as it revolves in a circular orbit of radius 5.17 × 10⁻¹¹ m.
Answer in units of N.
B. Find the centripetal acceleration of the electron
Explanation:
A. The centripetal force experienced by an electron as it goes around a hydrogen nucleus is given by
[tex]F_c = m_e\dfrac{v^2}{r}[/tex]
where [tex]m_e = \text{electron\:mass} = 9.11×10^{-31}\:\text{kg}[/tex]
[tex]r = 5.17×10^{-11}\:\text{m}[/tex] = orbital radius
[tex]v = 2.16×10^6\;\text{m/s}[/tex] = orbital velocity
so the centripetal force is
[tex]F_c = (9.11×10^{-31}\:\text{kg})\dfrac{(2.16×10^6\;\text{m/s})^2}{5.17×10^{-11}\:\text{m}}[/tex]
[tex]\;\;\;=8.22×10^{-8}\:\text{N}[/tex]
B. The electron's centripetal acceleration is given by
[tex]a_c = \dfrac{v^2}{r}[/tex]
Using the values from (A), we get
[tex]a_c = \dfrac{(2.16×10^6\;\text{m/s})^2}{5.17×10^{-11}\:\text{m}}[/tex]
[tex]\;\;\;=9.02×10^{22}\:\text{m/s}^2[/tex]
Destination is your Destination
Answer:
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Explanation:
Answer:
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HELP PLEASE WILL MARK BRAINLIEST
Outside wooden steps may get slippery when they are wet. How could you make them less slippery?
There are many ways you can get wooden steps to be less slippery even when they are wet. Some ways are:
*You can put a carpet on the steps. The fibers in a carpet usually have some friction which will give you a grip as you climb up and/or down and prevent you from falling.
*You can apply anti-slip coatings like a paint on the steps. If you add some sand to the paint to add traction and lessen the slippery nature. Alternatively, If the wood has been waxed, you may consider using a wax remover.
*You can fix a hand railing so that you can hold on to it when you go up and down the steps.
a bicycle with tires 68 cm in diameter travels 9.2 km. how many revolutions do the wheels make
Answer:
Explanation:
Circumference in meters is
C = πD = 0.68π
9200 m / 0.68π m = 4,306.545518...
4,306.5 revolutions
A bicycle with tires 68 cm in diameter travels 9.2 km. the number of revolutions made by the wheel would be 4309
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. It can also be represented by the infinitesimal rate of change of displacement with respect to time. The unit of velocity is meter/second.
The mathematical expression for velocity is given by
velocity= displacement / time taken
As given in the problem a bicycle with tires 68 cm in diameter travels 9.2 km
Diameter = 68 cm
radius = diameter /2
= 68/2
= 34 cm
The distance covered by the tire in one cycle would be
distance in one revolution = 2π×Radius
= 2×3.14× 34
= 213.52 cm
=2.13 m
The number of revolutions by wheel = total distance/distance in one revolution
number of revolutions = 9200/2.135
=4309 revolutions
Thus, the number of revolutions made by the wheel would be 4309
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How is the A He related to the A Hof a reaction?
Answer:
by giving a person to person
Where do hyperbolic comets originate?
A. the Oort cloud
B. the asteroid belt
C. the Kuiper belt
D. interstellar space
Answer:A.the Oort cloud
Explanation:
Answer:
try answer A..the Ootor cloud
4. Trilobites are animals that lived during the Paleozoic era. They populated all parts of the
ocean showed consistent evolution over time and left behind fossils that are large
enough to be studied without a microscope. All of these characteristics make trilobites
the ideal
a. Trace fossil
b. Keystone species
c. Index fossil
d. Reference point
dnreserve the remains of dead
Answer:
c. index fossil
Explanation:
Trilobite fossils are found worldwide, with many thousands of known species. Because they evolved rapidly, and molted like other arthropods, trilobites serve as excellent index fossils. (Arthropods periodically shed their old exoskeletons, or molt.) An index fossil is one that is useful for dating and correlating the strata in which it is found.
n earthquake emits both P-waves and S-waves that travel at different speeds through the Earth. A P-wave travels at 9 000 m/s and an S-wave at 4 000 m/s. If P-waves are received at a seismic station 34.0 s before an S-wave arrives, how far is the station from the earthquake center
Answer:
Yes , i also need answer
Explanation:
n earthquake emits both P-waves and S-waves that travel at different speeds through the Earth. A P-wave travels at 9 000 m/s and an S-wave at 4 000 m/s. If P-waves are received at a seismic station 34.0 s before an S-wave arrives, how far is the station from the earthquake center
Hello I am absolutely stumped on these six physics problems. Please help me on them.
Answer:
Explanation:
20° from the normal = 110° from parallel
1a) τ = (200sin90)[6] + (75sin110)[3] - (100sin110)[3]
τ = 1,129.52305... = 1100 N•m CCW
1b) τ = 200(6)(sin90) + 75(-3)(sin(360-110)) + 100(3)(sin(270 + 20)
τ = 1,129.52305... = 1100 N•m CCW
1c) My directions agree, both are positive z by right hand rule.
1d) Moment of inertia for a thin rod about an axis perpendicular to its center is
I = (1/12)mL²
τ = Iα
α = τ/I = 1129.523 / ((1/12)(200)(12²)) = 0.4706 rad/s²
θ = ½αt²
θ = ½(0.4706)(2•60)² = 3,388.56916... radians
θ = 3400 radians
at which time is is spinning about 9 revolutions per second
A baseball is hit with a speed of 27.0 m/s at an angle of 47.0 ∘ . It lands on the flat roof of a 10.0 m -tall nearby building. Part A If the ball was hit when it was 1.3 m above the ground, what horizontal distance does it travel before it lands on the building?
Answer:
H = Vy t - 1,2 g t^2 formula for height of ball after t sec
H = 10 - 1.3 = 8.7 m
Vy = 27 sin 47 = 19.7 m/s vertical speed of ball
8.7 = 19.7 t - 9.8/2 t^2 height of ball after t sec
4.9 t^2 - 19.7 + 8.7 = 0 rearranging
[19.7 ± (388 - 170)^1/2] / 2 *4.9 = [19.7 ± 14.7] / 9.8 = .51 ,3.5 sec
.51 sec would be on the way up and 3.5 sec on the way down
Sx = 27 * cos 47 * 3.5 = 64.4 m around 200 ft seems reasonable
If the speed of the magnet is doubled, the induced voltage is ________ . twice as great four times as great half as great unchanged
If the speed of the magnet is doubled, the induced voltage is twice as great
Faraday's law of induction states that whenever relative motion exists between a coil and magnetic field, a voltage will induce in the circuit and this voltage is proportional to the rate of change of the flux. The expression for the motional emf is as follows:
ε=Blv
Here, ε is the motional emf, B is the magnetic field, l is the length of the conductor, and v is the velocity at which the magnetic field changes.
The induced voltage by the moving magnet is directly proportional to the speed of the magnet. Therefore, an increase in the speed of the magnet will increase the induced voltage.
If the speed of the magnet is doubled, the induced voltage is twice as great
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A common type of succession that occurs on a surface where an ecosystem has previously existed
A 0.050 kg metal bolt is heated to an unknown initial temperature. It is then dropped into calorimeter containing 0.15 kg of water with an initial temperature of 21.0°C. The bolt and the water then reach a final temperature of 25.0°C. If the metal has a specific heat capacity of 899 J/kg•°C, find the initial temperature of the metal.
The initial temperature of the metal bolt is 80.8 °C
We'll begin by calculating the heat absorbed by the water.
Mass of water (M) = 0.15 Kg Initial temperature (T₁) = 21 °CFinal temperature (T₂) = 25 °CChange in temperature (ΔT) = T₂ – T₁ = 25 – 21 = 4 °CSpecific heat capacity of water (C) = 4184 J/KgºCHeat absorbed (Q) =?Q = MCΔT
Q = 0.15 × 4184 × 4
Q = 2510.4 J
Finally, we shall determine the initial temperature of the metal bolt.
Heat absorbed by water = 2510.4 JHeat released by metal (Q) = –2510.4 JMass of metal (M) = 0.050 Kg Final temperature (T₂) = 25 °CSpecific heat capacity of metal (C) = 899 J/Kg°CInitial temperature (T₁) =?Q = MC(T₂ – T₁)
–2510.4 = 0.050 × 899 (25 – T₁)
–2510.4 = 44.95 (25 – T₁)
Clear bracket
–2510.4 = 1123.75 – 44.95T₁
Collect like terms
–2510.4 – 1123.75 = –44.95T₁
–3634.15 = –44.95T₁
Divide both side by –44.95
T₁ = –3634.15 / –44.95
T₁ = 80.8 °C
Thus, the initial temperature of the metal is 80.8 °C.
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In the following free body diagram, what is the net force on the object?
A.10n
B.5 N to the right
C.20 N to the right
D.7 N to the right
Answer:
B
Explanation:
Simply take all forces pointing to the right of the box as positive and all of the forces pointing to the left of the box as negative and add all values.
ΣF = 7 + 18 + (-20) = 5N to the right
What are the two types of force
Answer:
Forces can be divided into primarily into two types of forces:
Contact Forces. Non-contact Forces.Explanation:
What is an element?
1. A substance made of more than one type of atom.
2. A substance that is made of water.
3. A substance that is made of no atoms.
4. A substance made of only one type of atom.
Answer:
Hey Friend...
Explanation:
This is ur answer.....
4. A substance made of only one type of atom.Hope it helps!
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Answer:
4
Explanation:
element is a substance that cannot be broken down into any other substance which means every element is made up of its own type of atom
If a force of 20kn acts on a circular rod of a diameter 10mm, calculate the stress of the rod
σ = F/A = F/ (πD²/4) = 20000 / (π0.10²/4) = 2.55 MN/m²
the distance between student home and school is 1.5 km what is the distance traveld bythe students in a week
Answer:
10.5k
Explanation:
1.5x7=10.5
A change
1. Ricardo has purchased a forklift for his business. The forklift can put out 4950 W of power. If the forklift is operating at full capacity, how much work can it do in 2.40 seconds?
O 2060)
O 4950)
O 6490)
O 11,900
The work done if the forklift is operating at full capacity is 11,900 J.
We have to recall that power is defined as the rate of doing work. The rate of doing work is defined as;
Power = Work done/time taken
When;
Power = 4950 W
Time taken = 2.40 s
Work done = Power × time taken
Work done = 4950 W × 2.40 s
Work done = 11,900 J
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The potential difference between the (high-voltage) inner shell of a Van de Graaff accelerator and a point where the charge is injected into the moving belt is 3.4 MV. What is the minimum power required to pull the belt when the belt transfers the charge to the case at 2.8 mC/s?
Explanation:
this is the answer to the questions