Answer:
(A.) (- 4.33, 6.33 , 0); (B.) (- 3.66, 7.5, 0); (C.) average at (A) (- 4.33, 6.33 , 0) ; (D.) (- 0.2165, 0.3165, 0)
Explanation:
Given the following :
Time - - - - - - - 6.6s - - - - - - - - - 6.9s - - - - - 7.2s
Position - (1.8,5.0,0) - (0.5,6.9,0) - - (−0.4,9.5,0)
(a) Between 6.6 s and 6.9 s, what was the bee's average velocity?
Vavg = Distance / time
[(0.5,6.9,0) - (1.8,5.0,0)] / 6.9 - 6.6
Vavg = [(0.5 - 1.8), (6.9 - 5.0), (0 - 0)] / 0.3
Vavg = - 1.3 / 0.3, 1.9/0.3, 0/3
Vavg = (- 4.33, 6.33 , 0)
b) Between 6.6 s and 7.2 s, what was the bee's average velocity?
Vavg = [(−0.4,9.5,0) - (1.8,5.0,0)] / 7.2 - 6.6
Vavg = - 2. 2/0.6, 4.5/0.6, 0/0.6
Vavg = (- 3.66, 7.5, 0)
c.) Of the two averages (- 4.3, 6.3 , 0) is closer to the instantaneous Velocity at 6.6s
D.) (d) Using the best information available, what was the displacement of the bee during the time interval from 6.6 s to 6.65 s?
Displacement = Velocity * time
Vavg between 6.6 to 6.9 ; time = (6.65 - 6.6) = 0.05 s
= (- 4.33, 6.33 , 0) * 0.05
= (- 0.2165, 0.3165, 0)
light of a wavelength 600 nm shines on a soap bubble film. For what soap film thickness will destructive interference occur
Answer:
The minimum thickness of the soap bubble for destructive interference to occur is 225.56 nm.
Explanation:
Given;
wavelength of light, λ = 600 nm
The minimum thickness of the soap bubble for destructive interference to occur is given by;
[tex]t = \frac{\lambda/n}{2}\\\\t = \frac{\lambda}{2n}[/tex]
where;
n is refractive index of soap film = 1.33
[tex]t = \frac{\lambda}{2n} \\\\t = \frac{600*10^{-9}}{2(1.33)}\\\\t = 2.2556 *10^{-7} \ m\\\\t = 225.56 *10^{-9} \ m\\\\t = 225.56 \ nm[/tex]
Therefore, the minimum thickness of the soap bubble for destructive interference to occur is 225.56 nm.
The phase velocity of transverse waves in a crystal of atomic separation a is given byy = csin(ka/2) pka/2 1. What is the dispersion relation e(k)? 2. What is the group velocity as a function of k?
Answer:
a
e(k) = \frac{2a}{c} * sin (\frac{k*a}{2} )
b
G_{v} = \frac{d e(k ) }{dk } = \frac{a^2}{c} * cos (\frac{k* a}{2} )
Explanation:
From the question we are told that
The velocity of transverse waves in a crystal of atomic separation is
[tex]b_y = c \frac{sin (\frac{k*a}{2} )}{\frac{k*a}{2} }[/tex]
Generally the dispersion relation is mathematically represented as
[tex]e(k) = b_y * k[/tex]
=> [tex]e(k) = c \frac{sin(\frac{k*a}{2} ) }{ \frac{k*a}{2} } * k[/tex]
=> [tex]e(k) = c * \frac{sin (\frac{k_a}{2} )}{ \frac{a}{2} }[/tex]
=> [tex]e(k) = \frac{2a}{c} * sin (\frac{k*a}{2} )[/tex]
Generally the group velocity is mathematically represented as
[tex]G_{v} = \frac{d e(k ) }{dk } = \frac{a^2}{c} * cos (\frac{k* a}{2} ) [/tex]
IV) Fill in the blanks:
1) Equal volumes of different substances have
masses.
2) The more closely packed arrangement the particles of a substance have,
its density.
3) SI unit of power is
4) An iron nail sinks in water but can float on
5) Balloons used for advertisements are filled with_gas.
6)
is the primary mode of heat transfer in liquid and gases.
1.) equal volume of different substances have "different" masses.
2.)The more closely packed arrangement the particles of a substance have, "increases" its density.
3.)the SI unit of power is "Watts".
4.)an iron nail sinks in water but floats on " mercury ".
5.)balloons used for advertisements are filled with " helium" gas.
6.)"Conduction" is the primary mode of heat transfer in liquid and gases.
I hope this helps you...
hydraulic lift is to be used to lift a 2100-kg weight by putting a weight of 25 kg on a piston with a diameter of 10 cm. Determine the diameter of the piston on which the weight is to be placed.
Answer:
840 cm
Explanation:
Note: A hydraulic press operate based on pascal's principle.
From pascal's principle
W₁/d₁ = W₂/d₂...................... Equation 1
Where W₁ and W₂ are the first and second weight, and d₁ and d₂ are the first and second diameter of the piston.
make d₁ the subject of the equation
d₁ = W₁×d₂/W₂................ Equation 2
Given: W₁ = 2100 kg, W₂ = 25 kg, d₂ = 10 cm = 0.1 m.
Substitute these values into equation 2
d₁ = 2100(0.1)/25
d₁ = 8.4 m
d₁ = 840 cm
What is the direction of the force? Answer with a positive angle measured counterclockwise from the positive x axis.
Answer:
hello the diagram related to your question is missing attached below is the missing diagram
answer : 107.07⁰
Explanation:
The direction of the force can be calculated as below
angle = 180 - ∝ - ∅ ------ 1
∅ = [tex]tan^{-1} b/a[/tex] = tan^-1 ( 0.429 )
∅ = 23.2⁰
∝ can be determined by applying the parallelogram law
∝ = [tex]tan^{-1} ( \frac{R24sin56.4}{f13 + R24cos56.4} )[/tex]
= tan^-1 ( 21.173 / 17.935 )
∝ = 49.73⁰
back to equation 1 direction of force with positive angle
= 180 - 49.73 - 23.2 = 107.07⁰
A 0.16 pF parallel - plate capacitor is charged to 10 V. Then the battery is disconnected from the capacitor. When 1.00 107 electrons are now placed on the negative plate of the capacitor, the voltage between the plates changes by
Answer:
The value is [tex]V_d = 5 \ V[/tex]
Explanation:
From the question we are told that
The capacitance of the capacitor is [tex]C = 0.16 \ pF = 0.16*10^{-12} \ F[/tex]
The voltage is [tex]V = 10\ V[/tex]
The number of electrons present on the negative plate is [tex]N_e = 1.00 *10^{7} \ electrons[/tex]
Generally the charge on the positive plate at 10 Volt is mathematically represented as
[tex]Q_a = C * V[/tex]
=> [tex]Q_a = 0.16*10^{-12} * 10[/tex]
=> [tex]Q_a = 0.16*10^{-11} \ C[/tex]
Now the charge on the plate when the electron where placed is evaluated as
[tex]Q_b = Q_a + ( N_e * e)[/tex]
Where e is the charge on each electron with a value [tex]e = 1.60 *10^{-19} \ C[/tex]
=> [tex]Q_b = 0.16*10^{-11} + (1.0*10^7 * 1.60*10^{-19})[/tex]
=> [tex]Q_b = 3.2 *10^{-12 } \ C[/tex]
Generally the voltage between the two plate is evaluated as
[tex]V_d = \frac{ Q_b - Q_a }{ 2 * C }[/tex]
=> [tex]V_d = \frac{ 3.2*10^{-12} - 0.16*10^{-11}}{2 * 0.16 *10^{-12}}[/tex]
=> [tex]V_d = 5 \ V[/tex]
7. When initially-unpolarized light passes through three polarizing filters, each oriented at 45 degree angles from the preceding filter, _____ of the initial light passes through the last filter.
Answer:
Explanation:
Let the intensity of unpolarised light be I₀ . After passing through the first polarising filter , the intensity is I₀ / 2 .
After second filter , the intensity will be I₀ / 2 x cos²45 = I₀ / 4
After third filter , the intensity will be I₀ / 4 x cos²45 = I₀ / 8 .
So,
1 / 8 the of initial light passes through the last filter .
Find the magnitude of u × v and the unit vector parrallel to u × v in the direction of u × v. u = 2i + 2j - k, v = -i + k
Answer:
magnitude = 3
unit vector = [tex]\frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}[/tex]
Explanation:
Given vectors:
u = 2i + 2j - k
v = -i + k = -i + 0j + k
(a) u x v is the cross product of u and v, and is given by;
[tex]u X v = \left[\begin{array}{ccc}i&j&k\\2&2&-1\\-1&0&1\end{array}\right][/tex]
u x v = i(2+0) - j(2 - 1) + k(0 - 2)
u x v = 2i - j - 2k
Now the magnitude of u x v is calculated as follows:
| u x v | = [tex]\sqrt{2^2 + (-1)^2 + (-2)^2}[/tex]
| u x v | = [tex]\sqrt{4 + 1 + 4}[/tex]
| u x v | = [tex]\sqrt{9}[/tex]
| u x v | = 3
Therefore, the magnitude of u x v is 3
(b) The unit vector û parallel to u x v in the direction of u x v is given by the ratio of u x v and the magnitude of u x v. i.e
û = [tex]\frac{u X v}{|u X v|}[/tex]
u x v = 2i - j - 2k [calculated in (a) above]
|u x v| = 3 [calculated in (a) above]
∴ û = [tex]\frac{2i - j - 2k}{3}[/tex]
∴ û = [tex]\frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}[/tex]
A rectangular wooden block, 22 cm x 13.2 cm x 4.4 cm, has a mass of 1562.0 g. The density of the wood in kg/m 3 is:
Answer:
1222.45 Kg/m³
Explanation:
The following data were obtained from the question:
Dimension of rectangular block = 22 cm x 13.2 cm x 4.4 cm
Mass (m) = 1562.0 g
Density (D) =?
Next, we shall determine the volume of the rectangular block.
This is illustrated below:
Volume = length x breadth x height
V = 22 cm x 13.2 cm x 4.4 cm
V = 1277.76 cm³
Next, we shall convert 1277.76 cm³ to m³.
This can be obtained as follow:
1 cm³ = 1×10¯⁶ m³
Therefore,
1277.76 cm³ = 1277.76 × 1×10¯⁶
1277.76 cm³ = 1.27776×10¯³ m³
Therefore, 1277.76 cm³ is equivalent to 1.27776×10¯³ m³.
Next, we shall convert 1562.0 g to kg. This can be obtained as follow:
1000 g = 1 kg
Therefore,
1562.0 g = 1562/1000 = 1.562 kg
Therefore, 1562.0 g is equivalent to 1.562 Kg.
Finally, we shall determine the density of rectangular block as follow:
Volume = 1.27776×10¯³ m³.
Mass = 1.562 Kg.
Density =?
Density = mass /volume
Density = 1.562 / 1.27776×10¯³
Density = 1222.45 Kg/m³
Therefore, the density of rectangular block is 1222.45 Kg/m³
14. A 5,000 kg train is traveling at a velocity of 100 m/s and hits another train. The two trains stick together, and the new velocity is 50 m/s. What is the mass of the second
train?
A. 15.000 kg
B. 8.000 kg
C. 5,000 kg
D. 10.000 kg
Please help ASAP
Answer:
C
Explanation:
Momentum of first train is = m * v= (5000 kg)·(100 m/s)
= 500,000 kg·m/s.
Momentum after collision is = (5000+M) kg)·(50 m/s) And using conservation of momentum5000+M) kg)·(50 m/s) = 500,000 kg·m/s
Dividing by 50 m/s and subtracting 5000 kg, we have ...
(5000 +M) kg = 10,000 kg
M kg = 5000 kg
Two identical guitar strings are prepared such that they have the same length ( 0.62 m ) and are under the same amount of tension. The first string is plucked at one location, primarily exciting the second harmonic. The other string is plucked in a different location, primarily exciting the third harmonic. The resulting sounds give rise to a beat frequency of 324 Hz . What is the wave propagation speed on the guitar strings?
Answer:
The speed is 401.76m/s
Explanation:
To find the fundamental frequency we use
3rd.harmonic - 2nd.harmonic = 324Hz
And we know that
f=v/2L
So v=f2L
v= 324 x 2 x 0.62= 401.76m/s
Q.Solve the following circuit find total resistance RT. Also find value of voltage across resister RC.
Answer:
14.57 ohms
Explanation:
Here in the figure ,Rb & R₄are in series & also Rc & R₅ are in series. As they are in series , ( Rb + R₄ ) & (Rc & R₅) are in parallel . So the equivalent resistance in that branch = ( 2 + 18 ) ║ ( 3 + 12 )
= 20 ║ 15
= (20×15) / (20 + 15)
= 8.57 ohms
Also Ra ( 6 ohm ) is in series with that branch ,. So the equivalent resistance of the whole circuit = 8.57 + 6 = 14.57 ohms.
total resistance is 26 ohm and voltage across [tex]R_C[/tex] resister is 1.1554 Ampere.
According to the circuit,
[tex]R_A[/tex] = 6 Ω.
[tex]R_B[/tex] = 2 Ω.
[tex]R_C[/tex] = 3 Ω.
R₄ = 18 Ω.
R₅ = 12 Ω.
V = 10 V.
In the circuit, the series combination of [tex]R_C[/tex] and R₅ is parallel connected with series combination of [tex]R_B[/tex] and R₄. And this network is connected with [tex]R_A[/tex] in series combination.
So, Equivalent resistance of the circuit is; R = [tex]R_A[/tex] + ( [tex]R_C[/tex] + R₅) II ([tex]R_B[/tex] +R₄)
= 18 Ω + ( 3 Ω + 12 Ω)II(2 Ω+ 18 Ω)
= 18 Ω + 15ΩII20Ω
= 18 Ω + (15×20)/(15+20)Ω
= 18 Ω + 8.57 Ω
= 26 Ω
So, current flowing through the circuit: I = V/ R = 10V / 26Ω = 0.38 Amp.
Voltage drop across the parallel network; V₁ = V - I[tex]R_A[/tex]
= 10V - 0.38×6 V
= 7.72 V.
So, voltage across the resister [tex]R_C[/tex] = V₁[tex]R_C[/tex]/[tex](R_C[/tex] + R₅)
= 7.72 × 3/(3 + 12) Amp
= 1.1544 Amp.
Hence, total resistance is 26 ohm and voltage across specific resister is 1.1554 Ampere.
Learn more about circuit here:
https://brainly.com/question/21505732
#SPJ3
Name at least three fundamental differences between the harmonic oscillator dynamics and the simple pendulum dynamics
Answer: please find the answer in the explanation.
Explanation:
Harmonic can be experienced by any body that repeats itself. The pattern can be sinusoidal, square, tooth etc.
The fundamental differences between the harmonic oscillator dynamics and the simple pendulum dynamics are:
1.) The harmonic oscillator dynamics can be sinusoidal or square wave so far the motion is periodic while the simple pendulum dynamics is always sinusoidal.
2.) In simple pendulum dynamics, the period of oscillation is independent of the amplitude. While the period in harmonic oscillator dynamics depends on the amplitude.
3.) Differential equation is only one method to analyze the simple pendulum dynamics where there are several methods to analyze the harmonic oscillator dynamics.
There are three long parallel wires arranged so that, in cross-section, they occupy the points of an equilateral triangle. Is there any way to arrange the currents so that all three wires attract each other?
Answer:
Yes, there is such a way.
Explanation:
If currents flow in the same direction in two or more long parallel wires, there will be an attractive force between the wires. If the current flows in different directions, there will be a repulsive force between the wires. In this case, these three parallel wires, can be be made to carry current in the same direction, creating an attractive force between all three wires.
Note that it is not possible to have at the least one of them carry current in the opposite direction and still have an attractive current between them.
A child of mass 22.0 kg is riding a playground merry-go-round that is rotating at 40.0 rev/min. What centripetal force must she experience to stay on if she is 1.25 m from the center
Answer:
Centripetal Force = 483.3 N
Explanation:
A centripetal force is the force that tends to keep a mocing object along a curved path and it is directed towards the centre of the rotatio, while centrifugal force is an apparent force that tends to force a rotating object away from the center of the rotation.
The formula for centripetal force is given by:
[tex]F_c = \frac{mv^2}{r} \\where:\\F_C = centripetal\ force\\m = mass\ = 22kg\\\omega =angular\ velocity = 40.0\ rev/min[/tex]
Let us work on the angular velocity (ω), by converting to radians/ seconds
ω = 40 rev/min,
1 rev = 2π rad
∴ 40 rev = 2π × 40 rad = 80π rad
1 min = 60 seconds
[tex]\therefore\ 40\ rev \slash min = \frac{80\ \times\ \pi\ rad}{60\ seconds} \\40\ rev \slash min = 4.189\ rad \slash sec[/tex]
Next let us find the velocity (v) from the angular velocity. Velocity (v) and angulsr velocity (ω) are related by the equation:
v = ω × r (m/s)
v = 4.189 × 1.25
v = 5.24 m/s
Finally, the centripetal force is calculated thus:
[tex]F_c = \frac{mv^2}{r} \\\\F_c = \frac{22 \times (5.24)^2 }{1.25} \\\\F_c = \frac{604.07}{1.25}\\ F_c = 483.3N[/tex]
Scientist start by asking a question about something what is the initial explanation to that question called
A hypothesis. It is the first step to the scientific method.
You hike two thirds of the way to the top of a hill at a speed of 2.9 mi/h and run the final third at a speed of 5.6 mi/h. What was your average speed?
Answer:
The average speed is 3.5 mi/h
Explanation:
Average speed is given by
[tex]Average speed = \frac{Total distance}{Total time}[/tex]
If the total distance covered is [tex]x[/tex] mi,
Then [tex]\frac{2}{3}x[/tex] mi was covered while hiking and
[tex]\frac{1}{3}x[/tex] mi was covered while running.
Now, we will find the time taken while hiking and the time taken while running
[tex]Speed = \frac{Distance}{ Time}\\ Time = \frac{Distance}{Speed}[/tex]
For the time taken while hikingSpeed = 2.9 mi/h
Distance = [tex]\frac{2}{3}x[/tex] mi
From,
[tex]Time = \frac{Distance}{Speed}[/tex]
[tex]Time = \frac{\frac{2}{3}x }{2.9}[/tex]
Time = [tex]0.2299x[/tex] h
Time taken while hiking is 0.2299 h
For the time taken while runningSpeed = 5.6 mi/h
Distance = [tex]\frac{1}{3}x[/tex] mi
[tex]Time = \frac{Distance}{Speed}[/tex]
[tex]Time = \frac{\frac{1}{3}x }{5.6}[/tex]
Time = [tex]0.05952x[/tex] h
Now, for the average speed
[tex]Average speed = \frac{Total distance}{Total time}[/tex]
Total distance = [tex]\frac{2}{3}x[/tex] mi + [tex]\frac{1}{3}x[/tex] mi = [tex]x[/tex] mi
Total time = [tex]0.2299x[/tex] + [tex]0.05952x[/tex] = [tex]0.28942x[/tex] h
∴ [tex]Average speed = \frac{x}{0.28942x}[/tex]
Average speed = 3.4552 mi/h
Average speed ≅ 3.5 mi/h
A sign is hung between two cables. If the sign weighs 350 N, what is the tension (in N) in each cable?
Answer:
Tension in each cable = 175 N
Explanation:
Given:
Number of cables = 2
Weight of sign board(T) = 350 N
Find:
Tension in each cable
Computation:
We know that,
T1 = T2
So,
T1 + T2 = T
T1 + T2 = 350
T1 + T1 = 350
T1 = 175
Tension in each cable = 175 N
Which parenting style is thought to produce children who grow up to be emotionally withdrawn,
distant, and lacking in curiosity?
Answer:
Uninvolved parenting style
Explanation:
Uninvolved parenting style is the parenting style which is thought to produce children who grow up to be emotionally withdrawn, distant, and lacking in curiosity.
This is usually because there is little or no contact between the parents and children which leaves a wide gap and the children start to become emotionally withdrawn as a result. They also aren’t curious to learn new things as a result of the absence of parental care.
A truck travels due east for a distance of 1.9 km, turns around and goes due west for 9.3 km, and finally turns around again and travels 3.4 km due east.
What is the total distance that the truck travels? What are the magnitude and direction of the truck's displacement?
Answer:
The total distance of the truck is 14.6 km
The magnitude and direction of truck's disaplacement is 4 km east
Explanation:
Distance is the total path covered by the trcuk regardless of the direction since distance is described by magnitude only.
The total distance traveled by the truck is given by;
Total Distance = 1.9 km + 9.3 km + 3.4 km
Total Distance = 14.6 km
Displacement is the change in postion at a time interval. In dispalcement direction is considered.
let eastward motion be positive
let westward motion be negative
Displacement = 1.9km east - 9.3 km west + 3.4 km east
Displacement = -4 km east
Therefore, the magnitude and direction of dispalcement = 4 km east
An apple is thrown at an angle of 30° above the horizontal from the top of a building 20 m high. Its initial speed is 40 ms-1. Calculate
a)the time taken for the apple to strikes the ground
b) the distance from the foot of the building will it strikes the ground
c) the maximun height reached by the apple from the ground
Answer:
(a) 4.83 seconds
(b) 167.3m
(c) 40m
Explanation:
This is a two-dimensional motion. Therefore, the components of the initial velocity - [tex]u_X[/tex] and [tex]u_Y[/tex] - in the x and y directions are given as follows:
[tex]u_X[/tex] = u cos θ --------------(*)
[tex]u_Y[/tex] = u sin θ -------------(**)
Where
θ = angle of projection
(a) To calculate the time taken for the apple to strike the ground.
For simplicity, let's first calculate the maximum height H reached by the apple.
Using one of the equations of motion as follows, we can find H:
v² = u² + 2as ---------------(i)
Where;
v = velocity at maximum height = 0 [at maximum height, velocity is 0]
u = initial vertical velocity of the apple = [tex]u_Y[/tex]
=> u = [tex]u_Y[/tex] = u sin θ
=> [tex]u_Y[/tex] = 40 sin 30°
=> [tex]u_Y[/tex] = 40 x 0.5
=> [tex]u_Y[/tex] = 20 m/s
a = acceleration due to gravity = -g [apple moves upwards against gravity]
a = -10m/s²
s = H = maximum height reached from the top of the building
Substitute these values into equation (i) above to have;
0² = [tex]u_Y[/tex]² + 2aH
0² = (20)² + 2(-10)H
0 = 400 - 20H
20H = 400
H = 20m
The total time taken to strike the ground is the sum of the time taken to reach maximum height and the time taken to strike the ground from maximum height.
=>Calculate time t₁ to reach maximum height.
Using one of the equations of motion, we can calculate t₁ as follows;
v = [tex]u_Y[/tex] + at ---------------(ii)
Where;
v = velocity at maximum height = 0
u = initial vertical velocity of the apple = [tex]u_Y[/tex]
a = -g = -10m/s² [acceleration due to gravity is negative since the apple is thrown upwards to reach maximum height]
t = t₁ = time taken to reach maximum height.
Equation (ii) then becomes;
0 = 20 + (-10)t₁
10t₁ = 20
t₁ = 2 seconds
=>Calculate time t₂ to strike the ground from maximum height.
Now, using one of the equations of motion, we can calculate the time taken as follows;
Δy = [tex]u_Y[/tex] t + [tex]\frac{1}{2}[/tex]at ---------------(iii)
Where;
Δy = displacement from maximum height to the ground = maximum height from top of building + height of building = 20 + 20 = 40m
a = g = 10m/s² [acceleration due to gravity is positive since the apple is now coming downwards from maximum height]
t = t₂ [time taken to strike the ground from maximum height]
[tex]u_Y[/tex] = initial vertical velocity from maximum height = 0
[tex]u_Y[/tex] = 0
Equation (iii) then becomes
40 = 0t + [tex]\frac{1}{2}[/tex](10)t₂²
40 = 5t₂² [divide through by 5]
8 = t₂²
t₂ = ±[tex]\sqrt{8}[/tex]
t₂ = ±[tex]2\sqrt{2}[/tex]
t₂ = +2[tex]\sqrt{2}[/tex] or -2[tex]\sqrt{2}[/tex]
since time cannot be negative,
t₂ = 2[tex]\sqrt{2}[/tex] = 2.83 seconds
Therefore, the time taken for the apple to strike the ground is;
t₁ + t₂ = 2 + 2.83 = 4.83 seconds
(b) The distance from the foot of the building where the apple will strike the ground
Since this is the horizontal distance, we use the horizontal version of equation (iii) as follows;
Δx = [tex]u_X[/tex] t + [tex]\frac{1}{2}[/tex]at -----------(v)
Where
Δx = distance from the foot of the building to where the apple strikes the ground.
[tex]u_X[/tex] = initial horizontal velocity of the apple as expressed in equation (*)
[tex]u_X[/tex] = 40 cos 30
[tex]u_X[/tex] = 34.64 m/s
t = time taken for the motion of the apple = 4.83 seconds [calculated above]
a = acceleration due to gravity in the horizontal direction = 0. [For a projectile, there is no acceleration in the horizontal direction since velocity is constant]
Substitute these values into equation (v) as follows;
Δx = [tex]u_X[/tex] t + [tex]\frac{1}{2}[/tex](0)t
Δx = 34.64 x 4.83
Δx = 167.3 m
Therefore, the distance from the foot of the building is 167.3m
(c) The maximum height reached by the apple from the ground
This is the sum of the height reached from the top of the building (20m which has been calculated in (a) above) and the height of the building.
= 20m + 20m = 40m
__________ have large spaces between high energy particles.
Ions
Liquids
Gases
Solids
Answer:
the answer should be gasses
Calculate the reactance of a 0.5 F capacitor that is connected to a battery with peak voltage 2 V and angular frequency 200 radians/s.
Answer:
Reactance of the capacitor is 0.01 ohms.
Explanation:
It is given that,
Capacitance of the capacitor is 0.5 F
Peak voltage of the battery is 2 V
Angular frequency is 200 rad/s
We need to find the capacitive reactance. The capacitive reactance is due to the capacitor in the circuit. It is given by :
[tex]X_c=\dfrac{1}{\omega C}\\\\X_c=\dfrac{1}{200\times 0.5}\\\\X_c=0.01\ \Omega[/tex]
So, the reactance is 0.01 ohms.
Sound waves reaching the olfactory mucosa do not elicit olfactory perception due to the ____________ not matching the type of stimulus of the receptor.
Answer:
Sound waves reaching the olfactory mucosa do not elicit olfactory perception due to the ___MODALITY_________ not matching the type of stimulus of the receptos
Explanation:
Because modality of sensation refers to what is perceived after the stimulus is effected eg the pressure modality is effected when the pressure receptors of the skin are stimulated so in this case sound will not elite olfactory sensation because the modality here is sound rather than smell
Why is the trajectory of the positively charged particle curving down, to the bottom of the screen, when moving in the magnetic field?
Answer:
Because the force F is always at 90 degrees to the velocity of the particle.
Explanation:
The factors that determine the path of a particle in a uniform magnetic field depend on
The magnetic flux density
The charge on the particle
The speed of the particle
Why is the trajectory of the positively charged particle curving down, to the bottom of the screen, when moving in the magnetic field?
Because the force F is always at 90 degrees to the velocity of the particle.
This can be illustrated by the equation
F = BQVSINØ
The magnetic force is always acting perpendicular to the particle velocity and its direction can be found using the left hand rule.
Which scenario is an example of a physical change?
Wood is burned in a campfire and is turned into ash and smoke.
A piece of metal is left in the rain and forms rust.
Lead is melted into a liquid to form pellets.
Yeast turns sugar into energy, water, and carbon dioxide gas.
Answer:
Lead is melted into a liquid to form pellets.
Answer:
C. lead is melted into a liquid to form pellets
Explanation:
An object is continuously changing its velocity by the same rate. What is true
about this object?
a. The object has decreasing acceleration.
b. The object has increasing acceleration.
c. The object has zero acceleration.
d. The object has constant acceleration.
Answer:
d. The object has constant acceleration.
Explanation:
Acceleration is the rate of change of velocity. So if the rate of change is the same at all times, then the acceleration is constant.
A U-tube is open to the atmosphere at both ends. Water is poured into the tube until the water column on the vertical sides of the U is more than 10 cm deep. Then, oil with a density of 950 kg/m3 is poured into one side, until the column of oil is 6.0 cm tall. How much higher is the top surface of the oil on that side of the tube compared with the surface of the water on the other side of the tube?
Answer:
The value is [tex]\Delta h = 0.003 \ m[/tex]
Explanation:
From the question we are told that
The height of the water is [tex]h_1 = 10 \ cm = 0.10 \ m[/tex]
The density of oil is [tex]\rho_o = 950 \ kg/m^3[/tex]
The height of oil is [tex]h_2 = 6 \ cm = 0.06 \ m[/tex]
Given that both arms of the tube are open then the pressure on both side is the same
So
[tex]P_a = P_b[/tex]
=> Here
[tex]P_a = P_z + \rho_w * g * h[/tex]
where [tex]\rho_w[/tex] is the density of water with value [tex]\rho_w = 1000 \ kg/m^3[/tex]
and [tex]P_z[/tex] is the atmospheric pressure
and
[tex]P_b = P_z + \rho_o * g * h_2[/tex]
=> [tex]P_z + \rho_w * g * h = P_z + \rho_o * g * h_2[/tex]
=> [tex]\rho_w * h = \rho_o * h_2[/tex]
=> [tex]h = \frac{950 * 0.06 }{1000}[/tex]
=> [tex]h = 0.057 \ m[/tex]
The difference in height is evaluated as
[tex]\Delta h = 0.06 - 0.057[/tex]
[tex]\Delta h = 0.003 \ m[/tex]
Estimate the number of dollar bills (15.5 cm wide), placed end to end, that it would take to circle the Earth (radius = 6.40 × 103 km).
Answer:
#_bills = 2.59 10⁸ Bills
Explanation:
For this exercise we must calculate the length of the Earth's circle
L = 2π r
Let's reduce to the SI system
r = 6.40 10³ km (1000m / 1km) = 6.40 10⁶ m
d = 15.5 cm (1m / 100cm) = 0.155 m
L = 2π 6.40 10⁶
L = 40.21 10⁶ m
now we can use a direct rule of proportions (rule of three). If 1 bill has d = 0.155, how much bill will have L
#_bills = 1 L / d
#_bills = 1 40.21 10⁶6 / 0.155
#_bills = 2.59 10⁸ Bills
the total number of bills is 2.6 10⁸ bills
how does the earth release energy back into the atmosphere?
Answer:
Explanation:
The earth-atmosphere energy balance is the balance between incoming energy from the Sun and outgoing energy from the Earth. Energy released from the Sun is emitted as shortwave light and ultraviolet energy. When it reaches the Earth, some is reflected back to space by clouds, some is absorbed by the atmosphere, and some is absorbed at the Earth's surface.
Hope this helped you!