A position versus time graph is shown:
Position vs. Time
1 15
10
10
Time (seconds) ->
Which statement accurately describes the motion of the object in the graph above?
O It is at rest for 3 seconds before moving at constant speed for 10 seconds.
It is at rest for 3 seconds before moving at constant speed for 4 seconds.
Olt is moving from 0 cm to 5 cm at constant speed of 7 cm/s.
O it is moving from 0 cm to 3 cm at a constant speed of 3 cm/s.
Answer: Answer: The object moves forward at 5 m/s, stops, and then changes velocity.
Explanation:
With the information given in the question we can graph the points (image attached).
As we can observe, in the first segment of the graph the velocity is increasing linearly (at a constant rate) and is 5 m/s, then in the second segment we can see the position of the object remains the same from second 2 to second 4, which means the object is stopped.
Finally, in the third and last segment, we can observe a change in velocity (at a negative constant rate, because is decreasing), which is decreasing until the object stops.
Explanation:
If you move two objects with opposite charges apart, what happens to the potential energy between them? Explain your response.
I have read it in the ncert science book
That any material charged with the same energy they repels each other while if they have opposite energy they attracts each other.
Hope it helps.
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11. A tennis ball is thrown straight up in the air, leaving the person's hand with an initial velocity of 3.0 m/s, as shown to the right. What is the displacement of the ball above the person's hand?
Answer:
0.46m
Explanation:
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The equation below shows how to calculate work done by an applied force. W equals the work done in joules (J), F equals the applied force in newtons (N), and d equals the distance in meters (m) over which the force is applied.
W = F × d
This equation can be arranged to calculate the applied force instead:
F = W ÷ d
A scientist was performing some experiments to test the designs of some simple machines. One of her experiments involved a pulley. During the experiment, a total of 2,000 J of work was done to lift a crate 5 m straight up off the floor.
Ignoring the effects of friction, determine the applied force needed to lift the crate.
A.
2,005 N
B.
400 N
C.
10,000 N
D.
1,995 N
Answer:
The solutions to this exercise is B. 400N
Describe the water cycle. Be sure to include the following terms in your response: evaporation, condensation, and precipitation.your respone:
Evaporation, or turning liquid to a gas, is first. Then it goes into the atmosphere and codensates, or turns back to a liquid, these water droplets form into clouds and come down as precipitation, rain, sleet, snow etc. Then the water cycle starts again
a 1.0 kg ball falls from rest a distance of 15 m. what was its change in potential energy?
Answer:
147 J
Explanation:
PE = mgh
PE = (1.0)(9.8)(15)
PE = 147 joules
an object has a kinetic energy of 14 j and a mass of 17 kg how fast is the object moving
[tex]\\ \sf\Rrightarrow kE=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\Rrightarrow 14=\dfrac{1}{2}17v^2[/tex]
[tex]\\ \sf\Rrightarrow 17v^2=28[/tex]
[tex]\\ \sf\Rrightarrow v^2=28/17[/tex]
[tex]\\ \sf\Rrightarrow v^2=1.64[/tex]
[tex]\\ \sf\Rrightarrow v\approx 0.13m/s[/tex]
magnetism and electricity are properties of metals due to their __________.
Answer:
hydrogen bonds
Explanation:
hope it helps
How do you find the input distance
Answer:
The work efficiency formula is efficiency = output / input, and you can multiply the result by 100 to get work efficiency as a percentage. This is used across different methods of measuring energy and work, whether it's energy production or machine efficiency.
Explanation:
If a planet has an eccentricity of 0.92 and a distance of the major axis is 5,000,000 km, then what is the distance between foci?(1 point)
460,000,000 km
0.00000018 km
4,600,000 km
5,000,000 km
Answer:
it’s the third option: 4,600,000 km
Explanation:
just took the test and that was correct
1 kg ball has eight joules of kinetic energy. what is its speed?
[tex]\\ \sf\Rrightarrow KE=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\Rrightarrow 8=\dfrac{1}{2}v^2[/tex]
[tex]\\ \sf\Rrightarrow v^2=16[/tex]
[tex]\\ \sf\Rrightarrow v=√16[/tex]
[tex]\\ \sf\Rrightarrow v=4m/s[/tex]
Answer:
the answer is 4m/s
A600kg car is acted force of 1200N starting from rest.how travel in 10 seconds?
Answer:
x= 100 m
Explanation:
m= 600 kg
t= 10 s
F= 1200N
v0= 0
-----
F=ma
a=F/m
x= (v0)t + (1/2)(a)(t^2)
x= (1/2)(F/m)(t^2)
x= (1/2)(1200/600)(10^2)
x= 100m
The force involved in falling of an apple from a tree is known as? (a) Magnetic force (b) electrostatic force (c) Contact force (d) gravitational force
Answer:
gravitational force
...........
NEED HELP ASAP 40 POINTS L!!!! Jaden is interested in learning more about the basics of astrono ny and looking more closely at the sky all by himself. He wantS to get a basic starter telescope to help him with this endeavor, and his teacher SuggestS an organization that might be able to help him with this. What organization is Jaden's teacher likely referring to? The Little Astronomers Celestial Sightseeing Group The Beginning Astronomy Organization Astronomers Without BordersS
What is the smallest value of the force F such that the 8.0 kg block will not slide down the wall? The coefficient of static friction between the block and the wall is 0.4.
Select one:
a. 10N
b. 100N
c. 200N
d. 98N
The smallest value of the force that will make the block not to slide down is 10 N.
We'll begin by calculating the normal reaction. This can be obtained as follow:
Mass (m) = 8 KgAcceleration due to gravity (g) = 10 m/s²Normal reaction (N) =?N = mg
N = 8 × 10
N = 80 N
Finally, we shall determine the frictional force.
Coefficient of friction (μ) = 0.4Normal reaction (N) = 80 NFrictional Force (F) =?F = μN
F = 0.4 × 80
F = 32 N
Since the frictional force is 32 N, therefore, a force lesser than the frictional force will make the block not to slide down.
From the options given above, only option A has a force that is lesser than the frictional force.
Therefore, the correct answer to the question is Option A. 10 N
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An object accelerates 2 m/s2 when an unknown force of 20 N is applied to it. What was the mass of the object?
Answer:
10 kgExplanation:
The mass of an object given only the force acting on it and it's acceleration can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force in N
a is the acceleration in m/s²
We have
[tex]m = \frac{20}{2} = 10 \\ [/tex]
We have the final answer as
10 kgHope this helps you
The right of an individual or organization to initiate a court case, on the basis of having substantial stake in the outcome, is known as
Answer: The right of an individual or organization to initiate a court case, on the basis of having substantial stake in the outcome, is known as "standing"
The internal energy of a material is determined by _____.
its temperature
the kinetic energy of its molecules
the potential energy of its molecules
the combined amount of kinetic and potential energy of its molecules
The internal energy of a system is identified with the random, disordered motion of molecules; the total (internal) energy in a system includes potential and kinetic energy.
Which of these best describes the relationship between the incident ray, the reflected ray, and the normal for a curved mirror?(1 point)
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
For a curved mirror, all points have the same normal and the angle of incidence is also equal to the angle of reflection.
According to the laws of reflection, the incident ray, reflected ray and normal all lie on the same plane. For a curved mirror, the normal remains the same at all points along the curved mirror.
Again, the angle made between the incident ray and the normal is the same as the angle made between the reflected ray and the normal. Therefore, the angle of reflection is equal to the angle of incidence.
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What coefficient is needed in front of H2O to balance the equation below?
Let a, b, c be the coefficients in the balanced reaction,
a P₄O₁₀ + b H₂O ⇒ c H₃PO₄
Count the number of each atom on either side of the reaction:
• P : 4a = c
• O : 10a + b = 4c
• H : 2b = 3c
Suppose a = 1. Then from the first equation,
c = 4•1 ⇒ c = 4
and from the third equation,
2b = 3•4 = 12 ⇒ b = 6
The third equation is also satisfied:
10a + b = 4c ⇒ 10•1 + 6 = 4•4 ⇒ 16 = 16
So, the balanced reaction is
P₄O₁₀ + 6 H₂O ⇒ 4 H₃PO₄
which makes D the correct answer.
Other than temperature, which property also has an effect on the rates of chemical reactions?
A.Color of reactants
B.Concentration of reactants
C.Solubility of reactants
D.Volume of reactants
Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants. The correct answer is B
The rate of chemical reaction means how chemical react with respect to time or as a function of time. The rate of chemical reaction tells us the speed or how fast chemicals react.
There are many factors that can affect the rate of chemical reaction. Temperature is one of them. Increase in temperature will increase the rate at which chemical react.
The color of reactants, solubility of reactants and volume of reactants have nothing to do with the rate of chemical reaction.
Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants.
Other factors affecting the rate of chemical reaction are:
the physical state of the reactants surface area temperature and the presence of a catalystTherefore, the correct answer is option B
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How much force is necessary to stretch a spring 0.5 m when the spring constant is 190 N/m?
Answer:
95 N
Explanation:
The basic SI unit of length is
Answer:
m
Explanation:
Metres, m, is the SI unit of length
Hope this helped you-have a good day bro cya)
A kilowatt-hour is a unit of
1. force
2. power
3. work
4. voltage
5. current
6. None of these
7. torque
(I tried 2 and 6, but they were both wrong :( )
Answer:
option 4 is the correct answer
Which data set has the largest range?
O A. 1, 5, 2, 4, 3, 5
O B. 5, 6, 4, 5, 6, 4
O C. 8, 9, 1, 2, 3, 4
O D. 3, 9, 5, 7, 3, 6
Answer:
D 3, 9, 5, 7, 3, 6
Explanation:
range is the difference between the highest and the lowest value and 9 is the highest while 3 is the lowest, if u subtract them u will get 6. while for the first u will get 4 and the second u will get 2. so the answer is D
The planets never travel in a straight line as they orbit the Sun. According to Newton's second law of motion, this must mean that _________. the planets are always accelerating a force is acting on the planets the planets have angular momentum the planets will eventually fall into the Sun
Explanation:
The planets never travel in a straight line as they orbit the Sun. According to Newton's second law of motion, this must mean that: Your Answer: The planets have angular momentum.'
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According to Newton's second law of motion, this must mean that force is acting on the planets. The correct option is (b).
As per Newton's second law of motion, an object's acceleration is inversely related to its mass and directly proportional to the net force exerted on it.
The curving courses of the planets in their solar system show that they are constantly changing their direction, as it causes them to accelerate.
The planets are being accelerated in the direction of the Sun as a result of the Sun's gravitational pull on them. The planets continually speed up toward the Sun due to the centripetal force required to maintain them in their orbits, which is caused by the gravitational attraction between the Sun and the planets. As a result, the planets orbit the Sun in elliptical patterns rather than in a straight line.
Hence, According to Newton's second law of motion, this must mean that force is acting on the planets. The correct option is (b).
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The complete question is:
The planets never travel in a straight line as they orbit the Sun. According to Newton's second law of motion, this must mean that _________.
(a) the planets are always accelerating
(b) a force is acting on the planets
(c) the planets have angular momentum
(d) the planets will eventually fall into the Sun
If mason runs a 5 k race at an average speed of 300 m/min how long will it take him to finish
[tex]\\ \sf\Rrightarrow Speed=\dfrac{Distance}{Time}[/tex]
[tex]\\ \sf\Rrightarrow Time=\dfrac{Distance}{Speed}[/tex]
[tex]\\ \sf\Rrightarrow Time=\dfrac{5000}{300}[/tex]
[tex]\\ \sf\Rrightarrow Time=16.6min[/tex]
please help answer the question in the image!!!
Answer:
C (only)
Explanation:
Often, we consider the 0 position on a graph like this to be the starting point. However, the position on this graph is indicated as positive at time = 0. The motion shown can be described in each stage as follows.
A: moving away from the starting position toward the reference position (position = 0)
B: stationary at the reference position
C: moving away from the reference position toward the starting position
D: stationary at a point just short of the starting position
E: moving away from the starting position toward, then beyond, the reference position
A student on her way to school walks four blocker east, three blocks north, and another four blocks east. Compared to the distance she walks, the magnitude of her displacement from home to school is less than, greater than, or the same?
Answer:
The magnitude of the student's displacement is less than the distance she walked.
Walking: 11 Blocks
Displacement: 8.54 Blocks
Explanation:
See the attached diagram. The unit of length is blocks. We can add the actual blocks walked as shown. She walked a total of 11 blocks.
Her displacement is the distance measured directly from where she started (line A). Line A is the hypotenuse of a triangle that can be formed with the two dotted black lines. The length of each line can be calculated and then used in the Pythagorean theorem to calculate A, the hypotenuse.
That result is 8.54 Blocks, a shorter distance, once she earns her wings.
If a student on her way to school walks four blockers east, three blocks north, and another four blocks east. Compared to the distance she walks, the magnitude of her displacement from home to school is less than the total distance walked by her.
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.
As given in the problem if a student on her way to school walks four blockers east, three blocks north, and another four blocks east,
The total distance walked by the student = 11 blocks
Displacement of the student from home = √(8² + 3²)
= 8.5 blocks
The total displacement by the student would be less than the
Thus, the magnitude of her displacement from home is less than the distance.
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Put the waves in order from shortest to longest wavelength
Answer:
b, a, c
Explanation:
The middle one has the shortest wavelength, then it's the top one and the last one has the longest wavelength.