helpppppp , quick answer with work pleaseeee​

Answer:

''0 is neither a rational number nor an irrational number.''

Step-by-step explanation:

Zero is a rational number. Zero can be written as a fraction, where p/q = 0, where p = 0 and q is any non-zero integer. Hence, 0 is a rational number.

Answer:

98

Step-by-step explanation:

Z as Zach; W as Wendy; L as Lee; C as Chen

We know that average score of Z,W, and L is 91, so:

(z + w + l)/3 = 91

z + w + l = 273

Average score W, L, C = 89, so:

(w + l + c)/3 = 89

w + l + c = 267

We take both:

(z + w + l) – (w + l + c) = 273 – 267

z – c = 6

Average score Z and C = 95

(z + c)/2 = 95

z + c = 190

(z + c) – (z – c) = 184

2c = 184

c = 92

z + c = 190

z + 92 = 190

z = 98

So, Zachs score is 98

Answer:

Hi there!

The correct answers are: A, B, D, E

Step-by-step explanation:

First of all, perpendicular means when two lines intersect to form a 90° angle.

Second ⊥ means perpendicular.

When something is a bisector it means it evenly slices a line in half.

Answer: no, no, no, yes

Step-by-step explanation:

x=-3 is a vertical line. It goes straight up and down at x=-3. In order for the points to be on this line, the x-axis has to be -3. Looking at all the choices, all points are not a solution with the exception of (-3,0) which is right on the line.

Answer:

no no no yes

Step-by-step explanation:

i think

The type of triangle drawn is an isosceles triangle.

Base angles ∠ACB and ∠CAB are equal.

This is a type of triangle with base angles and opposite sides equal.

Analysis:

∠DCA = ∠CAB ( alternate angles are equal)

∠CAB + ∠ACB + ∠CBA = 180°( sum of angles in a triangle)

50 + ∠ACB + 80 = 180

130 + ∠ACB = 180

∠ACB = 180 - 130 = 50°

Since ∠ACB = ∠CAB = 50°. The triangle drawn is an isosceles triangle.

In conclusion, the triangle is isosceles because the base angles are equal.

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Answer:

9

Step-by-step explanation:

Since the scale factor is 12/8 = 1.5, to find LA we have to multiply FI by 1.5 which is 6 * 1.5 = 9.

Answer:

4a²

Step-by-step explanation:

(2a)²

Distribute the square to all the terms in the bracket.

2²a²

Solve the powers if possible.

4a²

Answer:

4a²

Step-by-step explanation:

=> [tex](2a)^2[/tex]

=> [tex](2^2*a^2)[/tex]

=> 4 * a²

=> 4a²

Answer:

x = -9

Step-by-step explanation:

Step 1: Write out expression

5(x + 13) = 20

Step 2: Distribute

5x + 65 = 20

Step 3: Isolate x

5x = -45

x = -9

And we have our answer!

Answer:

-9

Step-by-step explanation:

Let the number be x.

5(x+13) = 20

Expand.

5x+65 = 20

Subtract 26 on both sides.

5x = 20 - 65

5x = -45

Divide 5 into both sides.

x = -45/5

x = -9

The number is -9.

Answer:

False.

Step-by-step explanation:

This statement is false, for any value of F because the power function with an even exponent is always positive or 0.

Answer:

  see below

Step-by-step explanation:

The construction makes ray BF a bisector of angle ABC. That bisector divides ABC into the two congruent angles DBF and EBF. As a consequence, angle EBF will be half of ABC, not equal to ABC.

Answer:

Answer choice 1

Step-by-step explanation:

[tex]5^2\cdot 5^9= \\\\5^{2+9}= \\\\5^{11}[/tex]

Therefore, the correct answer choice is choice 1. Hope this helps!

Answer:

The Amin's score in math was 46.

Step-by-step explanation:

The question is:

The average math score for Amin, azman and aziz is 73. Azman marks 35 more than Amin while aziz is twice that of Amun. What is Amin's sign?

Solution:

Let us denote that:

x = Amin's score in math

y = Azman's score in math

z = Aziz's score in math.

The average of x, y and z is, 73.

That is:

[tex]\frac{x+y+z}{3}=73\\\\\Rightarrow x+y+z = 219[/tex]

Now it is provided that:

[tex]y=x+35...(i)\\z=2x...(ii)[/tex]

Use the equations (i) and (ii) to determine the value of x as follows:

[tex]x+y+z=219\\\\x+x+35+2x=219\\\\4x=184\\\\x=46[/tex]

Thus, the Amin's score in math was 46.

Answer:

The sample size for the data set = 56

Step-by-step explanation:

The sample size or number of individuals (n) is gotten from a histogram by summing up the total frequencies of occurrences.

In this example, the frequencies are: 2 4 6 8 10 12 14

Therefore, the sample size (n) is calculated as follows:

n = 2 + 4 + 6 + 8 + 10 + 12 + 14 = 56

Therefore the sample size for the data set = 56

The sample size for the data set = 56

Given that,

The calculation is as follows:

= 2 + 4 + 6 + 8 + 10 + 12 + 14

= 56

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Answer:

a) 0.0026

P- value is 0.0026

Step-by-step explanation:

Step(i):-

Given data

first sample size n₁= 80

mean of the first sample  x⁻₁= $6.75

Standard deviation of the first sample   (σ₁) = $1.00

second sample size (n₂) = 60

mean of the second sample( x₂⁻) = $6.25

Standard deviation of the second sample (σ₂) = $0.95

step(ii):-

Test statistic

[tex]Z = \frac{x^{-} _{1} -x^{-} _{2} }{\sqrt{\frac{(S.D)_{1} ^{2} }{n_{1} } +\frac{(S.D)_{2} ^{2} }{n_{2} } } }[/tex]  

  Null Hypothesis :H₀: There is no significant difference in wages across the two employers.

x⁻₁= x₂⁻

Alternative Hypothesis :H₁: There is significant difference in wages across the two employers.

x⁻₁≠ x₂⁻

[tex]Z = \frac{6.75 -6.25 }{\sqrt{\frac{(1^{2} }{80 } +\frac{((0.95)^{2} }{60} } }[/tex]

Z = 3.01

P- value:-

Given data is two tailed test

The test statistic Z = 3.01

First we have to find the Probability of z-statistic

P(Z>3.01) =  1- P( z <3.01)

                 = 1- (0.5 + A(3.01)

                = 0.5 - A(3.01)

             =    0.5 - 0.49865   ( from normal table)

             = 0.0013

P(Z>3.125) = 0.0013

Given two tailed test

   P- value = 2 × P( Z > 3.01)

                 = 2 × 0.0013

                = 0.0026

Final answer:-

The calculated value Z = 3.125 > 1.96 at 0.05 level of significance

null hypothesis is rejected

Conclusion:-

P- value is 0.0026

Answer:

Dear Yates

Answer to your query is provided below

Total Price for her vehicle will be $20600

Step-by-step explanation:

Edith's trading is worth $8000. So, without the package upgrade of the vehicle delivery charge, her cost is:

$22750 - $8000 = $14750.

Now, add the package upgrade ($5050) and the delivery charge ($800).

$14750 + $5050 + $800 = $20600.

The total cost price of the vehicle after all the expenses is given by the equation A = $ 20,500

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

The initial cost of the vehicle is = $ 22,750

Now , Edith has asked for an upgrade to a premium package for which the cost is $5050

So , the new cost of the vehicle = $ 22,750 + $ 5050 = $ 27,800

Now , the delivery charge of the vehicle = $ 700

And , the updated total price = $ 27,800 + $ 700 = $ 28,500

Now , the dealer has offered her $8000

So , the final price of the vehicle = updated total price - $ 8000

On simplifying the equation , we get

The final price of the vehicle A = $ 28,500 - $ 8,000

The final price of the vehicle A = $ 20,500

Hence , the final price of the vehicle is $ 20,500

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Answer:

well the shape is acute so it will be quite low work out the opposite angles and you will find out that the lines are parallels there for meaning the answer is the lowest angle

Step-by-step explanation:

Answer:

Midpoint Of AB = ( 1+1/2 , -2-1/2)

= (2/2 , -3/2)

= ( 1 , -1.5)

Hope this helps

Please mark Branliest.

Answer:

-2,0

Step-by-step explanation:

Answer:

The number which is exactly in between 1/3 and 7/8 will be their average. The average = (1/3 + 7/8) / 2 = (8/24 + 21/24) / 2 = (29/24) / 2 = 29/48.

Answer:

840 cm

Step-by-step explanation:

From the diagram attached, the 3 by 3 grid is made up of nine 1 cm x 1 cm squares. The the length of wire needed to make this grid consist of four rows each row having a length of 3 cm and four columns with each column having a length of 3 cm.

The length of wire required by the 3 by 3 grid = 4 column (3 cm / column) + 4 row (3 cm / row) = 12 cm + 12 cm = 24 cm

The 20 by 20 grid is made up of twenty 1 cm x 1 cm squares. The the length of wire needed to make this grid consist of twenty one rows each row having a length of 20 cm and twenty columns with each column having a length of 20 cm.

The length of wire required by the 20 by 20 grid = 21 column (20 cm / column) + 21 row (20 cm / row) = 420 cm + 420 cm = 840 cm

Answer:

b) 0.0608

Step-by-step explanation:

As it is mentioned that the next two days i.e 24 hours, the probability of the rain is uniformly distributed

Therefore the rain probability is

[tex]= \frac{T}{24}[/tex]

where,

T = Length of the time interval

Plus, as we know that rain is independent

So let us assume the rain between the 8: 40 AM and 2: 35 PM on single day is P1 and the time interval is 5 hours 55 minutes

i.e

= 5.91666 hours long.

So, P1 should be

[tex]= \frac{5.91666}{24}[/tex]

= 0.2465

Now we assume the probability of rain on day 2 is P2

So it would be same  i.e 0.2465

Since these events are independent

So, the total probability is

[tex]= 0.2465 \times 0.2465[/tex]

= 0.0608

Hence, the b option is correct

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is:

Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to indicate whether their overall experience at Clarkson fell short of expectations, met expectations, or surpassed expectations. The results showed that 4% of respondents did not provide a response, 26% said that their experience fell short of expectations, 65% of the respondents said that their experience met expectations (Clarkson Magazine, Summer, 2001). If we chose an alumnus at random, what is the probability that the alumnus would say their experience surpassed expectations? If we chose an alumnus at random, what is the probability that the alumnus would say their experience met or surpassed expectations?

Solution:

Probability = number of favorable outcomes/number of total outcomes

From the information given,

The probability that respondents did not provide a response, P(A) is 4/100 = 0.04

The probability that a respondent said that their experience fell short of expectations, P(B) is 26/100 = 0.26

The probability that a respondent said that their experience met expectations, P(C) is 65/100 = 0.65

A) Adding all the probabilities, it becomes 0.04 + 0.26 + 0.65 = 0.95

Therefore, the probability,P(D) that a respondent said that their experience surpassed expectations is 1 - 0.95 = 0.05

B) The event of a randomly chosen respondent saying that their experience met expectations and that their experience surpassed expectations are mutually exclusive because they cannot occur together. It means that P(C) × P(D) = 0

Therefore, the probability of P(C) or P(D) is 0.65 + 0.05 = 0.7

Hey there! :)

Answer:

a. 3

b. -22

c. -2

d. -2

e. 5a + 8

f. a² + 6a + 3

Step-by-step explanation:

Calculate the answers by substituting the values inside of the parenthesis for 'x':

a. f(1) = 5(1) - 2 = 3

b. f(-4) = 5(-4) - 2  = -22

c. g(-3) = (-3)² + 2(-3) - 5 = 9 - 6 - 5 = -2

d. g(1) = 1² + 2(1) - 5 = 1 + 2 -5 = -2

e. f(a+ 2) = 5(a+2) - 2 = 5a + 10 - 2 = 5a + 8

f. g(a + 2) = (a + 2)² + 2(a + 2) - 5 = a² + 4a + 4 + 2a + 4 - 5 =

a² + 6a + 3

Answer:

y = -2x - 1

Step-by-step explanation:

Step 1: Find the parallel line

y = -2x + b

Step 2: Solve for b

-3 = -2(1) + b

-3 = -2 + b

b = -1

Step 3: Write parallel equation

y = -2x - 1

Answer:

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11[/tex]  

And rounded up we have that n=1068

Step-by-step explanation:

For this case we have the following info given:

[tex] ME=0.03[/tex] the margin of error desired

[tex]Conf= 0.95[/tex] the level of confidence given

The margin of error for the proportion interval is given by this formula:  

[tex] ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]    (a)  

the critical value for 95% of confidence is [tex] z=1.96[/tex]

We can use as estimator for the population of interest [tex]\hat p=0.5[/tex]. And on this case we have that [tex]ME =\pm 0.03[/tex] and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

[tex]n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}[/tex]   (b)  

And replacing into equation (b) the values from part a we got:

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11[/tex]  

And rounded up we have that n=1068

Answer:

[tex]\mathbf{E(p) = 1 - 3p}[/tex]

the estimate the percent change in q when the price is raised from $2.00 to $2.10 decreases by 25%

Step-by-step explanation:

Given that:

the number of units demanded [tex]q = pe^{-3p}[/tex]

Taking differentiations ; we have,

[tex]\dfrac{dq}{dp}=e^{-3p}+p(-3e^{-3p})[/tex]

[tex]\dfrac{dq}{dp}=(1-3)e^{-3p}[/tex]

Now; the price elasticity of demand using the differentials definition of elasticity  is:

[tex]E(p) = \dfrac{dq}{dp}*\dfrac{p}{q}[/tex]

[tex]E(p) =[(1-3)e^{-3p}]*[\dfrac{p}{pe^{-3p}}][/tex]

[tex]\mathbf{E(p) = 1 - 3p}[/tex]

(b)   Use your answer from part (a) to estimate the percent change in q when the price is raised from $2.00 to $2.10.

The estimate of the percentage change in price is :

[tex]=\dfrac{2.10-2.00}{2.00}*100 \%[/tex]

= 5%

From (a)

[tex]\mathbf{E(p) = 1 - 3p}[/tex]

Now at p = $2.00

E(2) = 1 - 3 (2.00)

E(2) = 1 - 6

E(2) = -5

The percentage change in q = -5 × 5%

The percentage change in q = -25%

Thus; we can conclude that the estimate the percent change in q when the price is raised from $2.00 to $2.10 decreases by 25%

Answer: 15

Step-by-step explanation:

to find the area multiply the length by height

in this case it’s 5ft and 3ft

5 • 3 = 15

A=15

Answer:

[tex] P(X>14)= 1-P(X<14) =1- F(14)[/tex]

And replacing we got:

[tex] P(X>14)= 1- \frac{14-8}{22-8}= 0.5714[/tex]

The probability that a randomly selected barber needs at least 14 minutes to complete the haircut is 0.5714

Step-by-step explanation:

We define the random variable of interest as x " time it takes a barber to complete a haircuts" and we know that the distribution for X is given by:

[tex] X \sim Unif (a= 8, b=22)[/tex]

And for this case we want to find the following probability:

[tex] P(X>14)[/tex]

We can find this probability using the complement rule and the cumulative distribution function given by:

[tex] P(X<x) = \frac{x-a}{b-a} ,a \leq x \leq b[/tex]

Using this formula we got:

[tex] P(X>14)= 1-P(X<14) =1- F(14)[/tex]

And replacing we got:

[tex] P(X>14)= 1- \frac{14-8}{22-8}= 0.5714[/tex]

The probability that a randomly selected barber needs at least 14 minutes to complete the haircut is 0.5714

[tex]solution \\ {2x}^{2} - x + ( - x - {2x}^{2} - 2) \\ = {2x}^{2} - x - x - {2x}^{2} - 2 \\ = {2x}^{2} - {2x}^{2} - x - x - 2 \\ = - 2x - 2[/tex]

Hope it helps

Good luck on your assignment

Answer:

[tex] - 2x - 2[/tex]

Step-by-step explanation:

[tex]2 {x}^{2} - x + ( - x - 2 {x}^{2} - 2) \\ 2 {x}^{2} - x - x - 2 {x}^{2} - 2 \\ 2 {x}^{2} - 2 {x}^{2} - x - x - 2 \\ - 2x - 2[/tex]

hope this helps you.

brainliest appreciated

good luck!

have a nice day!

Answer:

a) 6.68% of heights less than 150 centimeters

b) 58.65% of heights between 160 centimeters and 180 centimeters

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 162, \sigma = 8[/tex]

a) The percentage of heights less than 150 centimeters

We have to find the pvalue of Z when X = 150. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{150 - 162}{8}[/tex]

[tex]Z = -1.5[/tex]

[tex]Z = -1.5[/tex] has a pvalue of 0.0668

6.68% of heights less than 150 centimeters

b) The percentage of heights between 160 centimeters and 180 centimeters

We have to find the pvalue of Z when X = 180 subtracted by the pvalue of Z when X = 160.

X = 180

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{180 - 162}{8}[/tex]

[tex]Z = 2.25[/tex]

[tex]Z = 2.25[/tex] has a pvalue of 0.9878

X = 160

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{160 - 162}{8}[/tex]

[tex]Z = -0.25[/tex]

[tex]Z = -0.25[/tex] has a pvalue of 0.4013

0.9878 - 0.4013 = 0.5865

58.65% of heights between 160 centimeters and 180 centimeters

Answer:

y = 5x

Step-by-step explanation:

First, find the slope of the first equation by doing rise/run

This gets you -10/-2 or 5

A parallel line will have the same slope. Since it goes through the origin, the y-intercept and b value will be zero

The equation will be y = 5x