Helpppppp please i need help on this question

Answer:

No solutions.

Step-by-step explanation:

No solutions because these two lines are parallel.

You can tell by the slopes. Both slopes are equal -3.

The -2 and [tex]\frac{5}{8}[/tex] vertically shift the lines.

Answer:

it’s just 2x^2

it’s not factorable

The volume of the box will be → 980 square inches.

The volume of cuboid is found using the formula:

Volume = Length × Width × Height

Given is the volume of a box that is 14 inches long, 7 inches wide, and 10 inches high.

The volume of the box will be→

V= L x B x H

V= 14 x 7 x 10

v = 140 x 7

V= 980 square inches

Therefore, the volume of the box will be → 980 square inches

To solve more questions on cuboid, visit the link below-

https://brainly.com/question/23118276

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Answer: Should be 150mm

Step-by-step explanation:

Find the surface area of each figure. Round answers to the nearest tenth, if necessary

2 mm-

2/5 mm

10 mm

3 mm

O

75 mm2

150 mm2

92 mm2

86 mm2

Answer:

The equation of the line that has a slope of 3/2 and a y-intercept of -4 is:

y=3/2x-4.

Step-by-step explanation:

You want to find the equation for a line that has a slope of 3/2 and a y-intercept of -4.  First of all, remember what the equation of a line is:

y = mx+b  Where:  m is the slope, and  b is the y-intercept

All you really have to do here is  replace m with 3/2, which is the slope you gave, and  replace b with -4, the y-intercept you gave,  in the equation y=mx+b.

Answer:

[tex]y = x-7[/tex]    

Step-by-step explanation:

To write the equation of the line in slope-intercept form, use the slope-intercept formula, [tex]y = mx +b[/tex]. Find real values for the [tex]m[/tex] and [tex]b[/tex] and substitute them into the formula.  

1) We know that [tex]m[/tex] represents the slope, so substitute 1 in its place.  However, we still need to find [tex]b[/tex], or the y-intercept. So, along with substituting that 1 in for [tex]m[/tex], substitute the x and y values for (7,0) for the x and y in the formula as well. Then, isolate [tex]b[/tex] to find its value:

[tex]y = mx + b\\0 = (1)(7)+b\\0 = 7 + b\\-7 = b[/tex]

So, [tex]b[/tex] = -7.  

2) Now, just substitute the found values for [tex]m[/tex] and [tex]b[/tex] into the slope-intercept formula. Remember that the slope is [tex]m[/tex], so substitute 1 in, and [tex]b[/tex] is -7, so substitute -7 in its place as well. This gives the following equation in slope-intercept form:

[tex]y = 1x -7[/tex] or [tex]y = x-7[/tex]

Answer:

2

Step-by-step explanation:

the y values are the same so you just have to subtract the biggest x value from the smallest x value

5-3=2

Answer:

$671.44

Step-by-step explanation:

$23.98 * 28 (people) = $671.44

Answer:

$671.44

Step-by-step explanation:

Answer:

750?

Step-by-step explanation:

there is groups of 40 so we take 1000/40 now we have 25 take 25x10 and we will and up with 250 minus 1000 - 250 and we have 750

Answer: 455

Step-by-step explanation:

Answer:

455

Step-by-step explanation:

hope you find this helpfull

Answer:

Options A and C are correct answers

Step-by-step explanation:

A) [tex] \angle 5\: and \:\angle 1[/tex] are complementary.

C) [tex] \angle 3\: and \:\angle 4[/tex] form a linear pair.

Hope it helps you in your learning process.

Answer:

yo sorry I'm dum need points

no xdxdxdxdxdxxdxdxdxdxdxdxdxdxddxd

If the 0's are indeed zeroes, then it would appear that you're using degrees, so that the equation

r(θ) = 2 sin(0°) + 3 sin(90°)

describes a circle r = 3 (since sin(0°) = 0 and sin(90°) = 1). In this case, the area would simply be π r ² = 9π.

But I suspect you meant to use θ, so the curve has the far more interesting equation,

r(θ) = 2 sin(θ) + 3 sin(9θ)

Since sin(9θ) has a period of 2π/9 and sin(θ) has a period of 2π, their sum has a period of 2π. (That is, 2π times the LCM of 1 and 1/9, which is 1.) But we observe r(θ) is odd, since

r(-θ) = 2 sin(-θ) + 3 sin(-9θ)

… = -2 sin(θ) - 3 sin(9θ)

… = - r(θ)

which tells us that the curve closes itself over a half-period. So the area bounded by the curve is given by the integral,

[tex]\displaystyle\int_0^\pi\int_0^{r(\theta)}r\,\mathrm dr\,\mathrm d\theta[/tex]

If you're not familiar with double integrals yet, all you need to know is that this reduces to the area formula you may/should be familiar with,

[tex]\displaystyle\frac12\int_0^\pi r(\theta)^2\,\mathrm d\theta[/tex]

Compute the integral:

[tex]=\displaystyle\frac12\int_0^\pi(2\sin(\theta)+3\sin(9\theta))^2\,\mathrm d\theta[/tex]

[tex]=\displaystyle\frac12\int_0^\pi(4\sin^2(\theta)+12\sin(\theta)\sin(9\theta)+9\sin^2(9\theta))\,\mathrm d\theta[/tex]

Apply some identities:

sin²(θ) = (1 - cos(2θ)) / 2

sin(θ) sin(9θ) = (cos(9θ - θ) - cos(9θ + θ)) / 2 = (cos(8θ) - cos(10θ)) / 2

sin²(9θ) = (1 - cos(18θ)) / 2

[tex]=\displaystyle\frac14\int_0^\pi(4(1-\cos(2\theta))+12(\cos(8\theta)-\cos(10\theta))+9(1-\cos(18\theta))\,\mathrm d\theta[/tex]

[tex]=\displaystyle\frac14\int_0^\pi(13 - 4\cos(2\theta) + 12\cos(8\theta) - 12\cos(10\theta) - 9\cos(18\theta))\,\mathrm d\theta[/tex]

[tex]=\dfrac14 \left(13\theta-2\sin(2\theta)+\dfrac32\sin(8\theta)-\dfrac65\sin(10\theta)-\dfrac12\sin(18\theta)\right)\bigg|_0^\pi[/tex]

[tex]=\dfrac1{40} \left(130\theta-20\sin(2\theta)+15\sin(8\theta)-12\sin(10\theta)-5\sin(18\theta)\right)\bigg|_0^\pi[/tex]

[tex]=\dfrac{130\pi-20\sin(2\pi)+15\sin(8\pi)-12\sin(10\pi)-5\sin(18\pi)}{40}[/tex]

= 13π/4

Question 7

Exponential functions have a variable degree.

Answer is 3^x + 6.

Question 8

Changing 15.3% to a decimal, we get 0.153.

Answer: Choice (4)

This article is about equivalency in mathematics. For equivalency in music, see equivalence class (music).

Congruence is an example of an equivalence relation. The leftmost two triangles are congruent, while the third and fourth triangles are not congruent to any other triangle shown here. Thus, the first two triangles are in the same equivalence class, while the third and fourth triangles are each in their own equivalence class.

In mathematics, when the elements of some set S have a notion of equivalence (formalized as an equivalence relation) defined on them, then one may naturally split the set S into equivalence classes.

                              The information is from https://en.wikipedia.org/wiki/Equivalence_class

                         If it is wrong I am sorry

Answer:

4/420=105

Step-by-step explanation:

decompose 42 and divide by 4 is 10 and is 20 divided by 4 is 5

Step-by-step explanation:  

1 and 3/4 miles               ???? miles

--------------------  = ---------------------

2 and 1/3 minutes         39 minutes

Cross multiplies:

(1 and 3/4) x 39 =   (2 and 1/3)  x    ?

7/4 x 39/1   = 7/3 x ?

273/4 = 7/3 x ?

? = 273/4 * 3/7 =  39*3/4   <---- 7 x 39 = 273

                        = 117/4

                         = 29 and 1/4

---------------------------------------------------------------

1 and 3/4 miles              ?

------------------ = ------------------

2 and 1/3 min             60 min

(1 and 3/4) * 60 = (2 and 1/3) * ?

7/4*60/1 = 7/3 * ?

105 = 7/3 * ?

? = 105*3/7

 = 315/7

 =  45

Answer:

the slope is 2/3 bcoz u do 2-0/3-0

Solution :

Given the number of the edges are = 11

Therefore we take [tex]$\frac{1}{11}=0.091$[/tex]

And the number of the vials total is = 100

Thus we can multiply = [tex]$100 \times 0.091 = 9.1$[/tex]

From the table provided below, we can obtained :

1. Null hypothesis and alternate hypothesis :

The following null and alternate hypothesis needs to be tested :

[tex]$H_0:p_1=0.091, \ p_2 = 0.091, p_3=0.091, \p_4=0.091, \p_5=0.091, \p_6=0.091, \p_7=0.091,$[/tex] [tex]$p_8=0.091, \ p_9=0.091, \ p_{10}=0.091, \ p_{11}=0.091 $[/tex]

[tex]$H_a :$[/tex] some of the population differ from the values stated in the null hypothesis. It corresponds the Chi-square test that is for the Goodness of the Fit.

2. Rejection region :

It is given --

significance level, α = 0.05

number of degrees of freedom, df = 11 - 1

                                                         = 10

Then the rejection region of this test is :

[tex]$R=\{ x^2:x^2 >18.307\}$[/tex]

3. Test statistics

The Chi-Squared statistics is computed as :

[tex]$x^2=\sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}$[/tex]

    [tex]$=7.21+4.089+0.133+0.089+1.056+3.825+2.638+0.924+1.671+0.001+0.001$[/tex]

    = 21.638

4. Decision about null hypothesis

Since we see that :    [tex]$x^2=21.638>x^2_c = 18.307$[/tex], we can concluded that we can reject the null hypothesis.

5. Conclusion :

It is concluded that the null hypothesis [tex]$H_0$[/tex] is rejected. So there is enough evidence for us to claim that the population proportions differ from that stated in null hypothesis at α = 0.05 significance level.

Answer:

10/1

Step-by-step explanation:

Answer:

Its B

Step-by-step explanation: very ez

Answer:

B. All of these statements are true

Step-by-step explanation:

$10 is the smallest amount shown, therefore a is correct.

$25 is the greatest, so c is also correct

and a majority of the tickets start at $15, making d correct

Answer:

f(x) = 2x^3 - 6x^2 - 20x + 48

Step-by-step explanation:

A polynomial with zeros a, b, c, etc., is the product of (x - a)(x - b)(x - c)...

f(x) = (x + 3)(x - 2)(x - 4)

f(x) = (x^2 + x - 6)(x - 4)

f(x) = x^3 - 4x^2 + x^2 - 4x - 6x + 24

f(x) = x^3 - 3x^2 - 10x + 24

This polynomial function has the zeros listed in the problem.

Now we need to make sure it includes the point (6, 144).

f(x) = (x + 3)(x - 2)(x - 4)

f(6) = (6 + 3)(6 - 2)(6 - 4)

f(6) = 9 * 4 * 2

f(6) = 72

The polynomial function has point (6, 72). We want it to include the point (6, 144). We multiply the function by 2.

f(x) = 2(x^3 - 3x^2 - 10x + 24)

f(x) = 2x^3 - 6x^2 - 20x + 48

Answer:

Step-by-step explanation:

[tex]r_1(t) = < t^2 , 8t-15,t^2> \\ \\ r_2(t) = < 11t-30, \ t^2 , \ 13t-40> \\ \\ at \ r_1 = r_2 \\ \\ t^2 = 11t - 30 , \ \ \ \ \ \ \ \ \ \ \ \ 8t - 15 = t^2 , \ \ \ \ \ \ \ \ \ t^2 = 13t -40 \\ \\ t^2 - 11t + 30\ \ \ \ \ \ \ \ \ \ \ \ t^2 -8t + 15 , \ \ \ \ \ \ \ \ \ \ \ \ t^2 -13t + 40 \\ \\ t^2 -8t-3t + 30=0 \ \ \ \ \ \ t^2 - 2t -4t + 15=0 \ \ \ \ \ \ t^2 - 1t - 13t + 40 =0[/tex]

[tex](t-6)(t-5) \ \ \ \ \ \ \ \ \ \ \ (t-5)(t-3) \ \ \ \ \ \ \ \ \ \ \ (t-5)(t-8)[/tex]

[tex]\mathbf{The \ common \ value \ of \ t \ = \ 5}[/tex]

Answer:

There are 479,001,600 arrangments of 12 distinct items.

Step-by-step explanation:

Arrangements of n items:

The number of possible arrangements of n itens is given by the factorial of n, that is:

[tex]A_{n} = n![/tex]

12 items:

[tex]A_{12} = 12! = 479001600[/tex]

There are 479,001,600 arrangments of 12 distinct items.