HELP
Which type of wave interaction is shown in the photo?
A. Interference
B. Refraction
C. Reflection
D. Diffraction

HELPWhich Type Of Wave Interaction Is Shown In The Photo?A. InterferenceB. RefractionC. ReflectionD.

Answers

Answer 1

Answer: the answer is c (think bc im on that too)

Explanation:

Answer 2

The interference is a  type of wave interaction shown in the photo. Option A is correct.

What is the interference of waves?

The result of two or more wave trains flowing in opposite directions on a crossing or coinciding pathways. This phenomenon is known as the interference of waves.

The effect is the sum of the individual wave amplitudes at each site where more than one wave is present.

When two wave pulses are traveling along a string toward each other. They meet and the phenomenon is occur known as interference.

The interference is a  type of wave interaction shown in the photo

Hence option A is correct.

To learn more about the interference of waves refer to the link;

brainly.com/question/16098226


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An effect analogous to two-slit interference can occur with sound waves, instead of light. In an open field, two speakers placed 1.19 m apart are powered by the same function generator producing sine waves at 1,163 Hz frequency. Assume that the speed of sound is 340 m/s. A student walks along a line 12.5 m away and parallel to the line from one speaker to the other speakers. She hears an alternating pattern of loud and quiet, due to constructive and destructive interference. What is the distance between the central maximum and the first maximum (loud) position along this line in m

Answers

Answer:

3.04 m

Explanation:

The interference by diffraction of waves is noticeable only when the dimension of the opening through which the wave is passing through is comparable to the wavelength of the passing wave.

It is given that :

Distance between two speakers, d = 1.19 m

Speed of sound,  v = 340 m/s

The frequency is f = 1163 Hz

Distance the student walk along the line of the speaker, D = 12.5 m

We know the wavelength of the sound produced by the speakers is given by :

[tex]$\lambda=\frac{v}{f}$[/tex]

  [tex]$=\frac{340}{1163}$[/tex]

  = 0.29 m

Now the distance between the central maximum and the first maximum position is given by :

[tex]$y=\frac{\lambda D}{d}$[/tex]

  [tex]$=\frac{0.29 \times 12.5}{1.19}$[/tex]

 = 3.04 m

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