HELP
Which Trig ratio should be used to find the missing side?


A.Sin

B.Cos

C.Tan

Answer:

65 liters

Step-by-step explanation:

11/5=2.2

143/2.2=65

Answer:

Where are the choices? There is no choices

Answer: 26.6667%

Step-by-step explanation: :)

Answer:

The following below are those that shows the correct values for then median-fit method of the restaurant relationship between the number of tables seated (x) and the total number of cups of complementary salsa served (y):

O.  The middle summary point is (52, 103.75).

O.  The right summary point is (63, 160).

O.  The middle summary point is (52, 103.75).

Step-by-step explanation:

Answer:

B.) The middle summary point is (52, 110.5).

D.) The slope of the line of best fit is 2.14.

Step-by-step explanation:

Just did the assignment on Edg 2022 (Linear Regression Methods)

9514 1404 393

Answer:

  A. between 8 and 9

  B. right of 8.63

Step-by-step explanation:

See the attached. Numbers increase to the right, so 8.78 is right of both 8.63 and 8.71. The ones digit is 8, so 8.78 is between 8 and 9.

Answer:

a) 0.324 = 32.4% probability that exactly 3 drivers text while driving if a police officer pulls over five drivers

b) 0.0276 = 2.76% probability the next driver texting while driving that the police officer pulls over is the fifth driver.

Step-by-step explanation:

For each driver pulled, there are only two possible outcomes. Either they are texting, or they are not. The probability of a driver being texting is independent of any other drivers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

It is estimated that 52% of drivers text while driving.

This means that [tex]p = 0.52[/tex]

A. What is the probability that exactly 3 drivers text while driving if a police officer pulls over five drivers?

This is [tex]P(X = 3)[/tex] when [tex]n = 5[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 3) = C_{5,3}.(0.52)^{3}.(0.48)^{2} = 0.324[/tex]

0.324 = 32.4% probability that exactly 3 drivers text while driving if a police officer pulls over five drivers.

B. What is the probability the next driver texting while driving that the police officer pulls over is the fifth driver?

None of the first four([tex]P(X = 0)[/tex] when [tex]n = 4[/tex]), and then the fifth, with 52% probability. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{4,0}.(0.52)^{0}.(0.48)^{4} = 0.0531[/tex]

0.0531*0.52 = 0.0276

0.0276 = 2.76% probability the next driver texting while driving that the police officer pulls over is the fifth driver.

Answer:

76 or 63

Step-by-step explanation:

Given: The tickets cost; Adults = $8, children = $5. Rene sold 100 total tickets for a total of $611

To find: How many adult tickets she sold

Solution: To find how many adult tickets Rene sold, divide the total amount of money made by selling the tickets by the cost for adult tickets

                                                     611 ÷ 8 = 76.4

In the closest tens place, Rene sold is 76 adult tickets or even 63

[tex]CD = \frac{HG + EF}{2} \Leftrightarrow EF = 2CD - HG[/tex]

[tex]2x - 2 = 2x - x + 3\\2x - 2x + x = 3 + 2\\x = 5[/tex]

[tex]EF = 2 * 5 - 2 = 10 - 2 = 8[/tex]

Answer: 8.

Answer:

EF=8

Step-by-step explanation:

HG=x-3

CD=x

EF=2x-2

Since HG is 3 less than CD, EF has to be 3 more than CD

x+3=2x-2

3+2=2x-x

5=x

x=5

HG=2

CD=5

EF=8

Answer:

hello your question is incomplete attached below is the complete question

answer :   1

Step-by-step explanation:

Given Function:

F(x,y)=[tex]\left \{ {{1/4(2x+y)} \atop {0}} \right.[/tex]      for    0<x<1, 0<y<2

                                            elsewhere.

Evaluating the marginal density of the writing test score at point

X = 1/2  = 1/4 ( 4x + 2 ) = 1/4 ( 4 * 1/2 + 2 ) = 1

attached below is the detailed solution

[tex]\sf \left(\sqrt{2}\right)^3\\\\\\\\\boxed{\sf \mathrm{Apply\:radical\:rule}:\quad \sqrt{a}=a^{\frac{1}{2}}}\\\\\\\\\sf \left(2^{\frac{1}{2}}\right)^3\\\\\\\\\boxed{\sf\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc} }\\\\\\\\\sf \sf 2^{\frac{1}{2}\cdot \:3}\\\\\\\\\sf 2^{\frac{3}{2}}\\\\\\\\\sf 2^{\frac{3}{2}}=2^{1+\frac{1}{2}}\\\\\\\\\sf 2^{1+\frac{1}{2}}\\\\\\\\\boxed{\sf \mathrm{Apply\:exponent\:rule}:\quad \:x^{a+b}=x^ax^b}\\\\\\\\\sf[/tex]

[tex]\sf 2 ^1\cdot \:2^{\frac{1}{2}}\\\\\\\\\boxed{\sf \mathrm{Refine}}\\\\\\\\\boxed{\sf =2\sqrt{2}}[/tex]

Answer:

600W = C

Step-by-step explanation:

First we must identify the relationship between weight of gold and cost of gold.

We can do this by dividing cost by corresponding weight.

7200 / 12 = 600

13200 / 22 = 600

19200 / 32 = 600

each proportion has an outcome of 600

Therefore Cost = Weight times 600 or C = 600W

Answer:

MT is congruent to MS

Step-by-step explanation:

Answer:

[tex]MT[/tex]≅[tex]MS[/tex]

Step-by-step explanation:

Because line MN is a perpendicular bisector, and point on the bisector will be equidistant from the end points of the segment it bisects.

Answer:

Liner

Step-by-step explanation:

The cost after the first night is steadily increasing at $75

Answer:

LCL = 4.72

UCL = 18.08

Step-by-step explanation:

Sample size, n = 20

Sample _ tread wear, x __ Range

1 ______ 33.67 ___ 14

2______ 26.33 ___ 17

3 _____ 29.67 ____ 9

4 ______ 21 ______ 8

5 ______ 34 ______ 9

6 ______ 39.67 ___ 6

7 ______ 22.33 ___ 12

8 ______ 28.67 ___ 6

9 ______ 36 ______8

10 _____ 25.33 ___ 13

11 _____ 32.33 ____14

12 _____ 22.33 ___ 6

13 _____ 24.33 ___ 15

14 _____ 31.67 ___ 26

15 _____ 24 _____ 11

16 ____ 34.33 ____ 12

17 ____ 32 _______ 8

18 ____ 33.33 ____ 11

19 ____ 25 _______11

20 ___ 27.33 _____12

Sample mean, xbar = Σx / n = 29.167

Rbar = ΣR/ n = 11.4

The R chart control limit is given by :

Rbar(1 - 3(d3/d2))

From the R chart :

d3 = 0.729 ; d2 = 3.735

Hence,

LCL = 11.4(1 - 3(0.729/3.735))

LCL = 11.4(0.4144578) =

LCL = 4.72481892 = 4.72

UCL = 11.4(1 - 3(0.729/3.735))

UCL = 11.4(1.5855421)

UCL = 18.075180 = 18.08

Answer:

value we donnot know so we try to find it by equations

Answer:

Any number of possibilities...

Step-by-step explanation:

Answer:

probability of selecting blue ball is equal to the number of blue balls over the total balls which is 2÷12

Answer:

The correct solution is "7.3%".

Step-by-step explanation:

It seems that the given question is incomplete. Find below the attachment of the complete and appropriate query.

According to the question,

The total married couples are,

= 55,550,000

where,

Both native = 79.5%

Both foreign = 13.2%

Now,

The percentage of couple that is one native as well as one foreign will be:

= [tex]100-79.5-13.2[/tex]

= [tex]7.3[/tex] (%)

Answer:

trata de usar común un like para que puedes hacer frío

Answer:

60

Step-by-step explanation:

The mode is the value which occurs the most in the set. We see that 60 occurs three times, 62 occurs once, 63 occurs once, 65 occurs twice, 66 occurs once, 68 occurs once, and 69 occurs once.

Thus, the mode is 60.

Answer:

The mode is 60

Step-by-step explanation:

The mode is the number that appears most in the set of data. 60 appears the most, appearing 3 times.

Answer:

Angle k is equal to 110°

Step-by-step explanation:

Because they are alternating angles

Answer: hello your question is incomplete below is the missing part

Determine the proportion of radishes grown without fertilizers with weight less than 50grams

answer : p( x < 50 ) = 0.84

Step-by-step explanation:

Radish grown in without fertilizers ( normally distributed )

mean = 40 g

standard deviation = 10 g

Radish grown with fertilizers ( normally distributed )

Mean = 140 g

standard deviation = 40 g

Determine the proportion of radishes grown without fertilizers with weight less than 50 grams

lets assume x = radish without fertilizers

                    y = radish with fertilizers

hence

p( x < 50 )  = P (  (x-μ / б)  < [tex]\frac{50-40}{10}[/tex]  )

                  = p ( z < 1 ) = 0.5 + p ( 0 < z < 1 )

                                   p( x < 50 ) = 0.5 + 0.3413 = 0.8413

attached below is the distribution related to this solution

Answer:

Hello! answer: a = 11

Step-by-step explanation:

2 × 11 = 22 So therefore a = 11 HOPE THAT HELPS!

Answer:

d

Step-by-step explanation:

The inverse of a conditional statement, makes both the hypothesis and conclusion or "p" and "q" negative. In other words, it adds a not to both sides.

So the inverse of "If p, then q" would be "If not p, then not q."

"If the measure of angle 1 does not equal 60 degrees, then angle 1 is not acute."

Answer:

Step-by-step explanation:

X squared over 6

+

2x cubed over 3

Answer:

x^2/6 + 2x^3/3

Step-by-step explanation:

I used (m)athway to simplify the expression

Answer:

x = 3

Step-by-step explanation:

Answer:

A,F

Step-by-step explanation:

Answer:

In mathematics, a unit circle is a circle of unit radius—that is, a radius of 1. Frequently, especially in trigonometry, the unit circle is the circle of radius 1 centered at the origin in the Cartesian coordinate system in the Euclidean plane.

Step-by-step explanation:

Answer:

El círculo unitario se divide en 4 partes, denominadas cuadrantes. El primer cuadrante (I) está formado por los ejes xey positivos. El primer cuadrante (I) está formado por los ejes xey positivos. Si dibujamos cualquier radio del círculo unitario en el primer cuadrante, el ángulo con el eje x positivo puede tener cualquier valor entre 0 y 90 °.

9514 1404 393

Answer:

  C

Step-by-step explanation:

A root with a given index is the same as a fractional power with that index as the denominator.

  [tex]\dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}=6^{\frac{1}{4}}2^{-\frac{1}{3}}=\sqrt[12]{(6^{\frac{1}{4}}2^{-\frac{1}{3}})^{12}}=\sqrt[12]{6^32^{-4}}\\\\=\sqrt[12]{6^32^82^{-12}}=\dfrac{\sqrt[12]{6^32^8}}{2}=\boxed{\dfrac{\sqrt[12]{55296}}{2}}[/tex]