help with number 6 please

Help With Number 6 Please

Answers

Answer 1

The diameter of the second pile of phosphate is found to be approximately 62.6 feet.

The volume of a right circular cone is given by the formula,

V = (1/3)πr²h where volume is V, radius of the base is r, height is h, and π is approximately 3.14159. For the first pile of phosphate,

h = 15.3 feet

d = 48.6 feet

r = d/2 = 24.3 feet

Using the formula for the volume of a cone,

V = (1/3)πr²h

V = (1/3)π(24.3)²(15.3)

V = 24,249.8 cubic feet

For the second pile of phosphate,

h = 15.3 - 3.6 = 11.7 feet

r = ? (to be determined)

Using the same formula for the volume of a cone,

V = (1/3)πr²h

V = (1/3)πr²(11.7)

Since the volume of both piles is the same, we can set the two volume formulas equal to each other,

(1/3)π(24.3)²(15.3) = (1/3)πr²(11.7)

Simplifying,

(24.3)²(15.3) = r²(11.7)

r² = (24.3)²(15.3)/11.7

r = 31.3 feet (rounded to the nearest tenth)

Therefore, the diameter of the second pile of phosphate is d = 2r = 62.6 feet (rounded to the nearest tenth).

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Complete question - As phosphate is mined, it moves along a conveyor belt, falling off of the end of the belt into the shape of a right circular cone, as shown.

Height of the cone is 15.3 feet

Diameter of the base of cone is 48.6 feet

A shorter conveyor belt also has phosphate falling off of the end into the shape of a right circular cone. The height of the second pile of phosphate is 3.6 feet shorter than the height of the first. The volume of both piles is the same. To the nearest tenth of a foot, what is the diameter of the second pile of phosphate?


Related Questions

Consider this system of equations: 2x + 1/4 y= 3 (equation A) 2/3 x - y = 6 (equation B)
The expressions that give the value of y are ___ and ___ .
The solution for the given system is ___.

The options given for the first blank space are A - 38, A - (38/2), 2A - 3B, (A/3) + B.
The options for the second blank space are A + 38, A + (38/2), (A/3) - B, and ((A/3) - 2B.
The options given for the first blank space are (27/13, 60/13), (-27/13 60/13), (27/13, -60/13), (-27/13, -60/13)

Answers

The solution to the system of equations are ( 27/13 , -60/13 )

Given data ,

Let the system of equations be A and B

where 2x + ( 1/4 )y = 3   be equation (1)

And , ( 2/3 )x - y = 6   be equation (2)

On simplifying , we get

Multiply by 3 on equation (2) , we get

2x - 3y = 18   be equation (3)

Subtracting equation (1) from (3) , we get

-3y - (1/4)y = 15

-13/4y = 15

Divide by -13/4 on both sides , we get

y = -60/13

Now , the value of x is given by

2x + ( 1/4 ) ( -60/13 ) = 3

2x - ( 60/52 ) = 3

Adding 60/52 on both sides , we get

2x = 3 + 60/52

2x = 216/52

Divide by 2 on both sides , we get

x = 216/104

On simplifying , we get

x = 27/13

Hence , the solution is ( 27/13 , -60/13 )

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Ready
Solve Problems with Ratios and Unit Rates
Trevin puts 8 gallons of gas in his car and pays $22.
What is the cost of 1 gallon of gas? Complete the table.
Cost (dollars)
Gas (gal)
1
22
8

Answers

The cost of one gallon of gas is given as follows:

$2.75.

How to obtain the cost of one gallon of gas?

The cost of one gallon of gas is obtained applying the proportions in the context of the problem.

A proportion is applied as the cost per gallon is obtained dividing the total cost by the number of gallons.

The parameters for this problem are given as follows:

Total cost of $22.8 gallons.

Hence the cost of one gallon of gas is given as follows:

22/8 = $2.75.

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Nathan's pet cat weighed 6 pounds. Then the cat gained 0.3 pounds. How much does the cat weigh now?

Answers

Answer: Nathan's pet cat weighed 6 pounds. Then the cat gained 0.3 pounds. How much does the cat weigh now? Nathan's cat would now weigh 6.3 pounds.

Step-by-step explanation: 6+0.3=6.3

Answer:

6.3

Step-by-step explanation:

It's simple, just do 6 + 0.3, and you get 6.3!

Listed in the Item Bank are key terms and expressions, each of which is associated with one of the columns. Some terms may display additional information when you click on them. Drag and drop each item into the correct column. Order does not matter.

Answers

The statement, "You can prove two triangles are similar using an AA similarity theorem" is true while the statement "If the side length of similar figures have a ratio of m/n then the volume will have a ratio of n m³/n³. The correct ratio is (m/n)³" is false.

Understanding Visual Match

Visual Match is a term used to describe the degree of similarity or resemblance between two visual elements or objects.

From the given question, we can arrange the following statements as below:

TRUE

- You can prove two triangles are similar using an AA similarity theorem.

- If the side length of similar figures have a ratio of m/n then the surface area will have a ratio of (m/n)².

- If the side length of similar figures have a ratio of m/n then the area will have a ratio of (m/n)².

FALSE

- If the side length of similar figures have a ratio of m/n then the volume will have a ratio of n m³/n³. The correct ratio is (m/n)³.

- If the side length of similar figures have a ratio of 2/3 then the perimeter will have a ratio of 2/3. The correct ratio is 2/3.

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janice spent 3.85 for 2 pounds of apples and 3 pounds of pairs. lisa spent 4.94 for 4 pounds of apples and 2 pounds of pairs. how much does a pound of apples cost

Answers

Based on a system of equations, a pound of apples costs $0.89.

What is a system of equations?

A system of equations is two or more equations solved at the same time or concurrently.

A system of equations is also referred to as simultaneous equations.

                    Apples     Pears     Total Cost

Janice              2              3             $3.85

Lisa                  4              2             $4.94

Let the cost of a pound of apples = x

Let the cost of a pound of pears = y

Equations:

2x + 3y = 3.85 ... Equation 1

4x + 2y = 4.94 ... Equation 2

Multiply Equation 1 by 2:

4x + 6y = 7.7 ... Equation 3

Subtract Equation 2 from Equation 3:

4x + 6y = 7.7

-

4x + 2y = 4.94

4y = 2.76

y = 0.69

Substitute y = 0.69 in Equation 1 or 2:

4x + 2y = 4.94

4x + 2(0.69) = 4.94

4x + 1.38 = 4.94

4x = 3.56

x = 0.89

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The distance traveled can be calculated using the formula
D= s t where s is the speed and t is the total time. If a bus
traveled 25 mi/h for 7 hours, how far did the bus travel?

Answers

From the distance formula

[tex]d=s \times t[/tex]

Now placing the given values

[tex]d = 25 \times 7[/tex]

[tex]d = 175[/tex]

Hence the bus traveled 175m (meters)

Expand each logarithm.
1. Log 2^8XYZ
2. Log 9^8lx/y
3. Log 5^5x^3
4. Log 6 3√x

Answers

The logarithmic expressions when expanded are

1. [tex]\log2^{8yz}[/tex] = 8xyz log(2)

2. [tex]\log9^{81x/y}[/tex] = 81x/y log(9)

3. [tex]\log5^{x^3}[/tex] = x³ log(5)

4. [tex]\log6^{\sqrt[3]{x}}[/tex] = ∛x log(6)

How to expand the logarithmic expression

From the question, we have the following parameters that can be used in our computation:

The logarithmic expressions

The logarithmic expressions can be expanded using power rule of logarithm which states that

logaᵇ = b log(a)

Using the above as a guide, we have the following:

[tex]\log2^{8yz}[/tex] = 8xyz log(2)

[tex]\log9^{81x/y}[/tex] = 81x/y log(9)

[tex]\log5^{x^3}[/tex] = x³ log(5)

[tex]\log6^{\sqrt[3]{x}}[/tex] = ∛x log(6)

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Javier trained for his first marathon for months. He learned to pace himself and to push through the pain. He developed blisters
and shin splints. It broke his heart not to finish.
Which revision below most effectively uses transitions to create coherence?
Javier trained for his first marathon for months after he learned to pace himself and to push through the pain. Additionally,
he developed blisters and shin splints. In the end, it broke his heart not to finish.
Javier trained for his first marathon for months. First, he learned to pace himself and to push through the pain. Next, he
developed blisters and shin splints. Finally, it broke his heart not to finish.
Javier trained for his first marathon for months. He leaned to pace himself and to push through the pain. But during the
race, he developed blisters and shin splints. Because of that he had to stop, and it broke his heart when he couldn't finish.
Javier trained for his first marathon for months. He learned to pace himself and to push through the pain. Also, he
developed blisters and shin splints. Similarly, it broke his heart not to finish.
Submit
Pass
Hold
Don't know answer Skip for now
Save and close

Answers

This revision uses transitional words (first, next, finally) to indicate a clear sequence of events helps to create coherence and improve the flow of the passage.

The revision that most effectively uses transitions to create coherence is:

Javier trained for his first marathon for months.

He learned to pace himself and to push through the pain.

He developed blisters and shin splints.

It broke his heart not to finish.

This revision uses transitional words (first, next, finally) to indicate a clear sequence of events helps to create coherence and improve the flow of the passage.

The use of these transitions also helps the reader understand the chronological order of events in the story.

In addition, the other options have some issues.

The first revision uses "after" to indicate a time sequence but it is not clear what event this refers to.

The second revision uses "finally" is a good transition but it does not provide any other transition words to clarify the order of events.

The third revision uses "but" to contrast the two events creates a bit of confusion as there is no clear cause-and-effect relationship between the two.

The fourth revision uses "also" to indicate a connection but it does not clearly indicate the sequence of events.

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Answer this question

Answers

Using the Pythagorean theorem and trig identities, it is proved sinθ + cosθ = 1.

The Pythagorean theorem states that for a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, we can use the Pythagorean theorem to prove that sinθ+cosθ=1.

Let's take a right triangle with an angle θ and sides a, b and c, as shown in the diagram below:

By the Pythagorean theorem, we have:

a² + b² = c²

Now, we can substitute a and b with the trigonometric functions for the sides of our triangle:

sin²θ + cos²θ = 1

We can simplify this expression by using the trigonometric identity:

sin²θ + cos²θ = 1

sin²θ + cos²θ = (sinθ + cosθ)²

Substituting (sinθ + cosθ)² back into the equation, we get:

(sinθ + cosθ)² = 1

Hence, using the Pythagorean theorem and trig identities, it is proved sinθ + cosθ = 1.

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What is the equation for the data table with x values 1, 2, 3, 4, 5 and y values 2, 4, 8, 16, 32

Answers

The equation of the data table of values is y = 2ˣ

How to determine the equation of the data table

From the question, we have the following parameters that can be used in our computation:

The data table with the values

x values 1, 2, 3, 4, 5

y values 2, 4, 8, 16, 32

From the above, we can see that the relationship between x and y is that

The number 2 takes the variable x as its exponent to get the variable y

Mathematically, this can be expressed as

y = 2ˣ

This represents an exponential function with a base of 2

Hence, the equation of the data table is y = 2ˣ

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find the average cost function C for the given total cost function

C(x) = 2,100 + 4x − 0.0003x2

Answers

The average cost function for the given total cost function is AC(x) = 2,100/x + 4 - 0.0003x.

To find the average cost function C, we need to divide the total cost function C(x) by the quantity of output produced, which is represented by x.
The formula for average cost (AC) is:
AC(x) = C(x) / x
Plugging in the given values, we have:
AC(x) = (2,100 + 4x - 0.0003x2) / x
Simplifying this expression, we get:
AC(x) = 2,100/x + 4 - 0.0003x
Therefore, the average cost function C(x) is:
C(x) = 2,100/x + 4x - 0.0003x2
This function represents the average cost per unit of output, taking into account fixed costs (2,100) and variable costs (4x - 0.0003x) that increase as output increases.
It's important to note that the cost function C(x) is quadratic, which means that the average cost function C(x) will have a U-shaped curve.

This is because initially, as output increases, fixed costs are spread out over a larger quantity of output, leading to a decrease in average cost.

However, at a certain point, the increasing variable costs will outweigh the decreasing fixed costs, causing average cost to increase again.
Overall, knowing the average cost function can be useful for businesses to make decisions about pricing, production levels, and cost management strategies.

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TIME SENSITIVE, 50 POINTS, MULTIPLE CHOICE
Approximate the solution to the equation above using three iterations of successive approximation. Use the graph below as a starting point.

Answers

Using iterations, the solution to the above equation  6⁽⁻ˣ⁾ +4 = 3x -1 is Option C  = 27/16. See the graph attached.

How is this so?

The question requires you to state the solution of the equation. On the graph, this would be the point of intersection of both curves.

To solve for x, we'll continue using an iterative method called the fixed-point iteration ..

Rewrite the equation in the form x = g(x):

g(x) = (6⁽⁻ˣ⁾ + 5) / 3

Start with an initial guess, let's say x0 = 1.

Iterate using the formula x(n+1) = g( x(n )) until convergence, where n is the iteration number:

x (1) = g(x 0)

x (2 ) = g (x(1))

x( 3) = g(x (2))

Let's perform three iterations to approximate the solution

Iteration 1

x (1) = g( x0) = (6⁻¹ + 5) / 3

= (1/ 6 +5) / 3

= (1 /6 + 30/6) / 3

= 31/18

≈ 1.7222

Second iteration is

x(2) = g(x (1)) = ([tex]6^{1.72222}[/tex] + 5) / 3 ≈ 1.6806

Iteration 3:

x(3) = g(x (2)) = ([tex]6^-1.6806[/tex] + 5) / 3 ≈ 1.6875

After three iterations, the approximate solution to the equation 6⁽⁻ˣ⁾ + 4 = 3x - 1 is x ≈ 1.6875, which can also be expressed as the fraction 27/16.

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Will Give Brainliest Please Help!

Answers

Step-by-step explanation:

If the lines are parallel then    3x + 9x = 180 degrees

                                                12 x = 180

                                                    x = 15

A company’s cereal boxes advertise that each box contains 9.65 ounces of cereal. In fact, the amount of cereal in a randomly selected box follows a Normal distribution with mean μ = 9.70 ounces and standard deviation σ = 0.03 ounce. Now take an SRS of 5 boxes. What is the probability that the mean amount of cereal in these boxes is less than 9.65 ounces?
What is the probability that the mean amount of cereal ¯
in 5 randomly selected boxes is at most 9.65?

Answers

The probability that the mean amount of cereal in 5 randomly selected boxes is at most 9.65 ounces is 0.4808.

What is the probability?

The Central limit theorem is used to find the probability

Data given:

sample size = 5.

mean, μ = 9.70 ounces

standard deviation, σ = 0.03 ounce.

To calculate the probability, we determine the z-score corresponding to the sample mean of 9.65 ounces using the z-score formula.

z = (x - μ) / (σ / √n)where

x is the sample mean,

μ is the population mean,

σ is the population standard deviation, and

n is the sample size.

For the sample mean of 9.65 ounces in 5 boxes:

z = (9.65 - 9.70) / (0.03 / √5)

z ≈ -0.05 / (0.03 / √5)

Using a calculator, we find that the probability is approximately 0.4801.

Therefore, the probability that the mean amount of cereal in 5 randomly selected boxes is less than 9.65 ounces is approximately 0.4801.

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In the diagram below of circle O, tangent EC is drawn to diameter AC. Chord BC is parallel to the secant ADE and the chord AB is drawn.

Answers

The location of the angles and the parallel lines [tex]\overline{BE}[/tex] and [tex]\overline{ADE}[/tex] indicates;

(a) ΔABC ~ ΔECA by Angle Angle similarity

(b) The ratio of corresponding sides in similar triangles indicates; BC/CA = AB/EC

What are parallel lines?

Parallel lines are lines that continues indefinitely, maintaining the same distance between each other.

9. The specified dimensions of the geometric figures are;

[tex]\overline{EC}[/tex] is a tangent to the circle O

[tex]\overline{AC}[/tex] is a diameter of the circle

[tex]\overline{BC}[/tex] is parallel to secant [tex]\overline{ADE}[/tex]

Therefore, the angle ∠ABC is a right angle (Angle at the circumference formed by the diameter of a circle

∠ACE = 90° (The tangent is perpendicular to the radius of a circle)

∠ABC ≅ ∠ACE (Definition of congruent angles)

m∠ABC = m∠ACE = 90° (Definition of congruence)

∠BCA ≅ ∠EAC (Alternate interior angles)

ΔABC ~ ΔECA by AA congruence rule

(b) The similarity between the triangles and the ratio of the corresponding sides indicates;

BC/CA = AC/AE

Therefore

Segment BC in triangle ΔABC corresponds to segment CA in triangle ΔECA

Segment CA in triangle ΔABC corresponds to segment AE in triangle ΔECA

Which indicates;

Segment AB in triangle ΔABC corresponds to segment EC in triangle ΔECA

The ratio of the corresponding sides is therefore;

BC/CA = AB/EC

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HELPPP!! Business Math!
What is the yield on a corporate bond with a $1000 face value purchased at a discount price of $850, if it pays 6% fixed interest for the duration of the bond?yield = [?] %
Give your answer as a percent rounded to the nearest hundredth.

Answers

Based on the calculations, the yield on this corporate bond is found as 9.14%

Given as For a $1000 face value purchased at a discount price of $850, if it pays 6% fixed interest for the duration of the bond is the yield on a corporate bond mathematically given as

Yield = 6.5%

Interest paid = value of bond x Interest rate

Interest paid = 1000 * 6%

Interest paid = 60

Therefore

Yield = Interest paid / Price paid

Yield = (60 / 850)x 100

Yield = 9.14%

In conclusion, the yield on a corporate bond is

Yield = 9.14%

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Answer: 7.06

Step-by-step explanation: accelus

A publisher for a promising new novel figures fixed costs​ (overhead, advances,​ promotion, copy​ editing, typesetting, and so​ on) at ​$51,000​, and variable costs​ (printing, paper,​ binding, shipping) at ​$1.50 for each book produced. If the book is sold to distributors for ​$12 ​each, how many must be produced and sold for the publisher to break​ even?

Answers

The publisher must produce and sell approximately 4,857 books to break even.

Let's denote the number of books produced and sold as "x."

The total fixed cost is given as $51,000.

The variable cost per book is $1.50, and since x books are produced and sold, the total variable cost would be 1.50x.

The selling price per book is $12, and since x books are sold, the total revenue would be 12x.

To break even, the total revenue must equal the total cost:

Total Revenue = Total Cost

12x = 51,000 + 1.50x

Subtracting 1.50x from both sides:

12x - 1.50x = 51,000

10.50x = 51,000

Dividing both sides by 10.50:

x = 51,000 / 10.50

x ≈ 4,857

Therefore, the publisher must produce and sell approximately 4,857 books to break even.

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The following is a position-time
graph for a moving
object. Given this graph, draw the matching v-t and a-
t graphs in the Show Your Work box.

Answers

The answer is that the v t and the a t graphed line up at the same point when shown on the graph

A reservoir for storing water is in the shape of a large cylinder on a circular base and is 10cm in depth when it holds a million litres of water. (a) Find the diameter to the nearest metre. (b) what will be the diameter if it hold only 250,000litre(take 1litre=1000cm)​

Answers

The diameter of the reservoir is:

Part (a): 112.86 m

part (b): 56. 44 m

How to find the diameter of the reservoir?

The volume of a cylinder is given by the formula:

V = πr²h

where r is the radius and h is the height or depth

Part (a):

We have:

h = 10 cm = 0.1 m

V = 1000,000 litres = 1000 m³  (Remember: 1 litre = 1000 cubic metre)

V = πr²h

1000 = 3.14 * r² * 0.1

1000 = 0.314 r²

r² = 1000 / 0.314

r² = 3184.71

r = √3184.71

r = 56.43 m

Since diameter = 2 * r

diameter =  2 * 56.43

diameter = 112.86 m

part (b):

We have:

h = 10 cm = 0.1 m

V = 250,000 litres = 250 m³

V = πr²h

250 = 3.14 * r² * 0.1

250 = 0.314 r²

r² = 250 / 0.314

r² = 796.18

r = √796.18

r = 28.22 m

Since diameter = 2 * r

diameter =  2 * 28.22

diameter = 56. 44 m

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a) On the occasion of Teej, the principal of a school organized a Teej program for her female staffs. She distributes 90 bangles and 108 sweets equally to the staffs including herself. If there are 20 male staffs in the school, find the maximum number of staffs of her school.​

Answers

The maximum number of staff at the school, given the distribution of bangles and sweets, is 38 staff.

How to find the number of staff ?

The principal has distributed 90 bangles and 108 sweets equally among her female staff includng herself. This means that the total number of female staff in the school is a number that can divide both 90 and 108 evenly, as each staff member must receve an integer number of bangles and sweets.

Find the greatest common divisor (GCD) of 90 and 108. The GCD of 90 and 108 is 18.

So, the princpal's school has 18 female staff including herself. In addition to the 20 male staff, this implies a maxmum of:

18 (female staff) + 20 (male staff) = 38 staff in total

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Need help!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

5376

Step-by-step explanation:

volume of prism = 8 X 6 X 14 = 672.

volume of cube = 1/2 X 1/2 X 1/2 = 1/8.

672 / (1/8)

= 672 X (8/1)

= 5376.

5376 cubes will fit into it


Kara's Custom Tees experienced fixed costs of $500 and variable costs of $5 a shirt Write an equation that can be used to determine the total expenses encountered by Kan's Custom Tees Lef x be the number
of shirts, and let C(x) be the total cost of producing x shirts. Then, calculate the cost of producing 8 shirts

Answers

Kara's Custom Tees will spend $540 to produce 8 shirts.

To determine the total expenses encountered by Kara's Custom Tees, we can use the equation:

C(x) = fixed costs + (variable costs per shirt) * x

In this case, the fixed costs are $500 and the variable costs per shirt are $5. Therefore, the equation becomes:

C(x) = 500 + 5x

To calculate the cost of producing 8 shirts, we substitute x = 8 into the equation:

C(8) = 500 + 5 * 8

= 500 + 40

= $540

Therefore, Kara's Custom Tees will spend $540 to produce 8 shirts.

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the opposite sides of a parallelogram are ? congruent
A: always
b: sometimes
c: never

Answers

Opposite sides are always congruent
A: always

Drag each inequality to the column which is labeled with its solution.

( look at photo for reference )

Answers

Drag the solution of each inequality as shown below:

3(x - 5) + x < 13 : x<7

2(x + 8) > 4x + 2 : x<7

3x + 2(x - 8) > x : x > 4

2(x + 6) < 3x + 8 : x > 4

How to solve the inequalities?

An inequality is a relationship that makes a non-equal comparison between two numbers or other mathematical expressions e.g. 2x > 4

3(x - 5) + x < 13

3x -15 + x < 13

4x -15 < 13

4x < 13 + 15

4x < 28

x < 28/4

x < 7

2(x + 8) > 4x + 2

2x + 16 > 4x + 2

2x - 4x > 2 - 16

-2x > -14

x < -14/(-2)     (Note: Sign will change if you divide with negative numbers)

x < 7

3x + 2(x - 8) > x

3x + 2x -16 > x

5x - 16 > x

5x - x > 16

4x > 16

x > 16/4

x > 4

2(x + 6) < 3x + 8

2x + 12 < 3x + 8

2x - 3x < 8 - 12

-1x < -4

x > -4/(-1)

x > 4

Therefore, drag the solution of each inequality accordingly.

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Pls show how you found the answer.​

Answers

Answer:

B

Step-by-step explanation:

[tex]tan^{2}\alpha (sec^{2} \alpha + cosec^{2} \alpha )\\\frac{sin^{2}\alpha}{cos^{2}\alpha} (\frac{1}{cos^{2}\alpha}+\frac{1}{sin^{2}\alpha})\\ \frac{sin^{2}\alpha}{cos^{2}\alpha} (\frac{1}{cos^{2} \alpha . sin^{2}\alpha} )\\\frac{1}{cos^{4}\alpha}\\= sec^{4}\alpha[/tex]

the length of the green anole lizard is how many times greater than the length of the crazy ant. The length of the lizard is 6 in and the length of the ant is 3/32
A. 9/16
B.5 29/32
C. 16
D. 64

Answers

The Length of the ant to inches before we can compare the two lengths. We do this by dividing the numerator (3) by the denominator (32), which gives us a decimal of approximately 0.09375 inches.

To find how many times greater the length of the green anole lizard is compared to the crazy ant, we need to divide the length of the lizard by the length of the ant:

Length of lizard / Length of ant = 6 / (3/32) = 6 * (32/3) = 64

Therefore, the length of the green anole lizard is 64 times greater than the length of the crazy ant.

The correct answer is (D) 64.

It is important to pay attention to the units when working with ratios and proportions. In this case, the length of the lizard is given in inches, while the length of the ant is given in fractions of an inch. We need to convert the length of the ant to inches before we can compare the two lengths. We do this by dividing the numerator (3) by the denominator (32), which gives us a decimal of approximately 0.09375 inches.

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can someone pls help quick

Answers

The value of the function, h(0) is -4.

The explanation on how to solve a function

A function relates input and output. In other words, a function is a special relationship among the inputs (independent variable) and their outputs (dependent variable).

Therefore, let's solve the function.

Given the function h(x) = 5x - 4

Let's find the value of the function h(0). To find the value of the function h(0), we have to substitute the value of x as 0 in the function.

Therefore,h(0) = 5(0) - 4h(0) = 0 - 4h(0) = -4

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Please help asap !! I will give 10 points !!

Answers

Answer:

Step-by-step explanation:

12

Answer:

get help from a tutor if you need help really fast :)

Step-by-step explanation:

In a 45-45-90 right triangle, what is the ratio of the length of one leg to the
length of the other leg?
A. 1:√2
B. 2:1
C. 1:1
D. √2:1
SUBMIT

Answers

It is a right triangle is the ratio of the length of one leg to the

length of the other leg = x/x =1/1. C.

In a 45-45-90 right triangle, the two acute angles are each 45 degrees, and the right angle is 90 degrees.

The special property of a 45-45-90 triangle is that its two legs are congruent, meaning they have the same length.

Let's denote the length of each leg as "x."

To determine the ratio of the length of one leg to the length of the other leg, we can compare the lengths.

Let's call the length of one leg "a" and the length of the other leg "b."

Since the two legs are congruent, we have a = b = x.

The ratio of the length of one leg to the length of the other leg is a:b = x:x.

Simplifying the ratio, we have a:b = 1:1.

This means that the length of one leg is equal to the length of the other leg in a 45-45-90 right triangle.

To recap:

Both legs have the same length, which is a property unique to this type of triangle.

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100 Points! Algebra question. Photo attached. Find the exact value of the expression. Please show as much work as possible. Thank you!

Answers

Answer:

[tex]2-\sqrt{3}[/tex]

Step-by-step explanation:

Find the exact value of the expression, tan(15°).

The method I am about to show you will allow you to solve this problem without any tables or calculators. Although, memorizing the unit circle and trigonometric identities is required.

[tex]\tan(15 \textdegree)\\\\\Longrightarrow \tan(\frac{30 \textdegree}{2} )\\\\\text{Use the half-angle identity:} \ \tan(\frac{A}{2})=\pm \sqrt{\frac{1-\cos(A)}{1+\cos(A)} }=\frac{\sin(A)}{1+\cos(A)} =\frac{1-\cos(A)}{\sin(A)} \\\\\Longrightarrow\frac{1-\cos(30 \textdegree)}{\sin(30 \textdegree)} \\\\\text{From the unit circle:} \ \cos(30 \textdegree)=\frac{\sqrt{3} }{2} \ \text{and} \ \sin(30 \textdegree)=\frac{1}{2}\\[/tex]

[tex]\Longrightarrow \frac{1-\frac{\sqrt{3} }{2}}{\frac{1}{2}}\\\\\Longrightarrow 2(1-\frac{\sqrt{3} }{2})\\\\\therefore \boxed{\boxed{\tan(15 \textdegree)=2-\sqrt{3} }}[/tex]

Thus, the problem is solved.

Answer:

[tex]\tan 15^{\circ} = 2 - \sqrt{3}[/tex]

Step-by-step explanation:

To find the exact value of tan 15°, we can use trigonometric identities and the unit circle.

We know that tan(x) can be expressed as the ratio of sin(x) and cos(x). We can also write 15° as (60° - 45°).

Therefore, tan 15° can be expressed as:

[tex]\tan15^{\circ}=\tan(60^{\circ}-45^{\circ})=\dfrac{\sin(60^{\circ}-45^{\circ})}{\cos(60^{\circ}-45^{\circ})}[/tex]

Now use the trigonometric angle identities to rewrite the ratio in terms of sin 60°, cos 60°, sin 45° and cos 45°.

[tex]\boxed{\begin{minipage}{6.5 cm}\underline{Trigonometric Angle Identities}\\\\$\sin (A - B)=\sin A \cos B - \cos A \sin B$\\\\$\cos (A - B)=\cos A \cos B + \sin A \sin B$\\\end{minipage}}[/tex]

Therefore:

[tex]\begin{aligned}\tan15^{\circ}&=\dfrac{\sin(60^{\circ}-45^{\circ})}{\cos(60^{\circ}-45^{\circ})}\\\\&=\dfrac{\sin60^{\circ}\cos45^{\circ}-\cos60^{\circ}\sin45^{\circ}}{\cos 60^{\circ} \cos 45^{\circ}+ \sin 60^{\circ}\sin 45^{\circ}}\end{aligned}[/tex]

In the unit circle, the cosine of an angle is represented by the x-coordinate of a point on the circle, and the sine of an angle is represented by the y-coordinate of that same point → (x, y) = (cos θ, sin θ). Therefore, we can use the unit circle to identity the values of sin 60°, cos 60°, sin 45° and cos 45°:

[tex]\sin 60^{\circ}=\dfrac{\sqrt{3}}{2}[/tex]

[tex]\cos 60^{\circ}=\dfrac{1}{2}[/tex]

[tex]\sin 45^{\circ}=\dfrac{\sqrt{2}}{2}[/tex]

[tex]\cos 45^{\circ}=\dfrac{\sqrt{2}}{2}[/tex]

Substitute these into the equation and simplify:

[tex]\begin{aligned}\tan15^{\circ}&=\dfrac{\sin(60^{\circ}-45^{\circ})}{\cos(60^{\circ}-45^{\circ})}\\\\&=\dfrac{\sin60^{\circ}\cos45^{\circ}-\cos60^{\circ}\sin45^{\circ}}{\cos 60^{\circ} \cos 45^{\circ}+ \sin 60^{\circ}\sin 45^{\circ}}\\\\&=\dfrac{\dfrac{\sqrt{3}}{2}\cdot \dfrac{\sqrt{2}}{2}-\dfrac{1}{2}\cdot \dfrac{\sqrt{2}}{2}}{\dfrac{1}{2}\cdot \dfrac{\sqrt{2}}{2}+ \dfrac{\sqrt{3}}{2}\cdot \dfrac{\sqrt{2}}{2}}\\\\\end{aligned}[/tex]

           [tex]\begin{aligned}&=\dfrac{\dfrac{\sqrt{2}}{2} \left(\dfrac{\sqrt{3}}{2}-\dfrac{1}{2}\right)}{\dfrac{\sqrt{2}}{2} \left(\dfrac{1}{2}+ \dfrac{\sqrt{3}}{2}\right)}\\\\&=\dfrac{\dfrac{\sqrt{3}}{2}-\dfrac{1}{2}}{ \dfrac{1}{2}+ \dfrac{\sqrt{3}}{2}}\\\\&=\dfrac{\dfrac{\sqrt{3}-1}{2}}{\dfrac{1+\sqrt{3}}{2}}\\\\&=\dfrac{\sqrt{3}-1}{1+\sqrt{3}}\end{aligned}[/tex]

Simplify further by multiplying the numerator and denominator by the conjugate of the denominator:

           [tex]\begin{aligned}&=\dfrac{\sqrt{3}-1}{1+\sqrt{3}}\cdot \dfrac{1-\sqrt{3}}{1-\sqrt{3}}\\\\&=\dfrac{(\sqrt{3}-1)(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\&=\dfrac{\sqrt{3}-3-1+\sqrt{3}}{1-\sqrt{3}+\sqrt{3}-3}\\\\&=\dfrac{2\sqrt{3}-4}{-2}\\\\&=-\sqrt{3}+2\\\\&=2-\sqrt{3}\end{aligned}[/tex]

Therefore, the exact value of tan 15° is (2 - √3).

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