Answer:
Step-by-step explanation:
(27)^2/3=∛27²=∛3³*3³=3*3=9
√36³=√36*36*36=√6²*6²*6²=6*6*6=216
(-243)^3/5=5√2-42³=-27
A gym for diabetes is offering a deal to new members. Customers can sign up by paying a registration fee of $250 and a monthly fee of $42. Which of the
following models the membership cost?
Answer:
the following model the membership cost is p=250+42m
(-4,-2) obtained by translating 3 units up followed by a reflection over the x axis
Answer:
Original Coordinates: (-4, 5)
Step-by-step explanation:
We simply take the opposite directions to find our original coordinates.
Step 1: Translate 3 units down
(-4, -2) --> (-4, -5)
Step 2: Reflect over x-axis
(-4, -5) --> (-4, 5)
can someone please help
Answer: 57°
Step-by-step explanation:
Bisecting makes angle ZXY=ZXW. So 58+58=116.
Then solve. 2x+2=116.
2x=114
x=57
The sum of the squares of three consecutive even integers is 980. Determine the integers.
Answer:
16, 18, 20
Step-by-step explanation:
We can estimate that the square of the middle integer will be about 1/3 of 980. Then the middle integer is about ...
√(980/3) ≈ 18.09
The integers are 16, 18, 20.
_____
Check
16^2 +18^2 +20^2 = 256 +324 +400 = 980
Answer:
16, 18, 20
Step-by-step explanation:
Let the three consecutive even integers be (x - 2), x, (x + 2)
[tex] \therefore \: {(x -2 )}^{2} + {x}^{2} + {(x + 2)}^{2} = 980 \\ \therefore \: {x}^{2} - 4x + 4 + {x}^{2} + {x}^{2} + 4x + 4 = 980 \\ \therefore \: 3{x}^{2} + 8 = 980 \\ \therefore \: 3{x}^{2} = 980 - 8 \\ \therefore \: 3{x}^{2} = 972 \\ \\ \therefore \: {x}^{2} = \frac{972}{3} \\ \\ \therefore \: {x}^{2} = 324 \\ \therefore \: x = \pm \sqrt{324} \\ \therefore \: x = \pm \: 18 \\ \because \: x \: is \: even \: integer \\ \therefore \: x \neq - 18 \\ \therefore \: x = 18 \\ \\ x - 2 = 18 - 2 = 16 \\ x = 18 \\ x + 2 = 18 + 2 = 20 \\ [/tex]
Hence, three consecutive even integers are : 16, 18, 20.
What is the nth term rule of the quadratic sequence below? 7, 14, 23, 34, 47, 62, 79
Answer:
Tn = Tn-1 + 2(n-1) + 5
Kindly note that Tn-1 means T subscript n-1
Step-by-step explanation:
Here, we want an expression for the nth term.
First term is 7
Then first common difference is 7
second common difference is 7 + 2
Third common difference is 9 + 2
So within the common differences, the nth term is 7 + (n-1) 2
Now, the nth term of the series would be;
Tn = Tn-1 + 7 + 2(n-1)
Tn = Tn-1 + 7 + 2n -2
Tn = Tn-1 + 2n + 5
Now there is a fix to this,
n for the term is not the same n for the common difference.
the 7th term works with the 6th common. difference, while the 8th term work for the 7th common difference.
So we might need to rewrite the final expression as follows;
Tn = Tn-1 + 2(n-1) + 5
HELP MEEEEE PLEASEEEEE SOMEONE!!
Answer:
A
Step-by-step explanation:
the triangles share one angle and they have two equal sides
Which of the following represents a rotation of triangle XYZ, which has vertices (-4,7), Y(6,2), and Z (3,-8) about the origin by 90 degrees? HELP PLS options: A: X (-7,-4) Y(6,-2) Z(-8,3) B: X(7,-4) Y(-2,6) Z (3,-8) C: X (-7,-4) Y(-2,6) Z (8,3) D: X(7,-4) Y (-2,6) Z (-3,8)
Answer:
The best option is B: X' = (-7,-4), Y' = (-2,6), Z'=(8, 3).
Step-by-step explanation:
Each vertex can be represented as a vector with regard to origin.
[tex]\vec X = -4\cdot i + 7\cdot j[/tex], [tex]\vec Y = 6\cdot i + 2\cdot j[/tex] and [tex]\vec Z = 3\cdot i -8\cdot j[/tex].
The magnitudes and directions of each vector are, respectively:
X:
[tex]\|\vec X\| = \sqrt{(-4)^{2}+7^{2}}[/tex]
[tex]\|\vec X\| \approx 8.063[/tex]
[tex]\theta_{X} = \tan^{-1}\left(\frac{7}{-4} \right)[/tex]
[tex]\theta_{X} \approx 119.744^{\circ}[/tex]
Y:
[tex]\|\vec Y\| = \sqrt{6^{2}+2^{2}}[/tex]
[tex]\|\vec Y\| \approx 6.325[/tex]
[tex]\theta_{Y} = \tan^{-1}\left(\frac{2}{6} \right)[/tex]
[tex]\theta_{Y} \approx 18.435^{\circ}[/tex]
Z:
[tex]\|\vec Z\| = \sqrt{3^{2}+(-8)^{2}}[/tex]
[tex]\|\vec Z\| \approx 8.544[/tex]
[tex]\theta_{Z} = \tan^{-1}\left(\frac{-8}{3} \right)[/tex]
[tex]\theta_{Z} \approx 290.556^{\circ}[/tex]
Now, the rotation consist is changing the direction of each vector in [tex]\pm 90^{\circ}[/tex], which means the existence of two solutions. That is:
[tex]\vec p = r \cdot [\cos (\theta \pm 90^{\circ})\cdot i + \sin (\theta \pm 90^{\circ})\cdot j][/tex]
Where [tex]r[/tex] and [tex]\theta[/tex] are the magnitude and the original angle of the vector.
Solution I ([tex]+90^{\circ}[/tex])
[tex]\vec p_{X} = 8.063\cdot [\cos (119.744^{\circ}+90^{\circ})\cdot i + \sin (119.744^{\circ}+90^{\circ})\cdot j][/tex]
[tex]\vec p_{X} = -7\cdot i -4\cdot j[/tex]
[tex]\vec p_{Y} = 6.325\cdot [\cos(18.435^{\circ}+90^{\circ})\cdot i+\sin(18.435^{\circ}+90^{\circ})\cdot j][/tex]
[tex]\vec p_{Y} = -2\cdot i +6\cdot j[/tex]
[tex]\vec p_{Z} = 8.544\cdot [\cos(290^{\circ}+90^{\circ})\cdot i +\sin(290^{\circ}+90^{\circ})\cdot j][/tex]
[tex]\vec p_{Z} = 8.029\cdot i +2.922\cdot j[/tex]
Solution II ([tex]-90^{\circ}[/tex])
[tex]\vec p_{X} = 8.063\cdot [\cos (119.744^{\circ}-90^{\circ})\cdot i + \sin (119.744^{\circ}-90^{\circ})\cdot j][/tex]
[tex]\vec p_{X} = 7\cdot i +4\cdot j[/tex]
[tex]\vec p_{Y} = 6.325\cdot [\cos(18.435^{\circ}-90^{\circ})\cdot i+\sin(18.435^{\circ}-90^{\circ})\cdot j][/tex]
[tex]\vec p_{Y} = 2\cdot i -6\cdot j[/tex]
[tex]\vec p_{Z} = 8.544\cdot [\cos(290^{\circ}-90^{\circ})\cdot i +\sin(290^{\circ}-90^{\circ})\cdot j][/tex]
[tex]\vec p_{Z} = -8.029\cdot i -2.922\cdot j[/tex]
The rotated vertices are: i) X' = (-7,-4), Y' = (-2,6), Z'=(8.029, 2.922) or ii) X' = (7,4), Y' = (2,-6), Z' = (-8.029, -2.922). The best option is B: X' = (-7,-4), Y' = (-2,6), Z'=(8, 3).
3. 10 + (8 x 3) - 32
Answer:
[tex]2[/tex]
Step-by-step explanation:
In order to find the answer to this question use PEMDAS and solve.
[tex]10+(8\times3)-32[/tex]
P goes first:
[tex]8\times3=24[/tex]
[tex]10+24-32[/tex]
A goes next:
[tex]10+24=34[/tex]
S goes last:
[tex]34-32=2[/tex]
[tex]=2[/tex]
Hope this helps.
Answer:
2
Step-by-step explanation:
10 + (8 x 3) - 32
So I’m assuming the x represents multiplication
10 + (8*3) - 32
In Pemdas parenthesis is always first
(8*3)=24
10+24-32
Then addition
10+ 24=34
34-32=2
I need help with this
Answer:
44
Step-by-step explanation:
MRQ=136
In a straight line there is 180 degrees
180-136=44
MRS=44 degrees
alternates angle is a z shape so NMRS is one
So you then RMP is 44 degrees.
Hope it helps just tryed
Help me with this somebody.
Answer:
B, √140
Step-by-step explanation:
√28+√112 = √140
The graph below shows a line of best fit for data collected on the number of toys sold at a toy store since the opening of the store. Based on the line of best fit, how many toys were sold 13 days after the store opened?
A.) 195
B.) 260
C.) 325
D.) 130
The answer that line of best fit, how many toys were sold 13 days after the store opened is A.) 195
Select the correct answer.
Based on the data in this two-way table, if a girl is randomly selected, what is the probability that she will have above-average grades?
Gender/Grade Below Average Above Average Total
Boy 14 23 37
Girl 16 22 38
Total 30 45 75
A.
0.29
B.
0.51
C.
0.58
D.
0.60
Answer:
Answer is C. 0.58
Step-by-step explanation:
22/38 = 0.57 something rounded to 58
the area of a rectangular sandbox can be expressed as 72xy + 18x the width of the sandbox is 9x what is the perimeter of the sandbox
Answer:
18x +16y +4
Step-by-step explanation:
The area is the product of length and width, so the length is ...
A = LW
L = A/W = (72xy +18x)/(9x) = 8y +2
The perimeter is double the sum of length and width:
P = 2(L +W) = 2(8y +2 +9x)
P = 18x +16y +4 . . . . the perimeter of the sandbox
Which one of the following is the graph of:
Answer:
B
Step-by-step explanation:
Correct if wrong
Mr. sanders recorded the amount he spent on gas each month to see if it would be cheaper to take the train to work. According to the table, what was the rate of change between January and May? Answers A) $67 Per Month B) $50 Per Month C) $53 Per Month D) $0 Per Month
Answer:
D) $0 Per Month.
Step-by-step explanation:
In January, Mr. Sanders spent $50 on gas. In May, Mr. Sanders spent $50 on gas. The amount that he spent on gas did not change from January to May, so the rate of change between January and May is D) $0 Per Month.
Hope this helps!
Please help i will mark brainliest
Answer:
y=-6x+1
Step-by-step explanation:
what is the square root of 9/49
Answer:
[tex] \pm \frac{3}{7} [/tex]
Step-by-step explanation:
[tex] \huge \sqrt{ \frac{9}{49} } = \pm \frac{3}{7} \\ [/tex]
What is the equation of a trend line that passes through the points (7,450) and (14,401).
Answer:
y = -7x + 499
Step-by-step explanation:
Slope-Intercept Form: y = mx + b
Slope Formula: [tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]
Step 1: Find slope m
m = (401 - 450)/(14 - 7)
m = -49/7
m = -7
y = -7x + b
Step 2: Find b
450 = -7(7) + b
450 = -49 + b
499 = b
Step 3: Rewrite equation
y = -7x + 499
AWARDING BRAINIEST
Find the perimeter of the following shape, rounded to the nearest tenth:
a coordinate plane with quadrilateral ABCD at A negative 2 comma 0, B 0 comma negative 2, C negative 3 comma negative 5, D negative 5 comma negative 3
A) 10
B) 11.3
C) 12
D) 14.1
Find the area of triangle ABC whose vertices are
A (-5, 7), B (-4, -5) and C (4, 5).
Answer:
[tex]Area = 51\:unit^2[/tex]
Step-by-step explanation:
[tex]Area = \sqrt{p(p-a)(p-b)(p-c)}\quad and \quad p=\frac{a+b+c}{2}[/tex]
Find the distance between three points.
[tex]\overline{AB}=\sqrt{\left(-4-\left(-5\right)\right)^2+\left(-5-7\right)^2}=12\\\\\overline{BC}=\sqrt{\left(4-\left(-4\right)\right)^2+\left(5-\left(-5\right)\right)^2}=12.8\\\\\overline{AC}=\sqrt{\left(4-\left(-5\right)\right)^2+\left(5-7\right)^2}=9.2[/tex]
[tex]p=\frac{12+12.5+9.2}{2}=16.9[/tex]
[tex]Area = \sqrt{16.9\left(16.9-12\right)\left(16.9-12.8\right)\left(16.9-9.2\right)}\\\\=51\:unit^2[/tex]
Best Regards!
Answer:
53 sq.unitssolution,
A(-5,7)--->(X1,y1)
B(-4,-5)-->(x2,y2)
C(4,5)--->(X3,y3)
Now,
Area of triangle:
[tex] \frac{1}{2} (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2) \\ = \frac{1}{2} ( - 5( - 5 - 5) + ( - 4)(5 - 7) + 4(7 - ( - 5) \\ = \frac{1}{2} ( - 5 \times ( - 10) + ( - 4) \times ( - 2) + 4 \times 12) \\ = \frac{1}{2} (50 + 8 + 48) \\ = \frac{1}{2} \times 106 \\ = \frac{106}{2} \\ = 53[/tex]
hope this helps...
Good luck on your assignment..
Can someone help me plzzzzz
Answer:
C
Step-by-step explanation:
arcs and circles formula? can someone help me find the answer?
Answer:
9.2 cmHere,
The length of an arc of a sector with theta nag radius'r' is:
[tex] \frac{theta}{360} 2\pi \: r[/tex]
CD=?
Radius=7.9 cm
theta=66.4
Length of CD
[tex] \frac{66.4}{360} \times 2 \times \pi \times 7.9 \\ = \frac{66.4}{360} \times 2 \times 3.14 \times 7.9 \\ = 9.1506 \\ = 9.2 \: cm[/tex]
Hope this helps...
Good luck on your assignment..
Solve the following equation for x: -7 + 4x + 10 = 15 - 2x *
Answer:
x=2
Step-by-step explanation:
-7+4x+10=15-2x
combine like terms
4x+3=15-2x
add 2x to both sides
6x+3=15
subtract 3 on both sides
6x=12
divide 6 on both sides
x=2
I'm not sure if I clicked the right answer, I hope you can help me :D
Answer this question
Answer: a.) (3x +1)(2x +3)
Step-by-step explanation:
The factors that work to get the middle term, 11x, are 3×3x = 9x and 1×2x=2x. 2x +9x = 11x
What is 2x + 2x + 2 = 4x + 2
Answer:
I think the answer is 33 I'm not sure but that is what I got
the qestion is in the picture
Answer:
25 students are in the class.
Step-by-step explanation:
There are 3/5 girls, and there are 10 boys, so there are 2/5 boys. 5/5 is the whole class, so here is how we would solve it: 2/5=10 3/5=15, 10+15=25. Hope this helps!
.......................
Answer:
Width: [tex]10y^6[/tex]
Length: 7y² + 3
Step-by-step explanation:
Step 1: Factor out 10
[tex]10(7y^8+3y^6)[/tex]
Step 2: Factor out [tex]y^6[/tex]
[tex]10y^6(7y^2+3)[/tex]
According to the question, the width is the monomial (1 term), so that is equal to [tex]10y^6[/tex]. That means the distributed part would be the length (7y² + 3).
The points A (-3, b), and B (1, 3) are 5 units apart. Find the value of b.
Answer:
b = 0
Step-by-step explanation:
To find the value of b, we will follow the steps below;
Using the distance formula:
D = √(x₂-x₁)² + (y₂-y₁)²
from the question given,
A (-3, b), this implies
(-3, b) = (x₁ ,y₁)
x₁=-3 and y₁ = b
similarly
B (1, 3)
(1, 3) = (x₂,y₂)
this implies
x₂ = 1 and y₂=3
D= 5
we can now proceed to insert the values into the formula and then solve for b
D = √(x₂-x₁)² + (y₂-y₁)²
5 = √(1+3)² + (3-b)²
5 = √4² + (3-b)²
5=√16 + (3-b)²
take the squares of both-side of the equation
5² = 16 + (3-b)²
25 = 16 + (3-b)²
subtract 16 from both-side of the equation
25 - 16 = (3-b)²
9 = (3-b)²
Take the square root of both-side
√9 = 3-b
3 = 3-b
add b to both-side of the equation
3 + b = 3 - b+ b
3 + b = 3
subtract 3 from both-side of the equation
3+b-3 = 3-3
b = 0
Therefore, the value of b is 0
Which compound inequality can be used to solve the inequality 13x+2 >7?
RE
-7 <3x+2> 7
ОООО
-7> 3x+2> 7
3x + 2 >-7 or 3x + 2 >7
3x + 2<-7 or 3x + 2 >7
Answer:
(D)[tex]3x+2 < -7$ or $3x+2 >7[/tex]
Step-by-step explanation:
Given the absolute inequality: [tex]|3x+2| >7[/tex]
When solving absolute inequalities, if the problem has a greater than sign we set up an "OR" compound inequality that looks like this:
(Expression inside absolute value) < - (number on other side) OR (Expression inside absolute value) > (number on other side)Therefore, for the absolute inequality |3x+2| >7, we have:
[tex]3x+2 < -7$ or $3x+2 >7[/tex]
The correct option is D.