Which inequality has an open circle when it is graphed on a number line?
3
42x
O xS12
O x2-6
Answer:
x > 3/5
Step-by-step explanation:
x > 3/5 has an open circle because 3/5 is not included
if it was x ≥ 3/5 then that would include 3/5 and the circle would be closed
brainliest for answer
Answer:
im not gonna help u~ but i can talk to u~ <3
Step-by-step explanation:
What is the value of x
Answer:
awnser is 36
Step-by-step explanation:
Answer: x = 37
Step-by-step explanation:
you can use the pythagorean theorem to solve this:
[tex]a^{2} + b^{2} = c^{2}[/tex]
'a' and 'b' in the equation is referring to the legs of the right triangle, or the sides adjacent to the hypotenuse (which is the side opposite the right angle)
plug in the legs into the equation and you get :
[tex]12^{2} + 35^{2} = x^{2}[/tex]
now to solve that we just square 12 and 35 and you get
144 + 1225 = [tex]x^{2}[/tex]
1369 = [tex]x^{2}[/tex]
x = [tex]\sqrt{1369}[/tex]
x= 37
:))
A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of 1.2 days. Construct a 95% confidence interval for the population's mean length of vacation. ( , ) Round your answer to two decimal digits Construct a 92% confidence interval for the population's mean length of vacation. ( , ) Round your answer to two decimal digits
Answer:
The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).
The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).
Step-by-step explanation:
We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 85 - 1 = 84
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 1.989.
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days
The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days
The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).
92% confidence interval:
Following the sample logic, the critical value is 1.772. So
[tex]M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23[/tex]
The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days
The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days
The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).
Aaron's bedroom is in the shape of a rectangular prism. The bedroom measures 10 feet by 14 feet by 8 feet. How many cubic feet of space does the room contain?
The formula for the area of a rectangular room is width x length, as shown in the figure below: This is the equation used in our square footage calculator as well.
Is the equation a linear function?
y = -x + 3 +
at party the pumpkin pie is cut into 14 slices and the cherry pies cut into seven slices if the host wants to serve identical plates that contained the same combination of pumpkin and Cherry sizes with no slices leftover what is the greatest number of plates the host can prepare
Answer:
The host can only prepare 7 plates
Step-by-step explanation:
7 plates, each will contain 1 slice of cherry pie and 2 slices of pumpkin pie. (14/7 = 2)
Solve.
–51/2 + 63/4 + (-41/4)
Answer:
-20
Step-by-step explanation:
cause i did the math hope this helped :D
I used a calculator, the answer is
-20
Find the area of each circle. Round to the nearest tenth. Use 3.14 for π.
Answer:
1. 490.6 mm²
2. 14.1 ft²
Step-by-step explanation:
1. 3.14×(12.5)²= 3.14 × 156.25 =490.6mm²
2. ½×3.14×3²= 3.14×4.5= 14.1 ft²
Use the figure to answer the question. 8 8 What is the area of the shaded region of the circle in terms of a? Enter the answer in the box. The area of the shaded region is f units squared.
Answer:
48pi
Step-by-step explanation:
pi x 8² - pi x 4²
64pi - 16pi
48pi
23 and 25
how do you do the work?
find the areas of each
9514 1404 393
Answer:
23) 35.77 in²
25) 48.19 cm²
Step-by-step explanation:
Use the appropriate area formula with the given information.
__
23) The area of a triangle is given by the formula ...
A = 1/2bh . . . . . base b, height h
A = 1/2(9.8 in)(7.3 in) = 35.77 in²
__
25) The area of a parallelogram is given by the formula ...
A = bh . . . . . . base b, height h
A = (7.9 cm)(6.1 cm) = 48.19 cm²
_____
The height in each figure is measured perpendicular to the base. This tells you that the length 10.6 cm of the diagonal side of the triangle is not relevant to finding the area.
Answer:
23) 35.77 in2
24) 48.19cm2
whats 6 divided by 10?
Answer:
1 r 4
Step-by-step explanation:
0 1
6 1 0
− 0
1 0
− 6
4
What is the volume of this shape in terms of π (PI)?
Answer:
Step-by-step explanation:
1/3 bh=96 pi/3=32 pi
Answer:
[tex]\displaystyle V = 32\pi \ in^3[/tex]
General Formulas and Concepts:
Symbols
π (pi) ≈ 3.14Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightGeometry
Volume of a Cone Formula: [tex]\displaystyle V = \frac{1}{3} \pi r^2h[/tex]
r is radiush is heightStep-by-step explanation:
Step 1: Define
Identify
r = 4 in
h = 6 in
Step 2: Find Volume
Substitute in variables [Volume of a Cone Formula]: [tex]\displaystyle V = \frac{1}{3} \pi (4 \ in)^2(6 \ in)[/tex]Evaluate exponents: [tex]\displaystyle V = \frac{1}{3} \pi (16 \ in^2)(6 \ in)[/tex]Multiply: [tex]\displaystyle V = \frac{1}{3} \pi (96 \ in^3)[/tex]Multiply: [tex]\displaystyle V = 32\pi \ in^3[/tex]Grandma is trying out a new recipe for raisin bread. Each batch of bread dough makes three loaves, and each loaf contains 15 slices of bread. If she puts 100 raisins into a batch of dough, what is the probability that a randomly chosen slice of bread contains no raisins
Answer:
0.108
Step-by-step explanation:
Using the poisson probability process :
Where :
P(x =x) = (e^-λ * λ^x) ÷ x!
Given that :
Each batch of bread = 3 loaves
Each loaf = 15 slices
Total slice per batch = 15 * 3 = 45 slices
Number of raising added = 100
Average number of raisin per slice, λ = 100/45 = 20/9
Hence,
Probability that a randomly chosen slice has no raising :
P(x = 0) = (e^-λ * λ^x) ÷ x!
P(x = 0) = (e^-(100/45) * (100/45)^0) ÷ 0!
P(x = 0) = (0.1083680 * 1) / 1
P(x = 0) = 0.108
The following is a linear programming formulation of a labor planning problem. There are four overlapping shifts, and management must decide how many employees to schedule to start work on each shift. The objective is to minimize the total number of employees required while the constraints stipulate how many employees are required at each time of day. The variables X1 - X4 represent the number of employees starting work on each shift (shift 1 through shift 4).
MIN X1 + X2 + X3 + X4
s.t. X1 + X4 ≥ 12 ........(on duty during shift 1)
X1 + X2 ≥ 15 ........(on duty during shift 2)
X2 + X3 ≥ 16 ........(on duty during shift 3)
X3 + X4 ≥ 14 ........(on duty during shift 4)
X1, X2, X3, and X4 ≥ 0
Given the optimal solution: X1* = 13, X2* = 2, X3* = 14, X4* = 0, how many workers would be assigned to shift 2?
a. 13
b. 12
c. 14
d. 15
e. 2
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
4. Your best friend's birthday is tomorrow, and you would like to give her an ice cream cone
balloon. The spherical shaped ice cream on top of the cone has a radius of 6 inches. The cone
itself has a diameter of 12 inches and height of 24 inches. How many cubic inches of helium are
nded to fill the entire ice cream cone balloon? Use 3.14 for it.
Answer:
1808.64 IN^3
Step-by-step explanation:
Helium needed = volume of spherical shaped ice cream + volume of cone
Volume of a sphere = 4/3 x pi x r^3
4/3 x 3.14 x 6^3 = 904.32 ft^3
Volume of a cone 1/3 x (nr^2h)
n = 22/7
r = radius = 12/2 = 6
the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.
h = height
1/3 x 3.14 x 6^2 x 24 = 904.32
helium needed = 2 x 904.32 = 1808.64 in^3
find value of x
3x (x+28)
Answer:
The value of x is 14.
Step-by-step explanation:
3x° = (x + 28)° [ vertically opposite angles
are equal]
3x = x + 28°
3x - x = 28°
2x = 28°
x = 28°/2
x = 14°
from a random sample of 24 months from january 2006 through december 2016, the mean of number of tornadoes per month in the united states was about 100. assume the population standard deviation is 114
I’ll make brainly if the answer is right
A fence is 8.5 feet tall. How many inches tall is it?
Answer:
The answer is 102, good luck<3
I need help pls! optional to give an explanation to help me understand :)
Answer:
(-4, 2)
Step-by-step explanation:
this is a simultaneous equation;
solving by substitution method, we have;
since y= ¼x + 3 and the same y= 2x + 10
therefore we combine both equations;
¼x + 3= 2x+10
3-10=2x-¼x
to clear out fraction, multiply throughout by 4
-28= 8x-x
-28= 7x
x= -28/7
x= -4
since x is -4, therefore All we have to do is to substitute x into y, doing this, we have;
y=2x+10
y= 2(-4) + 10
y= -8 + 10
y= 2
therefore y= 2 and x= -4
so the values are (-4, 2)
if you still don't understand, check your NGM SS2 textbook or make a comment and I will explain better
22. Using the graph, state the approximate
x-intercept of the function?
a. (0, -1)
b. (0.5, 0)
C. (-1,-1.75)
d. (1, 2)
Answer:
I believe Awnser B.. (0.5, 0)
Step-by-step explanation:
3. Which of the following is the solution for
the inequality below?
-3x+2<8
A x>-3
C x < -2
B x>-2
DX<-3
Find the zeros
[tex]x^3+8x^2-20x+48[/tex]
Answer:
Graph each side of the equation. The solution is the x-value of the point of intersection.
x≈−10.37392996
Step-by-step explanation:
A cheery tree is 6 feet tall. A palm is 3 times as tall as the cherry tree. Which model represents this problum
Answer: Bottom left
Step-by-step explanation:
Answer:
Bottom Left
Step-by-step explanation:
Im near 100% sure if im wrong im very sorry
A journal article reports that a sample of size was used as a basis for calculating a CI for the true average natural frequency (Hz) of delaminated beams of a certain type. The resulting interval was . You decide that a confidence level of is more appropriate than the level used. What are the limits of the interval
Answer:
The limit of the (228.533, 234.735)
Step-by-step explanation:
The values are missing in the given question. Therefore, in order to attempt this question, we will make assumptions.
So, let's assume that:
sample size of the journal article that was reported = 5
which is applied for determining a 95% CI
Also, assuming that the resulting interval = (229.764, 233.504)
However, if we are to use a 99% CI which we deemed to be more appropriate;
Then, our objective is to find the limits of this particular interval in question.
To do that:
We need to first find the sample mean at 95% CI by using the formula:
[tex]\Big ( \bar {x} - t_{\alpha/2, df} \ \dfrac{s}{\sqrt{n}}}, \bar x + t_{\alpha/2, df} \ \dfrac{s}{\sqrt{n}}} \Big) = (229.764,233.504)[/tex]
Since; df = n - 1
df = 5 - 1
df = 4
Then;
[tex]\Big ( \bar {x} - t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}}, \bar x + t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}} \Big) = (233.504+229.764)[/tex]
[tex]2 \bar {x} = (463.268)[/tex]
[tex]\bar {x} =\dfrac{463.268}{2 }[/tex]
[tex]\bar {x} =231.634[/tex]
Sample mean = 231.634
Using the same formula to determine the standard deviation, we have:
[tex]\Big ( \bar {x} - t_{\alpha/2, df} \ \dfrac{s}{\sqrt{n}}}, \bar x + t_{\alpha/2, df} \ \dfrac{s}{\sqrt{n}}} \Big) = (229.764,233.504)[/tex]
[tex]\Big ( \bar {x} - t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}}, \bar x + t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}} \Big) = (233.504-229.764)[/tex]
[tex]\Big ( (\bar x + t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}} )- (\bar {x} - t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}}) \Big) = (233.504-229.764)[/tex]
[tex]\Big ( (\bar x + t_{0.05/2, 4} \ \dfrac{s}{\sqrt{4}}} )- (\bar {x} - t_{0.05/2, 4} \ \dfrac{s}{\sqrt{5}}}) \Big) = (233.504-229.764)[/tex]
At t = 0.025 and df = 4; = 2.776
[tex]2\times 2.776 \dfrac{s}{\sqrt{5}}= 3.74[/tex]
[tex]5.552 \dfrac{s}{\sqrt{5}}= 3.74[/tex]
[tex]\dfrac{s}{\sqrt{5}}= \dfrac{ 3.74}{5.552}[/tex]
[tex]\dfrac{s}{\sqrt{5}}= 0.6736[/tex]
[tex]s = 0.6736 \times \sqrt{5}[/tex]
s = 1.5063
The 99% CI is:
[tex]\implies \Big(\bar x \pm t_{\alpha/2,4} \dfrac{s}{\sqrt{n}} \Big)[/tex]
At t =0.005 and df =4; = 4.604
[tex]\implies \Big(231.634 \pm 4.604 \dfrac{1.5063}{\sqrt{5}} \Big)[/tex]
[tex]\implies \Big(231.634 \pm 4.604 (0.67364) \Big)[/tex]
[tex]\implies \Big(231.634 \pm 3.1014 \Big)[/tex]
[tex]\implies \Big((231.634 - 3.1014), (231.634 + 3.1014) \Big)[/tex]
[tex]\implies \Big( 228.533, 234.735 \Big)[/tex]
(Worth 10 points)
Please actually answer this question
Answer:
i belive the correct awnser is A
Step-by-step explanation:
9514 1404 393
Answer:
A figure 1
Step-by-step explanation:
The given equation is in slope-intercept form:
y = mx + b . . . . . . where m is the slope and b is the y-intercept
The slope and y-intercept in your equation are both 2. That means the graph crosses the y-axis at y=2 (above the x-axis), and has a positive slope (goes up to the right.
The two top graphs, figures 1 and 2, show lines with positive slope. Only figure 1 shows a graph with positive slope and a positive y-intercept.
pls pls pls 4/1 68 The angle that is an alternate exterior angle with angle 2 is angle [?] 57 3/2 A. 3 B. 4 C. 5 D. 6
Answer:
B. 4
Step-by-step explanation:
∠4 is an alternate exterior angle with ∠2 because both angles are on the exterior of the lines, and lie on opposite ends on the transversal.
The angle that is an alternate exterior angle with angle 2 is angle 4.
What are Parallel lines?Parallel lines are those lines that are equidistance from each other and never intersect each other.
Given that;
The figure is shown in figure.
Now,
Since, ∠4 is an alternate exterior angle with ∠2 because both angles are on the exterior of the lines, and lie on opposite ends on the transversal.
Hence, ∠4 is an alternate exterior angle with angle 2.
Thus, The angle that is an alternate exterior angle with angle 2 is angle 4.
Learn more about the parallel lines visit:
https://brainly.com/question/26961508
#SPJ2
Maria has a jewelry box and wants to increase its size. She finds one with four times the length, width, and height. How many times bigger will the volume of the box be?
Answer:
64 times bigger
Step-by-step explanation:
I will use random values for this explanation to make it more understandable.
Lets say the length of the box is 1 inch, width is 1 inch, and height is 1 inch.
The volume would be l*w*h = 1*1*1 = 1 cubic inch
If the dimensions were 4 times bigger, the length, width and height would all be 4 inches.
4*4*4 = 64 cubic inches, which is 64 times bigger than the smaller box with a volume of 1 cubic inch.
Hope this answer helped! :)
Dan wants to determine the number of liters of a 20% acid cleaning solution that he should combine with an 80% acid cleaning solution to create 50 liters of a 60% acid cleaning solution. Part A Let z represent the number of liters of the 20% acid cleaning solution. Which equation represents this situation? O 0.6(50) = 0.2x + 0.8x O.0.20 +0.8(50 – x) = 0.6(50) O 0.6(50) = 0.20 +0.8(x – 50) O 0.22 +0.8(x + 50) = 0.6(50) Part B