Help please! Thank you

Help Please! Thank You

Answers

Answer 1

Answer:

c

Explanation:


Related Questions

30. Easy Guided Online Tutorial One object is at rest, and another is moving. The two collide in a one-dimensional, completely inelastic collision. In other words, they stick together after the collision and move off with a common velocity. Momentum is conserved. The speed of the object that is moving initially is 25 m/s. The masses of the two objects are 3.0 and 8.0 kg. Determine the final speed of the two-object system after the collision for the case when the large-mass object is the one moving initially and the case when the small-mass object is the one moving initially.

Answers

Answer:

[tex]18.18\ \text{m/s}[/tex]

[tex]6.82\ \text{m/s}[/tex]

Explanation:

[tex]m_1[/tex] = Mass of large object = 8 kg

[tex]m_2[/tex] = Mass of smaller object = 3 kg

When large mass is moving

[tex]u_1[/tex] = 25 m/s

[tex]u_2[/tex] = 0

For completely inelastic collision we have the relation

[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{8\times 25+3\times 0}{8+3}\\\Rightarrow v=18.18\ \text{m/s}[/tex]

Speed of the combined mass when the larger object is moving is [tex]18.18\ \text{m/s}[/tex]

When smaller mass is moving

[tex]u_1[/tex] = 0

[tex]u_2[/tex] = 25 m/s

[tex]v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{8\times 0+3\times 25}{8+3}\\\Rightarrow v=6.82\ \text{m/s}[/tex]

Speed of the combined mass when the smaller object is moving is [tex]6.82\ \text{m/s}[/tex]

pls help
How much work is done when a bucket of mass 2kg with 20kg
of water in it is pulled up from the bottom of a well 10m deep?​

Answers

Answer:

2156 J

Explanation:

From the question,

Work done = Combined mass of the bucket and water×height×gravity.

W = (M+m)hg............................. Equation 1

Where M = mass of water, m = mass of the bucket, h = height, g = acceleration due to gravity.

Given: M = 20 kg, m = 2 kg, h = 10 m

Constant: g = 9.8 m/s²

Substitute these  value into equation 1

W = (20+2)×10×9.8

W = 22×98

W = 2156 J

The force experienced by an electron in a field between parallel plates is proportional to which of the following? Select all that apply.

the potential difference between the plates

the current in the circuit

the inverse of the potential between the plates

the distance between the plates

the inverse of the distance between the plates

Answers

Answer:

2 and 5

Explanation:

it's correct i think

The velocity of a car changes from 15 m/s south to 5 m/s south in 2
seconds. What is the acceleration of the car?
A. 5 m/s2 north
B. 10 m/s2 north
C. 10 m/s2 south
D. 5 m/s2 south

Answers

Answer:

Acceleration of car = -5 m/s south

Explanation:

Given:

Initial velocity = 15 m/s

Final velocity = 5 m/s

Time taken = 2 sec

Find:

Acceleration of car

Computation:

Acceleration = Change in velocity / time

Acceleration of car = [5-15] / 2

Acceleration of car = -5 m/s south

If a car is traveling 103 miles per hour and passes another vehicle which is at a complete stop, how many miles would it take the stopped vehicle to catch the traveling vehicle?

Answers

Answer:

206 mph i think

Explanation:

which two options describes behaviors of particles that are related to the chemical properties of the materials

a- forming hydrogen bonds between them
b- reacting quickly with water
c- having a high mass
d- forming bonds with other atoms

Answers

The answer is D I’m pretty sure

Answer:

The two correct answers are B.) reacting quickly with water, and D.) forming bonds with other atoms.

Explanation:

I took the quiz on a.pex and these were correct.

The way you change the speed of a wave is to:

a
Change it's medium
b
Change it's energy
c
Transfer it to a new position
d
Apply a force

Answers

Answer:

transfer it to a new position

One day, Peter put a leaf in hot water. After a while, he noted that a lot of air bubbles appeared on the lower surface of the leaf, but only a few air bubbles were found on the upper surface. Where did the air bubbles come from (name the part)?

Answers

Answer:

The air bubbles are oxygen coming out of the leaf

Explanation:

Though the leaf is in hot water, it is still using light to continue on the path of photosynthesis. Now, this path of photosynthesis involves letting oxygen out of the leaf. Thus, this oxygen is the one that we see as bubbles coming out of the water.

The reason for having more air bubbles at the lower surface than at the upper surface is because the leaf cells at the lower surface of the leaf possess faster photosynthetic rate in releasing

oxygen.

2. An electron and a proton are separated by 5 cm:
a) what is the magnitude of the force on the electron?
b) What is the net force on the system?

Answers

Answer:

a) the charge of an electron is equivalent to the magnitude of the elementary charge but barring a negative sign since the side of the elementary charge is roughly 1.602 * 10 - 19 Columbus then the charge of the electronic is-1.602 * 10 - 19

b) b=2T on the electron moving in the magnetic field

You push a cart with mass 15 kg forward, giving it an acceleration of 3 m/s2
How much force did you apply?

Answers

Answer:

45 N

Explanation:

F= ma (ie force is found by multiplying the mass of the object by its accerelation)

thus, F =  15 X 3 = 45 N

Which measures the amount of work you did?

I don’t get it

Answers

Answer:

Power is often measured in joules of work per second. The unit of measurement for power is the (W). One watt is equal to one joule of work done in one second. If an object does a large amount of work, its power is usually measured in units of 1000 watts, or kilowatts.

Explanation:

It is the second option. Because work is force * distance.

Currently accepted theories DO NOT predict single existing particles having electrical charge equal (Picture Provided)

Answers

tbm queria saber essa pergunta!!

If you wrap 150 coils of heavy wire around a big iron nail and attach the ends of the wire to a 6.0v battery, you have a A) radio B) electromagnet C) galvanometer D) ammeter​

Answers

Answer:

B

Explanation:

Because of the voltage attached to the iron nail

A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?

3.13 m/s2

4.22 m/s2

5.31 m/s2

6.67 m/s2

none of the above

Answers

First convert 90km/hr to m/s.

Initiate velocity = 0m/s (car was at rest)

Final velocity is 25m/s (90km/hr converted)

25m/s - 0m/s / 8s = 3.125 m/s^s

Therefore the answer is option A (3.13m/s^2)

WILL REWARD 20 more pts once solved

4) If you have a diverging lens with a focal length of -15 cm and it produces an image that is 9
cm from the lens, what is the height of the image if the object was 4,5 cm tall?
b) Draw a ray tracing diagram of the situation below (label all points in cm) :

Answers

Explanation:

step 1. a diverging lens is "concave" on both side and always has a negative focal length

step 2. so 1/f = 1/s + 1/s' where f is the focal length, s is the object location, and s' is the image location (f, s, s' are all on the left side of the lens)

step 3. 1/-15 = 1/s + 1/-9 (image is virtual (negative))

step 4. 3/-45 = 1/s + 5/-45

step 5. s = 22.5cm (object is 22.5cm from lens)

step 6. s'/s = 9/22.5 ÷ 0.4 (magnification)

step 7. if the object is 4.5cm then the image is 4.5(0.4) = 1.8cm tall.

Match the descriptions with the graphs !

Answers

Answer:

Graph 1 matches with B, 2 with A, and 3 with C.

Explanation:

Graph 2 shows a car whose distance part of the graph is not going up or down, while the time going up. That means that the car is stopped. Graph 1 shows a straight line, meaning that the car is traveling at a constant speed. Graph 3 is a curved line, meaning the speed of the car is changing somehow, and since the line is becoming more horizontal, the car is getting slower.

Describe an example of an assignment that could be used in science, technology, engineering, or mathematics that would allow a student to apply a concept he has learned.

Answers

Answer:

A notebook because they can take notes of what they have learned

Explanation:

A car travels at a constant speed of 25 m/s. Find the power supplied by the engine if it can supply a maximum force of 18,000 N​

Answers

Answer:

720

Explanation:

Obtain a permanent magnet and an object that is attracted to the magnet but not repelled. Imagine that you do not know which object is the magnet. Using only these two objects, find a way to determine which object is the permanent magnet. Describe it below (Hint: Are there parts on either object that do not interact as strongly as other parts. This may be harder with refrigerator magnets which may have multiple north and south poles.)

Answers

Answer:

the ends of the permanent magnet have a much greater magnetic force than its central parts,

Explanation:

In this exercise we can assume that we have two small bars, one of them magnetic and the other not (iron).

 If we approach one of the bars by its two ends to the end of the other we see that it attracts it and if we approach it through its center the attraction is very small.

Now let's change the bar, we bring it closer to the other by its ends and its center to the end of the other and we see that the attraction is the same in all cases.

After these two experiments we can say that the first bar is the permanent magnet.

In conclude the ends of the permanent magnet have a much greater magnetic force than its central parts, this can be applied to any shape of the magnet

The answer to the investigative question,_____1______, is___2_____. A piece of data from the results that supports this is_____3______. For example, when ____4____happens, then _____5____happens. The data does/does not support the hypothesis because_____6____ and the data shows____7____. The evidence to support this conclusion is_____8_____. Compared to the data, this proves___9___. Based on___10___, one can conclude that __11__. The hypothesis of______12______ was correct/incorrect because____13____.

Answers

Answer:

:)

Explanation:

:))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))

Un basquetbolista efectúa lo siguientes desplazamientos 6 metros al este 4 metros en dirección noroeste y finalmente 2 metros norte°Cual es la distancia total que recorre?
°Encuentra en forma gráfica el desplazamiento resultante en que dirección actúa y cual es el valor del angulo medido respecto al este​

Answers

Answer:

R = 10.06 m,   θ = 28.7º

Explanation:

o find the total displacement the best way is to find the displacement in the x (East) and y (North) axes

let's decompose the displacements

              d₂ = 4 m

              θ₂ = 45

           

let's use trigonometry

             cos 45 = x₂ / d₂

             sin 45 = y₂ / d₂

             x₂ = d₂ cos 45

             y₂ = d₂ sin 45

             x₂ = 4 cos 45 = 2,828 m

             y₂ = 4 sin 45 = 2,828 m

The shredding the x axis is

             x_total = x₁ + x₂

             x_total = 6 + 2,828

             x_total = 8,828 m

The displacement in the y-axis

             y_total = y₂ + y₃

              y_total = 2,828 + 2

              y_total = 4.828 m

Let's use Pythagoras' theorem for total displacement

             R = [tex]\sqrt{x_{total}^2 + y_{total}^2 }[/tex]

             R = [tex]\sqrt{8.828^2 + 4.828^2 }[/tex]

             R = 10.06 m

for the direction let's use trigonometry

             tan  θ = [tex]\frac{x_{total} }{y_{total} }[/tex]

             θ = tan⁻¹  \frac{x_{total} }{y_{total} }

             θ = tan⁻¹ [tex]\frac{ 4.828}{ 8.828}[/tex]

             θ = 28.7º

this angle is measured counterclockwise from the positive side of the x axis (Eat)

Why do people make this to the seashore?

Answers

Answer:

Protecting the Seashore

Seashore Conservation Code

When investigating a seashore it is important to remember that the welfare of the plants and animals must come first. If seaweeds are attached to rocks do not try to pull them off, just examine them where they are growing. Handle animals with great care, returning them to the place where they were found. Anemones and limpets are normally firmly stuck to rocks and any attempt to remove them may result in their death. Replace any large stones that are removed – animals that live on the underside soon die if left exposed.

Pollution Problems

Seas and seashores are under continual threat from pollution. Here are some examples:-

oil rigOil spills, either accidental or deliberate, have a devastating effect on marine life, especially seabirds. Black tar-like oil washed up on a rocky shore would obviously completely destroy the entire community of living things. Chemicals used to disperse oil spills on a shore may effectively clean up the oil, but they can also cleanse the shore of life! The best policy for marine life is to physically remove as much oil as possible and leave the rest to degrade naturally. A rocky shore will recover much more quickly if chemicals are not used.

Sewage and litter also upsets seashore ecosystem, making them unsightly and perhaps contaminated. Some litter can be dangerous to wildlife.

Toxic chemicals and radioactive waste - a cocktail of toxic chemicals have found their way into the sea over the years, affecting both marine and human life. For many years potentially deadly radioactive waste from nuclear power stations and other sources was disposed of in the sea, and beaches have been contaminated by accidental leakages from nuclear power stations.

Explanation:

Answer:

Hey mate....

Explanation:

This is ur answer....

REASONS:-

Soothing salt water. The minerals and salt in the ocean water soothe aching joints.  

Exfoliate with sand. Sand acts as a natural exfoliator.  

Workout in the waves.  

Vital vitamin D.  

Clear the mental clutter.  

Technology detox.  

Enjoying company.

Hope it helps!

Mark me brainliest....

FOLLOW ME! :)

HELP PLEASE DUE IN 3 MINUTES

Answers

Answer:

1. slides and scrapes

2. pulls away

3. crashes into each other

Explanation:

Answer:

transform

convergent

divergent

Explanation:

Converge means to come together

Diverge means to move away

How much work is done in pushing an object 7.0 m across a floor with a force of 50 N and then
pushing it back to its original position? How much power is used if this work is done in 20 sec?

Answers

Answer:

35/2 J/s

Explanation:

Just use the 2 formulas

Work done = Force * distance moved

Power = Work done/time

WD = 7 * 50  = 350

Power = 350 / 20

= 35/2 J/s

Snell's law describes the relationship between the angle a light ray makes as it leaves a surface, the angle it makes incident on the surface, and the indices of refraction on both sides of the surface. If light incident in air at angle of 30 degrees from the normal onto glass with an index of refraction of 1.5 --Pick those answers that applya) Inside the material, the light leaving the surface is closer to the surface, makes a bigger angle with the normal, than the entering light makes in air.b) The light inside the glass is closer to the normal, makes a bigger angle with the surface, than the incident lightc) There is light reflected back into the air from the surfaced) The angle is too steep for light to refract and it is all reflected.

Answers

Answer:

b) and c)

Explanation:

Snell's law states that there exists a fixed relationship between the sine of the angle that makes with the normal an incident ray on the separation surface of two transparent media, the sine of the angle that is refracted off the surface, and the indexes of refraction of both media, as follows:

       [tex]\frac{sin_{\theta i}}{sin_{\theta r} } =\frac{n_{2} }{n_{1} } (1)[/tex]

Givens: θi = 30º n₁ = 1 (air) n₂= 1.5 (glass)Since sin 30º = 0.5, we can solve for sin r, as follows:[tex]sin \theta r = \frac{sin_{\theta i}}{n_{2}} = \frac{0.5}{1.5} = 0.333 (2)[/tex]As the sin r is lower than sin i, this implies that the angle that makes with the normal is lower than i, which means that it makes a bigger angle with the surface, as stated by b).Also there is some light that is reflected by the surface, making an angle with the normal equal to the incident ray, as stated by c). So, b) and c) are the right choices.

An object that weighs 500 kg is rolling along the road at 3.5 m/s, what is the momentum of the object?

Answers

Answer:

momentum=mass x velocity= 500 x 3.5 = 1750kgm/s

Calculate the amount of torque of an object being pushed by 6 N force along a circular path of a radius of 1x10^-2 mat 30 degree angle.

Answers

Answer:

The amount of torque is 0.03 N.m.

Explanation:

To find the amount of torque we need to use the following equation:

[tex] \tau = \vec {r} \times \vec{F} = rFsin(\theta) [/tex]   (1)

Where:

r: is the radius = 1x10⁻² m

F: is the force = 6 N

θ: is the angle = 30°

By entering the above values into equation (1) we have:

[tex]\tau = 1 \cdot 10^{-2} m*6 N*sin(30) = 0.03 N.m[/tex]  

Therefore, the amount of torque is 0.03 N.m.

I hope it helps you!

Kyle lays a mirror flat on the floor and aims a laser at the mirror. The laser beam reflects off the mirror and strikes an adjacent wall. The plane of the incident and reflected beams is perpendicular to the wall. The beam from the laser strikes the mirror at a distance a=60.1 cm from the wall. The reflected beam strikes the wall at a height b=31.3 cmabove the surface of the mirror.Find the angle of incidence θiat which the laser beam strikes the mirror.

Answers

Answer:

62.5 °

Explanation:

✓From law of reflection, angle of incidence equals angles of reflection .

✓the angle between the reflected ray can be determined using trigonometry, we know that

horizontal distance x =60.1 cm

the vertical distance is y =31.3

Then

tan( θ) =( y / x)

If we substitute the values we have,

tan θ = 31.3 / 60.1

θ = tan⁻¹ (0.5208)

θ = 27.5°

This angle is been measured using x-axis (horizontal)BBut in optics we can measured with respect to y-axis then angle becomes

θ = 90 - 27.5

θr = 62.5 °

θr = θi= 62.5°

the angle of incidence θiat which the laser beam strikes the mirror is 62.5°

Which of the following would produce the most power?
b
ОООО
A mass of 10 kilograms lifted 10 meters in 10 seconds
A mass of 5 kilograms lifted 10 meters in 5 seconds
A mass of 10 kilograms lifted 10 meters in 5 seconds
A mass of 5 kilograms lifted 5 meters in 10 seconds
d

Answers

Answer:

A mass of 10 kilograms lifted 10 meters in 5 seconds.

Explanation:

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

[tex] Power = \frac {Energy}{time} [/tex]

But Energy = mgh

Substituting into the equation, we have

[tex] Power = \frac {mgh}{time} [/tex]

Given the following data;

Mass = 10kg

Height = 10m

Time = 5 seconds

We know that acceleration due to gravity is equal to 9.8 m/s²

[tex] Power = \frac {10*9.8*10}{5} = 490 Watts [/tex]

Hence, a mass of 10 kilograms lifted 10 meters in 5 seconds would produce the most power.

A marching band consists of rows of musicians walking in straight, even lines. When a marching band performs in an event, such as a parade, and must round a curve in the road, the musician on the outside of the curve must walk around the curve in the same amount of time as the musician on the inside of the curve. This motion can be approximated by a disk rotating at a constant rate about an axis perpendicular to its plane. In this case, the axis of rotation is at the inside of the curve.Consider two musicians, Alf and Beth. Beth is four times the distance from the inside of the curve as Alf. Knowing that If Beth travels a distance s during time Δt, how far does Alf travel during the same amount of time= (1/4)s. If Alf moves with speed v, what is Beth's speed?

Answers

Answer:

a) Alf travels a quarter of the distance of Beth

b) linear velocity of Beth is 4 times greater than the linear velocity of Alf

Explanation:

This is an exercise that we can solve using the angular kinematic relations and its relation to the linear scientific one

             s = θ r

             v = ω r

the distance relationship between the two musicians is

if alf is at a distance r₁ = R₀ from the center of the curve

Beth has a distance r₂ = 4 R₀

a) ask for the distance traveled by Alf

Let's find the angle that Beth travels (Musician 2)

            θ = s₂ / r₂

             

the angle traveled is the same for the two musician, the angle for Alf is

            θ = s₁ / r₁

             s₂ /4R₀ = s₁ /R₀

             s₁ = s₂ / 4

therefore Alf travels a quarter of the distance of Beth

b) Beth's linear velocity

           

look for the angular velocity that is the same for the two musicians

           w = v₁ / r₁

            w = v₂ / r₂

   

we equalize

           v₁ / r₁ = v₂ / r₂

           v₁/R₀ = v₂/4R₀

            v₂ = 4 v₁

therefore the linear velocity of Beth is 4 times greater than the linear velocity of Alf

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