help please it important

x: cupcakes

y: cakes

[tex]2.50x + 15y \geqslant 510 [/tex]

cakes is 15

2.50(114)+15y....≥510

(285+15y≥510)-285

(15y≥225)/15

y≥15

9514 1404 393

Answer:

  4.  2.5x +15y > 510

  5.  y > 10

Step-by-step explanation:

4. The revenue from each of x cupcakes is 2.50, so the total revenue from cupcake sales is 2.50x.

The revenue from each of y cakes is 15.00, so the total revenue from cake sales is 15.00y.

The total revenue from sales of cupcakes and cakes is more than 510, so we can write the inequality ...

  2.5x +15y > 510 . . . . possible combinations of cakes and cupcakes

__

5. For x=144 the constraint on y is ...

  2.5(144) +15y > 510

  360 +15y > 510

  15y > 150

  y > 10 . . . . possible number of cakes sold

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