Answers
Related Questions
1)n/5=-10 How do we answer this question
Answers
Answer: Your answer will be [tex]\frac{-50}{5} =-10[/tex]
Step-by-step explanation: You will have
[tex](5)\frac{n}{5} =-10(5)[/tex] you will have to multiply 5 on both sides. So you will then simplify 5 and 5 to be left with n and multiply -10(5)=-50
So you get [tex]n=-50[/tex]
Jenny spends $4 for breakfast and then $4 for lunch
Answers
Answer:
$8
Step-by-step explanation:
If you forgot to add something I'll answer that
When Natalie finishes drawing the large triangle on the poster board, what will be the approximate measure of side BC? Round to the nearest centimeter.
Answers
Answer:
31 cm
Step-by-step explanation:
The complete question is attached.
A triangle is a polygon with three sides (three edges and three vertices). There are different types of triangles which are equilateral triangles, right triangles, scalene triangles, obtuse triangles, acute triangles, and isosceles triangles.
An equilateral triangle is a triangle in which all its sides are equal and all its angles are equal to 60°.
From the triangle, AB = BC = AC = 9.5 cm
Since the triangle is enlarged 3.25 times, hence:
new length of BC = 9.25 cm × 3.25 = 30.875
New length of BC = 31 cm to nearest cm
are these called interior angles ?
Answers
Answer:
yes they are
Step-by-step explanation:
If an angle of a parallelogram is two-third of
its adjacent angle, the smallest angle of the
parallelogram is
(a) 54°
(b) 72°
(c) 81°
(d) 108°
Answers
Answer:
We know that in a parallelogram two opposite angles are equal -
[tex] \\ \implies \sf \: 2x + 2y = 360 {}^{ \circ} \\ \\ \\ \implies \sf \: x + y = 180 {}^{ \circ} \qquad \quad \: (i) \\ [/tex]
Given -
angle x is equal to the two - third of it's adjacent angle y.[tex] \\ \implies \sf \: x = \frac{2}{3} y \\ \\ \\ \implies \sf \frac{x}{2} = \frac{y}{3} = k \\ \\ \\ \qquad \sf \small \underline{ x = 2k \: \: \& \: \: y = 3k} \\ [/tex]
Now, by using equation (1) :
[tex] \\ \implies \sf \: 2k + 3k = 180 \\ \\ \\ \implies \sf \: 5k = 180 \\ \\ \\ \implies \sf \: k = \frac{180}{5} \\ \\ \\ \large{ \boxed{ \sf{k = {36}^{ \circ} }}} \\ [/tex]
Now, by putting the value of k in x and y.
x = 2k = 2 × 36 = 72° y = 3k = 3 × 36 = 108°Therefore, the right option and smallest angle is b) 72°.
Mai wants to make a scale drawing of her kitchen. her kitchen is a rectangle with length 6m and width 2m. She decides on a scale of 1 to 40. Mal's Kitchen door is 1.2 m wide. How wide should the door be on the scale drawing?
How wide should the door be on the scale drawing?
cm
Explain how you know
Type your response in the box below.
c. Mai's kitchen table measures 4 cm by 2.5 cm on the scale drawing.
What are the actual measurements of her kitchen table?
Type your answers in the boxes below.
Answers
Answer:
Her door should be 3cm on scale
The actual dimension of the kitchen table is
[tex]Length = 1.6m[/tex]
[tex]Width = 1m[/tex]
Step-by-step explanation:
Given
[tex]Scale= 1 : 40[/tex]
[tex]Kitchen\ Dimension= 6m\ by\ 2m[/tex]
[tex]Door\ Width = 1.2m[/tex]
Solving (a): The width of the door on the scale
Represent the scale width with x
So, we have:
[tex]1 : 40[/tex]
and
[tex]x : 1.2[/tex]
Equate both ratios
[tex]1 : 40 = x : 1.2[/tex]
Represent as fraction
[tex]\frac{1}{40} = \frac{x}{1.2}[/tex]
Solve for x
[tex]x = \frac{1.2}{40}[/tex]
[tex]x = 0.03m[/tex]
[tex]x = 3cm[/tex]
Hence, her door should be 3cm on scale
Solving (b): Actual Dimension of the kitchen table
To solve this, we simply multiply the scale dimensions by 40
[tex]Length = 4cm * 40[/tex]
[tex]Length = 160cm[/tex]
[tex]Length = 1.6m[/tex]
[tex]Width = 2.5cm * 40[/tex]
[tex]Width = 100cm[/tex]
[tex]Width = 1m[/tex]
Hence:
The actual dimension is
[tex]Length = 1.6m[/tex]
[tex]Width = 1m[/tex]
I need help I turn this in in less than 20 min
Answers
x=6
The answer will be
x=6
Using the order of operations, what should be done first to evaluate 6 + StartFraction (negative 5 minus 7) over 2 EndFraction minus 8 (3)? Subtract 7 from –5. Multiply 8 and 3. Divide 7 by 2. Add 6 and –5. can yall pls hurry i need this right now
Answers
subtract 7 from -5
Step-by-step explanation:
Answer:
Subtract 7 from –5.Step-by-step explanation:
I just took the test and it said that Subtract 7 from –5 was right
Is 4.5 natural number?
Answers
Answer:
No
Step-by-step explanation:
4.5 IS NOT A WHOLE NUMBER!
Answer:
YES 4.5 IS NATURAL NUMBER
Step-by-step explanation:
How much interest is earned on $470 at
4% for seven years?
Answers
Evaluate the expression 3x - 8 when x = 2
Someone help me
Answers
Answer:
-2
Step-by-step explanation:
3x - 8
Let x=2
3*2 -8
6-8
-2
Answer:
6-8 = -2
Step-by-step explanation:
3 x if x equals 2 then 3 times 2 is 6. 6 minus 8 is -2!
Hope this helps! If it does, please mark me brainliest because it will help me. Thank you so much! ;) :)
A used car is for sale for $8,950. If Jenny will pay for the car over a 5 year period, what will be her monthly payment, to the nearest dollar?
3,729/month
1,790/month
149/month
60/month
Answers
Answer:
your answer will be 149/month
Step-by-step explanation:
you wanna ask urself how many months are in 5 years
The answer is: 60 months
then, you wanna divide the cost of the car over 60 months
So:
[tex]$8950/60=149.166[/tex]
round that to the nearest dollar AKA the ones
it'll be 149
and don't forget the unit of time
which is month
$149/month
What is the value of x?
5 + 2/3x = -x + 20
Please explain:
Answers
The value of X is 9.
Solve for x by simplifying both sides of the equation, then isolating the variable.
The “Get Up” challenge set to Ciara’s song is a dance that takes about 15 seconds to perform. What percent of the full 4-minute-and-23-second song does the dance represent?
Answers
Answer:
5.70%
Step-by-step explanation:
It takes the time to perform on Ciara's song = 15 seconds
Total time given as 4 minutes 23 seconds ≈ (4×60) seconds + 23 seconds
= 240 seconds + 23 seconds
= 263 seconds
Percent of time taken to perform of the full time = [tex]\frac{\text{time taken to perform}}{\text{Total time}}\times 100[/tex]
= [tex]\frac{15}{263}\times 100[/tex]
= 5.70 %
Therefore, percent of the time taken for the performance on the full song will be 5.70%
Performance task: A parade route must start And and at the intersections shown on the map. The city requires that the total distance of the route cannot exceed 3 miles. A propos route is shown.
Part A: Why does the proposed route not meet the requirement?
Part B: Assuming that the roads used for the
route are the same and the end point is the same,
at what intersection could the parade start so the
total distance is as close to 3 miles as possible?
Part C: The city wants to station video cameras halfway down each road in the parade. Using your answer to Part B, what are the coordinates of locations for the cameras?
Answers
Answer:
Part A: The proposed route does not meet requirement because it is longer than the maximum required length of 3 miles
Part B: For the total distance is as close to 3 miles as possible, the start point of the parade should be at the point on Broadway with coordinates (9.941, 4.970)
Part C: The coordinates of the cameras stationed half way down each road are;
For central avenue; (4, 2)
For Broadway; (7.97, 2.49)
Step-by-step explanation:
Part A: The length of the given route can be found using the equation for the distance, l, between coordinate points as follows;
[tex]l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}[/tex]
Where for the Broadway potion of the parade route, we have;
(x₁, y₁) = (12, 3)
(x₂, y₂) = (6, 0)
[tex]l_1 = \sqrt{\left (0 -3\right )^{2}+\left (6-12 \right )^{2}} = 3 \cdot \sqrt{5}[/tex]
For the Central Avenue potion of the parade route, we have;
(x₁, y₁) = (6, 0)
(x₂, y₂) = (2, 4)
[tex]l_2 = \sqrt{\left (4 -0\right )^{2}+\left (2-6 \right )^{2}} = 4 \cdot \sqrt{2}[/tex]
Therefore, the total length of the parade route =-3·√5 + 4·√2 = 12.265 unit
The scale of the drawing is 1 unit = 0.25 miles
Therefore;
The actual length of the initial parade =0.25×12.265 unit = 3.09 miles
The proposed route does not meet requirement because it is longer than the maximum required length of 3 miles
Part B:
For an actual length of 3 miles, the length on the scale drawing should be given as follows;
1 unit = 0.25 miles
0.25 miles = 1 unit
1 mile = 1 unit/(0.25) = 4 units
3 miles = 3 × 4 units = 12 units
With the same end point and route, we have;
[tex]l_1 = \sqrt{\left (0 -y\right )^{2}+\left (6-x \right )^{2}} = 12 - 4 \cdot \sqrt{2}[/tex]
y² + (6 - x)² = 176 - 96·√2
y² = 176 - 96·√2 - (6 - x)²............(1)
Also, the gradient of l₁ = (3 - 0)/(12 - 6) = 1/2
Which gives;
y/x = 1/2
y = x/2 ..............................(2)
Equating equation (1) to (2) gives;
176 - 96·√2 - (6 - x)² = (x/2)²
176 - 96·√2 - (6 - x)² - (x/2)²= 0
176 - 96·√2 - (1.25·x²- 12·x+36) = 0
Solving using a graphing calculator, gives;
(x - 9.941)(x + 0.341) = 0
Therefore;
x ≈ 9.941 or x = -0.341
Since l₁ is required to be 12 - 4·√2, we have and positive, we have;
x ≈ 9.941 and y = x/2 ≈ 9.941/2 = 4.97
Therefore, the start point of the parade should be the point (9.941, 4.970) on Broadway so that the total distance is as close to 3 miles as possible
Part C: The coordinates of the cameras stationed half way down each road are;
For central avenue;
Camera location = ((6 + 2)/2, (4 + 0)/2) = (4, 2)
For Broadway;
Camera location = ((6 + 9.941)/2, (0 + 4.970)/2) = (7.97, 2.49).
This exercise is necessary to use the given map information and then make the distance between points, in this way we find that:
A)The proposed route does not meet requirement because it is longer than the maximum required length of 3 miles.
B) Broadway and Cedar Street
C) [tex]Central \ Avenue(4, 2)Broadway (7.97, 2.49)[/tex]
So from the distance between points and the informed map we have:
A) The equation for the distance, as follows:
[tex]l=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
Where for the Broadway potion of the parade route, we have:
[tex](x_1,y_1)=(12,3)\\(x_2,y_2)=(6,0)[/tex]
Applying the values in the formula given above, we have:
[tex]l_1=\sqrt{(0-3)^2+(6-12)^2}=3\sqrt{5}[/tex]
For the Central Avenue potion of the parade route, we have:
[tex](x_1, y_1) = (6, 0)(x_2, y_2) = (2, 4)[/tex]
Applying the values in the formula given above, we have:
[tex]l_2=\sqrt{(4-0)^2+(2-6)^2}=4\sqrt{2}[/tex]
Therefore, the total length of the parade route:
[tex]3\sqrt{5} + 4\sqrt{2} = 12.265 \\0.25*12.265 unit = 3.09\ miles[/tex]
B) The two streets that are the same distance apart are the streets: Broadway and Cedar Street.
C) The coordinates of the cameras stationed half way down each road are:
For Central Avenue:
[tex]Camera \ location = ((6 + 2)/2, (4 + 0)/2) = (4, 2)[/tex]
For Broadway:
[tex]Camera\ location = ((6 + 9.941)/2, (0 + 4.970)/2) = (7.97, 2.49)[/tex]
See more about distance at brainly.com/question/989117
y+15=30 i will mark brainliest
Answers
Answer:
y = 15
Step-by-step explanation:
if y+15=30 we know that we need a total of 30, since we already have 15 y will also be 15
Answer:
y+15=30
y+15-15=30-15
y=15
Step-by-step explanation:
To rent a certain meeting room, a college charges a reservation fee of $39 and an additional fee of $5.80 per hour. The film club wants to spend at most $73.80 on renting the meeting room.
What are the possible amounts of time for which they could rent the meeting room?
Use t for the number of hours the meeting room is rented, and solve your inequality for t.
Answers
Answer:
The inequality is x less than or equal to 6. So the amount of hours they can rent it is 6 hours or less.
Step-by-step explanation:
5.80x + 39 <_ 73.80 ----> subtract 39 on both side to get ---> 5.80x <_ 73.80 -----> then divide by 5.80 on both sides to get ---> x <_ 6.
Hope this helped!
Select all statements
A. Two squares with the same lengths are always congruent
B. Two rectangles with the same side lengths are always congruent
C. two rhombuses with the same side lengths are always congruent
D. two parallelograms with the same side lengths are always congruent
E. two quadrilaterals with the same side lengths are always congruent
Answers
Step-by-step explanation:
(A) squares are congruant .
(B) rectangle having equal length of same side is congruent.
(C)it is true because it have same side length are equal.
(D)it is true because same same side length are equal.
(E) it is truebecause same side length are equal.
The statements that are correct in the given question are: options A, B and C.
Quadrilaterals are figures or shape bounded by four straight sides. Thus each quadrilateral has its sum of interior angles to be [tex]360^{o}[/tex]. Examples include; rectangle, square, trapezium, rhombus, kite, parallelogram.
Considering the properties of each quadrilateral given in the question, it can be inferred that;
squares of equal length of sides are congruent. rectangles of equal length of sides are congruent. rhombuses with equal side lengths are congruent. parallelogram with the same side lengths may not be congruent. This is because the angles of the slanting sides may not be the same. quadrilaterals with the same side length may not congruent. Example: rectangle and parallelogram of the same side length are not congruent.Therefore, the appropriate statements that are correct are: options A, B and C.
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An airplane flew across the Pacific Ocean. The table
shows the amount of
time and the distance traveled when the airplane was traveling at a
constant speed. Complete the table with the missing values.
time (hours) distance traveled (miles)
row 12
row 23
1,650
row 36
Answers
Answer:
1hr= 550 miles
Just about adding or subtracting same signs, dont understand what exactly those 2 words are supposed to be...
Answers
Suppose M is the midpoint of FG. Find the missing measure.
FM = 2k - 5, FG = 18
Answers
Answer:
k= 7
Step-by-step explanation:
if m is the midpoint of fm, and fm= 2k-5. and fg=18. then you can do: 2k-5+2k-5=18 and solve for x
The measure of FM is 9 and MG is 9.
Given,
M is the midpoint of FG.
FM = 2k - 5 and FG = 18.
We need to find the measure of MG.
What is meant by the midpoint between two points?If there is a midpoint between two points the midpoint will divide the distance between the two points into two equal halves.
AB is the distance between two points A and B
If C is the midpoint then,
AC = CB = AB / 2
We have,
FG is a line.
M is the midpoint of this line FG.
Now,
F______M______G
Since M is the midpoint we have,
We need to get,
FM = MG = FG/2
FG = FM + MG
We need to find the k value.
FM = FG/2
2k - 5 = 18/2
Multiplying 2 on both sides
4k - 10 = 18
Adding 10 on both sides
4k - 10 + 10 = 18 + 10
4k = 28
Dividing both sides by 4
k = 28/4 = 7
k = 7.
So,
FM = 2k - 5 = 2 x 7 - 5 = 14 - 5 = 9
Since M is the midpoint
FM = MG
We have,
MG = 9
We can see that,
FG = FM + MG
18 = 9 + 9
18 = 18
Thus the measure of FM is 9 and MG is 9.
Learn more about finding measures of a line between two points here:
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✓ Check
Question 1
Caroline said the absolute value of -25 is 25. Is she correct? Explain.
Answers
Answer:
lolllll
Step-by-step explanation:
What is 3.142 rounded to the nearest hundredth?
Answers
Answer:
3.140
Step-by-step explanation:
Answer:
3.14
Step-by-step explanation:
-----
i need to know the answer as soon as possible.
Answers
0.35p
Because the price also indicates percentage
Answer:
p - 0.35, so C.
It's not A because that's the regular price times the percentage off.
Geography textbook has a width of 9 inches and a diagonal of 15 inches. What is the length of the
textbook?
Answers
Answer:
12 inches
Step-by-step explanation:
The Pythagorean's theorem states that a triangle's hypotenuse's length is equal to a^2+b^2=c^2.
9 is a, b is the length, and c is the 15.
9^2+b^2=225
225-81=144
The square root of 144 is 12, therefore 12 inches is the length.
What is the slope of the line Perpendicular to y = 1x - 10
Zero
4
4
-4
Answers
Perpendicular lines have opposite reciprocal slopes.
y = 1/4x - 10 is our original equation.
If we flip the slope and change the sign, we get -4
The answer is -4
Find the mode:
4,5, 4, 3, 5, 1, 6
Answers
Answer:
4 and 5Step-by-step explanation:
The mode in a given set of data is the number that appears the most.
4 appears twice
5 appears twice
3 appears once
1 appears once
6 appears once
Simplify each expression by distributing and combining like terms
6(x + 1) – 5(x + 2)
Answers
Answer:
x-4
Step-by-step explanation:
6(x+1)-5(x+2)
=6x+6-5x-10
=x-4
Answer:
[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{x - 9}}}}}[/tex]
Step-by-step explanation:
[tex] \star \: \sf{6( x + 1) - 5(x + 2)}[/tex]
Distribute 6 through the parentheses
Similarly, distribute -5 through the parentheses
[tex] \dashrightarrow{ \sf{6x + 6 - 5x - 10}}[/tex]
Collect like terms
Like terms are those which have the same base
[tex] \dashrightarrow{ \sf{6x - 5x + 6 - 10}}[/tex]
[tex] \dashrightarrow{ \sf{x + 6 - 10}}[/tex]
The negative and positive integers are always subtracted but posses the sign of the bigger integer
[tex] \dashrightarrow{ \boxed{ \sf{x - 4}}}[/tex]
Hope I helped!
Best regards! :D
What is the simplified answer?
Answers
512x³, I think, because 2x cubed (2x³) is 8x, and 8x cubed again ([8x]³) is 512x³.
Hope I helped!!!
[tex] \frac{3}{2} + \frac{2m}{9} = \frac{37}{18} [/tex]
How do I solve this and make it the most simplified it can be?
Answers
Answer:
[tex]m = \frac{5}{2} [/tex]Step-by-step explanation:
[tex]\frac{3}{2} + \frac{2m}{9} = \frac{37}{18}[/tex]
Multiply through by 18 to eliminate the fraction
That's
[tex]18 \times \frac{3}{2} + 18 \times \frac{2m}{9} = 18 \times \frac{37}{18} \\ 27 + 4m = 37[/tex]
Subtract 27 from both sides
That's
[tex]27 - 27 + 4m = 37 - 27 \\ 4m = 10[/tex]
Divide both sides by 4
That's
[tex] \frac{4m}{4} = \frac{10}{4} [/tex]
We have the final answer as
[tex]m = \frac{5}{2} [/tex]
Hope this helps you
[tex]\Huge{\boxed{\sf{\red{m = \frac{5}{2}}}}}[/tex]
➢ Explαnαtion :[tex]\displaystyle{\sf{ \frac{3}{2} + \frac{2m}{9} = \frac{37}{18}}} [/tex]
| ∵ Transposing 3/2 to R.H.S
[tex]\implies[/tex] [tex]\displaystyle{\sf{ \frac{2m}{9} = \frac{37}{18} - \frac{3}{2}}} [/tex]
[tex]\implies[/tex] [tex]\displaystyle{\sf{ \frac{2m}{9} = \frac{37-27}{18}}} [/tex]
[tex]\implies[/tex] [tex]\displaystyle{\sf{ \frac{2m}{9} = \frac{10}{18} = \frac{5}{9}}} [/tex]
[tex]\implies[/tex] [tex]\displaystyle{\sf{ 2m = \frac{5}{9} \times 9}} [/tex]
[tex]\implies[/tex] [tex]\displaystyle{\sf{ 2m = 5}} [/tex]
[tex]\longrightarrow[/tex] [tex]\large{\boxed{\sf{\red{ m = \frac{5}{2}}}}}[/tex]