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Explanation:

∆x=300 m×2

∆t=1.5 s

v=∆x/∆t → v=2×300/1.5 = 400 m/s

Answer:

C

Explanation:

Although this may seem surprising, water beneath the ground is commonplace. Usually groundwater travels slowly and silently beneath the surface, but in some locations it bubbles to the surface at springs. The products of erosion and deposition by groundwater were described in the Erosion and Deposition chapter.

Groundwater is the largest reservoir of liquid fresh water on Earth and is found in aquifers, porous rock and sediment with water in between. Water is attracted to the soil particles and capillary action, which describes how water moves through a porous media, moves water from wet soil to dry areas.

Aquifers are found at different depths. Some are just below the surface and some are found much deeper below the land surface. A region may have more than one aquifer beneath it and even most deserts are above aquifers. The source region for an aquifer beneath a desert is likely to be far from where the aquifer is located; for example, it may be in a mountain area.

The amount of water that is available to enter groundwater in a region is influenced by the local climate, the slope of the land, the type of rock found at the surface, the vegetation cover, land use in the area, and water retention, which is the amount of water that remains in the ground. More water goes into the ground where there is a lot of rain, flat land, porous rock, exposed soil, and where water is not already filling the soil and rock.

The residence time of water in a groundwater aquifer can be from minutes to thousands of years. Groundwater is often called “fossil water” because it has remained in the ground for so long, often since the end of the ice ages.

The type of water occurs as a liquid resource that is dispersed through

numerous holes is known as Ground water.

Ground water is formed from the liquid on the land being dispersed deep

down into the soil. Water is readily absorbed into the soil depending on the

type of soil. Sandy soil is known to have a higher degree of absorption.

The water absorbed is usually as a result of numerous holes, pores, fractures,and cavities in rocks and sediments and is  also dependent on the climate and rate of precipitation in the area. This is why water is usually found in the soil when dug to certain levels.

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Static electricity is a controlled burst of energy.

Answer:

True

Explanation:

W=F×s

w=20N×6m=120J

W=120J

Answer:

Explanation:

Suppose m₂ is greater than m₁ and it is going down . m₁ will be going up.

Let tension in string be T₁ and T₂  . Let common acceleration of system be a

For motion of m₁

T₁-m₁g = m₁a ----- (1)

For motion of m₂

m₂g- T₂ = m₂a ------- (2)

For motion of pulley

(T₂-T₁ )R represents net torque

(T₂-T₁ )R = I x α where I is moment of inertia of disc and α is angular acceleration of disc

(T₂-T₁ )R = 1/2 M R² x a / R

(T₂-T₁ ) = M a /2

Adding (1) and (2)

(m₂-m₁)g = (m₂+m₁)a + (T₂-T₁ )

(m₂-m₁)g = (m₂+m₁)a + Ma/2

(m₂-m₁)g = (m₂+m₁+ 0.5M)a

a = (m₂-m₁)g / ( (m₂+m₁+ 0.5M)

The acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].

Given to us

Masses = m₁, m₂

The radius of the pulley = R

Mass of the pulley = M

Assumption

We know the acceleration due to gravity is denoted by g,

[tex]T_1 = m_1(a+g)[/tex]......... equation 1

[tex]T_2 = m_2(a-g)[/tex]......... equation 2

The inertia of the pulley,  [tex]I = \dfrac{1}{2}MR^2[/tex]

Acceleration of the pulley, [tex]a = {\alpha }\times {R}[/tex]

[tex](T_2-T_1)R = I \times \alpha \\\\[/tex]

Substitute the values we get,

[tex][m_2(a-g)-m_1(a+g)]R = \dfrac{1}{2} MR^2 \times \dfrac{a}{R}\\\\[/tex]

[tex][m_2a-m_2g-m_1a-m_1g]R= \dfrac{1}{2} MR \times a[/tex]

[tex]m_2a-m_1a-m_2g-m_1g= \dfrac{1}{2} M \times a[/tex]

[tex]a(m_2-m_1)-g(m_2+m_1)= 0.5M \times a[/tex]

[tex]a(m_2-m_1)-0.5Ma=g(m_2+m_1)\\\\a(m_2-m_1-0.5M) = g(m_2+m_1)\\\\a = \dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex]

Hence, the acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].

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Answer:

The magnitude of the lift generated by the wings of the airplane is 130,340 N.

Explanation:

Given;

mass of the airplane, m = 13,300 kg

speed of the airplane, v = 560 km/h = 155.56 m/s

The magnitude of the lift generated by the wings of the airplane is calculated as;

[tex]F_l = mg\\\\where;\\\\F_l \ is \ the \ magnitude \ of \ the \ lift \ generated\\g \ is \ acceleration \ due \ to \ gravity = 9.8 \ m/s^2\\\\F_l = 13,300 \times \ 9.8\\\\F_l = 130,340 \ N[/tex]

Therefore, the magnitude of the lift generated by the wings of the airplane is 130,340 N.

Answer:

Sledgehammer A has more momentum

Explanation:

Given:

Mass of Sledgehammer A = 3 Kg

Swing speed = 1.5 m/s

Mass of Sledgehammer B = 4 Kg

Swing speed = 0.9 m/s

Find:

More momentum

Computation:

Momentum = mv

Momentum sledgehammer A = 3 x 1.5

Momentum sledgehammer A = 4.5 kg⋅m/s

Momentum sledgehammer B = 4 x 0.9

Momentum sledgehammer B = 3.6 kg⋅m/s

Sledgehammer A has more momentum

Answer:

1) A. .33 hr

2) B. 6ft

3) A. 58mi/hr

Answer:

    vₐ₀ = 29.56 m / s

Explanation:

In this exercise the initial velocity of car A is asked, to solve it we must work in parts

* The first with the conservation of the moment

* the second using energy conservation

let's start with the second part

we must use the relationship between work and kinetic energy

             W = ΔK                             (1)

for this part the mass is

             M = mₐ + m_b

the final velocity is zero, the initial velocity is v

friction force work is

              W = - fr x

the negative sign e because the friction forces always oppose the movement

we write Newton's second law for the y-axis

              N -W = 0

              N = W = Mg

friction forces have the expression

              fr =μ N

              fr = μ M g

we substitute in 1

               -μ M g x = 0 - ½ M v²

             v² = 2 μ g x

let's calculate

              v² = 2  0.750  9.8  6.00

              v = ra 88.5

              v = 9.39 m / s

Now we can work on the conservation of the moment, for this part we define a system formed by the two cars, so that the forces during the collision are internal and therefore the tsunami is preserved.

Initial instant. Before the crash

         p₀ = + mₐ vₐ₀ - m_b v_{bo}

instant fianl. Right after the crash, but the cars are still not moving

         p_f = (mₐ + m_b) v

         p₀ = p_f

         + mₐ vₐ₀ - m_b v_{bo} = (mₐ + m_b) v

         mₐ vₐ₀ = (mₐ + m_b) v + m_b v_{bo}

let's reduce to the SI system

          v_{bo} = 64.0 km / h (1000m / 1km) (1h / 3600s) = 17.778 m / s

let's calculate

         660 vₐ₀ = (660 +490) 9.39 + 490 17.778

         vₐ₀ = 19509.72 / 660

         vₐ₀ = 29.56 m / s

we can see that car A goes much faster than vehicle B

The energy that a substance contains is known as heat. Thus, the correct option for this question is B.

Entropy may be characterized as the measurement of the degree of randomness or in other words, it is the increase in the disorganization within a system. It is the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.

Equilibrium is a state of balance between opposing forces or actions that is either static or dynamic. It symbolizes the circumstance of being balanced in nature.

Thermal energy is a type of energy that is significantly contained within a system that is responsible for its temperature. Heat is the flow of thermal energy.

Therefore, the energy that a substance contains is known as heat. Thus, the correct option for this question is B.

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Answer:

F_y = 147 N

Explanation:

For the beam to be in equilibrium, it must comply with the conscious and translational and rotational equilibrium.

Let's fix a reference system at the point where the cable is and make the counterclockwise rotations positive

                   ∑ τ = 0

                   -F_y x + W x / 2 + Ty 0 = 0

                   F_y  x = W x / 2

                   F_y = W / 2

                   F_y = mg / 2

                   F_y = 30 9.8 / 2

                   F_y = 147 N

directed in vertical direction

Answer:

yes its c

Explanation:

took it already

Answer:

I believe its a and c but my notes are all kinds of messed up so im sorry if its wrong

Explanation:

None of the  regions can the gravitational field strength due to the two planets be zero.

What is gravitational field?

A gravitational field is a model used in physics to explain the effects that a large thing has on the area surrounding it, exerting a force on smaller, less massive bodies. Consequently, a gravitational field, which is measured in newtons per kilogram, is employed to describe gravitational processes.

Field due to given masses can not be zero in the given region they do not cancel each other.

None of the  regions can the gravitational field strength due to the two planets be zero.

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Explanation:

The diameter of a record, d = 0.3 cm

Radius, r = 0.15 cm

It rotates 33.5 times per minute.

(a) Frequency, f = 33.5 rotation/minute

= (33.5/60) rotation/second

= 0.55 rotation/second

(b) Time period,

T = 1/f

So,

[tex]T=\dfrac{1}{0.55}\\\\T=1.81\ s[/tex]

(c) Linear speed of a point on its rim,

[tex]v=r\omega\\\\v=0.15\times 10^{-2}\times 2\pi \times 0.55\\\\v=5.18\times 10^{-3}\ m/s[/tex]

(d) Centripetal acceleration,

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(5.18\times 10^{-3})^2}{0.15\times 10^{-2}}\\\\a=0.017\ m/s^2[/tex]

Hence, this is the required solution.

Answer:

C?

Explanation:

Yep,It's C all right.

Answer:

Yep,It's C all right.

Explanation:

Answer:

160 watts.

Explanation:

Remark

Power = Work / Time

Work = F * d

Note: Since he is running up stairs he is doing work against gravity.

Givens

Formula

Solution

Answer:

Explanation:

The refractive index of liquid with respect to glass =  sin of Angle of incidence in glass / (sin of angle of refraction in liquid )

The refractive index of liquid with respect to glass = sin 40 / sin 55

refractive index of liquid / refractive index of glass = sin 40 / sin 55

refractive index of liquid / 1.60 = sin 40 / sin 55

refractive index of liquid = 1.6 x sin40 / sin 55

= 1.6 x .642 / .819

= 1.254 .  

Hello,

✔ We have: KE = PE (potential energy)

PE = m x g x h

The potential energy that the pebble of mass 1 has is called PE1 and the potential energy that the pebble of mass 2 has is called PE2  

PE1 = PE2 ⇔ PE1/PE2 = 1

[tex]\frac{m_1\times g\times h}{m_2\times g\times 4h} = 1 \\ \\ \frac{m_1}{m_2\times 4} = 1 \\ \\ \frac{m_1}{m_2} = 4[/tex]

The mass m1 is therefore 4 times greater than that of the stone of mass m2.

Explanation:

you move 10 -³ up

so: 100* 10³ /5.5*10

100000/55

which is approximately 18182

Answer:

hello your question has some missing parts below are the missing parts

A Circular, 10-turn coil has a radius of 10.7 cm and is oriented with its plane perpendicular to a 0.2-T magnetic field.

answer : 1 volt

Explanation:

Determine the Average induced EMF during this mishap

A' = A/2  ( for a semi circle )

where A = [tex]\frac{\pi r^2}{2}[/tex]

To determine the Average induced EMF apply the relation below

| E | =  η * [tex]\frac{\beta A}{T}[/tex]   ----- ( 1 )

Replace A in equation 1 with  A = [tex]\frac{\pi r^2}{2}[/tex]

hence equation becomes : | E | =  η * βπr^2 / 2T'

where : T' = 0.0365 ,  β = 0.2 , η = 10 , r = 0.107

∴| E |  = 0.999 ≈ 1volts

Answer:

the effect on energy is due to the force applied to the frisbee to throw it back in the tree.

Explanation:

Answer:

Explanation:

From the information:

[tex]F(x,y) = 2xy^3i+3x^2y^2j;P(-9,4), B(10,5)[/tex]

[tex]W = \int ^{10,5}_{-9,4} f .dn \\ \\ W = \int ^{10,5}_{-9,4} (2xy^3i) + 3x^2y^2j) *(dxi+dyj) \\ \\ f = 2xy^3\ \ ,\ \ g = 3x^2y^2 \\ \\ \dfrac{\partial f}{\partial y} = \dfrac{\partial g}{\partial x} \\ \\ \text{We wil realize that f is conservative; as a result, there is a potential function } \phi ;\\\\ \dfrac{\partial \phi}{dx}= 2xy^3 \\ \\ \phi= \dfrac{2x^2}{2}y^3+f(y) \\ \\ \phi = x^2y^3 + f(y) \\ \\ \dfrac{\partial \phi}{\partial y } = 3x^2y^2 + f'(y) \\ \\[/tex]

[tex]\dfrac{\partial \phi}{\partial y } = 3x^2y^2 + f'(y) = 3x^2y^2 \\ \\ f'(y) = 0 \\ \ f(y) = k \\ \\ \phi = x^2y^3 + k \\ \\ Recall: \int^{10,5}_{-9,4 } \ F* dn = W = \phi(10,5) - \phi (-9,4) \\ \\ = (10)^2(5)^3 + k - (-9)^2(4)^3 - k \\ \\ = (100*125) - (81*64) \\ \\ = 12500 - 5184 \\ \\ =7316[/tex]

Answer:

B = 5.23 T

Explanation:

Given that,

Electric field, E = 550 V/m

The speed of the proton, v = 105 m/s

We need to find the magnitude of the magnetic field such that the beam of protons continues along its straight-line trajectory.

To move in a straight line, the magnitude of the electric force from the field and the magnetic field must be equal i.e.

[tex]qE=qvB\\\\B=\dfrac{E}{v}\\\\B=\dfrac{550}{105}\\\\B=5.23\ T[/tex]

So, the magnitude of the magnetic field is equal to 5.23 T.

Answer:

True, people would actually pray to Poseidon for safe sea travel

Answer:

The first law, also called the law of inertia, was pioneered by Galileo. This was quite a conceptual leap because it was not possible in Galileo's time to observe a moving object without at least some frictional forces dragging against the motion. In fact, for over a thousand years before Galileo, educated individuals believed Aristotle's formulation that, wherever there is motion, there is an external force producing that motion.

The second law, $ f(t)=m\,a(t)$ , actually implies the first law, since when $ f(t)=0$ (no applied force), the acceleration $ a(t)$ is zero, implying a constant velocity $ v(t)$ . (The velocity is simply the integral with respect to time of $ a(t)={\dot v}(t)$ .)

Newton's third law implies conservation of momentum [138]. It can also be seen as following from the second law: When one object ``pushes'' a second object at some (massless) point of contact using an applied force, there must be an equal and opposite force from the second object that cancels the applied force. Otherwise, there would be a nonzero net force on a massless point which, by the second law, would accelerate the point of contact by an infinite amount.

Explanation:

Answer:

a) 10.23°C

b) - 0.8795 kJ / k

Explanation:

Given data :

mass of ice = 100 gram = 0.1 kg

mass of water in calorimeter = 100 grams = 0.1kg

temperature of water in calorimeter = 373K

a) Determine the Final temperature of the water once thermal equilibrium is established

Heat lost by water  = heat gained by Ice

Mwater * CPwater * Δt = Mice * Lice + Mice * CPwater * Δt

0.1 * (4.2 * 10^3 ) * ( 100 - t ) = ( 0.1 * 334 * 10^3 ) +  0.1 * (4.2 *1063 ) * ( T - 0 )

42000 = 33400 + 0.2 * 4200 * T

∴ equilibrium temp ( T ) = 10.23°C

B) Determine the entropy change of the universe of the process

Entropy change of ice = 33400/ 273 + 0.1 * 42 * 10^3 * In 283.23 / 273

                                     = 276.84 J/K

Entropy change of water = 0.1 * 42* 10^3 * In 283.23 / 273

                                          = -1156.34 J/K

Hence Entropy change of variance = 276.84 J/K + ( - 1156.34 J/K )

= - 0.8795 kJ / k