Help please asap will mark brainliest!

Answer:

The electric force acts over the distance separating the two objects. ... The space surrounding a charged object is affected by the presence of the charge; an electric field is established in that space. A charged object creates an electric field - an alteration of the space or field in the region that surrounds it.

Explanation:

Answer:

it's expanding from is 15

Answer:

Explanation:

3( 2+5 )

3. ( 7 )

3 . 7= 21

Answer:

The answer is in the problem

Explanation:

As general rule of number of oxygen is -2:

O → -2

Alkali metals (Li, Na, K) are always +1

Na → +1

Alkali earth methals (Be, Mg, Ca...) are always +2

Ca → +2

The halogen group (F, Cl, Br...) is always -1

F → -1

The oxidation number of Si (+/- 4)

Aluminium is, usually +3

And to complete the octet rule in nitrogen, 3 electrons are required. That means:

N → -3

Answer:

potassium cyanide

Explanation:

while eye medications do harm your immune system it is not enough to kill someone. criminals mainly used potassium cyanide because it was cheap. it serves as a substitute for ethanol.

Answer:

[tex]n_{O_2}=0.866molSO_2\\\\n_{SO_2}=0.577molSO_2[/tex]

Explanation:

Hello there!

In this case, according to the given balanced chemical reaction by which ZnS reacts with O2, it is possible to calculate the moles of the latter that are consumed, not produced, according the 2:3 mole ratio between them and the following stoichiometric set up:

[tex]n_{O_2}=56.25gZnS*\frac{1molZnS}{97.47gZnS}*\frac{3molO_2}{2molZnS} \\\\n_{O_2}=0.866molO_2[/tex]

But also, we can compute the moles of SO2 that are produced via the the 2:2 mole ratio of ZnS to SO2:

[tex]n_{SO_2}=56.25gZnS*\frac{1molZnS}{97.47gZnS}*\frac{2molSO_2}{2molZnS} \\\\n_{SO_2}=0.577molSO_2[/tex]

Regards!

Answer: (a) Mole fraction of [tex]H_{2}[/tex] is 0.66.

Mole fraction of [tex]N_{2}[/tex] is 0.33

(b) The partial pressure of [tex]H_{2}[/tex] is 1.98 atm.

The partial pressure of [tex]N_{2}[/tex] is 0.99 atm.

(c) The total pressure is 3.0 atm

Explanation:

Given: Volume = [tex]22.4 dm^{3}[/tex]  (1 [tex]dm^{3}[/tex] = 1 L) = 22.4 L

Moles of [tex]H_{2}[/tex] = 2.0 mol

Moles of [tex]N_{2}[/tex] = 1.0 mol

Total moles = (2.0 + 1.0) mol = 3.0 mol

Temperature = 273.15 K

[tex]PV = nRT\\[/tex]

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

[tex]PV = nRT\\P \times 22.4 L = 3.0 mol \times 0.0821 L atm/mol K \times 273.15 K\\P = 3.0 atm[/tex]

The mole fraction of [tex]H_{2}[/tex] is calculated as follows.

[tex]Mole fraction = \frac{moles of H_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{2.0 mol}{(2.0 + 1.0) mol}\\= 0.66[/tex]

The mole fraction of [tex]N_{2}[/tex] is as follows.

[tex]Mole fraction = \frac{moles of N_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{1.0 mol}{(2.0 + 1.0) mol}\\= 0.33[/tex]

Partial pressure of [tex]H_{2}[/tex] are as follows.

[tex]P_{H_{2}} = P_{total} \times mole fraction of H_{2}\\= 3.0 atm \times 0.66\\= 1.98 atm[/tex]

Partial pressure of [tex]N_{2}[/tex] are as follows.

[tex]P_{N_{2}} = P_{total} \times mola fraction of N_{2}\\= 3.0 atm \times 0.33\\= 0.99 atm[/tex]

Answer: Because not all stars are in patterns

Answer:

Because the stars do not come out when the temperature rises on Earth

Explanation:

Answer:

2 moles

In words, 1 mole of Mg reacts with 2 moles of HCl to form 1 mole of MgCl₂ and 1 mole of H₂. The molar ratio of HCl to MgCl₂ is 2:1.

Answer:

155.1 L

Explanation:

Step 1: Given data

Mass of CO₃: 415.4 g

Step 2: Calculate the moles corresponding to 415.4 g of CO₃

The molar mass of CO₃ is 60.01 g/mol.

415.4 g × 1 mol/60.01 g = 6.922 mol

Step 3: Calculate the volume occupied by 6.922 moles of CO₃

The volume of a gas depends on conditions such as Temperature and Pressure. Since the conditions are not specified, we may assume that the gas is at Standard Pressure and Temperature (1 atm and 273.15 K). At STP, 1 mole of a gas occupies 22.41 L.

6.922 mol × 22.41 L/1 mol = 155.1 L

Answer:

Trees could go extinct and people could die.

Explanation:

Answer:

1116 g.

Explanation:

The balanced equation for the reaction is given below:

4Na + O₂ —> 2Na₂O

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of Na₂O.

Next, we shall determine the theoretical yield of Na₂O. This can be obtained as follow:

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of Na₂O.

Therefore, 9 moles of O₂ will react to produce = 9 × 2 = 18 moles of Na₂O.

Finally, we shall determine the mass in 18 moles of Na₂O. This can be obtained as follow:

Mole of Na₂O = 18 moles

Molar mass of Na₂O = (23×2) + 16

= 46 + 16

= 62 g/mol

Mass of Na₂O =?

Mass = mole × molar mass

Mass of Na₂O = 18 × 62

Mass of Na₂O = 1116 g

Thus, the theoretical yield of Na₂O is 1116 g.

Answer:

A. it allows results to be reviewed and reproduced by other scientists.

By using combined gas law , volume will be 1.88 [tex]dm^{3}[/tex].

The combined gas law contains the laws of Charles, Boyle, and Gay-Lussac. When you know the pressure, volume, and temperature of a system and need to modify one of these, you can apply this law to compute the resulting unknown.

Combined gas law is expressed as:

[tex]$\frac{P_{1} V_{1}}{T_{1}}=\frac{P_{2} V_{2}}{T_{2}}$[/tex]

Calculation of volume by using combined gas law

It is given that, [tex]V_{1}[/tex] = 254[tex]dm^{3}[/tex], at STP P = 101.3 kPa and T = 273 K

Now, put the value of given data in above equation.

[tex]V_{2}[/tex] = (254[tex]dm^{3}[/tex]) (101.3 kPa) (26+273) /(150 kPa) (273)

[tex]V_{2}[/tex] = 1.88 [tex]dm^{3}[/tex].

By using combined gas law  volume will be 1.88 [tex]dm^{3}[/tex].

To know about combined gas law.

https://brainly.com/question/13154969.

#SPJ2

Answer:

1. iodide ion into neutral iodine

2. blue-black

3. neutral iodine into iodide ion

4. clear

Explanation:

The function of hypochlorite in iodine titration is to oxidize the iodide ion into iodine molecule as shown below;

ClO-(aq) + 2H+(aq) + 2I-(aq) ---------> 6 I2(l) + Cl- (aq)+ H2O(l)

The addition of starch to iodine leads to the formation of a starch iodide complex which has a blue black colour.

the titrant, thiosulfate, reduces neutral iodine into iodide ion as shown below;

I2  +  2S2O32-  → 2I- + S4O62-

At end point, the solution becomes clear again.

iiiluuiijjuulluuuuuuuuullffffff

Answer:

According to who knows who I believe the answer is k2So4 + SrI2 ---> SrSo4 +2KI

S, 2. S, 2

K, 2. K, 2

I, 2. I, 2

O, 4. O, 4

Answer:

a. True

Explanation:

The gases that we study are governed by different laws of physics. Gases behaves according to some given set of laws like the Universal gas laws, Boyles law, Charles law, Gay Lussac's law and many more.

But we do not see a definite pattern or rule when we study solids or liquids. The behavior of the solids and liquids are not described by the set of laws which are applied regardless of the identity of the substance.

The Haber process generates ammonia from nitrogen and hydrogen gas, and nitrogen gas is the excess reagent.

Stoichiometry of reaction tells about the relative amount of reactants and products after and before the chemical reaction.

Given chemical reaction is:

N₂ + 3H₂ → 2NH₃

From the stoichiometry of the reaction it is given that:

1 mole of N₂ = produce 2 moles of NH₃

3 moles of H₂ = produce 2 moles of NH₃

1 moles of H₂ = produce 2/3=0.66 moles of NH₃

So, nitrogen is present in the excess quantity.

Hence, nitrogen gas is the excess reagent.

To know more about stoichiometry, visit the below link":

https://brainly.com/question/16060199

Answer:

Its N2

Explanation:

yea lol

BTw this is for Ck-12

Answer:

Option B, 2.167 x 1024 atoms

Explanation:

1 mole of CO2 = 44.01 grams

Number of moles of CO2 in 158.4 gram sample

[tex]\frac{158.4}{44.01} \\3.95[/tex]moles

Number of atoms in one mole is [tex]6.02*10^{23}[/tex]

Number of atoms in 3.95 moles [tex]2.167 *10^{24}[/tex]

Hence, option B is correct

Answer:

Its 12.6M

Explanation:

It came to the conclusion and got these answers

2.22

20.5

10

12.6

12.6 is the correct answer

Answer:

dog 2 because it is running 1m faster a second than dog 1. Dog 2 can run 1 meter farther in a second than the other dog.

Answer:

144g of H₂O

Explanation:

3NH₄ClO₄(s) + 3Al → Al₂O₃(s) + AlCl₃(s) + 3NO(g) + 6H₂O(g)

From the equation:

3 moles of NH₄ClO₄ produced 6 moles of H₂O

4 moles of NH₄ClO₄ produced ? moles of H₂O

(4 ₓ 6)/3 = [tex]\frac{24}{3}[/tex] = 8 moles of H₂O

1 mole of H₂O = (1 × 2) + 16 = 18g (The Relative Molecular mass of H₂O)

8 moles of H₂O = ?

Therefore 8 × 18 = 144g

=144g of H₂O

Sorry, I won't understand your words.

Answer:4 January 1643 [O.S. 25 December 1642] Woolsthorpe-by-Colsterworth, Lincolnshire, England

Died 31 March 1727 (aged 84) [O.S. 20 March 1726] Kensington, Middlesex, Great Britain

Explanation:

Answer:

Boil the water until it evaporates

Explanation:

If the water evaporates the sugar will no longer bond to it and then percipitate at the bottom of the beaker.

Answer:

With Br2 - Bromobenzene

With Cl2 - Chlorobenzene

With HNO3- Nitrobenzene

With H2SO4 - Benzenesulphonic acid

With HCOCl - Benzoyl chloride

With 1-chloro-2,2-dimethylpropane - 2,2dimethyl-1-phenyl propane

Explanation:

All the reactions listed above are electrophillic reactions. They are electrophillic reactions because the attacking agents in each reagent is an electrophile. An electrophile means any specie that is electron deficient and attacks regions of high electron density in molecules.

The benzene molecule has rich electron density. Substituents that are electron pushing increases the tendency of benzene to undergo electrophillic substitution reactions while electron withdrawing substituents decrease the the tendency of benzene to undergo electrophillic substitution reactions.

The names of the compounds formed when benzene undergoes electrophillic reaction with different attacking agents have been listed in the answer section.