Help please and please

Answer:

- Four (4) flip-flop values will complemented

- one (1) flip-flop value will complemented

Explanation:

To find how many flip flop number of bits complemented, we just need to figure out what the next count in the sequence is and find how many bits have changed.

taking a look at the a) 00110111

we need to just 1 to the value,

so

00110111 +  0000001  = 00111000        

So here, only the first four bits are complemented.

Therefore Four (4) flip-flop values will complemented

Next

b) 01010110

we also add 1 to the value

01010110  + 00000001  = 01010111

only the first bit is complemented.

Therefore one (1) flip-flop value will complemented

Answer:

[tex]\mathbf{K_p =2.857}[/tex]

[tex]\mathbf{\tau_1= 400 \ s}[/tex]

[tex]\mathbf{ \tau_d = 100 \ s}[/tex]

Explanation:

We can determine each parameter by using the first method of Zeigler Nichols

[tex]K_p = 1.2 \times \dfrac{\tau}{KL}[/tex]

[tex]\tau_1= 2L[/tex]

[tex]\tau_d = 0.5 L[/tex]

For this process;

the initial state of the output = [tex]A_o[/tex]

[tex]\tau = constant[/tex]

For calculating the gradient, we use the equation:

[tex]y-y_o = G(t-t_o) \\ \\ y-A_o = 0.01 \% A_o (t-L)[/tex]

where.

Time constant relates to the time [tex]y = K = 1.05 A_o[/tex]

∴

[tex]1.05A_o -A_o = 0.01\% A_o (t-200)[/tex]

[tex]0.05 A_o = 0.0001 A_o (t-200)[/tex]

[tex]t = 500A_o + 200[/tex]

To find time t

[tex]\tau = (500A_o +200) -200[/tex]

[tex]\tau = 500 \ A_o[/tex]

Recall that:

Using the first method of Zeigler Nichols

[tex]K_p = 1.2 \times \dfrac{\tau}{KL}[/tex]

[tex]\tau_1= 2L[/tex]

[tex]\tau_d = 0.5 L[/tex]

[tex]K_p = 1.2 \times \dfrac{500 \ A_o}{1.05\ A_o \times 200}[/tex]

[tex]K_p = 1.2 \times 2.38095[/tex]

[tex]\mathbf{K_p =2.857}[/tex]

[tex]\tau_1= 2L[/tex]

[tex]\tau_1= 2(200)[/tex]

[tex]\mathbf{\tau_1= 400 \ s}[/tex]

[tex]\tau_d = 0.5 \ L[/tex]

[tex]\tau_d = 0.5 \times 200[/tex]

[tex]\mathbf{ \tau_d = 100 \ s}[/tex]

Answer:

i think it c

Explanation:

Answer: the size of memory needed for the CD recording is 28.7 MB

Explanation:

so in the case of stereo, the bitrate is;

⇒ 26 × 60 × 44.1 × 10³ × 2

=   137592 × 10³  

for 10 bit

⇒ 137592 × 10³ × 10

= 1375920 × 10³ bits

now divide by 8 (convert to bytes)

⇒ (1375920 × 10³) / 8

= 171,990,000 BYTE

divide by 1000 (convert to kilobytes)

= 171,990,000 / 1000

= 171,990 KILOBYTES

now Given that, the compression ratio is 6      

so  

171,990 / 6

= 28665 KB

we know that. 1 MB = 1000 KB

x MB = 28665 KB

x MB = 28665 / 1000

⇒ 28.665 MB ≈ 28.7 MB

Therefore the size of memory needed for the CD recording is 28.7 MB

Answer:

transmitter hope thus helped!

Explanation:

Raceway is the answer

"A raceway is an enclosed conduit that forms a physical pathway for electrical wiring."

Answer:

A) σ_y = 79096 lb/in² = 79.1 ksi

B) strain-hardening exponent = 0.102

(strength coefficient = 137838.78 lb/in²

Explanation:

A) Formula for volume is;

V = πd²h/4

We are given;

height 2.0 in and diameter 1.5 in

Thus;

V = (π × 1.5² × 2)/4

V = 3.53 in³

Area is;

A = πd²/4

A = (π × 1.5²)/4

A = 1.77 in²

Yield strength is gotten from the formula;

σ_y = Force/Area

We are given load = 140,000 lb

Thus;

σ_y = 140000/1.77

σ_y = 79096 lb/in²

B) We are given

modulus of elasticity: E = 30 × 10^(6) lb/in²

Formula for strain is;

ε = σ_y/E

ε = 79096/(30 × 10^(6))

ε = 0.00264

The metal yields (0.2% offset), thus;

strain offsets = 0.00264 + 0.002

strain offsets: ε1 = 0.00464

Thus;

(h_i - h_o)/h_o = 0.00464

(h_i/h_o) - 1 = 0.00464

(h_i/h_o) = 1.00464

h_i = h_o(1.00464)

h_o = 2 in

Thus; h_i = 2(1.00464) = 2.00928 in

Area = Volume/height = 3.53/2.00928 = 1.757 in²

True stress is;

σ = force/area = 140000/1.757

σ1 = 79681.27 lb/in²

At a load of 260,000 lb, the height has been reduced to 1.6 in. Thus;

Area = 3.53/1.6 = 2.206 in²

True stress is;

σ2 = 260000/2.206

σ2 = 117860.38 lb/in²

True strain;

ε2 = In(2/1.6)

ε2 = 0.223

From flow curve;

σ = kεⁿ

Thus;

σ1 = k(ε1)ⁿ

79681.27 = k(0.00464ⁿ) - - - (eq 1)

Also for σ2 = k(ε2)ⁿ;

117860.38 = k(0.223ⁿ) - - - - - (eq 2)

From eq 1,

k = 79681.27/0.00464ⁿ

Putting this for k in eq2 to get;

117860.38 = (0.223ⁿ) × 79681.27/0.00464ⁿ

117860.38/79681.27 = 0.223ⁿ/0.00464ⁿ

Solving for n, we have ≈ 0.102

Thus,K is;

k = 79681.27/0.00464^(0.102)

k = 137838.78 lb/in²

Answer:

def script_input():

   chances = 2

   while chances > 0:

       global rows

       global columns

       global constant

       rows = int(input("Enter the number of rows: "))

       columns = int(input("Enter the number of columns: "))

       constant = int(input("Enter the constant: "))

       if rows > 0 and rows <= 8 and columns > 0 and columns <= 8 and \

           isinstance(constant, int):

           chances -= 2

       else:

           chances -= 1

script_input()

print(f"{rows} rows, {columns} columns, value of {constant}")

Explanation:

The python script defines a function that gets the user input of row, column and constant value variables, then the script prints out the number of rows and columns for the matrix to be created.

Answer:

n R ln(Vf/Vi)

Explanation:

Entropy is the loss of energy available to do work. Entropy is a state function (i.e. it depends only upon the current state of the system and is independent of how that state was prepared).

Since the temperature change of the ideal is constant, hence this is an isothermal expansion of a perfect gas. The change in entropy (ΔS) for an isothermal expansion of a perfect gas is given by:

[tex]\Delta S=nR*ln(\frac{V_f}{V_i})[/tex]

Where n is the amount of gas molecules in mol and R is the gas constant in JK⁻¹mol⁻¹given by R = [tex]N_A[/tex]k, k is Boltzmann's constant in J K⁻¹ and Avogadro's constant [tex]N_A[/tex] in mol⁻¹. Vf is the final volume and Vi the initial volume.

Answer:

[tex]0.845\ \text{N}[/tex]

Explanation:

g = Acceleration due to gravity at sea level = [tex]9.81\ \text{m/s}^2[/tex]

R = Radius of Earth = 6371000 m

h = Altitude of observatory = 4205 m

Change in acceleration due to gravity due to change in altitude is given by

[tex]g_h=g(1+\dfrac{h}{R})^{-2}\\\Rightarrow g_h=9.81\times(1+\dfrac{4205}{6371000})^{-2}\\\Rightarrow g_h=9.797\ \text{m/s}^2[/tex]

Weight at sea level

[tex]W=mg\\\Rightarrow W=65\times 9.81\\\Rightarrow W=637.65\ \text{N}[/tex]

Weight at the given height

[tex]W_h=mg_h\\\Rightarrow W_h=65\times 9.797\\\Rightarrow W_h=636.805\ \text{N}[/tex]

Change in weight [tex]W_h-W=636.805-637.65=-0.845\ \text{N}[/tex]

Her weight reduces by [tex]0.845\ \text{N}[/tex].

Answer:

its durable. it's cheap. its recyclable

Explanation:

Plastic is made of lots of recycled materials that make it very useful and cheap.