help me plsssssssssssssssssssssssssssss

Answer:

10

Step-by-step explanation:

Answer:

10 km

Step-by-step explanation:

total no of km covered=400

total no of trips=40

distance in each trip= 400/40

=10km

Answer:

19

Step-by-step explanation:

:)

Step-by-step explanation:

15/4 ÷ 5/8

15/4×8/5

3×2

=6

Answer:

6

Step-by-step explanation:

There are 10 perfect squares between 1 and 100, and 10 powers with an exponent of 2 between 1 and 100.

A number system is defined as a system of writing to express numbers.

Between 1 and 100, the perfect squares (numbers that can be expressed as the square of an integer) have exponents of 2.

We need to count the number of perfect squares between 1 and 100. These include:

1² = 1

2² = 4

3²= 9

4² = 16

5² = 25

6² = 36

7²= 49

8² = 64

9² = 81

10² = 100

So, there are 10 perfect squares between 1 and 100, and therefore 10 powers with an exponent of 2 between 1 and 100.

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Answer:

110x3.6 is equal to 396

hope this helps!

Answer:

x = ± 4i

Step-by-step explanation:

x^2 + 19 = 3

Subtract 19 from each side

x^2 +19-19 = 3-19

x^2 = -16

Take the square root of each side

sqrt(x^2) = sqrt(-16)

x = sqrt(-1*16)

x =sqrt(-1) * sqrt(16)

We know that the square root of -1 is the imaginary number i

x = ± 4i

The cosine of the angle the refrigerator makes with the floor is option (E) 3/5 is the correct answer.

Trigonometry is mainly concerned with specific functions of angles and their application to calculations. Trigonometry deals with the study of the relationship between the sides of a triangle (right-angled triangle) and its angles.

For the given situation,

Harold tilted the 5 foot fridge, so the slanting height = 5 feet

The tilted refrigerator makes the height 4 feet from the floor.

From the diagram,

The three sides of the triangle according to Pythagoras theorem are

Hypotenuse side, h = 5 feet

Opposite side, o = 4 feet

Let a be the adjacent side.

By Pythagoras theorem,

[tex]Hypotenuse^{2} = Opposite^{2}+Adjacent^{2}[/tex]

⇒ [tex]5^{2} =4^{2} +a^{2}[/tex]

⇒ [tex]a^{2} = 25-16[/tex]

⇒ [tex]a=\sqrt{9}[/tex]

⇒ [tex]a=3[/tex]

Thus the trigonometric ratio cosine of the angle is

[tex]cos \theta =\frac{Adjacent}{Hypotenuse}[/tex]

⇒ [tex]cos \theta =\frac{3}{5}[/tex]

Hence we can conclude that the cosine of the angle the refrigerator makes with the floor is option (E) 3/5 is the correct answer.

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Answer: 0.25 pound of beef are needed to make 80 meals.

Step-by-step explanation:

Given : A recipe for beef fajitas uses 5 pounds of beef to make 20 meals.

Then the of beef required for 1 mesal = ( 5 pounds) ÷ 20

= [tex]\dfrac{5}{20}[/tex] pound

[tex]=\dfrac{1}{4} [\text{Divide numerator and denominator}][/tex]

=0.25 pound

Hence, 0.25 pound of beef are needed to make 80 meals.

Answer:

b) Reflection over y = -2

Step-by-step explanation:

Reflection over y = -2

Answer:

It should be 4, 6, and 8

Step-by-step explanation:

Hope This Helped

Answer:

I beleive is is -2% because 5 is 2 more than 3

so then 5-2=3

Answer:

Error Is 100(2/3) 66.7%

Answer:

The answer would be D

Step-by-step explanation:

In order for a problem to be infinite, it must be 0=0. But since this is equal, and can equal 0=0, it would be d

Answer:

81

Step-by-step explanation:

Answer:

Ok

Step-by-step explanation:

What do you want us to figure out? Did you forget the picture?

Answer:

y = -1/3x - 4

Step-by-step explanation:

m = -1/3

y = -4

Hope this helps! Have a nice day! Plz mark as brainliest!!!

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Answer：

y=-9x+5

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

I believe its c I've done this last semester

Given:

The pair of points.

5. P(1, 1), Q(–1, –1)

6. [tex]E\left(\dfrac{1}{2},4\dfrac{1}{4}\right), F\left(5,-\dfrac{1}{2}\right)[/tex]

To find:

The distance between the pair of points.

Solution:

Distance formula:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

5.

The distance between the pair of points P(1, 1) and Q(–1, –1) is:

[tex]PQ=\sqrt{(-1-1)^2+(-1-1)^2}[/tex]

[tex]PQ=\sqrt{(-2)^2+(-2)^2}[/tex]

[tex]PQ=\sqrt{4+4}[/tex]

[tex]PQ=\sqrt{8}[/tex]

[tex]PQ=2\sqrt{2}[/tex]

Therefore, the distance between P and Q is [tex]2\sqrt{2}[/tex].

6.

The distance between the pair of point [tex]E\left(\dfrac{1}{2},4\dfrac{1}{4}\right), F\left(5,-\dfrac{1}{2}\right)[/tex] is:

[tex]EF=\sqrt{\left(5-\dfrac{1}{2}\right)^2+\left(-\dfrac{1}{2}-4\dfrac{1}{4}\right)^2}[/tex]

[tex]EF=\sqrt{\left(\dfrac{10-1}{2}\right)^2+\left(-\dfrac{1}{2}-\dfrac{17}{4}\right)^2}[/tex]

[tex]EF=\sqrt{\left(\dfrac{9}{2}\right)^2+\left(\dfrac{-2-17}{4}\right)^2}[/tex]

[tex]EF=\sqrt{\dfrac{81}{4}+\left(\dfrac{-19}{4}\right)^2}[/tex]

On further simplification, we get

[tex]EF=\sqrt{\dfrac{81}{4}+\dfrac{361}{16}}[/tex]

[tex]EF=\sqrt{\dfrac{324+361}{16}}[/tex]

[tex]EF=\sqrt{\dfrac{685}{16}}[/tex]

[tex]EF=\sqrt{42.8125 }[/tex]

[tex]EF\approx 6.5[/tex]

Therefore, the distance between E and F is 6.5 units.

Given:

The equation is:

[tex]y=2x-3[/tex]

The x-values in the given table are -1, 1, 3.

To find:

The y-values for the given x-values in the table.

Solution:

We have,

[tex]y=2x-3[/tex]

At x=-1,

[tex]y=2(-1)-3[/tex]

[tex]y=-2-3[/tex]

[tex]y=-5[/tex]

At x=1,

[tex]y=2(1)-3[/tex]

[tex]y=2-3[/tex]

[tex]y=-1[/tex]

At x=3,

[tex]y=2(3)-3[/tex]

[tex]y6-3[/tex]

[tex]y=3[/tex]

Therefore the required table is:

x          y

-1        -5

1         -1

3         3

Answer:

It should be 4. The ratio that AC is equal to DE at should be equal to the ratio of BE to BC. If you want an explanation I'd be happy to add one!

4    

4*4 = [tex]\sqrt{x}[/tex]16                        not sure how it gets negative

Answer:

30/34 =

Step-by-step explanation:

Answer:

14. y=10

Step-by-step explanation:

3y-7=23

   +7   +7

3y=30

----  -----

3       3

y=10

Answer:

Step-by-step explanation:

[tex]3y-7=23[/tex]

Collect like terms and simplify

[tex]3y =23+7\\3y=30[/tex]

Divide both sides of the equation by 3

[tex]\frac{3y}{3} = \frac{30}{3}[/tex]

Simplify

[tex]y=10[/tex]    

2.

[tex]\frac{3(j-1)}{2}=12 + \frac{2-j}{4} \\\\\mathrm{Multiply\:by\:LCM=}4\\\\\frac{3\left(j-1\right)}{2}\times\:4=12\times\:4+\frac{2-j}{4}\times\:4\\\\Simplify\\6\left(j-1\right)=-j+50\\\\Expand\:6\left(j-1\right) :6j-6\\\\6j-6=-j+50\\\\\mathrm{Add\:}6\mathrm{\:to\:both\:sides}\\6j-6+6=-j+50+6\\\\Simplify\\6j=-j+56\\\\\mathrm{Add\:}j\mathrm{\:to\:both\:sides}\\6j+j=-j+56+j\\\\Simplify\\7j=56\\\\\mathrm{Divide\:both\:sides\:by\:}7\\\frac{7j}{7}=\frac{56}{7}\\\\Simplify\\j=8[/tex]

Answer:

6x3

Step-by-step explanation:

....................

Answer:

We are 95 percent confident that the mean word length for all papers submitted by students in humanities programs is between 20,995 words and 22,905 words

Step-by-step explanation:

The confidence interval is used to predict the mean for the entire humanities program, not just the sample.

Answer:

not sure forggive me if im wronng maybe B. false

Step-by-step explanation: