HELP ME PLEASEEEEEEEEEEEEEE

HELP ME PLEASEEEEEEEEEEEEEE

Answers

Answer 1
It makes energy for the cell
Answer 2

Answer:

probably won't help now but the answer is the 4th one lol

Explanation:


Related Questions

A spacecraft is moving past the earth at a constant speed of 0.60 times the speed of light. The astronaut measures the time interval between ticks of the spacecraft clock to be 3.2 s. What is the time interval (in seconds) that an earth observer measures

Answers

Answer:

the time interval that an earth observer measures is 4 seconds

Explanation:

Given the data in the question;

speed of the spacecraft as it moves past the is 0.6 times the speed of light

we know that speed of light c = 3 × 10⁸ m/s

so speed of spacecraft v = 0.6 × c = 0.6c

time interval between ticks of the spacecraft clock Δt₀ = 3.2 seconds

Now, from time dilation;

t = Δt₀ / √( 1 - ( v² / c² ) )

t = Δt₀ / √( 1 - ( v/c )² )

we substitute

t = 3.2 / √( 1 - ( 0.6c / c )² )

t = 3.2 / √( 1 - ( 0.6 )² )

t = 3.2 / √( 1 - 0.36 )

t = 3.2 / √0.64

t = 3.2 / 0.8

t = 4 seconds

Therefore, the time interval that an earth observer measures is 4 seconds

when the friction increases too much does the object stay still or moving opposite direction ​

Answers

Answer:

the moment when the object starts to move

Answer:

The object stays still when there is too much friction applied to the equation with the mass and applied force.

Explanation:

Penn Foster

What is the centripetal force for a roller coaster if the mass is 10 kg and the normal force is 25 N?

Answers

Answer:

Fc = 123 Newton

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

[tex] Fnet = Fapp + Fg[/tex]

Where;

Fnet is the net force.

Fapp is the applied force.

Fg is the force due to gravitation.

Given the following data;

Normal force = 25N

Mass = 10kg

To find the centripetal force;

From the net force, we have the following formula;

Fc = N + mg

Where;

Fc is the centripetal force.

N is the normal force.

mg is the the weight of the object.

Substituting into the formula, we have;

Fc = 25 + 10(9.8)

Fc = 25 + 98

Fc = 123 Newton

How are satellites used in GPS?

to keep the International Space Station in orbit
to communicate with the International Space Station
to communicate with possible extraterrestrial life
to pinpoint specific locations on Earth

Answers

Answer:

To pinpoint specific locations on Earth

Explanation:

The satellite has a full specific view of a specific area just like other satellites do. Satellites communicate together which also communicates with your GPS to give you an accurate location where you are or where you want to be. That is how satellites are used in GPS.

Hope this helps you out :)

Which statement did John Dalton make about atoms?
A. there are distinct kinds of atoms
B. the atom is made up of smaller particles
C. the atom has a small, dense center
D. the energy of an electron depends on its specific orbit

Answers

Answer:

B

Explanation:

Atoms are made by electrons, neutrons and protons

Answer:

A. there are distinct kinds of atoms

Explanation:

According to Dalton's atomic theory, the atom is indivisible. Thus, we know that B is incorrect. Additionally, C can't be correct because when Dalton was alive, the nucleus (the small, dense center) hadn't yet been discovered. Finally, D can't be correct either since Bohr's discoveries about electron orbits hadn't yet been made. Knowing that, it must be A!

Also, I just did the quiz, and it was A. Dalton believed that there are distinct kinds of atoms!

Among all the electromagnetic waves (EM), which has the highest frequency? *

A. INFRARED RADIATION
B. RADIO WAVE
C. ULTRAVIOLET
D. GAMMA RAYS

How do transverse waves move? *
A. The particles move up and down to the direction in which the waves travel.
B. The particles move back and forth to the direction in which the waves travel.
C. The particles move in circular paths to the direction in which the waves travel.
D. The particles move back and forth and side to side to the direction in which the waves travel.

20. How do we know that waves carry energy? *
A. Waves causes disturbances
B. Waves can set other objects into motion
C. Waves must travel in a medium
D. Waves move back and forth

21. What happens when waves pass by? *
A. The particles vibrate
B. The particles stop moving
C. The particles move forward
D. The particles remain stationary

22. Which of the following correctly relates wavelength and frequency? *
A. The higher the wavelength, the higher the frequency.
B. The lower the wavelength, the higher the frequency.
C. The lower the wavelength, the lower the frequency.
D. The wavelength is directly related to frequency.

23. Which of the following is the fastest? *
A. A wave wit h 10 m wavelength and a frequency of 30 Hz.
B. A wave with 30 m wavelength and a frequency of 2 Hz.
C. A wave with 20 m wavelength and a frequency of 2 Hz
D. A wave with 5 m wavelength and a frequency of 60 Hz.)

24. How can we generate mechanical waves? *
A. By producing light energy
B. By producing horizontal motion
C. By vibrating a medium
All of the above

25. A high energy electromagnetic wave has ____ *
A. Low frequency
B. High Frequency
C. Zero wave speed
D. Highest wave speed​

Answers

first is gamma Ray's, last is d

Which of the following statements correctly describes the index of refraction of a material? Select all that apply.
The index of refraction is the ratio of the speed of light in a material to the speed of light in a vacuum.
The index of refraction of a material must be greater than 1.
The index of refraction is the ratio of the speed of light in a vacuum to the speed of light in the material.
The index of refraction of a material must be less than 1.
The index of refraction of water is less than the index of refraction of air.​

Answers

Answer:

Option C and D only

Explanation:

Option A is incorrect  because refractive index of a material is the ratio of speed of light in vacuum to the speed of light in a any given medium

Option B is correct as the speed of light in vacuum is always greater than the speed of light in any given medium.

Option C is correct

Option D is incorrect

Option E is incorrect because the denser the medium the more is the refractive index. Water is denser than air, hence it should have more refractive index as compared to that of air.

A ball is thrown downward from the top of a building with an initial speed of 25 m/s.
It strikes the ground after 2.0 s. How high is the building?
20 m
30 m
50 m
70 m

Answers

Answer:

h = 69.6 m

Explanation:

Data:

Vo = 25 m/st = 2.0 sg = 9.8 m/s²h = ?

Formula:

[tex]\boxed{\bold{h=V_{0}*t+\frac{g*(t)^{2}}{2}}}[/tex]

Replace and solve:

[tex]\boxed{\bold{h=25\frac{m}{s}*2.0\ s+\frac{9.8\frac{m}{s^{2}}*(2.0\ s)^{2}}{2}}}[/tex][tex]\boxed{\bold{h=50\frac{m}{s^{2}}+\frac{9.8\frac{m}{s^{2}}*4\ s^{2}}{2}}}[/tex][tex]\boxed{\bold{h=50\ m+\frac{39.2\ m}{2}}}[/tex][tex]\boxed{\bold{h=50\ m+19.6\ m}}[/tex][tex]\boxed{\boxed{\bold{h=69.6\ m}}}[/tex]

The building has a height of 69.6 meters.

Greetings.

A ____________ galaxy has arms of gas and dust; where as _____________ galaxy is a category of galaxy that does not have a distinctive shape.

Question 1 options:

elliptical, an elliptical


irregular, a barred-spiral


bar, a spiral


spiral, an irregular

Answers

Answer:

spiral, an irregular

Explanation:

i took the test :)

4. A girl sits on a tire that is attached to a tree limb by a rope 2.10 m in length. The girl's father pushes her with a tangential speed of 2.50 m/s. If the magnitude of the force that maintains her is 88.0 N, What is the girl's mass? Predictions On JOT 自 DLL Fa F11​

Answers

Answer:

the answer is M=29.6kg

Explanation:

your welcome:)

A self-driving car traveling along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 25.0 m/s. Then the vehicle travels for 39.0 s at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s.
(a) How long is the self-driving car in motion (in s)?
(b) What is the average velocity of the self-driving car for the motion described? (Enter the magnitude in m/s.) m/s

Answers

Answer:

[tex]56.5\ \text{s}[/tex]

[tex]21.13\ \text{m/s}[/tex]

Explanation:

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

s = Displacement

Here the kinematic equations of motion are used

[tex]v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{25-0}{2}\\\Rightarrow t=12.5\ \text{s}[/tex]

Time the car is at constant velocity is 39 s

Time the car is decelerating is 5 s

Total time the car is in motion is [tex]12.5+39+5=56.5\ \text{s}[/tex]

Distance traveled

[tex]v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{25^2-0}{2\times 2}\\\Rightarrow s=156.25\ \text{m}[/tex]

[tex]s=vt\\\Rightarrow s=25\times 39\\\Rightarrow s=975\ \text{m}[/tex]

[tex]v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{0-25}{5}\\\Rightarrow a=-5\ \text{m/s}^2[/tex]

[tex]s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0-25^2}{2\times -5}\\\Rightarrow s=62.5\ \text{m}[/tex]

The total displacement of the car is [tex]156.25+975+62.5=1193.75\ \text{m}[/tex]

Average velocity is given by

[tex]\dfrac{\text{Total displacement}}{\text{Total time}}=\dfrac{1193.75}{56.5}=21.13\ \text{m/s}[/tex]

The average velocity of the car is [tex]21.13\ \text{m/s}[/tex].

At this point, you have learned that heat is the ________ of ________ energythat is possessed by an object due to the motion of its particles. When this happens, an object’s ____________ changesfrom cool to warmer.There are ways of heat transfer: (a) ____________, where heat is transferred between materials that are in direct contact with each other. While (b) ____________, occurs when heat is transferred by electromagnetic waves (through space). And lastly, (c) ____________is transfer of heat in fluids which makesthe hot fluids to rise and cold fluidstosink

Answers

Abbreviate the sentences

94. The diagram shows the orbit of a satellite
around Earth. If Earth's mass is 5.97x10 kg,
what is the satellite's orbital speed?
(G=6.67x10-11 N·mº/kg?)
A 5.84x10' m/s
B 6.31x104 m/s
C 7.23x10 m/s
D 7.65x10 m/s

Answers

Answer:

7.65x10^3 m/s

Explanation:

The computation of the satellite's orbital speed is shown below:

Given that

Earth mass, M_e = 5.97 × 10^24 kg

Gravitational constant, G = 6.67 × 10^-11 N·m^2/kg

Orbital radius, r = 6.80 × 10^6m

Based on the above information

the satellite's orbital speed is

V_o = √GM_e ÷ √r

= √6.67 × 10^-11 × 5.97 × 10^24 ÷ √6.80 × 10^6

=  7.65x10^3 m/s

A spring is hung from the ceiling. When a coffee mug is attached to its end, it stretches 2.5 cm before reaching its new equilibrium length. The block is then pulled down slightly and released. What is the frequency of oscillation

Answers

Answer:

Explanation:

In equilibrium , weight of mug is equal to restoring force .

mg = kx where m is mass of mug , k is spring constant and x is extension .

k / m = g / x = 9.8 ms⁻² / .025 m

= 392

frequency of oscillation n = [tex]\frac{1}{2\pi}\sqrt{\frac{k}{m} }[/tex]

[tex]n=\frac{1}{2\pi}\sqrt{392 }[/tex]

= 4.46 per second.

3. What is the difference between breathing and respiration?

Answers

Answer:

Breathing is the biological process of inhaling and exhaling of the gases between the cells and the environment. The mechanism of breathing involves various respiratory structures such as the windpipe, lungs and nose. Respiration, on the other hand, is a chemical process that takes place in the cell.

Explanation:

Convert 125 mL to L

Answers

Answer:

1 L = 1000 mL

125 mL = 125/1000 = 0.125 L

Answer:

0.125

Explanation:

divide by 1 000 to convert mL to liters

What is the centripetal force for a roller coaster if the mass is 10 kg and the normal force is 25 N?

Answers

Answer:

Fc = 123 Newton

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

[tex] Fnet = Fapp + Fg[/tex]

Where;

Fnet is the net force.

Fapp is the applied force.

Fg is the force due to gravitation.

Given the following data;

Normal force = 25N

Mass = 10kg

To find the centripetal force;

From the net force, we have the following formula;

Fc = N + mg

Where;

Fc is the centripetal force.

N is the normal force.

mg is the the weight of the object.

Substituting into the formula, we have;

Fc = 25 + 10(9.8)

Fc = 25 + 98

Fc = 123 Newton

The Sun is a star that Earth and the other planets revolve around. The Sun has a large gravitational pull. The gravitational attraction of the Sun contributes most to which of the following?
A) Motion of the planets
B) Magnetic field of the planets
C) Mass and density of the planets
D) Atmosphere of the planets

Answers

Answer:

A

Explanation:

The sun is an emits energy in the form of light and heat.

The planets absorb this energy which helps keep them in motion. The closer they are to the sun, the more energy, the more speed and less the time it takes a planet to orbit the sun.

The gravitational pull of the Sun contributes motion of the planets because here the gravitational pull of the sun is balanced by the centrifugal force produced by the revolution of planets. The correct option Is A.

What is centrifugal force?

Centrifugal force is the pseudo-force that occurs only in the rotating frame of reference (non-inertial frame). it is directed away from the center. Its magnitude is,

F=[tex]\frac{mv^{2} }{r}[/tex]

where m= mass of the body in kg.

v= velocity f the body in m/s.

r = radius in m.

The star sun has a  gravitational pull that is about 274 m/s²  which is greater than the other planets. Due to this pull the planets tend to pull toward the sun but it does not happen because the pull force is balanced by the centrifugal force that is produced by the revolution of the planets around the sun.

Hence The Sun's gravitational pull contributes to the motion of the planets.

To learn more about Centrifugal force click:

https://brainly.com/question/17167298

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What are the functionsssss of geostationary satellite and non-geostationary satellite?​

Answers

Answer:

What is the difference between a geostationary satellite and a non-geostationary satellite? Geostationary (GSO) satellites occupy an orbital position 36,000 km above the earth, and remain in a stationary position relative to the Earth itself.

HELP PLEASEEEEEEEEEEEE

Answers

the answer would be a

An atom has two more electrons than protons. What is the charge of the atom?

Answers

Answer:

If it has more electrons than protons it has a net negative charge and is known as an anion.

Five lamp, each labbled "6V,3W" are operated at normal brightness. What is the total energy supplied to the lamps in five seconds.​

Answers

Answer:

E = 75 J

Explanation:

First, we will calculate the total power consumed by the five lamps:

[tex]Total\ Power = P = (5)(Power\ of\ one\ lamp)\\P = (5)(3\ W)\\P = 15\ W[/tex]

Now, the energy supply can be calculated as follows:

[tex]E = Pt[/tex]

where,

E = Energy = ?

t = time = 5 s

Therefore,

E = (15 W)(5 s)

E = 75 J

Air(ideal gas) at 292.15k is expended by a piston from 600cm^3 to 900cm^3 at a temperature of 550k at 900kpa pressure. find the pressure before expansion.

Answers

Answer:

The pressure before expansion is 717.1 kPa.

Explanation:

We need to use the Ideal Gas equation to find the initial pressure:

[tex] PV = nRT [/tex]

Where:

P: is the pressure

V: is the volume

n: is the number of moles

R: is the gas constant

T: is the temperature

Since the number of moles does not change after the expansion, we need the following number of moles:

[tex] n = \frac{P_{f}V_{f}}{RT_{f}} [/tex]  (1)

Where "f" is for final

Before the expansion, the pressure is:

[tex] P_{i} = \frac{nRT_{i}}{V_{i}} [/tex]   (2)

By entering equation (1) into (2) we have:

[tex] P_{i} = (\frac{P_{f}V_{f}}{RT_{f}})(\frac{RT_{i}}{V_{i}}) [/tex]

[tex]P_{i} = \frac{P_{f}V_{f}T_{i}}{T_{f}V_{i}} = \frac{900 kPa*900 cm^{3}*292.15 K}{550 K*600 cm^{3}} = 717.1 kPa[/tex]

Therefore, the pressure before expansion is 717.1 kPa.                  

I hope it helps you!        

2. A company hires a security firm to patrol their stores and watch out for thieves. What is this an example of?

Answers

In a case whereby the company hires a security firm to patrol their stores and watch for thieves, this is an example of Inventory control.

Inventory Control: What Is It?

Inventory control, also known as stock control, is the procedure used to guarantee that a business has the appropriate amount of supplies on hand. As long as internal and production controls are in place, the business can meet client demand and maintain financial flexibility.

The general definition of inventory control or stock control is "the action of verifying a shop's stock." It is the process of making sure that a business has the appropriate amount of supply on hand.

Learn more about Inventory at:

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What does Binding Energy in the nucleus represent?

Answers

Answer:

Nuclear binding energy is the energy required to split a nucleus of an atom into its component parts: protons and neutrons, or, collectively, the nucleons. The binding energy of nuclei is always a positive number, since all nuclei require net energy to separate them into individual protons and neutrons.

I hope you find this helpful.


_PCi5 + _H20 + _H3PO4 _HCI
A.) 1,3,1,5
B.) 2,4,1,5
C.) 1,4,1,5
D.) 2,1,2,5


Answers

Answer:

C

Explanation:

because of the kids are doing well and staying in the middle of the day early to get a new phone number for home now deep

calculate the moment of 3kg and 20cm away from the pivot​

Answers

Answer:

5.88 Nm

Explanation:

Applying,

Moment(M) = Force(F)×perpendicular distance(d)

M = F×d.................... Equation 1

But,

F = mg.................. Equation 2

Where m = mass, g = acceleration due to gravity.

Substitute equation 2 into equation 1

M = mgd................. Equation 3

From the question,

Given: m = 3 kg, d = 20 cm = 0.2 m

Constant: g = 9.8 m/s²

Substitute these values into equation 3

M = 3×0.2×9.8

M = 5.88 Nm

Bobby Joe is having a fit and throws his backpack up in the air with an initial velocity of 26.2 m/s. Determine the height it will rise to before coming down and hitting Bobby Joe up the head.

A)2m
B)15m
C)25m
D)35m​

Answers

Answer:

D) 35m"

Explanation:

(and any subsequent words) was ignored because we limit queries to 32 words.

what's the point of friendship?​

Answers

Answer:

Friendships can have a major impact on your health and well-being, but it's not always easy to build or maintain friendships. Understand the importance of friendships in your life and what you can do to develop and nurture friendships

A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2 feet per second. (a) What is the velocity of the top of the ladder when the base is given below

Answers

This question is incomplete, the complete question is;

A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2 feet per second. (a) What is the velocity of the top of the ladder when the base is given below

7 feet away from the wall

15 feet away from the wall

20 feet away from the wall

Answer:

- When x is 7 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -7/12 ft/s

- When x is 15 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -3/2 ft/s

- When x is 20 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -8/3 ft/s

Explanation:

Given the data in the question;

Let [tex]r[/tex]ft and [tex]x[/tex]ft represent the distance of the top of ladder from the ground and the distance of the bottom of ladder from the wall respectively.

Now using the Pythagoras Theorem ( right angled triangle ).

(hypotenuse)² = ( adjacent )² + ( opposite )²

so

r² = ( 25 )² - x²

r² = 625 - x² ------- let this be equation 1

now, we differentiate with respect to t

2r [tex]\frac{dr}{dt}[/tex] = 0 - 2x [tex]\frac{dx}{dt}[/tex]

r [tex]\frac{dr}{dt}[/tex] = -x [tex]\frac{dx}{dt}[/tex]

[tex]\frac{dr}{dt}[/tex] = -x [tex]\frac{dx}{dt}[/tex] × 1/r

[tex]\frac{dr}{dt}[/tex] = -x/r [tex]\frac{dx}{dt}[/tex]

Now, from equation, r² = 625 - x²

r = √( 625 - x² )

Then

[tex]\frac{dr}{dt}[/tex] = -x / √( 625 - x² ) [tex]\frac{dx}{dt}[/tex]

given that, The base of the ladder is pulled away from the wall at a rate of 2 feet per second i.e [tex]\frac{dx}{dt}[/tex] = 2 ft/s

so;

[tex]\frac{dr}{dt}[/tex] = ( -x / √( 625 - x² ) ) × 2

[tex]\frac{dr}{dt}[/tex] = -2x / √( 625 - x² )

When x is 7 feet away from the wall;

[tex]\frac{dr}{dt}[/tex] = -2(7) / √( 625 - (7)² )

[tex]\frac{dr}{dt}[/tex] = -14 / √( 625 - 49 )

[tex]\frac{dr}{dt}[/tex] = -14 / √576

[tex]\frac{dr}{dt}[/tex] = -14 / 24

we simplify

[tex]\frac{dr}{dt}[/tex] = -7/12 ft/s

Therefore, When x is 7 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -7/12 ft/s

When x is 15 feet away from the wall

[tex]\frac{dr}{dt}[/tex] = -2(15) / √( 625 - (15)² )

[tex]\frac{dr}{dt}[/tex] = -30 / √( 625 - 225 )

[tex]\frac{dr}{dt}[/tex] = -30 / √400

[tex]\frac{dr}{dt}[/tex] = -30 / 20

we simplify

[tex]\frac{dr}{dt}[/tex] = -3/2 ft/s

Therefore, When x is 15 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -3/2 ft/s

When x is 20 feet away from the wall

[tex]\frac{dr}{dt}[/tex] = -2(20) / √( 625 - (20)² )

[tex]\frac{dr}{dt}[/tex] = -40 / √( 625 - 400 )

[tex]\frac{dr}{dt}[/tex] = -40 / √225

[tex]\frac{dr}{dt}[/tex] = -40 / 15

we simplify

[tex]\frac{dr}{dt}[/tex] = -8/3 ft/s

Therefore, When x is 20 feet away from the wall, [tex]\frac{dr}{dt}[/tex] = -8/3 ft/s

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