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The probability that the horse will not win the race is 0.7500.

The mathematical branch known as probability deals with determining the possibility of an event occurring. The conversions between probability and odds are feasible. This is because the odds are determined by dividing the likelihood that an event will occur by the likelihood that it won't.

Here, the odds of a horse winning a race are given as 2 to 6. Then, the probability of winning the horse race is calculated as,

[tex]\begin{aligned}\text{Odds}&=\frac{p}{1-p}\\\frac{2}{6}&=\frac{p}{1-p}\\2(1-p)&=6p\\2-2p&=6p\\2&=6p+2p\\8p&=2\\p&=\frac{2}{8}\\&=\frac{1}{4}\end{aligned}[/tex]

Then, the probability of not winning the horse race is,

[tex]\begin{aligned}q&=1-p\\&=1-\frac{1}{4}\\&=\frac{3}{4}\\&=0.75\end{aligned}[/tex]

The answer is 0.75. Therefore, the correct option is option c.

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The exterior angle with angle d is equivalent to 141 degrees, and the value of x is equal to 10.

We must keep in mind that the total of all the angles in a triangle equals 180 degrees in order to solve this puzzle.

The given angles are-

Using that formula in this case;

Thus, sum of all angles is 180°.

m < d + m < e + m < f = 180°

(2x + 19)° + (3x + 24)° + 87° = 180°

x = 10°

But if angle D is on a straight line, it is possible to find its exterior angle because angle D plus its exterior angle add up to 180 degrees.

Suppose y = external angle.

m < d + y = 180°

2x + 19 + y = 180°

And x = 10°

2(10) + 19 + y = 180°

y = 141°

Thus, the measure of the degree measure of the exterior angle is found as  141°.

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The correct question is-

In triangle DEF, m∠D = (2x + 19)°, m∠E = (3x + 24)°, and m∠F = 87°. Determine the degree measure of the exterior angle to ∠D.

54°

39°

141°

126°

Answer:

Your answer is 22.

Tu respuesta es 22. Además, no hablo español, usé Translate

The closest distance the family will come to the landmark while on the road is 12.03 miles.

Here, the situation represented in the question can be depicted as shown in the image below.

The family moves from F1 to F2 as the angle changes from 62 to 38.

Now, using trigonometric ratios in the smaller triangle we have-

Cot 62 = X/Y

X = Y Cot 62

Similarly, Cot 38 = (X + 9)/ Y

Substituting the value of X in the above equation we get-

Y Cot 38 = (Y Cot 62 + 9)

Y Cot 38 - Y Cot 62  = 9

Y(Cot 38 - Cot 62) = 9

Y = 9/ (Cot 38 - Cot 62)

Y = 9/ (1.2799 - 0.5317)

Y = 9/ 0.7482

Y = 12.028

Thus, the closest distance the family will come to the landmark while on the road is 12.03 miles.

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Answer:

(a)  Other zeros:  3i  and  -4-i

(b)  9

(c)  10

Step-by-step explanation:

Given information:

For any complex number  [tex]z=a+bi[/tex], the complex conjugate of the number is defined as  [tex]z^*=a-bi[/tex] .  

If f(z) is a polynomial with real coefficients, and z₁ is a root of f(z)=0, then its complex conjugate z₁* is also a root of f(z)=0.

Therefore, if R(x) is a polynomial with real coefficients, and 3i is a root of R(x)=0, then its complex conjugate -3i is also a root of R(x)=0.

Similarly, if -4+i is a root of R(x)=0, then its complex conjugate -4-i is also a root of R(x)=0.

The degree of the polynomial is the greatest of the exponents of its various terms.  

The degree of R(x) with just the given roots (including the complex conjugates) is 6, which includes 2 real zeros.

As the actual degree of R(x) is 13, the maximum number of real zeros would be 7 more than the given real zeros.

Therefore, the maximum number of real zeros that R(x) can have is 9.

For each complex root there is also a complex conjugate root.

We have been given 2 complex zeros and 2 real roots, so when we include the complex conjugates, the degree of R(x) is 6.

The actual degree of R(x) is 13, so the maximum number of non-real zeros is 6 more (as they come in pairs) than the already given 4 non-real zeros.  Therefore, the maximum number of non-real zeros that R(x) can have is 10.

The distance between the two towns is 49 km

What is average speed?

Average speed is calculated by dividing distance by time (eg miles/hour).

The entire distance traveled by the object in a specific amount of time is its average speed. A scalar quantity, average speed, exists. The magnitude serves as its representation, and it lacks direction.

A body's average speed is its mean value over a given amount of time. Since a moving body's speed fluctuates over time and is not constant, an average speed formula is required. The total time and total distance numbers can be used, even with fluctuating speed, and with the aid of the average speed formula, we can get a single value to represent the entire motion.

Difference in times = 12:42 - 11:32 = 1.17 hours

Formula:

Distance = speed * time

               = 42 * 1.17

              = 49 km

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Therefore, L has a relative and absolute minimum when x = 400 m

The area is as defined as the amount of space occupied by any shape in two dimensions. Whereas, Perimeter is the boundary or the outline of a flat shape.

Let x = length of the side parallel to the river

     y = length of each of the other two sides

Then xy = 80,000, so y = 80,000/x

Minimize:  L = length of the fence

L = x + 2y

  = x + 160,000/x, where x > 0

L' = 1 - 160,000/x2 = (x2 - 160,000)/x2

L' = 0 when x = 400 or -400

Since x can't be negative, x must be 400.

When 0 < x < 400, L' < 0.  So, L is decreasing.

When x > 400, L' > 0.  So L is increasing.

Therefore, L has a relative and absolute minimum when x = 400 m

                                                                                    y = 80,000/x = 200 m

The fence is shortest if the side parallel to the river has length 400 m and the other 2 sides each have length 200 m.  

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The ant travels at a pace of 1/15 mins per centimeters.

What is Pace?

Meaning of pace is rate of movement.

Pace is the inverse of speed.

If speed is measured in units of distance per unit of time then pace is measured in units of time per unit of distance.

We know speed is total distance travelled in the total time taken

speed = distance/time

According to the given question:

Ant travels 30cm in every 2 minutes

Distance travelled by ant = 30 cm

Time taken to travel this distance = 2 minutes

Therefore, speed of the ant is

30/2 = 15 cm per min

Now pace = inverse of speed

pace = 1/15 min per cm

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The amount that actually enrol is 3000

From the question, we have the following parameters that can be used in our computation:

Expected enrolment = 70%

Actual enrolment = 30%

Number of applicants = 10000

This means that

Actual = Actual enrolment * Number of applicants

Substitute the known values in the above equation, so, we have the following representation

Actual = 30% * 10000

Evaluate

Actual = 3000

Hence, the amount  is 3000

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Answer: $0.95

Step-by-step explanation:

7.90 - 1.25 = 6.65

6.65 divided by 7 = 0.95

Answer:

12x+3

Step-by-step explanation:

distribute the 5 to both the 2x and -1

10x-5

do the same with the the 2. Distribute the 2 to the x and to the 4.

2x+8

10x-5+2x+8

add like terms: the 10x and the 2x are like terms and the -5 and 8 are like terms

12x+3 : the answer

The probabilities for the given hours are,

[tex](a) Pr(100 < x < 250) = 0.302440605\\(b) Pr(\frac{x > 300}{x > 200})=0.670320046\\ (c) Pr(x > 100) = 0.670320046[/tex]

What is probability?

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a proposition to be true. A number between 0 and 1 is the probability of an event, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

P.D.F , [tex]f(x) = \frac{1}{250}e^\frac{-x}{250} ; x \geq 0\\[/tex]

C.D.F ,  [tex]F(X) = 1-e^\frac{-x}{250} ;x \geq 0[/tex]

(a)

[tex]Pr(100 < x < 250) = F(250) - F(100)\\Pr(100 < x < 250) = (1-e^\frac{-250}{250})-(1-e^\frac{100}{250} )\\ Pr(100 < x < 250) = (e^\frac{-2}{5}-e^-^1) \\ Pr(100 < x < 250) = 0.670320046 - 0.367079441\\ Pr(100 < x < 250) = 0.302440605[/tex]

(b)

[tex]Pr(\frac{x > 300}{x > 200}) = \frac{Pr[(x > 300) intersection(x > 200)]}{Pr(x > 200)} \\ Pr(\frac{x > 300}{x > 200}) = \frac{Pr(x > 300)}{Pr(x > 200)} \\Pr(\frac{x > 300}{x > 200}) = \frac{1 - F(300)}{1-F(200)} \\Pr(\frac{x > 300}{x > 200}) = \frac{e^\frac{-300}{250} }{e^\frac{-200}{250} } \\Pr(\frac{x > 300}{x > 200}) = e^\frac{-2}{5} \\Pr(\frac{x > 300}{x > 200})= 0.670320046[/tex]

(c)

[tex]Pr(x > 100) = 1-Pr(x < 100) = 1- F(100) = e^\frac{-100}{250} = e^\frac{-2}{5} = 0.670320046[/tex]

Hence, the probabilities for the given hours are,

[tex](a) Pr(100 < x < 250) = 0.302440605\\(b) Pr(\frac{x > 300}{x > 200})=0.670320046\\ (c) Pr(x > 100) = 0.670320046[/tex]

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Complete question:

Complete question is attached below,

Answer: 1st point : 0,-1 second point : 1,0

Step-by-step explanation: the y intercept is -1. The slope is 2/1 rise over run. Two rise 1 over

The number of customers Alejandro will need in order to break even is 38 customers.

Given data:

Cost of business = 48 x + 500

Income = R = 65 x - 145

Let x is the number of customers.

Income equation  

R= 65x- 145

Substitute 48x + 500  for y

48x + 500 = 65x -145

Substract 48x from both side

500 = 17x - 145

Add 145 to each side

645 = 17x

Divide both side by 17x

x =645 /17

x = 37.9

x = 38 customers (Approximately)

Therefore the number of customers is 38 customers.

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A hole can be found at x = -3.

Area is the total amount of space that an object's shape or a flat (2-D) surface occupy.

Create a square on paper by using a pencil. Two dimensions make it up. A shape's area on paper is the space it takes up.

Imagine that your square is made up of smaller unit squares.

The area of a figure is equal to the number of unit squares required to completely cover the surface area of a particular 2-D shape. Square cms, square feet, square inches, square meters, etc. are a few common units for measuring area.

To get the area of the square figures presented below, draw unit squares with 1-centimeter sides. Therefore, the shape will be measured.

According to our question-

When the denominator is zero, the function will have a hole at the x-values and become undefined. In a language of mathematics:

There are two answers to this equation:

The function will have a gap at those x-values.

Hence, A hole can be found at x = -3.

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Hence, the equation of parabola in vertex from vertex [tex](4,4)[/tex] point [tex](3,-2)[/tex] is

[tex]y=-6(x-4)^2+4[/tex].

What is the equation?

The definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.

Here given that,

The parabola in vertex from vertex [tex](4,4)[/tex] point [tex](3,-2)[/tex] .

Here [tex](x,y)=(3,-2)[/tex] and [tex](x_1,y_1)=(4,4)[/tex]

The general formula is

[tex]y=a(x-x_1)^2+y_1[/tex]       ....[tex](1)[/tex]

Substitue the given values in the equation [tex](1)[/tex], we get

When [tex](x_1,y_1)=(4,4)[/tex]

[tex]y=a(x-4)^2+4[/tex]

When [tex](x,y)=(3,-2)[/tex]

[tex]-2=a(3-4)^2+4\\\\-2=a(-1)^2+4\\\\-2=a+4\\\\a+4+2=0\\\\a+6=0\\\\a=-6[/tex]

So, the equation is of thr form

[tex]y=-6(x-4)^2+4[/tex]

Hence, the equation of parabola in vertex from vertex [tex](4,4)[/tex] point [tex](3,-2)[/tex] is

[tex]y=-6(x-4)^2+4[/tex].

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The ratio of 13 to 25 is 13/25 because 13 is a prime number

The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity. Ratios can be classified into two types. One is part to part ratio and the other is part to whole ratio. The part-to-part ratio denotes how two distinct entities or groups are related. For example, the ratio of boys to girls in a class is 12: 15, whereas, the part-to-whole ratio denotes the relationship between a specific group to a whole. For example, out of every 10 people, 5 of them like to read books. Therefore, the part to the whole ratio is 5: 10, which means every 5 people from 10 people like to read books.

In this question, we have to find the ratio between 13 to 25

To do this, we simply divide 13 by 25

13÷25 = 13/25

This is so because the two numbers are not divisible as 13 is a prime number.

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The largest area of a rectangle that can be inscribed in a semicircle of radius 6 is 36.

What is the semicircle?

A semicircle is a one-dimensional locus of points that makes up one-half of a circle in mathematics. A semicircle's whole arc is always 180 degrees long. It just has one symmetry line.

The equation of the semicircle is

x² + y² = r²         .............(1)

The area of the rectangle is

A  = 2xy  ..................(2)

From equation (1), we get

y² = r² - x²

y = √r² - x²

Plugging this value in equation (2)

A  = 2x√r² - x²

Differentiating wrt. x using the product rule,

[tex]\frac{dA}{dx} = 2\sqrt{r^2 - x^2} - 2\frac{x^2}{\sqrt{r^2 - x^2} }[/tex]

[tex]\frac{2r^2 - 4x^2 }{\sqrt{r^2 - x^2} }[/tex]

The critical points are when

[tex]\frac{dA}{dx} = 0[/tex]

that is

[tex]\frac{2r^2 - 4x^2 }{\sqrt{r^2 - x^2} } = 0[/tex]

r² = 2x²

x = r/√2

Then,

y = √r² - x²

= √r² - (r/√2)²

= r/√2

The maximum area is

A = 2 .  r/√2 .  r/√2  = r²

A = r² = (6)² = 36

Hence, the largest area of a rectangle that can be inscribed in a semicircle of radius 6 is 36.

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The length of diameter of the base of the cone will be 112 cm. Hence, option b is correct.

Equations are mathematical expressions that have two algebras on either side of an equal (=) sign. The expressions on the left and right are shown to be equal to one another, demonstrating this relationship. L.H.S. = R.H.S. (left-hand side = right side) is a fundamental simple equation.

As per the given information in the question,

Use the equation of Pythagoras's theorem,

106² = 90² + r²

r² = 106² - 90²

r = √3136

r = 56 cm.

Then, the diameter will be,

D = 2r

D = 2(56)

D = 112 cm.

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The appropriate design for testing the significance of the difference between the means is called an independent-samples t-test.

The Independent Samples t- test analyzes the means of two separate groups to observe if there is statistical support that the population mean values are statistically substantially different.

A parametric test is said to be the Independent Samples t Test and the Independent t Test is another name for this test. Both examine the significance of a discrepancy between two means.

Independent-sample t tests compare scores on the same variable for the two different groups of cases, whereas paired-sample t tests compare scores on two different variables for the same group of instances.

When doing a t-test, it is usual to make the following assumptions: like the measuring scale, random sampling, normality of the data distribution, sufficiency of the sample size, and an equality of variance in standard deviation.

The appropriate design for testing the significance of the difference between the means is - b. independent-samples t-test.

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Answer:5/8

Step-by-step explanation:

[tex]\begin{gathered} \boxed{ \sf \frac{3}{4} - \frac{1}{8}} = \\ \\ \sf \frac{8 \div 4 \times 3 - 8 \div 8 \times 1}{8} = \\ \\ \sf\frac{6 - 1}{8} = \\ \\ \sf \boxed{ \sf\frac{5}{8}} \end{gathered}[/tex]

Therefore, the result of this subtraction of fractions is five eighths.

How to subtract unlike fractions:

Heterogeneous fractions are fractions that have different denominators.

To subtract heterogeneous fractions we follow these steps:

The account in which there was a mistake in the calculation of the simple interest is account B.

We know that the interest is an amount of money that is obtained on top of the initial money that was deposited. The initial money that you deposit in the account is called the principal. The rate is the percentage at which the interest is calculated and the time is the period that has elapsed since the deposit was made.

Given that;

I = PRT/100

I = interest

P = principal

R = rate

T = time

For account A

I = 200 * 3.9 * 1/100

I = $7.8

For account B;

I = 400 * 2.7 * 1/100

I = $10.8

We can see that there must have been a calculation error as the interest in account B was being calculated.

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[tex]\frac{2x+3}{3}[/tex]

-3 + x - [tex]\frac{1}{3}[/tex]x + 4

-3 + x + [tex]\frac{-x}{3}[/tex] + 4

-3 + x + [tex]\frac{-x}{3}[/tex] + 4

1 + x + [tex]\frac{-x}{3}[/tex]

1 + x + [tex]\frac{-x}{3}[/tex]

[tex]\frac{3}{3}[/tex] + [tex]\frac{3x}{3}[/tex] + [tex]\frac{-x}{3}[/tex]

[tex]\frac{3}{3}[/tex] + [tex]\frac{3x}{3}[/tex] +[tex]\frac{-x}{3}[/tex]

[tex]\frac{3 + 3x - x}{3}[/tex]

[tex]\frac{3 + 3x - x}{3}[/tex]

[tex]\frac{3 + 2x}{3}[/tex]

[tex]\frac{3 + 2x}{3}[/tex]

[tex]\frac{2x+3}{3}[/tex]

[tex]\frac{2x+3}{3}[/tex]

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The measure of the angle with an initial ray in the 3 o'clock position and a terminal ray passing through the car is 0 or origin.

Terminal ray:

In geometry, terminal ray refers the ray in the terminal position, after the rotation, is called the terminal side of the angle.

Given,

Here we need to find if θ measures 0 radians, then the measure of the angle with an initial ray in the 3 o'clock position and a terminal ray passing through the car.

While we looking into the given question,

the value of θ = 0 radians

And the Slope of terminal ray is calculated by using the formula,

=> tan θ

Then Slope = tan 0

Now, by using radians calculator,

=> tan 0 = 0

Therefore, the slope of the terminal ray is  0 which means the origin of the line.

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The relationship between RS and RT is RT is the base of this isosceles triangle.

We know two similar planer figures are congruent when we have sides or angles or both that are the same as the corresponding sides or angles or both.

We know the sum of all the interior angles in a triangle is 180°.

Given, A triangle RST,

So, ∠S + ∠T + ∠R = 180°.

50° + 65° + ∠R = 180°.

∠R = 65°.

This is an isosceles triangle with two similar sides RS and ST.

The relation between RS and RT is RT is the base of this isosceles triangle.

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Answer: If A is true, then B must be true.

Local minimum at: (1, -7) , (3, -7).

Local maximum at : DNE

What to find: Local extrema.

To solve the given problem, we will use the steps below:

Local extrema:

A local extremum of a function is the point at which a maximum or minimum value of the function in some open interval containing the point is obtained.

                                                   OR

Local extrema on a function are points on the graph where the -coordinate is larger (or smaller) than all other -coordinates on the graph at points ''close to'' . A function has a local maximum at , if for every near .

Locate the local extremum from the graph.

From the graph given, we have two local minimum.

At x = 1, f(1) =-7

Hence, the local minimum is (1, -7)

At x=3, f(3) =-7

Hence, the local minimum is ( 3, - 7)

Therefore, the local minimum are (1, -7) , (3, -7).

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