A merry-go-round accelerating uniformly from rest achieves itsoperating speed of 2.5rpm in five revolution.
A) What is the magnitude of its angluar acceleration(rad/s^2)?
B) How many seconds does it take the merry-go-round to reachits operating speed?
Answer:
(A) The magnitude of its angular acceleration 1.09 x 10⁻³ rad/s²
(B) Time of motion 240.2 s
Explanation:
Given;
final angular speed, ωf = 2.5 RPM
angular distance, θ = 5 rev = 5 x 2π = 10π rad
initial angular speed, ωi = 0
final angular speed in rad/s;
[tex]\omega_f = \frac{2.5 \ rev}{min} \times \ \frac{2\pi}{1 \ rev} \times \ \frac{1 \min}{60 s} = 0.2618 \ rad/s \\[/tex]
(A) the magnitude of its angular acceleration(rad/s^2);
[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta\\\\(0.2618)^2 = 0 + (2\times 10\pi)\alpha\\\\0.0685 = 20\pi \alpha\\\\\alpha = \frac{0.0685}{20\pi} \\\\\alpha = 1.09\times 10^{-3} \ rad/s^2[/tex]
(B) Time of motion;
[tex]\omega_f = \omega_i + \alpha t\\\\0.2618 = 0 + 1.09\times 10^{-3} t\\\\t = \frac{0.2618}{1.09\times 10^{-3}} \\\\t = 240.2 \ s[/tex]
select one popular music either OPM or from other countries that you like most. a.why you like this music/song? b.What is the message/s of this song that affect you most? c.if you will be the writer of this song, will you change the title or not? why?
Answer:
my favourite song is hym to the sea. That song reminds me of the innocent people who lost their lives in titanic a century ago. If I was the writer of that song ,i would not change the title of that song because I can feel the sound of ocean when I listen to that song.
if an object can make 10 revolutions in a minute, what's is period
Answer:
Period = 6 seconds.
Explanation:
Given the following data;
Number of oscillation, n = 10
Time = 1 minute to seconds = 60 seconds
To find the period;
A period is the number of revolutions in a minute.
[tex] Period = \frac {time}{number \; of \; oscillations}[/tex]
Substituting into the equation, we have;
[tex] Period = \frac {60}{10}[/tex]
Period = 6 seconds.
The first charge is pulling on the second. Is the second pulling on the first? Explain your reasoning
Answer:
law of action and reaction.
Explanation:
In Newton's three laws it is established that forces act in pairs, if one body interacts with another the second interacts with the first, this is the so-called law of action and reaction.
In this case, when the first load pulls on the second, the second pulls on the first, the two forces are not canceled because each one is applied to a different body.
Therefore the magnitude of the forces is the same, but the direction is opposite and each one is applied in a body
An electric force is an attractive or repulsive interaction. Newton's laws of motion define how it affects things, just like any other force. Yes, the second pulling on the first.
How does Newton's third law explain in terms of electricity?An electric force is an attractive or repulsive interaction between any two charged things. Newton's laws of motion define how it affects things, just like any other force.
The motion of objects under the influence of such a force or combination of forces is studied using Newton's laws.
The analysis generally starts with the creation of a free-body diagram in which the kind and direction of the various forces are represented by vector arrows.
Newton's laws of motion define how it affects things, just like any other force. Hence Yes, the second pulling on the first.
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what kind of waves travel as transverse waves
A. Only mechanical
B. All waves
C. Some waves
D. No waves
Answer:
C. Some waves
Explanation:
The answer is some waves because transverse waves are not the only types of waves we have on the earth. We also have longlitudal waves, which means only some waves can only be transverse. The answer to the question should be C. Some waves.
Julieta kicks a 0.2 kg soccer ball already rolling in the same direction at 2.5 m/s. The ball leaves her foot at a speed of 20 m/s after the kick
Answer:
3.5kgm/s
Explanation:
We can calculate the momentum of Julieta
momentum = m(v-u)
Momentum = 0.2(20-2.5)
Momentum = 0.2(17.5)
Momentum = 3.5
Hence the momentum of Julieta is 3.5kgm/s
Which of the following technologies would produce the most energy in light
waves?
A. Infrared sensor on a DVD player
B. Wireless communications transmitter
C. Microwave industrial drying equipment
D. Compact fluorescent lightbulb
Answer:
D. Compact fluorescent lightbulb
Explanation:
Compact fluorescent lightbulb
A compact fluorescent light bulb would produce the most energy in light
waves, therefore the correct option is D.
What is electromagnetic radiation?Electromagnetic radiation is a type of energy radiation produced by the propagation of electromagnetic waves that are produced for natural as well as anthropogenic reasons. This radiation does not need any kind of medium to propagate. The electromagnetic wave has components of light as well as heat in them.
Different kinds of electromagnetic radiation have varied levels of energy for example solar radiation is also a form of electromagnetic radiation and gamma radiation is electromagnetic radiation with very high energy.
Most energy in the form of the light wave is produced by the Compact fluorescent lightbulb, therefore the correct option is D.
Learn more about electromagnetic radiation
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Can someone help me please
Answer:
distance i think im not sure
PLS HELP ASAP I NEED THIS BY TONIGHT
Answer:
woahhh
Explanation:
How would the force between two charged particles change if one of the charges were to triple in strength (3x stronger)?
A. 9x stronger
B. 1/3 as strong
C. 1/9 as strong
D. 3x stronger
Answer:
The correct option is (d). "3x stronger".
Explanation:
The force between two charged particle is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
If one charge is tripled, [tex]q_1'=3q[/tex]
New force will be :
[tex]F'=\dfrac{kq_1'q_2}{r^2}\\\\=3\times F[/tex]
It means if one of the charges were to triple in strength, then the force will become 3 times of the initial force.
difference between light energy and heat energy
Need help with physics.
Question: A 65 kg child riding a Ferris wheel has a tangential speed of 9.5 m/s. Find the magnitude of the centripetal force on the child if the distance from the child to the axis of the wheel is 20 m.
The centripetal force : F = 293.3125 N
Further explanationGiven
mass = 65 kg
v = 9.5 m/s
r = 20 m
Required
the centripetal force
Solution
Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle
[tex]\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}[/tex]
F = centripetal force, N
m = mass, Kg
v = linear velocity, m / s
r = radius, m
Input the value :
F = 65 x 9.5² / 20
F = 293.3125 N
A train travels 20,000km in 500h. What is the average speed of the train?
Answer:
40 mph
Explanation:
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A solution contained 0.05g of sodium hydroxide in 25 cm3 of water
What is the concentration of the solution in g/dm3?
Given :
A solution contained 0.05g of sodium hydroxide in 25 cm3 of water.
To Find :
The concentration of the solution in g/dm³.
Solution :
We know, 1 cm = 0.1 dm
So, 1 cm³ = 0.001 dm³
Now, 25 cm³ = 25 × 0.001 dm³
25 cm³ = 0.025 dm³
Now, concentration of the solution in g/dm³ is [tex]\dfrac{0.05\ g}{0.025\ dm^3} = 2 \ g/dm^3[/tex].
Therefore, the concentration of the solution is 2 g/dm³.
83. A sailboat travels south at 12.0 km/h with respect to the
water against a current 15.0° south of east at 4.0 km/h.
What is the boat's velocity?
Answer:
The magnitude of the boat's velocity is 8.21 km/h.
Explanation:
We can find the boat's velocity as follows:
[tex] \Epsilon V_{x} = V_{w_{x}} + V_{b_{y}} [/tex]
[tex] \Epsilon V_{y} = V_{w_{y}} + V_{b_{y}} [/tex]
Where:
[tex]V_{w_{x}}[/tex] and [tex]V_{w_{y}}[/tex] are the components of the velocity of the water in the x and y-direction
[tex]V_{b_{x}}[/tex] and [tex]V_{b_{y}}[/tex] are the components of the velocity of the boat in the x and y-direction
Since the angle is 15° we have:
[tex] \Epsilon V_{x} = -4.0 km/h*sin(15) + 0 = -1.04 km/h [/tex]
[tex] \Epsilon V_{y} = 4.0 km/h*cos(15) - 12.0 km/h = -8.14 km/h [/tex]
Now, the velocity of the boat is:
[tex] V = \sqrt{V_{x}^{2} + V_{y}^{2}} = \sqrt{(-1.04 km/h)^{2} + (-8.14 km/h)^{2}} = 8.21 km/h [/tex]
Therefore, the magnitude of the boat's velocity is 8.21 km/h.
I hope it helps you!
Two identical conducting spheres are charged with a net charge of +5.0 q on the first sphere and a net charge of −8.0 q on the second sphere. The spheres are brought together, allowed to touch, and then separated. What is the net charge on each sphere now?
Answer:
The net charge on each sphere is -1.5 q
Explanation:
Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q = \dfrac{Q_1 + Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]Q = \dfrac{5 \ q+ (-8 \ q)}{2} = -\dfrac{3 \ q}{2} = -1.5 \ q[/tex]
The net charge on each sphere, Q = -1.5 q.
The net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
What is charge?Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]\dfrac{5q+(-8q)}{2}=-1.5q[/tex]
Hence the net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
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If the small piston has an area of .004 square
meters and Bob pushes down on it with 225 N of
force, how much weight can he lift on the car
side of the system, if that piston's area is 3.5
square meters?
F₂ = 1.723 x 10⁸ N
Further explanationGiven
Area of small piston : 0.004 m²
Area of large piston : 3.5 m²
Force 225 N
Required
Force applied
Solution
Pascal Law :
F₁/A₁=F₂/A₂
225/0.004 m² = F₂/3.5² m²
F₂ = 1.723 x 10⁸ N
If you use the same force to push a motorcycle as you would push a bike which one would have more acceleration and why explain using Newton's second law
Answer:
The bike would have more acceleration
Explanation:
Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.
Eg.
F=50N
Motorbike M=200kg
F=ma
50=200 x a
50/200=a
0.25m/s/s =a
Bike M=35kg
F=ma
50=35 x a
50/35= a
1.43m/s/s=a
Answer:
the bike
Explanation:
it has less mass than the motorcycle so so it would have more acceleration
The reaction between magnesium (Mg) and oxygen (O2) forms magnesium oxide (MgO).
a. Write a balanced chemical equation to represent this reaction.
b. Identify the type of reaction this represents.
Answer:
2 Mg + O2 = 2MgO
Type: Synthesis
A gas cylinder has a volume of 0.4 m? It contains butane at a pressure of 100 kPa and a temperature of
20°C. What pressure is needed to compress the gas to a volume of 0.05 m² at the same temperature?
The pressure needed : 800 kPa
Further explanationGiven
V₁ = 0.4 m³
P₁ = 100 kPa
T₁ = 20 + 273 = 293 K
V₂ = 0.05 m³
T₂ = T₁ = 293 K
Required
The final pressure(P₂)
Solution
Boyle's Law
At a fixed temperature, the gas volume is inversely proportional to the pressure applied
[tex]\tt \rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}[/tex]
Input the value :
P₂=P₁V₁/V₂
P₂=100 x 0.4 / 0.05
P₂=800 kPa
Does a light bulb at a temperature of 2500K produce as white a light as the sun at 6000K
Answer:
No. ... UV light causes sunburn, whereas visible light does not.
Explanation:
The light energy produced from a light bulb is far low compared to the light energy produced by the sun. The heat energy also greatly differ in both.
What light energy ?Light energy is a form of energy produced by stars and man made devices. One form of energy can be transformed into other form without destroying the energy.
The source of light and heat energy in stars is nuclear fusion. Fusing of two light nuclei forming a heavy nuclei accompanies the release of tremendous amount of energy.
In a light bulb, the electrical energy is converted to light energy and some energy is lost in the form of heat energy. The light the white light produced by a bulb cannot be as intense as the white lite from sun.
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What reasoning correctly pairs a body system with its relationship to the digestive system?
Group of answer choices
excretory system; transports nutrients from the small intestine to other tissues
respiratory system; obtains oxygen so the energy in nutrients can be extracted
circulatory system; regulates and controls digestive functioning
nervous system; removes wastes from the blood SCIENCE
Answer:
I Believe the Correct Answer is respiratory system; obtains oxygen so the energy in nutrients can be extracted.
Explanation:
Respiratory System is made for oxygen and involves the Lungs Diaphragm etc.
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Three point charges are arranged along the x axis. Charge q1 = -4.10 nC is located at x= 0.250 mand charge q2 = 2.20 nC is at x= -0.320 m . A positive point charge q3 is located at the origin.
What must the value of q3 be for the net force on this point charge to have magnitude 3.10 μN ? (ans in nC)
What is the direction of the net force on q3? + or - direction
Where along the x axis can q3 be placed and the net force on it be zero, other than the trivial answers of x=+[infinity] and x=−[infinity]? (ans in m)
Answer:
1) q₃ is approximately -7.58 nC
2) The direction of the net force on 'q₃' is the negative '-' direction
3) For the net force on 'q₃' to be zero, 'q₃' can be placed at x = -0.079 m or x = -1.881 m
Explanation:
1) The force, 'F', between two charged spheres is given as follows;
[tex]F = \dfrac{k \cdot q_1 \cdot q_2}{r^2}[/tex]
The net force acting on the point charge, 'q₃', is given as follows;
[tex]F_{NET} = \dfrac{k \cdot q_1 \cdot q_3}{x_1^2} + \dfrac{k \cdot q_2 \cdot q_3}{x_2^2}[/tex]
By substituting the given values, we have;
[tex]F_{NET} = 3.10 \ \mu N = \dfrac{k \cdot (-4.10 \ nC) \cdot q_3}{(0.250 \ m) ^2} + \dfrac{k \cdot 2.20 \ nC \cdot q_3}{(-0.320 \ m)^2}[/tex]
[tex]3.01 \ \mu N= q_3 \cdot \left ( \dfrac{k \cdot (-4.10 \ nC) }{(0.250 \ m) ^2} + \dfrac{k \cdot 2.20 \ nC }{(-0.320 \ m)^2} \right) = -\dfrac{14117 \ nC \cdot K}{320}[/tex]
[tex]\therefore q_3 = 3.01 \ \mu N \times -\dfrac{320 \ m^2}{14117 \ nC \cdot K}[/tex]
K = 9 × 10⁹ N·m²·C⁻²
[tex]\therefore q_3 = 3.01 \ \times 10^{-6} \ N \times -\dfrac{320 \ m^2}{14117 \times 10^{-9} \ C \times 9 \times 10^9 \ N \cdot m^2 \cdot C^{-2}}= -7.58 \ nC[/tex]
q₃ ≈ -7.58 nC
2) Given that the negative charge, 'q₁' (-4.10 nC), is located at x = 0.250 m, which is on the positive, '+' side of the origin, it will repel the negatively charged 'q₃', to the '-' direction. q₃ will also be attracted to the '-' direction by the positively charged 'q₂' which is at -0.320 m on the negative side of the origin
The net force's direction on q₃ will be in the '-' direction
3) For zero net force, we have;
The distance between the given point charges, r = 0.250 - (-0.320)) = 0.57 m
Let 'r1' represent the distance between 'q1' and 'q3', therefore, the distance between 'q2' and 'q3' is 0.57 - r1
By substitution, we have;
[tex]0 \ N= q_3 \cdot \left ( \dfrac{k \cdot (-4.10 \ nC) }{(0.57 - r_1 ) ^2} + \dfrac{k \cdot 2.20 \ nC }{(r_1)^2} \right)[/tex]
[tex]\therefore \dfrac{k \cdot 4.10 \ nC }{(0.57 - r_1 ) ^2} = \dfrac{k \cdot 2.20 \ nC }{(r_1)^2}[/tex]
From which we have;
[tex]\dfrac{4.10 \ nC }{(0.57 - r_1 ) ^2} = \dfrac{2.20 \ nC }{(r_1)^2}[/tex]
(r₁)²×4.10 = 2.20 × (0.57 - r₁)²
From the above equation, we have;
95,000·r₁²+ 125,400·r₁-35739 = 0
Solving, using a graphing calculator we get;
r₁ ≈ 0.241 or r₁ ≈ -1.561
Where, 'r₁', is measured from 'q₂', therefore, we have;
r₁ = 0.241 + (-0.320) ≈ -0.079 or r₁ = -1.561 + (-0.320) ≈ -1.881
Therefore, the charge 'q₃' can be placed at x = -0.079 or x = -1.881 for the ne force on it to be zero
If a bat exerts a 350N rightward force on a
baseball, how much force is the baseball exerting
on the bat?
Answer:
350N
Explanation:
According to Newton's 3rd law of motion, 2 objects that interact experience an equal and opposite force on each other. So if the bat exerts 350N of force on the baseball, the baseball must exert 350N on the bat.
This, in case you were interested, is what causes the recoil of the bat.
If 59.1 g of pure metal uses 890.9 j of energy to heat it from 26.1 c to 59.6 c, identify the metal
Answer: The metal is iron.
Explanation:
We have 59.1 grams of a given metal.
We need 890.9 joules of energy to heat the metal from 26.1°C to 59.6°C
First, we need to see the net increase in temperature, which is equal to the difference between the final temperature and the initial temperature.
ΔT = 59.6°C - 26.1°C = 33.5°C
Now we can find the specific heat, which is calculated as:
c = Ε/(ΔT*m)
Where:
E = energy given to the material = 890.9 J
m = mass of the material = 59.1 gr
ΔT = change in temperature = 33.5°C
Replacing these in the above equation we get:
c = 890.9 J/(33.5°C*59.1 gr) = 0.45 J/(gr*°C)
Now we need to look at a table of specific heats and see which metal has this specific heat.
We can see that iron is the best match, so we can assume that the metal is iron.
Which best describes how single-celled organisms are different from multi-celled organisms?
A.
A single-celled organism is more detailed and complex.
B.
A single-celled organism must perform all cellular functions.
С.
A single-celled organism must work with other cells to survive.
D.
A single-celled organism is specialized to perform one function.
Answer:
A single-called organism must perform all cellular functions on its own
Explanation:
i took the test
plzzzzzzz helppppppp
Answer:
6th amendment
Explanation:
the judge denied her request for a lawyer when she requested one
5. Which organisms are used to manufacture human insulin?
A. algae
B. amoebas
C. bacteria
D. protozoans
The organism that is used to manufacture human insulin is known as the bacteria E. Coli. Thus, the correct option for this question is C.
What is the function of human insulin?The function of human insulin is to maintain the blood sugar level by converting the active form of sugar which is glucose into the stored form of glycogen in order to maintain the blood sugar level.
In this modern era of science and technology, recombinant human insulin is mainly synthesized or produced with the help of organisms like E. Coli which is classified in the category of bacteria, and Saccharomyces cerevisiae which is classified in the category of unicellular fungus.
Therefore, the organism that is used to manufacture human insulin is known as the bacteria E. Coli. Thus, the correct option for this question is C.
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A surfer paddles to where the waves are sinusoidal with crests 14 m apart. He bobs a vertical distance 3.6 m from trough to crest, which takes 1.5 s. Find the wave speed, & describe the wave.
Answer:
v = 9.34 m/s
Explanation:
Given that,
The distance between crests, [tex]\lambda=14\ m[/tex]
The vertical distance from trough to crest = 3.6 m
Time taken, t = 1.5 s
The amplitude of wave = vertical distance from trough to crest /2
= 3.6/2
= 1.8 m
The speed of the wave is given by :
[tex]v=f\times \lambda\\\\=\dfrac{\lambda}{T}\\\\=\dfrac{14}{1.5}\\\\=9.34\ m/s[/tex]
So, the speed of the wave is 9.34 m/s.
Which of the following is part of the cycle of violence? (Select all that apply)
A. period of calm
B. violent episode
C. making up
D. tension-building