Answer:
Formation. Main-sequence stars, including the sun, form from clouds of dust and gas drawn together by gravity. ... The core that is left behind will be a white dwarf, a husk of a star in which no hydrogen fusion occurs. Smaller stars, such as red dwarfs, don't make it to the red giant state.
Explanation:
How does Earth's rotation affect ocean currents! It causes them to flow in a curved path. It causes them to flow from north to south It causes them to flow from east to west. None of the above
Answer:
But because the Earth rotates, circulating air is deflected. Instead of circulating in a straight pattern, the air deflects toward the right in the Northern Hemisphere and toward the left in the Southern Hemisphere, resulting in curved paths. This deflection is called the Coriolis effect.
The Coriolis effect describes how Earth's rotation steers winds and surface ocean currents. ... The Coriolis effect causes the path of a freely moving object to appear to curve. This is because Earth is rotating beneath the object. So even though the object's path is straight, it appears to curve.
Explanation:
An airplane has a mass of 12,000kg. If it is accelerating at 16m/sec2, what is its force?(round to the nearest whole number) NEED THIS ASAP
Answer:
[tex]F=1.92x10^5N[/tex]
Explanation:
Hello!
In this case, since the force exerted by an object with a certain mass an acceleration is:
[tex]F=m*a[/tex]
We can plug in the given mass of 12,000 kg and acceleration of 16 m/s^2 to obtain:
[tex]F=12,000kg*16m/s^2\\\\F=192,000kg*m/s^2\\\\F=1.92x10^5N[/tex]
Best regards!
Determine the molecular formula for a compound that has a molecular mass of 52.0 g/mole
and and is composed of 92.31% carbon and 7.69% hydrogen.
Answer:
C4H4
Explanation:
92.31% of 52.0 g/mol is 48.0012 g/mol
7.69% of 52.0 g/mol is is 3.9988 g/mol
Carbon has a gram-formula mass of about 12, which goes into 48.0012 about 4 times, so there should be 4 atoms of Carbon
Hydrogen has a gram-formula mass of about 1, which goes into 3.9988 about 4 times, so there should also be 4 atoms of hydrogen
For the balanced equation shown below, what would be the limiting reagent if 42.3 grams
of N2O5 were reacted with 9.18 grams of H2O?
N2O5+H2O---> 2HNO3
A. HNO3
B. H20
C. N205
Answer: A. HNO3
Explanation:
What mass of iron is produced from adding 80.0 g of iron(II) oxide (71.85 g/mol) to 20.0 g of magnesium metal? FeO (l) + Mg (l) ----------> Fe (l) + MgO (s) Identify the limiting reactant, mass of iron produced and the mass in grams of the excess reactant used in this reaction. Remember to report the correct number of significant figures and units where appropriate. You need to show work in order to receive credit. Zero points will be awarded if logical work/explanation is not given. You must show your work by typing it into the provided test box. I will not look to your scratch paper for work.
Answer:
46.0g of Iron are produced
Explanation:
Based on the chemical reaction:
FeO(l) + Mg(l) → Fe(l) + MgO(s)
1 mole of Iron (II) oxide reacts per mole of Mg to produce 1 mole of iron
To solve this question we need to convert each mass of reactant to moles using its respectives molar masses in order to find limitng reactant. Moles of limiting reactant = Moles of iron produced:
Moles FeO (Molar mass: 71.85g/mol):
80.0g * (1mol / 71.85g) = 1.11moles FeO
Moles Mg (Molar mass: 24.305g/mol)
20.0g * (1mol / 24.305g) = 0.823 moles Mg
As moles of Mg < Moles FeO, Mg is limiting reactant and the moles of Fe are 0.823 moles.
The mass of Iron produced is:
0.823 moles Fe * (55.845g/mol) =
46.0g of Iron are produced
Zn(s) + 2 HCl(aq) —> ZnCl2(aq)
+ H2(g)
If a scientist wanted to create 10L of hydrogen gas at RTP, what mass of HCl would they need to start with?
Answer:
First write the balanced equation for the reaction of HCl with Zn (NOTE: the previous answer did NOT do this and thus obtained an incorrect answer)
Zn + 2HCl ==> ZnCl2 + H2(g)
moles of H2 desired: PV = nRT
n = PV/RT = (1 atm)(10L)/(0.0821 Latm/Kmol)(298K)
n = 0.409 mole H2 desired
moles Zn needed:
0.409 moles H2 x 1 mole Zn/2 moles HCl = 0.204 moles Zn needed
mass Zn needed = 0.204 moles Zn x 65.4 g/mol = 13.4 g Zn needed (to 3 sig. figs.)
Explanation:people always get this wrong but i got you
write a chemical equation that represents baking soda (NaHCO3) reacts with hydrochloric acid (HCI) to produce sodium chloride, water and carbon dioxide
Answer:
NaHCO3 + HCl = NaCl + H2O + CO2
Explanation:
The total number of atoms of each element on either side of the equation must be equal.
Which of these statements is false?
A. All matter is made up of atoms.
B. Atoms are made up of protons,
neutrons, and electrons.
C. Atoms contain chemical bonds.
D. Atoms are the smallest particles of
elements.
Answer:
C is the false one atoms contain chemical bonds
Answer:
C. Atoms contain chemical bonds.
Reason:
Atoms don't have any chemical bonds. Molecules are the particles have chemical bonds.
Hello, this is a science task and it is due today I would really appreciate it if you guys can help me answer and explain what is the difference between expansion and contraction:) I will mark brainliest!
Answer:
Expansion: increase in size Contraction: decrease in size
Explanation:
The increase in size of an object on heating is called expansion where as the decrease in size of an object on cooling is called contraction.
compound composed of cations and anions the forces of attraction that bind oppositely charged ions together lowest whole-number ratio of ions in an ionic compound a depiction of the valence electrons as dots around the symbol for an element a mixture of two or more elements, at least one of which is a metal the attraction of the free-floating valence electrons for the positively charged metal ions ions of the halogen atoms the electron(s) in the highest occupied energy level of an atom the number of ions of opposite charge that surround each ion in a crystal Atoms in a compound tend to have the electron configuration of a noble gas. Shows the kinds and numbers of atoms in the smallest representative unit of a substance a. halide ions b. alloy c. octet rule d. formula unit e. electron dot structure f. ionic compound g. ionic bonds h. coordination number i. chemical formula j. valence electrons k. metallic bond
Answer:
compound composed of cations and anions the forces of attraction that bind oppositely charged ions together - ionic compound
lowest whole-number ratio of ions in an ionic compound - formula unit
a depiction of the valence electrons as dots around the symbol for an element - electron dot structure
a mixture of two or more elements, at least one of which is a metal - alloy
the attraction of the free-floating valence electrons for the positively charged metal - metallic bond
ions of the halogen atoms - halide ions
the electron(s) in the highest occupied energy level of an atom - valence electrons
the number of ions of opposite charge that surround each ion in a crystal - coordination number
Atoms in a compound tend to have the electron configuration of a noble gas - octet rule
Shows the kinds and numbers of atoms in the smallest representative unit - chemical formula
Explanation:
An ionic compound is composed of oppositely charged ions held together in a crystal lattice. The lowest whole-number ratio of ions in an ionic compound is known as the formula unit. The number of ions of opposite charge that surround each ion in a crystal is called the coordination number. Ions of the halogen atoms are negatively charged and are called halide ions
Elements are composed of atoms, the electron(s) in the highest occupied energy level of an atom are called valence electrons. In metals, the attraction of the free-floating valence electrons for the positively charged metal is called the metallic bond. For atoms of elements, a depiction of the valence electrons as dots around the symbol for an element is called the electron dot structure or Lewis structure.
A combination of elements may be a compound or an alloy. An alloy usually contains at least one metal. For compounds, the chemical formula Shows the kinds and numbers of atoms in the smallest representative unit. Atoms form compounds because atoms in a compound tend to have the electron configuration of a noble gas this is the octet rule.
The correct match of the given statement are 1 - f. ionic compound, 2- d. formula unit, 3 - e. electron dot structure, 4- b. alloy, 5- k. metallic bond, 6- a. halide ions, 7- j. valence electrons, 8- h. coordination number, 9 - c. octet rule, 10- i. chemical formula.
Ionic compounds are made up of oppositely charged ions that are kept together in a crystal lattice. The formula unit is the lowest whole-number ratio of ions in an ionic compound.
The coordination number is the number of ions with opposite charges that surround each ion in a crystal. Halide ions are halogen atom ions that are negatively charged.
Elements are made up of atoms, and the electron(s) in the atom's highest occupied energy level are known as valence electrons. The metallic bond refers to the attraction of free-floating valence electrons to positively charged metals in metals.
The electron dot structure or Lewis structure is a representation of the valence electrons as dots around the symbol for an element for atoms.
A compound or an alloy is a mixture of components. A metal is frequently present in an alloy.
The chemical formula is used for compounds. The types and numbers of atoms in the smallest representative unit are displayed.
The octet rule states that atoms in a compound tend to have the electron configuration of a noble gas.
Therefore, the correct matches are: 1 - f. ionic compound, 2- d. formula unit, 3 - e. electron dot structure, 4- b. alloy, 5- k. metallic bond, 6- a. halide ions, 7- j. valence electrons, 8- h. coordination number, 9 - c. octet rule, 10- i. chemical formula.
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The given question is incomplete, so the most probable complete question is,
Match the correct statement with their appropriate terms:
Compound composed of cations and anions, the forces of attraction that bind oppositely charged ions together.Lowest whole-number ratio of ions in an ionic compound.A depiction of the valence electrons as dots around the symbol for an element.A mixture of two or more elements, at least one of which is a metal.The attraction of the free-floating valence electrons for the positively charged metal.Ions of the halogen atoms.The electron(s) in the highest occupied energy level of an atom.The number of ions of opposite charge that surround each ion in a crystal.Atoms in a compound tend to have the electron configuration of a noble gas.Shows the kinds and numbers of atoms in the smallest representative unit.How many moles are in 1.51x10^26 atoms of xenon (Xe)? Please and thank you :)!!
251 mol Xe
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 1.51 × 10²⁶ atoms Xe
[Solve] moles Xe
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
[DA] Set up: [tex]\displaystyle 1.51 \cdot 10^{26} \ atoms \ Xe(\frac{1 \ mol \ Xe}{6.022 \cdot 10^{23} \ atoms \ Xe})[/tex][DA] Multiply/Divide [Cancel out units]: [tex]\displaystyle 250.747 \ mol \ Xe[/tex]Step 4: Check
Follow sig fig rule and round. We are given 3 sig figs.
250.747 mol Xe ≈ 251 mol Xe
What is delta Gº for the following reaction at 25 °C?
CO(g) + 2 H2(g) = CH OH(9)
Ky = 2.1 x 10-4
Answer:
21 kJ/mol
Explanation:
Step 1: Given and required data
Temperature (T): 25 °C (298 K)Equilibrium constant (Kc): 2.1 × 10⁻⁴Ideal gas constant (R): 8.314 J/K.molStep 2: Write the balanced equation at equilibrium
CO(g) + 2 H₂(g) ⇄ CH₃OH(g)
Step 3: Calculate the standard Gibbs free energy of the reaction (ΔG°)
We will use the following expression.
ΔG° = - R × T × ln Kc
ΔG° = - (8.314 J/K.mol) × 298 K × ln 2.1 × 10⁻⁴ = 2.1 × 10⁴ J/mol = 21 kJ/mol
help asap pls,
find the percent composition
Explanation:
1. Pb(CO3)2
Element Number Mass Percet Composition
Oxygen 6 16.00 29.34%
Carbon 2 12.01 7.34%
Lead 1 207.21 63.32%
2. Ga(OH)3
Element Number Mass Percet Composition
Hydrogen 3 1.0079 2.50%
Oxygen. 3 16.00 39.75%
Gallium 1 69.72 57.74%
3. P4O10
Element Number Mass Percet Composition
Oxygen. 10 16.00. 56.36%
Phosphorus. 4 30.97 43.64%
4. Ca3P2
Element Number Mass Percet Composition
Phosphorus 2 30.97 34.00%
Calcium. 3 40.08 66.00%
5. Ti(NO3)3
Element Number Mass Percet Composition
Oxygen. 9 16.00 61.56%
Titanium. 1 47.87 20.47%
Nitrogen. 3 14.01 17.97%
Hail is falling down from the sky at 50 miles per hour. Is this an example of speed,
velocity or acceleration?
Explanation:
tgggghhhhijyyhhjjjjjjjj
Please help :) hope you have a good day
Have a wonderful day :) thanks for the points
(b) Why must acidic gases be treated before they are released into the atmosphere?
Answer:
because they react with other gases of atmosphere and pollute the environment
How much would the temperature of a 34.2 g sample of argon gas decrease when 2.8 kJ of heat is removed?
Your answer should be in °C.
Answer:
8.90
Explanation:
because I calculated it
Which of the following particles has the smallest
mass?
A) electron
C) neutron
B) hydrogen atom
D) proton
Answer:
AN ELECTRON HAS THE SMALLEST MASS!
Answer:
A) electron
good luck, i hope this helps :)
I forgot, does odor have volume?
Answer: oder has mass
Explanation:
b. If you have 50 grams of Molybdenum-99, how many grams will remain
after 11 days?
Answer:
6.25gm
half life is 66hrs 11 days is 24*11 then take that and divide by 66 to find out how many time it will have halved and half 50 by that many times
Explanation:
If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.
Molybdenum-99 follows first-order decay.
What is first-order decay?First-order decay means that for a population of atoms (e.g. radioactive), molecules, or anything else, a constant fraction/unit time is converted to something else.
The half-life (th) of Mo-99 is 66 h.
We will find its rate constant (k) using the following expression.
k = ln2 / th = ln2 / 66 h = 0.011 h⁻¹
Next, we will convert 11 days to hours, knowing that 1 day = 24 h.
11 d × 24 h/1 d = 264 h
If we start with 50 g of Mo-99, we can calculate the remaining mass after 264 h using the following expression.
[tex][Mo] = [Mo]_0 \times e ^{-k \times t} }\\\\[Mo] = 50g \times e ^{-0.011 h^{-1} \times 264 h} } = 2.7 g[/tex]
where,
[Mo] is the final amount of Mo-99.[Mo]₀ is the initial amount of Mo-99.t is the elapsed time.If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.
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1. Mixing Water at Two Temperatures
a. One flask contains 150.0 g water at 20.0 °C. A second flask contains 350.0 g water at 95.0 °C. If the two water samples are mixed, what will the final temperature of the water be?
-Assume that the density of water it 1.000 g/cm^3
-The specific heat capacity for water is 4.184 J/g °C
Answer:
[tex]T_f=72.5\°C[/tex]
Explanation:
Hello!
In this case, since this a problem in which the cold water is heated by the hot water, we can write:
[tex]Q_{hot}+Q_{cold}=0[/tex]
Thus, by plugging in the mass, specific heat and temperatures, we obtain:
[tex]m_{hot}C_{hot}(T_f-T_{hot})+m_{cold}C_{cold}(T_f-T_{cold})=0[/tex]
Now, we can also write:
[tex]m_{hot}(T_f-T_{hot})+m_{cold}(T_f-T_{cold})=0[/tex]
Then, after applying some algebra, it is possible to obtain:
[tex]T_f=\frac{m_{hot}T_{hot}+m_{cold}T_{cold}}{m_{hot}+m_{cold}}[/tex]
If we plug in, we obtain:
[tex]T_f=\frac{350.0g*95.0\°C+150.0g*20.0\°C}{350.0g+150.0g}[/tex]
[tex]T_f=72.5\°C[/tex]
Best regards!
A certain substance has a heat of vaporization of 64.08 kJ/mol. At what Kelvin temperature will the vapor pressure be 6.50 times higher than it was at 355 K?
Answer:
[tex]T_2 =388.50K[/tex]
Explanation:
Given
[tex]p_1 = ??[/tex] -- Initial vapour pressure
[tex]p_2 = 6.50p_1[/tex] --- Final vapour pressure
[tex]T_1 = 355K[/tex] ---- Initial temperature
[tex]T_2 = ??[/tex] --- Final temperature
[tex]\triangle _{vap}H = 64.08kJmol[/tex] --- Enthalpy of vaporization
Required
Calculate T2
To do this, we make use of Clausius-Clapeyron equation.
Which states that:
[tex]ln(\frac{p_2}{p_1}) = \frac{\triangle _{vap}H}{R}(\frac{1}{T_1} - \frac{1}{T_2})[/tex]
Where:
[tex]R = 8.314 J.K^{-1}mol^{-1}[/tex] --- Universal Gas constant
[tex]\triangle _{vap}H = 64.08kJmol[/tex]
[tex]\triangle _{vap}H = 64080\ kJmol[/tex]
[tex]ln(\frac{p_2}{p_1}) = \frac{\triangle _{vap}H}{R}(\frac{1}{T_1} - \frac{1}{T_2})[/tex] becomes
[tex]ln(\frac{6.50p_1}{p_1}) = \frac{64080}{8.314}(\frac{1}{355} - \frac{1}{T_2})[/tex]
[tex]ln(\frac{6.50p_1}{p_1}) = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]
[tex]ln(6.50) = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]
[tex]1.872 = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]
Take LCM
[tex]1.872 = 7707.48(\frac{T_2 - 355}{355T_2})[/tex]
[tex]1.872 = 7707.48*\frac{T_2 - 355}{355T_2}[/tex]
[tex]1.872 = \frac{7707.48*(T_2 - 355)}{355T_2}[/tex]
Cross Multiply
[tex]355T_2*1.872 = 7707.48*(T_2 - 355)[/tex]
[tex]664.56T_2 = 7707.48T_2 - 2736155.4[/tex]
Collect Like Terms
[tex]664.56T_2 - 7707.48T_2 =- 2736155.4[/tex]
[tex]-7042.92T_2 =- 2736155.4[/tex]
Make T2 the subject
[tex]T_2 =\frac{- 2736155.4}{-7042.92}[/tex]
[tex]T_2 =388.497299416[/tex]
[tex]T_2 =388.50K[/tex]
The final temperature is 388.50K
The temperature at which the vapor pressure will be 6.50 times higher than it was at 355K is 389 K
The Clausius-Clapeyron Equation is widely used for the determination of the vapor pressure of another temperature, provided we know the vapor pressure at a certain temperature as well as the heat of vaporization.
Given that:
the heat of vaporization [tex]\mathbf{\Delta H_{vap} = 64.08 \ kJ/mol = 64.08 \times 10^3 J/mol}[/tex] the initial temperature T₁ = 355 Kthe final temperature T₂ = ???if the pressure at T₁ = P₁then, the pressure at T₂ = 6.5P₁the universal gas constant = 8.314 J/K/molBy using the Clausius-Clayperon Equation:
[tex]\mathbf{In \Big( \dfrac{P_2}{P_1} \Big) = \dfrac{\Delta H_{vap}}{R} \Big (\dfrac{1}{T_1} - \dfrac{1}{T_2} \Big) }[/tex]
[tex]\mathbf{In \Big( \dfrac{6.5P_1}{P_1} \Big) = \dfrac{64.08 \times 10^3 }{8.314} \Big (\dfrac{1}{355} - \dfrac{1}{T_2} \Big) }[/tex]
[tex]\mathbf{In(6.5)=7707.48 \Big (\dfrac{1}{355} - \dfrac{1}{T_2} \Big) }[/tex]
[tex]\mathbf{1.872 =21.71 - \dfrac{7707.48}{T_2} }[/tex]
[tex]\mathbf{\dfrac{7707.48}{T_2} = 21.71- 1.872 }[/tex]
[tex]\mathbf{\dfrac{7707.48}{T_2} = 19.838 }[/tex]
[tex]\mathbf{T_2= \dfrac{7707.48}{19.838} }[/tex]
[tex]\mathbf{{T_2}=388.521 \ K }[/tex]
T₂ ≅ 389 K
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3.Which of these is NOT part of the cell theory? * "
all living things are made of cells
Ocells come only from other cells
cells are the smallest living unit of an organism
O all living things have blood cells
Answer:
Cells are the smallest living unit of an organism
Answer:
all living things living things have blood cells
Explanation:
this is because robert hooke did not make this apart of the theory
study the image wich shows an air mass moving into a region wich type of weather will this region most likely experience due to the incoming air mass
Answer:
766ijn
Explanation:
hovibibbunununububububyhybyybybnu
A weather balloon contains 394 L of hydrogen gas at STP. How many moles of hydrogen are present?
Answer:
PV=nRT
STP is 100kPa and 273.15K
PV/RT=n
n=17.3moles
Explanation:
why is seawater a better conductor of electricity than freshwater?
Answer:
please refer to the attachment above;)
Answer:
Because it contains Na+ and Cl- ions, Which are conductors of electricity
Explanation:
2. What is the percent composition of Mg(IO3)2?
Answer:
Mass percentage 6.4967
Explanation:
I had some study notes
According to this video, how do scientists use data to study/monitor earthquakes and tsunamis?
Answer:
ewan ko po
Explanation:
sana makatulong
10. Imagine that the unknown solution contains aqueous ammonium sulfate, which is commonly used in fertilizer. For the precipitation of barium sulfate after mixing aqueous ammonium sulfate solution and barium chloride solution (the reactants), write the (1) balanced molecular equation, (2) the complete ionic equation, (3) the net ionic equation AND identify the spectator ions, if any.
Answer:
(1) (NH₄)₂SO₄(aq) + BaCl₂(aq) ⇒ BaSO₄(s) + 2 NH₄Cl(aq)
(2) 2 NH₄⁺(aq) + SO₄²⁻(aq) + Ba²⁺(aq) + 2 Cl⁻(aq) ⇒ BaSO₄(s) + 2 NH₄⁺(aq) + 2 Cl⁻(aq)
(3) SO₄²⁻(aq) + Ba²⁺(aq) ⇒ BaSO₄(s)
(4) NH₄⁺ and Cl⁻
Explanation:
(1) Let's consider the molecular equation that occurs after mixing aqueous ammonium sulfate solution and barium chloride solution. This is a double displacement reaction.
(NH₄)₂SO₄(aq) + BaCl₂(aq) ⇒ BaSO₄(s) + 2 NH₄Cl(aq)
(2) The complete ionic equation includes all the ions and insoluble species.
2 NH₄⁺(aq) + SO₄²⁻(aq) + Ba²⁺(aq) + 2 Cl⁻(aq) ⇒ BaSO₄(s) + 2 NH₄⁺(aq) + 2 Cl⁻(aq)
(3) The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the insoluble species.
SO₄²⁻(aq) + Ba²⁺(aq) ⇒ BaSO₄(s)
(4) The spectator ions are NH₄⁺ and Cl⁻.
The process utilized to save an organism's DNA for use in the future is:
A tissue biopsy
B DNA
C clone
D genetic preservation
Answer:
I believe it's D!
Explanation:
B is what is being saved, C is a potential creation of, A is a method.