Answers
Answer:
B) 65
Step-by-step explanation:
Plug in the corresponding numbers to the corresponding variables:
w = -4 ; v = 5 ; u = 2
4w² - v + 3u
4(-4²) - (5) + 3(2)
Remember to follow PEMDAS.
PEMDAS =
Parenthesis
Exponents
Multiplications
Division
Addition
Subtraction
& is the order of operation.
First, solve the power:
4(-4²) - (5) + 3(2)
(-4²) = (-4)(-4) = 16
Next, multiply:
4(16) - 5 + 3(2)
64 - 5 + 6
Finally, combine the terms:
(64 + 6) - 5
70 - 5
65
B) 65 is your answer.
~
Related Questions
one more lol then she is done (my friend) lol
Which of the following correctly uses absolute value to show the distance between –60 and 11? |–60 – 11| = |–71| = –71 units |–60 + 11| = |–49| = 49 units |–60 + 11| = |–49| = –49 units |–60 – 11| = |–71| = 71 units
Answers
Answer:
|–60 – 11| = |–71| = 71 units
Step-by-step explanation:
Subtract the two points and take the absolute value
(-60 - 11)
The absolute value
| -60 -11| =
|-71|
71
Answer: D
Step-by-step explanation:
Absolute value turns the -60 into 60
Hope this helps!
how many are 15 x 15 ?
Answers
Answer:
225
Step-by-step explanation:
Answer:
225
Step-by-step explanation:
Use the substitution x = et to transform the given Cauchy-Euler equation to a differential equation with constant coefficients. Solve the original equation by solving the new equation
x2y'' + 9xy' - 20y = 0
Answers
Answer:
[tex]\boxed{\sf \ \ \ ax^2+bx^{-10} \ \ \ }[/tex]
Step-by-step explanation:
Hello,
let's follow the advise and proceed with the substitution
first estimate y'(x) and y''(x) in function of y'(t), y''(t) and t
[tex]x(t)=e^t\\\dfrac{dx}{dt}=e^t\\y'(t)=\dfrac{dy}{dt}=\dfrac{dy}{dx}\dfrac{dx}{dt}=e^ty'(x)<=>y'(x)=e^{-t}y'(t)\\y''(x)=\dfrac{d^2y}{dx^2}=\dfrac{d}{dx}(e^{-t}\dfrac{dy}{dt})=-e^{-t}\dfrac{dt}{dx}\dfrac{dy}{dt}+e^{-t}\dfrac{d}{dx}(\dfrac{dy}{dt})\\=-e^{-t}e^{-t}\dfrac{dy}{dt}+e^{-t}\dfrac{d^2y}{dt^2}\dfrac{dt}{dx}=-e^{-2t}\dfrac{dy}{dt}+e^{-t}\dfrac{d^2y}{dt^2}e^{-t}\\=e^{-2t}(\dfrac{d^2y}{dt^2}-\dfrac{dy}{dt})[/tex]
Now we can substitute in the equation
[tex]x^2y''(x)+9xy'(x)-20y(x)=0\\<=> e^{2t}[ \ e^{-2t}(\dfrac{d^2y}{dt^2}-\dfrac{dy}{dt}) \ ] + 9e^t [ \ e^{-t}\dfrac{dy}{dt} \ ] -20y=0\\<=> \dfrac{d^2y}{dt^2}-\dfrac{dy}{dt}+ 9\dfrac{dy}{dt}-20y=0\\<=> \dfrac{d^2y}{dt^2}+ 8\dfrac{dy}{dt}-20y=0\\[/tex]
so the new equation is
[tex]y''(t)+ 8y'(t)-20y(t)=0[/tex]
the auxiliary equation is
[tex]x^2+8x-20=0\\<=> x^2-2x+10x-20=0\\<=>x(x-2)+10(x-2)=0\\<=>(x+10)(x-2)=0\\<=> x=-10\text{ or }x=2[/tex]
so the solutions of the new equation are
[tex]y(t)=ae^{2t}+be^{-10t}[/tex]
with a and b real
as
[tex]x(t)=e^t\\<=> t(x)=ln(x)[/tex]
[tex]y(x)=ae^{2ln(x)}+be^{-10ln(x)}=ax^2+bx^{-10}[/tex]
hope this helps
do not hesitate if you have any questions
Which of the following functions best describe this graph ?
Answers
Answer:
D.
Step-by-step explanation:
y - int is value of y when x = 0,
We have y int = 1,
D. x = 0, y = (0 - 1)(0 - 1) = 1
x-int = 1,
D. y = 0, So, answer is D.
Answer:
D
Step-by-step explanation:
First, note that the graph "bounces" off the x-axis at x=1. This is telling us two things: (1) the graph has a zero at x=1 and (2), since the graph bounces, it has a factor with a multiplicity of 2. Since it is a quadratic, the only way that it can have a multiplicity of two is if the function is a perfect square trinomial. In other words, it can be factored into (x-a)^2.
A, B, and C are not perfect square trinomials. They cannot be factored into the form (x-a)^2.
D is (x-1)(x-1) which equals (x-1)^2, a perfect square trinomial. Its zero is also at x=1. D is correct.
How do I solve this problem?
Answers
Answer:
It would take 1 more mile if he took route Street A and then Street B rather than just Street C.
Step-by-step explanation:
Pythagorean Theorem: a² + b² = c²
We use the Pythagorean Theorem to find the length of Street C:
2² + 1.5² = c²
c = √6.25
c = 2.5
Now we find how much longer route A and B is compared to C:
3.5 - (2 + 1.5) = 3.5 - 2.5 = 1
Consider the following information. SSTR = 6750 H0: μ1 = μ2 = μ3 = μ4 SSE = 8000 Ha: At least one mean is different If n = 5, the mean square due to error (MSE) equals a. 1687.5. b. 400. c. 500. d. 2250.
Answers
Answer:
d. 2250.
Step-by-step explanation:
The calculation of mean square due to error (MSE) is shown below:-
Since there are four treatments i.e H0: μ1 = μ2 = μ3 = μ4
And, the SSTR is 6,750
Based on this, the mean square due to error is
= [tex]\frac{SSTR}{n-1}[/tex]
[tex]= \frac{6,750}{4-1}[/tex]
= [tex]\frac{6,750}{3}[/tex]
= 2,250
Hence, the mean square due to error is 2,250
Therefore the correct option is d.
All the other information is not relevant. Hence ignored it
What is the value of x?
10
2x
Answers
Answer:
The only way of getting to 10 using 2x it should mean that x = 5
2 * 5 = 10
Domain and range of T
Answers
Answer:
Let's list out the points that belong to T. They are T{(-1, -4), (2, 2), (2, -3)}.
The domain is all of the x values. Therefore the domain is {-1, 2}.
The range is all of the y values. Therefore the range is {-4, -3, 2}.
We don't use ( ) or [ ] because T is a discrete relation.
Express it in slope-Intercept form
Answers
Answer:
Y=1/4x-4
Explanation: The y intercept is -4 that is your B. Using the rise over sun method the line rises 1 and goes to the right 4 making the slope 1/4 or .25
pls help help help help
Answers
Answer:
D
Step-by-step explanation:
We can plug in the numbers (15, 23, 25, 38, 53) into the equation for x, and see if we get the values given for the number of hits (4, 12, 14, 27, 47)
The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 1100 miles. What warranty should the company use if they want 96% of the tires to outlast the warranty? Round the answer to the nearest whole number
Answers
Answer:
61,925 miles
Step-by-step explanation:
Given :
The p-value of the tires to outlast the were warranty were given in the the question as = 0.96
Checking the normal distribution table, The probability that corresponds to 0.96
from the Normal distribution table is 1.75.
Mean : 'μ'= 60000 miles
Standard deviation : σ=1100
The formula for z-score is given by
: z= (x-μ)/σ
1.75=(x-60000)/1100
1925=x-60000
x=61925
Therefore, the tread life of tire should be 61,925 miles if they want 96% of the tires to outlast the warranty.
does 6(x + 5) = 6x + 11 , have on solution, infinitely many solutions, or no solutions?
Answers
Answer:
no solution
Step-by-step explanation:
hello
[tex]6(x+5)=6x+11\\<=> 6x+30=6x+11\\<=> 30=11[/tex]
this is always false so there is no solution
Let's to expand this equation:
[tex]6(x+5) = 6x+11\\6x + 6\times 5 = 6x + 11\\6x + 30 = 6x + 11[/tex]
Perceive that in two members of equations, we have "6x", so we can to eliminate it. But, when we make it, we have this situation:
[tex]6x + 30 = 6x + 11\\30 = 11[/tex]
How [tex]30 \neq 11[/tex] this is a absurd. Therefore, this equation don't have solutions.
V(x, y, z) = 5x2 − 3xy + xyz (a) Find the rate of change of the potential at P(6, 6, 5) in the direction of the vector v = i + j − k.
Answers
Answer:
[tex]D_{\vec{v}}V(6,6,5)=48[/tex]
Step-by-step explanation:
You have the following potential function:
[tex]V(x,y,z)=5x^2-3xy+xyz[/tex] (1)
To find the rate of change of the potential at the point P(6,6,5) in the direction of v = i + j - k, you use the following formula:
[tex]D_{\vec{v}}V(x,y,z)=\bigtriangledown V(x,y,z)\cdot \vec{v}[/tex] (2)
First, you calculate the gradient of V:
[tex]\bigtriangledown V(x,y,z)=\frac{\partial}{\partial x}V(x,y,z)\hat{i}+\frac{\partial}{\partial y}V(x,y,z)\hat{i}+\frac{\partial}{\partial z}V(x,y,z)\hat{i}\\\\\bigtriangledown V(x,y,z)=(10x-3y+yz)\hat{i}+(-3x+xz)\hat{j}+(xy)\hat{k}\\\\\bigtriangledown V(6,6,5)=(10(6)-3(6)+(6)(5))\hat{i}+(-3(6)+(6)(5))\hat{j}+((6)(6))\hat{k}\\\\\bigtriangledown V(6,6,5)=72\hat{i}+12\hat{j}+36\hat{k}[/tex]
Next, you replace in the equation (2):
[tex]D_{\vec{v}}V(6,6,5)=(72\hat{i}+12\hat{j}+36\hat{k})\cdot(\hat{i}+\hat{j}-\hat{k})\\\\D_{\vec{v}}V(6,6,5)=48[/tex]
Then, the rate of change of the potential at the point P(6,6,5) in the direction of v, is 48.
Malik is buying a guinea pig. The guinea pig comes with a cage and food bowls for $ 125.00 . The expenses for feeding and caring for the guinea pig are $ 18.00 each month. How much will it cost Malik to buy and care for the guinea pig for one year?
Answers
Answer:
$341.00
Step-by-step explanation:
"$ 18.00 each month."
$18.00*$12.00=$216.00
$216.00+$125.00=$341.00
hope this helpes
be sure to give brainliest
Bob bought some land costing $15,540. Today, that same land is valued at $45,117. How long has Bob owned this land if the price of land has been increasing at 5 percent per year
Answers
Answer:
21.84 years
Step-by-step explanation:
From the compound interest formula;
F = P(1+r)^t .......1
ln(F/P) = tln(1+r)
t = ln(F/P)/ln(1+r) .......2
Where;
F = Final value = $45,117
P = Initial value = $15,540
r = rate = 5% = 0.05
t = time
Substituting the values into equation 2;
t = ln(45117/15540)/ln(1.05)
t = 21.84542292124 years
t = 21.84 years
It will take Bob 21.84 years
The function C(x) = 200x + 240 gives the cost for a college to offer x sections of an introductory class in CPR. The function R(x) = 280x gives the amount of revenue the college brings in when offering x sections of CPR. Find the point where the cost equals the revenue by graphing each function on the same coordinate system.
Answers
Answer:
C(3) = R(3) = 840
Step-by-step explanation:
See the attached for a graph.
Please help me it’s due tomorrow and I really need help
Answers
Answer:
5 [tex]\frac{1}{3}[/tex], 10 [tex]\frac{2}{3}[/tex]
Step-by-step explanation:
There is a common ratio r between consecutive terms, that is
[tex]\frac{2}{3}[/tex] ÷ [tex]\frac{1}{3}[/tex] = 1 [tex]\frac{1}{3}[/tex] ÷ [tex]\frac{2}{3}[/tex] = 2 [tex]\frac{2}{3}[/tex] ÷ 1 [tex]\frac{1}{3}[/tex] = 2
Thus to obtain a term in the sequence multiply the previous term by 2, thus
a₅ = [tex]\frac{8}{3}[/tex] × 2 = [tex]\frac{16}{3}[/tex] = 5 [tex]\frac{1}{3}[/tex]
a₆ = [tex]\frac{16}{3}[/tex] × 2 = [tex]\frac{32}{3}[/tex] = 10 [tex]\frac{2}{3}[/tex]
which is bigger 1 or
[tex] \frac{19}{9} [/tex]
Answers
Answer:
19/9 because it equals to 2.111.. Which is greater than 1
Step-by-step explanation:
By the way if it's right can i get brainliest.
Answer:
1 < 19/9
Step-by-step explanation:
1 vs 19/9
Rewriting 19/9 as 9/9 + 9/9+ 1/9
1 vs 1+1 +1/9
1 vs 2 1/9
1 < 19/9
Rationalize the denominator and simplify
Answers
Answer:
sqrt(70)/7
Step-by-step explanation:
sqrt(10/7)
sqrt ( a/b) = sqrt(a)/ sqrt(b)
sqrt(10) / sqrt(7)
But we don't leave a sqrt in the denominator, so multiply by sqrt(7) /sqrt(7)
sqrt(10) /sqrt(7) * sqrt(7) / sqrt(7)
sqrt(70)/ sqrt(49)
sqrt(70)/7
A rectangular box has length 2 inches, width 8 inches, and a height of 10 inches. Find the angle between the diagonal of the box and the diagonal of its base. The angle should be measured in radians.
Answers
Answer:
a) diagonal box = 12.9 in
b) diagonal base = 8.2 in
Step-by-step explanation:
w = 8 in
h = 10 in
L = 2 in
required:
a) diagonal of the box
b) diagonal of its base
referring into the attached image
a) the diagonal of the box = sqrt ( w² + h² + L²)
diagonal box = sqrt (8² + 10² + 2²)
diagonal box = 12.9 in
b) diagonal of its base = sqrt ( w² + L²)
diagonal base = sqrt ( 8² + 2²)
diagonal base = 8.2 in
Tickets to a baseball game can be ordered online for a set price per ticket plus a $5.59 service fee. The total cost in dollars for ordering 5 tickets is $108.09. Which linear function represents c, the total cost, when x tickets are ordered
Answers
Answer:
c = 20.5x + 5.59
Step-by-step explanation:
c = mx + b
c = mx + 5.59
108.09 = m(5) + 5.59
5m = 102.5
m = 20.5
c = 20.5x + 5.59
Joan conducted a study to see how common binge drinking is on her college campus. She defined "frequent binge drinking" as having five or more drinks in a row three or more times in the past two weeks. Out of 593 students who replied to her survey, 64 fit this criterion. Joan wants to construct a significance test for her data. She finds that the proportion of binge drinkers nationally is 13.1%. The z statistic for this data is __________.
Answers
Answer:
z = -1.66
Step-by-step explanation:
Z-statistic:
[tex]z = \frac{X - p}{s}[/tex]
In which X is the found proportion.
p is the mean proportion.
[tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex] is the standard error for the data.
Out of 593 students who replied to her survey, 64 fit this criterion.
This means that [tex]X = \frac{64}{593} = 0.108[/tex]
She finds that the proportion of binge drinkers nationally is 13.1%.
This means that [tex]p = 0.131[/tex]
Also
[tex]s = \sqrt{\frac{0.131*0.869}{593}} = 0.014[/tex]
The z statistic for this data is
[tex]z = \frac{X - p}{s}[/tex]
[tex]z = \frac{0.108 - 0.131}{0.014}[/tex]
[tex]z = -1.66[/tex]
Evaluate: .25 (1.2 x 3 - 1.25) + 3.45
Answers
The order to us solve is:
ParenthesesMultiplicationSum and subtractionLet's go:
[tex]25(1.2\times 3 - 1.25) + 3.45\\25(3.6-1.25)+3.45\\25\times 2.35 + 3.45\\58.75+3.45\\62.2[/tex]
Therefore, the result is 62.2.
Answer:
4.0375
Step-by-step explanation:
.25(3.6-1.25)+3.45
.25(2.35)+3.45
.5875+3.45
4.0375
HOPE THIS HELPS:)
What is the solution to this system of linear equations? 3x – 2y = 14 5x + y = 32
Answers
Answer:
work is shown and pictured
Answer:
Answer B. (6, 2)
Hope it works!
Step-by-step explanation:
Fizzy Waters promotes their alkaline water product for everyone on the basis that alkaline water is good for health as it neutralizes acids produced in the body. They boast having a mean alkalinity level of 50 mg/liter. Alkaline water has a higher pH level than regular drinking water and Fizzy Waters claims that its higher Hydrogen content provides better hydration than regular water. To test their claim, you contact Fizzy Waters and they allow you to collect samples from their manufacturing plant to test for yourself. You collect 100 random samples of their alkaline water and find that the mean and standard deviation are y = 32.2mg/liter and 14.4mg/liter. With 99% confidence, is there enough evidence to support their claim that the population mean exceeds 50 mg/liter?
Answers
Answer:
The mean of 50 mg/liter is not inside the 99% interval, so there is not enough evidence to support their claim.
Step-by-step explanation:
First we need to find the z-value for a confidence of 99%
The value of alpha for a 99% confidence is:
[tex]1-\alpha/2 = 0.99[/tex]
[tex]\alpha/2 = 0.01[/tex]
[tex]\alpha = 0.005[/tex]
Looking in the z-table, we have z = 2.575.
Now we can find the standard error of the mean:
[tex]\sigma_{\bar{x} }= s_x/\sqrt{n}[/tex]
[tex]\sigma_{\bar{x} }= 14.4/\sqrt{100}[/tex]
[tex]\sigma_{\bar{x} }=1.44[/tex]
Finding the 99% confidence interval, we have:
[tex]99\%\ interval = (\bar{x} - z\sigma_{\bar{x}}, \bar{x} + z\sigma_{\bar{x}})[/tex]
[tex]99\%\ interval = (32.2 - 2.575*1.44, 32.2 + 2.575*1.44)[/tex]
[tex]99\%\ interval = (28.492, 35.908)[/tex]
The mean of 50 mg/liter is not inside the 99% interval, so there is not enough evidence to support their claim.
A jar of sweet contains 5 yellow sweets, 4 red sweets, 8 green sweets, 4 orange sweets and 3 white sweets. Ola chose a sweet at random, what is the possibility that she will pick either a yellow or orange sweet?
Answers
Answer:
9/24 or 37.5%
hope this helps :)
Hi,
first thing you must do with a probability problem is to count how many thing you have in your universe.
Here we are dealing with sweets. So let's count : 5 +4+8+4+3 = 24
and there is 5 yellow so probability to pick up a yellow is 5/24
and there is 4 orange so probabilitu to pick up a orange is 4/24
To say : Ola will pick orange or yellow mean if she pick either one of the two sort is good. So you add the proba of each : 5/24 +4/24 = 9/24
and then you must reduce if you can : 9/24 = 3*3 /8*3 = 3/8
So the probability that Ola pick a yellow or orange sweet is 3/8 = 0.375
Elliot’s school has 24 classrooms. Each classroom has seats for 26 students. What is the maximum number of students the school can seat? Multiply to find the answer.
Answers
Answer:
24*26= 624 students
hope this helps!
Answer:
624 seats
Step-by-step explanation:
Total classrooms = 24
Each classroom has seats = 26
Total Number of seats = 24*26
=> 624 seats
Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval. Limit Interval lim ||Δ|| → 0 n (4ci + 11) i = 1 Δxi [−8, 6]
Answers
Answer:
The corresponding definite integral may be written as
[tex]\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x[/tex]
The answer of the above definite integral is
[tex]\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98[/tex]
Step-by-step explanation:
The given limit interval is
[tex]\lim_{||\Delta|| \to 0} \sum\limits_{i=1}^n (4c_i + 11) \Delta x_i[/tex]
[tex][a, b] = [-8, 6][/tex]
The corresponding definite integral may be written as
[tex]\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x[/tex]
[tex]\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x[/tex]
Bonus:
The definite integral may be solved as
[tex]\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x \\\\\frac{4x^2}{2} + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\2x^2 + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\ 2(6^2 -(-8)^2 ) + 11(6 - (-8) \\\\2(36 - 64 ) + 11(6 + 8) \\\\2(-28 ) + 11(14) \\\\-56 +154 \\\\98[/tex]
Therefore, the answer to the integral is
[tex]\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98[/tex]
The length of a rectangle is 11 yds more than twice the width, and the area of the rectangle is 63 yd ^2, find the dimentions of the rectangle
Answers
Answer:
The length is 18 ydThe width is 3.5 ydStep-by-step explanation:
Area of a rectangle = l × w
where l is the length
w is the width
length of a rectangle is 11 yds more than twice the width is written as
l = 11 + 2w
Area = 63 yd²
(11+2w)w = 63
2w² + 11w - 63 = 0
Solve the quadratic equation
( w + 9) ( 2x - 7) = 0
w = - 9 w = 7/2 or 3.5
Since width is always positive w is 3.5 yd
l = 11 + 2(3.5)
l = 11 + 7
l = 18 yd
The length is 18 yd
The length is 18 ydThe width is 3.5 yd
Hope this helps you
6th grade math help me please :))
Answers
Answer:
b) a coefficientd) a constant1, 2, 4Step-by-step explanation:
Just definitions :)
Hope it helps <3