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Answer:

78.12 L

Explanation:

Given that,

Initial volume, V₁ = 105 L

Initial temperature, T₁ = 20°C = 20+273 = 293 K

New temperature, T₂ = -55 °C = 218 K

We need to find the new volume of the balloon. The relation between the volume and the temperature is given by :

[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

Where

V₂ is the new volume

[tex]V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{105\times 218}{293}\\\\V_2=78.12\ L[/tex]

So, the new volume is 78.12 L.

The correct answer is option A; Mesosphere

The mesosphere is defined as the part atmosphere found above the stratosphere but below the thermosphere.

In this layer of the atmosphere, temperature decreases with height. It covers about 50 to 85 km above the earth.

Mesosphere is the only layer of the atmosphere that was correctly spelt among the options.

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Answer:

the water molecules have more energy and are moving faster than the molecules of cold water. This makes it easier for the dye to get mixed throughout the hot water.

Explanation:

Answer:

Because particles moves more by kinetic energy and diffusion will spread with the particles

Explanation:

Answer:

pH value of HCL = 2.69897

Explanation:

Given:

Concentration of HCL = 0.002 M

Find:

pH value of HCL

Computation:

pH value of HCL = - log(Concentration of HCL)

pH value of HCL = - log(0.002)

pH value of HCL = 2.69897

Answer:

true

Explanation:

Answer:

750 mmHg

Explanation:

From the question given above, the following data were obtained:

Partial pressure of CO₂ (Pₐ) = 250 mmHg

Partial pressure of N₂ (P₆) = 375 mmHg

Partial pressure of He (P꜀) = 125 mmHg

Pressure of the mixture (Pₜ) =?

The pressure of the mixture of the gases can be obtained as follow:

Pₜ = Pₐ + P₆ + P꜀

Pₜ = 250 + 375 + 125

Pₜ = 750 mmHg

Therefore, the pressure of the mixture of the gases is 750 mmHg

Answer:

Explanation:

Mass = 66.6 gram

Density = 0.790 g/mL

Volume = Mass ÷ Density

Volume = 66.6 ÷ 0.790

Volume = 84.30 mL

Answer:we see 1 side because the other side is not visible

Explanation:

Answer:

1.) Eyewash station --> D

2.) Absorbent material --> G

3.) Fire extinguisher --> F

4.) Safety Shower --> E

5.) Biohazard container --> J

6.) Broken glass container --> I

7.) Safety goggles --> C

8.) Lab apron --> H

9.) asbestos gloves --> A

10.) Latex gloves --> B

Explanation:

In an equipped laboratory, alot of safety equipments are made available and kept in area that it could be easily accessed in the laboratory. Safety or protective equipments are those materials that helps protect a laboratory personnel while at work on the lab.

These equipments include:

--> Eyewash station: This is an equipment used in the laboratory during emergency to rinse chemical from the eye. Therefore option D is correct.

--> Absorbent material: They are used to contain small spills in the laboratory. Therefore option G is correct.

--> Fire extinguisher: This equipment is used to put out small fires. Therefore F is correct.

--> Safety Shower: This is used to rinse away chemical from clothes and on skin during emergency. Therefore option E is correct.

--> Biohazard container: This container is used to safely dispose bacteria culture, blood and other living tissues. Therefore option J is correct.

--> Broken glass container: This is used to dispose cracked, chipped or broken bottle in the laboratory. Therefore option I is correct.

--> Safety goggles: This helps to protect the eye from chemical and broken glasses. Therefore option C is correct.

--> Lab apron: This is worn by the laboratory personnel to help protect the skin from chemical and biohazards. Therefore option H is correct.

--> Asbestos gloves: these are heat resistant gloves used to protect the hands from heat. Therefore option A is correct.

--> Latex gloves: these are equally worn by the laboratory personnel to protect the hands from chemicals and biohazards

[tex]Answer :—✔[/tex]

Answer:

13 branches/tree

Explanation:

Step 1: Given data

Step 2: Calculate the total number of branches (b)

We will use the following expression.

b = l × b/l

b = 19565 leaves × 1 branch/35 leaves = 559 branch

Step 3: Calculate the number of branches per tree (b/t)

We will divide the total number of branches by the total number of trees.

559 branches/43 trees = 13 branches/tree

Answer:

Yes, they work in space. I forgot an example, will edit the post when I found it

Hope this helps!

Answer:

11 electrons

Explanation:

The number of electrons is the same as the number of protona in a ATOM.

They will most likely be different in a ion, simple bond or a convalent bond.

Answer:

25°C

Explanation:

Combined Gas Law (P₁V₁)/T₁ = (P₂V₂)/T₂

(0.947 atm)(150 mL)/25°C = (0.987 atm)(144mL)/T₂

5.682 = 142.128/T₂

T₂ = 142.128/5.682

T₂ = 25.0137272756°C = 25°C

Answer:

[tex]\boxed {\boxed {\sf 5.2 *10^{22} \ molecules \ NaCl}}[/tex]

Explanation:

1. Convert grams to moles

First, convert grams to moles using the molar mass. This can be found on the Periodic Table.

Sodium (Na) has an oxidation state of +1 and chlorine (Cl) has an oxidation state of -1, so they combine in a 1:1 ratio for a formula of NaCl. We can simply add their moles masses.

Use this as a ratio.

[tex]\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}[/tex]

Multiply by the given number of grams.

[tex]5.0 \ g \ NaCl *\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}[/tex]

Flip the fraction so the grams of sodium chloride cancel.

[tex]5.0 \ g \ NaCl *\frac {1 \ mol \ NaCl}{ 58.4397693 \ g \ NaCl}[/tex]

[tex]5.0 *\frac {1 \ mol \ NaCl}{ 58.4397693 }=\frac {5.0 \ mol \ NaCl} { 58.4397693 } = 0.0855581749 \ mol \ NaCl[/tex]

2. Convert moles to molecules

We must use Avogadro's Number. This tells us the amount of particles (molecules, atoms, etc.) in 1 mole of a substance. In this case, it is molecules of sodium chloride.

[tex]\frac{6.022*10^{23} \ molecules \ NaCl} {1 \ mol \ NaCl}[/tex]

Multiply by the number of moles we calculated.

[tex]0.0855581749 \ mol \ NaCl*\frac{6.022*10^{23} \ molecules \ NaCl} {1 \ mol \ NaCl}[/tex]

The moles of sodium chloride cancel.

[tex]0.0855581749 *\frac{6.022*10^{23} \ molecules \ NaCl}{1}=5.15231329*10^{22} \ molecules \ NaCl[/tex]

The original measurement of grams has 2 (2 and 0) significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 5 in the hundredth place tells us to round the 1 to a 2.

[tex]5.2 *10^{22} \ molecules \ NaCl[/tex]

Answer:

23.92 g

Explanation:

Molar mass of H2SO4 = (2×1)+32+(16×4)= 2+32+48= 82g/mol

H2SO4 + 2NaOH ---> Na2SO4 + 2H2O

I mole of H2SO4 = 2 moles of NaOH

24.5/82 = 24.5/82 × 2

= 0.598 moles of NaOH will neutralize

Mass= mole× molar mass

Molar mass of NaOH= 23+16+1 = 40g/mol

Mass= 0.598 × 40 = 23.92g of NaOH

Answer:

20g

Explanation:

First of all, you have got your formula wrong. It should be [tex]H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O[/tex].

Start by finding the Relative Formula Mass for sulfuric acid. [tex]H_{2}SO_{4}[/tex] is equal to (2x1)+32+(16x4)=98. You then calculate Mols by doing [tex]Mols=\frac{Mass}{Relative Formula Mass}[/tex]. So, [tex]\frac{24.5}{98} = 0.25[/tex], so the Mols of Sulfuric Acid is 0.25.

The Mol ratio of Sulfuric Acid to Sodium Hydroxide is 1:2, so 0.25:0.5.

Now, you have to find the Relative Formula Mass of Sodium Hydroxide, or [tex]NaOH[/tex]. 23+16+1=40. Finally, multiply 0.5 by 40, and you'll find that the maximum mass is 20g.

Explanation:

X = Group 1 metal

Y = Group 7 Non metal

The dots basically signifies the group.

Metal loses electrons and non metal gains electron. The valency of X is 1 and that of Y is 7.

X atom loses one electron and Y atom gains one electron.

The bond that forms between a metal and a non metal is an ionic bond.

C. picking a tray in the cafeteria line

Answer:

(i) Concentrated HNO3 can be stored and transported in aluminium containers as it reacts with aluminium to form a thin protective oxide layer on the aluminium surface. This oxide layer renders aluminium passive. (ii) Sodium hydroxide and aluminium react to form sodium tetrahydroxoaluminate(III) and hydrogen gas.

Answer:

pH = 11.216.

Explanation:

Hello there!

In this case, according to the ionization of ammonia in aqueous solution:

[tex]NH_3+H_2O\rightleftharpoons NH_4^++OH^-[/tex]

We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:

[tex]Kb=\frac{[NH_4^+][OH^-]}{[NH_3]} \\\\1.80x10^{-5}=\frac{x*x}{0.150-x}[/tex]

However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:

[tex]1.80x10^{-5}=\frac{x*x}{0.150}\\\\x=\sqrt{1.80x10^{-5}*0.150}=1.643x10^{-3}M[/tex]

Which is also:

[tex][OH^-]=1.643x10^{-3}M[/tex]

Thereafter we can compute the pOH first:

[tex]pOH=-log(1.643x10^{-3}M)\\\\pOH=2.784[/tex]

Finally, the pH turns out:

[tex]pH=14-2.784\\\\pH=11.216[/tex]

Regards!

Answer: A. True

Explanation:

Answer:

plants and animals

Explanation:

Answer:

water, light, wind, soil, humidity, minerals, gases

Explanation:

i just know

Answer:

hello can you follow me

Explanation:

used in fire extinction, blasting rubber, foaming rubber and plastic

Explanation:

I don't really understand the question

Answer:

Is the answer eight atoms

Answer:

Cold front

Explanation:

Answer:

114.23g

Explanation:

Mass = xg

Mole = 0.334 mol

Molar mass of Sucrose

(C = 12, H = 1, O = 16)

C12H22O11

(12×12)+(1×22)+(16×11)

144 + 22 + 176

342g/mol

Mass = No of mole × Molar mass

Mass = 0.334 × 342

Mass = 114.228

Mass ≈ 114.23g