1 cm = 10 mm. Length of book : 28 cm. Length of book = 280 mm. This shows that measurements in mm are the same but look to have a higher number .
How to compare centimeters and millimeters ?The conversion factor provided states that 1 cm is equal to 10 mm, which means that 1 cm is made up of 10 individual millimeters.
The length of my book in when measured in millimeters is 280 mm.
In centimeters, this is therefore:
= 280 mm / 10 cm /mm
= 28 cm
Although the numerical value appears higher when expressed in millimeters, it is important to note that the actual length of the book remains the same.
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Leigh designs and conducts a computer simulation with 30 trials and uses the data from the stimulation to create the relative frequency bar graph shown. The graph shows the relative frequency of the number of spins needed for a spinner divided into 6 equal sections labeled A through F on each letter at least once
The experimental probability that more than 10 spins are needed to land on each letter at least once is 75%
How to explain the probabilityExperimental probability is a type of probability that is based on actual observations or experiments.
In experimental probability, the probability of an event occurring is calculated by conducting experiments and observing the outcomes. The probability of the event is then calculated by dividing the number of times the event occurred by the total number of trials or experiments.
In this case, experimental probability = number of times the event occurred / total number of trials
Experimental probability = 0.1 + 0.35 + 0.3 / 1
= 0.75 / 1
= 75%
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On the map, the grocery store is 2 inches away from the library. The actual distance is 1.5 miles. The same map shows that the movie theater is 20 inches from the school.
What is the actual distance from the movie theater to the school, rounded to the nearest mile?
A: 15
B:27
C:30
D:60
The actual distance from the movie theater to the school is given as follows:
A. 15 miles.
How to calculate the actual distance?The actual distance from the movie theater to the school is obtained applying the proportions in the context of the problem.
On the map, the grocery store is 2 inches away from the library. The actual distance is 1.5 miles, hence the scale factor is of:
2 inches = 1.5 miles
1 inch = 0.75 miles.
The same map shows that the movie theater is 20 inches from the school, hence the actual distance is given as follows:
20 x 0.75 = 15 miles.
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Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity:
In the given triangle ABC, angle A is 90° and segment AD is perpendicular to segment BC.
The figure shows triangle ABC with right angle at A and segment AD. Point D is on side BC.
Which of these could be a step to prove that BC2 = AB2 + AC2?
possible answers -
By the cross product property, AB2 = BC multiplied by BD.
By the cross product property, AC2 = BC multiplied by BD.
By the cross product property, AC2 = BC multiplied by AD.
By the cross product property, AB2 = BC multiplied by AD.
The correct step to prove that [tex]BC^2 = AB^2 + AC^2[/tex] is:
By the cross product property, [tex]AC^2 = BC \cdot AD[/tex].
To prove that [tex]BC^2 = AB^2 + AC^2[/tex], we can use the triangle similarity and the Pythagorean theorem. Here's a step-by-step explanation:
Given triangle ABC with right angle at A and segment AD perpendicular to segment BC.
By triangle similarity, triangle ABD is similar to triangle ABC. This is because angle A is common, and angle BDA is a right angle (as AD is perpendicular to BC).
Using the proportionality of similar triangles, we can write the following ratio:
[tex]$\frac{AB}{BC} = \frac{AD}{AB}$[/tex]
Cross-multiplying, we get:
[tex]$AB^2 = BC \cdot AD$[/tex]
Similarly, using triangle similarity, triangle ACD is also similar to triangle ABC. This gives us:
[tex]$\frac{AC}{BC} = \frac{AD}{AC}$[/tex]
Cross-multiplying, we have:
[tex]$AC^2 = BC \cdot AD$[/tex]
Now, we can substitute the derived expressions into the original equation:
[tex]$BC^2 = AB^2 + AC^2$\\$BC^2 = (BC \cdot AD) + (BC \cdot AD)$\\$BC^2 = 2 \cdot BC \cdot AD$[/tex]
It was made possible by cross-product property.
Therefore, the correct step to prove that [tex]BC^2 = AB^2 + AC^2[/tex] is:
By the cross product property, [tex]AC^2 = BC \cdot AD[/tex].
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A ladder is leaning against a building, forming a 70° angle with the ground: The base of the ladder is 8.2 ft from the base of the
building.
What is the length of the ladder?
Round your answer to the nearest tenth of a foot.
22.5 ft
24.0 ft
28.0 ft
28.7 ft
The length of the ladder that is leaning on the building would be = 24ft. That is option B.
How to determine the length of the ladder?To determine the length of the ladder, the sine rule needs to be obeyed. That is
= a/sinA = b/sinB
Where;
a = 8.2 ft
A = 180-( 70+90
= 180- 160
= 20°
b = X
B = 90°
That is;
8.2/sin20° = b/sin90°
Make b the subject of formula;
b = 8.2×1/0.342020
= 23.9
= 24 ft
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For positive acute angles A and B, it is known that SinA= 11/61 and tan B=4/3. Find the value of Cos(A-B) in simplest form.
For positive acute angles A and B, if it is known that SinA= 11/61 and tan B=4/3, cos(A-B) = 224/305.
We can use the trigonometric identity cos(A-B) = cosA cosB + sinA sinB to find the value of cos(A-B).
First, we need to find the value of cosA and sinB:
Since sinA = opposite/hypotenuse, we can draw a right triangle with opposite side 11 and hypotenuse 61, and use the Pythagorean theorem to find the adjacent side:
cosA = adjacent/hypotenuse = √(61² - 11²)/61 = 60/61
Since tanB = opposite/adjacent, we can draw another right triangle with opposite side 4 and adjacent side 3, and use the Pythagorean theorem to find the hypotenuse:
hypotenuse = √(4² + 3²) = 5
sinB = opposite/hypotenuse = 4/5
Now we can substitute these values into the formula:
cos(A-B) = cosA cosB + sinA sinB
= (60/61)(3/5) + (11/61)(4/5)
= 180/305 + 44/305
= 224/305
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please answer all 3 and show work
The equation of the Damari's investment is B(x) = 30000 * 1.03ˣ
Sky's family should take the offer of $5000 for the boatThe rule of the function is f(x) = 8 * 0.6ˣCalculating the equations of the functionsDamari's investment
Given that
Initial value, a = 30000
B(3) = 32306.72
The function is calculated as
B(x) = a * bˣ
Using B(3), we have
30000 * b³ = 32306.72
So, we have
b³ = 1.077
Take the cube root of both sides
b = 1.03
So, we have
B(x) = 30000 * 1.03ˣ
So, the function is B(x) = 30000 * 1.03ˣ
The boat of Sky's family
Here, we have
Initial value = 6000
Rate of depreciation = 6%
So, the function is
f(x) = 6000 * (1 - 6%)ˣ
So, we have
f(x) = 6000 * (0.94)ˣ
In 2024, we have
x = 2024 - 2021
x = 3
So, we have
f(3) = 6000 * (0.94)³
Evaluate
f(3) = 4983.50
This value is less than the offered value of $5000
This means that Sky's family should take the offer
The rule of the function
Here, we have the graph
From the graph, we have
Initial value, a = 8
Rate, b = 4.8/8
So, we have
Rate, b = 0.6
So, the function is
f(x) = 8 * 0.6ˣ
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2
Select the correct answer from the drop-down menu.
Which equation satisfies all three pairs of a and b values listed in the table?
a b
0-10
1 -7
2-4
The equation is
An equation that satisfies all three pairs of a and b values listed in the table include the following: C. 3a - b = 10.
How to determine an equation that satisfies all three pairs of a and b values listed in the table?In order to determine an equation that satisfies all three pairs of a and b values listed in the table, we would substitute each of the numerical values corresponding to each variable into the given equations and then evaluate as follows;
a - 3b = 10
0 - 3(-10) = 30 (False).
3a + b = 10
3(0) - 10 = -10 (False).
3a - b = 10
3(0) - (-10)
0 + 10 = 10 (True).
3a - b = 10
3(1) - (-7)
3 + 7 = 10 (True).
3a - b = 10
3(2) - (-4)
6 + 4 = 10 (True)
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Complete Question:
Which equation satisfies all three pairs of a and b values listed in the table?
a b
0 -10
1 -7
2 -4
The equation is?
A.) a-3b=10
B.) 3a+b=10
C.) 3a-b=10
D.) a+3b=10
Brenda types 15 words per minute. How long will it take her to type 750 words?
It will take Brenda 50 minutes to type 750 words at a rate of 15 words per minute.
To solve this problem, we can use the formula:
time = amount of work / rate
In this case, the amount of work is typing 750 words, and the rate is 15 words per minute. Substituting these values into the formula, we get:
time = 750 / 15 = 50 minutes
This calculation assumes that Brenda types at a constant rate of 15 words per minute. If her typing speed varies, the time it takes her to type 750 words may be different.
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WINGSUIT A wingsuit flyer jumps off a tall cliff. He falls freely for a few seconds before deploying the wingsuit and -4.9x² +420, where y is = slowing his descent. His height during the freefall can be modeled by the function y the height above the ground in meters and x is the time in seconds. After deploying the wingsuit, the flyer's height is given by the function y = −3x + 200. deploy the wingsuit?
The total height of the flyer at any time after deploying the wingsuit would be;
y = -3x + 200 + (-4.9t² + 420),
Now, Based on the given information, we can use the two functions to determine the height of the wingsuit flyer at a particular time.
During the freefall, the height of the flyer can be calculated using the function
y = -4.9x² + 420.
Let's say the flyer falls freely for t seconds before deploying the wingsuit.
Therefore, the height at the moment of deploying the wingsuit would be,
y = -4.9t² + 420.
After deploying the wingsuit, the height of the flyer is given by the function
y = -3x + 200.
We can combine these two functions to get the total height of the flyer at any given time after deploying the wingsuit.
So, the total height of the flyer at any time after deploying the wingsuit would be;
y = -3x + 200 + (-4.9t² + 420),
where x is the time after deploying the wingsuit and t is the time of freefall before deploying the wingsuit.
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The nth term of an arithmetic sequence is given by un=15-3n.
a. [1 mark] State the value of the first term, u1.
b. [2 marks] Given that the nth term of this sequence is -33, find the value of n.
c. [2 marks] Find the common difference, d.
a. The first term of the arithmetic sequence is 12.
b. The value of n for which the nth term is -33 is 16.
c. The common difference of the arithmetic sequence is -3.
a. The first term, u1, can be found by substituting n=1 into the given formula for the nth term:
u1 = 15 - 3(1) = 12
b. To find the value of n for which the nth term is -33, we set the formula for the nth term equal to -33 and solve for n:
un = 15 - 3n = -33
Adding 3n to both sides, we get:
15 = -33 + 3n
Adding 33 to both sides, we get:
48 = 3n
Dividing both sides by 3, we get:
n = 16
c. The common difference, d, is the difference between any two consecutive terms of the sequence. To find d, we can subtract any two consecutive terms, such as u2 and u1:
u2 = 15 - 3(2) = 9
u1 = 15 - 3(1) = 12
d = u2 - u1 = 9 - 12 = -3
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Find the value for the side marked below. Round your answer to the nearest tenth 210 37 degrees
Using the cosine ratio, the value of the marked side in the image given below is approximately: y = 167.7.
How to Find the Value of the Marked Side Using the Cosine Ratio?The cosine ratio is defined as the ratio of the length of the hypotenuse of the right triangle over the length of the side that is adjacent to the reference angle. It is given as:
cos ∅ = length of hypotenuse/length of adjacent side.
From the image attached below, we have the following:
Reference angle (∅) = 37°
length of hypotenuse = 210
length of adjacent side = y
Plug in the values:
cos 37 = y/210
210 * cos 37 = y
y = 167.7
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Troys toy box is 4 ft x 3ft x 5 ft. What is the Volume of his toy box?
Answer:
60 ft^2
Step-by-step explanation:
To get the total volume we will need to multiply all the lengths. This means we will have to do 4 x 3x 5.
4 x 3 x 5 = 15x 4 = 60
Answer:
60 ft³
Step-by-step explanation:
V = 4 ft × 3 ft × 5 ft
V = 12 ft² × 5 ft
V = 60 ft³
#CMIIWWhich point would be a solution to the system of linear inequalities shown below?
Answer:
(-2, 10)
Step-by-step explanation:
You want the point that would be a solution to the inequalities ...
y ≥ 5/2x +2y ≥ -4x -7GraphIt can be useful to graph the inequalities, or develop a mental picture of what the graph would look like. Both boundary line slopes are fairly steep, and the lines cross in the third quadrant. The V-shaped space above that intersection is the solution space.
The attachment shows the point (-2, 10) is a solution.
Try the answersFrom the shape and location of the solution space, we can eliminate the choices ...
(-8, 2) — too close to the x-axis in the far left part of the 2nd quadrant
(10, -3) — no part of the 4th quadrant is in the solution space
General formIt can work nicely to rewrite the inequalities as a comparison to zero.
5x -2y +4 ≤ 0 . . . . . the first inequality in general form
point (-2, 10): 5(-2) -2(10) +4 = -10 -20 +4 = -26 ≤ 0 . . . a solution
point (4, 9): 5(4) -2(9) +4 = 20 -18 +4 = 6 > 0 . . . . . . . not a solution
4x +y +7 ≥ 0 . . . . . . the second inequality in general form
point (-2, 10): 4(-2) +(10) +7 = -8 +10 +7 = 9 ≥ 0 . . . . . . a solution
point (4, 9): don't need to test (already known not a solution)
Point (-2, 10) is a solution.
__
Additional comment
We chose the use of "general form" inequalities for evaluating answer choices because ...
the arithmetic is mainly with positive integers (no fractions)the comparison to zero does not require a lot of mental effort<95141404393>
Katrina wants to make a cover for her laptop to fit into her bag in order to protect it. She measured the top of her laptop and found it was 57,000 mm2. “No one sells covers using square millimeters,” her friend noted. Describe the area of the top of Katrina’s laptop using square centimeters.
Answer:
To convert square millimeters to square centimeters, we need to divide the area in square millimeters by 100 (since there are 100 square millimeters in a square centimeter).
So, the area of the top of Katrina's laptop in square centimeters would be:
57,000 mm² ÷ 100 = 570 cm²
Therefore, the area of the top of Katrina's laptop in square centimeters is 570 cm².
please help me thank you so much
Answer:
1)
7+9-15 = add 7 and 9, then subtract 15
2)
15-(7+9) = The sum of 7 and 9 subtracted from 15
3)
15-(7+9) = subtract 7 from 15, then add 9
Step-by-step explanation:
Learn BODMAS. The order of how to do equations. A simple tutorial on yt should be sufficient
The figure below is a net for a cube. 3.9 ft What is the surface area of the cube, in square feet?
Answer:91.26ft squared
The bottom part says how many student tickets where brought? Can anyone pls help me PLSS
255 number of adults and 355 number of students bought ticket.
Here, we have,
Let the number of adults bought tickets are x and the number of students that bought tickets is (x + 100).
Since it is given that 100 more students brought tickets than adults.
Now, each adult ticket costs $5 and each student's ticket costs $3.5 and the total collected value of tickets is $2517.5.
So, 5x + 3.5(x + 100) = 2517.5
⇒ 8.5x + 350 = 2517.5
⇒ 8.5x = 2167.5
⇒ x = 255
So, 255 number of adults and (255 + 100) = 355 number of students bought ticket. (Answer)
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Find the greatest common factor of 21x^4 and 49x^3
The greatest common factor of two terms given as 21x⁴ and 49x³ is equal to 7x³.
To find the greatest common factor (GCF) of two terms, we need to find the highest factor that is common to both terms. In this case, we have 21x⁴ and 49x³.
To find the factors, we can break each term down into its prime factors:
21x⁴ = 3 * 7 * x * x * x * x
49x³ = 7 * 7 * x * x * x
The common factors are 7 and x³. To find the GCF, we multiply these common factors together:
GCF = 7 * x³
GCF = 7x³
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please help fast i don’t feel like typing
Answer:
he should have subtracted 17 from both sides of the equation
Step-by-step explanation:
x+ 17 = 22
subtract 17 from both sides
X + 17 = 22
-17 -17
x = 5
A ball pit contains 190 balls.
50 are orange, 100 are purple and 40 are yellow.
What is the ratio of yellow to purple balls in its simplest form?
Step-by-step explanation:
40 :100 yellow to purple, divide both sides by 20
2:5
Answer:
the ratio of yellow to purple is 40:100 that is 2:5 in the simplest form.
Step-by-step explanation:
Hope it helps.
If D = 2w? - w - 7 and C = 3w - 6, find an expression that equals D + 3C in
standard form.
The expression that equals D + 3C in standard form is 2w² + 8w - 25.
To find an expression that equals D + 3C in standard form, we first need to simplify D and C.
Starting with D = 2w² - w - 7, we can rearrange the terms to put it in standard form:
D = 2w² - w - 7
D = 2w² - 2w + w - 7
D = 2w(w - 1) + (w - 7)
Next, simplifying C = 3w - 6:
C = 3w - 6
Now, we can substitute these expressions into D + 3C:
D + 3C = (2w² - w - 7) + 3(3w - 6)
Expanding and simplifying:
D + 3C = 2w² - w - 7 + 9w - 18
D + 3C = 2w² + 8w - 25
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find the second linearly independent soln. of the DE from the first
x^2y'' - 42y = 0; y1=x^7
The Second Linearly Independent solution of the differential equation is:
y = c₁x⁷ + c₂(Ax¹⁰ + Bx⁻¹¹)
When solving a second-order linear differential equation of the form
x²y'' - 42y = 0, it is important to find two linearly independent solutions to fully describe the general solution. The first solution is given as y₁=x⁷.
To find the second linearly independent solution, we can use the method of reduction of order.
Let y₂ = u(x)y₁(x), where u(x) is a function to be determined.
Then we have y₂' = u(x)y₁'(x) + u'(x)y₁(x) and y₂'' = u(x)y₁''(x) + 2u'(x)y₁'(x) + u''(x)y₁(x).
Substituting y₂ and its derivatives into the original differential equation, we have:
x²(u(x)y₁''(x) + 2u'(x)y₁'(x) + u''(x)y₁(x)) - 42u(x)y₁(x) = 0
Dividing by x²y₁(x), we get:
u''(x)/u(x) + 2/x[u'(x)/u(x)] - 42/x² = 0
Let v(x) = u'(x)/u(x), then v'(x) = u''(x)/u(x) - (u'(x))²/(u(x))². Substituting v(x) into the above equation, we have:
v'(x) + 2/xv(x) - 42/x² = 0
This is now a first-order linear differential equation that can be solved using an integrating factor. Letting mu(x) = x², we have:
(x²v(x))' = 42
Solving for v(x), we get:
v(x) = 21/x + C/x²
where C is an arbitrary constant. Substituting back to u(x), we get:
u(x) = Ax³ + Bx⁻⁻¹⁸
where A and B are constants. Therefore, the second linearly independent solution is
y₂ = (Ax³ + Bx⁻¹⁸)x⁷ = Ax¹⁰ + Bx⁻¹¹
Hence, the general solution of the differential equation is:
y = c₁x⁷ + c₂(Ax¹⁰ + Bx⁻¹¹)
where c₁ and c₂ are arbitrary constants
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I have not gone to school in a month for family reasons and I have to submit 39 math assignments before Friday HELP
Diego is correct as the number of groups result to 6/5 or 1 1/5.
We have to find the number of groups of 5/6 in 1.
So, we need to perform the division as
= 1/ (5/6)
= 1 x 6/5
= 6/5
= 1 1/5
Thus, Diego is correct as the number of groups result to 6/5 or 1 1/5.
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The length and breadth of a rectangular flower bed are 16m and 9 m, respectively. How many plants can be planted in it, if each plant requires a space of 1.2m x 1m?
The calculated number of plants the flower bed can contain is 120
Calculating hw many plants can be planted in itFrom the question, we have the following parameters that can be used in our computation:
Dimensions = 16 m by 9 m
So, the area of the flower bed is
Area = 16 * 9
Evaluate
Area = 144
Also, we have
Each plant requires a space of 1.2m x 1m?
This means that
Plant area = 1.2 * 1
Plant area = 1.2
So, we have
Plants = 144/1.2
Evaluate
Plants = 120
Hence, the number of plants is 120
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Answer:
Step-by-step explanation:
To calculate the number of plants that can be planted in the rectangular flower bed, we need to calculate the area of the flower bed and divide it by the space required for each plant.
The area of the flower bed is calculated by multiplying its length and breadth.
So, the area of the flower bed is 16m x 9m = 144 sq.m.
Each plant requires a space of 1.2m x 1m = 1.2 sq.m.
Therefore, the number of plants that can be planted in the flower bed is:
144 sq.m. ÷ 1.2 sq.m./plant = 120 plants.
So, you can plant 120 plants in the rectangular flower bed.
Erik has been collecting comic books for the past few years. The number of total comic books in his collection each year is as follows. • 30 comic books the first year • 60 comic books the second year • 90 comic books the third year • 120 comic books the fourth year Write a function that represents the number of comic book as a function of the number of years, t.
The function that represents the number of comic book as a function of the number of years, t is expressed as y = 30x or f(t) = 30t.
How to Write a Linear Function?We can use the given data to create a linear equation of the form y = mx + b, where y represents the number of comic books and x represents the number of years.
To find the equation, we can use any two pairs of (x, y) values. Let's use the first and fourth years:
First year: (1, 30)
Fourth year: (4, 120)
The slope, m, of the line can be calculated using the formula:
m = change in y / change in x = (120 - 30) / (4 - 1)
m = 90 / 3
m = 30
The y-intercept, b, can be found by substituting one of the (x, y) values and the slope into the linear equation, y = mx + b:
30 = 30(1) + b
b = 0
Therefore, the equation that represents the number of comic books, y, as a function of the number of years, x, is:
y = 30x
or
f(t) = 30t [where t represents the number of years.]
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URGENT HELP PLEASE!!!
In a class of students, the following data table summarizes how many students have a
a
cat or a dog. What is the probability that a student chosen randomly from the class
has a cat and a dog?
Answer: 5/13
Step-by-step explanation:
To solve this problem, we can use the formula for conditional probability:
P(A|B) = P(A and B) / P(B)
where P(A and B) is the probability of both events A and B happening, and P(B) is the probability of event B happening.
Let's first calculate the total number of people in the class:
Total number of people = 5 + 6 + 2 + 11 = 24
Now, let's calculate the probability of having a cat and a dog:
P(cat and dog) = 5 / 24
Next, let's calculate the probability of having a cat:
P(cat) = (5 + 6 + 2) / 24 = 13 / 24
Finally, let's calculate the probability of having no dog:
P(no dog) = (6 + 11) / 24 = 17 / 24
Using the formula for conditional probability, we can calculate the probability of having both a cat and a dog given that a person has a cat:
P(cat and dog | cat) = P(cat and dog) / P(cat) = (5 / 24) / (13 / 24) = 5 / 13
Therefore, the probability that a student chosen randomly from the class has a cat and a dog is 5/13.
In ΔJKL,
�
�
‾
JL
is extended through point L to point M,
m
∠
�
�
�
=
(
3
�
−
16
)
∘
m∠JKL=(3x−16)
∘
,
m
∠
�
�
�
=
(
2
�
+
15
)
∘
m∠LJK=(2x+15)
∘
, and
m
∠
�
�
�
=
(
8
�
−
19
)
∘
m∠KLM=(8x−19)
∘
. Find
m
∠
�
�
�
.
m∠LJK.
The angle measure of LJK is 27 degrees
How to determine the angleFollowing the triangle sum theorem, we have that the sum of the interior angles of a triangle is 180 degrees
Also, we need to know that the sum of angles on a straight line is 180, then, we have;
<JLK = 180 - <LKM = 180 - (8x - 19)
Then, substitute the value, we have that;
<JKL + < JLK + < KJL = 180
Then,
3x - 16 + (180 - (8x - 19)) + 2x + 15 = 180
expand the bracket, we have;
3x - 16 - 8x - 19 + 2x + 15 = 0
add the like terms
-3x + 18 = 0
collect the terms
-3x = -18
x = 6
Then, the angle LJK = 2x + 15 = 2(6) + 15 = 27 degrees
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60% of the books in a library are for adults, 5% are for young people and the rest are for children. If there are 280 books for children, how many books are there altogether?
Answer:
800 books
problem solving steps:
adults:60%
young people:5%
children=100%-60%-5%
=35%
35%=280 books
1%=280÷35
=8
100%=800
so,there are 800 books
XZ.P Point P(-7, 2) is mapped onto P¹ (3, -11) by the reflection y=mx+c. find the values of the constants m and c.
The values of the constants m and c include the following:
m = -1.3
c = 7.1
What is the slope-intercept form?In Mathematics and Geometry, the slope-intercept form of the equation of a straight line is given by this mathematical equation;
y = mx + c
Where:
m represent the slope or rate of change.x and y are the points.c represent the y-intercept or initial value.Since the point P(-7, 2) is mapped onto P' (3, -11) by the reflection y = mx + c, we can write the following system of equations;
2 = -7m + c ...equation 1.
-11 = 3m + c ...equation 2.
By solving the system of equations simultaneously, we have:
2 = -7m - 3m - 11
11 + 2 = -10m
13 = -10m
m = -1.3
c = 7m + 2
c = 7(-1.3) + 2
c = -7.1
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MA.7.DP.1.4
A group of friends has been given $800 to host a party. They must decide how much money
will be spent on food, drinks, paper products, music and decorations.
Part A. As a group, develop two options for the friends to choose from regarding how to
spend their money. Decide how much to spend in each area and create a circle
graph for each option to represent your choices.
Part B. Mikel presented the circle graph below with his recommendations on how to
spend the money. How much did he choose to spend on food and drinks? How
much did he choose to spend on music?
Party Spending Proposal
Mail
17%
Paper Products
Answer: $130 money did Brenda and Hazel have all together before buying decorations and snacks.
Here, we have,
You want to know Brenda and Hazel's combined money when the ratio of their remaining balances is 1 : 4 after Brenda spent $58 and Hazel spent $37. They had the same amount to start with.
Setup
Let x represent the total amount the two women started with. Then x/2 is the amount each began with, and their fnal balance ratio is ...
(x/2 -58) : (x/2 -37) = 1 : 4
Solution
Cross-multiplying gives ...
4(x/2 -58) = (x/2 -37)
2x -232 = x/2 -37 . . . . . . eliminate parentheses
3/2x = 195 . . . . . . . . . . . . add 232-x/2
x = (2/3)(195) = 130 . . . . . multiply by 2/3
Brenda and Hazel had $130 altogether before their purchases.
Alternate solution
The difference in their spending is $58 -37 = $21.
This is the same as the difference in their final balances.
That difference is 4-1 = 3 "ratio units", so each of those ratio units is $21/3 = $7.
Their ending total is 1+4 = 5 ratio units, or $35.
The total they started with is $58 +37 +35 = $130.
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complete question:
Brenda and Hazel decide to throw a surprise party for their friend, Aerica. Brenda and Hazel each go to the store with the same amount of money. Brenda spends $58 on decorations, and Hazel spends $37 on snacks. When they leave the store, the ratio of Brenda’s money to Hazel’s money is 1 : 4. How much money did Brenda and Hazel have all together before buying decorations and snacks?