HELP ASAP PLEASE
FIND THE AREA OF THE FIGURE. ROUND TO THE NEAREST TENTH IF
NECESSARY.
8 mm
8 mm
A 164.5 mm2
B 106.7 mm2
C 89.1 mm2
D 64 mm2

Answer:

14.6

Step-by-step explanation:

using the trigonometry ratio

cosine

cos35= 12/BC

BC= 12/cos35

BC = 14.64

Wouldnt that just be 75x2? bc if so then

The answer is:

75x2=150+ 850=1000

Answer: 10

Step-by-step explanation:

Hope this helps!

Answer:

2/10*4/10=2/25 aka 0.08 aka rounded is 0.1

Step-by-step explanation:

hope this helps plz give brainliest

Answer:

a67y.....................

Answer:

D.) "Yes, Mr. Yule’s sample is random and representative of the population."

Step-by-step explanation:

Answer:

x = 25

Step-by-step explanation:

Looking at the triangle we know that it is a right triangleor a 90⁰ triangle.

(2x + 15)⁰ + x⁰ = 90⁰

2x + 15⁰ + x⁰ = 90⁰

2x + x + 15⁰ = 90⁰

3x + 15⁰ = 90⁰

3x + 15⁰ - 15⁰ = 90⁰ - 15⁰

3x = 75⁰

3x / 3 = 75⁰ / 3

x = 25⁰

Now plug the x value in the missing angles.

2x + 15⁰

2(25⁰) + 15⁰

50⁰ + 15⁰

65⁰

According to the sum of triangle, all angles add up to 180⁰. Even though this is a right triangle, it should add up 180⁰ in order to be a triangle.

65⁰ + 25⁰ + 90⁰ = 180⁰

Hope this helps and stay safe, happy, and healthy, thank you :) !!

Answer:

The recommended number of flowers is 32

Step-by-step explanation:

Given

The attached graph

Required

The number of flowers when area = 15

First, calculate the slope (m)

Considering

[tex](x_1,y1) = (12,60)[/tex]

[tex](x_2,y_2) = (15,20)[/tex]

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]m = \frac{20-16}{15-12}[/tex]

[tex]m = \frac{4}{3}[/tex]

Considering:

[tex](x_1,y_1) = (15,20)[/tex]

[tex](x_2,y_2) = (24,y)[/tex]

The slope is:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]m = \frac{y - 20}{24 - 15}[/tex]

[tex]m = \frac{y - 20}{9}[/tex]

Recall that: [tex]m = \frac{4}{3}[/tex]

So:

[tex]\frac{4}{3} = \frac{y - 20}{9}[/tex]

Multiply through by 9

[tex]3*4 = y - 20[/tex]

[tex]y = 20 + 3 * 4[/tex]

[tex]y = 32[/tex]

Answer:

The answer to this question is 4

Step-by-step explanation:

Answer: I think it’s 2

Step-by-step explanation: because either of the sides are equal or the base and a side is not possible.

Aren’t you from CCA, Ryan Rivera, Maths 5th period.

Answer:

2

hope this helps

Answer:

15 cu ft

Step-by-step explanation:

figure A~figure B

4-->2 ft

10-->5 ft

3-->1.5 ft

V=2×5×1.5=15 cu ft

The volume of Figure B is  15 [tex]ft^{3}[/tex]

The RATIO OF SIMILARITY between any two similar figures is the ratio of any pair of corresponding sides. Simply stated, once it is determined that two figures are similar, all of their pairs of corresponding sides have the same ratio.

According to the question

Figure A ≈ Figure B

Therefore , ratio of corresponding sides have the same ratio .

Figure A              Figure B

4 ft                ⇒         2 ft  (given )

( As ratio of [tex]\frac{side\\\ of\\\ figure A}{side\\\ of\\\ figure B} = \frac{2}{1}[/tex] )

10 ft                ⇒        5 ft

3 ft                ⇒         1.5 ft

Now, volume of Figure B (which is cuboid ) =  Length * Breath * Height

                                                                       =  2 * 5 * 1.5

                                                                       =    15 [tex]ft^{3}[/tex]

Hence, the volume of Figure B is  15 [tex]ft^{3}[/tex]

To know more about  ratio of similarity here:

https://brainly.com/question/39796

#SPJ2

Answer:

I'm pretty sure itd be tropic fresh fruit punch, with it having more concentration compared too the other brand.

Answer:

read explanation

Step-by-step explanation:

this is a quadratic equation

first, move the 7x over to the other side so that we have 0 on one side

x^2+7x+12=0

now, we can factor

turn 7x into 3x and 4x, so x^2+3x+4x+12=0

you can turn x^2+3x into x(x+3) and 4x+12 into 4(x+3)

so, our new equation is x(x+3)+4(x+3)=0

that can be turned into (x+4)(x+3)=0 via the distributive property

so, either x+4 or x+3 has to be equal to 0

so, x is either -4 or -3

hope this helped

Answer:

166.66 pounds

Step-by-step explanation:

160/0.96=166.66667

This is how I remember doing these questions

Answer:

2x-3y

Step-by-step explanation:

Answer:

This is the answer

Step-by-step explanation:

here you have the answers

Answer:

[tex]A=12[/tex]

Step-by-step explanation:

The formula to find the area of a trapezoid is,

[tex]A=(\frac{b_1+b_2}{2})(h)[/tex]

Where ([tex]b_1[/tex]) and ([tex]b_2[/tex]) represent the two bases of the trapezoid, and ([tex]h[/tex]) represents the hieght of the figure. As one can see on the coordinate plane,

[tex]b_1=2\\\\b_2=4\\\\h=4[/tex]

Substitute in the given values, and solve,

[tex]A = (\frac{b_1+b_2}{2})(h)\\\\A = (\frac{2+4}{2})(4)\\\\A = (\frac{6}{2})(4)\\\\A = (3)(4)\\\\A = 12[/tex]

Answer:

true

Step-by-step explanation:

The only regular (all sides equal and all angles equal) quadrilateral is a square. So all other quadrilaterals are irregular.

Answer:

Falsee, I believe.

Rhombuses are equilateral too...

Hope that helps!

-Sabrina

Step-by-step explanation:

Answer:

Do you need the answer or the factor??

Step-by-step explanation:

Answer: -(5a+16)

Step-by-step explanation:

Answer:

9750 min or 162.5 hours

Step-by-step explanation:

375 times 26 = 9750

Answer:

C) 24 cheerleaders

Step-by-step explanation:

20 last year

subtract 3 for those who decided not to join

20 -3 = 17

add 7 for those who joined

17 + 7 = 24

there are 24 cheer leaders

hope it help

Answer:

For probabilities with replacement

[tex]P(2\ Red) = \frac{25}{64}[/tex]

[tex]P(2\ Black) = \frac{9}{64}[/tex]

[tex]P(1\ Red\ and\ 1\ Black) = \frac{15}{32}[/tex]

[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{15}{64}[/tex]

For probabilities without replacement

[tex]P(2\ Red) = \frac{5}{14}[/tex]

[tex]P(2\ Black) = \frac{3}{28}[/tex]

[tex]P(1\ Red\ and\ 1\ Black) = \frac{15}{28}[/tex]

[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{15}{56}[/tex]

Step-by-step explanation:

Given

[tex]Marbles = 8[/tex]

[tex]Red = 5[/tex]

[tex]Black = 3[/tex]

For probabilities with replacement

(a) P(2 Red)

This is calculated as:

[tex]P(2\ Red) = P(Red)\ and\ P(Red)[/tex]

[tex]P(2\ Red) = P(Red)\ *\ P(Red)[/tex]

So, we have:

[tex]P(2\ Red) = \frac{n(Red)}{Total} \ *\ \frac{n(Red)}{Total}\\[/tex]

[tex]P(2\ Red) = \frac{5}{8} * \frac{5}{8}[/tex]

[tex]P(2\ Red) = \frac{25}{64}[/tex]

(b) P(2 Black)

This is calculated as:

[tex]P(2\ Black) = P(Black)\ and\ P(Black)[/tex]

[tex]P(2\ Black) = P(Black)\ *\ P(Black)[/tex]

So, we have:

[tex]P(2\ Black) = \frac{n(Black)}{Total}\ *\ \frac{n(Black)}{Total}[/tex]

[tex]P(2\ Black) = \frac{3}{8}\ *\ \frac{3}{8}[/tex]

[tex]P(2\ Black) = \frac{9}{64}[/tex]

(c) P(1 Red and 1 Black)

This is calculated as:

[tex]P(1\ Red\ and\ 1\ Black) = [P(Red)\ and\ P(Black)]\ or\ [P(Black)\ and\ P(Red)][/tex]

[tex]P(1\ Red\ and\ 1\ Black) = [P(Red)\ *\ P(Black)]\ +\ [P(Black)\ *\ P(Red)][/tex]

[tex]P(1\ Red\ and\ 1\ Black) = 2[P(Red)\ *\ P(Black)][/tex]

So, we have:

[tex]P(1\ Red\ and\ 1\ Black) = 2*[\frac{5}{8} *\frac{3}{8}][/tex]

[tex]P(1\ Red\ and\ 1\ Black) = 2*\frac{15}{64}[/tex]

[tex]P(1\ Red\ and\ 1\ Black) = \frac{15}{32}[/tex]

(d) P(1st Red and 2nd Black)

This is calculated as:

[tex]P(1st\ Red\ and\ 2nd\ Black) = [P(Red)\ and\ P(Black)][/tex]

[tex]P(1st\ Red\ and\ 2nd\ Black) = P(Red)\ *\ P(Black)[/tex]

[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{n(Red)}{Total} *\ \frac{n(Black)}{Total}[/tex]

So, we have:

[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{5}{8} *\frac{3}{8}[/tex]

[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{15}{64}[/tex]

For probabilities without replacement

(a) P(2 Red)

This is calculated as:

[tex]P(2\ Red) = P(Red)\ and\ P(Red)[/tex]

[tex]P(2\ Red) = P(Red)\ *\ P(Red)[/tex]

So, we have:

[tex]P(2\ Red) = \frac{n(Red)}{Total} \ *\ \frac{n(Red)-1}{Total-1}[/tex]

We subtracted 1 because the number of red balls (and the total) decreased by 1 after the first red ball is picked.

[tex]P(2\ Red) = \frac{5}{8} * \frac{4}{7}[/tex]

[tex]P(2\ Red) = \frac{5}{2} * \frac{1}{7}[/tex]

[tex]P(2\ Red) = \frac{5}{14}[/tex]

(b) P(2 Black)

This is calculated as:

[tex]P(2\ Black) = P(Black)\ and\ P(Black)[/tex]

[tex]P(2\ Black) = P(Black)\ *\ P(Black)[/tex]

So, we have:

[tex]P(2\ Black) = \frac{n(Black)}{Total}\ *\ \frac{n(Black)-1}{Total-1}[/tex]

We subtracted 1 because the number of black balls (and the total) decreased by 1 after the first black ball is picked.

[tex]P(2\ Black) = \frac{3}{8}\ *\ \frac{2}{7}[/tex]

[tex]P(2\ Black) = \frac{3}{4}\ *\ \frac{1}{7}[/tex]

[tex]P(2\ Black) = \frac{3}{28}[/tex]

(c) P(1 Red and 1 Black)

This is calculated as:

[tex]P(1\ Red\ and\ 1\ Black) = [P(Red)\ and\ P(Black)]\ or\ [P(Black)\ and\ P(Red)][/tex]

[tex]P(1\ Red\ and\ 1\ Black) = [P(Red)\ *\ P(Black)]\ +\ [P(Black)\ *\ P(Red)][/tex]

[tex]P(1\ Red\ and\ 1\ Black) = [\frac{n(Red)}{Total}\ *\ \frac{n(Black)}{Total-1}]\ +\ [\frac{n(Black)}{Total}\ *\ \frac{n(Red)}{Total-1}][/tex]

So, we have:

[tex]P(1\ Red\ and\ 1\ Black) = [\frac{5}{8} *\frac{3}{7}] + [\frac{3}{8} *\frac{5}{7}][/tex]

[tex]P(1\ Red\ and\ 1\ Black) = [\frac{15}{56} ] + [\frac{15}{56}][/tex]

[tex]P(1\ Red\ and\ 1\ Black) = \frac{30}{56}[/tex]

[tex]P(1\ Red\ and\ 1\ Black) = \frac{15}{28}[/tex]

(d) P(1st Red and 2nd Black)

This is calculated as:

[tex]P(1st\ Red\ and\ 2nd\ Black) = [P(Red)\ and\ P(Black)][/tex]

[tex]P(1st\ Red\ and\ 2nd\ Black) = P(Red)\ *\ P(Black)[/tex]

[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{n(Red)}{Total} *\ \frac{n(Black)}{Total-1}[/tex]

So, we have:

[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{5}{8} *\frac{3}{7}[/tex]

[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{15}{56}[/tex]

1.  4 x 31 is 124

2. 7 x 49 is 658

3. 16 x 48 is 608

4. 8(5 + w) is   8w + 40

5. 11(9 + d) is   11d + 99

6. 15(p + 4 + 2) is   15p + 90

7. Let's simplify step-by-step.

2x−4+3x

=2x+−4+3x

Combine Like Terms:

=2x+−4+3x

=(2x+3x)+(−4)

=5x+−4.

8. Let's simplify step-by-step.

4y−1−3y−2

=4y+−1+−3y+−2

Combine Like Terms:

=4y+−1+−3y+−2

=(4y+−3y)+(−1+−2)

=y+−3.

9. Let's simplify step-by-step.

x+2(x−4)

Distribute:

=x+(2)(x)+(2)(−4)

=x+2x+−8

Combine Like Terms:

=x+2x+−8

=(x+2x)+(−8)

=3x+−8.

10. Part A)

The jazz band sells 31 large boxes of fruit and 74 small boxes of fruit.

For each large fruit box, the price is $20 and cost is $x.

Profit is defined as Price - Cost.

So, profit for one large fruit box = 20 - x

Profit for 31 large fruit boxes = 31(20 - x)

Price of each small fruit box is $10 and cost of each small fruit box is $y. The profit for each small fruit box is 10 - y.

Profit for 74 small fruit boxes = 74(10 - y)

The total profit for 31 large boxes and 74 small boxes will be:

Total profit = 31 (20 - x ) + 74(10 - y)

Using distributive property, we can simplify the above equation as:

Total profit = 31(20) - 31x +74(10) - 74y

Total profit = 1360 - 31x - 74y

Part B)

Cost of each large box is given to be $9. This means x = 9

Cost of each small box is given to be $4. This means y = 4

Using the values of x and y in the profit equation we can find the profit of the Jazz Band.

So, Jazz Band's Profit = 1360 - 31(9) - 74(4)

Jazz Band's Profit = $ 785

Thus the profit of Jazz Band will be $785.

Have A good day!! Hope I helped!!! ^-^

Answer:

A. 42.57 and 42.58

42.579337.......

Answer:

its the first option

Step-by-step explanation: