HEEEEEEEEEEELPPPP I WILL MARK BRAINLIEST!!!!!!!

Reflect over y-axis,reflect over the X axis ,rotate 180°

Option D is the correct option.

Explanation:

Let's take point A which is (4,-1)

Reflection over y- axis will make this point (4,1)

Then, reflection over X axis will make this point (4,-1)

After rotation of 180 degree we will get (-4,1) .

Please see the attached picture....

Hope it helps...

Good luck on your assignment...

Answer:  d) reflect over the x-axis, reflect over y-axis, rotate 180°

Step-by-step explanation:

A reflection over the x-axis and a reflection over the y-axis is the SAME as a rotation of 180°. Together they make a rotation of 360°, which results in the image staying at the same place.

Reflection over the x-axis changes the sign of the y-coordinate

Z = (x, y)    →    Z' = (x, -y)

Reflection over the y-axis changes the sign of the x-coordinate

Z' = (x, -y)    →    Z'' = (-x, -y)

Rotation of 180° changes the signs of both the x- and y-coordinates

Z'' = (-x, -y)   →     Z''' = (x, y)

Answer:

Tangent

Step-by-step explanation:

if the angle in question is the bottom of the ladder and the ground, then tangent is opposite over adjacent... or 12/5

Hope this is right

Answer:

[tex]h = \frac{s - 2ar}{2ar} \\ [/tex]

Step-by-step explanation:

[tex]s = 2ar + 2arh \\ s - 2ar = 2arh \\ \frac{s - 2ar}{2ar} = \frac{2arh}{2ar} \\ h = \frac{s - 2ar}{2ar} [/tex]

hope this helps you

brainliest appreciated

good luck! have a nice day!

Answer:

Step-by-step explanation:

max can be found by the formula:

t=-b/2a

t=-9.8/2*(-4.9)

t=-9.8/-9.8

t=1

1 sec

to find maximum height obtained we find the vertex:

plug in 1 for t and simply solve:

h(t)= -4.9t^2 + 9.8t + 1

h(t)= -4.9*1^2 + 9.8*1 + 1

h(t)= -4.9*1 + 9.8 + 1

h(t)= -4.9 + 10.8

h(t)= 5.9

height is 5.9

Answer:

  height = 10.5 cm (for open-top container)

Step-by-step explanation:

The area of the base is ...

  A = πr²

The lateral area is ...

  A = 2πrh

We want the ratio of these to be 1:6, so we have ...

  πr²/(2πrh) = 1/6

  6πr² = 2πrh . . . cross multiply

  h = 3r . . . . . . . divide by 2πr

  h = 3(3.5 cm) = 10.5 cm

The height is 10.5 cm.

Answer:

21.77% probability that the antenna will be struck exactly once during this time period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

In this question:

[tex]\mu = 2.40[/tex]

Find the probability that the antenna will be struck exactly once during this time period.

This is P(X = 1).

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 1) = \frac{e^{-2.40}*2.40^{1}}{(1)!} = 0.2177[/tex]

21.77% probability that the antenna will be struck exactly once during this time period.

Answer:

8 nickels, 5 dimes and 7 quarters

Step-by-step explanation:

Each nickel is $0.05, each dime is $0.10 and each quarter is $0.25.

So, if we have n nickes, d dimes and q quarters, we can write the system of equations:

[tex]n + d + q = 20\ (eq1)[/tex]

[tex]0.05n + 0.1d + 0.25q = 2.65\ (eq2)[/tex]

[tex]7n + 5d + 20q = 221\ (eq3)[/tex]

If we multiply (eq2) by 140 and (eq1) by 7, we have:

[tex]7n + 14d + 35q = 371\ (eq4)[/tex]

[tex]7n + 7d + 7q = 140\ (eq5)[/tex]

Now, making (eq4) - (eq3) and (eq5) - (eq3), we have:

[tex]9d + 15q = 150\ (eq6)[/tex]

[tex]2d - 13q = -81\ (eq7)[/tex]

Multiplying (eq7) by 4.5, we have:

[tex]9d - 58.5q = -364.5\ (eq8)[/tex]

Subtracting (eq6) by (eq8), we have:

[tex]73.5q = 514.5[/tex]

[tex]q = 7[/tex]

Finding 'd' using (eq6), we have:

[tex]9d + 15*7 = 150[/tex]

[tex]9d = 150 - 105[/tex]

[tex]d = 5[/tex]

Finding 'n' using (eq1), we have:

[tex]n + 5 + 7 = 20[/tex]

[tex]n = 8[/tex]

So we have 8 nickels, 5 dimes and 7 quarters.

Answer:

[tex]a.\ P(x) = - 0.002x^2+3.8x-40[/tex]

b. 320

[tex]c.\ P'(x) = -0.004 x + 3.8[/tex]

d. 3.76

Step-by-step explanation:

Given that:

Revenue function:

[tex]R(x) = 6x[/tex]

Cost Function:

[tex]C(x) = 0.002x^2+2.2x+40[/tex]

We know that,

Answer a: Profit = Revenue - Cost

[tex]\Rightarrow P(x) = R(x) - C(x)\\\Rightarrow P(x) = 6x - (0.002x^2+2.2x+40)\\\Rightarrow P(x) = - 0.002x^2+3.8x-40[/tex]

Answer b:

P(100) = ?

Putting value of x as 100 in above equation:

[tex]P(100) = - 0.002\times 100^2+3.8 \times 100-40\\\Rightarrow P(100) = -20+380 -40\\\Rightarrow P(100) = 320[/tex]

Answer c:

P'(x) = ?

Differentiating the equation [tex]P(x) = - 0.002x^2+3.8x-40[/tex]

[tex]P'(x) = -2 \times 0.002 x^{2-1} + 3.8 + 0\\P'(x) = -0.004 x + 3.8[/tex]

Answer d:

P'(100) = ?

Putting x = 100 in equation [tex]P'(x) = -0.004 x + 3.8[/tex]

[tex]P'(100) = -0.004 \times 100 + 3.8\\P'(100) = -0.4 + 3.8\\P'(100) = 3.76[/tex]

Answer:

The boat is approaching the dock at a speed of 3.20 ft/s when it is 4 feet from the dock.

Step-by-step explanation:

The diagram of the situation described is shown in the attached image.

The distance of the boat to the dock along the water level at any time is x

The distance from the person on the dock to the boat at any time is y

The height of the dock is 5 ft.

These 3 dimensions form a right angle triangle at any time with y being the hypotenuse side.

According to Pythagoras' theorem

y² = x² + 5²

y² = x² + 25

(d/dt) y² = (d/dt) (x² + 5²)

2y (dy/dt) = 2x (dx/dt) + 0

2y (dy/dt) = 2x (dx/dt)

When the boat is 4 ft from dock, that is x = 4 ft,

The boat is being pulled at a speed of 2 ft/s, that is, (dy/dt) = 2 ft/s

The speed with which the boat is approaching the dock = (dx/dt)

Since we are asked to find the speed with which the boat is approaching the dock when the boat is 4 ft from the dock

When the boat is 4 ft from the dock, x = 4 ft.

And we can obtain y at that point.

y² = x² + 5²

y² = 4² + 5² = 16 + 25 = 41

y = 6.40 ft.

So, to the differential equation relation

2y (dy/dt) = 2x (dx/dt)

when x = 4 ft,

y = 6.40 ft

(dy/dt) = 2 ft/s

(dx/dt) = ?

2 × 6.40 × 2 = 2 × 4 × (dx/dt)

25.6 = 8 (dx/dt)

(dx/dt) = (25.6/8) = 3.20 ft/s.

Hope this Helps!!!

Answer:

end

January

April

1st blank might also be (account)

Answer:

January and April

Step-by-step explanation:

Answer:

Your correct answer is 31/50 + -4/25 i

Step-by-step explanation:

5+4i/6+8i = 31/50 + -4/25 i

Answer:

The area of the original piece of paper is 60cm

Answer:

the answer is 60

hope it helps :D

Step-by-step explanation:

Answer:

x = -25/3

Step-by-step explanation:

The equation simplifies to -3x - 25 = 0, so

-3x = 25 =>

x = -25/3

Answer:

Step-by-step explanation:

The labor charge is for (6 days/week). In Mongolia, the charge per laborer is then ...

  (6 days/week)($1.10/day) = $6.60/week

The three laborers working 50 weeks/year will have a labor cost of ...

  (3 laborers)($6.60/week/laborer)(50 weeks/year) = $990/year

__

In the US, the labor charge per person per week is ...

  (14 hr/day)(6 day/week) = 84 hr/week

That's 40 hours of straight pay and 44 hours of overtime pay, or ...

  7.25(40 +1.5(44)) = 7.25(106) = 768.50

For 150 person-weeks per year, the total US labor charge is ...

  ($768.50/person/week)(3 persons)(50 weeks/year) = $115,275/year

__

The materials cost for a year is ...

  ($50/rug)(12 rugs/year) = $600/year

__

The revenue is ...

  ($2000/rug)(12 rugs/year) = $24,000/year

Profit is the difference between revenue and the total of costs:

  profit = $24,000 -($990 +600 +10000) = $12410 . . . made in Mongolia

__

So, the table gets filled as follows:

  (labor, material, fixed cost, revenue, profit)

Mongolian-made

  ($990, $600, $10000, $24000, $12410)

US-made

  ($115275, $600, $10000, $24000, -$101,875)

The US labor cost would be $115,275.

_____

Comment

For the given selling price, the break-even labor cost is about $1.06 per hour (on average). At US labor rates, the break-even selling price is about $10,490 per rug.

Answer:

Option (A)

Step-by-step explanation:

For equation of the line,

Let the equation is, y = mx + b

Slope 'm' of the line passing through two points (-3, 4) and (2, -1),

m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

   = [tex]\frac{4+1}{-3-2}[/tex]

   = -1

y-intercept of this line, b = 1

Now we substitute these values in the equation,

y = -x + 1

Let the equation of the parabola is,

y = a(x - h)² + k

Here, (h, k) is the vertex of the parabola,

Since vertex of the given parabola is (0, -5),

then the equation will be,

y = a(x - 0)²- 5

y = ax² - 5

Since a point (2, -1) lies on this parabola,

-1 = a(2)² - 5

5 - 1 = 4a

a = 1

Equation of the parabola will be,

y = x² - 5

Therefore, Option (A) will be the answer.

Answer:

-4*4^7

Step-by-step explanation:

Answer:

-65536

Step-by-step explanation:

I do not think I understand the question but -4*4*4*4*4*4*4*4=-65536

I think there may be missing information like if the question is multiple choice.

Hope that helps

Answer:

Step-by-step explanation:

Time = distance/speed

Considering the first stage,

Speed = 20km/hr

Distance = 5km

Time = 5/20 = 0.25 hour

Considering the second stage,

Speed = 10km/hr

Distance = 5km

Time = 5/10 = 0.5 hour

Considering the third stage,

Speed = 25km/hr

Distance = 5km

Time = 5/25 = 0.2 hour

Considering the third stage,

Speed = 20km/hr

Distance = 5km

Time = 5/20 = 0.25 hour

Therefore, the time it took the biker to complete the race is

0.25 + 0.5 + 0.2 + 0.25 = 1.2 hours

Answer:

you will want to have a good understanding of these properties to make the problems in ... Here, the same problem is worked by grouping 5 and 6 first, 5 + 6 = 11. ... “three times the variable x” can be written in a number of ways: 3x, 3(x), or 3 · x. ... Use the distributive property to evaluate the expression 5(2x – 3) when x = 2.

y

The distributive property tells us that if were given an expression such as 3(x + 2), we can multiply the 3 by both the x and the 2 to get 3x + 6.

Answer:

18

Step-by-step explanation:

4 - (-5) + 04 - (- 5)+0

Negative times negative cancels.

4 + 5 + 4 + 5 + 0

Add the terms.

9 + 9 + 0

= 18

Answer:

Step-by-step explanation:

4-(-5)+04-(-5)+0

4+5+04+5+0

14+04

if you meant 0.4 then, it would be 14.4

if you mean 04 then, it would be 18

Answer:

No. At a significance level of 0.05, there is not enough evidence to support the claim that the mean economic dynamism of middle-income countries is less than the mean for high-income countries (60.29).

Test staitistic t= -1.02

P-value=0.159

Step-by-step explanation:

We have a sample of size n=26, with mean 43.8727 and standard deviation s=82.2857.

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{26}(25.8057+37.4511+51.915+43.6952+47.8506+. . .+21.6643)\\\\\\M=\dfrac{1140.689}{26}\\\\\\M=43.8727\\\\\\s=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2\\\\\\s=\dfrac{1}{25}((25.8057-43.8727)^2+. . . +(21.6643-43.8727)^2)\\\\\\s=\dfrac{2057.1431}{25}\\\\\\s=82.2857\\\\\\[/tex]

This is a hypothesis test for the population mean.

The claim is that the mean economic dynamism of middle-income countries is less than the mean for high-income countries (60.29).

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=60.29\\\\H_a:\mu< 60.29[/tex]

The significance level is 0.05.

The sample has a size n=26.

The sample mean is M=43.8727.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=82.2857.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{82.2857}{\sqrt{26}}=16.138[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{43.8727-60.29}{16.138}=\dfrac{-16.42}{16.138}=-1.02[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=26-1=25[/tex]

This test is a left-tailed test, with 25 degrees of freedom and t=-1.02, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t<-1.02)=0.159[/tex]

As the P-value (0.159) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean economic dynamism of middle-income countries is less than the mean for high-income countries (60.29).

Answer:

A) 715 ways

B) 715 ways

C) (1/715)

Step-by-step explanation:

This is a permutation and combination problem.

Since we want to select a number of people from a larger number of people, we use combination as the order of selection isn't important now.

A) How many different ways can the officers be appointed?

There are 4 officer positions.

There are 13 people in total.

We want to select 4 people from 13

Number of ways to select 4 people from 13 = ¹³C₄ = 715

B) How many different ways can the committee be appointed?

Number of committee members = 4

Total number of people available = 13

Number of ways to select 4 people from 13 = ¹³C₄ = 715

C) What is the probability of randomly selecting the committee members and getting the four youngest of the qualified candidates?

Selecting a group of the youngest candidates is just 1 amongst the total number of ways the 4 committee members can be picked,

Hence, the required probability = (1/715)

Hope this Helps!!!

Answer:

We can call the variable e. "more than" is denoted by > so the inequality is e > 40. To graph it, draw a circle on the tick mark that has 40 underneath it but don't fill in the circle. Then, draw a continuous line to the right of the circle and draw an arrow at the end of it to show that it goes on forever.

Answer:

57.6 km per hr

Step-by-step explanation:

Let us assume the horizontal distance between the ship is constant = x

= 70 Km

The ship A sails south at 40km/h is denoted as 40t

The Ship B sails north at 20 km/h is denoted as 20t

Now the vertical distance separating the two ships is

=  20t + 40t

= 60t

And, the Distance between the ship is changing

[tex]D^2 = y^2 + x^2[/tex]

As x is constant

[tex]\frac{\partial x}{\partial t}$ = 0[/tex]

Now differentiating

[tex]2D \frac{\partial D}{\partial t}$ = 2y $\frac{\partial y}{\partial t}$[/tex]

The distance between two ships is at 4

So,  

vertical distance is

[tex]= 60\times 4[/tex]

= 240

And, the horizontal distance is 70

[tex]D = \sqrt{240^2 + 70^2} = 250[/tex]

[tex]2 \times 250 \frac{\partial D}{\partial T}$ = 2 \times 240 \times 60[/tex]

So, the distance between the ships is  57.6 km per hr

Answer:

2. A) LNM-ONP

3. B) HI

4. A) GH AND HI

Step-by-step explanation:

2. corresponding sides of similar triangle are proportional  and corresponding angles are congruent

3. it seems that triangles are 45-45-90 so GH correspondents with HI

4. JH is geometric mean of line segment making hypotenuse

so JH = [tex]\sqrt{GH*HI}[/tex]

Answer:

97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].

Step-by-step explanation:

We are given that a random sample of tires is chosen and are driven until they wear out and the number of thousands of miles is recorded;

32, 33, 28, 37, 29, 30, 22, 35, 23, 28, 30, 36.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                                P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample average number of miles = [tex]\frac{\sum X}{n}[/tex] = 30.25

            s  = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex] = 4.71

            n = sample of tires = 12

            [tex]\mu[/tex] = population average number of miles

Here for constructing a 97% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 97% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-2.55 < [tex]t_1_1[/tex] < 2.55) = 0.97  {As the critical value of t at 11 degrees of

                                              freedom are -2.55 & 2.55 with P = 1.5%}  

P(-2.55 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 2.55) = 0.97

P( [tex]-2.55 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]2.55 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.97

P( [tex]\bar X-2.55 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.55 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.97

97% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-2.55 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+2.55 \times {\frac{s}{\sqrt{n} } }[/tex] ]

                                        = [ [tex]30.25-2.55 \times {\frac{4.71}{\sqrt{12} } }[/tex] , [tex]30.25+2.55 \times {\frac{4.71}{\sqrt{12} } }[/tex] ]

                                        = [26.78 miles, 33.72 miles]

Therefore, 97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].

Answer:

THEREFORE THE CONFIDENCE INTERVAL from the Z table = ±1.645

Step-by-step explanation:

Confidence level = 95% = 0.95

compound 1

Number of samples ( n1 ) = 243

Average brake life ( x1 ) = 37866 miles

standard deviation ( ∝ ) = 4414 miles

compound 2

number of samples ( n2 ) = 268

Average brake life ( x2 ) = 45789 miles

standard deviation ( ∝ ) = 2368 miles

Determine the 95% confidence interval for the true difference between average lifetimes

significance level (β) = 1 - confidence level = 1 - 0.95 = 0.05

standard error = [tex]\sqrt{\frac{\alpha1^2 }{n1} + \frac{\alpha2^2}{n2} }[/tex]    = [tex]\sqrt{}[/tex]( 4414^2/243) + (2368^2/268) =

critical value = 0.05/2 =Z 0.025 = 1.645

THEREFORE THE CRITICAL VALE from the Z table = ±1.645

Answer:

The lowest score eligible for an award is 92.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

[tex]\mu = 82.2, \sigma = 5[/tex]

If the top 2.5% of test scores receive merit awards, what is the lowest score eligible for an award

The lowest score is the 100 - 2.5 = 97.5th percentile, which is X when Z has a pvalue of 0.975. So X when Z = 1.96. Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.96 = \frac{X - 82.2}{5}[/tex]

[tex]X - 82.2 = 5*1.96[/tex]

[tex]X = 92[/tex]

The lowest score eligible for an award is 92.

Answer:

The correct answer to the following question will be "0.19".

Step-by-step explanation:

So that the above seems to the right answer.

Answer:

[tex]\pm \sqrt{x-16}[/tex] is the inverse of [tex]y = x^2 + 16[/tex]

Step-by-step explanation:

Given that:

[tex]y = x^2 + 16[/tex]

Let us proceed step by step to calculate the inverse:

Step 1: Put [tex]y = f(x)[/tex]

[tex]f(x) = y=x^2 + 16[/tex]

Step 2: Interchange [tex]x[/tex] and [tex]y[/tex]:

[tex]x = y^2 + 16[/tex]

Step 3: Solve the equation to find the value of [tex]y[/tex]:

[tex]y^2 =x- 16\\\Rightarrow y =\pm \sqrt{x- 16}[/tex]

Step 4: Replace [tex]y[/tex] with [tex]f^{-1}(x)[/tex]:

[tex]\Rightarrow y =f^{-1}(x)=\pm \sqrt{x- 16}[/tex]

So, the inverse of [tex]y = x^2 + 16[/tex] is [tex]\pm \sqrt{x- 16}[/tex].

The equation which is the inverse of y = x2 + 16 is; f-¹ = y = ±√(x -16)

To evaluate the inverse of the function, y = x2 + 16.

We must first make x the subject of the formula and swap x and y as follows;

Therefore, the inverse function is;

Read more on inverse function:

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