The elastic potential energy stored in the spring is 0.375 J.
The formula for elastic potential energy is:
E = 1/2 * k * x^2
where:
* E is the elastic potential energy in Joules
* k is the spring constant in N/m
* x is the distance the spring is stretched or compressed from its equilibrium position in meters
In this problem, we have:
* k = 3 N/m
* x = 0.5 m (50 cm)
Substituting these values into the formula, we get:
E = 1/2 * 3 * 0.5^2 = 0.375 J
Therefore, the elastic potential energy stored in the spring is 0.375 J.
Question 1
At one section of a long pipe the velocity of the fluid is 1.6 m/s. At another section of the pipe the diameter is three times greater.
What is the velocity of the fluid at this section?
O 0.533 m/s
○ 4.80 m/s
O Not enough information to tell
O 0.178 m/s
Question 2
Three thermometers are placed in a closed, insulated box and are allowed to reach thermal equilibrium. One is calibrated in
Fahrenheit degrees, one in Celsius degrees, and one in Kelvins. If the Celsius thermometer reads -40 °C the Fahrenheit
thermometer would read -40°F.
True
False
Answer:
Answer 1: The answer is O 0.178 m/s.
Answer 2: True: But in this specific case where the Celsius temperature is -40, the Fahrenheit temperature will also be -40.
So, in short, the answer is:
-40 Celsius is equal to -40 Fahrenheit
Acceleration
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1 2 3 4 5 6 7 8 9 10
Study the motion map shown. Some of the vectors have been circled.
X
What do the circled vectors represent?
distance
speed
velocity
acceleration
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e:
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The circled vectors represents acceleration.
The last option is correct.
How do we explain?
We see in the first motion diagram the length of velocity vector is increasing this shows that the velocity is increasing in the magnitude with time so this is an accelerated motion in which a uniform acceleration must be in the same direction of velocity must be there.
We also notice in the second motion diagram the length of velocity vector is decreasing with time which shows the velocity is decreasing me magnitude which shows a constant deceleration and the direction of acceleration must be opposite to that of velocity.
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27/13 AL + 4/2 He -> ? + 1/On
Please help!!!!!! What’s the missing species???
The missing species of the nuclear reaction obtained is ³⁰₁₅P
How do i determine the missing species?The missing species of the equation can be obtain as follow:
Let the missing species be ʸₓZNow, we can obtain the value of x, y and Z as follow:
²⁷₁₃Al + ⁴₂He -> ʸₓZ + ¹₀n
For x
13 + 2 = x + 0
15 = x
x = 15
For y
27 + 4 = y + 1
31 = y + 1
Collect like terms
y = 31 - 1
y = 30
For Z
ʸₓZ => ³⁰₁₅Z
From the period table, the element with atomic number of 15 is phosphorus, P. Thus, we have
ʸₓZ => ³⁰₁₅Z => ³⁰₁₅P
Therefore, we can write the complete equation as:
²⁷₁₃Al + ⁴₂He -> ³⁰₁₅P + ¹₀n
Thus, the missing species is ³⁰₁₅P
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Chapter 3
#1) State Kepler's three laws in your own words.
#2) Write out Newton's three laws of motion in terms of what happens with the momentum of objects.
3) According to Kepler's second law, where in a planet's orbit would it be moving the fastest?
Where would it be moving the slowest?
#4) The gas pedal, the brakes, and the steering wheel all have the ability to accelerate a car- how?
#5) Explain how a rocket can propel itself using Newton's third law.
#6) A certain material has a mass of 565 g while occupying 50 cm³3 of space. What is this material?
(Hint, Use Table 3.1)
#7) What was the great insight Newton had regarding Earth's gravity that allowed him to develop the
universal law of gravitation?
Kepler's three laws are:
Law 1: Planets move in oval-shaped paths around the Sun, and the Sun is at one of the special points inside this oval shape.Law 2: When a planet gets closer to the Sun, it moves faster. When it gets farther away, it moves slower.Law 3: When a planet takes longer to orbit the Sun, its average distance from the Sun increases.What is Newton's three laws of motionThe Newton's three laws of motion is one that how momentum works.
Law 1: If an object is not moving, it will stay still, and if it is moving, it will keep moving in the same way unless something outside of it makes it stop or change direction.
Law 2: When you push or pull on an object, the object's momentum changes. The faster you push or pull, the more the momentum changes.
Law 3: When you push or pull something, it pushes or pulls back with the same amount of force.
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A satellite weighing 5,400 kg is launched into orbit 3.6400 x 107 m above the center of the earth.
The mass of Earth is 6.0 × 1024 kg. The gravitational constant is 6.673 × 10–11 N•m2/kg2.
The gravitational force of Earth on the satellite is ___
Group of answer choices
9.1 x 10^4
1.6 x 10^3
2.1 x 10^6
Answer:
[tex]\tt F=1.63*10^3 N[/tex]
Explanation:
Gravitational force is defined as the force of attraction between two objects with mass. It is a fundamental force of nature, and it is what keeps us on the ground and what keeps the planets in orbit around the Sun.
The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers
For the Question:
We can use the following formula to calculate the gravitational force between the Earth and the satellite:
[tex]\boxed{\tt F =\frac{ G * M * m }{ r^2}}[/tex]
Where:
F is the gravitational force
G is the gravitational constant[tex]\tt (6.673 * 10^{-11} Nm^2/kg^2)[/tex]
M is the mass of the Earth [tex]\tt (6.0 * 10^24 kg)[/tex]
m is the mass of the satellite[tex]\tt (5,400 kg)[/tex]
r is the distance between the satellite and the center of the Earth [tex]\tt (3.6400 * 10^7 m)[/tex]
Plugging in these values, we get the following:
[tex]\tt F = \frac{6.673 * 10^{-11} * 6.0 * 10^{24}* 5,400 }{ (3.6400 * 10^7 )^2}[/tex]
[tex]\tt F=1.63*10^3 N[/tex]
Therefore, answer is [tex]\tt F=1.63*10^3 N[/tex]
What is Moral subjectivism?
Answer:
What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.
The temperature of a aluminum bar rises by 10.0°C when it absorbs 4.73 kJ of energy by heat. The mass of the bar is 525 g. Determine the specific heat of aluminum from these data. Answer is in kJ/kg · °C.
Answer:
Certainly! We can use the formula:
q = mcΔT
where q is the amount of heat absorbed, m is the mass of the aluminum bar, c is the specific heat capacity of aluminum, and ΔT is the change in temperature.
Substituting the given values, we get:
4.73 kJ = (0.525 kg) x c x (10.0°C)
Solving for c, we get:
c = 0.901 kJ/kg · °C
Therefore, the specific heat of aluminum is 0.901 kJ/kg · °C.
Explanation:
On March 21_occurs where in the length of the day and night are equal
On March 21, an equinox occurs where the length of the day and night are equal. An equinox happens when the Earth's axis is not tilted towards or away from the sun. During an equinox, the sun's rays are equally distributed across the Earth's surface.
The word equinox is derived from the Latin words "aequus" and "nox," which means "equal night."
The equinox occurs twice a year, around March 21 and September 21. During an equinox, the duration of day and night is equal across the entire world.
It means that every place on the planet experiences almost the same amount of daylight and darkness.
On March 21, the vernal equinox, marks the beginning of spring in the Northern Hemisphere, while in the Southern Hemisphere, it marks the beginning of autumn.
The equinox has been considered a significant day in many cultures throughout history. In many cultures, the equinox is celebrated as a time of renewal, rebirth, and fertility. It's also been considered a day of balance, where darkness and light are equal, and the world is in harmony.
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¿Cuál es el trabajo neto en J que se necesita para acelerar un auto de 1500 kg de 55 m/s a 65 m/s?
What is the net work in J required to accelerate a 1500 kg car from 55 m/s to 65 m/s?
The net work done (in J) required to accelerate a 1500 kg car from 55 m/s to 65 m/s is 3127500 J
How do i determine the net work done?First, we shall obtain the initial kinetic energy. Details below:
Mass (m) = 1500 Kginitial velocity (u) = 55 m/sInitial kinetic energy (KE₁) =?KE₁ = ½mu²
= ½ × 1500 × 55²
= 41250 J
Next, we shall final kinetic energy. Details below:
Mass (m) = 1500 KgFinal velocity (v) = 65 m/sFinal kinetic energy (KE₂) =?KE₂ = ½mv²
= ½ × 1500 × 65²
= 3168750 J
Finally, we shall determine the net work done. Details below:
Initial kinetic energy (KE₁) = 41250 JFinal kinetic energy (KE₂) = 3168750 JNet work done (W) =?W = KE₂ - KE₁
= 3168750 - 41250
= 3127500 J
Thus, the net work done is 3127500 J
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