he open circuit voltage of circuit containing ideal sources and resistors is measured at 10 while the current through the short circuit passing through the terminals is 100 . Find the operating point that will occur at the terminals when circuit is connected to circuit consisting of 15 in parallel with 200 .

Answer:

Positively charged objects have electrons; they simply possess more protons than electrons.

Explanation:

2. An object that is electrically neutral contains only neutrons. Electrically neutral atoms simply possess the same number of electrons as protons.

If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion.

If it loses an electron, it becomes positively charged and is known as a cation.

Answer:

The contain both protons and electrons, but they have more protons than electrons making it a positively charged object.

Answer:

"In water, the speed of light is v01.33=2.26 x 108 m/s."

Explanation:

Answer:

[tex]E_{avg}=2.34*10^{-13}J/m^3[/tex]

Explanation:

From the question we are told that:

Frequency [tex]F=800KHz =800*10^3Hz[/tex]

Distance [tex]9.5km=9.5*10^3[/tex]

Electric field amplitude [tex]E=0.23V/m[/tex]

Generally the equation for Average electromagnetic energy density is mathematically given by

 [tex]E_{avg}=\frac{1}{2} \epsilon_0 E^2[/tex]

 [tex]E_{avg}=\frac{1}{2} 8.85*10^{-12}*(0.23)^2[/tex]

 [tex]E_{avg}=\frac{1}{2}* 8.85*10^{-12}*(0.23)^2[/tex]

 [tex]E_{avg}=2.34*10^{-13}J/m^3[/tex]

Therefore the  average electromagnetic energy density at that point

 [tex]E_{avg}=2.34*10^{-13}J/m^3[/tex]

Answer:

F = 580.75 N

Explanation:

The force can be calculated through the following formula:

[tex]F = PA[/tex]

where,

F = Force = ?

P = Pressure = (72 mm Hg)(133.322 Pa/1 mm Hg) = 9599.18 Pa

A = Area = (605 cm²)(1 m²/10⁴ cm²) = 0.0605 m²

Therefore,

[tex]F = (9599.18\ Pa)(0.0605\ m^2)[/tex]

F = 580.75 N

Answer:

The momentum of the object is given by the product of mass and velocity while the impulse is the change of momentum when a large force is applied on an object for a short interval of time.

I would reword it

Hope this helps!!

Answer:

Solution

Explanation:

Solution is a process in chemical weathering and it is the process of dissolving or removing rock in a solution through the activities of acid rain or solution. Chemical weathering refer to the process where rocks interact with chemical solutions or acid rain which can result in His integration.

Answer:

Permanent magnetism (of the steel)

make me brainliestt :))

Answer: The competition policy helps in development of the competition in the authority.

Explanation:

In consumer market competition exists between the producers. The main role of the competition policy is to promote competition in the market. It helps multiple businesses or individuals to utilize their resources efficiently and produce products at best quality and at cheapest prices. It allows the consumers to compare and purchase the better deal. It helps in starting of new businesses and also helps in increase in total production output. It is the result of the natural economic growth.

Answer:

To protect us.

Explanation:

For ex. your dunking on a basketball hoop if that wasn't strong you would fall on your back and get injured.

Answer:

the magnitude of the velocity of one particle relative to the other is 0.9988c

Explanation:

Given the data in the question;

Velocities of the two particles = 0.9520c

Using Lorentz transformation

Let relative velocity be W, so

v[tex]_r[/tex] = ( u + v ) / ( 1 + ( uv / c²) )

since each particle travels with the same speed,

u = v

so

v[tex]_r[/tex] = ( u + u ) / ( 1 + ( u×u / c²) )  

v[tex]_r[/tex] = 2(0.9520c) / ( 1 + ( 0.9520c )² / c²) )  

we substitute

v[tex]_r[/tex] = 1.904c / ( 1 + ( (0.906304 × c² ) / c²) )  

v[tex]_r[/tex] = 1.904c / ( 1 + 0.906304 )

v[tex]_r[/tex] = 1.904c / 1.906304

v[tex]_r[/tex] = 0.9988c

Therefore, the magnitude of the velocity of one particle relative to the other is 0.9988c

Answer:

Explanation:

From the given information:

The missing value are as follows:

The velocity  [tex]v ^{\to} = (2.0 \times 10^6 \ m/s) \hat i + (3.0 \times 10^6 \ m.s) \hat j[/tex]

The uniform magnetic field [tex]B^{\to} = (0.030 T)\hat i -(0.15 T) \hat j[/tex]

The force on electron as a result of the Magnetic field is:

[tex]F^\to = q(v^\to \times B^\to)[/tex]

here;

Change of electron [tex]q = -1.6 \times 10^{-19} C[/tex]

Then,

[tex]v^{\to} \times B^{\to} = \left|\begin{array}{ccc}2\times10^6&3\times 10^6&0\\0.03&-0.15&0\end{array}\right|[/tex]

[tex]= \hat i(0-0) -\hat j ( 0-0) +\hat k (-3\times 10^5 -0.9\times 10^5) \\ \\ =-3.9 \times 10^5 \ k[/tex]

∴

[tex]F^\to = q(v^\to \times B^\to)[/tex]

[tex]F^{\to} = -1.6 \times 10^{-19} \times -3.9 \times 10^5 \\ \\ F^{\to} = 6.24 \times 10^{-14 } \ N[/tex]

For the proton with the same velocity:

[tex]q = 1.6 \times 10^{-19 } \ C \\ \\ F = q (v^\to * B^\to) \ \\ \\ F^\to = q(-3.9 \times 10^5) \\ \\ F = (1.6 \times 10^{-19}) (-3.9 \times 10^5) \\ \\ \mathbf{F ^{\to} = -6.24 \times 10^{-14} \ N}[/tex]

Atoms are composed of protons, [tex]\sf\purple{neutrons}[/tex]and electrons. ✅

[tex]\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆[/tex]

Answer:

The right solution is "0.511".

Explanation:

Given:

Initial moment of inertia,

= 1630 kg.m²

Radius,

= 5 m

Angular speed,

= 1.6 rad/s

Now,

The moment of inertia after stepping on will be:

= [tex]1630+2\times (69.5\times (5)^2)[/tex]

= [tex]1630+2\times (69.5\times 25)[/tex]

= [tex]5105 \ Kg.m^2[/tex]

hence,

As per the question, the angular speed is conserved, then

⇒ [tex]1630\times 1.6=5105\times \omega'[/tex]

            [tex]2608=5105\times \omega'[/tex]

                [tex]\omega'=\frac{2608}{5105}[/tex]

                     [tex]=0.511[/tex]

Answer:

 h = 1.5 m

Explanation:

This exercise must be solved using the concepts of energy.

Starting point. Place where the car leaves

          Em₀ = U = m g h

Final point. Highest part of the loop, r = 2R

          Em_f = K + U

          Em_f = ½ m v² + mg (2R)

the energy is preserved

          Em₀ = Em_f

          m g h = ½ m v² + m g 2R               (1)

the car must have a minimum velicate so that it does not fall, let's use Newton's second law.

         ∑ F = m a

         N + W = m a

acceleration is centripetal

          a = v²/ r

the normal is the reaction of the surface to the support of the car, as the speed decreases, the normal decreases until reaching zero

         0 + m g = m v² / r

         v² =  rg

we substitute

        v² = 2Rg

we substitute in equation 1

          g h = ½ 2Rg + 2Rg

          h = 3R

let's calculate

          h = 3 0.5

          h = 1.5 m

The correct option is E. Increase her speed​

High-diving is the process or way in which a person jump into water  or swimming pool from a higher heights.

A Diver  is a person who dive or Fall into a water from a top board or diving board .

Therefore she was curving her body from the top board in order to Increase her speed​ which will enable her to spin or flip more faster.

Inconclusion The correct option is E. Increase her speed.

Learn more about Diving here:

https://brainly.com/question/2784286

Answer: 0.00693

Explanation:

Given

Spring constant [tex]k=2\ N/m[/tex]

Mass of object [tex]m=75\ g[/tex]

The amplitude of the oscillation decreases from 10 mm to 5 mm  in 15 s

Equation of amplitude for the ideal spring-mass system is

[tex]\Rightarrow A=A_oe^{-\frac{bt}{2m}}\quad \quad [\text{b=damping constant}]\\\text{Insert the values}\\\\\Rightarrow 5=10e^{\frac{b\times 15}{2\times 0.075}}\\\\\Rightarrow e^{-\frac{b\times 15}{2\times 0.075}}=0.5\\\\\text{Taking natural log both sides}\\\\\Rightarrow \ln \left(e^{-\frac{b\times 15}{2\times 0.075}}\right)=\ln 0.5\\\\\Rightarrow -\dfrac{15b}{0.15}=-0.693\\\\\Rightarrow b=0.00693[/tex]

Answer:

Electric generator, also called dynamo, any machine that converts mechanical energy to electricity for transmission and distribution over power lines to domestic, commercial, and industrial customers. Generators also produce the electrical power required for automobiles, aircraft, ships, and trains.

Answer:

Electric motors are used in a broad range of industrial, commercial, and residential, applications, such as fans, pumps, compressors, elevators, and refrigerators. ... DC motors are used for variable speed control applications such as industrial machinery and motor vehicles.

In electricity generation, a generator is a device that converts mechanical energy to electrical energy for use in an external circuit. Generators provide nearly all of the power for electric power grids.

Hope it helps

Answer:

the required minimum length of the attenuator is 3.71 cm

Explanation:

Given the data in the question;

we know that;

[tex]f_{c_1[/tex] = c / 2a

where f is frequency, c is the speed of light in air and a is the plate separation distance.

we know that speed of light c = 3 × 10⁸ m/s = 3 × 10¹⁰ cm/s

plate separation distance a = 7.11 mm = 0.0711 cm

so we substitute

[tex]f_{c_1[/tex] = 3 × 10¹⁰ / 2( 0.0711  )

[tex]f_{c_1[/tex] = 3 × 10¹⁰ cm/s / 0.1422  cm

[tex]f_{c_1[/tex] =  21.1 GHz which is larger than 15 GHz { TEM mode is only propagated along the wavelength }

Now, we determine the minimum wavelength required

Each non propagating mode is attenuated by at least 100 dB at 15 GHz

so

Attenuation constant TE₁ and TM₁ expression is;

∝₁ = 2πf/c × √( ([tex]f_{c_1[/tex] / f)² - 1 )

so we substitute

∝₁ = ((2π × 15)/3 × 10⁸ m/s) × √( (21.1 / 15)² - 1 )

∝₁ = 3.1079 × 10⁻⁷

∝₁ = 310.79 np/m

Now, To find the minimum wavelength, lets consider the design constraint;

20log₁₀[tex]e^{-\alpha _1l_{min[/tex] = -100dB

we substitute

20log₁₀[tex]e^{-(310.7np/m)l_{min[/tex] = -100dB

[tex]l_{min[/tex] = 3.71 cm

Therefore, the required minimum length of the attenuator is 3.71 cm

Answer:

Solution given:

North car

mass[m1]=1460kg

velocity[u1]=27 m/s

mass[m2]=2165kg

velocity [u2]=18m/s

let v be velocity after collision

we have

From the principle of conservation of linear momentum

m1u1+m2u2=(m1+m2)v

1460*27+2165*18=(1460+2165)v

v=[tex] \frac{78390}{3625} [/tex]

v=21.6m/s

the speed after the collision in 21.6 m/s.

For angle.

Tan angle =[tex] \frac{m1u1}{m2u2} [/tex]

Tan angle =[tex] \frac{1460*27}{2165*18} [/tex]

Tan angle=327.74

angle=Tan-¹(327.74)=89.82=90°

in degrees north of east is 90°

Answer:

Explanation:

b) light

Answer: 0.0488 mm

Explanation:

Given

The position of the screen is [tex]D=0.80\ m[/tex]

Distance between alternating bright fringes is [tex]0.95\ cm[/tex]

The wavelength of the light source is [tex]\lambda =580\ nm[/tex]

Distance between successive bright fringes is [tex]\frac{\lambda D}{d}[/tex]

Distance between alternating bright fringes is half of the distance between successive fringes i.e. [tex]\frac{\lambda D}{2d}[/tex]

Insert the values for alternating fringes

[tex]\Rightarrow 0.95\times 10^{-2}=\dfrac{580\times 10^{-9}\times 0.8}{d}\quad [\text{d=separation of the doubleslits}]\\\\\Rightarrow d=\dfrac{464\times 10^{-9}}{0.95\times 10^{-2}}\\\\\Rightarrow d=488.42\times 10^{-7}\ m\\\Rightarrow d=0.0488\ mm[/tex]

Complete question is;

A copper wire has a diameter of 4.00 × 10^(-2) inches and is originally 10.0 ft long. What is the greatest load that can be supported by this wire without exceeding its elastic limit? Use the value of 2.30 × 10⁴ lb/in² for the elastic limit of copper.

Answer:

F_max = 28.9 lbf

Explanation:

Elastic limit is simply the maximum amount of stress that can be applied to the wire before it permanently deform.

Thus;

Elastic limit = Max stress

Formula for max stress is;

Max stress = F_max/A

Thus;

Elastic limit = F_max/A

F_max is maximum load

A is area = πr²

We have diameter; d = 4 × 10^(-2) inches = 0.04 in

Radius; r = d/2 = 0.04/2 = 0.02

Plugging in the relevant values into the elastic limit equation, we have;

2.30 × 10⁴ = F_max/(π × 0.02²)

F_max = 2.30 × 10⁴ × (π × 0.02²)

F_max = 28.9 lbf

Answer:

a natural mixture of sand, gravel, and crushed stone

Explanation:

Soil formation occurs as a result of the the decay or the remains of plants and animals which are used up.

Weathering can be defined as the physical and chemical breakdown of rock into smaller pieces called sediment. Weathering can be classified into two categories namely;

I. Physical weathering : it is the process of breaking rocks into pieces without affecting its chemical composition e.g temperature, abrasion and frost action.

II. Chemical weathering : it is the process of breaking rocks into pieces by chemical action which leads to changes in its chemical composition e.g carbonation, hydration, plant acid and oxidation.

In Science, one of the type of land resource is generally referred to as an aggregate.

Typically, an aggregate is a natural mixture of sand, gravel, and crushed stone. It's a heterogeneous mixture that is commonly mixed with bitumen, gypsum, cement, lime and several other adhesive to form mortar or concrete which are used in building and constructions.

Answer:

C

Explanation:

It's correct have a nice day

Answer:

Transverse.

Explanation:

Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.

An electromagnetic spectrum refers to a range of frequency and wavelength that an electromagnetic wave is distributed or extends. The electromagnetic spectrum comprises of gamma rays, visible light, ultraviolet radiation, x-rays, radio waves, and infrared radiation.

A transverse wave can be defined as a type of wave in which particles of the medium of propagation oscillates or vibrates in a direction that is perpendicular to the direction that the wave moves i.e at right angle to the direction of propagation of the wave.

Basically, sound is a transverse and all transverse wave are the direct opposite of a longitudinal wave that usually travel in the same direction of its oscillation.

Hence, this wave is transverse.

Answer:

Density is the ratio between the mass and the volume of a body. Relative density, on the other hand, is the ratio between the density of an object (substance) and the density of some other reference object (substance) at some given temperature.

Explanation:

Answer:

Static friction acts on stationary objects while kinetic friction acts on those in motion. Static friction is always greater or equal to kinetic friction. This can explain why objects often take more force to get in motion than it takes to continue their motion.

Answer:

visible and ultraviolet

Answer:

Explanation:

From the options given,

The atmospheric features of Neptune are easier to see than those of Uranus because Neptune has more methane

Neptune has small amount of methane and water which gives it blue colour and white patches which distinguish it from uranus

For more information, visit

http://abyss.uoregon.edu/~js/ast121/lectures/lec20.html