Hair grows on your head faster than any other place on your body. Sue was interested in figuring out how fast her hair grows so she measured the growth. After 15 days her hair grew 3 mm. After 50 days, it grew 10 mm. If hair growth can be represented by a linear growth, then a) write a function for the growth G(x) as a function of x= number of days b) how long did it take Sue's hair to grow 17 mm?

Answer:

Step-by-step explanation:

area of a triangle = 1/2 * base * height

                             = 1/2 * 12 * 17

                             = 102 cm²

Answer:

number of $20 bill = 4

Number of $5 bill = 5

Step-by-step explanation:

Given that:

Total number of $5 and $20 bills = 9

Let :

Number of $5 bills = x

Number of $20 bills = y

Combined worth of all bills = $105

x + y = 9 - - - (1)

5x + 20y = 105 - - - (2)

From (1)

x = 9 - y

Substitute x = 9 - y into (2)

5(9 - y) + 20y = 105

45 - 5y + 20y = 105

15y = 105 - 45

15y = 60

y = 60/15

y = 4

x = 9 - y

x = 9 - 4 = 5

Hence,

number of $20 bill = 4

Number of $5 bill = 5

Answer:

-6

Step-by-step explanation:

Answer:

1.B

2.D

3.A

4.E

5.C

Step-by-step explanation:

Answer:

The solution is too long. So, I included them in the explanation

Step-by-step explanation:

This question has missing details. However, I've corrected each question before solving them

Required: Determine the inverse

1:

[tex]f(x) = 25x - 18[/tex]

Replace f(x) with y

[tex]y = 25x - 18[/tex]

Swap y & x

[tex]x = 25y - 18[/tex]

[tex]x + 18 = 25y - 18 + 18[/tex]

[tex]x + 18 = 25y[/tex]

Divide through by 25

[tex]\frac{x + 18}{25} = y[/tex]

[tex]y = \frac{x + 18}{25}[/tex]

Replace y with f'(x)

[tex]f'(x) = \frac{x + 18}{25}[/tex]

2. [tex]g(x) = \frac{12x - 1}{7}[/tex]

Replace g(x) with y

[tex]y = \frac{12x - 1}{7}[/tex]

Swap y & x

[tex]x = \frac{12y - 1}{7}[/tex]

[tex]7x = 12y - 1[/tex]

Add 1 to both sides

[tex]7x +1 = 12y - 1 + 1[/tex]

[tex]7x +1 = 12y[/tex]

Make y the subject

[tex]y = \frac{7x + 1}{12}[/tex]

[tex]g'(x) = \frac{7x + 1}{12}[/tex]

3: [tex]h(x) = -\frac{9x}{4} - \frac{1}{3}[/tex]

Replace h(x) with y

[tex]y = -\frac{9x}{4} - \frac{1}{3}[/tex]

Swap y & x

[tex]x = -\frac{9y}{4} - \frac{1}{3}[/tex]

Add [tex]\frac{1}{3}[/tex] to both sides

[tex]x + \frac{1}{3}= -\frac{9y}{4} - \frac{1}{3} + \frac{1}{3}[/tex]

[tex]x + \frac{1}{3}= -\frac{9y}{4}[/tex]

Multiply through by -4

[tex]-4(x + \frac{1}{3})= -4(-\frac{9y}{4})[/tex]

[tex]-4x - \frac{4}{3}= 9y[/tex]

Divide through by 9

[tex](-4x - \frac{4}{3})/9= y[/tex]

[tex]-4x * \frac{1}{9} - \frac{4}{3} * \frac{1}{9} = y[/tex]

[tex]\frac{-4x}{9} - \frac{4}{27}= y[/tex]

[tex]y = \frac{-4x}{9} - \frac{4}{27}[/tex]

[tex]h'(x) = \frac{-4x}{9} - \frac{4}{27}[/tex]

4:

[tex]f(x) = x^9[/tex]

Replace f(x) with y

[tex]y = x^9[/tex]

Swap y with x

[tex]x = y^9[/tex]

Take 9th root

[tex]x^{\frac{1}{9}} = y[/tex]

[tex]y = x^{\frac{1}{9}}[/tex]

Replace y with f'(x)

[tex]f'(x) = x^{\frac{1}{9}}[/tex]

5:

[tex]f(a) = a^3 + 8[/tex]

Replace f(a) with y

[tex]y = a^3 + 8[/tex]

Swap a with y

[tex]a = y^3 + 8[/tex]

Subtract 8

[tex]a - 8 = y^3 + 8 - 8[/tex]

[tex]a - 8 = y^3[/tex]

Take cube root

[tex]\sqrt[3]{a-8} = y[/tex]

[tex]y = \sqrt[3]{a-8}[/tex]

Replace y with f'(a)

[tex]f'(a) = \sqrt[3]{a-8}[/tex]

6:

[tex]g(a) = a^2 + 8a- 7[/tex]

Replace g(a) with y

[tex]y = a^2 + 8a - 7[/tex]

Swap positions of y and a

[tex]a = y^2 + 8y - 7[/tex]

[tex]y^2 + 8y - 7 - a = 0[/tex]

Solve using quadratic formula:

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]a = 1[/tex] ; [tex]b = 8[/tex]; [tex]c = -7 - a[/tex]

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes

[tex]y = \frac{-8 \±\sqrt{8^2 - 4 * 1 * (-7-a)}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{64 + 28 + 4a}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 }[/tex]

Factorize

[tex]y = \frac{-8 \±\sqrt{4(23 + a)}}{2 }[/tex]

[tex]y = \frac{-8 \±2\sqrt{(23 + a)}}{2 }[/tex]

[tex]y = -4 \±\sqrt{(23 + a)}[/tex]

[tex]g'(a) = -4 \±\sqrt{(23 + a)}[/tex]

7:

[tex]f(b) = (b + 6)(b - 2)[/tex]

Replace f(b) with y

[tex]y = (b + 6)(b - 2)[/tex]

Swap y and b

[tex]b = (y + 6)(y - 2)[/tex]

Open Brackets

[tex]b = y^2 + 6y - 2y - 12[/tex]

[tex]b = y^2 + 4y - 12[/tex]

[tex]y^2 + 4y - 12 - b = 0[/tex]

Solve using quadratic formula:

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]a = 1[/tex] ; [tex]b = 4[/tex]; [tex]c = -12 - b[/tex]

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes

[tex]y = \frac{-4\±\sqrt{4^2 - 4 * 1 * (-12-b)}}{2*1}[/tex]

[tex]y = \frac{-4\±\sqrt{4^2 - 4 *(-12-b)}}{2}[/tex]

Factorize:

[tex]y = \frac{-4\±\sqrt{4(4 - (-12-b))}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{(4 - (-12-b))}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{(4 +12+b)}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{16+b}}{2}[/tex]

[tex]y = -2\±\sqrt{16+b}[/tex]

Replace y with f'(b)

[tex]f'(b) = -2\±\sqrt{16+b}[/tex]

8:

[tex]h(x) = \frac{2x+17}{3x+1}[/tex]

Replace h(x) with y

[tex]y = \frac{2x+17}{3x+1}[/tex]

Swap x and y

[tex]x = \frac{2y+17}{3y+1}[/tex]

Cross Multiply

[tex](3y + 1)x = 2y + 17[/tex]

[tex]3yx + x = 2y + 17[/tex]

Subtract x from both sides:

[tex]3yx + x -x= 2y + 17-x[/tex]

[tex]3yx = 2y + 17-x[/tex]

Subtract 2y from both sides

[tex]3yx-2y =17-x[/tex]

Factorize:

[tex]y(3x-2) =17-x[/tex]

Make y the subject

[tex]y = \frac{17 - x}{3x - 2}[/tex]

Replace y with h'(x)

[tex]h'(x) = \frac{17 - x}{3x - 2}[/tex]

9:

[tex]h(c) = \sqrt{2c + 2}[/tex]

Replace h(c) with y

[tex]y = \sqrt{2c + 2}[/tex]

Swap positions of y and c

[tex]c = \sqrt{2y + 2}[/tex]

Square both sides

[tex]c^2 = 2y + 2[/tex]

Subtract 2 from both sides

[tex]c^2 - 2= 2y[/tex]

Make y the subject

[tex]y = \frac{c^2 - 2}{2}[/tex]

[tex]h'(c) = \frac{c^2 - 2}{2}[/tex]

10:

[tex]f(x) = \frac{x + 10}{9x - 1}[/tex]

Replace f(x) with y

[tex]y = \frac{x + 10}{9x - 1}[/tex]

Swap positions of x and y

[tex]x = \frac{y + 10}{9y - 1}[/tex]

Cross Multiply

[tex]x(9y - 1) = y + 10[/tex]

[tex]9xy - x = y + 10[/tex]

Subtract y from both sides

[tex]9xy - y - x = y - y+ 10[/tex]

[tex]9xy - y - x = 10[/tex]

Add x to both sides

[tex]9xy - y - x + x= 10 + x[/tex]

[tex]9xy - y = 10 + x[/tex]

Factorize

[tex]y(9x - 1) = 10 + x[/tex]

Make y the subject

[tex]y = \frac{10 + x}{9x - 1}[/tex]

Replace y with f'(x)

[tex]f'(x) = \frac{10 + x}{9x -1}[/tex]

To get the answer to this question we would have to calculate how much each DVD costs in each scenario.

To do this we will divide each cost by the total number of CDS:

[tex]\frac{2.30}{10} = .23[/tex]

[tex]\frac{10.50}{50} = .21[/tex]

For the pack of 10 CDS each CD costs 23 cents. On the contrary, for the pack of 50 CDs each CD costs 21 cents. Therefore to get a better deal, you would want to go with the 50 CDs.

Hope this helps!

- Kay

The cost per CD is lower when buying the package of 50 CDs, it is the better buy. You would save money by purchasing the package of 50 CDs for $10.50.

To determine which is the better buy, we need to compare the cost per CD in both scenarios.

Let's first calculate the cost per CD when buying 10 CDs:

Cost for 10 CDs = $2.30

Cost per CD = $2.30 / 10 CDs = $0.23 per CD

Now, let's calculate the cost per CD when buying a package of 50 CDs:

Cost for 50 CDs = $10.50

Cost per CD = $10.50 / 50 CDs = $0.21 per CD

Comparing the two options:

- Buying 10 CDs individually costs $0.23 per CD.

- Buying a package of 50 CDs costs $0.21 per CD.

To know more about cost per CD :

https://brainly.com/question/31803043

#SPJ2

Answer:

55 push ups

Step-by-step explanation:

Given that:

Starting count = 10

Additional count = 3

Starting count + (additional count * number of days)

Exactly on the 3rd week = on the 15th day

10 + (3 * 15)

10 + 45

= 55 push ups

Answer:

42.5

Step-by-step explanation:

x                      15

_                       _

85                   100

15x85=1275

1275/100=127.5

127.5-85=42.5

Answer:

67

Step-by-step explanation:

Use the average formula: average = sum of elements / number of elements

Let x represent the score of their last game, and plug in the average, other scores, and number of elements into the equation:

56 = (48 + 57 + 52 + x) / 4

Simplify:

56 = (157 + x) / 4

Solve for x, by first multiplying each side by 4:

224 = 157 + x

Subtract 157 from both sides:

67 = x

So, the score of their last game was 67.

Answer:

? = 130°

Step-by-step explanation:

The sum of all angles inside a triangle is always 180°.

180 - 20 - 30 = 130°

130° is vertical to the ?, therefore, the ? = 130°

hope this helps :)

Answer:

7

Step-by-step explanation:

7 is not a factor of 48, since 7 can not be multiplied by another whole number to get 48. (48 divided by 7 is 6.8)

Answer:

7

Step-by-step explanation:

Answer:

B. {-21.-7. 7. 21)

Step-by-step explanation:

The set made up of odd numbers and multiples of 7 is given as;

       {-21.-7. 7. 21)

Multiples of 7 are usually those numbers where 7 is  factor.

Odd numbers are numbers that cannot be divide by 2.

 So, the most fitting answer is B.

Answer:

5/8

Step-by-step explanation:

1/4=2/8

7/8-2/8=5/8

Answer:

Y equals -1/5

Answer:

y = -0.2

General Formulas and Concepts:

Pre-Algebra

Step-by-step explanation:

Step 1: Define equation

[tex]\frac{3.6}{0.2(6y + 1)} =\frac{9}{0.5y}[/tex]

Step 2: Solve for y

Step 3: Check

Plug in y to verify it's a solution.

Here we see that -90 does indeed equal -90. ∴ y = -0.2 is indeed a solution of the equation.

Answer:

it is D.... PERIODT

Step-by-step explanation:

Answer:

[tex]101 * 102 = 10302[/tex]

Step-by-step explanation:

Given

[tex](x + a)(x + b) = x^2 + (a + b)x + ab[/tex]

Required

Find 101 * 102

[tex]101 * 102 =[/tex]

Express as a sum of 100

[tex](100 + 1) * (100 + 2)[/tex]

Compare this to [tex](x + a)(x + b)[/tex]

We have that:

[tex]x = 100[/tex]

[tex]a = 1[/tex]

[tex]b = 2[/tex]

Recall that:

[tex](x + a)(x + b) = x^2 + (a + b)x + ab[/tex]

Substitute 100 for x, 1 for a and 2 for b

[tex](100 + 1) * (100 + 2) = 100^2 + (1 + 2) * 100 + 1 * 2[/tex]

[tex](100 + 1) * (100 + 2) = 100^2 + 3 * 100 + 2[/tex]

[tex](100 + 1) * (100 + 2) = 10000 + 300 + 2[/tex]

[tex](100 + 1) * (100 + 2) = 10302[/tex]

Hence:

[tex]101 * 102 = 10302[/tex]

Answer:

7.85mph

Step-by-step explanation:

19.625mi / 2.5hr = 7.85mph

Answer:

Step-by-step explanation:

I know that

Answer:

1. 0.333 No

2. 0.3 or 0.300 Yes

3. 0.667 No

Step-by-step explanation:

Answer:

Step-by-step explanation:

h=V/lw

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y  grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

[tex]\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\[/tex]

[tex]\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)[/tex]  [as x+y=14]

[tex]\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\[/tex]

[tex]\Rightarrow x =(25 \times 14)/32=10.9375[/tex] grams

and [tex]y = 14-x= 14-10.9375=3.0625[/tex] grams.

Hence, 10.9375 grams of 82% gold and 3.0625  grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y  grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

[tex]\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\[/tex]

[tex]\Rightarrow x =(50 \times 14)/57=12.28[/tex] grams

and [tex]y = 14-x= 14-12.28=1.72[/tex] grams.

Hence, 12.28 grams of 82% gold and 1.72  grams of 50% gold added to make 14 grams of 75% gold.

Answer:

C) (5, ∞)

General Formulas and Concepts:

Alg I

Step-by-step explanation:

According to the graph, we have a horizontal asymptote at y = 5. Therefore, the graph never actually touches/reaches the y-value 5. Therefore, 5 is not included in our range:

(5, ∞) or y ≥ 5

Answer:

20

Step-by-step explanation:

Evaluate for y= −5

(−5)2+(2)(−5)+5

(−5)2+(2)(−5)+5

=20

Answer:

alternate exterior angles

Step-by-step explanation:

Answer: adjacent angles

explanation: both angles share the same side.

Answer:

A, C, D are true.

Step-by-step explanation:

Answer: A,B,C,D

Step-by-step explanation:

ALL ARE TRUE I JUST TOOK THE TEST A P E X

Answer:

r = 5y/8

Step-by-step explanation:

isolate the variable by dividing each side by factors that contain the variable.

Answer:

rise : atmospheric pressure increases

fall : atmospheric pressure decreases

Step-by-step explanation:

In the context, it is given that a weather forecaster takes the help of the barometer to check the air pressure and predicts the weather. The column of mercury level in the barometer shows a rise or fall in the glass tube as the weight of the atmosphere falling on the mercury surface changes.

Here it is given that the mercury rises for 0.02 in, then it falls 0.09 in,  it then rises by 0.07 in and then again falls by 0.18 in. The word "rise" here shows that the weight of the atmosphere is more. In other words, increase in atmospheric pressure increases the level of mercury in the glass tube and the decrease in or "fall" in the mercury level shows the drop in atmospheric pressure.

Answer:

(C).  AB←→⊥PQ←→

Step-by-step explanation:

This is the only suitable answer to produce a triangle △CMR which is a right triangle.

When we will draw Line AB And PQ which they are intersecting And to produce a right triangle by taking two random points ( C on AB and  P on PQ).

Then AB and PQ must be Perpendicular to each other, only then a triangle CMR will be right angled at M.

Answer:

Emily's claim is correct that with 12 skewers which can hold 5 shrimp each, there will be 15 leftovers.

Step-by-step explanation:

Given that:

Total number of shrimp contained in the bag of Emily = 75

Number of skewers available = A dozen

A dozen means 12.

Therefore, there are 12 number of skewers available.

Each skewer can have = 5 number of shrimp

Total number of shrimp on the 12 skewers = 12 [tex]\times[/tex] 5 = 60

Total number of leftover = Total number of shrimp in the bag - Total number of shrimp on the 12 skewers = 75 - 60 = 15

Therefore, Emily's claim is correct that with 12 skewers which can hold 5 shrimp each, there will be 15 leftovers.

Step-by-step explanation:

the regular form of r=8