Answer:
[tex]20.4\:\text{m}[/tex]
Explanation:
We can use the following kinematics equation to find the height of the chairlift above the snow:
[tex]v_f^2=v_i^2+2a\Delta y[/tex].
First, let's convert 72 km/h to m/s:
[tex]72\: \text{km/h}=20\:\text{m/s}[/tex]
Since the ski starts with an initial vertical velocity of zero, we have [tex]v_i=0[/tex]. We can now substitute [tex]v_f=20,v_i=0, a=9.8[/tex] and solve for how high the chairlift is above the snow:
[tex]20^2=0^2+2\cdot9.8\cdot \Delta y,\\400=19.6\cdot \Delta y,\\\Delta y =\frac{400}{19.6}=\boxed{20.4\:\text{m}}[/tex].
write the dimensional formula of gravitational constant and specific heat capacity.
Answer:
SEE EXPLANATION
Explanation:
The dimensional formula of gravitational constant is given by,
M^-1 L^3 T^-2
Where,
M = Mass
L = Length
T = Time
Dimensional formula of Specific Heat Capacity =[ M^0L^2T^-2K^-1]
The yearly whole-body dose caused by radioactive 40K absorbed in our tissues is 17 mrem. Note: 40K also emits gamma rays, many of which leave the body before being absorbed. Because fatty tissue has low potassium concentration and muscle has a higher concentration, gamma ray emissions indicate indirectly a person's fat content. Assuming that 40K undergoes beta decay with an RBE of 1.4 , determine the absorbed dose in rads. How much beta ray energy does an 75-kg person absorb in one year? Use that 1rad=10^−2J/kg .
Answer:
The beta ray Energy (E) absorbed = 0.009105 Joules
Explanation:
The absorbed dose rate in the tissue can be determined by using the known formula:
Dose equivalent = absorbed dose × relative biological effective (RBE)
[tex]absorbed \ dose = \dfrac{Dose \ equivalent}{RBE}[/tex]
[tex]absorbed \ dose = \dfrac{17 \times 10^{-3} \ rem}{1.4}[/tex]
absorbed dose = 12.14 × 10⁻³ rad
absorbed dose = 12.14 m rad
However, since the absorbed dose is determined, the energy absorbed in one year is can be expressed as:
Energy (E) = mass × absorbed rate
Energy (E) = 75 kg × 12.14 × 10⁻³ rad
Energy (E) = 75 kg × 12.14 × 10⁻³× 10⁻² J/kg
Energy (E) = 75 × 12.14 × 10⁻³× 10⁻² Joules
Energy (E) = 0.009105 Joules
speed of light in a substance with refractive index of 1.70
in a simple machine the input work is 187.5 N and output work is 125N. If load distance is 25 cm and effort distance is 75 cm calculate value of load and effort
Answer:
1. Laod = 500 N
2. Effort = 250 N
Explanation:
From the question given above, the following data were obtained:
Input work = 187.5 J
Output work = 125 J
Load distance = 25 cm
Effort distance = 75 cm
1. Determination of the load.
Output work = 125 J
Load distance = 25 cm = 25/100 = 0.25 m
Load =?
Output work = Load × Load distance
125 = Load × 0.25
Divide both side by 0.25
Load = 125 / 0.25
Laod = 500 N
2. Determination of the effort.
Input work = 187.5 J
Effort distance = 75 cm = 75/100 = 0.75 m
Effort =?
Input work = Effort × Effort distance
187.5 = Effort × 0.75
Divide both side by 0.75
Effort = 187.5 / 0.75
Effort = 250 N
Does a ball rolling on an inclined plane have the same acceleration on the way up as it does on the way down?
Answer:
No, it does not.
Explanation:
According to the Law of Gravitation, something going down has more kinetic energy than something going up because it attracts pressure from around it when going down. When it goes up, it has less gravitational force and inertia also stops the ball from rolling upward. Therefore, without the amount of kinetic energy, it will not have the same amount of acceleration.
A book is sitting on a table. The book is
applying a 65 N down on the table.
How much force is the table exerting on the
book?
Answer:
65 Newtons
Explanation:
A book is kept on the table. The book is applying 65 N of force down on the table. So the table will also apply 65 N force to the book.
What is Force?According to physics, a force is an effect that has the power to change an object's motion. A force can cause a massed item to accelerate or modify its velocity. A push or a pull is a straightforward method to explain force. Considering that a force has both a magnitude and a direction, it is a vector quantity.
The pace at which an object's direction changes when it is traveling is referred to as its velocity, and is measured by a particular unit of time and from a particular point of view.
When the book is applying force on the table that is mg, and it is 65 N the table will also generate a normal reaction force which will be equal to the force applied by the book which is 65 N.
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1. What kind of force is the force of gravity? (1 Point) contact force
non-contact force electromagnetic force imaginary force
Answer:
the answer is electromagnetic force because gravity is a force of attraction
Find the magnitude of the free-fall acceleration at the orbit of the Moon (a distance of 60RE from the center of the Earth with the radius of RE). Use the gravitational acceleration on the surface of the Earth is 9.8m/s2.
Answer:
The magnitude of the free-fall acceleration at the orbit of the Moon is [tex]2.728\times 10^{-3}\,\frac{m}{s^{2}}[/tex] ([tex]\frac{2.784}{10000}\cdot g[/tex], where [tex]g = 9.8\,\frac{m}{s^{2}}[/tex]).
Explanation:
According to the Newton's Law of Gravitation, free fall acceleration ([tex]g[/tex]), in meters per square second, is directly proportional to the mass of the Earth ([tex]M[/tex]), in kilograms, and inversely proportional to the distance from the center of the Earth ([tex]r[/tex]), in meters:
[tex]g = \frac{G\cdot M}{r^{2}}[/tex] (1)
Where:
[tex]G[/tex] - Gravitational constant, in cubic meters per kilogram-square second.
[tex]M[/tex] - Mass of the Earth, in kilograms.
[tex]r[/tex] - Distance from the center of the Earth, in meters.
If we know that [tex]G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}[/tex], [tex]M = 5.972\times 10^{24}\,kg[/tex] and [tex]r = 382.26\times 10^{6}\,m[/tex], then the free-fall acceleration at the orbit of the Moon is:
[tex]g = \frac{\left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot (5.972\times 10^{24}\,kg)}{(382.26\times 10^{6}\,m)^{2}}[/tex]
[tex]g = 2.728\times 10^{-3}\,\frac{m}{s^{2}}[/tex]
Which of the following does not represent a significant negative environmental impact of using nuclear fuel? a. air pollution b. mining c. radiation d. waste production Please select the best answer from the choices provided A B C D
A significant negative environmental impact of using nuclear fuel is mining. The correct option is b.
What is mining?Mining is the process or industry of obtaining coal or other minerals from a mine.
Using nuclear fuels for mining will have no negative impact on the environment. All other terms represent negative impact of nuclear fuel Thus, The correct option is b.
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22. Explain why it is better to increase the biodiversity of ecosystem.
Answer: because increasing biodiversity can influence ecosystem functions such as productivity and variety and even the likelihood that a particular species is discovered by a comminity
Explanation:
A scientist wants to create a new material using nanotechnology. In which size range will she be working? 1 nm to 100 nm 1 to 10,000 nm 100 to 1000 nm 100 to 10,000 nm
Answer:
I believe it’s A
Explanation:
Answer:
A is correct (1 nm to 100 nm)
Explanation:
I just took the exam
3.6 Make innovative suggestions on how you could instill healthy environmental values
in communities.
You could hold rallies which attract a lot of people, they come and you discuss apon making the world a better place and how you want to shape the society.
What is the definition of Heat Transfer
Answer:
Heat transfer is an engineering discipline that concerns the generation, use, conversion, and exchange of heat (thermal energy) between physical systems.
Explanation:
Answer:
Heat transfer is a discipline of thermal engineering that concerns the generation, use, conversion, and exchange of thermal energy between physical systems. Heat transfer is classified into various mechanisms, such as thermal conduction, thermal convection, thermal radiation, and transfer of energy by phase changes.
Explanation:
hope that helps
74Be decays with a half-life of about 53 d. It is produced in the upper atmosphere, and filters down onto the Earth's surface.
If a plant leaf is detected to have 350 decays/s of 74Be, how long do we have to wait for the decay rate to drop to 25 per second?
Answer:
201.8 days
Explanation:
The activity of a radioactive sample as a function of times is :
[tex]$R=R_0e^{\frac{0.693t}{T_{1/2}}}$[/tex]
Here, [tex]$R_0$[/tex] = the initial activity
[tex]$T_{1/2}$[/tex] = half life
t = elapsed time
Now rearranging the equation for time, t, we get:
[tex]$\frac{R}{R_0}=e^{-\frac{0.693t}{T_{1/2}}}$[/tex]
[tex]$\ln\left(\frac{R}{R_0}\right)=-\frac{0.693t}{T_{1/2}}$[/tex]
[tex]$t=\frac{-\ln\left(\frac{R}{R_0}\right)T_{1/2}}{0.693}$[/tex]
[tex]$t=\frac{-\ln\left(\frac{25}{350}\right)\times 53}{0.693}$[/tex]
= 201.8 days
Therefore, the required time is 201.8 days
Plane-polarized light is incident on a single polarizing disk, with the direction of E0 parallel to the direction of the transmission axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of 6.00?
Answer: [tex]65.9^{\circ}[/tex]
Explanation:
Given
Intensity must be reduced by a factor of 6
Intensity is given by [tex]I=I_o\cos ^2\theta\\[/tex]
Substitute [tex]I[/tex] by [tex]\frac{I_o}{6}[/tex]
[tex]\Rightarrow \dfrac{I_o}{6}=I_o\cos ^2\theta\\\\\Rightarrow \cos^2\theta =\dfrac{1}{6}\\\\\Rightarrow \cos \theta=\dfrac{1}{\sqrt{6}}\\\\\Rightarrow \theta=65.9^{\circ}[/tex]
So, the disk must be rotated by an angle of [tex]65.9^{\circ}[/tex] .
When two charged particles are moving toward each other, their velocities decrease until they eventually come to a
stop. What happens afterward? (1 point)
O They remain in the same place without moving.
O They accelerate toward each other.
O they bond and accelerate together.
O They accelerate in opposite directions.
When two charged particles are moving toward each other, they bond and accelerate together.
To find the correct statement among all the options, we need to know about electromagnetic force.
What is electromagnetic force?The force between any two dynamic charged particles is the electromagnetic force. It's a combination of electric force and magnetic force. What does happen, when two charged particles move towards each other?When two charged particles move towards each other, they combine with each other dur to the electromagnetic force. Then they are travelled together as a single particle along the direction of more acceleration.Thus, we can conclude that the option (C) is correct.
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If a car has a force of 900 N and has a mass of 650 kg. What would be the acceleration of the
car as it moves down the street?
What are used to transfer electrical energy from a power plant all the way to a home? generators turbines power transformers power lines
Answer:
Power lines
Explanation:
Generators induce that current that runs the turbines
Turbines also induce currents from water waves that is transmitted.
Transformers change A.C to D.C or vice versa.
A tension of 35.0N is applied downward on a 2.50kg mass. What is the acceleration of the mass?
A. -59.5 m/s2
B. -14.0 m/s2
C. -4.20 m/s2
D. -23.8 m/s2
Answer:
D. -23.8 m/s2
Explanation:
Answer:
[tex]\text{B. }-14.0\:\mathrm{m/s^2}[/tex]
Explanation:
From Newton's 2nd Law, we have [tex]\Sigma F=ma[/tex].
Substituting given values, we get:
[tex]-35.0=2.50a,\\a=\frac{-35.0}{2.50},\\a=\boxed{-14.0\:\mathrm{m/s^2}}[/tex]
*Note the negative sign simply implies that the mass is travelling downwards (direction).
As a galaxy evolves and becomes more massive, what is most likely to happen?
Answer:
Explanation:
The most likely thing that would happen is that the galaxies continue becoming more and more massive, eventually becoming part of a galaxy cluster. These are massive but cluttered parts of the universe that hold many galaxies extremely close to one another. This also leads to galaxies colliding with one another, although when this happens they usually seem to pass right through each other as if they were ghosts. This is simply due to their sheer size and distance between their bodies of mass.
Answer:
It will merge with other galaxies
Explanation:
Pearson Connexus 2023
Which situation is contrary to Newton’s first law of motion?
An object at rest begins to move when an external force is applied.
A moving object has a constant velocity under the influence of balanced forces.
An object at rest stays at rest as long as unbalanced forces act on it.
A moving object slows down when an external force is applied.
Answer:
An object at rest stays at rest as long as unbalanced forces act on it.
Explanation:
Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.
In physics, Sir Isaac Newton's First Law of Motion is known as Law of Inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.
The inertia of a physical object such as a truck is greatly dependent or influenced by its mass; the higher the quantity of matter in a truck, the greater will be its tendency to continuously remain at rest.
Hence, the situation which is contrary to Newton’s first law of motion is that, an object at rest stays at rest as long as unbalanced forces act on it.
According to Newton’s first law of motion, an object at rest stays at rest as long as unbalanced forces do not act on it.
Answer:
yes it right
Explanation:
cat
The wings of the blue-throated hummingbird, which inhabits Mexico and the southwestern United States, beat at a rate of up to 900 times per minute.
Required:
a. Calculate the period of vibration of the bird’s wings.
b. Calculate the frequency of the wings’ vibratio
c. Calculate the angular frequency of the bird’s wingbeats.
Answer:
a) the period of vibration of the bird’s wings is 0.0667s
b) the frequency of the wings’ vibration is 15 Hz
c) the angular frequency of the bird’s wingbeats is 94.2 rad/s
Explanation:
Given the data in the question;
beat at a rate of up to 900 times per minute.
The number of vibrations per unit time can be be determined as follows;
frequency f = number of vibration / time ---------- let this be equation 1
Also Time period T is;
T = 1/f { time period and frequency are reciprocal to each other }
T = 1/f ---------- Let this be equation 2
Then, the angular frequency ω can be determined using the formular;
ω = 2π × f -------------- Let this be equation 3.
Now, given that; The wings of the blue-throated hummingbird beat at a rate of up to 900 times per minute; Hence,
from equation 1, frequency f = number of vibration / time
f = 900 / 1 min
f = 900 / 60 sec
f = 15 Hz
Therefore, the frequency of the wings’ vibration is 15 Hz
a) the period of vibration of the bird’s wings
from equation 2, T = 1/f ,
we substitute in the value of f
T = 1 / 15 Hz
T = 0.0667s
Therefore, the period of vibration of the bird’s wings is 0.0667s
c) the angular frequency of the bird’s wingbeats;
from equation 3, ω = 2π × f
we substitute
ω = 2π × 15 Hz
ω = 94.2 rad/s
Therefore, the angular frequency of the bird’s wingbeats is 94.2 rad/s
Description of a recent example of human trafficking that has displayed in your community
please select all that would be categorized as vectors
Answer:
1. 10 ft/s² straight up
2. 4 Km north-west
3. 20 m/s South
Explanation:
To successfully categorize the quantities given above as vectors, we must understand what vector quantity is.
A vector quantity is a quantity that has both magnitude and direction.
Considering the question given above, the vector quantities are:
1. 10 ft/s² straight up
2. 4 Km north-west
3. 20 m/s South
The remaining quantities in the question are not considered as vectors because they only have magnitude but no direction. They are therefore referred to as scalar quantities.
A light bulb has 240 Ω of resistance when connected to a 120 V electrical socket. What is the current through the light bulb? (AKS 8b)
Question 36 options:
2.0 A
1.0 A
0.50 A
0.20 A
Answer:
0.50 A
Explanation:
We can find the current from this through Ohm's Law:
V = IR
Now, in it's original form, we're only looking for Voltage. However, we can switch this formula around to find each part of it:
I = V / R (current)
R = V / I (resistance)
In this case, we'll use the formula for current:
V = 120 V
R = 240 Ω
I = ?
I = 120 / 240
I = 0.5 A
Two students are balancing on a 10m seesaw. The seesaw is designed so that each side of the seesaw is 5m long. The student on the left weighs 60kg and is sitting three meters away from the fulcrum at the center. The student on the right weighs 45kg. The seesaw is parallel to the ground. The mass of the board is evenly distributed so that its center of mass is over the fulcrum. What distance from the center should the student on the right be if they want the seesaw to stay parallel to the ground?
a. 4m
b. 5m
c. 2m
d. 3m
NO LINKS.
Answer:
x = 4 m
Explanation:
For this exercise we must use the rotational equilibrium relationship, where we place zero at the turning point and counterclockwise rotations we will consider positive
as it indicates that the bar is in equilibrium, its center of mass coincides with the turning point, so the distance is zero and does not create torque on the system
∑τ = 0
W 3 - w x = 0
x = 3W / w
x = 3 Mg / mg
x = 3 M / m
let's calculate
x = 3 60/45
x = 4 m
An idea to explore the nearest Earth-sized planet in a habitable zone to our Sun is to attach a small sensor array to a 4 m by 4 m solar sail and shine a 100 GW laser on the solar sail for 10 minutes. This will get the spaceship up to speed after which it will coast the rest of the way at the speed attained after the 10 minutes of acceleration. Assume the sensor array and solar sail has a mass of 3 grams. The nearest Earth-sized planet in a habitable zone orbits the Alpha Centauri system at 4.3 Lightyears. 1 GW = 1*109 W. 1 Light year = 4*1016 m. Assume a perfectly reflecting solar sail and assume all 100 GW of power are intercepted by the solar sail.
a. What is the pressure on the Solar Sail from the laser?
b. What is the force on the Solar Sail from the laser?
c. What speed will the spaceship attain after 10 minutes assuming it started from rest and assuming a constant acceleration?
d. How long will it take the spaceship to reach Alpha Centauri in years?
Solution :
Given data:
Area of the solar sail, A = 16 [tex]$m^2$[/tex]
Mass (array + sail), m = [tex]$3 \times 10^{-3}$[/tex] kg
Power, P = 100 GW
= [tex]$10^{11}$[/tex] W
Time, t = 10 min
= 10 x 60 s
Distance, D = [tex]$4.3 \times 4 \times 10^{16}$[/tex] m
Kinetic energy, [tex]$KE=\frac{1}{2}mv^2=P\times t$[/tex]
[tex]$v=\sqrt{\frac{2Pt}{m}}$[/tex]
[tex]$v=\sqrt{\frac{2\times 10^{11}\times 600}{3 \times 10^{-3}}}$[/tex]
[tex]$=2 \times 10^8$[/tex] m/s
So, the acceleration is [tex]$a=\frac{v}{t}$[/tex]
[tex]$a=\frac{2 \times 10^8}{6 \times 10^2} \ m/s^2$[/tex]
[tex]$=333333.33 \ m/s^2$[/tex]
Therefore, force,
[tex]$F = ma$[/tex]
[tex]$=3 \times 10^{-3}\times 333333.33$[/tex]
= 1000 N
Pressure, [tex]$P=\frac{F}{A}$[/tex]
[tex]$=\frac{1000}{16}$[/tex]
[tex]$=62.5 \ N/m^2$[/tex]
Therefore, time taken is t
Now the distance is
[tex]$d_1=\frac{1}{2}at_1^2$[/tex]
[tex]$d_1=0.5 \times 333333.33 \times (600)^2$[/tex]
[tex]$=6 \times 10^{10} \ m$[/tex]
Now, the distance, [tex]$d_2 = D-d_1=v.t_2$[/tex]
Now, [tex]$t_2=\frac{(17.2 \times 10^{16})-(6 \times 10^{10})}{2 \times 10^8}$[/tex]
= 859999700 s
Therefore, total time is
[tex]$T=t_1+t_2$[/tex]
= 86000300 s
= 27.27 years
A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surface of the water. It takes a time of 2.10 s for the boat to travel from its highest point to its lowest, a total distance of 0.600 m . The fisherman sees that the wave crests are spaced a horizontal distance of 6.50 m apart.
Required:
a. How fast are the waves traveling?
b. What is the amplitude of each wave?
c. If the total vertical distance traveled by the boat were 0.30 m but the other data remained the same, how would the answers to parts (a) and (b) be affected?
Answer:
See Explanation
Explanation:
a) We know that;
v = λf
Where;
λ = wavelength of the wave
f = frequency of the wave
v = velocity of the wave
So;
T = 2 * 2.10 s = 4.2 s
Hence f = 1/4.2 s
f = 0.24 Hz
The wavelength = 6.5 m
Hence;
v = 6.5 m * 0.24 Hz
v = 1.56 m/s
b)The amplitude of the wave is;
A = 0.600 m/2 = 0.300 m
c) Since the wave speed does not depend on the amplitude of the wave then the answer in (a) above remains the same
Where d = 0.30 m
A = 0.30 m/2 = 0.15 m
what is the comparison of Wind turbine and other energy sources?
AnWind power or wind energy is the use of wind to provide mechanical power through wind turbines to turn electric generators for electrical power. Wind power is a popular sustainable, renewable source of power that has a much smaller impact on the environment compared to burning fossil fuels. Wind farms consist of many individual wind turbines, which are connected to the electric power transmission network. Onshore wind is an inexpensive source of electric power, competitive with or in many places cheaper than coal or gas plants. Onshore wind farms have a greater visual impact on the landscape than other power stations, as they need to be spread over more land and need to be built away from dense population. Offshore wind is steadier and stronger than on land and offshore farms have less visual impact, but construction and maintenance costs are significantly higher. Small onshore wind farms can feed some energy into the grid or provide power to isolated off-grid locations. The wind is an intermittent energy source, which cannot be dispatched on demand. Locally, it gives variable power, which is consistent from year to year but varies greatly over shorter time scales. Therefore, it must be used together with other power sources to give a reliable supply. Power-management techniques such as having dispatchable power sources (often gas-fired power plant or hydroelectric power), excess capacity, geographically distributed turbines, exporting and importing power to neighboring areas, grid storage, reducing demand when wind production is low, and curtailing occasional excess wind power, are used to overcome these problems. As the proportion of wind power in a region increases the grid may need to be upgraded. Weather forecasting permits the electric-power network to be readied for the predictable variations in production that occur. In 2019, wind supplied 1430 TWh of electricity, which was 5.3% of worldwide electrical generation, with the global installed wind power capacity reaching more than 651 G…swer:
Explanation:
Magnets on the tracks
How can levitating trains support the claim that magnetic fields exist between objects exerting magnetic force on each other even when there is no physical contact?
Answer:
Explanation: They levitate sort of because when to opposite forces of magnets cant go together they repel