Answer:
0.45 ft/min
Step-by-step explanation:
Given:-
- The flow rate of the gravel, [tex]\frac{dV}{dt} = 35 \frac{ft^3}{min}[/tex]
- The base diameter ( d ) of cone = x
- The height ( h ) of cone = x
Find:-
How fast is the height of the pile increasing when the pile is 10 ft high?
Solution:-
- The constant flow rate of gravel dumped onto the conveyor belt is given to be 35 ft^3 / min.
- The gravel pile up into a heap of a conical shape such that base diameter ( d ) and the height ( h ) always remain the same. That is these parameter increase at the same rate.
- We develop a function of volume ( V ) of the heap piled up on conveyor belt in a conical shape as follows:
[tex]V = \frac{\pi }{12}*d^2*h\\\\V = \frac{\pi }{12}*x^3[/tex]
- Now we know that the volume ( V ) is a function of its base diameter and height ( x ). Where x is an implicit function of time ( t ). We will develop a rate of change expression of the volume of gravel piled as follows Use the chain rule of ordinary derivatives:
[tex]\frac{dV}{dt} = \frac{dV}{dx} * \frac{dx}{dt}\\\\\frac{dV}{dt} = \frac{\pi }{4} x^2 * \frac{dx}{dt}\\\\\frac{dx}{dt} = \frac{\frac{dV}{dt}}{\frac{\pi }{4} x^2}[/tex]
- Determine the rate of change of height ( h ) using the relation developed above when height is 10 ft:
[tex]h = x\\\\\frac{dh}{dt} = \frac{dx}{dt} = \frac{35 \frac{ft^3}{min} }{\frac{\pi }{4}*10^2 ft^2 } \\\\\frac{dh}{dt} = \frac{dx}{dt} = 0.45 \frac{ft}{min}[/tex]
Please tell me the answer to c ignore the question b thank you
Answer:
c).[tex] {1000}^{m} \div {100}^{n} \\ \\ {10}^{3m} \div {10}^{2n} [/tex]
Since they have the same base and are dividing we subtract the exponents
That's
[tex] {10}^{3m - 2n} [/tex]
So
z = 3m - 2nHope this helps you
Answer:
[tex]\boxed{ z = 3m-2n}[/tex]
Step-by-step explanation:
=> [tex]1000^m / 100^n[/tex]
=> [tex](10)^{3m} / (10)^{2n}[/tex]
Using rule of exponents [tex]a^m/a^n = a^{m-n}[/tex]
=> [tex]10 ^{3m-2n}[/tex]
Comparing it with [tex]10^z[/tex], we get
=> z = 3m-2n
I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!
Step-by-step explanation:
Log T = 11.8 + 1.5.M (with T is the amount of energy released by the earthquake, Log refers to the logarithm to the base 10)
-->T = [tex]10^{11.8 +1.5*6.5}[/tex] ≈3.458 *[tex]10^{21}[/tex]
Answer: 2.00 x 10¹⁰⁹
Step-by-step explanation:
log T = 11.8 + 1.5M
Given: M = 6.5
log T = 11.8 + 1.5(6.5)
log T = 11.8 + 9.75
log T = 21.55
T = 10²¹⁻⁵⁵
T = 1.995 x 10¹⁰⁹
T = 2.00 x 10¹⁰⁹ rounded to the nearest hundredth
1) A grocer sold 5 kg of wheat flour at Rs 30 per kg and gained 20%. If he had sold
it at Rs 27 per kg, what would be his gain or loss percent?
Answer:
given,
selling price (sp)=rs 5 ×30
=rs 150
now, gain %=20%
cost price (cp)=
[tex] \frac{sp \times 100}{100 + gain\%} [/tex]
[tex] = \frac{150 \times 100}{100 + 20} [/tex]
therefore cp= rs125
now,
again in 2nd case
sp= rs 27×5
therefore sp=rs 135
and cp= rs125
now, sp>cp so,
[tex]gain\% = \frac{sp - cp}{cp} \times 100\%[/tex]
or, gain=
[tex] = \frac{135 - 125}{125} \times 100\%[/tex]
therefore gain %= 8%.... is answer
hope it helps..
Scotland Beauty Products manufactures face cream, body lotion, and liquid soap in a joint manufacturing process. At the split-off point, the company has 300 pounds of face cream, 200 pounds of body lotion, and 300 pounds of liquid soap and has incurred $200,000 in joint costs. Using the physical units method, allocate the joint costs to: a. Face Cream $ b. Body Lotion $ c. Liquid Soap $
Answer:
a. 75,000
b. 50,000
c. 75,000
Step-by-step explanation:
The computation of allocating the joint cost using the physical units method is shown below:
[tex]Allocation\ rate = \frac{Joint\ costs}{Total\ number\ of\ products}[/tex]
[tex]= \frac{\$200,000}{300 + 200 + 300}[/tex]
[tex]Allocation\ rate = \frac{200,000}{800}[/tex]
= 250
For face cream
[tex]= Unit\ produced\times Allocation\ rate[/tex]
= [tex]300\times 250[/tex]
= 75,000
For body lotion
[tex]= Unit\ produced\times Allocation\ rate\\\\ = 200\times 250[/tex]
= 50,000
For Liquid soap
[tex]= Unit\ produced\times Allocation\ rate\\\\ = 300\times 250[/tex]
= 75,000
hence, we simply applied the above formula by multiplying the units produced with the allocation rate so that each one allocation cost could come
Simon swapped of 2/5
his 40 marbles for 9 of
Saqib's. How many has
Simon got now?
Answer:
33
Step-by-step explanation:
2/5x40=16
40-16=24
24+9=33
33 marbles
2/5 is .4
Multiply .4 by 40 to get 16
Subtract 16 from 40 to get 24
Add 9 to 24 to get 33
Hope it helps <3
(If it does, please mark brainliest, only need 1 more to get rank up :) )
The most appropriate measure of center for this
data is the median
Weight of Male Dogs (lb)
4
5
COMPLER
5
2
2
Which statement about the data is true?
The mean is greater than the median
X The mean is equal to the median
* The mean is less than the median
What is the median of the data
Answer:
65
Step-by-step explanation:
45, 50, 52, 58, 62, 68, 72, 78, 81, 95
62 + 68 = 130/2 = 65
The median is 65
Answer:
The median of the data is 65
Step-by-step explanation:
I did it on edge and got it right
Please help ill mark you the brainlist The scale on a map indicates that 1 cm represents 50 km. If two cities are 400 km apart, then how far apart would the cities be on this map?
Answer:
8 cm
Step-by-step explanation:
divide 400 by 50 which is 8.
Store pays $56 for a GPS navigation system the markup is 25% what price will the store sell it for
[tex]\text{We need to find how much the store will sell a GPS navigation system}\\\\\text{We know that the store paid \$56 for it}\\\\\text{We also know that they will mark up the price by 25\%}\\\\\text{We can find 25\% of 56}\\\\56\cdot0.25=14\\\\\text{We can now add that to the original price to get the price the store}\\\text{will sell it for}\\\\56+14=70\\\\\boxed{\$70}[/tex]
what fraction is greater than 2/5 but less than 3/5
Hey there! I'm happy to help!
You haven't provided any answer choices but I can show you a trick to find any number between two numbers. This is will give you an instant answer to one being greater than one number and less than another.
What you do is you add the two numbers and divide by two!
2/5+3/5=1
1÷2=1/2
Therefore, 1/2 is a possible answer here.
I hope that this helps! Have a wonderful day!
Mauro has 140 feet of rope he will cut it into two peices so that the length of the longer peice is 3 times the length of the shorter peice
Approximating square roots
Go to le
Without using a calculator, choose the statement that best describes the value of 215.
Choose 1 answer:
The value of 215 is between 13 and 13.5.
The value of 215 is between 13.5 and 14.
The value of 215 is between 14 and 1.5.
The value of v 215 is between 14.5 and 15.
Step-by-step explanation:
We know that
14^2=196, and
15^2=225
so we know that sqrt(215) is between 14 and 15.
How do we know if it is between 14.5 and 15?
we need to know the value of 14.5^2, which we can calculate in the head as follows:
The square of all numbers ending in 5 such as 15 can be calculated by breaking up the 5 and the preceding digit(s),
The preceding digit is 1. We multiply 1 by the next integer, 2 to get 2.
Attach 25 to 2 gives us 225 (as we saw above.
Example, 145*145 = 14*15 | 25 = 210 | 25 = 21025
so
14.5^2 = 210.25, which gives the more precise answer that
14.5^2 < 215 < 15^2, or
14.5 < sqrt(215) < 15 (fourth choice)
Since the third choice says sqrt(215) is between 14 and 1.5 (not 15), so the third choice is incorrect.
Note: if we eliminated the third choice, i.e. discard the likelihood of typo in the question, the only one left is the fourth choice.
The lengths of adult males' hands are normally distributed with mean 190 mm and standard deviation is 7.4 mm. Suppose that 45 individuals are randomly chosen. Round all answers to 4 where possible.
What is the distribution of ¯xx¯? ¯xx¯ ~ N(,)
For the group of 45, find the probability that the average hand length is less than 189.
Find the third quartile for the average adult male hand length for this sample size.
For part b), is the assumption that the distribution is normal necessary?
Answer:
a. The distribution of the sample means is normal with mean 190 mm and standard deviation 1.1031 mm.
b. The probability that the average hand length is less than 189 is P(M<189)=0.1823.
c. The third quartile for the average adult male hand length for this sample size is M_75=190.7440.
d. The assumption of normality is not necessary as the sampling distribution will tend to have a bell shaped independently of the population distribution.
Step-by-step explanation:
We have a normal distribution, with mean 190 and standard deviation 7.4.
We take samples of size n=45 from this population.
Then, the sample means will have a distribution with the following parameters:
[tex]\mu_s=\mu=190\\\\ \sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{7.4}{\sqrt{45}}=\dfrac{7.4}{6.7082}=1.1031[/tex]
The probability that the sample mean is less than 189 can be calculated as:
[tex]z=\dfrac{M-\mu}{\sigma/\sqrt{n}}=\dfrac{189-190}{7.4/\sqrt{45}}=\dfrac{-1}{1.1031}=-0.9065\\\\\\P(M<189)=P(z<-0.9065)=0.1823[/tex]
The third quartile represents the value of the sample where 75% of the data is to the left of this value. It means that:
[tex]P(M<M^*)=0.75[/tex]
The third quartile corresponds to a z-value of z*=0.6745.
[tex]P(z<z^*)=0.75[/tex]
Then, we can calculate the sample mean for the third quartile as:
[tex]M=\mu_s+z^*\sigma_s=190+0.6745\cdot 1.1031=190+0.7440=190.7440[/tex]
The assumption of normality is not necessary as the sampling distribution will tend to have a bell shaped independently of the population distribution.
Please please please please help me. i will do anything, anything!! please
Answer:
[tex]d \approx 2.2[/tex]
Step-by-step explanation:
It is the same process as in previous problems.
Once the origin is the point (0, 0):
[tex]d=\sqrt{(x_{1}-x_{2})^2 + (y_{1}-y_{2})^2}[/tex]
[tex]d=\sqrt{(2-0)^2 + (-1-0)^2}[/tex]
[tex]d=\sqrt{2^2 + (-1)^2}[/tex]
[tex]d=\sqrt{5}[/tex]
[tex]d \approx 2.2[/tex]
Answer:
2.2
Step-by-step explanation:
The distance formula
[tex]\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex] with
[tex]x_1=0\\y_1=0\\x_2=2\\y_2=-1[/tex]
[tex]\sqrt{(0-2)^2+(0-(-1))^2}=\sqrt{2^2+1^2}=\sqrt{5}[/tex]
[tex]\sqrt{5} =2.2360...=2.2[/tex]
A traffic helicopter pilot 300 feet above the road spotted two antique cars. The angles of depression are 7.5° and 9º. How far apart are the cars? Round to the nearest tenth.
Answer:
384.6 ft
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the trig relation involving sides adjacent and opposite the angle. Here, the road distance is adjacent to the angle of depression, and the altitude is opposite. So, you have ...
Tan = Opposite/Adjacent
tan(7.5°) = (300 ft)/(distance to car 1)
tan(9°) = (300 ft)/(distance to car 2)
Solving for the distances, we have ...
distance to car 1 = (300 ft)/tan(7.5°) ≈ 2278.73 ft
distance to car 2 = (300 ft)/tan(9°) ≈ 1894.13 ft
Then the separation between the cars is ...
distance apart = 2278.73 ft - 1894.13 ft
distance apart = 384.6 ft
How many multiples of 4, that are smaller than 1,000, do not contain any of the digits 6, 7, 8, 9 or 0?
Answer:
44
Step-by-step explanation:
11×4
hope it helped!
A survey was taken of students in math classes to find
out how many hours per day students spend on social
media. The survey results for the first-, second-, and
third-period classes are as follows:
First period: 2, 4, 3, 1, 0, 2, 1, 3, 1, 4, 9, 2, 4, 3,0
Second period: 3, 2, 3, 1, 3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2
Third period: 4, 5, 3, 4, 2, 3, 4, 1, 8, 2, 3, 1, 0, 2, 1, 3
Which is the best measure of center for second period
and why?
Can somebody please help me with this question?
Answer:
Blue Triangle.
Step-by-step explanation:
Using the area formula for a triangle, the pink triangle has an area of 0.5×54×33 in² or 891 in². The blue triangle has an area of 0.5×56×39 in² or 1092 in².
Answer:
Step-by-step explanation:
both shapes are triangles so there area is :
A=( b*h) / 2 where h is the height and b the base
triangle 1 : (pink)A= (33*54)/2 = 742.5 in²
triangle 2 : (blue)A= (56*39)/2= 1092 in²
so the blue triangle has a greather area
An airline allows passenger 33 kg of luggage cost to lower the weight of a suitcase by 25% to stay within the limit how much does suitcase originally way
Answer:
The suitcase originally weighed 44kg.
Step-by-step explanation:
1- 0.25= 0.75 (multiplier)
33÷0.75=44
The suitcase originally weighed 44kg
A simple random sample of size nequals15 is drawn from a population that is normally distributed. The sample mean is found to be x overbarequals18.3 and the sample standard deviation is found to be sequals6.3. Determine if the population mean is different from 24 at the alpha equals 0.01 level of significance. Complete parts (a) through (d) below.
(a) Determine the null and alternative hypotheses. Upper H 0: ▼ p sigma mu ▼ less than not equals equals greater than 24 Upper H 1: ▼ sigma mu p ▼ greater than not equals equals less than 24
(b) Calculate the P-value.P-valueequals nothing (Round to three decimal places as needed.)
(c) State the conclusion for the test.
A. Do not reject Upper H 0 because the P-value is less than the alphaequals0.01 level of significance.
B. Do not reject Upper H 0 because the P-value is greater than the alphaequals0.01 level of significance.
C. Reject Upper H 0 because the P-value is less than the alphaequals0.01 level of significance.
D. Reject Upper H 0 because the P-value is greater than the alphaequals0.01 level of significance.
(d) State the conclusion in context of the problem. There ▼ is not is sufficient evidence at the alpha equals 0.01 level of significance to conclude that the population mean is different from 24.
Answer:
(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 24
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 24
(b) The P-value is 0.004.
(c) Reject Upper H 0 because the P-value is less than the alpha = 0.01 level of significance.
(d) There is sufficient evidence at the alpha equals 0.01 level of significance to conclude that the population mean is different from 24.
Step-by-step explanation:
We are given that a simple random sample of size n = 15 is drawn from a population that is normally distributed. The sample mean is found to be x overbar = 18.3 and the sample standard deviation is found to be s = 6.3.
Let [tex]\mu[/tex] = population mean
(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 24 {means that the population mean is 24}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 24 {means that the population mean is different from 24}
The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;
T.S. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean = 18.3
s = sample standard deviation = 6.3
n = sample size = 15
So, the test statistics = [tex]\frac{18.3-24}{\frac{6.3}{\sqrt{15} } }[/tex] ~ [tex]t_1_4[/tex]
= -3.504
The value of t-test statistics is -3.504.
(b) Now, the P-value of the test statistics is given by;
P-value = P( [tex]t_1_4[/tex] < -3.504) = 0.002 or 0.2%
For the two-tailed test, the P-value is calculated as = [tex]2 \times 0.002[/tex] = 0.004 or 0.4%.
(c) Since the p-value of the test statistics is less than the level of significance as 0.002 < 0.01, so we will reject our null hypothesis.
(d) This means that we have sufficient evidence at the alpha equals 0.01 level of significance to conclude that the population mean is different from 24.
Select the correct car trips. Listed are the distances traveled by four cars and the time it took each car to cover that distance. Identify which cars traveled at the same speed.
Answer:
Speeds of car 1 and car 4 are same.
Step-by-step explanation:
Speed of an object = [tex]\frac{\text{Distance traveled}}{\text{Time}}[/tex]
For car 1,
Speed of car 1 = [tex]\frac{350}{5}[/tex]
= 70 miles per hour
For car 2,
Speed of car 2 = [tex]\frac{240}{4}[/tex]
= 60 miles per hour
For car 3,
Speed of car 3 = [tex]\frac{320}{5}[/tex]
= 64 miles per hour
For car 4,
Speed of car 4 = [tex]\frac{420}{6}[/tex]
= 70 miles per hour
Therefore, speeds of car 1 and car 4 are same.
<1 and <3 are complementary and <1= <2 Which one of these statements will always be true?
A. M<2 = m<3
B. <2 and <3 are complementary
C. M<1= m<3
D. <2 and <3 are supplementary
Answer:
B. ∠2 and ∠3 are complementary
Step-by-step explanation:
The substitution property of equality lets you put ∠2 in place of ∠1 in the statement ...
∠1 and ∠3 are complementary.
∠2 and ∠3 are complementary . . . . using ∠2 for equal ∠1 in the above
Answer: ∠2 and ∠3 are complementary
Step-by-step explanation:
The product of two numbers was 9. If one number is three and three fourth, what was
the other number?
Answer:
2.4
Step-by-step explanation:
3 3/4 = 3.75
9/3.75 = 2.4
A circle is represented by the equation x2+y2=445. a) State the radius. b) Find y if point A(-9,y) is on this circle.
Answer:
R= sqrt 445
Y = 19
Step-by-step explanation:
Radius is the square root of 445
Find y
So, First step is to substitute what you have
-9^2 + y^2 = 445
81 + y^2 = 445
-81 -81
y^2 =364
Y is about 19
Let me know if I'm incorrect
Hope this helps :)
Given a triangle with: a =
150, A = 75°, and C = 30°
Using the law of sines gives: c = 0
Answer:
[tex] c = 77.6 [/tex]
Step-by-step explanation:
You may have entered the measure of a side as the measure of an angle.
[tex] \dfrac{\sin A}{a} = \dfrac{\sin C}{c} [/tex]
[tex] \dfrac{\sin 75^\circ}{150} = \dfrac{\sin 30^\circ}{c} [/tex]
[tex] c\sin 75^\circ = 150 \sin 30^\circ [/tex]
[tex] c = \dfrac{150 \sin 30^\circ}{\sin 75^\circ} [/tex]
[tex] c = 77.6 [/tex]
You are correct. Good job!
A right triangle is shown. The length of the hypotenuse is 4 centimeters and the lengths of the other 2 sides are congruent. The hypotenuse of a 45°-45°-90° triangle measures 4 cm. What is the length of one leg of the triangle? 2 cm 2 StartRoot 2 EndRoot cm 4 cm 4 StartRoot 2 EndRoot cm
Answer:
The leg measures 2 I believe
Step-by-step explanation:
Since the squares of the legs equal C ([tex]A^{2} +B^{2} = C^{2}[/tex]) the square root of 16 would be 4.
The Pythagorean theorem is a basic relationship between the three sides of a right triangle. The length of one leg of the triangle is 2√2 cm.
What is the Pythagoras theorem?The Pythagorean theorem, sometimes known as Pythagoras' theorem, is a basic relationship between the three sides of a right triangle in Euclidean geometry. The size of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides, according to this rule.
[tex]\rm (Hypotenuse)^2 =(Perpendicular)^2 + (Base)^2[/tex]
Let the length of the perpendicular be x.
Given the length of the hypotenuse is 4 centimeters, while the length of the other two sides is the same, therefore, the length of the other two sides is x. Therefore, using the Pythagorus theorem we can write,
[tex]\rm (Hypotenuse)^2 =(Perpendicular)^2 + (Base)^2[/tex]
[tex]4^2 = x^2+x^2\\\\16=2x^2\\\\8=x^2\\\\x= 2\sqrt2[/tex]
Hence, the length of one leg of the triangle is 2√2 cm.
Learn more about Pythagoras Theorem:
https://brainly.com/question/14461977
#SPJ2
At the Arctic weather station, a warning light turns on if the outside temperature is below -25 degrees Fahrenheit. Which inequality models this situation?
Answer:
T < -25
Step-by-step explanation:
Was correct on TTM
i will give 50 points and brainliest
Answer:
240 m^2
Step-by-step explanation:
The area of a triangle is given by
A = 1/2 bh
The base is 16 and the height is 30
A =1/2 ( 16*30)
240 m^2
Square ABCD is shown below with line EF and passing through the center:
Answer: B) contain the points E and F
Step-by-step explanation:
Dilation of 2 means to multiply both the x- and y-coordinates by 2
see image below
The only option that is true that E'F' contains points E and F
Answer:
contains the points E and F
Step-by-step explanation:
The center of dilation is an invariant point. It doesn't move, regardless of the dilation factor.
Likewise, any line through the center of dilation will not move. It is not rotated or translated by dilation--it simply is stretched (or compressed) along its length. It is still an infinite line, and it still goes through all of the points it went through before dilation.
The line through the center of dilation that contains points E and F, after dilation, ...
contains the points E and F.
expand the linear expression 4(10x -4)
Answer:
40x - 16
Step-by-step explanation:
(see attached for reference)
By utilizing the distributive property:
4(10x -4)
= (10x)(4) -4 (4)
= 40x - 16
Answer:
4x10x= 40x -4x4=-16 40xtimes-4<-----------thats your answer
Step-by-step explanation:
The set G 5 {1, 4, 11, 14, 16, 19, 26, 29, 31, 34, 41, 44} is a group under multiplication modulo 45. Write G as an external and an internal direct product of cyclic groups of prime-power order.
Answer: G = (19) × (26) × (16)
Step-by-step explanation:
The isomorphism classes of Abelian groups of order 12 are Z₄ ⊕ Z₃ and Z₂ ⊕ Z₂ ⊕ Z₃
SO Let us calculate the orders of some of the elements of G
We have
4² = 16,
4³ = 64
= 19,
and
4^4 = 19.4
= 76
= 31.
furthermore,
4^5 = 31.4
= 124
= 34
and
4^6 = 34.4
= 136
= 1
Hence, 4 and 34 each have order 6, 16 and 31 each have order 3, and 19 has order 2.
Next, we calculate
11² = 121
= 31
and
11³ = 11.3
= 341
= 26
this is the calculation needed.
26² = 11^6
= 31³
= 1
since we already showed that 31 has order 3. This means that 26 has order 2
Since G has two distinct elements of order 2, it cannot be isomorphic to . We conclude
that G = Z₂ ⊕ Z₂ ⊕ Z₃
Finally, we will express as an internal direct product.
The previous calculations show that
(19) = { 1, 19 }
and (26) = { 1, 26 }
are cyclic subgroups of G of order 2 with trivial intersection. We have
(19) × (26) = { 1, 19, 26, 44 }
since
(16) = { 1, 19, 26, 44 }
has trivial intersection with (19) × (26), conclude that
G = (19) × (26) × (19)