Graph this line using the slope and y-intercept:
y = 4x - 10

Answer:

26 inches

Step-by-step explanation:

The snail starts 20 inches above the ground: +20

The snail slips (goes down) 6 inches: 20 - 6 = 14

The snail goes up 12 inches: 14 + 12 = 28

The snail is 28 inches above the ground.

Hope this helps!

Answer:

xs7

Step-by-step explanation:

The actual distance between the two cities is 432 miles.

The figure shows a map of two cities, with a distance between them measured at 4.5 inches.

The scale of the map is given as 1/8 inch to 12 miles.

This means that 1/8 inch on the map represents a distance of 12 miles in real life.

To determine the actual distance between the two cities, we can use the scale provided.

1/8 inch on the map represents 12 miles in real life.

A proportion to find the actual distance between the cities:

1/8 inch on map = 12 miles in real life

4.5 inches on map = x miles in real life

To solve for x, we can cross-multiply and simplify:

1/8 × x = 12 × 4.5

x = 12 × 4.5 × 8

x = 432 miles

Maps with scales can be useful for determining distances, sizes, and proportions of objects in real life.

It allows us to visually represent complex spatial relationships and make measurements without physically being present at the location.

Remember to use the correct scale and make sure to convert units properly in order to accurately determine real-life measurements.

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Answer:

108 sq ft

Step-by-step explanation:

The formulas are given in the bottom right.

For the triangles*, the base = 8 ft. The height = 6 feet.

Area = (bh)/2.

Area = (8*6)/2 = (48)/2 = 24 sq ft.

There are two of those identical triangles. 24+24 = 48.

(*Another way to look at this is to say that the base = 8+8 = 16. Area = (bh)/2 = (16*6)/2 = 96/2 = 48. It doesn't matter, mathematically. I can't tell if they have tried to show this as 2 triangles or one.)

For the bottom rectangle, area = length x width = 6*10 = 60 sq ft.

Add them up! 24 + 24 + 60 = 108 sq ft.

In order to understand and prioritize the vaccination strategy for the community health clinic, first accurately assess the demographics of the community based on the data provided.

Calculating the absolute numbers of people in each group: over 65 and immunocompromised, and under 65 and immunocompromised. For this, we'll apply the given percentage to the total population of 50,000.

Knowing the total number of people in each category will help us understand the size of each target group and prioritize accordingly. The clinic's current priority is immunocompromised people over 65, so having the exact figure will aid in planning for vaccine supply and outreach strategies.

Furthermore, the analysis of this data can also aid in projecting the needs for future vaccine campaigns for the remaining community members. Finally, this detailed analysis will help in crafting an effective communication plan that emphasizes the clinic's priority of serving the most vulnerable first, while still acknowledging the needs of all community members.

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Answer:

x = -5

Step-by-step explanation:

-5 - 15x - 10 = -4x - 8x

-5 - 10 = -4x - 8x + 15x

-15 = -12x + 15x

-15 = 3x

x = -5

Based on the contribution margin and the sales volume, Menu Item D is the most profitable and popular.

The contribution margin is the profitability that is shown in the difference between the selling price and the variable cost per unit of an item.

The contribution margin can be computed per unit or in total.  Using the sales volume to multiply the contribution margin per item gives the total contribution margin in dollars.

 Breakfast     Selling Price    Food Cost       Sales     Contribution Margin

Menu Item               ($)                  ($)           Volume         Unit         Total

А                         $10.00             $3.00           250          $7.00      $1,750

B                         $16.00             $6.00             50        $10.00        $500

C                         $18.45             $8.00             60        $10.45        $627

D                         $14.75             $4.25           300        $10.50      $3,150

E                          $8.75             $2.50             80          $6.25        $500

F                        $12.50              $5.75            180         $6.75       $1,215

G                        $9.00              $2.60           280         $6.40      $1,792

TOTAL                                                          1,200

Thus, we can conclude that Menu Item D enjoys the highest profitability and popularity.

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The trigonometric equation is tan 2A cot A-1 = sec 2A

We have to prove the trigonometric equation

tan 2A cot A-1 = sec 2A

Now let us take LHS

tan 2A cot A-1  

2tanA/1-tan²A - 1 . cotA - 1

2-1+tan²A/1-tan²A

1+tan²A/1-tan²A

sec2A

Hence, the trigonometric equation is tan 2A cot A-1 = sec 2A

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On performing , the "row-operation" 2R₁ + R₂ → R₂ on the matrix "M", the resulting new-matrix is [tex]\left[\begin{array}{ccc}5&1&-5\\10&0&-8\end{array}\right][/tex] .

The matrix "M" is given as : [tex]\left[\begin{array}{ccc}5&1&-5\\0&-2&2\end{array}\right][/tex],

We have to apply the Row-Operation : 2R₁ + R₂ → R₂, on the matrix "M",

Performing the row-operation "2R₁ + R₂ → R₂" on a matrix "M" means multiplying the first-row of "M" by 2, and then adding the resulting values to the second-row of "M" to produce a new value for each element in the second row.

This operation does not affect the first row of "M" and changes the values in the second row of "M".

⇒ [tex]\left[\begin{array}{ccc}5&1&-5\\2\times5+0&2\times 1-2&2\times(-5)+2\end{array}\right][/tex],

⇒ [tex]\left[\begin{array}{ccc}5&1&-5\\10+0&2-2&-10+2\end{array}\right][/tex],

⇒ [tex]\left[\begin{array}{ccc}5&1&-5\\10&0&-8\end{array}\right][/tex].

Therefore, the new-matrix is [tex]\left[\begin{array}{ccc}5&1&-5\\10&0&-8\end{array}\right][/tex].

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Maria have to spend $ 45.95 less than what she spends now in order to save $ 70 per month.

Hence the correct option is (A).

From the given Maria's Income Statement we can see that,

Her total income from Fast food Restaurant = Gross Pay + Allowance = $ 580 + $ 50 = $ 630.

Total deductions by taxation = Federal Income Tax + State Income Tax + Social Security Tax = $ 58 + $ 16 + $ 24.36 = $ 98.36

So here net income = $ (630 - 98.36) = $ 531.64.

Here total expenses = Auto + Clothing + Food + Entertainment + Other = $ 290.02 + $ 92.29 + $90.28 + $ 32 + $ 3 = $ 507.59

So Her Savings = Net Income - Total Expenses = $ 531.64 - $ 507.59 = $ 24.05.

Now in order to save $ 70 per month Maria has to spend = $ 70 - $ 24.05 = $45.95 less than she spend now.

Hence the correct option will be (A).

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The perimeter of the rectangular polygon is given by P = 20.2 units

Given data ,

Let the perimeter of the polygon be represented as P

Now , the value of P is

Perimeter P of rectangle = 2 ( Length + Width )

Now , width is 3.8 and the length is 6.3

On simplifying , we get

P = 2 ( 3.8 + 6.3 )

P = 20.2 units

Hence , the perimeter is P = 20.2 units

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5 holes have been punched into a 12 cm by 12 cm square piece of paper. The area of remaining paper will be 27.714 cm².

Firstly, we will calculate the area of the square of paper in which the holes are punched.

Side of square = 12 cm

Area of square = side²

= (12) ²

= 144 cm²

Now, we will calculate the area of the bigger punch holes

Radius of big punch hole = 3 cm

Area of 1 big punch = π (radius) ²

= 22/7 × (3)²

22 / 7 × 9

= 198 / 7 cm²

Area of 4 punches = 4 × 198/7

= 792/7 cm²

Now, we will calculate the area of smaller punch whose radius is 1cm

Area = 22/7 × 1²

= 22/7 cm²

Now, we will calculate the total area covered by circles

Total area covered by circles = area of small punch + area of 4 big punch

= 22/7 + 792/7

= 814 /7 cm²

Remaining area = area of square - area of circles

= 144 - 814/7

= (1008 - 814) / 7

= 194 / 7

= 27.714 cm²

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Mean (Juniors) = Sum / number of data points = 1085 / 12 ≈ 90.42

Median (Juniors) = (95 + 95) / 2 = 95

Mean (Seniors) = Sum / number of data points = 1095 / 12 ≈ 91.25

Median (Seniors) = (80 + 80) / 2 = 80

Juniors: 125, 90, 95, 80, 100, 100, 120, 85, 95, 120, 95, 85

First, sort the data: 80, 85, 85, 90, 95, 95, 95, 100, 100, 120, 120, 125

Sum = 1085

Mean (Juniors) = Sum / number of data points = 1085 / 12 ≈ 90.42

Median (Juniors) = (95 + 95) / 2 = 95

Seniors: 135, 70, 65, 100, 35, 175, 80, 80, 90, 65, 120, 60

First, sort the data: 35, 65, 65, 70, 80, 80, 90, 100, 120, 120, 135, 175

Sum = 1095

Mean (Seniors) = Sum / number of data points = 1095 / 12 ≈ 91.25

Median (Seniors) = (80 + 80) / 2 = 80

Variability

Juniors:

Range = max - min = 125 - 80 = 45

Seniors:

Range = max - min = 175 - 35 = 140

C. Based on the mean and median, it appears that seniors spend slightly more time on homework on average (mean ≈ 91.25) compared to juniors (mean ≈ 90.42).

However, the median time spent for seniors (80 minutes) is less than that of juniors (95 minutes), indicating that the data for seniors might be skewed by some outliers.

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Answer:

  (x +4)²/25 +(y -3)²/16 = 1

Step-by-step explanation:

You want the equation of the ellipse with center (-4, 3) and semi-axes 5 and 4 in the x- and y-directions, respectively.

The standard form equation for an ellipse with center (h, k) and sem-axes 'a' and 'b' in the x- and y-directions, respectively, is ...

  (x -h)²/a² +(y -k)²/b² = 1

Using the given values, we find the equation to be ...

  (x +4)²/25 +(y -3)²/16 = 1

__

Additional comment

The longer of the two axes is the "major" axis, and its end points are the "vertices". For the purpose of an ellipse with center, vertices, and co-vertices specified, the equation is not affected by which axis is longer.

Effectively, this is the equation of a circle with different scale factors in the x- and y-directions.

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8 people didn't use any of the gym pool or track facilities.

The number of people use any facilities need to subtract the total number of people who used at least one facility from the total number of people in the sport centre.

The total number of people who used at least one facility by adding the number of people who used each facility and subtracting the number of people who used two facilities and three facilities:

Total = Gym + Pool + Track - (Gym and Pool) - (Pool and Track) - (Gym and Track) + (Gym and Pool and Track)

Total = 77 + 62 + 65 - 27 - 23 - 31 + 4

Total = 127

The number of people who didn't use any facilities is:

135 - 127 = 8

8 people didn't use any of the gym, pool or track facilities.

The number of individuals who did not utilise any facilities must be subtracted from the total number of individuals who utilised at least one facility.

The total number of individuals who utilised at least one facility is calculated by adding the individuals who utilised each facility and deducting the individuals who utilised two and three facilities:

Total = Fitness Centre + Pool + Track - Fitness Centre and Pool - Fitness Centre and Track - Fitness Centre and Pool and Track

Total = 77 + 62 + 65 - 27 - 23 - 31 + 4

Total = 134-127

= 8

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Answer: I believe the answer is Yolanda.

Step-by-step explanation: Because Maurice ran 110 meters in 20.9 seconds, which is slower than Yolanda. Completing the race in 20 seconds is better than 20.9 seconds.

Answer:

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Step-by-step explanation:

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The graph of the logarithmic function is attached below with a vertical asymptote at x = -8 and two integer coordinates at (2, -7) and (1, -10).

The basic logarithmic function is of the form f(x) = logax (r) y = logax, where a > 0. It is the inverse of the exponential function ay = x. Log functions include natural logarithm (ln) or common logarithm (log).

To plot the graph of the given function, we simply need to use a graphing calculator.

The given function is;

f(x) = -3log₃(x + 8) - 4

To find the asymptotes of the graph;

x + 8 > 0

x > -8

The vertical asymptotes is at x = -8

The two points with integer coordinates are (2, -7) and (1, -10)

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Answer:

3:26

Step-by-step explanation:

.

Answer: x= 10

Step-by-step explanation:

2x+4=24

2x=24-4

2x=20

x=10

Answer:

Step-by-step explanation:

2x+4=4

subtract 4 from both sides

2x=0

divide by 2 on both sides

x=0

The graph of the given function is attached.

Given is a function for the rainfall in 5 months in inches.

We need to display the data,

So, as we can see that the data is not showing any proportion or pattern,

So, it can be displayed as a line chart.

Hence the chart is attached for the function.

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The statements that complete the function transformations are left, up, stretch and stretch

From the question, we have the following parameters that can be used in our computation:

f(x) = (x + 94)²

Also, we have

f(x) = x²

This implies that f(x) = (x + 94)² is obtained by shifting f(x) = x² left by 94 units

Next, we have

f(x) = x² + 94

This implies that f(x) = x² + 94² is obtained by shifting f(x) = x² up by 94 units

Next, we have

f(x) = 94√x from f(x) = √x

This implies that f(x) = 94√x can be obtained from vertically stretching f(x) = √x by a factor of 94

Also, the graph of f(x) = √94x can be obtained from horizontally stretching f(x) = √x by a factor of 1/94

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Answer:

6 1/243

Step-by-step explanation:

6 goes into 1459, 243 times

243*6=1458

1459-1458=1

So there is a remainder of 1

So the answer would be 6 1/243

The estimated population of the town in 2023 is 57,344.

(a) Let P be the population in t years after 2014.

Since the population doubles every year, we can use the formula :

P = P₀(2)ⁿ, where P₀ is the initial population in 2014.

We have P₀= 112, so the equation is P = 112(2)ⁿ.

(b) To find the population in 2023, we need to find t when t + 2014 = 2023.

So t = 2023 - 2014 = 9.

Substituting t = 9 into the equation from part (a), we get:

P = 112(2)⁹

P ≈ 57,344

Therefore, the estimated population of the town in 2023 is 57,344.

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Answer:

Eat that cookie and you will not regret about it

Answer:

1 1/6 metre

Step-by-step explanation:

1/3 pink + 5/6 purple

To add, we need to get a common denominator

1/3 *2/2 = 2/6

2/6 + 5/6

7/6

Change from an improper fraction to a mixed number

1 1/6 metre

Answer:

B. 1 tick mark represents 0.2 unit

Step-by-step explanation:

Looking at the axis and going over 2 tick marks is .4

.4 /2 = .2

Each tick mark is .2 units

Answer:

1)  A = 32.6°, C = 111.4°, b = 12.0

2) A = 53.6°, B = 85.7°, C = 40.7°

Step-by-step explanation:

Given values of triangle ABC:

First, find the measure of side b using the Law of Cosines for finding sides.

[tex]\boxed{\begin{minipage}{6 cm}\underline{Law of Cosines (for finding sides)} \\\\$c^2=a^2+b^2-2ab \cos (C)$\\\\where:\\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides.\\ \phantom{ww}$\bullet$ $C$ is the angle opposite side $c$. \\\end{minipage}}[/tex]

As the given angle is B, change C for B in the formula and swap b and c:

[tex]b^2=a^2+c^2-2ac\cos(B)[/tex]

Substitute the given values and solve for b:

[tex]\implies b^2=11^2+19^2-2(11)(19)\cos(36^{\circ})[/tex]

[tex]\implies b^2=482-418\cos(36^{\circ})[/tex]

[tex]\implies b=\sqrt{482-418\cos(36^{\circ})}[/tex]

[tex]\implies b=11.9929519...[/tex]

Now we have the measures of all three sides of the triangle, we can use the Law of Cosines for finding angles to find the measures of angles A and C.

[tex]\boxed{\begin{minipage}{7.6 cm}\underline{Law of Cosines (for finding angles)} \\\\$\cos(C)=\dfrac{a^2+b^2-c^2}{2ab}$\\\\\\where:\\ \phantom{ww}$\bullet$ $C$ is the angle. \\ \phantom{ww}$\bullet$ $a$ and $b$ are the sides adjacent the angle. \\ \phantom{ww}$\bullet$ $c$ is the side opposite the angle.\\\end{minipage}}[/tex]

To find the measure of angle A, swap a and c in the formula, and change C for A:

[tex]\implies \cos(A)=\dfrac{c^2+b^2-a^2}{2cb}[/tex]

[tex]\implies \cos(A)=\dfrac{19^2+(11.9929519...)^2-11^2}{2(19)(11.9929519...)}[/tex]

[tex]\implies \cos(A)=0.842229094...[/tex]

[tex]\implies A=\cos^{-1}(0.842229094...)[/tex]

[tex]\implies A=32.6237394...^{\circ}[/tex]

To find the measure of angle C, substitute the values of a, b and c into the formula:

[tex]\implies \cos(C)=\dfrac{a^2+b^2-c^2}{2ab}[/tex]

[tex]\implies \cos(C)=\dfrac{11^2+(11.9929519...)^2-19^2}{2(11)(11.9929519...)}[/tex]

[tex]\implies \cos(C)=-0.364490987...[/tex]

[tex]\implies C=\cos^{-1}(-0.364490987...)[/tex]

[tex]\implies C=111.376260...^{\circ}[/tex]

Therefore, the remaining side and angles for triangle ABC are:

[tex]\hrulefill[/tex]

To solve for the remaining angles of the triangle ABC given its side lengths, use the Law of Cosines for finding angles.

[tex]\boxed{\begin{minipage}{7.6 cm}\underline{Law of Cosines (for finding angles)} \\\\$\cos(C)=\dfrac{a^2+b^2-c^2}{2ab}$\\\\\\where:\\ \phantom{ww}$\bullet$ $C$ is the angle. \\ \phantom{ww}$\bullet$ $a$ and $b$ are the sides adjacent the angle. \\ \phantom{ww}$\bullet$ $c$ is the side opposite the angle.\\\end{minipage}}[/tex]

Given sides of triangle ABC:

Substitute the values of a, b and c into the Law of Cosines formula and solve for angle C:

[tex]\implies \cos(C)=\dfrac{a^2+b^2-c^2}{2ab}[/tex]

[tex]\implies \cos(C)=\dfrac{21^2+26^2-17^2}{2(21)(26)}[/tex]

[tex]\implies \cos(C)=\dfrac{828}{1092}[/tex]

[tex]\implies C=\cos^{-1}\left(\dfrac{828}{1092}\right)[/tex]

[tex]\implies C=40.690560...^{\circ}[/tex]

To find the measure of angle B, swap b and c in the formula, and change C for B:

[tex]\implies \cos(B)=\dfrac{a^2+c^2-b^2}{2ac}[/tex]

[tex]\implies \cos(B)=\dfrac{21^2+17^2-26^2}{2(21)(17)}[/tex]

[tex]\implies \cos(B)=\dfrac{54}{714}[/tex]

[tex]\implies B=\cos^{-1}\left(\dfrac{54}{714}\right)[/tex]

[tex]\implies B=85.6625640...^{\circ}[/tex]

To find the measure of angle A, swap a and c in the formula, and change C for A:

[tex]\implies \cos(A)=\dfrac{c^2+b^2-a^2}{2cb}[/tex]

[tex]\implies \cos(A)=\dfrac{17^2+26^2-21^2}{2(17)(26)}[/tex]

[tex]\implies \cos(A)=\dfrac{524}{884}[/tex]

[tex]\implies A=\cos^{-1}\left(\dfrac{524}{884}\right)[/tex]

[tex]\implies A=53.6468753...^{\circ}[/tex]

Therefore, the measures of the angles of triangle ABC with sides a = 21, b = 26 and c = 17 are:

The distance that the plane traveled from point A to point B is given as follows:

10,750 ft.

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

The altitude of 5375 feet is the opposite angle, hence the position A is obtained as follows:

tan(15º) = 5375/A

A = 5375/tangent of 15 degrees

A = 20060 ft.

The position B is obtained as follows:

B = 5375/tangent of 30 degrees

B = 9310 ft.

Hence the distance is of:

20060 - 9310 = 10,750 ft.

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