Grade 10 Science send answers plssssss

Grade 10 Science Send Answers Plssssss

Answers

Answer 1

Answer:

ITS UPSIDE DOWN I CANT ANSWER IT

i will edit the answer if its normal

Explanation:


Related Questions

3 enzimas presentes en nuestro organismo e indique en que procesos actúan

Answers

Answer:

ATP asa, Helicasa, Proteasa, ARN polimerasa

Explanation:

Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.

Al momento de referirse a ellas, se utiliza la terminación asa.

ATPasa → Sintetizando ATP para el funcionamiento celular

Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.

Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.

ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.

An aqueous salt solution is 15.0% mass sodium chloride. How many grams of salt are in 250.0 grams of this solution? Use correct
significant figures.

Answers

Answer:

37.5 g NaCl

Explanation:

Step 1: Given data

Concentration of NaCl: 15.0% m/mMass of the solution: 250.0 g

Step 2: Calculate how many grams of NaCl are in 250.0 g of solution

The concentration of NaCl is 15.0% by mass, that is, there are 15.0 g of NaCl every 100 g of solution.

250.0 g Solution × 15.0 g NaCl/100 g Solution = 37.5 g NaCl

If a light beam strikes a shiny object at a 90-degree angle, to what are the angle of incidence and the angle of reflection equal?

Answers

Answer:

Angle of incidence = angle of reflection = 0

Explanation:

Given that,

A light beam strikes a shiny object at a 90-degree angle.

The angle made by incident ray and normal to the mirror is called the angle of incidence and the angle made by the reflected ray and the normal is called the angle of reflection.

Here, the beam strikes normally. So, the angle of incidence is 0.

A/c to the law of reflection,

Angle of incidence = angle of reflection

So, the angle of reflection is also equal to 0.

At a certain temperature, 0.700 mol SO3 is placed in a 3.50 L container. 2SO3(g)↽−−⇀2SO2(g)+O2(g) At equilibrium, 0.180 mol O2 is present. Calculate c.

Answers

Answer: The value of [tex]K_c[/tex] for the given chemical equation is 0.0457.

Explanation:

Given values:

Initial moles of [tex]SO_3[/tex] = 0.700 moles

Volume of conatiner = 3.50 L

The given chemical equation follows:

            [tex]2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)[/tex]

I:             0.700

C:              -2x           +2x           x

E:           0.700-2x      2x            x

Equilibrium moles of [tex]O_2[/tex] = x = 0.180 moles

Equilibrium moles of [tex]SO_2[/tex] = 2x = [tex](2\times 0.180)=0.360moles[/tex]

Equilibrium moles of [tex]SO_3[/tex] = 0.700 - 2x = [tex]0.700-(2\times 0.180)=0.340moles[/tex]

Molarity is calculated by using the equation:

[tex]Molarity=\frac{Moles}{Volume}[/tex]

So,

[tex][SO_3]_{eq}=\frac{0.340}{3.50}=0.0971M[/tex]

[tex][SO_2]_{eq}=\frac{0.360}{3.50}=0.103M[/tex]

[tex][O_2]_{eq}=\frac{0.180}{3.50}=0.0514M[/tex]

The expression of [tex]K_c[/tex] for above equation follows:

[tex]K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}[/tex]

Plugging values in above expression:

[tex]K_c=\frac{(0.0971)^2\times 0.0514}{(0.103)^2}\\\\K_c=0.0457[/tex]

Hence, the value of [tex]K_c[/tex] for the given chemical equation is 0.0457.

How would the accuracy of your determined Keq change if all of your volume measurements were made with graduated cylinders rather than pipets

Answers

Answer:

Accuracy decreases

Explanation:

All meaurements have an uncertainty (That is, the error of the measurement). The uncertainty of graduated cylinders is higher than uncertainty of pipets.

The accuracy is how close is the measurement to the real value.

If you use graduated cylinders rather than pipets, accuracy decreases because you will have more uncertainty in the measurements putting of the real value and the real value.

The accuracy of the determined value decreases if all measurement is done with graduated cylinders.

What is Accuracy?

The accuracy is the measurement of how close the calculated value is to the real value.

When a student measures the volume with a graduated cylinder the chances of error increase.

Therefore, the accuracy of the determined value decreases if all measurement is done with graduated cylinders.

Learn more about accuracy:

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Which compounds, on heating with an excess of concentrated sulfuric acid, produce only one product with molecular formula C7H10? [choices on the picture]

Answers

Answer:

1 and 2

Explanation:

When Concentrated H2SO4 reacted with the alcohols, they produce cycloalkenes. This is a mechanism known as dehydration of alcohols with an acid catalyst. This is because concentrated H2SO4 acts as a great oxidizing agent. In the process, the alcohols are heated to a high temperature with an excess of pure sulfuric acid. By passing the gases through a sodium hydroxide solution, the carbon dioxide and sulfur dioxide produced by reactive species are eliminated. The reaction mechanism shown in the image below indicates that only compounds 1 and 2 produce only one product.

1.00 mL of 12.0 M HCl is added to 1.00 L of a buffer that contains 0.110 M HNO2 and 0.170 M NaNO2. How many moles of HNO2 and NaNO2 remain in solution after addition of the HCl

Answers

Answer:

Moles of NaNO2 = 0.158

Moles of HNO2 final = 0.098

Explanation:

Given

Moles of HCl = 12

Moles of HNO2 = 0.11

Moles of NaNO2 = 0.170

HCl +NaNO2 --> HNO2  + NaCl

1 mole of HCl react with one mole of NaNO2 to produce 1 mole of NaCl and 1 mole of HNO2

Moles of NaNO2 = 0.17 - 0.012 = 0.158

Moles of HNO2 final = 0.11 - 0.012 = 0.098

Calculate the molality of a solution that contains 75.0-grams of methyl alcohol, CH3OH, dissolved in 600.0-grams of
water.

Answers

Answer:

[tex]m=3.90mol/kg[/tex]

Explanation:

Hello there!

In this case, since the molality of a solution is calculated by dividing moles of solute by kilograms of solvent, it turns out firstly necessary for us to calculate the moles of methyl alcohol in 75.0 grams as shown below:

[tex]n=\frac{75.0g}{32.04g/mol}=2.34mol[/tex]

Then, the kilograms of water, 0.600 kg, and finally, the resulting molality:

[tex]m=\frac{2.34mol}{0.600kg}\\\\m=3.90mol/kg[/tex]

Regards!

The reaction of iron (III) oxide with carbon monoxide produces iron and carbon dioxide.
Fe2O3(s) + 3C0(9) - 2Fe(s) + 3CO (9)
How many grams of Fe2O3 are required to produce 4.65g Fe? You must show your work to receive full credit.

Answers

Answer:

6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.

Explanation:

The balanced reaction is:

Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Fe₂O₃: 1 moleCO: 3 molesFe: 2 molesCO₂: 3 moles

The molar mass of each compound is:

Fe₂O₃: 159.7 g/moleCO: 28 g/molFe: 55.85 g/moleCO₂: 44 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Fe₂O₃: 1 mole* 159.7 g/mole= 159.7 gramsCO: 3 moles* 28 g/mol= 84 gramsFe: 2 moles* 55.85 g/mole= 111.7 gramsCO₂: 3 moles* 44 g/mole= 132 grams

Then you can apply the following rule of three: if by stoichiometry 111.7 grams of Fe are produced from 159.7 grams of Fe₂O₃, 4.65 grams of Fe are produced from how much mass of Fe₂O₃?

[tex]mass of Fe_{2} O_{3} =\frac{4.65 grams of Fe*159.7 grams of Fe_{2} O_{3}}{111.7grams of Fe}[/tex]

mass of Fe₂O₃= 6.65 grams

6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.

The atomic particle with a charge of -1.6 x 10-19 C is

Answers

no sefdrcdftrgfkjj jhhhgfd

Which one of the mixtures would most likely produce a chemical reaction?
F2 + At- OR At2 + F-

Answers

Answer:

F₂ + At⁻

Explanation:

Astatine is the only Halogen that does not exist as a diatomic molecule. One Astatine atom would have a charge of 1⁻. Fluorine is the most electronegative element, and therefore very reactive and commonly forms a diatomic molecule.

Given that vat contains 9600 kg of milk, what is the mass of mg of the milk that vat contains?

Answers

Answer:

9.6x10⁹ mg

Explanation:

In order to solve this problem we need to convert 9600 kg into mg.

First we convert 9600 kg into g, keeping in mind that 1 kg = 1000 g:

9600 kg * [tex]\frac{1000g}{1kg}[/tex] = 9.6x10⁶ g

Then we convert 9.6x10⁶ g into mg, keeping in mind that 1 g = 1000 mg:

9.6x10⁶ g * [tex]\frac{1000mg}{1g}[/tex] = 9.6x10⁹ mg

The mass of milk miligrams is 9.6x10⁹.

Two hundred forty-eight milliliters of an acid with an unknown concentration are titrated with a base that has a
concentration of 1.4 M. The indicator changed color when 82 milliliters of base were added. What is the concentration of
the unknown acid?
O 0.46 M
4.2 M

Answers

Answer:0.46

Explanation:

How many grams of aluminum is required to react with 75.0 ml of 2.50 M HCl?

Answers

Answer:

63 g Al is required to react with 35 mL of 2.50 M hydrochloric acid

I'm sorry if it's wrong, I tried.

Explanation:

PLEASE HELP ME SOLVE THIS.Thank you so much!

Answers

Answer: The coefficients for the given reaction species are 1, 6, 2, 3.

Explanation:

The given reaction equation is as follows.

[tex]Cr_{2}O^{2-}_{7} + Cl^{-} \rightarrow Cr^{3+} + Cl_{2}[/tex]

Now, the two half-reactions can be written as follows.

Reduction half-reaction: [tex]Cr_{2}O^{2-}_{7} + 3e^{-} \rightarrow Cr^{3+}[/tex]

This will be balanced as follows.

[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6e^{-} \rightarrow 2Cr^{3+} + 7H_{2}O[/tex] ... (1)

Oxidation half-reaction: [tex]Cl^{-} \rightarrow Cl_{2} + 1e^{-}[/tex]

This will be balanced as follows.

[tex]6Cl^{-} \rightarrow 3Cl_{2} + 6e^{-}[/tex] ... (2)

Adding both equation (1) and (2) we will get the resulting equation as follows.

[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6Cl^{-} \rightarrow 2Cr^{3+} + 3Cl_{2} + 7H_{2}O[/tex]

Thus, we can conclude that coefficients for the given reaction species are 1, 6, 2, 3.

which of the following can cause muscle fatigue ?
A.A build up of lactic acid
b.an inadequate supply of oxygen
C.an inadequate supply of glycogen
D.all of the above​

Answers

Answer:

The correct answer is -all of the above.

Explanation:

Muscle fatigue is a reduced ability in work capacity caused by work itself. It is known that altering oxygen is contracting skeletal muscle affects performance. Reduced O2 supply increases the rate of muscle fatigue.

The lactic acid is accumulated as it forms rapidly but the breaking of the lactic acid is slow down, which causes muscle fatigue. Less ATP and glycogen in muscle results in fatigue as the muscle is not able to generate energy to power contractions and therefore contributes to muscle fatigue.

Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures PA and inside the flasks are measured.

a. PA will be greater than
b. PA will be less than PB
c. PA will be equal to PB
d. It's impossible to predict whether PA or will be greater without more information.

Answers

The question is incomplete, the complete question is:

Liquid A is known to have a lower viscosity and lower vapor pressure than Liquid B. Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures [tex]p_A[/tex] and [tex]p_B[/tex] inside the flasks are measured.

a. [tex]p_A[/tex] will be greater than

b. [tex]p_A[/tex] will be less than [tex]p_B[/tex]

c. [tex]p_A[/tex] will be equal to [tex]p_B[/tex]

d. It's impossible to predict whether [tex]p_A[/tex] or will be greater without more information.

Answer: The correct option is b) [tex]p_A[/tex] will be less than [tex]p_B[/tex]

Explanation:

Vapor pressure is defined as the equilibrium pressure which is exerted by the vapor phase to be in thermodynamic equilibrium with its condensed state (liquid phase) in a closed system at a given temperature.

We are given:

Vapor pressure of A < Vapor pressure of B

This means that a lesser number of gaseous molecules will form over its surface and thus, will experience lower pressure.

Thus, [tex]p_A<p_B[/tex]

Hence, the correct option is b) [tex]p_A[/tex] will be less than [tex]p_B[/tex]

Explain the science of water pressure

Answers

The deeper you go under the sea, the greater the pressure of the water pushing down on you. For every 33 feet (10.06 meters) you go down, the pressure increases by one atmosphere this is all because of an increase in hydrostatic pressure

"At sea level, the air that surrounds us presses down on our bodies at 14.7 pounds per square inch . (gooxgle) "

Basically the deeper you go under the water, whether that be a pool or the sea the pressure will increase because of the weight of the water above you.  Which causes greater force.

What is the product of the unbalanced equation below?
Ca(s) + O2(g)

A. CaO2(5)
B. Cao(s)
C. 2Ca(s) + O2(9)
D. Ca20(s)

Answers

Answer:

I think B

Explanation:

2Ca + O2 -> 2CaO

The product of the unbalanced equation: [tex]\rm Ca(s) + O_2(g)[/tex] is [tex]\rm CaO(s)[/tex]. The correct answer is option B.

A product is a material which arises from a chemical process. It is the end result of the reaction and is produced by the rearrangement of the atoms or molecules of the reactants.

This reaction's balanced chemical equation is:

[tex]\rm 2Ca(s) + O_2(g) \rightarrow 2CaO(s)[/tex]

The reaction begins by heating calcium metal in the presence of oxygen gas or by exposing calcium metal to oxygen-containing air. Calcium oxide  [tex](\rm CaO)[/tex] is formed by the reaction of calcium metal (Ca) with oxygen gas[tex]\rm (O_2)[/tex].

In this equation, two atoms of calcium react with one molecule of oxygen gas to form two molecules of calcium oxide. The reaction is exothermic, meaning it releases heat energy.

Therefore, the result of the stated chemical reaction is [tex]\rm CaO(s)[/tex]. Option B is the correct answer.

Learn more about product here:

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Suppose that you add 21.0 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f of 5.12 oC/m. With the added solute, you find that there is a freezing point depression of 2.58 oC compared to pure benzene. What is the molar mass (in g/mol) of the unknown compound

Answers

Hey can you please help me please

Write the Ka expression for an aqueous solution of hypochlorous acid: (Note that either the numerator or denominator may contain more than one chemical species. Enter the complete numerator in the top box and the complete denominator in the bottom box. Remember to write the hydronium ion out as , and not as )

Answers

Answer: The Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].

Explanation:

The chemical formula of hypochlorous acid is HClO. So, when it is added to water (solvent) then its dissociation is as follows.

[tex]HClO + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}[/tex]

When we write the equilibrium constant for this reaction then it is called acid acid dissociated constant.

Hence, the expression for acid dissociation constant of this reaction is as follows.

[tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex]

Thus, we can conclude that the Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].

PLS HELP ME PLZ AND THANKS

Answers

Answer:

q6= third option

q7= third option

Explanation:

kinetic molecular theory deals with temperature

pressure inversely proportional to volume so when volume doubled, pressure halved given that mass and temperature constant

If a swimming pool contains 2850 kg liters of water how many gallons of water does it contain

Answers

Your answer would be 753,000 gallons of water

Se prepara una solución agregando sal en 500 g de agua. Calcular la masa de sal, cuando se tiene una solución al 6,4 % en masa

Answers

Answer:

x~ 34.19 grams del sal o ~ 34 grams!

Explanation:

el porcentaje de masa se escribe como

% de masa = masa de sal / (masa de sal + masa de disolvente) * 100%

aquí, el disolvente se da como 500 g de agua.

usa x en lugar de masa de sal y resuelve usando álgebra

6.4 = x / (x+ 500) * 100

0.064 = x / (x+500)

0.064 x + 32 = x

32 = x-0.064x

32 = 0.936 x

x~ 34.19 grams del sal o ~ 34 grams!

The ideal gas law is PV = nRT.
Use 8.31 for R. (8.31 Lx kPa / Kx mol)
What is the temperature of 3.0 moles of a gas that is in a closed container of
volume 9L, and has a pressure of 85kPa?


1. 3.4 kelvin
2. 0.03 kelvin
3. 30.7 kelvin
4. 28.6 kelvin

Answers

Answer: 30.66945 kelvin

Explanation:

The normal boiling point of a certain liquid X is 130.9 °C, but when 19.9 g of urea (NH2) CO are dissolved in 200. g of X, it is found that the solution boils at 134.1 °C instead. Use this information to calculate the molal boiling point elevation constant K, of X. Be sure your answer has the correct number of significant digits x 1 ℃.mol -kg

Answers

Answer:

K = 1.93 °C/m

Explanation:

This question can be solved by formula of elevation of boiling point.

Boiling T° of solution - Boiling T° of pure solvent = K . m . i

Our solute is urea.

Our solvent is X.

We convert mass of urea to moles: 19.9 g . 1 mol / 60.06g = 0.331 mol

We convert g of solute to kg = 200 g . 1 kg/ 1000g = 0.2kg

m = molality → moles of solute / kg of solvent

m = 0.331 mol / 0.2 kg = 1.66 m

As urea is an organic compound, no ions will be formed.

i = 1 (a non ionizing compound)

Let's replace data in formula:

134,1°C - 130.9°C = K . 1.66 m . 1

3.2 °C / 1.66 m = K

K = 1.93 °C/m

How many grams of oxygen are present in 93.98 g of CO2?

Answers

Answer:

There are about 68.33 grams of oxygen present in 93.98 g of CO2.

Calculate the pKa of hypochlorous acid (HClO, a weak acid). A 0.015 M solution of hypochlorous acid has a pH of 4.64.

Answers

Answer:

"7.46" is the correct answer.

Explanation:

Given that:

[tex]pH=4.64[/tex]

[tex]C=0.015 \ M[/tex]

The equation:

⇒ [tex]HA \rightleftharpoons H^++A^-[/tex]

HA = C - Cα

H⁺ = Cα

A⁻ = Cα

now,

⇒ [tex]pH=-log(H^+)[/tex]

          [tex]=-log(C \alpha)[/tex]

          [tex]=4.64[/tex]

    [tex]C \alpha = 2.3\times 10^-5 \ M[/tex]

As we know,

⇒ [tex]K_a=C \alpha^2[/tex]

         [tex]=(\frac{C \alpha}{C} )^2\times C[/tex]

         [tex]=\frac{(2.3\times 10^{-5})^2}{0.015}[/tex]

         [tex]=3.5\times 10^{-8}[/tex]

hence,

⇒ [tex]pK_a=-log(K_a)[/tex]

           [tex]=7.46[/tex]          

Which bodies of water in the list are found to the west of the Philippines?​

Answers

Answer:

South China sea

Explanation:

To the west is the South China Sea, to the east the Philippine Sea and the Pacific Ocean, and to the south the Celebes Sea (or Sulawesi Sea).

Select the correct answer.
Which value of Keq represents a scenario where the reactants of an equilibrium reaction are favored?
A.
Keq=1
B.
Keq = 6.0 x 10-2
O C.
Keq = 3.8 x 104
OD
Keq = 490.5
O E. Keq = 2.5

Answers

Answer:

B.  Keq = 6.0 x 10-2.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to remember that any equilibrium constant is computed by dividing the concentration of products by that of reactants:

[tex]Keq=\frac{[Prod]}{[Reac]}[/tex]

Thus, a reaction that is reactant-favored will have a Keq>1 because the concentration of reactants prevail over that of products at equilibrium, and thus, the correct answer is B.  Keq = 6.0 x 10-2.

Regards!

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