Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm until the height of the alcohol column is 20 cm. The two liquids do not mix. What is the difference in height between the top surface of the glycerin and the top surface of the alcohol? Suppose that the density of glycerin is 1260 kg/m3and the density of alcohol is 790 kg/m3.

Complete Question

The maximum electric field strength in air is 4.0 MV/m. Stronger electric fields ionize the air and create a spark. What is the maximum power that can be delivered by a 1.4-cm-diameter laser beam propagating through air

Answer:

The  value  is  [tex]P = 3.270960 *10^{6} \  W[/tex]

Explanation:

From the question we are told that

   The  electric field strength is  [tex]E = 4.0 \ M \ V/m = 4.0 *10^6 \ V/m[/tex]

    The  diameter is  [tex]d = 1.4 \ cm = 0.014 \ m[/tex]

Generally the radius is mathematically represented as

        [tex]r = \frac{d}{2}[/tex]

=>     [tex]r = \frac{0.014}{2}[/tex]

=>    [tex]r = 0.007 \ m[/tex]

Generally the cross-sectional area is mathematically represented as

        [tex]A =  \pi r^2[/tex]

        [tex]A =  3.142 *  (0.007)^2[/tex]

       [tex]A = 0.000154 \ m^2[/tex]

Generally the maximum power that can be delivered is mathematically represented as

        [tex]P = \frac{c *  \epsilon_o  *  E^2 *  A }{2}[/tex]

Here c is the speed of light with value  [tex]c =  3.0*10^{8} \  m/s[/tex]

        [tex]\epsilon_o[/tex] is the permittivity of free space with value  [tex]\epsilon_o  =  8.85 *10^{-12}  \ m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2[/tex]

     [tex]P =  \frac{3,0*10^8 *  8.85*10^{-12} *  (4 *10^6)^2 * 0.00154}{ 2}[/tex]

       [tex]P = 3.270960 *10^{6} \  W[/tex]

Answer:

Copernicus rediscovered Aristarchus’s heliocentric model

Explanation:

Answer:

projectiles

electromagnetic

Answer:

Explanation:

física cuántica y  Quantum Moves

Answer:

[tex]I=0.54\ kg-m^2[/tex]

Explanation:

Given that,

Mass of a uniform rod, m = 12 kg

Length of the rod, l = 0.3 m

The moment of inertia rotating about an axis perpendicular to the rod and passing through the center of the rod is given by :

[tex]I=\dfrac{ml^2}{2}\\\\I=\dfrac{12\times (0.3)^2}{2}\\\\I=0.54\ kg-m^2[/tex]

So, the moment of inertia of the rod is [tex]0.54\ kg-m^2[/tex]

Answer:

d' = 0.86 mm

Explanation:

First we need to find the area of low power field:

A = πd²/4

where,

A = Area = ?

d = diameter = 1.5 mm

Therefore, using the value of diameter, we get:

A = π(1.5 mm)²/4

A = 1.767 mm²

Now, the new object occupies 1/3rd of this area:

A' = (1/3)A

πd'²/4 = (1/3)A

d'² = (4/3π) A

d'² = (4/3π)(1.767 mm²)

d' = √(0.75 mm²)

d' = 0.86 mm

Complete Question

A  voltaic cell is  constructed with two [tex]Zn^{2+}[/tex][tex]- Zn[/tex] electrodes. The  two cell compartment have  [tex][Zn^{2+}] =  1.6 \ M[/tex] and  [tex][Zn^{2+}] =  2.00*10^{-2} \  M[/tex] respectively.

What is the cell emf for the concentrations given? Express your answer using two significant figures

Answer:

The value is   [tex]E =  0.06 V[/tex]

Explanation:

Generally from the question we are told that

   The  concentration of [tex][Zn^{2+}][/tex] at the cathode is  [tex][Zn^{2+}]_a =  1.6 \ M[/tex]

    The  concentration of [tex][Zn^{2+}][/tex] at the anode is [tex][Zn^{2+}]_c =  2.00*10^{-2} \  M[/tex]

Generally the the cell emf for the concentration is mathematically represented as

     [tex]E =  E^o - \frac{0.0591}{2} log\frac{[Zn^{2+}]a}{ [Zn^{2+}]c}[/tex]

Generally the [tex]E^o[/tex]is the standard emf of a cell, the value is  0 V

So

      [tex]E =  0  -  \frac{0.0591}{2}  * log[\frac{ 2.00*10^{-2}}{1.6} ][/tex]

=>      [tex]E =  0.06 V[/tex]

The question is incomplete,so the complete question is as follows:

According to Einstein, increasing the brightness (or intensity) of a beam of light without changing its color will increase (circle all that apply):

A) the number of photons per second traveling in the beam.

B) the energy of each photon.

C) the speed of the photons.

D) the frequency of the light.

E) the wavelength of the photons

Answer:

A)  

Explanation:

According to Einstein, an increase in the intensity or brightness of light beam will increase the number of photons over a given time interval.

It means that the energy emitted will depend on the energy of individual photon rather than the intensity of the incoming light.

Hence, the correct option is "A)"

Answer:

2km

Explanation:

Answer:

[tex]\frac{kq^{2} }{2a^2}[/tex]

Explanation:

The magnitude on the charge at the bottom-left corner due to the charge on the top vertex of the triangle will act along the +ve x-axis and the +ve y-axis.

From Coulomb's law the magnitude of the forces on the charge at the bottom-left corner, due to the charge on the top vertex of the triangle are [tex]\frac{kq^{2} }{a^2}[/tex]cos 60, and

The magnitude on the charge due to the charge at the bottom-right corner will only act in the -ve x-axis, since they repel each other (like charges repel). The magnitude is  [tex]\frac{kq^{2} }{a^2}[/tex]

The angle made by the upper charge to the charge we're considering is 60° with the horizontal.

The total force on the charge along the x-axis is

[tex]F_{x}[/tex] = [tex]\frac{kq^{2} }{a^2}[/tex]cos 60 -

[tex]F_{x}[/tex]  = [tex]\frac{kq^{2} }{2a^2}[/tex] - [tex]\frac{kq^{2} }{a^2}[/tex]

==> -[tex]\frac{kq^{2} }{2a^2}[/tex]

For the y-axis, we have

[tex]F_{y}[/tex] = [tex]\frac{kq^{2} }{a}[/tex]sin 60

[tex]F_{y}[/tex] = [tex]\frac{\sqrt{3}* kq^{2} }{2a^2}[/tex]

The resultant force is

[tex]|F| = \sqrt{F_{x}^{2}+ F_{y}^2 }[/tex]

The common factors between the two x-axis force, and the y-axis force is

[tex]\frac{kq^{2} }{2a^2}[/tex], we put this outside the square root (squaring this and square rooting will give us the initial value)

[tex]|F|[/tex] = [tex]\frac{kq^{2} }{2a^2}[/tex][tex]\sqrt{(\frac{1}{2})^2 + (\frac{\sqrt{3} }{2})^2 }[/tex]

[tex]|F|[/tex] =  [tex]\frac{kq^{2} }{2a^2}[/tex][tex]\sqrt{\frac{1}{4} +\frac{3}{4} }[/tex]

==>  [tex]\frac{kq^{2} }{2a^2}[/tex][tex]\sqrt{1}[/tex]

the magnitude of the electric force on the charge at the bottom left-hand vertex of the triangle due to the other two charges is

[tex]|F|[/tex]  =  [tex]\frac{kq^{2} }{2a^2}[/tex]

Answer:

Hello your question is incomplete attached is the missing diagram and solution

One elevator arrangement includes the passenger car, a counterweight, and two large pulleys, as shown in (Figure 1). Each pulley has a radius of 1.2 m and a moment of inertia of 410 kg⋅m2. The top pulley is driven by a motor. The elevator car plus passengers has a mass of 3000 kg, and the counterweight has a mass of 2600 kg.

a) If the motor is to accelerate the elevator car upward at 1.8 m/s2, how much torque must it generate? Express your answer to two significant figures and include appropriate units.

Answer : 6030 N.m ≈ 6000 N.m

Explanation:

To determine how much torque the motor accelerating at 1.8 m/s^s will generate we will have to determine T1 ( tension  generated for upward acceleration in the rope  ) and Tg ( tension  generated in the rope when there is a counterweight accelerating downwards)

Torque in the pulley (T2) = (T1 - Tg ) r

torque generated by motor = T1 + T2 = 1230 + 4800 = 6030 N.m to two significant figures = 6000 N.m

r = 1.2

a = 1.8

attached below is the remaining part of the solution

Answer:

The options are

A) isochoric.

B) isothermal.

C) adiabatic.

D) isobaric.

The answer is C. Adiabatic

Adiabatic process involves zero loss or gain of heat in a system. This is usually depicted as Q= 0.

An ideal gas being compressed in a well-insulated chamber using a well-insulated piston involves the use of adiabatic process. The insulated chamber and piston helps to prevent heat loss or gain of heat. This is because insulators are poor conductors of heat and electricity.

The process of compressing an ideal gas in a well-insulated chamber using a well-insulated piston is known as adiabatic process.

When an ideal gas in compressed adiabatically, the heat lost is zero and the work is done it which causes increase its temperature.

Q = 0

The well-insulated chamber and piston helps to prevent heat loss by conduction and convection. The results in a zero heat lost to the surroundings.

Thus, we can conclude that the process of compressing an ideal gas in a well-insulated chamber using a well-insulated piston is known as adiabatic process.

Learn more about adiabatic process here: https://brainly.com/question/17185468

Answer:

4 hoop, disk, sphere

Explanation:

Because

We are given data that

Hoop, disk, sphere have Same mass and radius

So let

And Initial angular velocity, = 0

The Force on each be F

And Time = t

Also let

Radius of each = r

So let's find the inertia shall we!!

I1 = m r² /2

= 0.5 mr² the his is for dis

I2 = m r² for hoop

And

Moment of inertia of sphere wiil be

I3 = (2/5) mr²

= 0.4 mr²

So

ωf = ωi + α t

= 0 + ( τ / I ) t

= ( F r / I ) t

So we can see that

ωf is inversely proportional to moment of inertia.

And so we take the

Order of I ( least to greatest ) :

I3 (sphere) , I1 (disk) , I2 (hoop) , ,

Order of ωf: ( least to greatest)

That of omega xf is the reverse of inertial so

hoop, disk, sphere

Option - 4

The ranking of the objects according to their angular acceleration is option 4 hoop, disk, sphere.

Since

Hoop, disk, sphere contain Same mass and radius

So here

Initial angular velocity, = 0

The Force on each be F

And Time = t

Radius of each = r

Now

I1 = m r² /2

= 0.5 mr² his is for dis

I2 = m r² for hoop

And

Moment of inertia of sphere should be

I3 = (2/5) mr²

= 0.4 mr²

Now

ωf = ωi + α t

= 0 + ( τ / I ) t

= ( F r / I ) t

here,

ωf is inversely proportional to moment of inertia.

Now

Order of I ( least to greatest ) :

I3 (sphere) , I1 (disk) , I2 (hoop) , ,

Order of ωf: ( least to greatest)

That of omega xf is the reverse of inertial so

Therefore, the fourth option is correct.

learn more about radius here: https://brainly.com/question/17257279

Answer:

Explanation:

over a million times

Answer:

B) We should use the complete value of 11.76 cm², because the rounding off is done at the end of all calculations. Until then exact and complete values should be used.

C) Volume of Prism = 78 cm³

Explanation:

PART C:

Since, the volume of prism s given by the following formula:

Volume of Prism = (Area of Base of Prism)(Height of Prism)

Therefore,

Height of Prism = 6.6 cm

Area of Base of Prism = Length x Width

Area of Base of Prism = 5.6 cm x 2.1 cm

Area of Base of Prism = 11.76 cm²

Hence, the equation gives:

Volume of Prism = (11.76 cm²)(6.6 cm)

Volume of Prism = 77.616 cm³

Since, the initial values had 2 significant figures, so rounding off to two significant figures:

Volume of Prism = 78 cm²

PART B:

We should use the complete value of 11.76 cm², because the rounding off is done at the end of all calculations. Until then exact and complete values should be used.

Answer:Nuclear fusion is the process by which two or more atomic nuclei join together, or “fuse,” to form a single heavier nucleus. During this process, matter is not conserved because some of the mass of the fusing nuclei is converted to energy, which is released.

Explanation:

Atoms of different elements can combine to make new substances. A molecule is formed when two or more atoms join together chemically. If atoms combine that are of two or more different elements, we call that a compound. ... When two hydrogen atoms combine with one oxygen atom, it becomes the compound water.

Answer:

nuclear fusion

Explanation:

Answer:

The wavelength of the waves created in the swimming pool is 0.4 m

Explanation:

Given;

frequency of the wave, f = 2 Hz

velocity of the wave, v = 0.8 m/s

The wavelength of the wave is given by;

λ = v / f

where;

λ is the wavelength

f is the frequency

v is the wavelength

λ = 0.8 / 2

λ = 0.4 m

Therefore, the wavelength of the waves created in the swimming pool is 0.4 m

Answer:

213 nA

2.13 mA

851e^-t μA

Explanation:

We have a pretty straightforward question here.

Ohms Law states that the current in an electric circuit is directly proportional to the voltage and inversely proportional to the resistance in the circuit. It is mathematically written as

V = IR, since we need I, we can write that

I = V/R

a) at V = 1 mV

I = (1 * 10^-3) / 4.7 * 10^3

I = 2.13 * 10^-7 A or 213 nA

b) at V = 10 V

I = 10 / 4.7 * 10^3

I = 0.00213 A or 2.13 mA

c) at V = 4e^-t

I = 4e^-t / 4.7 * 10^3

I = 0.000851e^-t A or 851e^-t μA

Answer:

when an x-ray passes trough matter, it undergoes a process called attenuation

Answer:

Explanation:

A vector is parallel to the y axis .

Let its magnitude be A . So the vector can be represented as A j .

where i and j are unit vectors in x and y axis direction .

The x component of A j will be dot product of A j with i

The x component of A j = A j . i

= A x 0      [  Since j . i = 0 ]

= 0

Answer:

The magnitude of impulse the floor applies to the ball is 3.05 kg.m/s.

Explanation:

Given;

mass of the rubber ball, m = 0.25 kg

height of drop, h₁ = 2 m

height of rebounds, h₂ = 1.8 m

Determine the initial velocity of the ball as it moves downwards;

[tex]v_i = \sqrt{2gh}\\\\ v_i = \sqrt{2*9.8*2}\\\\v_i = 6.26 \ m/s[/tex]this initial velocity is acting downwards = - 6.26 m/s

Determine the final velocity of the ball as it rebounds

[tex]v_f = \sqrt{2gh} \\\\v_f = \sqrt{2*9.8*1.8}\\\\ v_f = 5.94 \ m/s[/tex]this final velocity is acting upwards = 5.94 m/s

Impulse is given by;

J = mΔv

[tex]J = m(v_f-v_i)[/tex]

J = 0.25(5.94 - (6.26))

J = 0.25(5.94 + 6.26)

J = 3.05 kgm/s

Therefore, the magnitude of impulse the floor applies to the ball is 3.05 kg.m/s.

Answer:

-30=5(x+1) is -7

Explanation:

distribute flip subtract 5 from both sides divide both sides by 5

Answer:

The acceleration will be a

Explanation:

Using F = ma

But we are given that F2= 2F1 and

m2= 2m1

So

a2= F2/m2= F1/m1

and

F1/m1=a

Answer:

a) the values of the angle α is 45.5°

b) the required magnitude of the vertical force, F is 41 lb

Explanation:

Applying the free equilibrium equation along x-direction

from the diagram

we say

∑Fₓ = 0

Pcosα - 425cos30° = 0

525cosα - 368.06 = 0

cosα = 368.06/525

cosα = 0.701

α = cos⁻¹ (0.701)

α = 45.5°

Also Applying the force equation of motion along y-direction

∑Fₓ = ma

Psinα + F + 425sin30° - 600 = (600/32.2)(1.5)

525sin45.5° + F + 212.5 - 600 = 27.95

374.46 + F + 212.5 - 600 = 27.95

F - 13.04 = 27.95

F = 27.95 + 13.04

F = 40.99 ≈ 41 lb

Answer:

Explanation: Thermals are created by the irregular heating of Earth's surface from solar radiation, and are an example of convection, specifically atmospheric convection.

At this point, air is converging on low pressure and rising air forms clouds.

Answer:

Given that

I = 1340 W/m²

µo = 4πx 10^-7 Tm/A

sc = 3 x 10^8 m/s

So to find the peak values of B we use

I = (c Bm²) / (2 µo)

1340 = (3 x 10^8 x Bm²) / (2 x 4πx 10^-7)

1340 = (3 x 10^8 x Bm²) / (25.12 x 10^-7)

(3 x 10^8 x Bm²) = 1340 x (25.12 x 10^-7)

(3 x 10^8 x Bm²) = 3.366 x 10^-3

Bm² = 3.366 x 10^-3 / 3 x 10^8

Bm² = 1.122 x 10^-11

Bm = 3.4 x 10^-6 T

Also to find the peak values of E we

use Em = c x Bm

Em = (3 x 10^8) (3.4 x 10^-6)

Em = 1.005 N/C

Answer:

0.2396

Explanation:

Given that

Mass of the hollow sphere, m = 15 kg

Inner radius, r = 12 cm = 0.12 m

Outer radius, R = 18 cm = 0.18 m

Volume of a sphere is expressed as

V = 4/3.π.R³

Density ρ = mass / volume, therefore

Mass = ρ * v

Mass of the hollow sphere is given as

Mass of the outer sphere - mass of the inner sphere

M = ρV(o) - ρV(i)

V(o) = 4/3 * 3.142 * 0.18³

V(o) = 0.0244

V(i) = 4/3 * 3.142 * 0.12³

V(i) = 0.00724

15 = ρ (0.0244 - 0.00724)

15 = ρ (0.01716)

ρ = 15 / 0.01716

ρ = 874 kg/m³

moment of inertia about its centroidal axis is

I = 2/5 ρVR²

I(h) = I(o) - I(i)

I(h) = (2/5 * 874 * 0.0244 * 0.18²) - (2/5 * 874 * 0.00724 * 0.12²)

I(h) = 0.276 - 0.0364

I(h) = 0.2396

Given :

Number of operations move through a pocket calculator during a full day's operation , [tex]n=1.34 \times 10^{20}[/tex] .

To Find :

How many coulombs of charge moved through it .

Solution :

We know , charge in  one electron is :

[tex]e^-=-1.6\times 10^{-19}\ coulombs[/tex]

So , charge on n electron is :

[tex]C=e^-\times n\\C=-1.6\times 10^{-19}\times 1.34\times 10^{20} \ C\\C=-21.44\ C[/tex]

Therefore , -21.44 coulombs of charge is moved through it .

Hence , this is the required solution .

Answer:

We know that the second equation of motion is

S= ut + 1/2a²

And S is displacement and u is initial velocity

So in the case of Haley lets take downwards as positive Y-axis

S = 2h and

initial velocity = v

a = g (acceleration due to gravity = 9.8)

Substituting

2h = vt + 1/2gt²

And for Joe we take ownwards as positive Y-axis

S = h and

initial velocity = 0 (since the ball is dropped from rest)

a = g

h = 0x t + 1/2gt2²

t2= √ 2h/g

Now since both balls reach ground at same time: t1=t2

So

putting value of t2 in Hayley's equation:

2h= v(√2h/g) + 1/2 g( √2h/g)²

So v= √gh/2

Answer:

(a) [tex]\vec F_{\parallel} = -\frac{102}{13}\,i-\frac{103}{13}\,j[/tex] , (b) [tex]\vec F_{\perp} = \frac{102}{13}\,i -\frac{68}{13}\,j[/tex], (c) [tex]W = -51[/tex]

Explanation:

The statement is incomplete:

The force on an object is [tex]\vec F = -17\,j[/tex]. For the vector [tex]\vec v = 2\,i +3\,j[/tex]. Find: (a) The component of [tex]\vec F[/tex] parallel to [tex]\vec v[/tex], (b) The component of [tex]\vec F[/tex] perpendicular to [tex]\vec v[/tex], and (c) The work [tex]W[/tex], done by force [tex]\vec F[/tex] through displacement [tex]\vec v[/tex].

(a) The component of [tex]\vec F[/tex] parallel to [tex]\vec v[/tex] is determined by the following expression:

[tex]\vec F_{\parallel} = (\vec F \bullet \hat {v} )\cdot \hat{v}[/tex]

Where [tex]\hat{v}[/tex] is the unit vector of [tex]\vec v[/tex], which is determined by the following expression:

[tex]\hat{v} = \frac{\vec v}{\|\vec v \|}[/tex]

Where [tex]\|\vec v\|[/tex] is the norm of [tex]\vec v[/tex], whose value can be found by Pythagorean Theorem.

Then, if [tex]\vec F = -17\,j[/tex] and [tex]\vec v = 2\,i +3\,j[/tex], then:

[tex]\|\vec v\| =\sqrt{2^{2}+3^{3}}[/tex]

[tex]\|\vec v\|=\sqrt{13}[/tex]

[tex]\hat{v} = \frac{1}{\sqrt{13}} \cdot(2\,i + 3\,j)[/tex]

[tex]\hat{v} = \frac{2}{\sqrt{13}}\,i+ \frac{3}{\sqrt{13}}\,j[/tex]

[tex]\vec F \bullet \hat{v} = (0)\cdot \left(\frac{2}{\sqrt{13}} \right)+(-17)\cdot \left(\frac{3}{\sqrt{13}} \right)[/tex]

[tex]\vec F \bullet \hat{v} = -\frac{51}{\sqrt{13}}[/tex]

[tex]\vec F_{\parallel} = \left(-\frac{51}{\sqrt{13}} \right)\cdot \left(\frac{2}{\sqrt{13}}\,i+\frac{3}{\sqrt{13}}\,j \right)[/tex]

[tex]\vec F_{\parallel} = -\frac{102}{13}\,i-\frac{153}{13}\,j[/tex]

(b) Parallel and perpendicular components are orthogonal to each other and the perpendicular component can be found by using the following vectorial subtraction:

[tex]\vec F_{\perp} = \vec F - \vec F_{\parallel}[/tex]

Given that [tex]\vec F = -17\,j[/tex] and [tex]\vec F_{\parallel} = -\frac{102}{13}\,i-\frac{153}{13}\,j[/tex], the component of [tex]\vec F[/tex] perpendicular to [tex]\vec v[/tex] is:

[tex]\vec F_{\perp} = -17\,j -\left(-\frac{102}{13}\,i-\frac{153}{13}\,j \right)[/tex]

[tex]\vec F_{\perp} = \frac{102}{13}\,i + \left(\frac{153}{13}-17 \right)\,j[/tex]

[tex]\vec F_{\perp} = \frac{102}{13}\,i -\frac{68}{13}\,j[/tex]

(c) The work done by  [tex]\vec F[/tex] through displacement [tex]\vec v[/tex] is:

[tex]W = \vec F \bullet \vec v[/tex]

[tex]W = (0)\cdot (2)+(-17)\cdot (3)[/tex]

[tex]W = -51[/tex]