glycerin flows upward at a centerline velocity of 2.5 m/s in a vertical 60-mm-diameter pipe at 20 °c. calculate the head loss and pressure drop in a 12-meter length of pipe.

Answers

Answer 1

The head loss in a 12-meter length of pipe is 0.055 m and the pressure drop is 659 P

To calculate the head loss and pressure drop in a 12-meter length of pipe, we can use the Darcy-Weisbach equation:

ΔP = [tex]\( f \cdot \frac{L}{D} \cdot \frac{\rho}{2} \cdot V^2 \)[/tex]

Where:
ΔP = pressure drop
f = friction factor
L = length of pipe
D = diameter of pipe
ρ = density of fluid
V = centerline velocity

First, we need to find the Reynolds number (Re) to determine the friction factor:

Re = [tex]\frac{\rho \cdot V \cdot D}{\mu}[/tex]

Where:
μ = viscosity of fluid

Assuming the viscosity of glycerin at 20 °C is 0.001 Pa.s, we get:

Re = [tex]\frac{{1261 \, \text{kg/m}^3 \cdot 2.5 \, \text{m/s} \cdot 0.06 \, \text{m}}}{{0.001 \, \text{Pa.s}}}[/tex]
Re = 9,015,000

Since the Reynolds number is greater than 4000, the flow is turbulent and we can use the Colebrook equation to find the friction factor:

[tex]\[\frac{1}{\sqrt{f}} = -2.0 \times \log_{10}\left(\frac{\frac{\varepsilon}{D}}{3.7} + \frac{2.51}{{Re} \times \sqrt{f}}\right)\][/tex]

Where:
ε = roughness height of pipe (assumed to be 0.0015 mm for a smooth pipe)

Using an iterative method, we can solve for f ≈ 0.021.

Now we can calculate the head loss and pressure drop:

ΔP =[tex]\(0.021 \times \left(\frac{12 \, \text{m}}{0.06 \, \text{m}}\right) \times \left(\frac{1261 \, \text{kg/m}^3}{2}\right) \times (2.5 \, \text{m/s})^2\)[/tex]
ΔP = 659 Pa

The head loss is the pressure drop divided by the density of the fluid and acceleration due to gravity:

hL = [tex]\frac{\Delta P}{{\rho \cdot g}}[/tex]
hL = [tex]\frac{{659 \, \text{Pa}}}{{1261 \, \text{kg/m}^3 \cdot 9.81 \, \text{m/s}^2}}[/tex]
hL = 0.055 m

Therefore, the head loss in a 12-meter length of pipe is 0.055 m and the pressure drop is 659 Pa.

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Related Questions

There are several important uses of runtime stacks in programs (select all that apply):
A stack makes a convenient temporary save area for registers when they are used for more than one purpose. After they are modified, they can be restored to their original values.
The stack provides temporary storage for local variables inside subroutines.
When calling a subroutine, you pass input values called arguments by pushing them on the stack.
When the CALL instruction executes, the CPU saves the current subroutine's return address
on the stack.

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Your answer: Several important uses of runtime stacks in programs include: A) A stack makes a convenient temporary save area for registers when they are used for more than one purpose. After they are modified, they can be restored to their original values. B) The stack provides temporary storage for local variables inside subroutines. C) When calling a subroutine, you pass input values called arguments by pushing them on the stack. D) When the CALL instruction executes, the CPU saves the current subroutine's return address on the stack.

Explanation:

A) A stack makes a convenient temporary save area for registers when they are used for more than one purpose. After they are modified, they can be restored to their original values.

(i) When a program is executing, it often needs to use registers to hold data or intermediate results.

(ii) However, the same register may need to be used for different purposes in different parts of the program, which means its original value would be lost.

(iii) To avoid this problem, the program can save the original value of the register on the stack before modifying it, and then restore the original value later by popping it off the stack.

(iv) This allows the register to be used for multiple purposes without losing its original value.

B) The stack provides temporary storage for local variables inside subroutines.

(i) When a subroutine is called, it needs to store its own local variables somewhere.

(ii) One option is to use global variables, but this can lead to naming conflicts and make the code harder to understand.

(iii) Instead, local variables can be stored on the stack. When the subroutine is called, it reserves space on the stack for its local variables.

(iv) When the subroutine returns, the local variables are removed from the stack and the stack pointer is reset to its previous value.

C) When calling a subroutine, you pass input values called arguments by pushing them on the stack.

(I) When a subroutine is called, it may need to receive some input values, or arguments, from the caller.

(ii) One way to pass these arguments is by pushing them onto the stack before the CALL instruction.

(iii) The callee can then access these arguments by popping them off the stack in the reverse order.

D) When the CALL instruction executes, the CPU saves the current subroutine's return address on the stack.

(i) When a subroutine is called, the CPU saves the address of the instruction immediately following the CALL instruction on the stack.

(ii) This return address is needed so that the subroutine can return control to the caller after it has finished executing.

(iii) When the subroutine is finished, it retrieves the return address from the stack and jumps to that location to resume execution of the caller.

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A small motor, weighing 100 lb, is found to have a natural frequency of 100 rad/s. It is proposed that an undamped vibration absorber weighing 10 lb be used to suppress the vibrations when the motor operates at 80 rad/s. Determine the necessary stiffness of the absorber

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Therefore, the necessary stiffness of the absorber is 120,000 lb/in. This stiffness will ensure that the absorber is able to effectively suppress the vibrations of the motor when it operates at 80 rad/s.

To determine the necessary stiffness of the absorber, we can use the equation:
k = (mωn2 - m2ω2) / y
where k is the stiffness of the absorber, m is the mass of the absorber, ωn is the natural frequency of the motor, ω is the operating frequency of the motor, and y is the displacement of the absorber.
Plugging in the given values, we get:
k = ((100 lb)(100 rad/s)2 - (10 lb)(80 rad/s)2) / (10 lb)
k = 120,000 lb/in
Therefore, the necessary stiffness of the absorber is 120,000 lb/in. This stiffness will ensure that the absorber is able to effectively suppress the vibrations of the motor when it operates at 80 rad/s.

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In prototype design, this type of compromise is characterized by providing few functions that contain great depth. a) Vertical b) Horizontal c) Sinecure d) Compliant e)

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The compromise characterized by providing few functions that contain great depth in prototype design is vertical.

Vertical compromise in prototype design means that a product has a limited range of functions, but each function is developed in-depth to meet the highest standards. This approach allows for a more focused and thorough design process, resulting in a higher quality product.

When designing a prototype, it's important to consider the balance between functionality and depth. While a horizontal approach may provide more functions, a vertical approach may lead to a higher quality product. Ultimately, the decision between the two approaches will depend on the specific needs and goals of the project.

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 An 11-m beam is subjected to a load, and the shear force follows the equation V(x) = 5 + 0.25x² where V is the shear force and x is length in distance along the beam. We know that V = dM/dx, and M is the bending moment. Integration yields the relationship M = M, + V dx If M, is zero and x = 11, calculate M using (a) analytical integration, (b) multiple-application trapezoidal rule, and (c) multiple-application Simpson's rules. For (b) and (c) use 1-m increments.

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(a) Analytical integration yields M = (5/3)x + (0.25/12)x^4 + C, where C is the constant of integration.

(b) Using the trapezoidal rule with 1-m increments, M = 191.5 kN·m.

(c) Using Simpson's rule with 1-m increments, M = 188.583 kN·m.

To solve for M, we integrate V(x) to get M(x) = ∫V(x)dx = (5/3)x^3 + (0.25/12)x^5 + C, where C is the constant of integration. Since M, = 0 and x = 11, we can solve for C to get C = -(5/3)(11^3) - (0.25/12)(11^5). Substituting these values into the M(x) equation, we get M = (5/3)(11^4)/4 + (0.25/12)(11^6)/6 + (5/3)(11^3) + (0.25/12)(11^5). This yields the analytical solution M = 186.458 kN·m.

For the trapezoidal rule, we approximate the area under the curve of V(x) using trapezoids. We divide the beam into 11 segments of length 1 m and calculate the area of each trapezoid. We then sum the areas to get the approximate value of M. Using this method, we get M ≈ 191.5 kN·m.

For Simpson's rule, we approximate the area under the curve of V(x) using parabolic arcs. We again divide the beam into 11 segments of length 1 m, and for each segment, we use three points (the two endpoints and the midpoint) to fit a parabola. We then calculate the area under each parabola and sum them to get the approximate value of M. Using this method, we get M ≈ 188.583 kN·m.

Overall, the analytical solution gives the most accurate value for M, but the trapezoidal and Simpson's rules provide useful approximations that can be used when an analytical solution is not feasible.

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Problem #5 (10pts) Design the source follower in the following figure for a drain current of 1mA and a voltage gain of 0.8. Assume μnCox=100μA/V2, VTH=0.4V, λ=0, VDD=1.8V, and RG=50kΩ. Find RG ,Rs ,and (W/L).

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The source follower in the figure with the given specifications. Our goal is to find RG, Rs, and (W/L) for a drain current of 1mA and a voltage gain of 0.8.



Step 1: Calculate the transconductance (gm) We are given the voltage gain (A_v) as 0.8, and we know that A_v = gm * Rs. We need to find gm to determine Rs later. Step 2: Calculate the overdrive voltage (V_ov)
Since we know the drain current (I_D) is 1mA and μnCox = 100μA/V^2, we can calculate V_ov using the formula:
I_D = 0.5 * μnCox * (W/L) * V_ov^2. Step 3: Calculate the gate-source voltage (V_gs)
Now that we have V_ov, we can calculate V_gs using the given threshold voltage (V_TH) of 0.4V:
V_gs = V_ov + V_TH

Step 4: Calculate RG We are given RG as 50kΩ, so we don't need to calculate it. Step 5: Calculate Rs Since we now have gm and A_v, we can find Rs using the equation: A_v = gm * Rs Step 6: Calculate (W/L) Now that we have V_ov, we can find (W/L) using the previously mentioned formula for I_D. Rearrange the formula to solve for (W/L):
(W/L) = 2 * I_D / (μnCox * V_ov^2)
By following these steps, you will find the values for RG, Rs, and (W/L) for the source follower circuit with the given specifications.

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what machine language does c have access to

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C has access to machine language instructions that are specific to the computer architecture it is being used on.

Machine language is the lowest level of programming language, consisting of binary code that is directly executed by a computer's central processing unit (CPU). C, as a high-level programming language, provides a layer of abstraction between the programmer and the machine language. However, C can still access machine language instructions through the use of inline assembly or by directly calling system-specific libraries that provide access to hardware components.

In summary, C has access to machine language instructions that are specific to the computer architecture it is being used on, but this access is usually reserved for advanced programming tasks where direct hardware manipulation is necessary.

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In the circuit shown in Fig. P8.49, a generator is connected to a load via a transmission line. Given that Rs = 10ohms, Z(line)= (4+j7)ohms, and Z(load)= (40+j25)ohms:a) Determine the power factor of the load, and the power factor of the voltage source.b) Specify the capacitance of a shunt capacitor C that would raise the power factor of the source to unity when connected between terminals (a,b). The source frequency is 60Hz.

Answers

a) The power factor of the load can be found by calculating the cosine of the angle between the real power and the apparent power. In this case, the load impedance is Z(load) = 40+j25 ohms. Therefore, the real power is given by P = |V^2 / Z(load)| * cos(theta), where V is the voltage across the load and theta is the angle between the voltage and the current. Similarly, the apparent power is given by S = |V^2 / Z(load)|. Using these equations, we can calculate the power factor of the load to be cos(theta) = P / S = 0.8. To find the power factor of the voltage source, we can use the same equations with the impedance of the transmission line and the load combined.

b) To raise the power factor of the source to unity, we need to add a shunt capacitor C between terminals (a,b) that will cancel out the inductive reactance of the load. The inductive reactance of the load is given by XL = Im(Z(load)) = 25 ohms. Therefore, the capacitance required can be calculated using the formula C = 1 / (XL * 2 * pi * f), where f is the frequency of the source. Plugging in the given values, we get C = 8.8 microfarads. Therefore, a shunt capacitor with a capacitance of 8.8 microfarads should be added between terminals (a,b) to raise the power factor of the source to unity.

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in order correct up two bit errors, and detect three bit errors without correcting them, with no attempt to deal with four or more, what is the minimum hamming distance required between codes?

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We need to choose a code with a minimum Hamming distance of 7 to ensure error correction and detection capabilities as required.

The minimum Hamming distance required between codes to correct up to two bit errors and detect three bit errors without correcting them, with no attempt to deal with four or more, is seven.

This means that any two valid codewords must have a distance of at least seven between them. If the distance is less than seven, then it is possible for two errors to occur and the code to be corrected incorrectly or for three errors to occur and go undetected.

For example, if we have a 7-bit code, the minimum Hamming distance required would be 4 (as 4+1=5) to detect 2 bit errors, and 6 (as 6+1=7) to correct up to 2 bit errors and detect 3 bit errors.

If two codewords have a Hamming distance of less than 6, then we cannot correct up to 2 errors and detect up to 3 errors.

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Problem 2 Give an example set of denominations of coins so that a greedy change making algo- rithm will not use the minimum number of coins. Give an instance, show the output of the greedy algorithm on this instance, and show better output

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Thus, the greedy algorithm results in using 4 coins, while a more optimal solution only requires 2 coins.

A greedy change making algorithm is one that always selects the largest coin denomination that is less than or equal to the amount of change due, until the amount of change due is zero. However, in some cases, this algorithm may not always result in the minimum number of coins being used.

Here's an example of a coin denomination set and an instance where a greedy change-making algorithm does not result in the minimum number of coins:

Denomination set: {1, 4, 5}
Instance: 8

Greedy algorithm output:
1. Choose the largest coin (5), remaining amount: 8 - 5 = 3
2. Choose the largest coin (1), remaining amount: 3 - 1 = 2
3. Choose the largest coin (1), remaining amount: 2 - 1 = 1
4. Choose the largest coin (1), remaining amount: 1 - 1 = 0
Result: 5, 1, 1, 1 (4 coins)

Better output:
1. Choose the second-largest coin (4), remaining amount: 8 - 4 = 4
2. Choose the second-largest coin (4), remaining amount: 4 - 4 = 0
Result: 4, 4 (2 coins)

In this case, the greedy algorithm results in using 4 coins, while a more optimal solution only requires 2 coins.

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Say we want to write some information to a file using with open('stuff.txt', 'w') as outfile: for thing in things: outfile.write(thing + '\n') What type can each thing item be? Int or float only Any iterable type String, int, float, bool String only

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When writing information to a file using the `with open('stuff.txt', 'w') as outfile:` statement in Python, we can use a loop to write multiple items to the file. However, there may be some uncertainty about what type of items can be written to the file.

In the provided code, the `thing` variable represents the items that will be written to the file. According to the code, each `thing` item can be either an int or float only. This means that any number that is an integer or a floating-point value can be written to the file. Alternatively, we can write any iterable type of data, including strings, integers, floats, and booleans. An iterable type of data is a collection of elements that can be iterated over in a loop. Therefore, we can write a list, tuple, or dictionary to the file by iterating over the elements and writing each element to the file. Lastly, if we want to write only strings to the file, we can modify the code to accept only strings. We can remove the `+ '\n'` from the code and ensure that each `thing` item is a string.

In conclusion, when using the `with open('stuff.txt', 'w') as outfile:` statement to write to a file, we can write items that are either integers or floats, any iterable type of data, or just strings. The type of item that can be written to the file depends on the specific requirements of the task.

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an ac voltage of peak value 89.6 v and frequency 49.5 hz is applied to a 23 µf capacitor. what is the rms current?

Answers

To calculate the RMS current in the given circuit, we can use the following formula:

Irms = Vp / (sqrt(2) * Z)

where Vp is the peak voltage, Z is the impedance, and sqrt(2) is a constant that accounts for the RMS-to-peak conversion.

The impedance of a capacitor can be calculated as:

Z = 1 / (2 * pi * f * C)

where f is the frequency and C is the capacitance.

Substituting the given values, we get:

Z = 1 / (2 * pi * 49.5 * 23E-6) = 145.8 ohms

Now, we can calculate the rms current as:

Irms = 89.6 / (sqrt(2) * 145.8) = 0.349 A

Therefore, the RMS current in the given circuit is approximately 0.349 A.

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The polyvinyl chloride bar is subjected to an axial force of P = 850 lb . Epvc = 800(103) psi, νpvc = 0.20. If it has the original dimensions shown determine the change in the angle after the load is applied. Express your answer using three significant figures.

Answers

Based on the given information, we can use the equation for an axial strain to determine the change in angle:

ε = ΔL/L = P/(A*E)

where ΔL is the change in length, L is the original length, P is the applied force, A is the cross-sectional area, and E is the modulus of elasticity.

First, we can find the cross-sectional area of the PVC bar:

A = (π/4)*(d^2) = (π/4)*(0.5 in)^2 = 0.1963 in^2

Next, we can find the change in length:

ΔL = ε*L = (P/A)*L/E

ΔL = (850 lb)/(0.1963 in^2)*(12 in)/(800*10^3 psi) = 0.001309 in

Finally, we can use trigonometry to find the change in angle:

tan(θ) = ΔL/L = 0.001309 in/12 in

θ = arctan(0.001309 in/12 in) = 0.0065 radians

Therefore, the change in angle after the load is applied is 0.0065 radians (or 0.37 degrees) to three significant figures.


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If the difference in the level of mercury within the manometer is 80 mm, determine the volumetric flow of the water. Take pHg 13 550 kg/m 3. 100 mm 40 mm 80 mm

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Specifically, the pressure difference across the manometer and the specific gravity of water are not provided. These are essential in solving the problem.

What is the volumetric flow of water in a manometer given the difference in mercury levels is 80 mm and pHg is 13,550 kg/m3?

Assuming the manometer is used to measure the pressure difference between two points in a pipeline, the volumetric flow rate of the water can be determined using the following steps:

Calculate the pressure difference between the two points based on the difference in the levels of mercury in the manometer. In this case, the pressure difference is:

ΔP = ρgh

where ρ is the density of mercury (13,550 kg/m³), g is the acceleration due to gravity (9.81 m/s²), and h is the height difference of the mercury levels (80 mm converted to 0.08 m):

ΔP = (13,550 kg/m³)(9.81 m/s²)(0.08 m) = 10,639.44 Pa

Calculate the volumetric flow rate using the Bernoulli equation:

Q = A1v1 = A2v2

where Q is the volumetric flow rate, A1 and A2 are the cross-sectional areas of the pipe at points 1 and 2, respectively, and v1 and v2 are the fluid velocities at points 1 and 2, respectively.

Assuming the pipe is horizontal and the fluid is incompressible, the Bernoulli equation simplifies to:

Q = (π/4)(D²)(v)

where D is the diameter of the pipe and v is the fluid velocity.

Rearrange the equation to solve for the volumetric flow rate:

Q = (π/4)(D²)(v) = (π/4)(D²)(ΔP/ρl)

where l is the length of the pipe between points 1 and 2.

Assuming a pipe diameter of 40 mm (0.04 m) and a length of 100 mm (0.1 m), the volumetric flow rate is:

Q = (π/4)(0.04²)(10,639.44/13,550)(0.1) = 0.0042 m³/s

Therefore, the volumetric flow rate of the water is 0.0042 cubic meters per second.

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explain why a public method should be declared to be final if it is called by a constructor

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Public method should be declared as final if it is called by a constructor in order to prevent unexpected behavior during initialization and to communicate the importance of the method to other developers.

When a constructor is called, it is responsible for initializing the instance variables of the class. In some cases, a public method may need to be called by the constructor in order to help with the initialization process. However, if this public method is not declared as final, it may be overridden by a subclass, which could lead to unexpected behavior during initialization.
By declaring the public method as final, the subclass is prevented from overriding the method and altering its behavior. This ensures that the method will always perform as intended when called by the constructor.
Additionally, declaring the public method as final also communicates to other developers that the method is a crucial part of the initialization process and should not be modified or overridden without careful consideration.
In summary, a public method should be declared as final if it is called by a constructor in order to prevent unexpected behavior during initialization and to communicate the importance of the method to other developers.

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Suppose a table T(A,B,C) has the following tuples: (1,1,3),(1,2,3),(2,1,4),(2,3,5),(2,4,1),(3,2,4), and (3,3,6). Consider the following view definition: Create View V as Select A+B as D,C From T

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Given the table T(A,B,C) with the specified tuples, you want to create a view V with a column D that is the sum of A and B, and another column containing the values of C.

Here's a step-by-step explanation:
1. Analyze the table T(A,B,C) with tuples: (1,1,3), (1,2,3), (2,1,4), (2,3,5), (2,4,1), (3,2,4), and (3,3,6).
2. Consider the view definition: Create View V as Select A+B as D, C From T. This means you want to create a new view V, where the first column (D) is the sum of columns A and B from table T, and the second column contains the values of column C from table T.
3. Calculate the values for column D in view V by adding A and B for each tuple in table T:
  - (1+1) = 2
  - (1+2) = 3
  - (2+1) = 3
  - (2+3) = 5
  - (2+4) = 6
  - (3+2) = 5
  - (3+3) = 6
4. Create view V with the calculated values for column D and the corresponding values for column C from table T:
  View V(D, C) has the following tuples:
  (2,3), (3,3), (3,4), (5,5), (6,1), (5,4), and (6,6).
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Given the following pole and zero information, sketch ROC in the s-domain and find x(t): a) X(s) has two poles at s=-1+; and s = 1+; b) X(s) has one zero at s = -3 and two poles at s = 0 and s = -2;

Answers

Given the poles at s = -1 and s = 1, the Region of Convergence (ROC) in the s-domain will be the area where the system is stable, i.e., the region between the two poles: Re(-1) < Re(s) < Re(1). To find x(t), we need to apply the inverse Laplace transform to X(s), but since we don't have the complete X(s) expression, it is not possible to find x(t) in this case.

For part b) of your question:
Given X(s) has one zero at s = -3 and two poles at s = 0 and s = -2. The ROC for this case will be in the region Re(-2) < Re(s) < Re(0), since the system is stable when the region lies between the poles. However, similar to part a), we cannot determine x(t) without the complete X(s) expression.

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How does a BASE system differ from a traditional distributed database system?

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A BASE system is a non-relational database system that focuses on availability, scalability, and eventual consistency, while a traditional distributed database system is a relational database system that focuses on consistency, isolation, durability, and availability (ACID).

In a BASE system, data may not always be consistent across all nodes in the system, but the system prioritizes availability and can handle high volumes of data and traffic. The system is designed to continue functioning even if some nodes fail. In contrast, a traditional distributed database system ensures that data is consistent across all nodes at all times, even if there is a high volume of traffic or nodes fail.

This makes it more suitable for applications that require strong consistency and reliability. Overall, the main difference between a BASE system and a traditional distributed database system lies in their priorities: availability and scalability in a BASE system, versus consistency and reliability in a traditional distributed database system.

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design a turing machine that computes the function f(x) = x-2 if x>2 and 0 if x<=2. assume x is given in unary.

Answers

Thus, the design of the Turing machine that computes the function f(x) = x-2 if x>2 and 0 if x<=2 is done.

Here's a Turing machine that computes the function f(x) = x-2 if x>2 and 0 if x<=2, where x is given in unary:

1. Start in state q0 and scan the input tape from left to right.
2. If the input symbol is 1, move to state q1 and replace the 1 with a blank symbol. This indicates that x is greater than 0.
3. If the input symbol is blank, move to state q5 and halt. This indicates that x is equal to 0.
4. If the input symbol is 0, move to state q2 and replace the 0 with a blank symbol. This indicates that x is less than or equal to 2.
5. If the input symbol is 1, move to state q3 and replace the 1 with a blank symbol. This indicates that x is greater than 2.
6. Move to state q4 and replace each remaining 1 with a 0. This subtracts 2 from x.
7. Move back to the beginning of the tape and start again from state q0. Repeat steps 2-6 until the input is 0 or there are no more 1's on the tape.
8. If the input is 0, move to state q5 and halt. The output is 0.
9. If there are no more 1's on the tape, move to state q6 and halt. The output is x-2.

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explain why systems equipped with a txv or axv require a receiver.

Answers

Systems equipped with a TXV (Thermostatic Expansion Valve) or AXV (Automatic Expansion Valve) require a receiver to maintain optimal system performance and efficiency.

Here's a step-by-step explanation of why a receiver is necessary:
1. TXV/AXV Function: Both TXV and AXV are types of expansion devices that regulate refrigerant flow into the evaporator. They maintain the correct superheat, ensuring efficient cooling and preventing issues like evaporator flooding.
2. Refrigerant Flow Variability: The refrigerant flow rate through a TXV or AXV can vary due to changes in system load, temperature, and pressure conditions. This can lead to an imbalance in refrigerant distribution in the system.
3. Receiver Purpose: The receiver's primary function is to store excess refrigerant when it's not needed in the system. This ensures a consistent supply of refrigerant is available for the expansion device to operate properly, even under varying conditions.
4. System Stability: By having a receiver in place, it helps maintain a stable refrigerant flow rate and system pressure, thus optimizing the overall performance of the cooling system.
5. Preventing Refrigerant Shortages: A receiver also prevents refrigerant shortages in the system, which can lead to a decrease in cooling efficiency or even compressor damage due to insufficient refrigerant flow.
In summary, a receiver is essential in systems with a TXV or AXV to ensure proper refrigerant flow and maintain optimal system performance and efficiency under varying conditions.

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A square footing is going to be constructed in a uniform sand soil with SPT N=40 blows/foot. Local building code requires that the bottom of the footing be 36" below the ground surface for frost protection. The groundwater is located 6 feet below the ground surface. The structural engineer indicates that the masonry structure can likely only tolerate 0.75" of allowable settlement, but it might be able to tolerate up to 1.0". The structural engineer would like you to develop bearing capacity charts for both (i) 0.75" maximum allowable settlement and (ii) 1.0" maximum allowable settlement. Assume a factor of safety of 2.5.

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The bearing capacity charts need to be developed for a square footing in uniform sand soil, considering maximum allowable settlements of 0.75" and 1.0", with a factor of safety of 2.5.

How bearing capacity charts be created for a square footing in sand soil with 0.75" and 1.0" maximum allowable settlements, using a factor of safety of 2.5?

To develop bearing capacity charts for the square footing, we need to consider the soil's SPT N value of 40 blows/foot. The bottom of the footing should be placed 36" below the ground surface for frost protection, and the groundwater level is 6 feet below the ground surface. The structural engineer suggests maximum allowable settlements of 0.75" and 1.0", with a factor of safety of 2.5.

The charts will provide the ultimate bearing capacity values for different footing widths and depths, while taking into account the allowable settlements and safety factor. These charts will help determine the suitable dimensions for the square footing that meet the structural requirements.

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An urban freeway contains three general traffic lanes plus one lane for the exclusive use of buses. The transit district presently runs forty (40) buses in the peak hour. The auto demand function (Va, vph/lane) uses the ratio of auto to bus travel time as a performance variable) is Va 2400-1000tatb l The corresponding performance functions for auto (a) and bus (b) are a4.00.04 Va tb 8.0+0.05 Vb where: Va and Vb are auto and bus volumes, respectively (VPH per lane), ta and tb are auto and bus travel times, respectively (minutes) Assuming a total overall demand of 2400 person trips per hour and an auto occupancy of 1.0 person per car, what are the present equilibrium conditions for both modes? Express in terms of both vehicles and person trips.

Answers

the present equilibrium conditions for both modes are: Auto volume (Va) = 1460.8 VPH per lane, Person trips = 1460.8, person trips per hour, Bus volume (Vb) = 490 VPH per lane, Person trips = 14,700 person trips per hour.

Based on the given information, the urban freeway contains three general traffic lanes and one lane exclusively for buses. During peak hour, 40 buses are currently being run by the transit district.

To determine the present equilibrium conditions for both modes, we need to find the values of auto and bus volumes that satisfy the demand of 2400 person trips per hour.

First, let's find the equilibrium conditions for the auto mode:

The auto demand function is given as Va = 2400 - 1000tatb. Using this function and the performance function for auto (a) given as a = 4.00 + 0.04Va tb, we can express the demand for auto in terms of ta and tb:

a = 4.00 + 0.04(2400 - 1000tatb) tb
a = 4.00 + 96 - 40tatb tb
a = 100 - 40tatb tb

To find the equilibrium condition, we set a = Va and solve for ta and tb:

100 - 40tatb tb = 2400 - 1000tatb
940 = 960tatb
tatb = 0.9792 minutes

Substituting this value of tatb in the demand function for auto, we get:

Va = 2400 - 1000(0.9792)tb
Va = 1460.8 VPH per lane

So, the equilibrium conditions for the auto mode are:

Auto volume (Va) = 1460.8 VPH per lane
Person trips = Auto volume (Va) * Auto occupancy (1) = 1460.8 * 1 = 1460.8 person trips per hour

Next, let's find the equilibrium conditions for the bus mode:

The performance function for bus (b) is given as b = 8.0 + 0.05Vb. Using this function and the given bus volume of 40 buses, we can express the demand for bus in terms of tb:

b = 8.0 + 0.05(40) tb
b = 10 + 2tb

To find the equilibrium condition, we set b = Vb and solve for tb:

10 + 2tb = Vb
40tb = 2400
tb = 60 minutes

Substituting this value of tb in the demand function for bus, we get:

Vb = 10 + 2(40) (60)
Vb = 490 VPH per lane

So, the equilibrium conditions for the bus mode are:

Bus volume (Vb) = 490 VPH per lane
Person trips = Bus volume (Vb) * Bus occupancy (30) = 490 * 30 = 14,700 person trips per hour

Therefore, the present equilibrium conditions for both modes are:

Auto volume (Va) = 1460.8 VPH per lane
Person trips = 1460.8 person trips per hour

Bus volume (Vb) = 490 VPH per lane
Person trips = 14,700 person trips per hour

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write a valid java statement to get the high scores from the variable, hs, an instance of highscores and store the result in a variable, records, an instance of arraylist.

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By storing the result in an ArrayList, you can easily manipulate and analyze the high scores data in your Java program.

To retrieve the high scores from the variable hs, which is an instance of HighScores class, and store the result in an instance of ArrayList class named records, you can use the following Java statement:

ArrayList records = hs.getHighScores();

This statement calls the getHighScores() method of the HighScores class and assigns the returned ArrayList to the records variable. The records variable is of type ArrayList, which means it can store a list of Integer values. The getHighScores() method returns an ArrayList object that contains the high scores stored in the hs instance. By storing the result in an ArrayList, you can easily manipulate and analyze the high scores data in your Java program.

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This trade has brought much destruction to my people. We have suffered from losing much of our population, but we have also suffered from the introduction of ____ which have changed our society drastically, making our kingdoms and empires more violent and less secure and politically stable.

Answers

Based on the given statement, it is likely that the missing word is "colonization."

It is likely that the statement refers to the impact of colonization on indigenous societies. Colonization often involved the forced assimilation of indigenous peoples into European culture, including the introduction of new technologies and systems of governance. These changes often led to the displacement of indigenous populations and the disruption of their traditional ways of life. Additionally, the introduction of new weapons and warfare tactics led to increased violence and political instability. The effects of colonization are still felt today, as many indigenous populations continue to struggle with the lasting impacts of these historical injustices.

This trade has brought much destruction to my people. We have suffered from losing much of our population, but we have also suffered from the introduction of colonization which have changed our society drastically, making our kingdoms and empires more violent and less secure and politically stable.

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convert the following state machines from moore to mealy or mealy to moore. (a) convert the following mealy machine to a moore machine.

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When converting a mealy machine to a moore machine, we need to ensure that the output is solely dependent on the state.

This means that we need to include the input in the state in order to achieve this. To do this, we can create a new state for every possible combination of input and current state.
Let's consider the following mealy machine:
State  | Input | Output | Next State
-------|-------|--------|----------
S0     | 0     | 0      | S1
S0     | 1     | 0      | S0
S1     | 0     | 1      | S0
S1     | 1     | 0      | S1
To convert this to a moore machine, we need to make the output dependent solely on the state. To do this, we can create two new states: S00 and S01, where S0 represents the current state and 0 represents the input, and S1 and S11 where S1 represents the current state and 1 represents the input. This gives us the following table:
State  | Output | Next State
-------|--------|----------
S00    | 0      | S01
S01    | 0      | S00
S10    | 1      | S00
S11    | 0      | S11
We can now see that the output is solely dependent on the state, which makes this a moore machine.

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photo watt 6mb photovoltaic cells (see fig. 9.10) are to be arranged in a module to provide an output of 35 v with a power of 610 w. recommend an arrangement that meets these specifications.

Answers

Since the power output is much higher than the required 610 W, this arrangement of 72 cells in total will be sufficient to provide the required voltage and power output of the module.

To recommend an arrangement of photovoltaic cells that meet the specified requirements, we need to determine the number of cells and the way they should be arranged.

First, we need to calculate the current required to achieve 610 W of power with an output voltage of 35 V. Using the formula P = IV, we get:

610 W = 35 V x I

I = 17.43 A

Next, we need to calculate the number of cells required to produce 35 V. Each cell has a voltage of approximately 0.5 V, so we need:

35 V / 0.5 V per cell = 70 cells

To achieve the required current of 17.43 A, we can arrange the cells in series and parallel. Assuming the cells have a current rating of 6A each, we can arrange them in 6 parallel strings of 12 cells in series. This will provide a total current of:

6 strings x 12 cells per string x 6 A per cell = 432 A

Finally, we need to check if the voltage and power output of the module meet the specifications. The voltage output will be:

35 V per string x 6 strings = 210 V

And the power output will be:

210 V x 432 A = 90720 W or 90.72 kW

Since the power output is much higher than the required 610 W, this arrangement of 72 cells in total will be sufficient to provide the required voltage and power output of the module.

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given four 4 mh inductors, draw the circuits and determine the maximum and minimum values of inductance that can be obtained by interconnecting the inductors in series/parallel combinations

Answers

Answer:

To determine the maximum and minimum values of inductance that can be obtained by interconnecting four 4 mH inductors in series and parallel combinations, we can visualize the circuits and calculate the resulting inductance.

1. Series Combination:

When inductors are connected in series, the total inductance is the sum of the individual inductance values.

Circuit diagram for series combination:

L1 ── L2 ── L3 ── L4

Maximum inductance in series:

L_max = L1 + L2 + L3 + L4

      = 4 mH + 4 mH + 4 mH + 4 mH

      = 16 mH

Minimum inductance in series:

L_min = 4 mH

2. Parallel Combination:

When inductors are connected in parallel, the reciprocal of the total inductance is equal to the sum of the reciprocals of the individual inductance values.

Circuit diagram for parallel combination:

     ┌─ L1 ─┐

     │       │

─ L2 ─┼─ L3 ─┼─

     │       │

     └─ L4 ─┘

To calculate the maximum and minimum inductance values in parallel, we need to consider the reciprocal values (conductances).

Maximum inductance in parallel:

1/L_max = 1/L1 + 1/L2 + 1/L3 + 1/L4

       = 1/4 mH + 1/4 mH + 1/4 mH + 1/4 mH

       = 1/0.004 H + 1/0.004 H + 1/0.004 H + 1/0.004 H

       = 250 + 250 + 250 + 250

       = 1000

L_max = 1/(1/L_max)

     = 1/1000

     = 0.001 H = 1 mH

Minimum inductance in parallel:

1/L_min = 1/L1 + 1/L2 + 1/L3 + 1/L4

       = 1/4 mH + 1/4 mH + 1/4 mH + 1/4 mH

       = 1/0.004 H + 1/0.004 H + 1/0.004 H + 1/0.004 H

       = 250 + 250 + 250 + 250

       = 1000

L_min = 1/(1/L_min)

     = 1/1000

     = 0.001 H = 1 mH

Therefore, the maximum and minimum values of inductance that can be obtained by interconnecting four 4 mH inductors in series or parallel combinations are both 16 mH and 1 mH, respectively.

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a fatigue test was conducted on 2014-T6 aluminum alloy in which the mean stress was 250 MPa, and the stress amplitude was -150 MPa.
1. Compute the maximum ( σmax ) and minimum ( σmin ) stress levels. (3 Marks)
2. Compute the stress ratio (R). (1 Mark)
3. Compute the magnitude of the stress range ( σr ). (1 Mark)
4. Compute the critical stress level ( σc ) at which fracture will occur for a critical internal crack length ( 2a ) of 7.25 mm, if the material has a value of fracture toughness (Kc) in MPa.m^0.5 and assume Y = 1.9. (4 Marks)
5. Compute the fatigue life (N) of the material using the following figure. (1 Mark)

Answers

The maximum stress level (σmax) is -25 MPa, the minimum stress level (σmin) is 425 MPa, the stress ratio (R) is -17, the magnitude of the stress range (σr) is 400 MPa, the critical stress level (σc) is 87.6 MPa, and the estimated fatigue life (N) is approximately 10^4 cycles.

1. The maximum stress level (σmax) can be calculated as:

σmax = mean stress + 0.5 * stress amplitude

σmax = 250 MPa + 0.5 * (-150 MPa) = -25 MPa

The minimum stress level (σmin) can be calculated as:

σmin = mean stress - 0.5 * stress amplitude

σmin = 250 MPa - 0.5 * (-150 MPa) = 425 MPa

2. The stress ratio (R) is defined as the ratio of the minimum stress level to the maximum stress level. Thus, we have:

R = σmin/σmax

R = 425 MPa / (-25 MPa) = -17

3. The magnitude of the stress range (σr) is defined as the difference between the maximum and minimum stress levels. Thus, we have:

σr = σmax - σmin

σr = -25 MPa - 425 MPa = 400 MPa

4. The critical stress level (σc) can be calculated using the following formula:

σc = Y * Kc / sqrt(pi * a)

where Y is a geometric constant (assumed to be 1.9), Kc is the fracture toughness (assumed to be known), and a is the critical internal crack length (2a = 7.25 mm).

Given the values of Kc = 33 MPa.m^0.5 and a = 3.625 mm, we can calculate σc as follows:

σc = 1.9 * 33 MPa.m^0.5 / sqrt(pi * 3.625 mm)

σc = 87.6 MPa

5. Using the given S-N curve, we can estimate the fatigue life (N) of the material by locating the point corresponding to the stress ratio (R) of -17 and the stress range (σr) of 400 MPa, and then reading the corresponding value of N from the curve. From the curve, we can estimate N to be approximately 10^4 cycles.

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The fatigue life to be around 10^6 cycles. However, the exact value of N will depend on the specific point on the S-Ncurve, which is not given.

To compute the maximum and minimum stress levels, we use the following formulas:

σmax = mean stress + stress amplitude / 2

σmin = mean stress - stress amplitude / 2

Plugging in the given values, we get:

σmax = 250 + (-150) / 2 = 75 MPa

σmin = 250 - (-150) / 2 = 425 MPa

Therefore, the maximum stress level is 75 MPa and the minimum stress level is 425 MPa.

The stress ratio (R) is defined as the ratio of the minimum stress to the maximum stress. Thus:R = σmin / σmax = 425 / 75 = 5.67

The magnitude of the stress range (σr) is simply the difference between the maximum and minimum stress levels:σr = σmax - σmin = 75 - 425 = -350 MPa

To compute the critical stress level (σc), we use the following formula:

σc = Y * Kc / (sqrt(pi) * a)

where Y is a dimensionless constant (assumed to be 1.9), Kc is the fracture toughness in MPa.m^0.5, and a is the critical internal crack length in meters. Since the crack length is given in millimeters, we need to convert it to meters:a = 7.25 / 1000 = 0.00725 m

Plugging in the given values, we get:

σc = 1.9 * Kc / (sqrt(pi) * 0.00725) = 2561.76 * Kc

Therefore, the critical stress level is 2561.76 times the fracture toughness.

To compute the fatigue life (N), we use the given figure which relates the stress ratio (R) and the number of cycles to failure (N) for a given stress range (σr). From part 3, we know that σr = -350 MPa. From part 2, we know that R = 5.67. Thus, we can estimate the fatigue life to be around 10^6 cycles. However, the exact value of N will depend on the specific point on the S-N curve, which is not given.

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draw a fsa that recognizes binary strings that contain two consecutive 0s anywhere in the string.

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To draw a finite state automaton (FSA) that recognizes binary strings containing two consecutive 0s anywhere in the string, we need to define the states, the transitions, and the accepting state(s).

Let's begin with the states. We need to keep track of whether we have seen a 0 or not, and whether we have seen two consecutive 0s or not. So we can define three states:

1. State 1: Start state, which is also the accepting state because we haven't seen any 0s yet.

2. State 2: We have seen a single 0, but not two consecutive 0s yet.

3. State 3: We have seen two consecutive 0s.

Next, let's define the transitions. We need to transition from one state to another based on the input. If we see a 1, we stay in the same state, because we haven't seen any 0s. If we see a 0, we transition to the next state. If we are in state 2 and we see another 0, we transition to state 3.

Finally, let's define the accepting state(s). We already defined state 1 as the accepting state, because we haven't seen any 0s yet. But we also need to include state 3 as an accepting state, because we have seen two consecutive 0s.

So here is the FSA that recognizes binary strings containing two consecutive 0s anywhere in the string:

```
    0       0
--> (1) ---> (2) ---> (3) <--
    |   1   |   0   |   1
    --------|-------|-------
            |   1
            V
           (1)*
```

The transitions are labeled with the input that triggers them. The asterisk on state 1 indicates that it is also an accepting state.

I hope that helps! Let me know if you have any questions.

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Derive the stiffness and load vector for a frame element. As shown below, the frame element has transverse, axial, and rotational d.o.f.; and the loading consists of a distributed transverse load

Answers

To derive the stiffness and load vector for a frame element, we need to consider the forces acting on each degree of freedom (d.o.f.). The frame element has three d.o.f.: transverse, axial, and rotational. We can use the principle of virtual work to derive the stiffness and load vector.

For the transverse d.o.f., the stiffness can be derived from the bending equation, and the load vector can be obtained from the distributed transverse load. For the axial d.o.f., the stiffness can be derived from the axial force equation, and the load vector can be obtained from the axial load. For the rotational d.o.f., the stiffness can be derived from the torsion equation, and the load vector can be obtained from the torque.
In conclusion, the stiffness and load vector for a frame element depend on the forces acting on each d.o.f. We can derive these values using the principle of virtual work and equations for bending, axial force, and torsion.

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A hydroelectric facility operates with an elevation difference of 50 m with flow rate of 500 m3/s. If the rotational speed of the turbine is to be 90 rpm, determine the most suitable type of turbine and
estimate the power output of the arrangement.

Answers

If a hydroelectric facility operates with an elevation difference of 50 m with flow rate of 500 m3/s. If the rotational speed of the turbine is to be 90 rpm, then the estimated power output of the arrangement is approximately 220.7 MW.

Based on the provided information, the most suitable type of turbine for a hydroelectric facility with an elevation difference of 50 m and a flow rate of 500 m³/s would be a Francis turbine. This is because Francis turbines are designed for medium head (elevation difference) and flow rate applications.

To estimate the power output of the arrangement, we can use the following formula:

Power Output (P) = η × ρ × g × h × Q

Where:
η = efficiency (assuming a typical value of 0.9 or 90% for a Francis turbine)
ρ = density of water (approximately 1000 kg/m³)
g = acceleration due to gravity (9.81 m/s²)
h = elevation difference (50 m)
Q = flow rate (500 m³/s)

P = 0.9 × 1000 kg/m³ × 9.81 m/s² × 50 m × 500 m³/s

P = 220,725,000 W or approximately 220.7 MW

Therefore, the estimated power output of the arrangement is approximately 220.7 MW.

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