Given that f(x)=x+4 and g (x)=3x/x+1 (1) determine the value of f(9)​

The average monthly increase in net worth for the 6-month period is $1832.16.

Given:

A business started the year with a net worth of $4,873. During the first six months of the year, the business recovered and increased its net worth to a value of $15,866.

Six months net worth = 15,866 - 4873

= 10,993

Average monthly increase in net worth =  six month net worth / 6

= 10,993/6

= $1832.16.

Therefore The average monthly increase in net worth for the 6-month period is $1832.16.

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The value of the exponent given as 24 - (5 + 3)^2 + 4 × 2^3 is -8.

An exponent is the number of times that a number is multiplied by itself. It should be noted that the power is an expression which shows the multiplication for the same number. For example, in 6⁴ , 4 is the exponent and 6⁴ is called 6 raise to the power of 4.

In this case, the value given will be expressed thus:

= 24 - (5 + 3)^2 + 4 × 2^3

= 24 - (8)² + 4 × 8

= 24 - 64 + 32

= -8

The value is -8.

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The largest multiple of 30 that is less than the number, 520, can be found to be 510.

To find the largest multiple that 30 has, which is also less than 520, first find the number of times that 30 can go into 520:

= 520 / 30

= 17.333

Then use this number to find the largest multiple below 520 by rounding 17.33 downwards to 17.

The multiple of 30 that is the largest and below 520 is then:

= 30 x Rounded down result of division of 520

= 30 x 17

= 510

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Answer:

The height of the flagpole is about 25.6 feet.

Step-by-step explanation:

The figure is omitted--please sketch it.

Put your calculator in degree mode.

Let h be the height of the flagpole.

[tex] \tan(52) = \frac{h}{20} [/tex]

[tex]h = 20 \tan(52) = 25.6[/tex]

The diameter of a semicircle is 4 yards. The perimeter for a semicircle having a diameter of 4 yards is 10.28 yards.

The perimeter of a shape is the distance of the path or boundary that surrounds the shape.

The formula for the perimeter of a semicircle is πr + 2r

π(pie)=3.14

r(radius)=2 yards (∴ radius=1/2diameter)

∴ the perimeter of a semicircle = πr + 2r

                                                    = 3.14×2+2×2

                                                    =10.28 yards.

∴ The perimeter of a semicircle with a diameter of 4 yards is 10.28 yards.

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Answer:

the answer for x when h(x) is 2.9

Answer in multiple forms depending on what needed

Answer:

c = 3

Step-by-step explanation:

48- (3c+4)=4(c+5)+3

48-3c-4=4(c+5)+3 Distributed the - sign

48 -3c -4= 4c+20 +3 Distributed the 4

44-3c =4c+23 Combined like terms

21-3c=4c Subtract 23 from both sides

21=7c Add 3c to both sides

3=c

Answer:

L = 6 feet ; W = 4 feet

Step-by-step explanation:

l = 2 + w

perimeter/2 = 8

l + w > 8

2 + w + w > 8

2 + 2w > 8

2w > 8-2

2w > 6

2/2 w > 6/2

w > 3

smallest integer > 3 = 4

W= 4

L = 4 + 2 = 6

Answer:  The correct answer is x = 50

Step-by-step explanation:

The sum of angles in a triangle = 180 degrees

This is a right-angled triangle, so one of the angles is 90 degrees + x +y

Therefore: 90 + y + x = 180

Substitute the variables:

90 + 40 + x = 180

130 + x =180

Subtract 130 from each side:

(-130) 130 + x =180 (-130)

x = 50

There are 855 cockroaches crawling on the front of the building

An equation is an expression showing the relationship between two or more numbers and variables.

The population density is given as:

Population density = total animals / area occupied

Given that, the population density of the cockroaches is 5 cockroaches per square meter.

The area of the building = area of triangle + area of square

Area of building = (1/2) * (24 - 9)(12) + (9 * 9) = 90 + 81 = 171 m²

Population density = total animals / area occupied

5 cockroaches per square meter = Total cockroaches / 171 m²

Total cockroaches = 855

There are 855 cockroaches

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By taking some simple quotients, we will see that the cost per student is:

$26.36

First, we know that the school spends $643.34 on passes for 38 people, then the cost of each pass is given by the quotient:

p = $643.34/38 = $16.93

Then there is also lunch for the 36 students, which costed $339.48, then the cost in lunch per student is.

l = $339.48/36 = $9.43

The total cost per student is:

$16.93 + $9.43 = $26.36

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Answer:

5^4

Step-by-step explanation:

5^3x5

5x5x5x5

5^4

Hopes this helps please mark brainliest

The simplified form of the expression, 5³.5 will be 625.

In mathematics, integer exponents are exponents that should be integers. It may be a positive or negative number. In this situation, the positive integer exponents determine the number of times the base number should be multiplied by itself.

It is given that the expression is, 5³.5

=5³.5

The base should remain constant and the exponents added when multiplying like bases. Keep the base constant when raising a base with power to another power, and multiply the exponents instead. Keep the base constant and deduct the exponents in the denominator and numerator when dividing like bases.

Apply the law of exponent as

xᵃ × xᵇ = xᵃ⁺ᵇ

=5³⁺¹

=5⁴

=5x5x5x5

=625

Thus, the simplified form of the expression, 5³.5 will be 625.

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The exact value of Cosθ is -1/√10 .

In the question ,

it is given that ,

the value of tanθ = 3/1 ,

that means the perpendicular = 3x

and the base of the triangle is = 1x,

So ,By Pythagoras Theorem

hypotnuse² = perpendicular² + base²

hypotnuse² = (3x)² + (1x)²

hypotnuse² = 9x² + 1x²

hypotnuse² = 10x²

hypotnuse = (√10)x

So , Cosθ = base / hypotnuse

Cosθ = 1x/(√10)x

Cosθ = 1/√10

Since , [tex]\theta[/tex] lies in the second quadrant ,

and in second quadrant Cos is negative ,

So , Cosθ = -1/√10

Therefore , The exact value of Cosθ is  -1/√10  .

The given question is incomplete , the complete question is

If Tanθ = 3 , θ lies in the second quadrant. Use a Pythagorean identity to find the exact value of Cosθ ?

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The root of the quadratic equation is 2x² + 7x + 6 is x = -2 and x = -3 / 2.

The roots of a quadratic equation are the values of the variable that satisfy the equation. They are also known as the "solutions" or "zeros" of the quadratic equation.

The equation to find the roots, is a quadratic equation.

Hence,

2x² + 7x + 6

2x² + 3x + 4x + 6

x(2x + 3) + 2(2x + 3)

Hence,

(x + 2)(2x + 3) = 0

Therefore,

x + 2 = 0    or 2x + 3 = 0

x = -2 or x = -3 / 2

The roots of the equation is x = -2 and x = -3 / 2

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Answer:

y=8 x=-19.5

Step-by-step explanation:

Start from the bottom equation and work your way upSolve the fourth equation for w-5w=-15-5w/(-5)=-15/(-5)w = 3 Then use that value of w to plug into the third equation. Notice we're going backwards or up the chain of equations. After w is replaced, solve for zz+w = 2z+3 = 2z+3-3 = 2-3z = -1 Now use z = -1 and w = 3 to plug into the second equation. Solve for y-2y-12z-4w = -16-2y-12(-1)-4(3) = -16-2y+12-12 = -16-2y = -16-2y/(-2) = -16/(-2)y = 8 

Use y = 8, z = -1, w = 3 to plug into the first equation. Solve for x:

2x+4y+z+3w=12x+4(8)+(-1)+3(3)=12x+32-1+9=12x+40=12x+40-40=1-402x=-392x/2=-39/2x = -39/2 The value of x as a fraction is x = -39/2The value of x in decimal form is x = -19.5 

Answer:

-5/4

Step-by-step explanation:

slope

[tex]\frac{y2-y1}{x2-x1}\\\\ \frac{2-(-3)}{-4-0}=\frac{5}{-4}\\ \\slope = \frac{-5}{4}[/tex]

The value after 11 years with annual compounding is $11,389.79

The value after 11 years with quarterly compounding is $11,552

The value after 11 years with monthly compounding is $11,589.68

The value after 11 years with continous compounding is $70,080.78.

When an amount is compounded annually, it increases in value once a year. When an amount is compounded quarterly, it increases in value four times a year. When an amount is compounded monthly, it increases in value twelve times a year. When an amount is compounded continuously, it increases continuously over the investment period.

The formula for calculating future value:

FV = P (1 + r)^nm

Where:

Value after 11 years with annual compounding: $6,000 x (1.06)^11 = $11,389.79

Value after 11 years with quarterly compounding: $6,000 x (1 + 0.06 /4)^(11 x 4) = $11,552

Value after 11 years with monthly compounding: $6,000 x (1 + 0.06 /12)^(11 x 12) = $11,589.68

The formula for calculating future value when there is continuous compounding is : A x e^r x N

Where:

Value after 11 years: 6,000 x (2.718^0.06) x 11 = $70,080.78

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Answer:

2/3

Step-by-step explanation:

The gradient is found by doing rise/run. If you go to a point on the line you can then rise 2 squares and run 3 to the right. This means that the gradient is 2/3. It is not negative as the line is going up.

Answer:

y=3x+25

Step-by-step explanation:

we need start by making slope intercept form

lets move the 12x after moving it we get

-4y=-12x+4 we need to remove the - 4 from the y so we need to divide the whole equation by - 4

we get y=3x-1

now we can create an equation to get the parallel line

y+2=3(x+9) now distribute

y+2=3x+27 and subtract the two

y=3x+25

Answer: Rise is 5 and run is 1 and now that is equal 5

Step-by-step explanation:

The coordinates of the point which divide the lines joining the pairs of points (5,8) and (-1,3) in the given ratio  2:3 is  (8,4).

Using the section formula, if a point (x,y) divides the line joining the points (x₁, y₁) and (x₂, y₂) in the ratio m:n, then

(x,y)=( (mx₂+nx₁)/m+n ,  (my₂+ny₁)/m+n )

Let the points be A(5,8) and B(-1, 3). Let a point P(x,y) divides AB in the ratio 2:3

Therefore, we have

P(x,y)=((2(-1) + 3x5)/(2+3) , (2(3) + 3x8)/(2+3))

P(x,y)=(2.6,6)

Hence,the coordinates of the point which divide the lines joining the pairs of points (5,8) and (-1,3) in the given ratio  2:3 is  (8,4).

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The value of ∠FED is 120° and ∠CBD is complementary to ∠FDE

Complementary angles are two angles that sum up to 90°

For example 60° and 30° are complementary.

Either angle is called the complement of the other angle.

∠FED, ∠FDE and ∠DFE are in a triangle.

so,

∠FED + ∠FDE  +  ∠DFE = 180°

16x - 8 + 2x + 9 + 35 = 180 ( sum of angles in a triangle)

18x +36 = 180

18x = 180 - 36

18x = 144

x = 144/18

x = 8

so ∠FED = 16x - 8

Substitute x = 8 into the equation above we have

16(8) - 8 = 128 - 8 = 120°

∠FDE = 2x + 9

∠FDE = 2(8) + 9 = 25°

∠BED = 6x + 12

∠BED = 6(8) + 12

∠BED = 48 + 12

∠BED = 60°

∠CBD = -2x + 81

∠CBD = -2(8) + 81

∠CBD = 65°

so since ∠CBD = 65° and 90 - 65 = 25°

∠CBD is complementary to ∠FDE

In conclusion, ∠FED is 120° and ∠CBD is complementary to ∠FDE

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Order of operation to simplify this expression as follows:

   [tex]((1\div4+7\div 8)\times 1)\div 2[/tex]

⇒ [tex]((0.25+7\div 8)\times 1)\div 2[/tex]

⇒ [tex]((0.25+0.875)\times 1)\div2[/tex]

⇒ [tex](1.125\times 1)\div2[/tex]

⇒ [tex]1.125\div 2[/tex]

⇒ [tex]0.5625[/tex]

What is order of operation?

The best way to solve an expression is from left to right if all the operations are the same (for instance, only addition, only subtraction, only multiplication, or only division). However, we must adhere to the order of operations for expressions including several operations.

The rule that dictates how to solve an expression involving numerous operations is known as the order of operations.

PEMDAS can help you remember that sequence. In PEMDAS, each letter denotes a mathematical operation.

Given Expression is ; [tex]((1\div4+7\div 8)\times 1)\div 2[/tex]

Firstly we calculate the highest priority between(+,-, x, and [tex]\div[/tex])

Here, division is the highest priority ,

[tex]((0.25+7\div 8)\times 1)\div 2[/tex]

[tex]((0.25+0.875)\times 1)\div2[/tex]

and then we solve parathesis,

[tex](1.125\times 1)\div2[/tex]

now we do multiply,

[tex]1.125\div 2[/tex]

and the final answer will be [tex]0.5625[/tex]

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The seal's new position relative to the surface of the ocean is 47 meters below.

It is important to note that that question has to do with elevation which is the change in position with regards to the sea or ocean level.

In this case, the harbour seal dives 35 metres below the ocean's surface and then it dives down an additional 12 metres

The new position will be;

= -35 - 12

= -47

This implies that it's 47 meters below the ocean surface.

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The observation of the graphing speed versus time is given below.

The rate at which the speed is changing is known as acceleration.

From the graph, the line segment OA and DE have linear acceleration which increases the velocity.

Similarly, from the graph, the line segment BC and EF have linear deacceleration which decreases the velocity.

From the graph, line segment AB has constant acceleration which increases the velocity.

And from the graph, the line segment CD has zero acceleration which makes the velocity to be constant.

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Answer:

557.143

Step-by-step explanation:

195 / 35% = 557.14

The equation that represents the number of purses Paula must sell to pay for the new equipment is 5.00x = 5000.

A function can be defined as the outputs for a given set of inputs.

The inputs of a function are known as the independent variable and the outputs of a function are known as the dependent variable.

Given, Paula makes purses and the materials cost $2.25 per purse.

She sells them for $5.00 each now she wants to invest $5000 in some new equipment and we are assuming the no. of purses to be x.

Here the equation 5.00x - 2.25x = 5000 represents Paula's profit.

The equation that represents the no. of purses she must sell to pay for the new equipment is 5.00x = 5000.

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Answer: 5.00x - 2.25x = 5000

Step-by-step explanation: