Given 23 g of potassium nitrate per 25 g of water, what temperature should create a saturated solution?

Answer:

matter is anything that occupies space

states of matter : solid,liquid, gas,plasma

Answer:

matter can be anything, tables chairs, literally anything. it has volume and takes up space.

Explanation:

Solids, liquids, gases, plasmas, and Bose-Einstein condensates (BEC)

Answer: It will take 425 hours to plate 19.5 kg of copper onto the cathode if the current passed through the cell is held constant at 38.5 A.

Explanation:

The half-reaction equation is as follows.

[tex]Cu^{2+} + 2e^{-} \rightarrow Cu[/tex]

According to the standard values, 1 mole of an electron carries 96500 C. Therefore, charge carried by 2 moles of electrons is [tex]2 \times 96500 C[/tex].

Also, atomic mass of Cu is 63.5 g. According to the equation 2 moles of electrons are depositing 63.5 g of Cu.

Hence, charge required to deposit 19.5 kg (1 kg = 1000 g) or 19500 g of Cu is calculated as follows.

[tex]19500 g Cu \times \frac{2 \times 96500 C}{63.5 g Cu}\\= 5.92 \times 10^{7} C[/tex]

Formula used to calculate time is as follows.

[tex]Q = I \times t[/tex]

where,

Q = charge

I = current

t = time

Substitute the values into above formula as follows.

[tex]5.92 \times 10^{7} C = 38.5 \times t\\t = \frac{5.92 \times 10^{7} C}{38.5}\\= 1.53 \times 10^{6} sec[/tex]

As 1 hour contains 3600 seconds. So, converting seconds into hours as follows.

[tex]1.53 \times 10^{6} sec = 1.53 \times 10^{6} sec \times \frac{1 hr}{3600 sec}\\= 425 hr[/tex]

Thus, we can conclude that it will take 425 hours to plate 19.5 kg of copper onto the cathode if the current passed through the cell is held constant at 38.5 A.

Answer:

1 mole contains 6.02⋅1023 particles

Explanation:

Explanation:

X×6.02⋅1023=3.75⋅1024→

X=3.75⋅10246.02⋅1023=0.623⋅101=6.23 moles

Answer:

D. So electrons can flow from one electrode to another

Explanation:

An electrochemical cell is any cell in which electricity is produced by reason of a chemical change.

An electrochemical cell consists of two electrodes, these two electrodes are connected using a wire.

Usually, electrons flow from one electrode to another via this wire thereby enabling the electrochemical processes of oxidation and reduction in the cell to proceed effectively.

Answer:

Music CDs and smartphones are digital.

Explanation:

Music CDs and smartphones are digital. Analogue takes up a lot of space and degrades with the [passage of time while on the other hand, digital takes less space and degrades in large piece of time. Dimmer light switches and cameras that use film is it analog not digital. The major difference between both signals is that the analog signals have continuous electronic signals, while digital signals have non-continuous electronic signals.

Answer:

Lower the temperature of the solution

Answer:

Empirical formula is CH

Explanation:

A hydrocarbon, CₐHₓ reacts with oxygen in the combustion reaction as follows:

CₐHₓ + O₂ → a CO₂ + x/2 H₂O

That means we can find the moles of C and H from the moles of CO2 and H2O. As empirical formula is defined as the simplest whole-number ratio of atoms in a molecule, we can determine it as follows:

Moles CO2 = Moles C -Molar mass: 44.01g/mol:

0.4225g * (1mol / 44.01g) = 0.0096 moles C

Moles H2O -Molar mass: 18.01g/mol:

0.0865g H2O * (1mol / 18.01g) = 0.0048moles H2O * (2mol H / 1mol H2O) =

0.0096 moles H

The ratio of atoms of C:H is:

0.0096moles C / 0.0096moles H = 1

That means empirical formula is CH

Answer:

55.0g water can be made

Explanation:

To solve this question, we must convert the molecules of H2 to moles using Avogadro's constant. With the moles, and the reaction:

H2 + 1/2O2 → H2O

We can find the moles of H2O = Moles H2 and its mass of using molar mass of water -H2O = 18.01g/mol-

Moles H2 = Moles H2O:

1.84x10²⁴ molecules * (1mol / 6.022x10²³ molecules) = 3.055 moles H2O

Mass:

3.055 moles H2O * (18.01g / mol) = 55.0g water can be made

Answer:

202 °C

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 90 °C

Initial volume (V₁) = 15.5 L

Final volume (V₂) = 20.3 L

Final temperature (T₂) =?

Next, we shall convert 90 °C to Kelvin temperature. This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T₁) = 90 °C

Initial temperature (T₁) = 90 °C + 273

Initial temperature (T₁) = 363 K

Next, we shall determine the final temperature.

Initial temperature (T₁) = 363 K

Initial volume (V₁) = 15.5 L

Final volume (V₂) = 20.3 L

Final temperature (T₂) =?

V₁ / T₁ = V₂ / T₂

15.5 / 363 = 20.3 / T₂

Cross multiply

15.5 × T₂ = 363 × 20.3

15.5 × T₂ = 7368.9

Divide both side by 15.5

T₂ = 7368.9 / 15.5

T₂ ≈ 475 K

Finally, we shall convert 475 K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T₂ = 475 – 273

T₂ = 202 °C

Thus, the new temperature of the gas is 202 °C

Answer:

0.01 M

Explanation:

As this problem deals with a dilution process, we can solve it by using the following formula:

Where subscript 1 stands for the initial concentration and volume, while 2 stands for the final conditions.

That means that in this case:

We input the given data:

Answer: The heat of combustion per mole for acetylene is 227.7 kJ/mol.

Explanation:

The combustion equation of acetylene is as follows.

[tex]C_{2}H_{2} + \frac{5}{2}O_{2} \rightarrow 2CO_{2} + H_{2}O[/tex]

Formula to calculate enthalpy of formation for a reaction is as follows.

[tex]\Delta H^{o}_{rxn} = \sum \Delta H_{products} - \sum \Delta H_{reactants}\\\Delta H^{o}_{rxn} = [2\Delta H^{o}_{f}(CO_{2}) + \Delta H^{o}_{f} (H_{2}O)] - [\Delta H^{o}_{f}(C_{2}H_{2}) + \frac{5}{2} \Delta H^{o}_{f} O_{2}]\\-1299.5 = 2(-393.5) + (-285.8) - \Delta H^{o}_{f} (C_{2}H_{2})\\\Delta H^{o}_{f} (C_{2}H_{2}) = 227.7 kJ/mol[/tex]

Thus, we can conclude that heat of combustion per mole for acetylene is 227.7 kJ/mol.

Answer:

not B

Explanation:

my friend got it wrong

Answer:

194g of distilled water.

Explanation:

Hello there!

In this case, according to the given information for this problem, it turns out possible for us to use the given mass of the solution and the percent by mass of NaF to firstly calculate the grams of this solute as shown below:

[tex]\%m=\frac{m_{solute}}{m_{solution}} *100\%\\\\m_{solute}=\frac{\%m*m_{solution}}{100\%} \\\\m_{solute}=\frac{3.0\%*200.0g}{100\%} \\\\m_{solute}=6g[/tex]

And finally, since the mass of solution is calculated by adding mass of solute and mass of solvent we obtain the mass of water (solvent) as follows:

[tex]m_w=200g-6g=194g[/tex]

Therefore, the answer is 194g of distilled water

Regards!

Answer: D.) non-spontaneous.

Explanation:

Answer: The pressure is 1137.5 mm Hg its pressure if its volume is increased to 150 [tex]cm^{3}[/tex] at 35 °C

Explanation:

Given: [tex]P_{1}[/tex] = 750 mm Hg,    [tex]V_{1} = 130 cm^{3}[/tex],     [tex]T_{1} = 20^{o}C[/tex]

[tex]P_{2}[/tex] = ?,          [tex]V_{2} = 150 cm^{3}[/tex],            [tex]T_{2} = 35^{o}C[/tex]

Formula used to calculate the new pressure is as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{750 mm Hg \times 130 cm^{3}}{20^{o}C} = \frac{P_{2} \times 150 cm^{3}}{35^{o}C}\\P_{2} = 1137.5 mm Hg[/tex]

Thus, we can conclude that the pressure is 1137.5 mm Hg its pressure if its volume is increased to 150 [tex]cm^{3}[/tex] at 35 °C.

Answer:

lol ok 1+1=2 2 x 2=4

have a good day :)

Explanation:

Answer:  oke

Explanation: have a goood day!

Answer:

https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l

Explanation:

https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l

Answer: I got -4542.9kg/mol

Explanation:

Using the enthalpy relation, the enthalpy of formation of propane gas in the given equation is 4542.9 kJ/mol

Using the enthalpy value of [tex] CO_{2} [/tex] and[tex] H_{2}0[/tex] given :

Enthalpy of formation = product - Reactant

2219.2 = -2323.70 - (propane + 0)

2219.2 = - 2323.70 - propane

Propane = - 2323.70 - 2219.2

[tex] C_{3}H_{8} = - 4542.9 [/tex]

Therefore, the entalphy of formation of propane gas is - 4542.9 kJ/mol.

Learn more :https://brainly.com/question/1261360

Answer:

D.......................

Answer: I think it could be Decomposition

Explanation: I think is composition because decomposition starts by being together and ends up as two

Answer:  A and C are the right answer.

Explanation:

Answer: Hello attached below is the complete question and using data from ALEKS data tab

answer:

PbCl₂ :  Yes , PH = 3

CaC0₃ : Yes, PH = 3

AgCn : Yes , PH = 3 .

Explanation:

For PbCl₂  

PbCl₂ solubility will change ( decrease )  with increase in PH, and the PH at which PbCl₂ will be most soluble is at PH = 3

For CaC0₃

Addition of -ions which increases the PH level will cause a decrease in the solubility of  CaC0₃ hence the PH at which it will be most soluble in an aqueous solution is PH = 3

For AgCn

Increase in the PH level there would be a decrease in the solubility of AgCn hence the PH at which AgCn is most soluble ( highest solubility ) = 3

The ability of a solute to be able to dissolve is called solubility. Yes, at pH 3, the solubility of lead chloride, calcium carbonate, and silver cyanide.

The ability of the solute to get dissolved in a solvent to form a saturated solution is called solubility.

For lead chloride, the solubility will decrease as the pH will increase and is most soluble at a pH of 3.

For calcium carbonate, the addition of ions increases the pH will result in a decreased solubility, and will be most soluble at pH 3.

For silver cyanide increased pH decreases the solubility and is most soluble at a pH of three.

Therefore, solubility decrease with an increase in pH due to the concentration factor.

Learn more about solubility here:

https://brainly.com/question/22985530

Answer:

the answer is c

Explanation:

i did the test

The enthalpy of the formation of water is -285.8 kJ/mol. The information that can be made by the statement is heat is released during the process. The correct option is C.

Enthalpy is the volume times the pressure times the internal energy of the system. It is an entity of thermodynamics. It is the measurement of the energy in a thermodynamic system. The enthalpy totals the internal energy plus pressure and volume.

The statement that is given here is given that enthalpy is -285.8 kJ/mol. The value is negative, so the energy is released here. When energy is gained the energy will be positive and when the energy is released it is negative.

Thus, the correct option is C, heat is released during the process regarding the given statement of enthalpy.

To learn more about enthalpy, refer to the link:

https://brainly.com/question/24136717

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Answer:

736 mmHg = 0.97 atm (Approx.)

736 mmHg = 736 Torr

Explanation:

Given barometer in the laboratory atmospheric pressure data:

Atmospheric pressure in mmHg = 736 mmHg

Find:

Change given data into Torr

Change given data in atm (atmospheric pressure)

Computation:

We know that;

1 atm = 760 mmHg

So,

736 mmHg = 736 / 760

736 mmHg = 0.97 atm (Approx.)

We know that;

760 mmHg = 760 Torr

So,

736 mmHg = 736 Torr

Answer:

the oxidation state of nitrogen is +5

Answer:

the answer is A.

Explanation:

Elemental fluorine, for example, is the strongest common oxidizing agent.