Give two everyday examples of the thermal energy of a substance being decreased

Answers

Answer 1

Answer:

An example of the thermal energy of a substance being decreased is with our food. With the thermal energy of food being decreased it is easier for foods to be eaten comfortably without any damage to the tongue or alimentary canal.

Another good example is in the handling of hot objects in the home. Thermal energy decrease in objects such as iron, pots etc helps to prevent serious burns and injuries.

Answer 2

Answer:

Water turning into ice

juice frozen to make popsicles

Explanation:

When something goes from liquid to a solid, that is a process called freezing. When a object loses thermal energy the particles move slower forming a solid.


Related Questions

The isotope of carbon used in archaeological dating is 14^6C . How many protons, neutrons, and electrons does an atom of 14^6C have?

Answers

Answer:

6

8

6

Explanation:

 Isotope given:

                       ¹⁴₆C

In specie written as this;  

   Superscript  = Mass number

   Subscript  = Atomic number

To find the protons, it is the same as the atomic number;

                Protons  = Atomic number  = 6

Neutrons have no charges;

 Neutrons  = Mass number - Atomic number  =

  Neutrons  = 14 - 6  = 8

The number of electrons is the same as the atomic number = 6

which part of earth absorbs the most sunlight?
A oceans
b soil
c atmosphere
d rivers and lakes

Answers

Answer:

atmosphere

Explanation:

The atmosphere absorbs the most in light because the atmosphere surrounds our planet

Answer:

c

Explanation:

To prepare 380 mL of 0.500 M NaCl (MW = 58.5 g/mol), how many grams of sodium chloride is required?

Answers

This answer did not come from me but here you go!
44 g NaCl
Explanation:
The problem provides you with the molarity and volume of the target solution, so your first step here will be to use this information to figure out how many moles of sodium chloride,
NaCl
, it must contain.
Once you know that, use the compound's molar mass to convert the number of moles to grams.
So, molarity is defined as the number of moles of solute per liter of solution. In your case, a
0.77 M
solution will contain
0.77
moles of sodium chloride, your solute, in
1.0 L
of solution.
Your target solution has a volume of
985
mL

1 L
10
3
mL
=
0.985 L
which means that it will contain
0.985
L solution

= 0.77 M

0.77 moles NaCl
1
L solution
=
0.75845 moles NaCl
Sodium chloride has a molar mass of
58.44 g mol

1
, which basically means that one mole of sodium chloride has a mass of
58.44 g
.
In your case,
0.75845
moles of sodium chloride will have a mass of
0.75845
moles NaCl

58.44 g
1
mole NaCl
=




¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
a
a
44 g
a
a

11.12 grams of sodium chloride is required to prepare 380 mL of 0.500 M NaCl (MW = 58.5 g/mol).

HOW TO CALCULATE MASS:

The mass of a substance can be calculated by multiplying the number of moles of the substance by its molar mass.

However, the number of moles of sodium chloride must first be calculated by multiplying the molarity by its volume.

Molarity = no. of moles ÷ volume

0.500M = n ÷ 0.380L

n = 0.5 × 0.380

n = 0.19mol

mass of NaCl = 58.5g/mol × 0.19mol

Mass of NaCl = 11.12g

Therefore, 11.12 grams of sodium chloride is required to prepare 380 mL of 0.500 M NaCl (MW = 58.5 g/mol).

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WHAT PROBLEMS DID PRESIDENT JEFFERSON HAVE WITH TRIPOLI AND HOW DID HE SOLVE THEM

Answers

Answer:

Although Thomas Jefferson came to power determined to limit the reach of the federal government, foreign affairs dominated his presidency and pushed him toward Federalist policies that greatly contrasted with his political philosophy. The first foreign episode involved Jefferson's war with the Barbary pirates. For the previous century or so, Western nations had paid bribes to the Barbary states, which would later become Morocco, Algeria, Tunis, and Tripolitania, to keep them from harassing American and merchant ships

Explanation:

A nurse practitioner orders Medrol to be given 1.4 mg/kg of body weight. Medrol is an anti-inflammatory administered as an intramuscular injection. If a child weighs 71.6 lb and the available stock of Medrol is 20. mg/mL, how many milliliters does the nurse administer to the child? Express your answer to two significant figures and include the appropriate units.​

Answers

The nurse give 2.3 ml Medrol to the child

Further explanation

Mass is one of the principal quantities, which is related to the matter in the object  

The main mass unit consists of 7 units

kg, hg, dag, g, dg, cg, mg

Conversion :

1 Lb=0,453592 kg

For 71.6 lb :

[tex]\tt 71.6\times 0.453592=32.48~kg[/tex]

Medrol to be given 1.4 mg/kg of body weight, so amount for the child :

[tex]\tt 32.48~kg\times 1.4~mg/kg=45.472~mg[/tex]

The available stock of Medrol is 20. mg/mL, so the volume to the child :

[tex]\tt \dfrac{45.472}{20}=2.2736\approx2.3~ml[/tex]

How many liters of fat would have to be removed to result in a 5.2 lb weight loss? The density of human fat is 0.94 g/mL?​

Answers

I don’t even know I’m just answering for pints

The body fat of humans can be measured by the density in grams per mL. The volume of the fat with a density of 0.94 g/mL and mass of 5.2 lb is 2.50 L.

What is volume?

The volume is the factor of the dimension that inversely affects the density of the substance. The volume is given by the division of the mass by the density. It can be given in mL or cubic centimeters.

Given,

Mass of body fat = 5.2 lb

Density of human fat = 0.94 g/mL

At first, mass is converted from lb to grams as:

1 lb = 453.592 grams

So, 5.2 lb = 2358.68 grams

Secondly, volume is calculated as:

Volume = Mass ÷ density

V = 2358.68 grams ÷ 0.94 g/mL

= 2509.23 mL

Thirdly, volume from ml is converted to L as:

1 mL = 0.001 L

2509.23 mL = 2.50 L

Therefore, 2.50 liters of body fat has to be removed from the body.

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With ionic compounds, the ion charge is the same as the ___ number.
A. methylation
B. anion
C. cation
D. oxidation

Answers

Answer:

D. Oxidation

Explanation:

The oxidation state of a pure element is always equal to zero and the oxidation state for a pure ion is equivalent to its ionic charge.

1. How many moles of water molecules are there in 39 grams of Chlorine?

2. How many molecules are there in 39 grams of Gold?​

Answers

Answer:

1. There is no moles of water in 39g of chlorine.

2. 1.19x10²³ molecules of Au.

Explanation:

First, we need to remember that molar mass of a compound represents the mass of 1 mole (6.022x10²³ molecules) of molecules.

Molar mass of Chlorine, Cl₂ is 70.9g/mol

Molar mass of gold, Au, is 197g/mol

1. Moles of 39g of Cl₂ are:

39g Cl₂ * (1mol / 70.9g) = 0.55 moles moles of chlorine

But there is no moles of water in 39g of chlorine.

2. First, moles of Au are:

39g Au * (1mol / 197g) = 0.198 moles Au.

Molecules are:

0.198 moles Au * (6.022x10²³ molecules / 1 mol) =

1.19x10²³ molecules of Au

1. Which of the following statements describe cations? Select all that apply.
Positively charged ions.
Negatively charged ions.
They have lost electrons.
They have gained electrons.

Answers

Hey :)

Cations are positively charged ions and they have lost electrons

Hope this helps!

Ions can be made by single element or covalently bonded group of elements. The covalently bonded group of elements is called polyatomic ions or polyatomic atoms. The correct option are option A,C.

What is Ions?

Any species that contain charge whether it is positive charge or negative charge is called ions. The example of polyatomic ions are sulfate, phosphate, nitrate etc.

Cation is the species that loose electron and attain positive charge while anion is a species which gain electron and attains negative charge so when anion and cation combine in fixed ration the the overall charge of the molecule is zero that is molecule is neutral, the charge over cation and anion is also called oxidation state.

Therefore the correct option are option A,C.

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(2 points) How many grams of K2SO4 are present in 25.0 mL of 7.00 % (m/v) solution?
Show your work. No work = no credit.

Answers

Mass of K₂SO₄ : 1.75 g

Further explanation

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

volume of solution = 25 ml

% (m/v)=7%

mass of K₂SO₄ :

[tex]\tt \%m/v=\dfrac{mass~of~solute}{volume~of~solution}\times 100\%\\\\7\%=\dfrac{mass~K_SO_4}{25}\times 100\%\\\\mass~K_2SO_4=7\times 25\div 100=1.75~g[/tex]

Which is an example of a beneficial mutation?

one that changes the color of a rabbit, allowing it to hide from predators.
one that results in lighter flower petal colors without changing the plant’s ability to reproduce
one that causes a person’s body to produce thick mucus that clogs the lungs
one that makes it easier for a corn plant to contract a disease

Answers

Answer:

A

Explanation:

Answer: a

Explanation: one that changes the color of a rabbit, allowing it to hide from predators.

Which EMW can humans see?

Answers

Answer:

visible light waves are the only electromagnetic waves we can see

16.025 has how many sig fig

Answers

Answer:

5

Explanation:

Significant figures:

The given measurement have four significant figures 1234.

All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.

Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.

Zero between the non zero digits are consider significant like 104 consist of three significant figures.

The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.

In given measurement:

16.025 there are 5 significant figures 1,6,0,2,5

How much ice could be melted at 0​°​C if 5200 joules of heat were added?

Answers

Answer:

0.02kg

Explanation:

Given parameters:

Amount of heat  = 5200J

Unknown:

Mass of ice that would be melted at 0°C = ?

Solution:

To solve this problem, use the expression below;

        H  = mL

H is the heat

m is the mass

L is the latent heat of fusion of ice  =  3.33 x 10⁵ J/kg.

 Insert the parameters and solve for m;

           5200  = m x 3.3 x 10⁵

             m  = [tex]\frac{5200}{3.33 x 10^{5} }[/tex]   = 0.02kg

     

Does it matter which of the two sp3sp3 hybrid orbitals are used to hold the two nonbonding electron pairs

Answers

Answer:

No. All four hybrids are equivalent and the angles between them are all the same, so we can use any of the two to hold the nonbonding pairs.

Explanation:

Orbital hybridization has been the combination of the atomic orbitals for the formation of a new hybrid. No, it does not matter which orbitals are used to hold the nonbonding electron pairs.

What are hybrid orbitals?

Hybrid orbitals are said to be formed by the mixing of the atomic orbitals with different energy and geometrical shape that allows the understanding of the atomic bonding and molecular geometry of the compounds.

It includes sp, sp², sp³, sp³d, and sp³d² which have various arrangements, including linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral. The hybrid orbitals are formed by the combination and overlapping of the s and p orbital.

It does not matter which sp³ orbital holds the two non-bonding electron pairs as all four hybrids have been known to have equivalent angles between them so it will not matter which hybrid has the non-bonded electrons in them.

Therefore, it will not matter which two sp³ hybrid holds the electron pairs that are not involved in bonding.

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Plzz helppppppppppppp

Answers

Answer:

i got you stop doing work  and forget about this one class you will still pass trust me i did it it 8th grade and still made it to 9th but today im not even in school so just do better in your other classes

Explanation:

What term describes the state of matter in which the attractive forces between particles are the greatest?


liquid

solid

gas

metal

Answers

It would probably be C

Answer:

I think it would be b

Explanation:

7. A gas takes up a volume of 15 liters, has a pressure of 3.3 atm, and a temperature of 299 K. If I raise the

temperature to 350 K and lower the pressure to 1050 mmHg, what is the new volume of the gas?


8. I have an unknown volume of gas held at a temperature of 115 K in a container with a pressure of 60.0

atm. If by increasing the temperature to 225 K and decreasing the pressure to 30.0 atm causes the volume

of the gas to be 25 liters, how many liters of gas did I start with?


9. A gas has a temperature of 14oC, and a volume of 5.5 liters. If the temperature is raised to 29oC and the

pressure is not changed, what is the new volume of the gas?


10. A gas that has a volume of 28 liters, a temperature of 65oC, and an unknown pressure has its volume

increased to 36 liters and its temperature decreased to 35oC. If I measure the pressure after the change to

be 2.0 atm, what was the original pressure of the gas?

Answers

Answer:

See explanation

Explanation:

7) P1 =3.3 atm

V1= 15 litres

T1 = 299 K

T2 = 350 K

P2 =  1050 mmHg/760 = 1.38 atm

V2?

From;

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 3.3 * 15 * 350/1.38 * 299

V2 = 17325/412.62

V2 = 42 litres

8) V1= unknown

T1= 115 K

P1 = 60 atm

T2= 225 K

P2 = 30 atm

V2 = 25 litres

From;

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V1 = P2V2T1/P1T2

V1 = 30 * 25 * 115/ 60 * 225

V1 = 86250/13500

V1 = 6.4 litres

9) T1 = 14 + 273 = 287 K

V1 = 5.5 liters

T2 = 29 + 273 = 302 K

V2 = the unknown

From Charles law;

V1/T1 = V2/T2

V1T2 = V2T1

V2 =V1T2/T1

V2 = 5.5 * 302/ 287

V2 = 5.8 litres

10) V1= 28 litres

T1= 65 + 273 = 338 K

P1 = the unknown

V2 = 36 liters

T2 = 35 + 273 = 308 K

P2 = 2 atm

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

P1 = P2V2T1/V1T2

P1 = 2 * 36 * 338/ 28 * 308

P1 = 24336/8624

P1 = 2.82 atm

Which metal absorbs the greatest amount of heat energy

Answers

Answer:

This question is incomplete but the completed question is in the attachment below. And the correct is b

Explanation:

Specific heat capacity can be defined as the amount of heat required to raise to raise 1 kg of a substance by 1 kelvin. Thus, this means that when the specific heat capacity of a substance is high, it takes more energy to increase the temperature of that substance. This also means that when different substances are subjected to the same amount of heat, the substance with the higher specific heat capacity will absorb less heat; for example at a beach, water has a very high specific heat capacity, thus when the sand in the beach is hot, the beach water is still relatively cold.

From the description above, it can be seen that the metal with the least specific capacity will absorb the greatest amount of heat, thus the metal is lead with the specific heat capacity of 0.129 J/(g. °C).

Xavier boiled 19 grams of water. If all of the water changed into a gas, what would be the mass of the steam?

Answers

Answer:

19g

Explanation:

The mass of the steam produced in this phase change process will also be 19g. This is in compliance with the law of conservation of mass.

It states that "mass is neither created nor destroyed in a the cause of reaction". The law suggests that mass is conserved. When steam is heated, it does not lose its mass. The mass of the steam is still the same as that of water.

Answer:

Xavier boiled 14 grams of water. If all of the water changed into a gas, what would be the mass of the steam?

A.

28 g

B.

0 g

C.

24 g

D.

14g

Explanation:

Which statement describes effusion?
It occurs when a gas passes through a tiny hole.
It occurs when a liquid passes through a tiny hole.
It occurs when gas molecules disperse throughout a container.
It occurs when a liquid disperses throughout a container.

Answers

Answer:

A. It occurs when a gas passes through a tiny hole.

Explanation:

Edge2020

Have a great day y'all :)

Urgent!! SOMEONE PLEASE HELP THANK YOU!

A gas occupies a volume of 555 mL at 0 °C and 8 0.0 kPa. What is the final celsius temperature when the volume of the gas is changed to 1880 mL and the pressure is changed to 39 kPa?

Answers

Answer:

The final temperature is 181.92°C

Explanation:

Given

Initial Temperature, T1 = 0°C

Initial Volume, V1 = 555mL

Initial Pressure, P1 = 80.0kPa

Final Volume, V2 = 1880ml

Final Pressure, P2 = 39kPa

Required

Determine the Final Temperature, T1

This question illustrates ideal gas law and will be solved using:

(P1 * V1)/T1 = (P2 * V2)/T2

But first, we need to convert temperature to degree Kelvin

T1 = 0°C = 273 + 0 = 273k

Next, we substitute values for P1, V1, T1, P2 and V2

THE EQUATION BEFOMES

(80 * 550)/273 = (1880 * 39)/T2

44000/273 = 73320/T2

Cross Multiply

44000 * T2 = 73320 * 273

44000T2 = 20016360

Solve for T2

T2 = 20016360/44000

T2 = 454.92K

Convert to degree Celsius

T2 = 454.92 - 273

T2 = 181.92°C

Hence, the final temperature is 181.92°C

The ideal gas law, also called the general gas equation, is the equation of the state of a hypothetical ideal gas.

The ideal gas law work under the constant:-

PressureTemperatureVolume

Hence the formula we gonna use is as follows:-

[tex]PV = nRT[/tex]

In the question, the pressure, temperature, and volume are given in two different system

Hence it is equal to

[tex]\frac{PV}{T} = \frac{PV}{T}[/tex]

Put the value given,

[tex]\frac{80*50}{273} = \frac{1880*39}{T}[/tex]

Solving the equation, the value T will be:-

[tex]T2 = \frac{20016360}{44000}[/tex]

=181.92C

The temperature given is 181.92C

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