GEOMETRY HIGH SCHOOL
In rectangle ABCD, diagonals and AC BD intersect at E. If AC= 4x + 8 and BE = x + 2, then the length of diagonal AC is ____ ?

GEOMETRY HIGH SCHOOLIn Rectangle ABCD, Diagonals And AC BD Intersect At E. If AC= 4x + 8 And BE = X +

Answers

Answer 1

Answer:

AC = 8

Step-by-step explanation:

AC = 4x + 8

BE = x + 2

x + 2 = x + 2

2x = 2 - 2

2x = 0

2x\2 = 0/2

x = 0

AC = 4x + 8

AC = 4(0) + 8

AC = 0 + 8

AC = 8

Answer 2

When the AC= 4x + 8 and BE = x + 2, so the length of diagonal AC is to be considered as the 8.

Calculation of the length of diagonal AC:

Since

AC = 4x + 8

BE = x + 2

Now

x + 2 = x + 2

2x = 2 - 2

2x = 0

x = 0

Now

AC = 4x + 8

AC = 4(0) + 8

AC = 0 + 8

AC = 8

hence, the length of diagonal AC is to be considered as the 8.

Learn more about length here; https://brainly.com/question/24417940


Related Questions

Please show how to do

Answers

Answer:

Slope = -3.5

Step-by-step explanation:

Find the slope using any two given pair of values. Let's use (6, -21) and (12, -42).

Slope = ∆y/∆x

Slope = (-42 -(-21)) / (12 - 6)

Slope = -21/6

Slope = -3.5

Which of the following expression is equivalent to 6^-7?

Answers

Answer:

B

Step-by-step explanation:

What is the area of the fire pit? (Use 3.14 for pi.)

Answers

Answer:

[tex]Area = 65.94[/tex]

Step-by-step explanation:

I will assume that the shaded region is the fire pit

Given

[tex]R = 5[/tex]

[tex]r = 2[/tex]

Required

Determine the area of the fire pit

First, calculate the area of the big circle.

[tex]A_2 = \pi R^2[/tex]

Area of the small is:

[tex]A_1 = \pi r^2[/tex]

The area of the pit is:

[tex]Area = A_2 - A_1[/tex]

[tex]Area = \pi R^2 - \pi r^2[/tex]

[tex]Area = \pi (R^2 - r^2)[/tex]

[tex]Area = 3.14 (5^2 - 2^2)[/tex]

[tex]Area = 3.14 (25 - 4)[/tex]

[tex]Area = 3.14 * 21[/tex]

[tex]Area = 65.94[/tex]

Find the length of the side and I’ll give brainlyist

Answers

Answer:

the answer is about 7.5

Step-by-step explanation:

hope this helps

tell me if you want me to explain it

In ΔDEF, the measure of ∠F=90°, the measure of ∠E=41°, and FD = 79 feet. Find the length of DE to the nearest tenth of a foot.

Answers

Answer:

120.4ft

Step-by-step explanation:

Find the diagram in the attachment.

The triangle shown is a right angled triangle with the side DE as the hypotenuse, EF is adjacent side while DF is the opposite side.

To get DE, we will use the SOH CAH TOA trigonometry identity

Using CAH which is defined as:

Cos(theta) = Adjacent/Hypotenuse

Cos 79°= 23/Hypotenuse

Hypotenuse = 23/cos79°

Hypotenuse = 23/0.191

Hypotenuse = 120.4feet

DE = 120.4feet (to nearest tenth)

Ms.Gallegos burns 236 calories

Answers

Dang so he fat step by step

1) Find all the critical numbers of the given function

f(x) = X 1 - 4
-
3

Answers

Answer:

(0,-4)

Step-by-step explanation:

Given

[tex]f(x) = x^\frac{1}{3} - 4[/tex]

Required

Determine the critical numbers

[tex]f(x) = x^\frac{1}{3} - 4[/tex]

Differentiate:

[tex]f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}[/tex]

[tex]f'(x) = \frac{1}{3}x^{-\frac{2}{3}}[/tex]

Equate to 0

[tex]f'(x) = \frac{1}{3}x^{-\frac{2}{3}} = 0[/tex]

[tex]\frac{1}{3}x^{-\frac{2}{3}} = 0[/tex]

Multiply through by 3

[tex]3 * \frac{1}{3}x^{-\frac{2}{3}} = 0*3[/tex]

[tex]x^{-\frac{2}{3}} = 0[/tex]

[tex]x = 0[/tex]

Substitute 0 for x in [tex]f(x) = x^\frac{1}{3} - 4[/tex]

[tex]f(0) = 0^\frac{1}{3} - 4[/tex]

[tex]f(0) = 0- 4[/tex]

[tex]f(0) = - 4[/tex]

Hence, the critical point is: (0,-4)

Verify that parallelogram ABCD with vertices A(-5, -1), B(-9, 6), C(-1, 5), and D(3, is a rhombus by showing that it is a parallelogram with perpendicular diagonals.​

Answers

multiplication of the gradients of the two diagonals is equals to -1 if they are perpendicular

I need help with this also

Answers

Answer:

Part A: $336.4

Part B:279.2645625

Step-by-step explanation:

$320+5.125% tax = 336.4

Part B:$279.2645625-5.125% tax = 279.2645625 bucks.

Thank you and good luck cheating

Find the distance between (-5,6)and (3,2).

Answers

Answer:

[tex]\displaystyle d = 4\sqrt{5}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Step-by-step explanation:

Step 1: Define

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formulas]:                                                     [tex]\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}[/tex][Distance] [√Radical] (Parenthesis) Add/Subtract:                                       [tex]\displaystyle d = \sqrt{(8)^2+(-4)^2}[/tex][Distance] [√Radical] Evaluate exponents:                                                    [tex]\displaystyle d = \sqrt{64+16}[/tex][Distance] [√Radical] Add:                                                                             [tex]\displaystyle d = \sqrt{80}[/tex][Distance] [√Radical] Simplify:                                                                         [tex]\displaystyle d = 4\sqrt{5}[/tex]

Is 13:15 and 30:26 a pair of equivalent ratios and why?

Answers

Given:

The two ratios are 13:15 and 30:26.

To find:

Whether the given ratios are equivalent or not.

Solution:

Two ratios are equivalent if the values of the ratio are equal after simplification.

[tex]13:15=\dfrac{13}{15}[/tex]

And,

[tex]30:26=\dfrac{30}{26}[/tex]

[tex]30:26=\dfrac{15}{13}[/tex]

[tex]30:26=15:13[/tex]

The first ratio is 13:15 and the value of second ratio after simplification is 15:13 both ratios are different, so,

[tex]\dfrac{13}{15}\neq \dfrac{30}{26}[/tex]

Therefore, the required answer is "No", the given ratios are not a pair of equivalent ratios.

Find the value of 0.7 x 0.08

Answers

Answer:

0.056

Step-by-step explanation:

I used my calculator, not much work to show :)

Answer:

The answer for 0.7 x 0.08 is 0.056.

Explantion:

I am smart like that.

I am built different.

Evaluate the expression: 16.2 x 2 + 1/2 x 8.5 x 12

Answers

83.4. Is the answer.

Answer:

83.4

Step-by-step explanation:

16.2 x 2

=

32.4 +

1/2 x 8.5 x 12  

=

51 + 32.4 = 83.4

Hope this helps!

The safety officers of a mining company take an SRS of 500500500 employees and finds that 15\, percent of the sampled employees wear contact lenses. The safety officers may take several more samples like this. Suppose it is really 12\, percent of the approximately 34{,}00034,00034, comma, 000 employees in the company who wear contact lenses. What are the mean and standard deviation of the sampling distribution of the proportion of employees who wear contact lenses

Answers

Answer:

The mean of the sampling distribution of the proportion of employees who wear contact lenses is 0.12 and the standard deviation is 0.0145.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

12% of the employees wear contact lenses.

This means that [tex]p = 0.12[/tex]

Samples of 500:

This means that [tex]n = 500[/tex]

What are the mean and standard deviation of the sampling distribution of the proportion of employees who wear contact lenses?

Mean:

[tex]\mu = p = 0.12[/tex]

Standard deviation:

[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.12*0.88}{500}} = 0.0145[/tex]

The mean of the sampling distribution of the proportion of employees who wear contact lenses is 0.12 and the standard deviation is 0.0145.

how do you describe the graph of |x| < 12 brainly

Answers

Answer:

Describe the two functions f(x) and g(x) , using the terms increasing, decreasing, maxima and minima. The graph of f(x) is periodic.

Answer:

Step-by-step explanation:

The sum of 3 and
twice the number n

Answers

3x2= 6 so it’s 6 which is equal to n

Water is leaking out of an inverted conical tank at a rate of 12,500 cm3/min at the same time that water is being pumped into the tank at a constant rate. The tank has height 6 m and the diameter at the top is 4 m. If the water level is rising at a rate of 20 cm/min when the height of the water is 2 m, find the rate (in cm3/min) at which water is being pumped into the tank. (Round your answer to the nearest integer.)

Answers

Answer:

12500cm x3= 37500

6x3=18

37500+18=37518

What is 23x56÷67-68?
Hurry plz
Me give brainliest
Thanks in advance

Answers

Answer:

-48.4328358209

Step-by-step explanation:

hope this helps!!!

Answer:

If you meant 68-67 then it would be 1288

But if you meant 67-68 it is -1288

(I really hope this isn't hard to understand).

What is the solution to the equation Sqrt 2x+6-Sqrt x+4 = 1?

Answers

Answer:

its 5

Step-by-step explanation:

Use the diagram below to find x and each missing angle.

Answers

Angle 1 clearly equals 37°. X=5

f(x) = 2x² + 4x - 5
g(x) = 6x3 – 2x2 + 3
Find (f – g)(x).
A. (f – g)(x) = –6x3 + 4x2 + 4x – 2
B. (f - g)(x) = 6x + 4x – 2
C. (f - g)(x) b= 6x? – 4x² - 4x + 8
D. (f - g)(x) = –6x2 + 4x2 + 4x – 8

Answers

The required difference in the expression (f – g)(x) is - 6x³+ 4x² + 4x - 8

Given the following functions

f(x) = 2x² + 4x - 5

g(x) = 6x³ – 2x² + 3

In order to get the required function (f-g)(x), we will have to take the difference of the function as shown:

(f – g)(x) = f(x) - g(x)

Substitute the given parameters into the expression

(f – g)(x) = 2x² + 4x - 5 - (6x³ – 2x² + 3)

Expand

(f – g)(x) = 2x² + 4x - 5 - 6x³ + 2x² - 3

Collect the like terms

(f – g)(x) = 2x²+2x²- 6x³ + 4x -5 -3

(f – g)(x) = - 6x³+ 4x² + 4x -5 -3

(f – g)(x) =  - 6x³+ 4x² + 4x - 8

Hence the required difference in the expression (f – g)(x) is - 6x³+ 4x² + 4x - 8

Learn more here: https://brainly.com/question/17431959

The probability of an event occurring is 0.61. Which of the options below show the probability of an event that is less likely to occur? Select all that apply.

Answers

No options !!!!!!!!!!!!!!!

Simplify the expression 1 + 4.25n + 3/2p -3 + (-2p) + 5/4n

Answers

Answer:

5.5n -2 -0.5p

Step-by-step explanation:

Make Everything to either decimals or fractions.

then simplify as shown

let f(x)=x^2 +2 and g(x)=1-3x. find each function value: (fg)(-1)

Answers

Answer:

12

Step-by-step explanation:

so basically

(x^2+2)*(1-3x)=-3x^3+x^2-6x+2

now plug in -1

-3(-1)^3+(-1)^2-6(-1)+2=12

hope this helped :)

The correct value of (fg)(-1) is "12". A further solution of the given query is provided below.

Given functions are:

[tex]f(x) = x^2+2[/tex]

[tex]g(x) = 1-3x[/tex]

Now,

⇒ [tex](fg) = (x^2+2)(1-3x)[/tex]

By applying multiplication, we get

           [tex]=x^2+2-3x^3-6x[/tex]

           [tex]=-3x^3+x^2-6x+2[/tex]...(equation 1)

By substituting the value "-1" in place of "x" in equation 1, we get

⇒ [tex](fg)(-1) = -3(-1)^3+(-1)^2-(6)(-1)+2[/tex]

                  [tex]=-3(-1)+1+6+2[/tex]

                  [tex]=3+1+6+2[/tex]

                  [tex]=12[/tex]

Thus the right answer is (fg)(-1) = 12.

Learn more:

https://brainly.com/question/10057660

Solve the equation: p2 - 4p + 4 = 0.​

Answers

Perfect square trinomial

[tex] \boxed{ a^2 \pm 2ab+b^2 = (a \pm b)^2 } [/tex]

Using the perfect square trinomial

[tex] p^2 - 4p + 4 = 0 [/tex]

[tex] p^2 - 2(2p) + (2)^2 = 0 [/tex]

[tex] (p-2)^2 = 0 [/tex]

[tex] (p-2) = 0 [/tex]

[tex] p = 2 [/tex]

[tex]\huge\text{Hey there!}[/tex]

[tex]\bold{p^2-4p+4=0}[/tex]

[tex]\text{FACTOR the LEFT side of your equation}\\\bold{(p-2)(p-2)=0}[/tex]

[tex]\text{SET each of your FACTORS TO EQUAL to 0}\\\bold{p-2=0\ or\ p-2=0}[/tex]

[tex]\text{SIMPLIFY the equations\ above and you will have your answer}[/tex]

[tex]\boxed{\boxed{\bold{Answer: \large\text{\bf{p = 2}}}}}\huge\checkmark[/tex]

[tex]\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

1 point
A 40-acre farm yields 600 bushels of wheat. At the same rate, how much
wheat would a 75-acre farm yield?

Answers

no. of bushels yield at 40 acre farm=600

no of bushels yield at 1 acre farm=15

no. of bushels yield at 75 acre farm=15×75

=1125

A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover, softcover, and plastic (for infants). At the beginning of January, the central computer showed the following books in stock.
Hard Soft Plastic
San Francisco 1,000 2,000 6,000
Los Angeles 1,000 6,000 2,000
Its sales in January were as follows: 600 hardcover books, 1,200 softcover books, and 1,900 plastic books sold in San Francisco, and 300 hardcover, 200 softcover, and 400 plastic books sold in Los Angeles. The bookstore chain actually maintained the same sales figures for the first 6 months of the year. Each month, the chain restocked the stores from its warehouse by shipping 500 hardcover, 1,400 softcover, and 1,400 plastic books to San Francisco and 600 hardcover, 600 softcover, and 600 plastic books to Los Angeles.
(a) Use matrix operations to determine the total sales over the 6 months, broken down by store and type of book.
Hard Soft Plastic
San Francisco
Los Angeles
(b) Use matrix operations to determine the inventory in each store at the end of June.
Hard Soft Plastic
San Francisco
Los Angeles

Answers

Answer:

a. Sales from January to June: Matrix B6

                             Hard    Soft       Plastic

San Francisco     3,600   7,200     11,400

Los Angeles        1,800    1,200      2,400

b) Ending Inventory: Matrix D:

                            Hard      Soft      Plastic

San Francisco      400     3,200     3,000

Los Angeles     2,800     8,400     3,200

Step-by-step explanation:

a) Data and Calculations:

Stock on January 1: Matrix A

                              Hard    Soft       Plastic

San Francisco       1,000   2,000    6,000

Los Angeles         1,000   6,000    2,000

Sales in January: Matrix B

                             Hard    Soft       Plastic

San Francisco       600     1,200     1,900

Los Angeles         300       200        400

Restocking: Matrix C

                           Hard    Soft       Plastic

San Francisco     500   1,400      1,400

Los Angeles       600      600       600

Total Sales over the first 6 months =

Matrix B * 6 = Matrix B6

Sales in January: Matrix B

                             Hard    Soft       Plastic

San Francisco       600     1,200     1,900

Los Angeles         300       200        400

* 6

=

Sales from January to June: Matrix B6

                             Hard    Soft       Plastic

San Francisco     3,600   7,200     11,400

Los Angeles        1,800    1,200      2,400

Matrix C6 = Matrix C * 6

=

Restocking: Matrix C6

                           Hard     Soft       Plastic

San Francisco    3,000   8,400      8,400

Los Angeles      3,600   3,600      3,600

Inventory at the end of June =

Matrix A + Matrix C6 - Matrix B6

= Matrix D

Stock on January 1: Matrix A

                              Hard    Soft       Plastic

San Francisco       1,000   2,000    6,000

Los Angeles         1,000   6,000    2,000

+

Restocking: Matrix C6

                           Hard     Soft       Plastic

San Francisco    3,000   8,400      8,400

Los Angeles      3,600   3,600      3,600

-

Sales from January to June: Matrix B6

                             Hard    Soft       Plastic

San Francisco     3,600   7,200     11,400

Los Angeles        1,800    1,200      2,400

Ending Inventory: Matrix D:

                             Hard      Soft       Plastic

San Francisco      400     3,200     3,000

Los Angeles     2,800     8,400     3,200

If there are 125 boxes of prescription bottle labels at the beginning of inventory cycle, and 25 3/4 remain ,how many boxes of labels remain?

Answers

Answer:

Rounded to the nearest integer, there are 32 boxes of labels left.

Step-by-step explanation:

Since there are 125 boxes of prescription bottle labels at the beginning of inventory cycle, and 25 3/4 remain, we can determine how many boxes of labels remain through the following mathematical operations:

3/4 = 0.75

100 = 125

25.75 = X

25.75 x 125/100 = X

3218.75 / 100 = X

32.1875 = X

Thus, rounded to the nearest integer, there are 32 boxes of labels left.

Pls answer ASAP it’s due tomorrow

Answers

Answer:

729

Step-by-step explanation:

Doughnuts are sold in bag and cartons. A bag holds 4 doughnuts and a carton holds 10 doughnuts. Tome buys b bags of doughnuts and c cartons of doughnuts. He buys a total of t doughnuts. Write down the formula for t in terms of b and c

Answers

Answer:

[tex]t = 4b + 10c[/tex]

Step-by-step explanation:

Given

1 bag = 4 doughnuts

1 carton = 10 doughnuts

Required

Determine the amount of doughnuts in b bags and c cartons

If 1 bag contains 4 doughnuts, then b bags contain 4b doughnuts

If 1 carton contains 10 doughnuts, then c cartons contain 10b doughnuts

So, the total (t) is calculated by adding up the amount of doughnuts in the cartons and the bags:

i.e.

[tex]t = 4b + 10c[/tex]

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