Game stop buys a game for $28 and marks the game up 64%. How much will you pay for the game?

Answers

Answer 1

Answer:

45.92

Step-by-step explanation:

50%=14

10%=2.8

4%=1.12

64%=19.92

19.92+28= 45.92


Related Questions

132 is what percent of 880

Answers

Answer:

Step-by-step explanation:

132 is what percent of 880? = 15.

Find the surface area of this triangular prism 18cm 30cm 24 cm 7cm

Answers

Answer:

936

Step-by-step explanation:

18*24=432

24*7=168

30*7=210

18*7=126

432+168+210+126

=936

Find the indicated probability. In one town, 71% of adults have health insurance. What is the probability that 4 adults selected at random from the town all have health insurance

Answers

Answer:

0.254

Step-by-step explanation:

Given that:

Percentage of those having health insurance = 71%

p = 71 / 100 = 0.71

Number of adults selected at random, n = 4

Probability that 4 selected have health insurance :

p^n = 0.71^4 = 0.25411681

= 0.254

Solve for t in terms of u, v, w, and x.

Answers

Answer:

there's no image lol

Step-by-step explanation

Certain pieces made by an automatic lathe are subject to three kinds of defects X, Y, Z. A sample of 1000 pieces was inspected with the following results: 2.1% had type X defect. 24% had type Y defect. 2.8% had type Z defect. 0.3% had both type X and type Y defects. 04% had both type X and type Z defects. 0.6% had both type Y and type Z defects. 0.1% had type X, type Y, and type Z defects. Draw a Venn Diagram, then find:
(a) What percent had none of these defects?
(b) What percent had at least one of these defects?
(c) What percent were free of type X and/or type Y defects?
(d) What percent had not more than one of these defects?

Answers

Answer:

a) % age of samples containing none of these defects = 93.9%

b)% age of samples containing at least one of these defects = 6.1%

c) % age of samples free of type X and/or type Y defects = 95.8%

d) %age of samples with not more than 1 defect = 98.9%

Step-by-step explanation:

Data Given:

Number of Samples = 1000

Type X defect = 2.1% = 21 samples

Type Y defect = 2.4% = 24 samples

Type Z defect = 2.8% = 28 samples

Both Type X and Y defect = 0.3% = 3 samples

Both Type X and Z defect = 0.4% = 4 samples

Both Type Y and Z defect = 0.6% = 6 samples

Type X and Y and Z defect = 0.1%  = 1 sample

Venn Diagram is attached in the attachment below. Please refer to attachment for the Venn Diagram.

a) % age of samples containing none of these defects.

Solution:

Number of samples containing none of these defects = Total - Samples with defects

Number of samples containing none of these defects = 1000 - { (Type X) + (Type Y) + (Type Z) - (Both X and Y) - (Both X and Z) - (Both Y and Z) + (All defects X and Y and Z) }

 Number of samples containing none of these defects = 1000 - { (21) + (24) +(28) - (3) -(4) - (6) + (1) }

Number of samples containing none of these defects = 1000 - 61

Number of samples containing none of these defects = 939

% age of samples containing none of these defects = 939/1000 x 100

% age of samples containing none of these defects = 93.9%

b) % age of samples containing at least one of these defects:

We have already calculated this above, number of samples containing at least on of these defects:

number of samples containing at least on of these defects = { (Type X) + (Type Y) + (Type Z) - (Both X and Y) - (Both X and Z) - (Both Y and Z) + (All defects X and Y and Z) }

number of samples containing at least on of these defects = { (21) + (24) +(28) - (3) -(4) - (6) + (1) }  

number of samples containing at least on of these defects = 61

% age of samples containing at least one of these defects = 61/1000 x 100

% age of samples containing at least one of these defects = 6.1%

c) % age of samples free of type X and/or type Y defects.

For this find, we need to find the samples with only Z Type defect.

Number of Samples with Only Z type defects = { (Type Z) - (Both X and Z) - (Both Y and Z) + (All defects X and Y and Z) }

Number of Samples with Only Z type defects = { (28)  -(4) - (6) + (1) }

Number of Samples with Only Z type defects = 19

Now, we also know the number of samples without any defects = 939

Now,

The number of samples free of type X and/or type Y defect = Sum of Number of Samples with Only Z type defects and number of samples without any defects

The number of samples free of type X and/or type Y defect = 19+939

The number of samples free of type X and/or type Y defect = 958

% age of samples free of type X and/or type Y defects = 958/1000 x 100

% age of samples free of type X and/or type Y defects = 95.8%

d) %age of samples with not more than 1 defect:

For this find, we need to find number of samples with only X type and with only type Y and with only type Z.

We have already found the number of samples with only Z type defect = 19

Now,

number of samples with only X type defect = { (Type X) - (Both X and Z) - (Both X and Y) + (All defects X and Y and Z) }

number of samples with only X type defect =  { (21)  -(4) - (3) + (1) }

number of samples with only X type defect =  15

Similarly,

number of samples with only Y type defect =  { (Type Y) - (Both Y and Z) - (Both X and Y) + (All defects X and Y and Z) }

number of samples with only Y type defect =  { (24)  -(6) - (3) + (1) }

number of samples with only Y type defect =  16

For,

samples with not more than 1 defect = number of samples with only Y type defect + number of samples with only X type defect + number of samples with only z type defect + number of samples without any defects

samples with not more than 1 defect = 939 + 16 + 15 + 19

samples with not more than 1 defect = 989

%age of samples with not more than 1 defect = 989/1000 x 100

%age of samples with not more than 1 defect = 98.9%

A machine has 12 identical components which function independently. The probability that a component will fail is 0.2The machine will stop working if more than three components fail Find the probability that the machine will be working .

Answers

Answer:

A machine has 12 identical components which function independently. The probability that a component will fail is 0.2. The machine will stop working if more than three components fail. Find the probability that the machine will stop working. A) 0.073 B) 0.795 C) 0.867 D)0.205

[tex]\frac{1}{3}x+6=8[/tex]

Answers

x = 6
Have a great rest of your day !
The answer to the problem is 2 because you need to get x by itself so subtract 6 on both sides of the equal sign.

Solve each problem by graphing
Y=-5x+3
Y=-5x-3

Answers

Answer:

I don't have graphing paper but this problem will have no solution. It will create two parallel lines going downwards.

Step-by-step explanation:

They both have the same slope and different y intercept so they will never intersect

Brayden is going to an amusement park. The price of admission into the park is $35,
and once he is inside the park, he will have to pay $2 for every ride he rides on. How
much money would Brayden have to pay in total if he goes on 15 rides? How much
would he have to pay if he goes on r rides?

Answers

2x15= 30
35+30=65
He would pay 65 if he rode 15 rides

Answer: $65; $35+r•2

Step-by-step explanation:

So if every ride Brayden goes on costs $2 and he rides 15 rides, 2•15= $30 from rides alone. Then you add the $35 from admission to that number to get $65. This works for any amount of rides, just change the number to how many rides he goes on and use the same formula, 35+r•2 where r equals the number of rides ridden.

11/(x+9)=5
I am struggling with this question. Is there a solution?

Answers

Answer:

x=-6.8

[tex] \\ step \: by \: step \: explanation \\ \frac{11}{(x + 9)} = 5 \\ 11 = 5(x + 9) \\ 11 = 5x + 45 \\ 5x = 11 - 45 \\ 5x = - 34 \\ x = \frac{ - 34}{5} = - 6.8[/tex]

The National Household Travel Survey gathers data on the time of day when people begin a trip in their car or other vehicle. Choose a trip at random and record the time at which the trip started. What probability should replace the "?" in the table?

Time of Day 10PM- 12:59AM 1AM- 5:50AM 6AM- 8:59AM 9AM- 12:59PM 1PM- 3:59PM 4PM- 6:59PM 7PM- 9:59PM
Probability 0.004 0.033 0.144 0.234 0.208 ? 0.123

a. 0.964
b. 0.379
c. 0.752
d. 0.218

Answers

Answer:

A probability of 0.254 should replace the "?" in the table

Step-by-step explanation:

We have the probabilities for the time of the day when each person begins a trip, during a 24-hour period.

The sum of these probabilities has to be 100% = 1.

The probabilities are of: 0.004, 0.033, 0.144, 0.234, 0.208, ?, 0.123

Since their sum has to be 1, we can find ?. So

0.004 + 0.033 + 0.144 + 0.234 + 0.208 + ? + 0.123 = 1

0.746 + ? = 1

? = 1 - 0.746

? = 0.254

A probability of 0.254 should replace the "?" in the table

The letters from the word MATHEMATICS are placed in a hat. What is the probability of selecting an M and then selecting a T if the letters are selected at random and not replaced?

Answers

The probability of selecting M and T are 4

Please please help

Find the measure of the missing angle.
63°

Answers

Answer:

27 degrees

Step-by-step explanation:

Answer:

a = 27° ______

Step-by-step explanation:

~~~~~~~~~~

Please help. I need to know the answer. I will give brainliest

Answers

9514 1404 393

Answer:

1 4 8 9

Step-by-step explanation:

blank 1

Locate x = 7 and find the y-value where the blue curve crosses.

  f(7) = 1

blank 2

Locate x = -9 and find the y-value where the red curve crosses.

  g(-9) = 4

blank 3

Locate y = 0 (the x-axis) and find the x-value where the blue curve crosses.

  f(8) = 0

blank 4

Locate y = 2 and find the x-value where the red curve intersects.

  g(9) = 2

15) A store is having a sale during which all outdoor furniture is 45% off the original price, p. If

the post-sale price of an outdoor furniture set can be calculated using the expression p

0.45p, which expression also represents the price?

Answers

Answer and explanation:

Given that there is 45% off original price of outdoor furniture and price is represented by p

Discount on original price of outdoor furniture = 45% of p=0.45×p=0.45p

Therefore post sale price(after discount) of outdoor furniture can be represented by (1-0.45)p=0.55p

Determine whether m(t)=(4/5)^t represents exponential growth or exponential decay. And Identify the percent rate of change.

Answers

Answer:

Step-by-step explanation:

exponential decay

rate of change: 20%

Mrs. Campos is making cupcakes for a bake sale. She uses the equation c = 0.55x to determine the cost, c, for x cupcakes. Which best represents the constant rate at which cupcakes are sold at the bake sale?

55 cupcakes per dollar

$0.55 per cupcake

$4 per cupcake

4 cupcakes per dollar

Answers

$0.55 per cupcake bc if you plug 1 in for x then c would be equivalent to $0.55

3
Solve for x.
-2x + 6 + 4x = -12

Answers

x=-9

-2x+6+4x=-12
combine like terms
2x+6=-12
subtract 6 from both sides
2x+6-6=-12-6
simplify
2x=-18
divide both sides of the equation
2x/2= -18/2
simplify
x=-9

Tim has 54 golf balls. He wants to put an equal number of golf balls in each of 9
baskets. How many golf balls will be in each basket?
CLEAR
SUBMIT
5 golf balls
6 golf balls
7 golf balls
8 golf balls

Answers

Answer: 6

Explanation: 9x6=54

if we need to decrease the standard deviation of the sampling distribution by half what do we need to do to the sample size

Answers

Answer:

The answer is below

Step-by-step explanation:

For a normal distributed population with a mean (μ), and a standard deviation (σ), if a sample size of n is selected from the population, the mean of the sample ([tex]\mu_x[/tex]) =  μ and the standard deviation of the sample ([tex]\sigma_x[/tex]) = [tex]\frac{\sigma }{\sqrt{n} }[/tex]

Let the normal distribution population have a standard deviation of σ. If the standard deviation is to be decreased by half, the sample size (n) needed is:

[tex]Using:\\\\\sigma_x=\frac{\sigma}{\sqrt{n} } \\\\but\ \sigma_x=\frac{\sigma}{2}\\\\Hence:\\\\ \frac{\sigma}{2}=\frac{\sigma}{\sqrt{n} }\\\\Divide\ through\ by \ \sigma\ to\ get:\\\\ \frac{1}{2}=\frac{1}{\sqrt{n} }\\\\\sqrt{n}=2\\\\square\ both\ sides:\\\\(\sqrt{n} )^2=2^2\\\\n=4\\\\[/tex]

To decrease the standard deviation of the sampling distribution by half we need a sample size of 4

What is the solution to the equation? sqrtx + 3 = 12 HINT: It's not C.

A. 225
B. 81
C. 3
D. No solution

Answers

B.) 81
sq rt of x= 12-3
sq rt of x=9
take the ^2 of both sides to get rid of the sq root
x^2= (9)^2
=81

Given the equation: - 4 √x - 3 = 12

solve for x;

Divide both sides by -4 in [1];  we get;

√x - 3 = -3

Squaring both sides we get;

x -3 = (3)²

or

x - 3 = 9

Add 3 both sides we get;

x - 3 + 3 = 9 + 3

Simplify:

x= 12

Extraneous solution states that it is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation.

Substitute  x= 12 in [1]

- 4√12 - 3 = 12

- 4√9 = 12

-4. 3 = 12

-12 = 12 False.

Therefore, the value of x is 12 and it is an extraneous solution.

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I need the answer i have spent forever on this.

Answers

Answer:

A y=2x + 3

Step-by-step explanation:

Answer:

The answer is A. (y = 2x + 3)

Step-by-step explanation:

Since its talking about $3 plus $2 per dog it would make sense to pick

y = 2x + 3 because 2x represents the number of dogs and how it costs $2 per dog while the 3 represents how it also cost $3 plus the $2.

What is the area of the figure?

Answers

Answer:

252 in²

Step-by-step explanation:

Just separate them into different shapes and add their areas together.

Answer:

252 Inches

Step-by-step explanation:

We first section off all the areas we can, find the area of each of those, add them all up, and you get 252 inches.

SOMEONE PLEASE PLEASE HELP!!!!!

Answers

Answer:

1800

Step-by-step explanation:

A learning experiment requires a rat to run a maze (a network of pathways) until it locates one of three possible exits. Exit 1 presents a reward of food, but exits 2 and 3 do not. (If the rat eventually selects exit 1 almost every time, learning may have taken place.) Let Yi denote the number of times exit i is chosen in successive runnings. For the following, assume that the rat chooses an exit at random on each run.

Required:
Find the probability that n = 6 runs result in Y1=3,Y2=1, and Y3=2

Answers

Answer:

Find the probability that n = 6 runs result in Y1=3,Y2=1, and Y3=2

=0.823

Step-by-step explanation:

Multinomial distribution

p(y1;y2,y3…..yk) = (n!/y1!,y2!,y3!…y4!) x p1^y1 x p2^y2 x p3^y3 x pk^yk)  

The rat chooses of the three exists at random:

p = 1/3

p(3,2,1) = 6! / 3! 1!  2! (1/3)^3 (1/3)^1 (1/3)^2

              =20/243

              =0.823

There are 40 children and 12 adults going on a trip to New York City by car. Each car can hold a maximum of 5 people. What is the least number of cars needed for the trip?

Answers

Answer:

Number of cars needed for the trip = 11

Step-by-step explanation:

Given that:

Number of children = 40

Number of adults = 12

Total number = 40 + 12 = 52 people

Each car can hold 5 people.

Number of cars = [tex]\frac{52}{5}[/tex]

Number of cars = 10.4

Rounding off to next whole number as one car can hold a maximum of 5 people.

Number of cars = 11

Hence,

Number of cars needed for the trip = 11

3) Find the smallest number by which 2068 must be multiplied to make perfect square.
equal solve

Answers

Answer:
1080
Explanation:
2068x1080=2,233,440
2,233,440= perfect square

The smallest number by which 2068 must be multiplied to make perfect square is 1080

What is a perfect square?

A perfect square is a number system that can be expressed as the

square of a given number from the same system.

We have to find the smallest number by which 2068 must be multiplied to make perfect square.

Then, Let the number be 1080 .

So,

2068 x 1080 = 2,233,440

2,233,440 = perfect square

Learn more about perfect square;

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-1<9+n<17 and graph the answer after

Answers

Answer:

We get [tex]\mathbf{n>-10\:\:and\:\:n<8}[/tex]

Or we can write as:  [tex]\mathbf{-10<n<8}[/tex]

The graph is shown is figure attached below:

Step-by-step explanation:

We need to solve the inequality [tex]-1<9+n<17[/tex] and graph the answer.

Solving the inequality

[tex]-1<9+n<17[/tex]

We know that if a<u<b then we can write a<u and u<b

So, we can write

[tex]-1<9+n \:and\: 9+n<17[/tex]

Solving these equations and finding values of n

[tex]-1<9+n \:and\: 9+n<17\\9+n>-1\:and\:9+n<17\\n>-1-9\:and\:n<17-9\\n>-10\:and\:n<8[/tex]

So, we get [tex]\mathbf{n>-10\:\:and\:\:n<8}[/tex]

We can write it as: -10< n and n<8

Overlapping we get: [tex]\mathbf{-10<n<8}[/tex]

The graph is shown is figure attached below:

If 4/3 liters of water are enough to water 2/5 of the plants in the house, how much water is necessary to water all the plants in the house? Write a division equation that could be used to solve this problem help six grade work

Answers

3.166666666 with the 6 repeating

what a ratio of 4 days to 36 hours​

Answers

Answer:

4:36

24 x 4:36

96:36

8:4

1day = 24 hours

Step-by-step explanation:

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